Sarah's family traveled 5 8 of the distance to her grandmother's house on Saturday. They traveled 1 3 of the remaining distance on Sunday. What fraction of the total distance to her grandmother's house was traveled on Sunday?

Answer:

C = 4 pi ft

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

Solving for r

4 pi = pi r^2

Dividing each side by pi

4 = r^2

Taking the square root of each side

sqrt(4) = sqrt(r^2)

2 = r

Now we can find the circumference

C = 2 * pi *r

C = 2*pi*2

C = 4 pi ft

Answer:

35 is correct

Step-by-step explanation:

hope this helps.

Answer:

35°

Step-by-step explanation:

Angle ACD is 70°. The little tick marks on the angle mean both sides of the split are the same amount. This means if you divide the angle in half, you will find out what both of them are equal to.

Answer:

11 unit

Step-by-step explanation:

Applying,

s = √[(y₂-y₁)²+(x₂-x₁)²]...................... Equation 1

Where s = length of the side formed.

From the question,

Given: x₁ = -2, x₂ = 9, y₁ = 5, y₂ = 5

Substitute these values into equation 1

s = √[(9+2)²+(5-5)²]

s = √(11²)

s = 11 unit.

Hence the length of the side formed by the vertices is 11 unit

Answer:

Number of additional inches= x

Number of additional topping= y

Total cost= 8+1.5(x)+0.75(y)

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hope it helps...

have a great day!!

Answer:

[tex] \frac{15 \sqrt{209} }{209} [/tex]

Step-by-step explanation:

Objective: Understand and work with trig identies.

Recall multiple trig identies and manipulate them to get from cosecant to secant.

Given

[tex] \csc(a) = \frac{60}{16} [/tex]

Apply reciprocal identity csc a = 1/sin a.

[tex] \sin(a) = \frac{16}{60} [/tex]

Apply pythagorean identity to find cos a.

[tex]( \frac{16}{60}) {}^{2} + \cos(x) {}^{2} = 1[/tex]

[tex] \frac{256}{3600} + \cos(x) {}^{2} = 1[/tex]

[tex] \cos(x) {}^{2} = \frac{3600}{3600} - \frac{256}{3600} [/tex]

We can simplify both expression

[tex] \cos(x) {}^{2} = \frac{225}{225} - \frac{16}{225} [/tex]

[tex] \cos(x) = \frac{ \sqrt{209} }{15} [/tex]

Cosine is positve on quadrant 1 so that cos(a)

Apply reciprocal identity sec a= 1/ cos a.

The answer is

[tex] \sec(a) = \frac{15}{ \sqrt{209} } [/tex]

Rationalize the denominator.

[tex] \frac{15}{ \sqrt{209} } \times \frac{ \sqrt{209} }{ \sqrt{209} } = \frac{15 \sqrt{209} }{209} [/tex]

Answer:

(47+21√5)/2

Step-by-step explanation:

Given the expression

7+3√5/7-3√5

= 7+3√5/7-3√5 * (7+3√5)/(7+3√5)

= 49+21√5+21√5+9(5)/[7(7)-9(5)]

= 49+42√5+45/49-45

= 94+42√5/4

= 2(47+21√5)/4

=(47+21√5)/2

Hence the required expression is (47+21√5)/2

Answer:

x=5

Step-by-step explanation:

7x - 4y = 23 and x + y = 8

Multiply the second equation by 4

4x + 4y = 32

Add this to the first equation

7x - 4y = 23

4x + 4y = 32

------------------------

11x    = 55

Divide each side by 11

11x/11 = 55/11

x = 5

Answer:

[tex]\huge\boxed{x=5}[/tex]

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}7x-4y=23\\x+y=8&|\text{subtract}\ x\ \text{from both sides}\end{array}\right\\\left\{\begin{array}{ccc}7x-4y=23&(1)\\y=8-x&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\7x-4(8-x)=23\qquad|\text{use the distributive property}\\\\7x+(-4)(8)+(-4)(-x)=23\\\\7x-32+4x=23\qquad|\text{combine like terms}\\\\(7x+4x)-32=23\qquad|\text{add 32 to both sides}\\\\11x-32+32=23+32\\\\11x=55\qquad|\text{divide both sides by 11}\\\\\dfrac{11x}{11}=\dfrac{55}{11}\\\\x=5[/tex]

Answer:

El número de facturas

5 lempiras = 10 billetes

20 lempiras = 15 billetes

Step-by-step explanation:

Vamos a representar

El número de facturas de

5 lempiras = x

20 lempiras = y

Nuestro sistema de ecuaciones se da como:

x + y = 25 ..... Ecuación 1

x = 25 - y

5 × x + 20 × y = 350

5x + 20y = 350 .... Ecuación 2

Sustituiríamos x por 25 - y en la ecuación 2

5 (25 - años) + 20y = 350

125 - 5 años + 20 años = 350

125 + 15 años = 350

15 años = 350 - 125

15 años = 225

y = 225/15

y = 15

Resolviendo para x

x = 25 - y

x = 25 - 15

x = 10

Por lo tanto, el número de facturas

5 lempiras = 10 billetes

20 lempiras = 15 billetes

Answer:

1:26

Step-by-step explanation:

You can divide both sides by 2.

Answer:

3mm brainliest please

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

9mm times 1:3 of the rectangle is 245

Answer:

HCF×LCM=a×b

6×60=a×b

a×b=360

So the numbers are whose product is 360 and LCM is 60

These two numbers can be 6,60 or 12,30

Answer:

The coefficient is 3, the number right before the variable.

Answer:

3

Step-by-step explanation:

Answer:

there is one more zero

Step-by-step explanation:

now it's 8 million rather than 800 thousand.

Answer:

The missing parts of the proof includes;

1) ∠ABC = m∠CBD + m∠ABD = 90° (Angle addition postulate)

2) m∠CBD = m∠ABD (Definition of angle bisector)

3) m∠CBD + m∠ABD  = m∠CBD + m∠CBD (Substitution property of equality)

Step-by-step explanation:

The given details of the proof are;

∠ABC is a right angle = 90°

Line DB is a bisector of ∠ABC

Therefore;

1) ∠ABC = m∠CBD + m∠ABD = 90° by angle addition postulate

By the definition of angle bisector, we have;

The angles formed by line DB from ∠ABC are equal,

2) m∠CBD = m∠ABD by the definition of angle bisector

3) m∠CBD + m∠ABD = 90° = m∠CBD + m∠CBD = 2 × m∠CBD by substitution property of equality

2 × m∠CBD = 90°

∴ m∠CBD = 90°/2 = 45°

Answer:

A: Given

B: measure the angle ABC = 90

C: angle addition postulate

D: 2 times the measure of angle CBD = 90

Step-by-step explanation:

Hope this helps <3

Answer:

0.76

or

-0.76

hope this helps

Answer:

-6 and -1

Step-by-step explanation:

The excluded values are the values of x that satisfy [tex]2x^{2} + 14x + 12 = 0[/tex]

Let us solve the equation [tex]2x^{2} + 14x + 12 = 0[/tex]

It's a quadratic equation

Thus, let us calculate the discriminant Δ

Δ [tex]= 14^{2} - 4 .2.12 = 100[/tex]

the discriminant is greater than 0, so the equation has two solutions

[tex]x = \frac{-14 - 10}{4} = \frac{-24}{4} = -6[/tex]  or  [tex]x = \frac{-14+10}{4} = \frac{-4}{4} = -1[/tex]

the excluded values are -6 and -1

Answer:

hypotenuse = 7.3

Step-by-step explanation:

here 7 and 2 are the legs og the right triangle .we should find hypotenuse.

let the legs of the right triangle be a nd b respectively . And c be hypotenuse

using pythagoras theorem to find hypotenuse

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.28 = c

7.3 =c

Answer:

7.3

Step-by-step explanation:

[tex]7^{2} + 2^{2} = x^{2} \\ 53 = x^{2}\\\sqrt{53} = \sqrt{x^{2}} \\x = 7.3[/tex]

Answer:

Expression B: 0.8p

Expression D: p - 0.2p

Step-by-step explanation:

The regular price of an item at a store is p dollars. The item is on sale for 20% off the regular price. Some of the expressions shown below represent the sale price, in dollars, of the item.

Expression A: 0.2p

Expression B: 0.8p

Expression C:1 - 0.2p

Expression D: p - 0.2p

Expression E: p - 0.8p

Which two expressions each represent the sale price of the item?

Regular price of the item = $p

Sale price = 20% off regular price

Sale price = $p - 20% of p

= p - 20/100 * p

= p - 0.2 * p

= p - 0.2p

= p(1 - 0.2)

= p(0.8)

= 0.8p

The sale price is represented by the following expressions

Expression B: 0.8p

Expression D: p - 0.2p

Answer:

16/49

Step-by-step explanation:

2/ 7÷ 7/8

Copy dot flip

2/7 * 8/7

Multiply the numerators

2*8 =16

Multiply the denominators

7*7 = 49

numerator over denominator

16/49

Answer:

[tex]\frac{16}{49}[/tex]

Step-by-step explanation:

Answer:

The answer is [tex]3^3\times 2^2[/tex].

Step-by-step explanation:

According to the rules of exponents

a^n = a x a x a x .... n times

So,

[tex]3^{2}\times (2^{3}+4)\\\\=9\times (8 +4)\\\\=108\\\\=3^{3}\times 2^{2}[/tex]

[tex]\longrightarrow{\green{\frac{5}{6}}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \frac{1}{2} + \frac{1}{3} [/tex]

Since the denominators are unequal, we find the L.C.M (lowest common multiple) for both denominators.

The L. C. M for 2 and 3 is 6.

Now, multiply the L.C.M. with both numerator & denominator.

[tex] = \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} [/tex]

[tex]= \frac{3}{6} + \frac{2}{6} [/tex]

Now that the denominators are equal, we can add them.

[tex]= \frac{3 + 2}{6} \\ \\ = \frac{5}{6} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

Answer:

[tex]slope = \frac{2 - ( - 1)}{0 - ( - 1)} \\ = 3 \\ y = mx + c \\ 2 = (0 \times 3) + c \\ c = 2 \\ { \boxed{y = 3x + 2}}[/tex]

Answer:

x + 1 y+1

Step-by-step explanation:

it translated 1 unit up the x axis and 1 unit y axis

Answer:

reflected across the y-axis and translated 1 to the right and 1 up

Step-by-step explanation:

answer is

B. 6√2

hope this helps!

Answer:

Possible outcomes = 6

Step-by-step explanation:

Since the spinner is divided into red, yellow, orange, purple, blue and pink

Total of 6 colors.

Answer:

(x, y) = (10, 290)

Step-by-step explanation:

From the table

Total fees = fixed + variable

Fixed:

When number of times Ahmed mowed, x = 0

y = 40

When x = 2, y = 65

Rate of change = y2 - y1

= 65 - 40

= 25

y = 40 + 25x

Where,

y = total fees charged

40 = fixed fee

25x = variable fee

Total amount Ahmed will make for mowing 10 times

when x = 10

y = 40 + 25x

y = 40 + 25(10)

= 40 + 250

= 290

y = 290

(x, y) = (10, 290)

Answer:

option  C

Step-by-step explanation:

We will take 2 coordinates from the graph and Find the equation of the line.

Let the coordinates be : ( 0, 1) and (1, 3)

step 1 : find slope

[tex]slope , m = \frac{y_2 - y_ 1}{x_2 - x_1} = \frac{3-1}{1-0} = 2[/tex]

Step 2 : equation of the line :

[tex]( y - y_1) = m (x- x_1)[/tex]

[tex](y -1) = 2 ( x -0)\\y - 1 = 2x \\y = 2x + 1[/tex]

Therefore, y = 2x + 1 represent the equation of the line.

Answer:

C

Step-by-step explanation:

You need to solve for y = mx + b

You can solve for b right away. It is clear that the line crosses the y axis at (0,1) so you have

y = mx + 1 so far.

Normally you would need two clear points to solve for m, but since you know the y intercept, you need only 1 point.

The clearest point I can see is (-2,-3) which means that

x = -2

y = - 3

Put that into the equation and solve for m.

-3 = m(-2) + 1          Subtract 1 from both sides

-3-1 = m(-2)             Combine

-4 = -2 m                 Divide both sides by - 2

-4/-2 = m

m = 2

Answer

only a and c are real choices. That's because m = 2 in both cases.

The equation we got is y = 2x + 1 which is c