Select all that apply to Enums: Group of answer choices While mainly a readability feature, we can technically use Enum to do things like spoof a boolean type in C allowing us some level of functionality Enums let us build a series of any kind of constant Enums allow us to print names for integers instead of numbers Enums are great for representing states and other common constants like colors Enums let us specifically value each constant we create Flag question: Question 59 Question 59

Answer:

A. true

Explanation:

because 5s is the.................

Explanation:

The following six steps must be followed to solve a problem using computer.

Problem Analysis.

Program Design - Algorithm, Flowchart and Pseudocode.

Coding.

Compilation and Execution.

Debugging and Testing.

Program Documentation.

Answer:

Explanation:

1) Chart area: This is the area where the chart is inserted. 2) Data series: This comprises of the various series which are present in a chart i.e., the row and column of numbers present. 3) Axes: There are two axes present in a chart. ... 4)Plot area: The main area of the chart is the plot area

Answer:

an optical instrument used for viewing very small objects, such as mineral samples or animal or plant cells, typically magnified several hundred times

Answer:

A microscope is a laboratory instrument used to examine objects that are too small to be seen by the naked eyes.

Answer:

The modified program in Python is as follows:

triangle_char = input('Enter a character:\n')

triangle_height = int(input('Enter triangle height:\n'))  

for i in range(triangle_height):

   print(triangle_char * (i+1))

Explanation:

This gets the character from the user

triangle_char = input('Enter a character:\n')

This gets the height of the triangle from the user

triangle_height = int(input('Enter triangle height:\n'))  

This iterates through the height

for i in range(triangle_height):

This prints extra characters up to the height of the triangle

   print(triangle_char * (i+1))

Here's the modified program that incorporates the requested changes:

python

Copy code

triangle_char = input('Enter a character:\n')

triangle_height = int(input('Enter triangle height:\n'))

print('')

for i in range(1, triangle_height + 1):

   line = triangle_char * i + ' ' * (triangle_height - i)

   print(line)

This program uses a loop to iterate from 1 to triangle_height. In each iteration, it creates a line by concatenating triangle_char repeated i times with spaces (' ') repeated (triangle_height - i) times. The resulting line is then printed.

For example, if the user enters % as the character and 5 as the height, the output will be to make sure to maintain the indentation properly in your code for it to work correctly.

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Which XXX declares a student's name.

public class Student {

   XXX

   private double myGPA;  

   private int myID;

   public int getID() {

        return myID;

   }

}

Group of answer choices

a. String myName;

b. public String myName;

c. private myName;

d. private String myName;

private String myName;

To declare a student's name, the following should be noted.

i. The name of the student is of type String

ii. Since all of the instance variables (myGPA and myID) have a private access modifier, then myName (which is the variable name used to declare the student's name) should be no exception. In other words, the student's name should also have a private access.

Therefore, XXX which declares a student's name should be written as

private String myName;

Option (a) would have been a correct option if it had the private keyword

Option (b) is not the correct option because it has a public access rather than a private access.

Option (c) is not a valid syntax since, although it has a private access, the data type of the variable myName is not specified.

Option (d) is the correct option.

Answer:

128 KB      

Explanation:

Given data :

The block size = 512 bytes

Block pointer size = 2 bytes

In an indexed allocation, a special block named Index Block contains all the pointers to the blocks that the file had occupied.

Therefore, the maximum number of block pointer in 1 block :

[tex]$=\frac{\text{block size}}{\text{pointer size}}$[/tex]

[tex]$=\frac{512}{2}$[/tex]

= 256

Thus, a block can hold maximum 256 pointers.

It is given the level of indexing is one. So,

Maximum size of the file =  maximum number of block pointers in 1 file x block size

                                          = 256 x 512

                                          [tex]$=2^8 \times 2^9$[/tex]

                                          [tex]$=2^{8+9}$[/tex]

                                           [tex]$=2^{17}$[/tex]

                                          [tex]$=2^7 \times 2^{10}$[/tex]

                                          [tex]$=128 \times 2^{10}$[/tex]

                                          = 128 KB   (∵ 1 KB = [tex]2^{10} \ B[/tex] )

Therefore, the largest file that 1 level if indexed allocation method can handle is 128 KB.