Scouts of ABC school made to run around a regular hexagonal ground fig 9, of perimeter 270 m .If they started running from point X and covered two fifth (2/5th) of the total distance.Which side of the ground will they reach?

Answer:

y=3

Step-by-step explanation:

Answer:

9, 13, 17, 21

Step-by-step explanation:

If x=2,

y=1+4(2)

y=9

This goes on, like a pattern. If x increases by 1, y inreases by 4. So, if y=3, x=13. If x=4, y=17, and so on.

Answer:

x = 6/4, or x = 3/2, OR x = 1 1/2

Step-by-step explanation:

5x - [7 - (2x-1)] = 3(x-5) + 4(x+3)

Pick one side to work on first, I will chose the right side,

Distribute on the right side.

5x - [7 - (2x-1)] = 3x - 15 + 4x + 3

Now, add like terms on the right side.

5x - [7 - (2x-1)] = 7x - 12

Now, to isolate 7 - (2x -1), subtract 5x from both sides.

so now,

-7 - (2x-1) = 2x - 12

Now, we can add 7 to both sides of the equation to isolate -(2x-1)

we add instead of subtract because the seven is a negative.

-(2x-1) = 2x - 5

Now, there is still a negative sign in front of the (2x-1), so we distribute the - to the equation.

-2x + 1 = 2x - 5

Now, we can isolate the variable and numbers bu adding five to both sides, and adding 2 to both sides. This is to make the equation easier by removing any negative terms.

6 = 4x

Divide both sides by 4

x = 6/4, or x = 3/2, OR x = 1 1/2

The question is not complete, so i have attached it.

Answer:

Option A - The data may not be reliable because there is an outlier.

Step-by-step explanation:

Looking at the question attached and the number of the gorrila vis - a - vis the time to interact, we can see that majority of the time to interact falls between 2.5 and 3.4.

However, we have a time of 8.3 days which is for gorrila 3.

This 8.3 is far higher than the range of the other values. Thus, we have an outlier because an outlier is a value is much more smaller or larger than most of the other values in a set of given data.

Thus, the data may not be reliable because there is an outlier.

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

Answer:

Answer:

215483 cm³

Step-by-step explanation:

Formula for volume of a cylinder = πr² · h

radius = 1/2diameter

1. Set up the equation

(3.14)(15²)(305)

2. Solve

215482.5

rounded to the nearest cubic centimeter = 215483 cm³

Answer:

215483 cm³

Step-by-step explanation:

credit goes to person up top

Answer:

y = 2x + 1

Step-by-step explanation:

Given a point and the slope, we can plug in these values into the equation to find the value of b:

y = mx + b

3 = 2(1) + b

3 = 2 + b

1 = b

Plug b into the equation:

y = 2x + 1

Answer:

y = 2x + 1

Step-by-step explanation:

Answer:  see graph

Step-by-step explanation:

Look at the Unit Circle to see the coordinates of the quadrangles.

Build a sine table for one period (0° - 360°).

    x        y = sin(x)          y² = (sin(x))²      (x, y²)    

    0°       sin(0°) = 0          (0)² = 0              (0°, 0)

   90°     sin(90°) = 1          (1)² = 1               (90°, 1)

  180°     sin(180°) = 0        (0)² = 0            (180°, 0)

  270°     sin(270°) = -1       (-1)² = 1             (270°, 1)

  360°     sin(360°) = 0       (0)² = 0            (360°, 0)

Now plot the (x, y²) coordinates on your graph.

Answer:

330.00cm²

Step-by-step explanation:

find the area of both circles and subtract the smaller one from the bigger one.

area of a circle= πr²

π wasn't given so I will use 22/7

so area of the bigger circle = 22/7 × 11²

=22/7 × 121

=380.28cm²

area of the small circle=22/7 × 4²

= 22/7 × 16

= 50.28cm²

Area of the shaded portion = 380.28 - 50.28

= 330.00cm²

Answer:

[tex] \boxed{12 \sqrt{2} }[/tex]

Step-by-step explanation:

Isosceles triangle are those triangle which have two equal sides.

Perpendicular ( p ) = 12 inches

Base ( b ) = 12 inches

Hypotenuse ( h ) = ?

Now,Using Pythagoras theorem,

[tex] \mathsf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

Plug the values

[tex] \mathsf{ {h}^{2} = {12}^{2} + {12}^{2} }[/tex]

Evaluate the power

[tex] \mathsf{ {h}^{2} = 144 + 144}[/tex]

Calculate the sum

[tex] \mathsf{ {h}^{2} = 288}[/tex]

Squaring on both sides

[tex] \mathsf{h = 12 \sqrt{2} }[/tex]

Hope I helped!

Best regards!

Answer:

Value of F(2) = 12

Step-by-step explanation:

Given:

F(x) = 7x - 2

Find:

Value of F(2)

Computation:

F(x) = 7x - 2

putting x = 2

f(2) = 7(2) -2

f(2) = 14 - 2

f(2) = 12

So, Value of F(2) = 12

Answer:

1- 5xy³√5y

2- 2xy²∛3y²

Step-by-step explanation:

√125x²y^7=

√25*5x²y^6y

5xy³√5y

2) ∛24x³y^8=

∛2³*3x³y^8=

2xy²∛3y²

Answer:

x-6/2=2x/7

7x-42=4x

7x-4x=42

3x= 42

X = 42/3

Answer:

4 cm

Step-by-step explanation:

Volume is given by area of cross section * height

_______________________________

For condition 1

height = 12 cm

base for area of cross section is 5*8

that is length 8 cm and width 5 cm

thus area of cross section = 5*8 = 40 cm square

volume of milk =  area of cross section* height of milk = 40*12 = 480 cm cube.

_______________________________________________

now milk is turned such that base of area of cross section will

15 by 8

that is length: 15 cm and width : 8 cm

thus area of cross section = 15*8 = 120 cm square

let the depth of milk be x

thus, volume of milk =  area of cross section* height of milk = 120*x

= 120x cm cube

Since milk is in the same container , its volume before and after the change of alignment of container will remain same

thus

120x cm cube = 480 cm

=> x = 480/120 = 4

Thus, depth under given situation will be 4 cm.

Answer:

The systems of equation for the amount spent are as follows

[tex]Y= 0.99x+5[/tex]

[tex]Y= 0.79x+10[/tex]

Step-by-step explanation:

In this problem we are expect to give a model or an equation that represents the amount of money spent per month given a fix subscription amount and a variable fee which is based on extra minutes spent.

let Y represent the amount of money spent in total for the month

The first case:

Subscription =$5

charges per minutes = $0.99

therefore the amount spent can be modeled as

[tex]Y= 0.99x+5[/tex]

The second case:

Subscription =$10

charges per minutes = $0.79

therefore the amount spent can be modeled as

[tex]Y= 0.79x+10[/tex]

Answer:

Options (B) and (D)

Step-by-step explanation:

If a triangle is a 30° - 60° - 90° triangle, measure of the angle between the leg and hypotenuse will be either 60° or 90°.

Therefore, by applying Cosine rule in the given options.

c² = a² + b² - 2abCosC

All the given options are the right triangles.

[Since they follow the Pythagoras theorem]

Option (A),

Angle between the sides having measures 3 and 5 units,

4² = 3² + 5² - 2(3)(5)CosC

16 = 9 + 25 - 30.CosC

30.CosC = 18

[tex]C=\text{Cos}^{-1}(\frac{5}{6} )[/tex]

C = 33.56°

Therefore, this triangle is not a 30-60-90 triangle.

Option (B),

Angle between the sides measuring 5 and 10 units,

[tex](5\sqrt{3})^2=5^2+10^2-2(5)(10)\text{CosC}[/tex]

75 = 125 - 100(CosC)

Cos(C) = 0.5

C = 60°

Therefore, other angles of the triangle will be 30° and 90°.

And it's a 30°-60°-90° triangle.

Option (C),

10, 10, 10√2

It's a right triangle and the measure of legs are equal.

Since legs of this sides are equal, angles opposite to these equal sides will be equal.

Sum of all interior angles = 180°

m∠A + m∠B + m∠C = 180°

If m∠B = 90°

m∠A + 90° + m∠C = 180°

2(m∠A) = 90°

m∠A = 45°

Therefore, the given sides make a 45°- 45°- 90° triangle.

Option (D).

Angle between the sides 3 and 6,

(3√3)² = 3² + 6² -2(3)(6)CosC

27 = 9 + 36 - 36.(CosC)

CosC = [tex]\frac{18}{36}[/tex]

C = [tex]\text{Cos}^{-1}(\frac{1}{2})[/tex]

C = 60°

Therefore,

These sides make a 30°- 60°- 90° triangle.

Options (B) and (D) are the 30°- 60°- 90° triangle.  

Answer:

3(a). The ship travelled in north is 26.0 km.

(b). The ship travelled in east is 23.4 km.

4(a). The ship travelled in south is -88.61 km.

(b). The ship travelled in west is -179.29 km.

Step-by-step explanation:

Given that,

(3). Distance = 35 km

Angle = 42°

Let distance in north is y km.

We need to calculate the distance

Using vertical component

[tex]y = d\cos\theta[/tex]

Put the value into the formula

[tex]y = 35\cos42[/tex]

[tex]y=26.0\ km[/tex]

Let distance in east is x  km

We need to calculate the distance

Using horizontal component

[tex]x =d\sin\theta[/tex]

Put the value into the formula

[tex]x = 35\sin42[/tex]

[tex]x=23.4\ km[/tex]

(4). A ship sails 200 km on a bearing of 243.7°

Let distance in south is y km.

We need to calculate the distance

Using vertical component

[tex]y = d\cos\theta[/tex]

Put the value into the formula

[tex]y = 200\cos243.7[/tex]

[tex]y=-88.61\ km[/tex]

Let distance in west is x  km

We need to calculate the distance

Using horizontal component

[tex]x =d\sin\theta[/tex]

Put the value into the formula

[tex]x = 200\sin243.7[/tex]

[tex]x=-179.29\ km[/tex]

Hence, 3(a). The ship travelled in north is 26.0 km.

(b). The ship travelled in east is 23.4 km.

4(a). The ship travelled in south is -88.61 km.

(b). The ship travelled in west is -179.29 km.

Answer:

25.4 cm

Step-by-step explanation:

will make it simple and short

2*b + 2*h

2*4.5 + 2*8.2 = 25.4 cm

Hey there! I'm happy to help!

The perimeter is the distance around the rectangle.

In a rectangle, there are two pairs of opposite sides, and those opposite sides are equal. They are known as the length and the width.

In a rectangle, you have two sides that have the same length and two that have the same width. If you add these all up, you get the perimeter.

If our length is L and our width is W, we can write this equation.

P=2L+2W

So, we can plug in our lengths and widths to find the perimeter!

P=2(4.5)+2(8.2)

P=9+16.4

P=25.4

Therefore, our perimeter is 25.4 cm.

Have a wonderful day! Feel free to message me if you have any questions! :D

Answer:

i. a = 7

ii. b = 7

iii. c = 14

Step-by-step explanation:

1. In a parallelogram, the pair of opposite sides are equal, thus;

6a + 10 = 8a -4

4 + 10 = 8a - 6a

14 = 2a

Divide both sides by 2,

a = 7

2. <SPQ + <PSR = [tex]180^{0}[/tex]

(18b - 11) + (9b + 2) =  [tex]180^{0}[/tex]

18b + 9b + 2 -11 =  [tex]180^{0}[/tex]

27b -9 =  [tex]180^{0}[/tex]

27b =  [tex]180^{0}[/tex] + [tex]9^{0}[/tex]

27b = [tex]189^{0}[/tex]

Divide both sides by 27,

b = 7

Therefore,

c = a + b

  = 7 + 7

  = 14

c = 14

Answer:

9 small boxes and 15 large boxes

Step-by-step explanation:

x = small box

y = large box

x + y = 24

9x + 24y = 441

-9x - 9y = -216

15y = 225

y = 15

x + 15 = 24

x = 9

Answer:

Let x be the small boxes

Let y be the large boxes

x+y=24

9x+24y=441

Step-by-step explanation:

Answer:

Equivalent  expression:

6a + 10

or

9a + 15

Step-by-step explanation:

[ -6 +22 – 6 + 8 ] = 18

18 ÷ (-9) = -2

{40 – (-2) -3 – ( -1)} = { 40 + 2 -3 + 1} = 40

400 ÷ 40 = 10

(40 x 23) + (40 x -17)

920 + (-680)

= 240

(1673 x 99) + 1673

1673 x 100

= 167300

Hope this helps ^-^

Answer:

3x^2

Step-by-step explanation:

Given:

(3x) * {(1/x)^-4 }* (x^-3)

=(3x) * {1 ÷ (1/x)^4} * {1/x^3}

=(3x) * {1(x/1)^4} * (1/x^3)

=(3x) * (x^4) * (1/x^3)

=(3x) (x^4) (1) / x^3

Multiply the denominators

=3x^5 / x^3

Can also be written as

=3*x*x*x*x*x / x*x*x

Divide the x

= 3*x*x / 1

=3x^2

Answer:

[tex]\boxed{ Graph. B}[/tex]

Step-by-step explanation:

Hey there!

Well slope is aka rise/run,

so starting at the red dot and rising 4 units an ruing to the right 5 units,

graph b is the correct answer.

Hope this helps :)

Graph B has a slope of 4/5.

Slope is calculated with the aid of finding the ratio of the "vertical change" to the "horizontal alternate" among (any) distinct factors on a line.

Typically, the slope of a line offers the measure of its steepness and path. The slope of an instant line among two factors says (x1,y1) and (x2,y2) may be without problems decided by finding the difference between the coordinates of the points. The slope is commonly represented by using the letter 'm'.

Learn more about slope here https://brainly.com/question/1884491

#SPJ2

the two lines are parallel, the angle they make should be equal and one angle is common so the triangles are similar by AAA.

Now the ratio of sides are [tex] \frac{20+8}{20}=\frac{x+18}{x}[/tex]

use divideno, [tex]\frac8{20}=\frac{18}x[/tex]

and then inverse the whole equation to get [tex]x=20\times\frac{18}{8} \implies x= 45[/tex]

Answer:

[tex]\Large \boxed{\mathrm{B) \ 45}}[/tex]

Step-by-step explanation:

We can solve the problem using ratios.

[tex]\displaystyle \frac{x}{20} =\frac{x+18}{20+8}[/tex]

Cross multiply.

[tex]20(x+18)=x(20+8)[/tex]

Expand brackets.

[tex]20x+360=28x[/tex]

Subtract 20x from both sides.

[tex]360=8x[/tex]

Divide both sides by 8.

[tex]45=x[/tex]

Answer:

Clarissa will take 10 hours by herself

Step-by-step explanation:

Let s = time for shawna

s-5 = time for clarissa

The formula for determining the time is

1/a + 1/b = 1/c  where a and b are the times alone and c is the time together

1/s + 1/(s-5) = 1/6

Multiply each side by 6s(s-5) to clear the fractions

6s(s-5) ( 1/s + 1/(s-5)) = 1/6 *6s(s-5)

Distribute

6(s-5) + 6s = s(s-5)

Distribute

6s -30 +6s = s^2 -5s

Combine like terms

12s -30 = s^2 -5s

Move everything to the right

0 = s^2 -5s -12s +30

0 = s^2 -17s +30

Factor

0 = ( s-15) (s-2)

Using the zero product property

s-15 =0   s-2 =0

s =15     s=2 ( This is not a reasonable answer since it is less than the time together)

s=15

s-5 = 10

Clarissa will take 10 hours by herself

Answer:

The sum of the arithmetic progression is 2520

Step-by-step explanation:

The sum, Sₙ, of an arithmetic progression, AP, is given as follows;

[tex]S_{n}=\dfrac{n}{2}\cdot \left (2\cdot a+\left (n-1 \right )\cdot d \right )[/tex]

Where;

n = The nth term of the progression

a = The first term = 100

d = The common difference = -2

Given that the last term = -10, we have;

-10 = 100 + (n - 1) ×(-2)

n = (-10 - 100)/(-2) + 1 = 56

Therefore, the sum of the 56 terms of the arithmetic progression is [tex]S_{56}=\dfrac{56}{2}\cdot \left (2\cdot 100+\left (56-1 \right )\cdot (-2) \right )[/tex]

Which gives;

[tex]S_{56}={28}\cdot \left (200-\left 110 \right ) = 2520[/tex]

Answer:

about 62m^3

Step-by-step explanation:

Answer:

0.86, 8.14

Step-by-step explanation: