Show all work to multiply (3+ Square root of -16)(6- square root of -64)

The sum of the 15th square number and the 5th cube number is 350.

The 15th square number will be:

15² = 15 × 15

= 225

The 5th cube number will be:

5³ = 5 × 5 × 5

= 125

The sum of the numbers will be:

225 + 125

= 350

Therefore, we get that, the sum of the 15th square number and the 5th cube number is 350.

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Explanation:

Consider something like 2b+6 factoring to 2(b+3). When we distribute that outer 2 back inside the parenthesis, we're multiplying that 2 by everything inside. Factoring goes in reverse of this and we divide each term of 2b+6 by the GCF 2.

The same thing applies to this current problem as well.

Divide each term by the -1.8 we want to factor out.

The results -2b and 5 will go inside the parenthesis. That's how we end up with -1.8(-2b+5)

You can use distribution to verify this

-1.8(-2b+5)

-1.8*(-2b) - 1.8*(5)

3.6b - 9

Answer:

A.

Step-by-step explanation:

4y = 12x + 16

3x = y - 4

=>

y = 3x + 4

using that in the first equation

4(3x+4) = 12x + 16

12x + 16 = 12x + 16

=> both lines/equations are identical, so they have infinitely many solutions.

Answer: 3172

Step-by-step explanation:

Answer:

1/3 fraction of whole paint is used by mark

Step-by-step explanation:

Mark used  1/2 out of 3/2 cans.

[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}[/tex]

Answer:

56 different outfits

Step-by-step explanation:

Given:

The limit problem is:

[tex]lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}[/tex]

To find:

The value of the given limit problem.

Solution:

We have,

[tex]lim_{x\to -5}\dfrac{\dfrac{1}{5}+\dfrac{1}{x}}{10+2x}[/tex]

It can be written as:

[tex]=lim_{x\to -5}\dfrac{\dfrac{x+5}{5x}}{2(5+x)}[/tex]

[tex]=lim_{x\to -5}\dfrac{x+5}{5x}\times \dfrac{1}{2(5+x)}[/tex]

[tex]=lim_{x\to -5}\dfrac{1}{5x\times 2}[/tex]

[tex]=lim_{x\to -5}\dfrac{1}{10x}[/tex]

Applying limit, we get

[tex]lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{10(-5)}[/tex]

[tex]lim_{x\to -5}\dfrac{1}{10x}=\dfrac{1}{-50}[/tex]

Therefore, the value of given limit problem is [tex]-\dfrac{1}{50}[/tex].

Answer:

$29.69

Step-by-step explanation:

23.52 * 1.1 = $25.872 so this is the marked up price. ----- (1.1 = 110%)

25.872 * 0.1475 = $3.81612  is the sales tax.

Total is 25.872 + 3.81612  ~ $29.69

Answer:

Step-by-step explanation:

x : 100 = 7740 : 98 000 000

x = (7740 * 100)/98 000 000

x = 0.007898 %

A percentage is a hundredth of a number      Then                                                    [tex]\displaystyle\bf \frac{7740}{98\cdot10^6} \cdot100=\frac{387}{49000} \approx 0,00789\%[/tex]                                                      

Answer:

[tex]Height = 12cm[/tex]

Step-by-step explanation:

Given

[tex]Volume = 1200cm^3[/tex]

The dimension of the base is:

[tex]Base =10cm[/tex]

[tex]Sides = 13cm[/tex]

See comment for complete question

Required

The height of the base

To do this, we make use of Pythagoras theorem where:

[tex]Sides^2 = (Base/2)^2 + Height^2[/tex]

So, we have:

[tex]13^2 = (10/2)^2 + Height^2[/tex]

[tex]13^2 = 5^2 + Height^2[/tex]

[tex]169 = 25 + Height^2[/tex]

Collect like terms

[tex]Height^2 = 169 - 25[/tex]

[tex]Height^2 = 144[/tex]

Take square roots of both sides

[tex]Height = 12cm[/tex]

Answer:

36.7

Step-by-step explanation:

180 - 102.9 - 40.4= 36.7

The measure of the third angle of the given triangle after applying the angle sum property of a triangle is 36.7 degrees.

The measures of the two angles of a triangle are 102.9 and 40.4.

We need to find the measure of the third angle.

The angle sum property of a triangle states that the sum of all three interior angles of a triangle is 180 degrees.

If A, B, and C are the interior angles we have,

A + B + C = 180.

Consider the three interior angles to be A, B, and C.

We are given two angles 102.9 and 40.4.

Let  A = 102.9,  B = 40.4.

and C = angle to be measured.

Now,

Applying the angle sum property of a triangle.

We have,

A + B + C = 180

102.9 + 40.4 + C = 180

143.3 + C = 180

C = 180 - 143.3

C = 36.7 degrees.

After applying the angle sum property of a triangle we got the measure of the third angle as 36.7 degrees.

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Answer:

See step by Step

Step-by-step explanation:

Both are correct. As long as we undo the operations that was given from the original term to both sides until we get the variable by itself., any way can be applied.

Both, Spencer and Jeremiah are correct. We can verify this by testing their methods.

Spencer's method:

[tex]6x - 2 = - 4x + 2[/tex]

[tex]6x - 2 + 4x= - 4x + 2 + 4x[/tex]

[tex]10x - 2 = 2[/tex]

[tex]10x = 2 + 2[/tex]

[tex]10x = 4[/tex]

[tex]x = \frac{4}{10} [/tex]

[tex]x = 0.4[/tex]

Jeremiah's method:

[tex]6x - 2 = - 4x + 2[/tex]

[tex]6x - 2 - 6x = - 4x + 2 - 6x[/tex]

[tex] - 2 = - 10x + 2[/tex]

[tex] - 2 - 2 = - 10x[/tex]

[tex] - 4 = - 10x[/tex]

[tex] \frac{ - 4}{ - 10} = x[/tex]

[tex]0.4 = x[/tex]

As seen, we get the correct answer by using Spencer's and Jeremiah's method. So, we can say that they both are correct.

Answer:

160°

Step-by-step explanation:

Let one angle be x

Let second angle be 8x

Sum of supplementary angles = 180°

x+ 8x = 180°

9x = 180

x = 180/9 = 20

First angle= x= 20°

Second angle = 8x = 8*20 = 160°

Answer:

28

Step-by-step explanation:

Answer:

Area=7850 cm

Step-by-step explanation:

Since the formula for area is A=c(radius squared), we need to plug in the radius first. 50x50=2500. We can identify 'pi' as 3.14 and use that decimal instead of a longer one. The product of 2500 and 3.14 is 7850. Therefore, your answer is 7850 cm

Answer:

The answer is C 100πcm^3

Hello,

[tex](211)_x=(10110)_2\\\\2*x^2+x+1=22\\\\2x^2+x-21=0\\\Delta=1+4*2*21=169=13^2\\x=\dfrac{-1+13}{4}= 3\\or\\x=\dfrac{-1-13}{4}\ may\ not\ be\ negative\\\\[/tex]

x=3

Answer:

D. 160

Step-by-step explanation:

Answer:

Step-by-step explanation:

as angles of two triangles are equal, so they are similar.

x/17 =35/14=40/16

x/17=35/14

x=35/14×17=85/2=42.5

perimeter of ΔJKL=40+35+42.5=117.5

find the DB =[tex]\displaystyle\bf \sqrt{17^2-8^2} =15[/tex]  ; now find AD=AB-DB=21-15=6  .Then                AC=[tex]\displaystyle\bf \sqrt{AD^2+CD^2} =\sqrt{6^2+8^2} =10[/tex]  

Answer:

C

Step-by-step explanation:

Using Pythagoras' identity in both right triangles

To find BD

BD² + CD² = BC²

BD² + 8² = 17²

BD² + 64 = 289 ( subtract 64 from both sides )

BD² = 225 ( take the square root of both sides )

BD = [tex]\sqrt{225}[/tex] = 15

Then

AD = AB - BD = 21 - 15 = 6

To find AC

AC² = AD² + CD²

AC² = 6² + 8² = 36 + 64 = 100 ( take the square root of both sides )

AC = [tex]\sqrt{100}[/tex] = 10 → C

Answer: 68

Step-by-step explanation: Complementary angles are angles that add up to 90. So, you need to do 90-22=68.

Answer:

D.

Step-by-step explanation:

.

Answer:

20 Lines

Step-by-step explanation:

According to the Question,

Now,  the total pairs of points which can be formed is 9

And, the line passing through 2 such points 9c2 = 9! / (2! x 7!) = 9x4 ⇒ 36

Here, We have overcounted all of the lines which pass through three points.

And, each line that passes through three points will have been counted 3c2 = 3! / 2! ⇒ 3 times

Now, the sides of the square consist of 3 points. We have counted each side thrice, so 4*2 are repeated.