Answer:
a) 2 nonsingular 2 by 2 matrices are not closed when added together hence it is not a vector space( i.e. their sum = singular and not nonsingular )
b) 2 singular 2 by 2 matrices is not closed under addition, hence they are not a vector space. ( i.e. their sum = nonsingular )
Step-by-step explanation:
a) Prove that nonsingular 2 by 2 matrices is not a vector space
2 nonsingular matrices are not closed when added together hence it is not a vector space ( i.e. their sum = singular and not nonsingular )
vector A = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] + vector B = [tex]\left[\begin{array}{ccc}0&1\\1&0\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&1\\1&1\\\end{array}\right][/tex] ( singular vector )
b) Prove that singular 2 by 2 matrices is not a vector space
2 singular 2 by 2 matrices is not closed under addition, hence they are not a vector space. ( i.e. their sum = nonsingular )
Vector C = [tex]\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right][/tex] + vector D = [tex]\left[\begin{array}{ccc}0&0\\0&1\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] ( nonsingular vector )
what is the value of a+bc when a=4, b=6 and c =2? also please include how to do it step by step :)
Answer:
16
Step-by-step explanation:
a+bc
a+(b×c)
4+(6×2)
4+12
answer=16
Jesse takes two data points from the weight and feed cost data set to calculate a slope, or average rate of change. A hamster weighs half a pound and costs $2 per week to feed, while a Labrador Retriever weighs 62.5 pounds and costs $10 per week to feed. Using weight as the explanatory variable, what is the slope of a line between these two points? Answer choices are rounded to the nearest hundredth.
a. $0.13 / Ib.
b. $4.00 / Ib
c. $6.25 / Ib.
d. $7.75 / Ib.
Answer:
a. $0.13 / Ib.
Step-by-step explanation:
Slope of a line:
Suppose we have two data-points in a line. The slope is given by the change in the output divided by the change in the output.
In this question:
Input: weight(in pounds)
Output: Weekly cost to feed.
A hamster weighs half a pound and costs $2 per week to feed, while a Labrador Retriever weighs 62.5 pounds and costs $10 per week to feed.
Inputs: 0.5, 62.5
Outputs: 2, 10
Change in the outputs: 10 - 2 = 8
Change in the inputs: 62.5 - 0.5 = 62
Slope: [tex]m = \frac{8}{62} = 0.13[/tex]
So the correct answer is given by option A.
Answer:
0.13
Step-by-step explanation:
50 points!
What is the area of triangle xyz? Use special right triangles to help find the height. Leave your answer in terms of radical. Show work.
Find the zeros of the quadratic function: y = 6x2 + x – 35.
The zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3
How to determine the zeros?The function is given as:
y = 6x^2 + x - 35
Expand the function
y = 6x^2 + 15x - 14x - 35
Factorize the function
y = (2x + 5) * (3x - 7)
Set the function to 0
(2x + 5) * (3x - 7) = 0
Split
2x + 5 = 0 or 3x - 7 = 0
Solve for x
x = -2.5 or x = 7/3
Hence, the zeros of the quadratic function: y = 6x^2 + x – 35 are x = -2.5 or x = 7/3
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Four students want to have their picture taken together. They will stand side-by-side for the picture. In how many different ways can the four students be arranged to take a picture?
Show your work, please :')
Answer:
24 waysStep-by-step explanation:
This is the permutation of 4:
4P4 = 4! = 1*2*3*4 = 24 ways[tex]\huge\qquad \mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}[/tex]
✶⊶⊷⊶⊷❍❁❥❀❥❁❍⊶⊷⊶⊷✶
Four students want to have their picture taken together. They will stand side-by-side for the picture. In how many different ways can the four students be arranged to take a picture
so we have to find the permutation of 4
4×3×2×124.°. In 24 different ways can the four students be arranged to take a picture
Assume that you purchased a new car today and financed $55,000 of the price on a 72-month payment contract with a nominal rate of 6.00%. Further, assume that you plan on paying off the balance of the car loan after you make your 48th payment. How much will your loan balance be when you pay off the car?
Answer:
The amount that your loan balance will be when you pay off the car is $20,566.18.
Step-by-step explanation:
Step 1. Calculation of monthly payment
This can be calculated using the formula for calculating the present value of an ordinary annuity as follows:
PV = P * ((1 - (1 / (1 + r))^n) / r) …………………………………. (1)
Where;
PV = Present value or the cost of the new car = $55,000
P = Monthly payment = ?
r = Monthly nominal rate = Nominal rate / 12 = 6% / 12 = 0.06 / 12 = 0.005
n = number of months = 72
Substitute the values into equation (1) and solve for P, we have:
$55,000 = P * ((1 - (1 / (1 + 0.005))^72) / 0.005)
$55,000 = P * 60.3395139355201
P = $55,000 / 60.3395139355201 = $911.51
Step 2. Calculation of the loan amount balance when you pay off the car
This can be calculated using the ballon payment formula as follows:
P = (PV - (Ballon / (1 + r)^n)) * (r / (1 – (1 + r)^-n)) ...................... (1)
Where:
P = Monthly payment = $911.51
PV = Present value or the cost of the new car = $55,000
Ballon = Ballon payment or the loan amount balance when you pay off the car = ?
r = Monthly nominal rate = Nominal rate / 12 = 6% / 12 = 0.06 / 12 = 0.005
n = number months to pay off the loan amount balance = 48
Substituting the values into equation (1) and solve for Ballon, we have:
911.51 = (55,000 - (Ballon / (1 + 0.005)^48)) * (0.005 / (1 - (1 + 0.005)^-48))
911.51 = (55,000 - (Ballon / 1.27048916109538)) * 0.0234850290479363
911.51 / 0.0234850290479363 = 55,000 - (Ballon / 1.27048916109538)
38,812.39 = 55,000 - (Ballon / 1.27048916109538)
Ballon / 1.27048916109538 = 55,000 - 38,812.39
Ballon / 1.27048916109538 = 16,187.61
Ballon = 16,187.61 * 1.27048916109538
Ballon = $20,566.18
Therefore, the amount that your loan balance will be when you pay off the car is $20,566.18.
Can someone please answer this ASAP?
Answer:
Letter C
Step-by-step explanation:
Given:
[tex]5a+18<-27[/tex]
Subtract 18 from both sides
[tex]5a<-45[/tex]
Divide 5 from both sides to get [tex]a[/tex] alone
[tex]a<-9[/tex]
Letter C is the correct answer choice because the dot is at -9, the arrow is facing to the left, and the dot is open indicating that it's not greater/less than ""or equal to"".
Hope this is helpful
1/3(-15 divide 1/2) 1/4 what does it equal
Answer:
-2.5 or - 2 1/2
Step-by-step explanation:
Writing out the expression Mathematically ;
1/3(-15÷1/2)1/4
Using PEMDAS :
Solving the bracket first
(-15 ÷ 1/2) = (-15 * 2/1) = - 30
We have :
1/3(-30)1/4 = - 10 * 1/4 = - 10 / 4 = - 2.5
-2.5 = - 2 1/2
If P = (7,-4), Find:
(180° (P)
([?], []
Enter
Step-by-step explanation:
the answer is in the above image
help with algebra 1 equation pls help
Answer:
b. [tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]
Step-by-step explanation:
[tex] l = 14j + 3k [/tex]
Switch sides.
[tex] 14j + 3k = l [/tex]
Subtract 14j from both sides.
[tex] 3k = l - 14j [/tex]
Divide both sides by 3.
[tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]
A, B, and C are collinear points:
B is between A and C.
If AB = 3x + 4, BC = 4x - 1, and AC = 6x + 5,
find AC.
9514 1404 393
Answer:
AC = 17
Step-by-step explanation:
The segment sum theorem tells you ...
AB +BC = AC
Substituting the given expressions, we have ...
(3x +4) +(4x -1) = (6x +5)
x = 2 . . . . . . . . . . . . . . . . . . subtract 3+6x from both sides
AC = 6x +5 = 6(2) +5
AC = 17
_____
AB = 10, BC = 7
What are some easy ways to find the value of
(2017^4−2016^4)/(2017^2+2016^2) without calculator
Answer:
4033
Step-by-step explanation:
An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:
a^2 = 2017^4
a = 2017^2
b^2 = 2016^4
b = 2016^2
Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:
[tex]\frac{(2017^2+2016^2)(2017^2 - 2016^2)}{2017^2+2016^2}[/tex]We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by [tex]\frac{2017^2+2016^2}{2017^2+2016^2}[/tex] which is just one, and will simplify the fraction to just:
2017^2 - 2016^2
This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:
(2017 + 2016)(2017 - 2016)
And, without using a calculator, this is easy to simplify:
(4033)(1)
4033
Which of the following is the equation of a line in slope-intercept form for a
line with slope = and yintercept at (0, -1)?
O A. y - x-
1
B. y = 4x-1
O c. y= |x-1
O D. y=x+1
Answer:
y=1/4x - 1
Step-by-step explanation:
going off of the picture, I'd say this is your answer
The angles of a quadrilateral are 2x , 3x , 7x , and 8x find x
Answer:
x = 18
Step-by-step explanation:
The sum of the angles in a quadrilateral is 360
2x + 3x + 7x + 8x = 360
Combine like terms
20x = 360
Divide both sides by 20
x = 18
A sports trainer has monthly costs of $80 for phone service and $40 for his website and advertising. In addition he pays a $15 fee to the gym for each session in which he works with a client.
Required:
a. Write a function representing the average cost
b. Find the number of sessions the trainer needs if he wants the average cost to drop below $16 per session.
Answer:
Step-by-step explanation:
The average cost for the training session provided he is a sports trainer can be computed as follows:
Let's assume that;
average cost = C(x)
the no. of session = x
Then:
[tex]C(x) = \dfrac{\text{Total cost}}{\text{no. \ of sessions}}[/tex]
[tex]C(x) = \dfrac{\text{80 + 40 + 15x}}{\text{x}}[/tex]
[tex]C(x) = \dfrac{\text{120+ 15x}}{\text{x}}[/tex]
Now, suppose the trainer wants the average cost C(x) to drop below $16;
Then, we have the following function:
[tex]\dfrac{120+15x}{x}\leq C(x)[/tex]
[tex]\dfrac{120+15x}{x}\leq16[/tex]
By cross multiply:
120 + 15x ≤ 16x
120 ≤ 16x - 15x
120 ≤ x
Therefore, the required no. of session, if the average cost should drop below $16, is 120.
Following are the solution to the required points:
Assuming that he's also a sports trainer, the typical cost of such a training program is just as follows:Total cost = C(x)
Total session = x
Then:
[tex]\to C(x)=\frac{\text{Total cost}}{\text{Total sessions}}=\frac{80+40+15x}{x}= \frac{120+15x}{x}[/tex]
Assume the trainer desires that the average cost C(x) be less than $16. So function is therefore available:[tex]\to \frac{120+15x}{x} \leq C(x)\\\\\to \frac{120+15x}{x} \leq 16\\\\[/tex]
By cross multiply:
[tex]\to 120 + 15x \leq 16x\\\\\to 120 \leq 16x - 15x\\\\ \to 120 \leq x[/tex]
As a result, if the average cost drops below $16, the required number of sessions is 120.
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HW HELP ASAP PLZZZZZ
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (x - 5)(x - 4) }}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\blue{Step-by-step\:explanation}}{\blue{:}}}}}[/tex]
[tex] {x}^{2} - 9x + 20[/tex]
[tex] = {x}^{2} - 4x - 5x + 20[/tex]
Taking "[tex]x[/tex]" as common from first two terms and "[tex]5[/tex]" from last two terms, we have
[tex] = x(x - 4) - 5(x - 4)[/tex]
Taking the factor [tex](x-4)[/tex] as common,
[tex] = (x - 5)(x - 4)[/tex]
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]
Use the formula v = IR for current flowing through a resistor, where V is the voltage in volts, I is current in amps, and R is resistance in ohms. Find the current through a resistor with resistance 15 ohms if the voltage across it is 3 volts.
Answer:
0.2 amps
Step-by-step explanation:
Given data
The formula V=IR is the formula for ohms law
Which state that the voltage is directly proportional to the current and the resistance in an electric circuit
Now
R= 15 ohms
V= 3volts
V= IR
3= I*15
I= 3/15
I= 0.2 amps
Hence he current flowing is 0.2 amps
PLS HELP! The picture is down below
PLEASE ANSWER MAKE SURE YOU ARE RIGHT PLEASE I WILL MARK AS BRAINIEST
FIND THE VOLUME OF THE SPHERE
Answer:
Step-by-step explanation:
r = 1/2 unit
[tex]Volume= \frac{4}{3}\pi r^{3}\\\\=\frac{4}{3}\pi *\frac{1}{2}*\frac{1}{2}*\frac{1}{2}\\\\=\frac{1}{3}*\pi *\frac{1}{2}\\\\=\frac{1}{6}\pi[/tex]
What's the area of the trapezoid
Answer:
i dont know just study hard bro
Step-by-step explanation:
Answer:
A =36 ft^2
Step-by-step explanation:
The area of a trapezoid is given by
A = 1/2 ( b1+b2)h where b1 and b2 are the lengths of the bases
A = 1/2 ( 13+5) *4
A = 1/2 ( 18)*4
A =36 ft^2
In practice, the most frequently encountered hypothesis test about a population variance is a _____. a. two-tailed test, with equal-size rejection regions b. two-tailed test, with unequal-size rejection regions c. one-tailed test, with rejection region in upper tail d. one-tailed test, with rejection region in lower tail
Answer:
c. one-tailed test, with rejection region in the upper tail.
Step-by-step explanation:
One tailed test is statistical test in which critical area of distribution is one sided and greater or less than certain value. One tailed test can be left or right sided depending on the population distribution. Rejection region of the one tailed test will determine whether to accept or reject the null hypothesis.
Question 31 of 50
An electrician charges (1) an initial fee of $20 and then $30 per hour. Which linear equation represents this if (h) represents hours?
f = 20h + 30
f=30h + 20
f = 50h
Answer:
ok so if it is 30 dollars per hour so 30h plus 20 so
f=30h+20
Hope This Helps!!!
Solve the system 6x -2y+z= -2 2x+ 3y - 3z =11 x+ 6y=31
Answer:
x = 1
y = 5
z = 2
Step-by-step explanation:
System of equations:
6x - 2y + z = -2
2x + 3y - 3z = 11
x + 6y = 31
Isolate one variable in any of the equations:
x + 6y = 31
x = 31 - 6y
Plug in this value for x in another equation:
6(31 - 6y) - 2y + z = -2
186 - 36y - 2y + z = -2
186 - 38y + z = -2
-38y + z = -188
z = -188 + 38y
Plug in these values in the remaining equation:
2(31 - 6y) + 3y - 3(-188 + 38y) = 11
62 - 12y + 3y + 564 - 114y = 11
626 - 12y + 3y - 114y = 11
626 - 9y - 114y = 11
626 - 123y = 11
-123y = -615
y = 5
Plug in value of y into our other answers to solve for x and z:
x = 31 - 6(5)
x = 31 - 30
x = 1
z = -188 + 38(5)
z = -188 + 190
z = 2
Check your work:
6x - 2y + z = -2
6(1) - 2(5) + 2 = -2
6 - 10 + 2 = -2
-4 + 2 = -2
-2 = -2
Correct!
*Note there are several ways to solve for these types of problems. I used substitution*
How many one-to-one functions are there from the set {A, B, C} to the set {x, y, z, t, w, k}?
Answer:
120 different one-to-one functions
Step-by-step explanation:
A one-to-one function means that each element from the domain can be mapped into only one element from the range (like for a typical function), and each element from the range can be mapped only once.
This means that, for two different inputs x₁ and x₂, we can't have:
f(x₁) = f(x₂)
Because that would mean that two different values of the domain are being mapped into the same element from the range.
Ok, now that we know this, let's count the number of possible "mappings" for each element in the domain.
For the first element, A, we have the options {x, y, z, t, w, k} (a total of 6 options).
For the second element, B, we will have an option less (because one was already taken) so here we have 5 options.
For the last element on the domain, C, there will be again an option less than in the previous case, so here we have 4 options.
The total number of combinations (each combination defines a different one-to-one function) is equal to the product between all the options for each case, then the total number of one-to-one functions is:
C = 6*5*4 = 120
There are 120 different one-to-one functions.
HELP FAST PLS
Factor x2 - 7x + 8.
O (X + 8)(x - 1)
O Prime
O (x - 3)(x - 1)
O (X + 8)(x + 1)
Solve the Inequality: [tex]\frac{b}{3} \geq -1[/tex]
[tex] \frac{b}{3} \geq - 1 \\ = 3 \times \frac{b}{3} \geq \times ( -1 ) \\ = b \geq3 \times ( - 1) \\ = b \geq - 3 \times 1 \\ \\ = b \geq - 3[/tex]
Step By Step Explanation:
Multiply both sides of the inequality by 3Reduce the numbers with the greatest common factor 3Multiplying a positive and a negative equals a negative Any expression multiplied by 1 remains the same ☆彡Hanna#CarryOnLearning
John throws a biased four-sided dice.
The probabilities of getting each number are summarised in the table below.
Number
1
2
3
4
Probability
0.2
x
0.2
0.2
Work out the probability that the dice lands on 2.
Answer:
0.4
Step-by-step explanation:
0.2+0.2+0.2=0.6
1.0-0.6=0.4
This isn't 0.2 like the others which is why it's a biased dice like it says.
Which graph represents the solution set of the compound inequality -4 s 3x-1 and 2x+4 518?
-10
-5
0
10
O
+
-10
-5
0
5
10
5
-10
0
5
10
+
-10
-5
0
10
Answer:
it's the first one where X is greater or equals to -1 and X is less or equals to positive 7
The compound inequality in x : -1 ≤ x ≤ 7
The correct graph is A .
Given, inequality: -4 ≤ 3x -1 and 2x + 4 ≤ 18 .
First inequality:
-4 ≤ 3x -1
Take -2 from RHS to LHS .
-4 + 1 ≤ 3x
-3 ≤ 3x
x ≥ -1
X will have values greater than equal to -1 .
Second inequality:
2x + 4 ≤ 18
take 4 from LHS to RHS.
2x ≤ 18 - 4
2x ≤ 14
x ≤ 7
x will have values less than equals to 7.
Combined result of both inequalities: -1 ≤ x ≤ 7 .Thus graph A is correct.
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Find the whole using the percent proportion. 70% of what number of hay bales is
63 hay bales?
Answer:
90
Step-by-step explanation:
Let the whole number be x.
100% is to x as 70% is to 63
100/x = 70/63
10/x = 10/9
10x = 90 * 10
x = 90
Answer: 90
Step-by-step explanation:
0.7x = 63, x = 63/0.7 = 90
Substance A decomposes at a rate proportional to the amount of A present. a) Write an equation that gives the amount A left of an initial amount A0 after time t. b) It is found that 8 lb of A will reduce to 4 lb in 4.6 hr After how long will there be only 1 lb left?
a) Choose the equation that gives A in terms of A0, t, and k, where k > 0.
b) There will be 1 lb left after 14 hr (Do not round until the final answer. Then round to the nearest whole number as needed.)
Answer:
(a) [tex]A = A_0 * e^{kt}[/tex]
(b) There will be 1lb left after 14 hours
Step-by-step explanation:
Solving (a): The equation
Since the substance decomposes at a proportional rate, then it follows the following equation
[tex]A(t) = A_0 * e^{kt}[/tex]
Where
[tex]A_0 \to[/tex] Initial Amount
[tex]k \to[/tex] rate
[tex]t \to[/tex] time
[tex]A(t) \to[/tex] Amount at time t
Solving (b):
We have:
[tex]t = 4.6hr[/tex]
[tex]A_0 = 8[/tex]
[tex]A(4.6) = 4[/tex]
First, we calculate k using:
[tex]A(t) = A_0 * e^{kt}[/tex]
This gives:
[tex]A(4.6) = 8 * e^{k*4.6}[/tex]
Substitute: [tex]A(4.6) = 4[/tex]
[tex]4 = 8 * e^{k*4.6}[/tex]
Divide both sides by 4
[tex]0.5 = e^{k*4.6}[/tex]
Take natural logarithm of both sides
[tex]\ln(0.5) = \ln(e^{k*4.6})[/tex]
This gives:
[tex]-0.6931 = k*4.6[/tex]
Solve for k
[tex]k = \frac{-0.6931}{4.6}[/tex]
[tex]k = -0.1507[/tex]
So, we have:
[tex]A(t) = A_0 * e^{kt}[/tex]
[tex]A(t) = 8e^{-0.1507t}[/tex]
To calculate the time when 1 lb will remain, we have:
[tex]A(t) = 1[/tex]
So, the equation becomes
[tex]1= 8e^{-0.1507t}[/tex]
Divide both sides by 8
[tex]0.125= e^{-0.1507t}[/tex]
Take natural logarithm of both sides
[tex]\ln(0.125)= \ln(e^{-0.1507t})[/tex]
[tex]-2.0794= -0.1507t[/tex]
Solve for t
[tex]t = \frac{-2.0794}{-0.1507}[/tex]
[tex]t = 13.7983[/tex]
[tex]t = 14[/tex] --- approximated