74.5kg
Step-by-step explanation:
(140kg ÷ 2 = 70kg) 70kg - 4.5kg = 65.5 (65.5 is raima's weight) 70kg +4.5kg = 74.5kg (74.5kg is sia's weight)
a, 0,03m3=............ dm3=...........cm3
Answer:
0.03 m³ = 30 dm³ = 30000 cm³
if A = 1 2 1 1 and B= 0 -1 1 2 then show that (AB)^-1 = B^-1 A^-1
help meeeee plessss
[tex]A = \begin{bmatrix}1&2\\1&1\end{bmatrix} \implies A^{-1} = \dfrac1{\det(A)}\begin{bmatrix}1&-1\\-2&1\end{bmatrix} = \begin{bmatrix}-1&1\\2&-1\end{bmatrix}[/tex]
where det(A) = 1×1 - 2×1 = -1.
[tex]B = \begin{bmatrix}0&-1\\1&2\end{bmatrix} \implies B^{-1} = \dfrac1{\det(B)}\begin{bmatrix}2&1\\-1&0\end{bmatrix} = \begin{bmatrix}2&1\\-1&0\end{bmatrix}[/tex]
where det(B) = 0×2 - (-1)×1 = 1. Then
[tex]B^{-1}A^{-1} = \begin{bmatrix}2&1\\-1&0\end{bmatrix} \begin{bmatrix}-1&1\\2&-1\end{bmatrix} = \begin{bmatrix}-1&3\\1&-2\end{bmatrix}[/tex]
On the other side, we have
[tex]AB = \begin{bmatrix}1&2\\1&1\end{bmatrix} \begin{bmatrix}0&-1\\1&2\end{bmatrix} = \begin{bmatrix}2&3\\1&1\end{bmatrix}[/tex]
and det(AB) = det(A) det(B) = (-1)×1 = -1. So
[tex](AB)^{-1} = \dfrac1{\det(AB)}\begin{bmatrix}1&-3\\-1&2\end{bmatrix} = \begin{bmatrix}-1&3\\1&-2\end{bmatrix}[/tex]
and both matrices are clearly the same.
More generally, we have by definition of inverse,
[tex](AB)(AB)^{-1} = I[/tex]
where [tex]I[/tex] is the identity matrix. Multiply on the left by A ⁻¹ to get
[tex]A^{-1}(AB)(AB)^{-1} = A^{-1}I = A^{-1}[/tex]
Multiplication of matrices is associative, so we can regroup terms as
[tex](A^{-1}A)B(AB)^{-1} = A^{-1} \\\\ B(AB)^{-1} = A^{-1}[/tex]
Now multiply again on the left by B ⁻¹ and do the same thing:
[tex]B^{-1}\left(B(AB)^{-1}\right) = (B^{-1}B)(AB)^{-1} = B^{-1}A^{-1} \\\\ (AB)^{-1} = B^{-1}A^{-1}[/tex]
Find the length of the third side. If necessary, round to the nearest tenth.
4
Submit Answer
Answer:
attempt 1 out of 2
PLS HELP ASAP
Answer:
5
Step-by-step explanation:
p=4 b=3 h=?
h²=p²+b²
=4²+3²
=16+9
h²=25
h=5
PLEASE HURRY!!!
Find the area of the region that is NOT shaded.
Answer: 122 square feet
Explanation:
The larger rectangle has area of 14*15 = 210 square feet.
The smaller rectangle has a horizontal dimension of 15-4 = 11 ft and its vertical dimension is 14-6 = 8 ft. Therefore, the area is 11*8 = 88 square feet.
The non-shaded region has area that is the difference of the two previous areas calculated earlier. So that would be 210-88 = 122 square feet
1. Sederhanakan dan nyatakan hasilnya dalam bentuk eksponen.
2. Nyatakan soal berikut dalam notasi ilmiah.
Answer:
>
Step-by-step explanation:
The roots of the quadratic function describing the relationship between number of products produced and overall profit margin are x=0 and 100. The vertex is (50,1000). The maximum profit of $ dollars is reached when items are produced. The first root tells us that the profit will be 0 when 0 products are produced. The second root says once 100 items are made, the company is no longer making any profit. (They do not have production capacity and have to outsource for anything over 50.)
Answer:
I assume that we want to complete the statement:
"The maximum profit of $__ dollars is reached when __ items are produced"
We know that the profit equation is defined between x = 0 and x = 100, which are the two roots of the equation (so the profit is equal to zero for x = 0 and for x = 100).
Then we can assume that the profit will be positive in this range.
Thus, the quadratic equation should have a negative leading coefficient, which would mean that the arms of the graph go downwards.
If this is the case, we know that the maximum will be at the vertex.
Here we know that the vertex is:
(50, 1000)
Where remember, x represents the number of items and y represents the profit.
So, given that the maximum is at the vertex, and we know that the vertex is (50, 1000) we can conclude that the maximum profit is $1000, and this happens when the number of produced items is 50.
Then the complete statement is:
"The maximum profit of $1000 dollars is reached when 50 items are produced"
Tricia starts school at 7:00 AM and has lunch at 12:00 PM. She wants to make sure she has something to eat in between. Determine what time she should eat her snack if she is to eat at exactly a time between starting school and eating lunch. (Hint: Set up a horizontal number line as a timeline.) A. A. 9:30 AM
B. 10:00 AM
C. 9:00 AM
D. 10:30 AM
Answer:
D) 9:00 am
Step-by-step explanation:
Because 9:00 is the midpoint of 7 and 12
Can you Help me on 23 ?
Answer:
x is 11
Step-by-step explanation:
[tex]{ \sf{ \sqrt{x + 5} - 3 = 1}} \\ { \sf{ \sqrt{x + 5} = 4 }} \\ { \sf{x + 5 = 16}} \\ { \sf{x = 11}}[/tex]
Answer:
[tex]x = 11[/tex]
Step-by-step explanation:
[tex] \sqrt{x + 5} −3=1[/tex]
[tex] \sqrt{x + 5} = 1 + 3[/tex]
[tex] \sqrt{ {x} + 5 } = 4[/tex]
[tex] \sqrt{x + {5}^{2} } = {4}^{2} [/tex]
[tex]x + 5 = 16[/tex]
[tex]x = 16 - 5[/tex]
[tex]x = 11[/tex]
Hope it is helpful....Una empresa de comunicaciones internacional ofrece paquete de servicios de internet por demanda y que incluye un cargo fijo mensual. Si el cargo fijo es de $8000 y el costo por MB consumido es de $ 34, entonces el costo por consumo de 512 Mb es de:
El costo por el consumo de 512 MB, con base en los cargos mencionados, es de $25408.
Cálculo del costo paso a paso.
Según los datos en el ejercicio, se puede identificar que el costo mensual debe contener el cargo fijo mensual ($8000), más los megabytes consumidos por $34, teniendo eso en cuenta, se puede generar la siguiente fórmula:
Costo por consumo = Cargo fijo mensual + MB * $34Donde:
MB = Megabytes consumidas.Si reemplazamos el valor de MB por la cantidad mencionada en el ejercicio (512 Mb), y el cargo fijo mensual ($8000) obtenemos:
Costo por consumo = $8000 + 512 * $34Costo por consumo = $8000 + $17408Costo por consumo = $25408Por lo tanto, el costo por consumo de 512 Mb es de $25408.
Si deseas ver ejercicios similares, revisa el enlace a continuación: https://brainly.com/question/12918169?referrer=searchResults
Find the measure of the indicated angle to the nearest degree
We know
[tex]\boxed{\sf cos\theta=\dfrac{B}{H}}[/tex]
[tex]\\ \sf\longmapsto cos\theta=\dfrac{8}{16}[/tex]
[tex]\\ \sf\longmapsto cos\theta=\dfrac{1}{2}[/tex]
[tex]\\ \sf\longmapsto cos\theta=cos60[/tex]
[tex]\\ \sf\longmapsto \theta=60[/tex]
Item 4
Ellie has 20 books on her shelf. Four of these books are nonfiction, and the rest are fiction.
What is the ratio of fiction books to nonfiction books on the shelf?
5:4
5:1
4:1
I don't know.
Answer:4:1 just taking to test as soon as you
Step-by-step explanation:
The ratio of fiction books to nonfiction books on the shelf is, 4
What is the ratio?A ratio in mathematics is a comparison of two or more numbers that shows how big one is in comparison to the other. The dividend or number being divided is referred to as the antecedent, while the divisor or number that is dividing is referred to as the consequent.
Given that,
Ellie has 20 books on her shelf
Four of these books are nonfiction
The rest are fiction
The ratio of fiction books to nonfiction books on the shelf = ?
The number of fiction books = ?
The number of fiction books = 20 - 4
= 16
Ratio = fiction/nonfiction
= 16/4
= 4
Hence, the ratio is 4
To know more about Ratio check:
https://brainly.in/question/7996583
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on the unit circle, which of the following angles has the terminal point coordinates of (\sqrt(2))/(2),-(\sqrt(2))/(2)
a)5pi/4
b)pi/4
c)3pi/4
d)7pi/4
Answer:
c)3pi/4
Step-by-step explanation:
What’s the answer to this question ?
Answer:
Step-by-step explanation:
[tex]\frac{3}{4} x \frac{8}{3} =2[/tex]
The polygons in each pair are similar. find the missing side length
If polygons are similar ratio of sides will be same
[tex]\\ \sf\longmapsto \frac{6}{14} = \frac{3}{x} \\ \\ \sf\longmapsto 6x = 14 \times 3 \\ \\ \sf\longmapsto 6x = 42 \\ \\ \sf\longmapsto x = \frac{42}{6} \\ \\ \sf\longmapsto x = 7[/tex]
What is the answer? Don’t give me 4.
Answer:
what?
Step-by-step explanation:
........................................................................
Geometry, please answer question ASAP
This is my last problem guys please help me
Answer:
Step-by-step explanation:
a) 9.5 feet above the ground
b) max height at of 34.5 feet 5 feet horizontal distance
c) 10.87 feet away
PLEASE HELP ME WITH THIS MATH QUESTION!
Answer:
C
Step-by-step explanation:
First, let's say 4³ is a and 5⁻² is b. We know that (a/b)ⁿ = aⁿ/bⁿ for any n, so
(a/b)⁵ = a⁵/b⁵
= (4³)⁵ /(5⁻²)⁵
Next, one power rule states that (4³)⁵ = 4 ⁽³ˣ⁵⁾ = 4¹⁵ and (5⁻²)⁵ = 5 ⁽⁻²ₓ⁵⁾=5⁻¹⁰, so
(4³)⁵ /(5⁻²)⁵ = 4¹⁵ / 5⁻¹⁰
Next, anything to a negative power (e.g. x⁻ⁿ) is equal to 1 over the absolute value of the power, so x⁻ⁿ = 1/xⁿ. Applying that here, we can say that
5⁻¹⁰ = 1/5¹⁰
4¹⁵ / 5⁻¹⁰ = 4¹⁵ / (1/5¹⁰) = (4¹⁵/1) / (1/5¹⁰) = 4¹⁵ * 5¹⁰
Complete the paragraph proof.
Given: and are right angles
Line segment A B is-congruent-to line segment B C Line segment B C is-congruent-to line segment A C
Prove: Line A R bisects Angle B A C
Answer:
wea did tha r come from??
Step-by-step explanation:
it is supposed to be d
Mr. Hamilton decorates his U.S. History classroom by putting up pictures of the presidents. The wall is 9.75 feet long. In the center, there is a window that is 5 ¾ feet long.
Each president's picture is 6 inches wide.
4. How would your answer change if the pictures were 10 inches wide? Explain.
Answer:
The number of pictures changes from 8 to 4.
Step-by-step explanation:
I assume the first question was the number of pictures that could be placed when the pictures are 6 inches wide.
Let's first answer the first question.
Wall length: 9.75 ft
Window: 5¾ ft = 5.75 ft
Available wall space for pictures:
9.75 ft - 5.75 ft = 4 ft
Now we convert 4 ft to inches.
1 ft = 12 inches
4 ft = 4 * 12 inches = 48 inches
There is 48 inches of wall space to place pictures that measure 6 inches each.
48 inches / 6 inches = 8
Originally, there is room for 8 pictures.
Question 4.
Each picture is 10 inches wide.
There is still 48 inches of wall space for the pictures.
48 inches / 10 inches = 4.8
There is room for 4.8 pictures. Since Mr. Hamilton will place only whole picture, he can only place 4 pictures now.
Answer: The number of pictures changes from 8 to 4.
The sale price for a jacket that regularly costs $102.00 is now $74.00. With sales tax, a customer pays $82.40.
a polynomial has been factored below but some constants are missing. 2x^3-8x^2-24x=ax(x+b)(x+c)
Answer:
The polynomial is 2x^3 - 8x^2 - 24x
And we can factor out a 2x from each of the three terms:
2x(x^2 - 4x - 12)
Lastly, factor the remaining quadratic:
2x(x+(-2))(x+6)
And we have our answer:
a=2
b=-2
c=6
Let me know if this helps!
Answer:
a =2, b =2, and c = -6
Step-by-step explanation:
We factor the polynomial and then see which value corresponds to what.
2x^3-8x^2-24x
As we see it, all terms are factorable by 2x. So if we take out 2x from every term, we get
2x(x^2 - 4x - 12)
Now we factor the quadratic, which we can do mentally to get
2x(x+2)(x-6)
ax(x+b)(x+c)
Comparing that to ax(x+b)(x+c), we can tell that a =2, b =2, and c = -6.
Miles is putting a fence around his garden. The total area of the garden is 4,864 square feet. The length of the garden is 152 feet. How many feet of fencing does he need to go around the whole garden?
Help pls!!
Fencing required to go around the whole garden = 368 feet
To calculate the fencing needed, given measures in the question,
Total area of the garden is 4864 square feet.Length of the garden is 152 feet.Since, area of a rectangular garden is given by the expression,
Area = Length × Width
4864 = 152 × Width
Width = [tex]\frac{4864}{152}[/tex]
= 32 feet
Since, length of the fence needed = Perimeter of the garden
And Perimeter of a rectangular garden is given by the expression,
Perimeter = 2(length + width)
By substituting the values of length and width of the garden in the expression,
Perimeter = 2(152 + 32)
= 368 feet
Therefore, 368 feet of the fence will be required to go around the whole garden.
Learn more,
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Q:1)A ball is thrown upwards and it goes to the height of 100meter and comes down. What is the net displacement?
Q:2)An athlete completes one round of a circular track of diameter 200m in 30 seconds. Find the distance covered by the athlete at the end of 30 second.
$\sf\underline\bold{Question:1-}$
A ball is thrown upwards and it goes to the height of 100meter and comes down. What is the net displacement?
$\sf\underline\bold{Solution}$
$\sf{According \: to\:the\: question,}$
Displacement for the above situation is 0. As we know, that displacement is the shortest path from the initial to the final point. Here, the initial and the final points are the same, and henceforth, it takes no time to travel. So the displacement is 0.
_________________________$\sf\underline\bold{Question:2-}$
An athlete completes one round of a circular track of diameter 200m in 30 seconds. Find the distance covered by the athlete at the end of 30 second.
$\sf\underline\bold{Solution:}$
$\sf\bold{Given\:parameters:}$
$\sf\small{☆The\:diameter\:of\:the\:circular\:track:200m}$
$\sf{Radius=}$ $\sf\dfrac{200}{2}$ → $\sf\underline{Radius = 100m}$
☆Time taken by an athlete to complete one round : 30 seconds.
$\space$
$\sf\bold{To\:find:}$
❍Distance travelled by an athlete in 30 seconds.
$\space$
❍ AND,Distance travelled by the athlete will be equal to the cumference of the circle.
$\space$
$\space$ $\space$ $\space$ $\space$ $\space$ $\space$ $\sf{So,}$
$\mapsto$ $\sf{Circumference\:of\:the\:circle: 2 πr}$
$\space$
$\mapsto$ $\sf{Circumference=2\times}$ $\sf\dfrac{22}{7}$ $\sf{\times 100}$
$\space$
$\mapsto$ Circumference of the circle : $\sf\dfrac{4400}{7}$
$\space$
[tex]\sf\underline\bold{∴Circumference = 628.57m}[/tex]
$\space$
||Therefore,The distance travelled in 30 seconds, by the athlete is 628.57m.||
______________________0 = 1st answer
628.57 m = Question 2 answer.
what is the equation of the line that passes through the points (-8,8) and (4,-1)
Answer:
y = (-3/4)x + 2
Step-by-step explanation:
Find the slope of this line. Note how the first x-coordinate (-8) becomes 4, a jump of 12, and how the first y-coordinate (8) becomes -1, a decrease of 9. Then the slope is
m = (change in y) / (change in x) = -9/12 = m = -3/4
Find the y-intercept from this data using the slope-intercept form:
y = mx + b becomes 8 = (-3/4)(-8) + b when x = -8, y = 8 and m = -3/4.
Solving this equation for b, we get:
8 = 6 + b, so that b must be 2.
The desired equation is y = (-3/4)x + 2.
Divide. Write your answer as a fraction in simplest form.
−1/5÷20=
Answer:
-1/100
Step-by-step explanation:
Answer:-1/100
Step-by-step explanation:
A telephone long distance carrier charges customers $0.99 for the first 10 minutes and then $0.09 for each minute beyond 10 minutes. If Mary uses this carrier, how long can she talk for $5.00
Answer:
5 minutes
Step-by-step explanation:
5 * $0.99 = $4.95
Calculate the mode of: 4.6, 3, 8.1, 9, 12, 3, 9, 3.5, 7, 3.
Answer:
the Mode Is 3
Step-by-step explanation:
You Have To Put the numbers from ascending order to descending order..The Numbers that appears the most is the mode
find the surface area of this cylinder??
Answer:
4
Step-by-step explanation:
A=ch
then,
2ft×2ft
4ft
x-1 = [tex]\sqrt{x} -1[/tex]
Answer:
[tex]x = 0[/tex] or [tex]x = 1[/tex].
Step-by-step explanation:
Start by adding [tex]1[/tex] to both sides of this equation:
[tex](x - 1) + 1 = (\sqrt{x} - 1) + 1[/tex].
[tex]x = \sqrt{x}[/tex].
If two numbers are equal, their square should also be equal. Therefore, since[tex]x = \sqrt{x}[/tex], it must be true that [tex]x^{2} = (\sqrt{x})^{2}[/tex]. That is: [tex]x^{2} = x[/tex].
Notice that since [tex]x[/tex] is under a square root, the result must ensure that [tex]x \ge 0[/tex].
Subtract [tex]x[/tex] from both sides of the equation:
[tex]x^{2} - x = x - x[/tex].
[tex]x^{2} - x = 0[/tex].
Factor [tex]x[/tex] out:
[tex]x\, (x - 1) = 0[/tex].
Hence, by the Factor Theorem, [tex]x = 0[/tex] and [tex]x = 1[/tex] would satisfy this rearranged equation. Because of the square root in the original equation, these two value must be non-negative ([tex]x \ge 0[/tex]) to qualify as actual roots of that equation.
In this example, both [tex]x = 0[/tex] and [tex]x = 1[/tex] qualify as roots of that equation.
x-1 = \sqrt{x} -1
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