Answer:
since .875 > .857 Snail B is moving faster
Step-by-step explanation:
divide 6 by 7 to get the number of feet in one hour for Snail A
7 into 6 is .857
divide 7 by 8 to get the number of feet in one hour for Snail B
8 into 7 is .875
I believe the answer to this is:
Snail B went faster than Snail A.
Hope this helps! :D
Help with both please
Answer:
Step-by-step explanation:
12. To find the carpet needed. Find the area :
The figure is combination of semi circle and a rectangle.
So Area = Area of semi circle + Area of rectangle
[tex]Area \ of \ semi \ circle = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi \times 25 = 39.25 \ ft^2 \\\\Area \ of \ rectangle = Length \times Breadth = 15 \times 10 =150 \ ft^2[/tex]
Area = 150 + 39.25 = 189.25 sq ft
13. Cost per square feet = $$9.95
Therefore cost for 189.25 square feet = 9.95 x 189.25 = $1883.04
A school is tracking its freshmen attendance for the first marking period. Shown below is a table summarizing the findings for the 284 members of the freshmen class.
(a) Find the mean and median number of days absent Round your mean to the nearest tenth
(b) What proportion of the population that has an absenteeism greater than 4 days?
Answer:
The median number of days absent is zero (0)
The mean number of days absent is 1.0 day
(b) The proportion of the population that has absenteeism greater than 4 days is 6.34 %
Step-by-step explanation:
total number of students, n = 284
The total number of students is even, the median number of days absent will in (n/2).
n/2 = 284/2 = 142
The cumulative frequency that falls in 148 students = 0 day
The median number of days absent is zero (0)
For mean:
Let the days absent = x
let the number of students = f
[tex]mean (\bar x) = \frac{\sum fx}{\sum f}\\\\\bar x = \frac{(158\times 0)+ (64\times 1)+(18\times 2)+(22\times 3)+(4\times 4)+(5\times 7)+(6\times 8)+(9\times 2)+(13\times 1)}{284} \\\\\bar x = \frac{296}{284} \\\\\bar x = 1.0 \ day[/tex]
(b) the number of students with absenteeism greater than 4 dyas;
= 7 + 8 + 2 + 1
= 18
The proportion of these students;
[tex]= \frac{18}{284} \\\\= 0.0634 \\\\= 6.34 \ \%[/tex]
Using statistical concepts, it is found that:
a) The mean number of days absent is of 1, while the median is of 0.b) 0.0634 = 6.34% of the population has an absenteeism greater than 4 days.Mean and Median:The mean is given the sum of the multiplication of each value and it's number of observations, divided by the number of observations.The median is the number of days absent for which the sum of the number of students will be half of the total number, that is, half of 284, which is 142.Question a:
Then, the mean is:
[tex]M = \frac{0(158) + 1(64) + 2(18) + 3(22) + 4(4) + 5(7) + 6(8) + 9(2) + 13(1)}{284} = 1[/tex]
158 > 142, hence, the median is 0.
Question b:
In the sample, there are 284 students.Of those, 7 + 8 + 2 + 1 = 18 were absent four more than 4 days, hence:[tex]p = \frac{18}{284} = 0.0634[/tex]
0.0634 = 6.34% of the population has an absenteeism greater than 4 days.
To learn more about mean and median, you can take a look at https://brainly.com/question/24732674
Có bao nhiêu hoán vị {1.2….9} mà 4,5,6 không đứng cạnh nhau theo thứ tự tăng dần
Answer:
Yeah buddy
Step-by-step explanation:
Cabs here cabs here cabs here cabs here cabs here
Use the distributive property to find a equivalent expression for 6(x+4)
Answer:
6x +24
Step-by-step explanation:
you factor out the 6 so 6x and 6*4 is 24
please help (math) brainliest
Answer:
the answer is the first one
Có bao nhiêu hoán vị {1.2….9} mà 4,5,6 không đứng cạnh nhau theo thứ tự tăng dần
Answer: razon de ser
Step-by-step explanation:
Tu eres como agua Clara que lluvi del suelo
Use this table of values for the rate of rainfall over time.
Rate of Rainfall (mm per hour) Time 6:00 am 20 6.15 am 28 630 am 3.0 645 am 35 7:00 am 3.8 7:15 am 42 7:30 am 4.8 7:45 am 5.6 8:00 am 4.0 8.15 am 3.3 8:30 am 1.8 8:45 am 0.4 9:00 am 1.2.
An approximation of the total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is
a. 9.3 mm.
b. 9.6 mm.
Solution :
Here the subintervals of equal length will be :
[tex][6:00, 6:30], [6:30, 7:00], [7:00, 7:30], [7:30, 8:00], [8:00, 8:30], [8:30, 9:00][/tex]
So thee mid points are
[tex]x_1 = 6:15, \ x_2=6:45, \ x_3=7:15, \ x_4=7:45, \ x_5, 8:15, \ x_6 = 8:45[/tex]
The length of each sub-interval is = [tex]\frac{9-6}{6} = \frac{3}{6} = 0.5[/tex]
So, total amount of rainfall will be :
[tex]$=0.5 \sum^6_{i=1} f(x_i)$[/tex]
[tex]$=0.5\left( f(x_1)+f(x_2)+....+ f(x_6)\right)$[/tex]
= 0.5 (2.8 + 3.5 + 4.2 + 5.6 + 3.3 + 0.4)
= 0.5 (19.8)
= 9.9
The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.
Given that,
The rate of rainfall (mm per hour) over time.
Rate of rainfall;
6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00
Time
2.0 2.8 3.0 3.5 3.8 4.2 4.8 5.6 4.0 3.3 1.8 0.4 1.2
We have to determine,
0.4 9:00 am 1.2.
The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is?
According to the question,
Rate of rainfall;
6;00 6;15 6;30 6;45 7;00 7;15 7;30 7;45 8;00 8;15 8;30 8;45 9;00
Time
2.0 2.8 3.0 3.5 3.8 4.2 4.8 5.6 4.0 3.3 1.8 0.4 1.2
Here, the midpoints sum with 6 equal subintervals are,
[tex]\rm x_1 = 6;15, \ x _2 = 6;45, \ x_3 = 7;15, \ x_4 = 7;45, x_5 = 8;15 , \ x_6 = 8;45[/tex]
Then, the length of each subinterval is,
[tex]= \dfrac{9-6}{6}\\\\= \dfrac{3}{6}\\\\= \dfrac{1}{2}[/tex]
The total amount of rainfall that falls between 6;00 to 9;00 am using the midpoint subinterval is,
[tex]\rm = \dfrac{1}{2} \sum^{6}_{i=0} f(x_i)\\\\= \dfrac{1}{2} \sum^{6}_{i=0} f(x_1)+ f(x_2) + f(x_3) + f(x_4) +f(x_5)+f(x_6)\\\\= \dfrac{1}{2} (2.8+ 3.5+4.2+ 5.6+3.3+0.4}\\\\= \dfrac{1}{2} \times 19.8\\\\= 9.9[/tex]
Hence, The total amount of rainfall that falls between 6:00 a.m. and 9:00 a.m. using a midpoint sum with 6 equal subintervals is 9.9.
For more details refer to the link given below.
https://brainly.com/question/795909
Jackson is making brownies. He uses the following ingredients.
Ingredients Amount for 1
Batch of Brownies
Flour 3 cups
Sugar 2 cups
Butter 1/3 cup
Cocoa Powder 1/4 cup
Jackson has 1 cup of butter. If he wants to use all the butter, how many batches of brownies can he make?
Part A
Which equation can you use to solve the problem?
A. 1 ÷ 3 = 3
B. 1 ÷ 13 = 3
C. 1 × 13 = 13
D. 1 + 13 = 13
Part B
Jackson used all the butter to make the brownies.
If each brownie is 1/9 of a batch, how many brownies did he make?
Enter your answer in the box.
Answer:
It's B (1÷13=3) for Part a
1 whole is equal to 3/3. One batch of brownies uses up to 1/3 of butter. So 1 ÷ 1/3 = 3.
Step-by-step explanation:
Please answer this your award will be 20 points for the first answer and brainliest
Step-by-step explanation:
pool = 1600 sq.cm
1600 sq.sm = 50cm × 32cm
AB = 50cm
the area of the park of A'B' :
50cm×4=200 sq.cm
1:Under what condition will the line px+py+r=0 mat be a normal to the circke x²+y²+2gx+2fy+c=0
2:prove that the two circles x²+y²+2ax+c²=0 and x²+y²+2by+c²=0 touch if
[tex]\frac{1}{a²}+\frac{1}{b²}=\frac{1}{c²}[/tex]
Answer:
#1The normal overlaps with the diameter, so it passes through the center.
Let's find the center of the circle:
x² + y² + 2gx + 2fy + c = 0(x + g)² + (y + f)² = c + g² + f²The center is:
(-g, -f)Since the line passes through (-g, -f) the equation of the line becomes:
p(-g) + p(-f) + r = 0r = p(g + f)This is the required condition
#2
Rewrite equations and find centers and radius of both circles.
Circle 1
x² + y² + 2ax + c² = 0 (x + a)² + y² = a² - c²The center is (-a, 0) and radius is √(a² - c²)Circle 2
x² + y² + 2by + c² = 0 x² + (y + b)² = b² - c²The center is (0, -b) and radius is √(b² - c²)The distance between two centers is same as sum of the radius of them:
d = √(a² + b²)Sum of radiuses:
√(a² - c²) + √(b² - c²)Since they are same we have:
√(a² + b²) = √(a² - c²) + √(b² - c²)Square both sides:
a² + b² = a² - c² + b² - c² + 2√(a² - c²)(b² - c²)2c² = 2√(a² - c²)(b² - c²)Square both sides:
c⁴ = (a² - c²)(b² - c²)c⁴ = a²b² - a²c² - b²c² + c⁴a²c² + b²c² = a²b²Divide both sides by a²b²c²:
1/a² + 1/b² = 1/c²Proved
Answer:
Answer is in the picture
[12÷(9-6)]+4×6
please help
The answer is 28 ez.
Answer:
the answer is 28
Step-by-step explanation:
Create an example of a situation where there is a negative cash flow.?
Please help me on this question, ignore the pencil marks.
The answer choices are
A. 4
B. 5
C. 6
D. 7
E. 8
The question is on the picture
answer:
ABCD is not congruent to KLMN
ABCD cannot be mapped onto KLMN
HELPPPPPP don't troll ima report
Answer:
The x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.
Step-by-step explanation:
We have the function:
[tex]\displaystyle y=\frac{x^2 -1}{x}[/tex]
And we want to find the x-coordinates for which the gradient (or slope) at the point is 5.
The gradients of a curve at a point is given by its derivative. Find the derivative:
[tex]\displaystyle \frac{dy}{dx}=\frac{d}{dx}\left[\frac{x^2-1}{x}\right][/tex]
Use the quotient rule:
[tex]\displaystyle \frac{dy}{dx}=\frac{(x^2-1)'(x)-(x^2-1)(x)'}{(x)^2}[/tex]
Simplify:
[tex]\displaystyle \frac{dy}{dx}=\frac{(2x)(x)-(x^2-1)(1)}{x^2}[/tex]
Simplify:
[tex]\displaystyle \frac{dy}{dx}=\frac{x^2+1}{x^2}[/tex]
Since the gradient is 5, substitute 5 for dy/dx and solve for x:
[tex]\displaystyle 5=\frac{x^2+1}{x^2}[/tex]Multiply both sides by x² (x ≠ 0):
[tex]5x^2=x^2+1[/tex]
Subtract x² from boths sides:
[tex]4x^2=1[/tex]
Solve for x:
[tex]\displaystyle x=\pm\sqrt{\frac{1}{4}}=\frac{1}{2}\text{ or } -\frac{1}{2}[/tex]
So, the x-coordinates for which the gradient of the curve is 5 is at x = -1/2 and x = 1/2.
In the accompanying diagram, ABC is isosceles, BC is extended to D. AB = AC. and M
Answer:
m∠ACD = 130
Step-by-step explanation:
If ABC is an isosceles, AB = AC and m∠A = 80°, then m∠B and m∠C is equal to 50°.
This is because angles in a triangle adds up to 180°.
180° - 80° = 100°/2 = 50°
∴ m∠ACD = 130°, this is because the interior opposite angles in a triangle is supplementary to the opposite exterior angle:
50° + 80° = 130°
Or
Angles on a straight line adds up to 180°.
180° - 50° = 130°
[tex]xy = 3xy + 25 \\ 3 = y - 20[/tex]
solve for x andy
Answer:
x= -0.5
y= 23
Step-by-step explanation:
3=y-20 so y= 23
xy=3xy+25
23x=69x+25
-46x= 25
x=-0.5
Someone please answer yes I give brainliest
Please answer! Really need help! ASAP! Giving brainliest
=================================================
Explanation:
The y is a placeholder for a number. In this case, we'll replace it with 4.
So [tex]5y^2 - 10[/tex] becomes [tex]5(4)^2-10[/tex]
Use the order of operations PEMDAS to simplify
[tex]5(4)^2-10\\\\5(16)-10\\\\80-10\\\\70\\\\[/tex]
Therefore, [tex]5y^2-10\\\\[/tex] evaluates to 70 when y = 4.
Put another way, the equation [tex]5y^2-10 = 70\\\\[/tex] has one solution that is y = 4.
PLS HELP ASAP! Find the Surface Area of the given figure.
THANK YOU!
Answer:
158 m^2
Step-by-step explanation:
l = 5 m, w = 3 m, h = 8 m
S.A. = [tex]2(lw+wh+lh)[/tex]
S.A. = 2{(5)(3) + (3)(8) + (5)(8)}
S.A. = 2(15 + 24 + 40)
S.A. = 2(79)
S.A. = 158 m^2
Hope this help!!!
Have a nice day!!!
What is the slope of the line represented by the equation y = 4/5x - 3 ?? Someone help :0 !!
Answer: 4/5
Step-by-step explanation:
hello guys can you help me with this?
Answer:
Step-by-step explanation:
1. Title of the graph → Comparison of the Plant Growth
2. y-axis represents the height of the plants in centimeters.
3. On day 2:
Height of plant A (plant outside) = 5.1 cm
Height of plant B (plant near the window) = 2.25 cm
4. Plant outside shows great increase in the height.
On day 5,
Height of the plant outside = 6.75 cm
Growth in height from day 2 to day 5 = 6.75 - 5.1
= 1.65 cm
Height of the plant near the window = 2.5 cm
Growth in height of the plant from day 2 to day 5 = 2.5 - 2.25
= 0.25 cm
Therefore, plant outside shows the great increase in height.
5. Plant near the window grew 0.25 cm in height.
can anyone help with this trig question?? any help would be greatly appreciated! :)
Answer:
Step-by-step explanation:
Hope this helps u!!
Determine whether the vectors u and v are parallel, orthogonal, or neither.
u = <2,-4>, v = <6,3> (5 points)
===========================================================
Explanation:
For any two vectors defined as follows
u = <a,b>
v = <c,d>
the dot product is computed by
u dot v = a*c + b*d
If the dot product of the vectors is 0, then the vectors are orthogonal. Meaning they are perpendicular to one another.
-------------------
Let's find the dot product of these two given vectors
u = < 2, -4 >
v = < 6, 3 >
u dot v = 2*6 + (-4)*3
u dot v = 12 - 12
u dot v = 0
Therefore, these two vectors form a right angle and are orthogonal
-------------------
Extra info:
If we can show that u = <a, b> and v = <ka, kb> for some real number k, then we have shown that vectors u and v are parallel.
HELP HURRY PLS I really really need help
Answer:
a big number
Step-by-step explanation:
Can any one help me on this
point D is the answer
________
What number is exactly halfway between 5/9 and 7/9
Answer:
11/18
Step-by-step explanation:
Directly between 5/9 and 6/9 would be 5.5/9 (or 5 and half ninths. However, you’re not supposed to mix regular fractions and decimal fractions.
So, the easiest way to get the proper answer would be to convert the fractions to eighteenths, which would give you a whole number numerator between the two given fractions.
So, 5/9 = 10/18 and 6/9 = 12/18. What number is directly exactly between 10 and 12? 11.
Fill in the table of values so that this is a proportional relationship with k=3/2 X. Y. *blank*. 0 2. *blank*. *blank*. 6. -2. *blank*
Answer:
x => y
0 => 0
2 => 3
4 => 6
-2 => -3
Step-by-step explanation:
The equation of a proportional relationship is represented as y = kx,
where, k = y/x
We are given that k = ³/2
This means that, equation of the relationship therefore would be:
y = ³/2x
Use this equation to solve for each missing value on the table given:
✔️Where, y = 0, substitute y = 0 into y = ³/2x to find x:
0 = ³/2x
0 * 2 = 3x
0 = 3x
0/3 = x
x = 0
✔️Where, x = 2, substitute x = 2 into y = ³/2x to find y:
y = ³/2(2)
y = 3
✔️Where, y = 6, substitute y = 6 into y = ³/2x to find x:
6 = ³/2x
6 * 2 = 3x
12 = 3x
12/3 = x
x = 4
✔️Where, x = -2, substitute x = -2 into y = ³/2x to find y:
y = ³/2(-2)
y = -3
how to calculate surface area
9514 1404 393
Explanation:
Divide the figure into areas for which you have a surface area formula. Use the appropriate formula for each area, then add up the results.
Formulas are available for surface areas of a cone, cylinder, sphere, pyramid, rectangular prism, and for plane shapes that are circles, ellipses, triangles, rectangles, trapezoids, and regular polygons.
Most of the figures for which you are asked to find the area will decompose to some subset of these shapes. Take care to identify the relevant dimensions of each of the constituent parts of the area, and to make sure that all parts are accounted for. Do not allow your parts of the area to overlap, unless you intend to account for that overlap by subtracting the area that is counted more than once.
Also, use your common sense. A semicircle will have half the area of a circle, for example.
In some cases, it may be expedient to compute the area of a larger figure than the one you have, then subtract the part of that area that is missing from your figure.
Jenna just got done jumping at the Trampoline center. The total cost of the session was $15.23
She had to pay an entrance fee of $7.25 and $1.45 for every minute she was on the trampoline.
Answer:
≈ 5.5 minutes.
Step-by-step explanation:
Let m = number of minutes on the trampoline.
[tex]1.45m+7.25=15.23\\1.45m=7.98\\m=5.5[/tex]
She was on the trampoline for approximately 5.5 minutes.
Answer:
= 5.5 minutes
Step-by-step explanation:
1.45 + 7.25 = 15. 23
1. 45 = 15. 23 - 7. 25
1. 45 = 7 . 98
m = 5.5
Hope this answer helps you :)
Have a great day
Mark brainliest
