Answer:
Explanation:
Football and badminton enquire you use your lems and you would need equipment
Football and badminton enquire you use your legs and you would need equipment.
What are the similarities between badminton and tennis?Similarities of Tennis & Badminton both are racket sports. both video games consist of a net in which the ball/shuttlecock needs to be hit over the internet to the opponent's court which will win the point. Both video games have guys singles, guys doubles, girls singles, girls doubles, and combined doubles categories.
Each game and sports activities have hard and fast policies, which ensure honest opposition. they may involve teams or individual competitions. Human beings play video games and sports for activity and amusement, but in addition, they benefit from numerous skills and understanding via video games and sports activities.
While soccer is played through feet, handball is a game played by using hand. Both sports have some similarities which consist of the function of the goalkeeper who can play with ft and arms in the strive of saving the ball from attaining the purpose.
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Atoms of which pair of elements will form ionic bonds in a compound?
A.
Ti and Ni
B.
Ti and O
C.
Cl and Br
D.
P and Cl
Answer:
Ti and O
Explanation:
It is what it is.
Answer:
B. Ti and O
Explanation:
A.P.E.X
Observer A, who is at rest in the laboratory, is studing a particle that is moving through the laboratory at a speed of 0.624c and determines its lifetime to be 159ns a) Obsever A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory? b) Obsever B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
Answer:
a) the markers are 29.76 m far apart in the laboratory
b) According to B, the markers are 23.21 m far apart in the laboratory
Explanation:
Given that;
speed of particle = 0.624c = (0.624 × 3×10⁸m/s)
{ where c is the speed of light}
lifetime of the particle t = 159ns = 1.59 × 10⁻⁷
a) Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory
lets apply the formula distance = velocity × time
lets substitute
distance = (0.624×3×10⁸ m/s) × (1.59 × 10⁻⁷ s)
distance = 29.76 m
Therefore, the markers are 29.76 m far apart in the laboratory
b) Observer B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?
lifetime of the particle t = 124ns = 1.24 × 10⁻⁷
distance = (0.624×3×10⁸ m/s) × (1.24 × 10⁻⁷ s)
distance = 23.21 m
Therefore, According to B, the markers are 23.21 m far apart in the laboratory
Three point charges are fixed in place in a right triangle, as shown in the figure.
What is the magnitude of the electric force on the +1.00-C charge due to the other two charges?
What angle does the force make with the -x-axis? A positive angle is counterclockwise from the -x-axis.
For the three-point charges fixed in a right triangle, we have:
1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.
2. The force does an angle of 21.68° with the x-axis.
1. Magnitude of the electric forceFirst, let's denote the charges as is shown in the picture below:
q₁: is the charge 1 = +0.800 μC = +0.800x10⁻⁶ Cq₂: is the charge 2 = +1.00 μC = +1.00x10⁻⁶ Cq₃: is the charge 3 = -0.600 μC = -0.600x10⁻⁶ C
The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:
[tex]|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}[/tex] (1)
Where:
[tex]\Sigma\vec{F}_{x}[/tex]: is the sum of the forces acting on the x-axis[tex]\Sigma\vec{F}_{y}[/tex]: is the sum of the forces acting on the y-axisWe can calculate the electrical forces with Coulomb's law:
[tex]\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}[/tex]
Where:
K is the Coulomb's constant = 9.00x10⁹ Nm²/C² q₁ and q₂ are the chargesd is the distance between the charges
Forces in the x-axis ([tex]\Sigma\vec{F}_{x}[/tex])
The forces in the x-component are given by:
[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}[/tex]
[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}[/tex]
[tex]\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}[/tex] (2)
Where:
θ: is the angle of the force F₂₁ with the x-axisd₁₂ = z = 9.60 cm = 0.0960 m d₂₃ = xWe can calculate the angle θ with the following trigonometric function:
[tex]sin(\theta) = \frac{y}{z}[/tex]
[tex]\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ[/tex]
To find the distance x (d₂₃), we need to use Pythagoras:
[tex]x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m[/tex]
After entering θ and x (d₂₃) into equation 2, we have:
[tex]\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}[/tex]
[tex]\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N[/tex]
Hence, the x-component of the force is -1.66 N.
Forces in the y-axis ([tex]\Sigma\vec{F}_{y}[/tex])
The only force acting on the y-axis is the y-component of the force F₂₁, so:
[tex]\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)[/tex]
The minus sign is because the vector is pointing in the negative y-direction (see the picture below).
[tex]\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N[/tex]
Hence, the y-component of the force is -0.66 N.
Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):
[tex]|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N[/tex]
Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.
2. Direction of the force with the x-axisAccording to the picture below, the angle of the force with respect to the x-axis is given by:
[tex]tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}[/tex]
[tex]\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ[/tex]
Therefore, the force does an angle of 21.68° with the x-axis.
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1) A spring, which has a spring constant k=7.50 N/m, has been stretched 0.40 m from ts equilibrium position . What the potential energy now tored in the spring ?
[tex]\displaystyle U_s = 0.6 \ J[/tex]
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightPhysics
Energy
Elastic Potential Energy: [tex]\displaystyle U_s = \frac{1}{2} k \triangle x^2[/tex]
U is energy (in J)k is spring constant (in N/m)Δx is displacement from equilibrium (in m)Explanation:Step 1: Define
k = 7.50 N/m
Δx = 0.40 m
Step 2: Find Potential Energy
Substitute in variables [Elastic Potential Energy]: [tex]\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.40 \ m)^2[/tex]Evaluate exponents: [tex]\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.16 \ m^2)[/tex]Multiply: [tex]\displaystyle U_s = (3.75 \ N/m) (0.16 \ m^2)[/tex]Multiply: [tex]\displaystyle U_s = 0.6 \ J[/tex]An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 1.0 cm, and the electric field within the capacitor has a magnitude of 2.9 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate
Answer:
K = 4.64 10⁻¹⁵ J
Explanation:
For this exercise we can use conservation of energy
starting point. Next to the negative plate
Em₀ = U = e V
final point. Right when you hit the positive plate
Emf = K = ½ m v²
energy is conserved
Em₀ = Em_f
e V = K
The electric potential is related to the electric field
V = - Ed
we substitute
-e E d = K
let's calculate
K = -1.6 10⁻¹⁹ (-2.9 10⁶) 1.0 10⁻²
K = 4.64 10⁻¹⁵ J
A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is the initial height of the bob?
Answer:
h = 18.4 cm
Explanation:
Given that,
The speed of the bob at the bottom of the swing is 1.9m/s.
We need to find the initial height of the bob. Let it is h.
We can find it using the conservation of energy i.e.
[tex]mgh=\dfrac{1}{2}mv^2[/tex]
Where
v is speed of the bob
So,
[tex]h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m[/tex]
or
h = 18.4 cm
So, the initial height of the bob is 18.4 cm.
The initial height of bob will be "18.4 cm".
Speed and height:Speed would be the scalar quantity that describes "how quickly an attribute moves." This could sometimes be defined as this same rate whereby an object travels a given distance.
According to the question,
The speed of the bob = 1.9 m/s
Let,
The initial height be "h".
By using the conservation of energy, we get
→ mgh = [tex]\frac{1}{2}[/tex]mv²
or,
→ h = [tex]\frac{v^2}{2g}[/tex]
By substituting the values, we get
= [tex]\frac{(1.9)^2}{2\times 9.8}[/tex]
= 0.184 m or,
= 18.4 cm
Thus the above answer is correct.
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A 20.0 newton force is used to push a 2.00 kilogram cart a distance of 5.00 meters how much work is done on the cart
Answer:
100
w=f*s
20*5=100....
100 Joules of work is done on the cart.
What is Work done?Work done by a force is defined as the product of the displacement and the component of the applied force on the object in the direction of displacement. When we push a block with some force, the body moves with some acceleration, so it is called work done.
Work done is expressed as W=Fd and its unit is joules which can be defined as the amount of work done by a force in Newton is applied to an object, as a result of which it is displaced in meter.
For above given information,
Force= 20 N
Distance= 5 m
So, work done= 20*5= 100 Joules
Thus, 100 Joules of work is done on the cart.
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Problem 3 (a) Assuming the human body (skin temperature 34◦C) to behave like an ideal thermal radiator, find the wavelength where the intensity from the body is a maximum. In what region of the electromagnetic spectrum is radiation with this wavelength? (b) Making whatever (reasonable) assumptions you may need, estimate the power radiated by a typical person isolated from the surroundings. (c) Estimate the radiation power absorbed by a person in a room in which the temperature is 20◦C.
Answer:
Explanation:
a )
We shall apply Wein's displacement law
λm x T = b where λm is wavelength of radiation having maximum intensity
T is absolute temperature of body , and b is a constant
b = 2898 μm-K
T = 273 + 34 = 307 K
λm x 307 = 2898
λm = 9.44 μm
= 9440 nm
It is infrared radiation .
b )
We shall apply Stefan's law of radiation.
E = σA T⁴
E is emitted radiation by body acting as black body , A is surface area , T is absolute temperature of body
σ = 5.67 x 10⁻⁸ J / m²T⁴
Surface area of a typical man's body A = 1.9 m²
T = 273 + 34 = 307 K
Assuming human body as black body
E = 5.67 x 10⁻⁸ x 1.9 x 307⁴ J/s
= 9.57 x 10² J/s
= 957 W .
c )
Radiation absorbed
E = 5.67 x 10⁻⁸ x 1.9 x ( 273 + 20 )⁴ J/s
= 794 W .
what is a likely consequence of continued human population growth
Answer:
Rapid human population growth has a number of consequences. Population grows fastest in the world's poorest countries. High fertility rates have historically had a strong relation with poverty, and high childhood mortality rates
Explanation:
i got it from goo.gle but i hope that helps:)
have a good day bro
Which diagram is the best model for a solid?
Substance A
Substance B
О Substance C
Answer:
This link was diagram
Explanation:
https://doubtnut.app.link/FnsNC80Dccb
Can heating cooking oil you’ll be classified as producing a chemical change?
yes it is boiling creating bubbles that aren't their originally
Explanation:
When cooking oils are subjected to heat in the presence of air and water (from food), such as in deep-fat frying and sautéing (pan frying), they can undergo at least three chemical changes: 1) oxidation of the fatty acids, 2) polymerization of the fatty acids, and 3) breaking apart of the triglyceride molecules into free fatty acids and glycerol by hydrolysis (reaction with water from the food being cooked) (Choe and Min 2007)
Determine the position of a train moving at 45 m/s after 5 minutes.
The train has covered 13,500 meters of track.
We don't know its position, because we don't know where it started from, and we don't know how straight the track is.
A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted by the source?
Answer:
Please see below as the answer is self-explanatory.
Explanation:
The visible range extends roughly from 400 nm (violet) to 700 nm (red).Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.The wavelengths in the range of 650 to 690 nm have red as the dominant color.often occurs at subduction zones. Check all that apply:
O convergence
trench
upward convection currents in the mantle below it
Orifts
most volcanoes...Pacific Ring of Fire
continental plate subducts because it's less dense
Answer:
convergence and trench
Explanation:
LOL
The
principle which allows a rainbow to form is
Explanation:
A rainbow is a meteorological phenomenon that is caused by reflection, refraction and dispersion of light in water droplets resulting in a spectrum of light appearing in the sky. It takes the form of a multicoloured circular arc. Rainbows caused by sunlight always appear in the section of sky directly opposite the sun.
Hope it helps You °_°
When potassium chromate (K2CrO4) is added to a solution containing 0.500 g silver nitrate (AgNO3), solid silver chromate (Ag2CrO4) is formed. a) Determine the chromate precipitate
Answer:
OK id k the names of everything but the quantity would be around 2.22222222222222222222222222222222222222222222222222222222222222222222222222222 ok?
Explanation:
At the bottom of a mine shaft, the air
pressure is 138,000 Pa. How deep is
the mine?
(Unit = m)
1 atm = 101300 Pa
Pair = 1.29 kg/m3
Plz help
Answer:2900
Explanation:
I think
Question 11 (1 point)
Anytime there is height, the object must have...
a
kinetic energy
gravitational potential energy
GPE & KPE
C
Od
elastic potential energy
Answer:
gravitational potential energy.
Explanation:
Gravitational potential energy (GPE) can be defined as an energy possessed by an object or body due to its position above the earth surface.
Mathematically, gravitational potential energy is given by the formula;
[tex] G.P.E = mgh[/tex]
Where,
G.P.E represents gravitational potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
This ultimately implies that, anytime there is height, the object must have gravitational potential energy.
Hence, an object possesses gravitational potential energy due to its height (position) and the earth's gravitational force.
Define :density٬archimedes principle
Answer:
density is defined as the amount of mass contained in unit volume of a body .its si unit is kg/m*3
Answer:
Density is the amount of mass per unit volume of a substance.
Archimedes principle states that"When a body is totally or partially immersed in a liquid,it experience an upthrust which is equal to the weight of the liquid displaced"
Shine the flashlight on the liquid sheet. Did you observe evidence that light carries energy
Answer:
Think of an object you have observed ... Work with your group to gather evidence that light carries energy, then answer the questions below. Shine the flashlight on the liquid crystal sheet.
A rotating paddle wheel is inserted in a closed pot of water. The stirring action of the paddle wheel heats the water. During the process, 30 kJ of heat is transferred to the water and 5 kJ is lost to the surrounding air. The paddle wheel work amounts to 500 J. Determine the final energy of the system if its initial energy is 10 kJ.
Answer:
the final energy of the system is 35.5 kJ.
Explanation:
Given;
initial energy of the system, E₁ = 10 kJ
heat transferred to the system, q₁ 30 kJ
Heat lost to the surrounding, q₂ = 5kJ
heat gained by the system, Q = q₁ - q₂ = 30 kJ - 5kJ = 25 kJ
work done on the system, W = 500 J = 0.5 kJ
Apply first law of thermodynamic,
ΔU = Q + W
where;
ΔU is change in internal energy
Q is the heat gained by the system
W is work done on the system
ΔU = 25kJ + 0.5 kJ
ΔU = 25.5 kJ
The final energy of the system is calculated as;
E₂ = E₁ + ΔU
E₂ = 10 kJ + 25.5 kJ
E₂ = 35.5 kJ.
Therefore, the final energy of the system is 35.5 kJ.
image.
A concave lens always produces a(n)
A. inverted
o
B. real
C. virtual
D. magnified
Answer:
Explanation:
Its Virtual, how would you describe the image formed by a convex mirrior? virtual upright, smaller
help help help help help help help help help
A 2.70 kg book rests on an incline of 13.0. You give it a sharp push up the frictionless ramp. It comes to a stop in 25.25 at 17.5 m up the ramp before starting its descent(a) What is the magnitude of the normal force on the book
Answer:
the magnitude of the normal force on the book is 25.78N
Explanation:
The computation of the magnitude of the normal force on the book is shown below
Normal force = N is
= mgcosβ
= 2.70 × 9.8 × cos13°
= 25.78N
hence, the magnitude of the normal force on the book is 25.78N
The above formula should be applied
Use the graph one more time to help you with this question. Changes in both the North and South occurred due to the .
Answer:
industrial revolution
Explanation:
Need help guys please
Answer:
c is the answer,................
Explain temperature and how it is measured.
PLEASE PLEASE HELP ME!! I NEED IT AND PLEASE DO IT IN YOUR OWN WORDS!! PLEASE I JUST NEED IT!! OWN WORDS PLEASE!!
Answer:
temperature is the degree of heat in a item or object and is measured by a thermometer.
Explanation:
A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?
Answer:
1km west
Explanation:
Because if the cyclist is going back 2km then its 3-2=1km
what scale ranks minerals from softest to hardest
Answer: Mohs Scale
Explanation: Mohs Scale of Hardness
hope this helped!!!!!!!!!!!
When one person shouts at a football game, the sound intensity level at the center of the field is 69.6 dB. When all the people shout together, the intensity level increases to 103 dB. Assuming that each person generates the same sound intensity at the center of the field, how many people are at the game
Answer:
there are 2188 people at the game
Explanation:
Given the data in the question;
we know that decibel is defined as; dB = 10log(l/l₀)
so if one produces an intensity l₁, it results in 69.6 dB
69.6 = 10log(l₁/l₀) ---- equ1
also. if x number of people produces this intensity, it result to 103 dB
103 = 10log(xl₁/l₀)
103 = 10( log(l₁/l₀) + log(x) )
103 = 10log(l₁/l₀) + 10log(x) ----- equ2
input equation 1 into to equation 2
103 = 69.6 + 10log(x)
10log(x) = 103 - 69.6
10log(x) = 33.4
divide both side by 10
log(x) = 3.34
x = [tex]10^{3.34}[/tex]
x = 2187.76 ≈ 2188
Therefore, there are 2188 people at the game
