Round 5.342km to the nearest 100m

Answers

Answer 1

Answer:

5300 m

Step-by-step explanation:

Hi there!

First, we must change 5.342 km to meters by multiplying it by 1000:

5.342 × 1000 = 5342

Now, we know that 5.342 km is equivalent to 5342 m.

To round to the nearest 100 m, look at the hundreds place value in 5342 m. It is 3. The number before is 4. Because 4 is less than 5, it means we keep 3 as 3 and replace all the digits before with 0:

5300 m

I hope this helps!


Related Questions

You withdraw $40 each month from your savings account. what integer represents the change in your balance after 4 months?

Answers

Answer:

The balance would be $160 from whatever it was before the 4 months.

Step-by-step explanation:

Since the bank balance is being added by 40 for each month for 4 months, 4 * 40 is just 4*4 with an extra zero on the end. so that would be $160.

So if the balance before was $40, then the new balance after 4 months would be $200.

If there's no money previously, then there is now $160 after 4 months.

If there's a value before the $40 for 4 months, let me know and I will explain and tell you what it is.

If a=b+7 and b+7=9, then a=9

Answers

Answer:

a = 9

b = 2

Step-by-step explanation:

Given : a = 9

a = b + 7

9 = b + 7

b = 9 - 7 = 2

What is 6(x-6)+12=6(x+1)-3x show your work.

Answers

This is your awnser I hope it helped “X=10 “

a + (b-4) when a-24 and b-7

Answers

Answer:

a=24

b=7

now

24+(7-4)

24+3

27

so the answer is 27

Somebody help with 1 & 2

Answers

Answer:

c

Step-by-step explanation:

let x represent the equally priced bracelets of which there are 4 , so 4x

We know she spent $64 on rings and a total of $200 was spent , then

64 + 4x = 200 ← represents the situation

x represents the cost of a bracelet

Answer:

c

Step-by-step explanation:

the total amount paid at the jewelry is 200

64 was spent on rings

the rest amount of money was spent on 4 bracelets

let the price of one bracelet be x

200=4(x)+64

200=4x+64

a squared + b - c squared

Answers

Answer:

a²+(b-c)²

hope it helps

Plss tell me guy's plssssssssssssssssssssssssssssssssssssssssssssss

Answers

Answer:

According to my equation it's 20°

2x=5x-60
-3x=-60
X=20

So the angle is 40

An elephant is as strong as how many horses?

Answers

Answer:

4 horses

Step-by-step explanation:

The answer would be four horses


x=-4 +6+ (11 +4(-3))

Answers

Answer:

x=1

Step-by-step explanation:

x = -4 + 6 + (11 + 4(-3)).

First get the numbers in the parentheses

x = -4 + 6 + (11 - 12)

Since 11 - 12 = -1. We can replace (11-12) with -1

x = -4 + 6 -1

Now add and subtract

x = 1

b+6/4 when b=1.5???????????????????????

Answers

Answer:

3

Step-by-step explanation:

Help with this question. Will give brainliest.

Answers

Step-by-step explanation:

x = elsie ticket

[tex] \frac{2}{3} x + 10 = 21[/tex]

Answer:

No I am pretty sure it is the 4th answer my guy.

Step-by-step explanation:

2/3x-10=21

When completing the sum 5.8×3.87 Dominica forgot to put the decimal point in her answer. She wrote 22446. What should she have written?

Answers

22.446. This is because the decimal point is moved a total of three times between both of the numbers. in 5.8, the decimal point is moved once. in 3.87, the decimal point is moved twice. 1+2=3

Julie is arranging pictures in a photo album one time she arranges them into six on each page she rearrange them with eight on each page what is the least number of photos Julie could have put in her album

Answers

Answer:

Step-by-step explanation:

please helpppppp!!!!!!!!!

Answers

Answer:

64w^2

Step-by-step explanation:

Because 8w is in parentheses, you must apply the exponent to both the 8 and w.

So, it becomes (8*8)(x*x) which equals (64)(x^2).

Which then gives you your final answer, 64x^2.

If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you know that

it is a type of active transport.

it is a type of passive transport.

it could be active or passive transport.

Answers

It is a type of active transport because it will require energy to move against the concentration gradient (low to high)
- option A

If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you know that

it is a type of active transport.

 

What do pinocytosis and phagocytosis have in common?

They are both forms of endocytosis.

P, Q, V, and K are collinear with V between K and P, and Q between V and K. If VP = 14x + 4, PK = x + 630, VQ = 17x + 6, and KQ = 11x + 5, solve for VP.

Answers

   If the points P, Q, V and K are collinear, they will follow the segment addition postulate.

Measure of segment VP will be 214 units.

   It's given in the question,

P, Q, V and K are collinear.VP = 14x + 4PK = x + 630VQ = 17x + 6KQ = 11x + 5

By segment addition postulate,

            KQ + VQ + VP = KP

Substitute the values in the expression,

(11x + 5) + (17x + 6) + (14x + 4) = x + 630

(11x + 17x + 14x) + (5 + 6 + 4) = x + 630

42x + 15 = x + 630

42x - x = 630 - 15

41x = 615

x = [tex]\frac{615}{41}[/tex]

x = 15

Therefore, measure of VP = (14x + 4)

                                           = 14(15) + 4

                                          = 214 units

Measure of segment VP will be 214 units.

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Approximate the solution to the graphed system. Explain how you got your answer.

Answers

Answer:

(7.5, 12)

Step-by-step explanation:

The solution of a linear system is the intersection of the lines.

We can see the lines A and B intersect at the point (7.5, 12) which is the solution.

See attached for better visualization.

Answer:

(7.5,12.5)

Step-by-step explanation:

See the intersected point is almost situated at the middle of 10 and 15 .Hence its 12.5 on y.And the point is situated in the middle of 7 and 8 .Hence its 7.5 on x.

An amusement park sold 4 discount tickets and 36 full-price tickets. What percentage of the tickets sold were discount tickets?

Answers

10%
because 40 tickets were sold total and 4 were discounted.

On a number line, point S is located at -3 and point T is located at 9. What is the location of point R on ST given that the ratio of SR to RT is 3:4

A) 27/7
B) 2 1/4
C) 15/7
D) 1 1/4

Answers

Answer:

Im pretty sure it would be C

Step-by-step explanation:

The location of R on the number line will be 15/7 so option (C) will be correct.

What is a number line?

In mathematics, a number line is a straight line containing numbers arranged at equal segments or periods throughout its duration.

In another word, a number line is basically a line in which infinite numbers have been written in ascending order or increasing order.

A horizontal number line is the most common representation and can be extended infinitely in any direction.

Distance from S to T = 3 + 9 = 12

So,

SR + RT = 12

And given,

SR/RT = 3/4 ⇒ SR = (3/4)RT

By substitution,

(3/4)RT + RT = 12

RT ( 7/4) = 12

RT = 48/7

Now the location of point R ⇒

OT - RT = 9 - 48/7 = 15/7

Hence "The location of R on the number line will be 15/7".

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Write the equation of the line in fully simplified slope-intercept form.

Answers

Here is the answer to your question

plz help me plz and correctly!!!! only 3 questions plz!!!​ 100 points

Answers

Answer:

Step-by-step explanation:

6)b) Sin A - x Cos A = 0

Sin A = x Cos A

[tex]\dfrac{Sin \ A}{Cos \ A} = x[/tex]

[tex]\dfrac{1}{x}=\dfrac{1}{\dfrac{Sin \ A }{Cos \ A}}=1*\dfrac{Cos \ A}{Sin \ A}=\dfrac{Cos \ A}{Sin \ A}[/tex]

[tex]RHS = x +\dfrac{1}{x}\\\\\\[/tex]

         [tex]= \dfrac{Sin \ A}{Cos \ A}+\dfrac{Cos \ A}{Sin \ A}\\\\\\=\dfrac{Sin \ A*Sin \ A}{Cos \ A*Sin \ A}+\dfrac{Cos \ A * Cos \ A}{Sin \ A* Cos \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Cos \ A*Sin \ A}+\dfrac{Cos^{2} \ A}{Cos \ A* Sin \ A}\\\\= \dfrac{Sin^{2} \ A+Cos^{2} \ A}{Cos \ A*Sin \ A}\\\\=\dfrac{1}{Cos \A*Sin \ A}\\\\= \dfrac{1}{Cos \ A}*\dfrac{1}{Sin \ A}\\\\=Sec \ A * Cosec \ A[/tex]

          = LHS

7a) 1 - Sin A = 1/2

     [tex]1 = \dfrac{1}{2}+ Sin \ A\\\\1-\dfrac{1}{2}=Sin \ A\\\\\dfrac{1}{2}=Sin \ A\\[/tex]

⇒ A = 30°

Sec² A = Sec² 30° = [tex](\frac{2}{\sqrt{3}})^{2}=\frac{2^{2}}{(\sqrt{3)^{2}}}=\frac{4}{3}[/tex]

[tex]tan^{2} \ A = tan^{2} 30 = (\dfrac{1}{\sqrt{3}})^{2} = \dfrac{1}{3}[/tex]

LHS = 6 Sec² A + 9 tan² A

       [tex]= 6*\dfrac{4}{3}+9*\dfrac{1}{3}\\\\\\=2*4 + 3*1\\\\\\= 8 + 3\\\\= 11 = RHS[/tex]

Answer the question please

Answers

Similar to the other one, you now have a scale factor of 1/2, meaning each coordinate will be multiplied by 1/2.
(This will have the effect of pulling things in closer to the origin.)

Step 1: Identify the coordinates of Point K.
Step 2: Multiply both of those coordinates by 1/2.

Do you have it from there?

If 3x = y -5 and x = 4, then y =

Answers

Answer:

y = 17

Step-by-step explanation:

3x = y - 5, for x = 4

=> 3(4) = y - 5

=> 12 = y - 5

=> 12 + 5 = y

=> 17 = y

Help me on this math questionnn

Answers

where is the question?

Solve for x.



-5x = -10

x = 2
x = -2
x = 50

Answers

Answer:

Putting x= 2

[tex]( - 5) \times 2 = - 10 \\ - 10 = - 10[/tex]

putting x = -2

[tex]( - 5) \times ( - 2) = - 10 \\ 5 \times 2 = - 10 \\ 10 = - 10 \\ this \: is \: not \: correct \: equation[/tex]

putting x = 50

[tex]( - 5) \times 50 = - 10 \\ - 250 = - 10 \\ this \: is \: also \: not \: correct \: equation[/tex]

so, x = 2 is applicable.

How do you find the GCF of each?

Answers

The first step is to consider the GCF of the numbers (coefficients) separately from that of the x’s and that separately from the GCF of the y’s.

For the coefficients, take the smaller number (so 30 in the exercise #12) and find all the numbers that divide into 30:
1, 2, 3, 5, 6, 10, 15, 30
Then start with the largest of those and see which is the first to divide into 66.
30 does not divide evenly into 66.
15 does not divide evenly into 66.
10 does not divide evenly into 66.
6 does. You’ll use 6.

For the x’s, consider how many x’s each expression has.
66yx has 1 x
30x^2y has 2 x’s.
The greatest number they all have is 1 x.

For the y’s, do the same thing:
66xy has 1 y.
30x^2y has 1 y.
They both have 1 y in common.

So the greatest things they all have in common are 6xy. That’s your GCF.

Point B is the midpoint of AC. AB=3x and AC=5x+21 . What is the value of AB?

Answers

First, let's write down what we know.

AB = 3x

AC = 5x+21

Since B is the midpoint, AB is half the length of AC. The sum of AB + AB is equal to the length of AC.

AB + AB = AC

Let's plug in our values.

3x + 3x = 5x + 21

Simplify the left side.

6x = 5x + 21

Subtract 5x from both sides.

x = 21

Now, let's plug in 21 for x in AB

AB = 3x = 3(21) = 63

Does anyone know 81,452 divided by 93

Answers

Answer:

875

Step-by-step explanation:

The answer should be 875.82

The square of the difference between 2x and y

Answers

Answer:

this question doesn`t have much information but here`s my best guess

(2x-y)^2

[tex](2x - y)^2[/tex]. This expression represents the result of squaring the difference between 2x and y.

1. **Difference between 2x and y:** The difference between 2x and y is calculated by subtracting y from 2x. This gives us the expression "2x - y," which represents the numerical difference between these two quantities.

2. **Square of the Difference:** To square this difference, we simply multiply "2x - y" by itself. When you square something, you multiply it by itself. In mathematical notation, squaring is denoted using an exponent of 2, which is written as "^2."

So, combining the two steps, we have:

[tex](2x - y)^2[/tex]. This expression represents the result of squaring the difference between 2x and y. When you expand this expression, you get a quadratic expression, which may include terms like [tex]4x^2, y^2[/tex], and -2xy, among others, depending on the values of x and y.

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Zach and Ginny are building model cars. Ginny's car is 2 more than 3 times the length of Zach's car. The sum of the lengths of both cars is 30 inches. Write an equation to determine the lengths of Zach's and Ginny's cars.
3x + 2 = 30
x + 2 + 3x = 30
2x + 3 = 30
x + 2x + 3 = 30

Answers

Answer:

x + 2 + 3x = 30

Step-by-step explanation:

Both lengths are unknown, but Ginny's car length is described in terms of Zach's car length, so we choose a variable for Zach's car length.

Let x = Zach's car length.

Zach's car length is x.

"Ginny's car is 2 more than 3 times the length of Zach's car."

Ginny's car length is 2 + 3x.

Add the lengths:

x + 2 + 3x

"The sum of the lengths of both cars is 30 inches."

x + 2 + 3x = 30

Answer: x + 2 + 3x = 30

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