A piece of coaxial cable has 75ohms Characteristics impedance and a nominal capacitance of 69pF/m. what is its inductance per meter ? If the diameter of the inner conductor is 0.584mm, and the dielectric constant of the insulation is 2.23, what is the outer diameter of the conductor ?
Answer:
A) L = 0.388 μm
B) D = 3.78 mm
Explanation:
We are given;
Characteristics impedance; Z_o = 75 ohms
Nominal capacitance; C = 69pF/m = 69 × 10^(-12) F/m
dielectric constant; k = 2.23
Inner diameter of conductor; d = 0.584 mm
A) Now formula for Characteristics impedance is given as;
Z_o = √(L/C)
Where L is the inductance per metre.
Making L the subject, we have;
L = (Z_o)²C
L = 75² × 69 × 10^(-12)
L = 0.388 × 10^(-6) m
L = 0.388 μm
B) To get the outer diameter, we will use the formula;
Z_o = (138/√k) log(D/d)
Where;
D is outer diameter.
Thus, Plugging in the relevant values;
75 = (138/√2.23) × log (D/0.584)
log (D/0.584) = 0.81158611538
(D/0.584) = 10^(0.81158611538)
D/0.584 = 6.48016576435
D = 6.48016576435 × 0.584
D = 3.78 mm
EnQueue(X): Thêm phần tử X vào Queue
DeQueue() : Lấy 1 phần tử ra khỏi Queue
Hãy cho biết phần tử ở đầu của Queue có giá trị bằng bao nhiêu sau khi thực hiện lần lượt các phép toán sau:
EnQueue(1); EnQueue(2); DeQueue(); EnQueue(3);
EnQueue(4); DeQueue(); DeQueue();
Two engineers are to solve an actual heat transfer problem in a manufacturing facility. Engineer A makes the necessary simplifying assumptions and solves the problem analytically, while engineer B solves it numerically using a powerful software package. Engineer A claims he solved the problem exactly and, thus, his results are better, while engineer B claims that he used a more realistic model and, thus, his results are better. Will the experiments prove engineer B right
Answer:
Engineer A results will be more accurate
Explanation:
Analytical method is better than numerical method. Engineer A has used analytical method and therefore his results will be more accurate because he used simplified method. Engineer B has used software to solve the problem related to heat transfer his results will be approximate.
Wave flow of an incompressible fluid into a solid surface follows a sinusoidal pattern. Flow is two-dimensional with the x-axis normal to the surface and y axis along the wall. The x component of the flow follows the pattern
u = Ax sin (2πt/T)
Determine the y-component of flow (v) and the convective and local components of the acceleration vector.
Answer:
sorry , for my point
Explanation:
Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 6 cm and 4 cm.
Answer:
Minimum area of rectangle = 24 cm²
Explanation:
Given:
Length of rectangle = 6 cm
Width of rectangle = 4 cm
Find:
Minimum area of rectangle
Computation:
Area of rectangle = Length of rectangle x Width of rectangle
Minimum area of rectangle = Length of rectangle x Width of rectangle
Minimum area of rectangle = 6 x 4
Minimum area of rectangle = 24 cm²
Make a sketch of a simple mechanically expanded brake and indicate the forces acting on the leading shoe when the brake is applied.
An unconstrained 10mm thick plate of steel 100mm on a side with a 25mm diameter hole in the center is heated from 20 degrees C to 120 degrees C. The linear CTE is 12x10-6/⁰C. What is the final diameter of the hole
Answer:
The correct answer is "25.03 mm".
Explanation:
Given:
Thickness of plate,
= 10 mm
On a side,
= 100 mm
Diameter hole,
= 25 mm
Coefficient of thermal expansion,
CTE = [tex]12\times 10^{-6} /^{\circ} C[/tex]
Now,
⇒ [tex]D_i\times (12\times 10^{-6}) \Delta \theta = \Delta D[/tex]
= [tex]25\times 12\times 10^{-6} \Delta \theta[/tex]
= [tex]3\times 10^{-4} \Delta \theta[/tex]
= [tex]3\times 10^{-2}[/tex]
hence,
The final diameter of hole will be:
[tex]D_f=25.03 \ mm[/tex]
How would you describe what would happen to methane if the primary bonds were to break?
Answer:
All the bonds in methane (CH4CH4) are equivalent, and all have the same dissociation energy.
The product of the dissociation is methyl radical (CH3CH3). All the bonds in methyl radical are equivalent, and all have the same dissociation energy.
The product of that dissociation is methylene (CH2CH2). All the bonds in methylene are equivalent, and all have the same dissociation energy.
The product of that dissociation is methyne (CHCH) .
The C-H bonds in methane do not have the same dissociation energy as C-H bonds in methyl radical, which in turn do not have the same dissociation energy as the C-H bonds in methylene, which are again different from the C-H bond in methyne.
If (by some miracle) you were able to get all four bonds in methane to dissociate absolutely simultaneously, they would all show the same dissociation energy… but that energy, per bond broken, would be different than the energy required to break just one C-H bond in methane, because the products are different.
(In this case, it’s CH4→C+4HCH4→C+4H versus CH4→CH3+HCH4→CH3+H.)
To alter hydrocarbons you add enough energy to break a C-H bond. Why does only one bond break? What concentrates the energy on one C-H bond?
the weakest CH bond is the one that breaks. in plain alkanes it has to do with the molecular orbital interactions between neighboring carbon atoms. look at propane for example. the middle carbon has two C-C bonds, and each of those C-C bonds is strengthened by slight electron delocalization from the C-H bonds overlapping with the antibonding orbitals of the adjacent carbons.
since the C-H bonds on the middle carbon donate electron density to both of its neighbors, those two are weakest.
one of them will break preferentially.
which one actually breaks depends on the reaction conditions (kinetics). frankly it's whichever one ramdomly approaches a nucleophile first. when the nucleophile pulls of one of the H's, the other C-H bonds start to share (delocalize) the negative charge across the whole molecule. so while the middle C feels the majority of the negative charge character, the other two C's take on a fair amount as well...
by the way, alkanes don't really like to break and form anions like that.
a better example would be something like isopropyl iodide, where the C-I bond breaks and the I carries away the electron pair, forming a carbocation (also not particularly stable, but more so than the carbanion).
c. Assuming a fixed-priority scheduling. Consider two tasks to be executed periodically on a single processor, where task 1 has period p= 4 and task 2 has period p= 6.
If execution time of task I be e;=1
Find the maximum value for the execution time e2 of task 2 such that the Rate Monotonic (RM) schedule is feasible.
Answer:
hi hello tata byebye nice
As per the given data, the maximum value of e2 such that the RM schedule is feasible is 0.985.
What is fixed-priority scheduling?Fixed-priority scheduling is a scheduling algorithm used in real-time operating systems to assign priorities to tasks based on their relative importance or urgency.
In a fixed-priority scheduling algorithm, tasks with higher priority are assigned shorter periods.
Since task 1 has a period of 4 and task 2 has a period of 6, we can assume that task 1 has a higher priority than task 2. Therefore, we can apply the Rate Monotonic (RM) scheduling algorithm.
The RM scheduling algorithm states that a feasible schedule exists if the following condition is satisfied:
Σ (ei / pi) ≤ n(2^(1/n)-1)
Where Σ (ei / pi) is the sum of the ratio of execution time to period for all tasks, n is the total number of tasks, and the base of the exponential function is 2.
In this case, we have two tasks, so n = 2. We know that e1 = 1 and p1 = 4. For task 2, we need to find the maximum value of e2 such that the schedule is feasible. Therefore, we can set e2 = x and p2 = 6.
Substituting the values into the RM scheduling formula, we get
(e1/p1) + (e2/p2) ≤ 2^(1/2) - 1
(1/4) + (x/6) ≤ 0.4142
Multiplying both sides by 12, we get:
3 + 2x ≤ 4.97
2x ≤ 1.97
x ≤ 0.985
Therefore, the maximum value of e2 such that the RM schedule is feasible is 0.985.
For more details regarding priority scheduling, visit:
https://brainly.com/question/19721841
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Karl and Susan have agreed to come to our party, _______ has made Maria very happy. that which what who
Answer:
that
I am not sure that this is the answer
but i hopethis will help you
Karl and Susan agreed to come to our party, which made Maria very happy. The correct option is b.
What are relative pronouns?Relative pronouns are words that are used to show the relation between two statements. Who/whom, whoever/whomever, whose, that, and which are the most common relative pronouns. "what," "when," and "where" might operate as relative pronouns.
Relative pronouns introduce dependent sentences called relative clauses. Happy is an emotion that is non-living things and with non-living things, which is used.
The relative pronouns "which" and "that" begin adjective clauses. Both provide additional information about the noun they follow.
Therefore, the correct option is b, which. Karl and Susan agreed to come to our party, which made Maria very happy.
To learn more about relative pronouns, refer to the link:
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If a cylindrical part with a length of 20 mm and a diameter of 20 mm is to be machined to a cylindrical part with 18 mm in diameter with the same length. The machine has a mechanical efficiency of 50% and a power of 80 kW. If the cutting rake angle is 0 degrees and the cutting tool is made of uncoated carbides and the cutting speed is 10 m/s. What material can we choose for the cylinder
Answer:
Titanium Alloy
Explanation:
Length ( L ) = 20 mm
D1 = 20 mm
d2 = 18 mm
l = 20 mm
Mechanical efficiency = 50%
power = 80 kW
cutting rake angle = 0°
cutting speed ( v ) = 10 m/s
Determine the material to be for the cylinder
In order to choose a material for the cylinder we have to calculate the cutting force
P = Fc * V
80 = Fc * 10 m/s
therefore Fc = 80 / 10 = 8 N
Hence the material we can use is Titanium Alloy due to low cutting force value
A gas tank is known to have a thickness of 0.5 inches and an internal pressure of 2.2 ksi. Assuming that the maximum allowable shear stress in the tank wall is 12 ksi, determine the necessary outer diameter for the tank. Assume that the tank is made of a cold drawn steel whose elastic modulus is 35000 ksi and whose Poisson ratio is 0.292. If y
Answer:
[tex]D_o=11.9inch[/tex]
Explanation:
From the question we are told that:
Thickness [tex]T=0.5[/tex]
Internal Pressure[tex]P=2.2Ksi[/tex]
Shear stress [tex]\sigma=12ksi[/tex]
Elastic modulus [tex]\gamma= 35000[/tex]
Generally the equation for shear stress is mathematically given by
[tex]\sigma=\frac{P*r_1}{2*t}[/tex]
Where
r_i=internal Radius
Therefore
[tex]12=\frac{2.2*r_1}{2*0.5}[/tex]
[tex]r_i=5.45[/tex]
Generally
[tex]r_o=r_1+t[/tex]
[tex]r_o=5.45+0.5[/tex]
[tex]r_o=5.95[/tex]
Generally the equation for outer diameter is mathematically given by
[tex]D_o=2r_o[/tex]
[tex]D_o=11.9inch[/tex]
Therefore
Assuming that the thin cylinder is subjected to integral Pressure
Outer Diameter is
[tex]D_o=11.9inch[/tex]
Alternating current lesson 4 exam
in plumbing what is a video snake used for
Answer:
How to stop toilets
Explanation:
I think
Hope this helps
The maximum tensile force a solid, cylindrical wire can withstand increases as the thickness of the wire increases.
True
False
Tech A says that proper footwear may include both leather and steel-toed shoes. Tech B says that when working in the shop, you only need to wear safety glasses if you are doing something dangerous. Who is correct?
Answer:
Tech A is correct.
Explanation:
If a person is doing something dangerous in a shop, he should wear safety glasses to protect his eyes from danger and also wear leather shoes to protect himself from any electric shock. Leather boots will disconnect a person with direct earth and therefore he can save himself if he gets a electric shock.
What are the assumptions made for air standard cycle analysis?
a.The working medium is prefect gas throughout i.e. it follows PV=mRT
b.The working medium does not undergo any chemical change throughout the cycle
c.The compression and expansion processes are reversible adiabatic i.e. there is no loss or gain in entropy.
d.All of above
La iluminación de la superficie de un patio amplio es 1600 lx cuando el ángulo de elevación del sol 53°. Calcular la iluminación cuando el ángulo de elevación del Sol sea 37°
Answer:
I = 1205.69 Lx
Explanation:
The irradiation or intensity of the solar radiation on the earth is maximum for the vertical fire, with a value I₀
I = I₀ sin θ
in this case with the initial data we can calculate the initial irradiance
I₀ = [tex]\frac{I}{sin \ \theta }[/tex]
I₀ = 1600 /sin 53
I₀ = 2003.42 lx
for when the angle is θ = 37º
I = 2003.42 sin 37
I = 1205.69 Lx
A shunt regulator utilizing a zener diode with an incremental resistance of 8 ohm is fed through an 82-Ohm resistor. If the raw supply changes by 1.0 V, what is the correspondig change in the regulated outut voltage?
Answer:
[tex]\triangle V_0=0.08V[/tex]
Explanation:
From the question we are told that:
Incremental resistance [tex]R=8ohms[/tex]
Resistor Feed [tex]R_f=82ohms[/tex]
Supply Change [tex]\triangle V=1[/tex]
Generally the equation for voltage rate of change is mathematically given by
[tex]\frac{dV_0}{dV}=\frca{R}{R_1r_3}[/tex]
Therefore
[tex]\triangle V_0=\triangle V*\frac{R}{R_fR}[/tex]
[tex]\triangle V_0=1*\frac{8}{8*82}[/tex]
[tex]\triangle V_0=0.08V[/tex]
A symmetric biplane having forward / aft wedge angles 2° is placed in supersonic
flow as shown below.
Estimate the lift and drag of this configuration by using the idea of method of
characteristics. (Recall v±0=const on different direction i.e left or right running waves)
%3D
The wave pattern on the biplane is shown in dashed lines.
(v,0)»=(28,0)
Answer:
you are good thx dedo please ❤️
Explanation:
please give me thx pls pls pls
9. What is a whip check?
Answer:
¿Cuál es el efecto látigo?
Es un grave desajuste entre la demanda real de un producto y la demanda de los actores intermediarios en la cadena de suministro
Explanation: espero que te yueda
A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the lower end of a slender 23-lb bar of length L = 30 in. Knowing that h = 12 in. and that the bar is initially at rest. Determine the angular velocity of the bar immediately after the bullet becomes embedded.
Answer: hello attached below is the missing image the slender weight is different from what is in the question here so I worked with 23-Ib as requested in the question
answer
≈ 12.17 Rad/sec
Explanation:
weight of bullet ( Wb ) = 0.08 Ib
horizontal velocity = 1800 ft/s
Slender(Wr) = 23-Ib bar with
length ( L ) = 30
h = 12 inches
Vro = 0
Calculate the angular velocity of the bar immediately after the bullet becomes embedded
attached below is a detailed solution
6.708 = ( 0.05011 + 0.5011 ) w'
w' = 6.708 / 0.55121 ≈ 12.17 Rad/sec
The part dimension for an injection-molded part made of polycarbonate is specified as 4.00 in. Compute the corresponding dimension to which the mold cavity should be machined.
Answer:
[tex]D=4.02[/tex]
Explanation:
From the question we are told that:
Part Dimension [tex]x=4.00in[/tex]
Generally the equation for the corresponding dimension to which the mold cavity should be machined is mathematically given by
[tex]D=x-(xS)+(4S^2)[/tex]
Where
S= Value for Skinage
From Table pf AB's
[tex]S=0.006[/tex]
Therefore
[tex]D=4-(4*0.006)+(4(0.006)^2)[/tex]
[tex]D=4.02[/tex]
USING THE ONTARIO BUILDING CODE TO SOLVE THESE QUESTIONS ARCH1013
Architectural Engineering
1. Calculate the minimum width and thickness of footings required to support walls of Cassidy House Elevation B. (1.5/4).
a)Footing width and thickness of exterior walls, if the floor joists span less than 4.9 m:
Cassidy is a Two-storey house, minimum thickness of footing (Table 9.15.3.4.)=
Two storeys of Brick veneer (9.15.3.5.) =
Adjusted Footing width for Cassidy House =
Thickness (9.15.3.8.)=
b)Assume that the house has a load bearing masonry interior wall that is 150mm thick supporting both first and second storey. Determine the minimum width and thickness required of its footing:
Min. thickness of footing for an interior wall that supports two floors (Table 9.15.3.4) =
Adjust for two storey of masonry wall (9.15.3.6.) =
Thickness =
2. Answer the following questions based on foundations details of Cassidy Elevation B. (1.5/4).
a)What is the maximum height of finished ground the foundation wall can support, if it is 2.5m high?
Table 9.15.4.2.A, Construction Notes
b) If you were to build this wall with 190mm thick ICF, what is the minimum vertical reinforcement required, using the height of foundation wall and ground found in earlier questions?
Table 9.15.4.B.
c) If you were to build this wall with unreinforced concrete blocks, what is the minimum thickness of the foundation wall?
Table 9.15.4.2.A.
3. Calculate the footing width of an external wall of a three storey wood frame brick veneered house. Assume it supports joists spanning 11.5m on first and second floors and 10m on third floor. (1/4)
9.15.2.4.B: use the formula;
W = w (εsjs/ storeys x 4.9)
If anyone has any Idea on how to do this or has any Architectural background please explain to me!
Elevation B: Page 13
Answer:
I cannot open the pdf file . There is some probem .So I dont know the answer
Generally, the primary source of all water supply is said to be
IAMURLORDANDSAVIORILiKENUGEETSHELLOLOL
Answer:
lol Jebus?
Explanation:
Answer:
addsa
sdadsa
Explanation:
dsads
The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any friction and calculate their speed v when they reach the horizontal bottom position. At the top position, the radius of the circular path of their mass centers is 21 m, and all six cars have the same mass. What is v?
Complete Question
The cars of a roller-coaster ride have a speed of 19.0 km/h as they pass over the top of the circular track. Neglect any friction and calculate their speed v when they reach the horizontal bottom position. At the top position, the radius of the circular path of their mass centers is 21 m, and all six cars have the same mass.V = -18 m What is v?X km/h
Answer:
[tex]v=23.6m/s[/tex]
Explanation:
Velocity [tex]v_c=18.0km/h[/tex]
Radius [tex]r=21m[/tex]
initial velocity u[tex]u=19=>5.27778[/tex]
Generally the equation for Angle is mathematically given by
[tex]\theta=\frac{v_c}{2r}[/tex]
[tex]\theta=\frac{18}{2*21}[/tex]
[tex]\theta=0.45[/tex]
[tex]\theta=25.7831 \textdegree[/tex]
Generally
Height of mass
[tex]h=\frac{rsin\theta}{\theta}[/tex]
[tex]h=\frac{21sin25.78}{0.45}[/tex]
[tex]h=20.3m[/tex]
Generally the equation for Work Energy is mathematically given by
[tex]0.5mv_0^2+mgh=0.5mv^2[/tex]
Therefore
[tex]v=\sqrt{u^2+2gh}[/tex]
[tex]v=\sqrt{=5.27778^2+2*9.81*20.3}[/tex]
[tex]v=23.6m/s[/tex]
(Laminar flow) A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length 21. The flow is laminar and fully developed. The pressure drop for the first pipe is 1.657 times greater than it is for the second pipe. If the diameter of the first pipe is D, determine the diameter of the second pipe. D3 = D the tolerance is +/-3%
This question is incomplete, the complete question is;
(Laminar flow) A fluid flows through two horizontal pipes of equal length which are connected together to form a pipe of length 2[tex]l[/tex]. The flow is laminar and fully developed. The pressure drop for the first pipe is 1.657 times greater than it is for the second pipe. If the diameter of the first pipe is D, determine the diameter of the second pipe.
D₃ = _____D.
{ the tolerance is +/-3% }
Answer:
the diameter of the second pipe D₃ is 1.13D
Explanation:
Given the data in the question;
Length = 2[tex]l[/tex]
pressure drop in the first pipe is 1.657 times greater than it is for the second pipe.
Now, we know that for Laminar Flow;
V' = πD⁴ΔP / 128μL
where V'₁ = V'₂ and ΔP₁₋₂ = 1.657 ΔP₂₋₃
Hence,
V'₁ = πD⁴ΔP₁₋₂ / 128μL = V'₃ = πD₃⁴ΔP₂₋₃ / 128μL
so
D₃ = D[tex]([/tex] ΔP₁₋₂ / ΔP₂₋₃ [tex])^{\frac{1}{4}[/tex]
we substitute
D₃ = D[tex]([/tex] 1.657 [tex])^{\frac{1}{4}[/tex]
D₃ = D( 1.134568 )
D₃ = 1.13D
Therefore, the diameter of the second pipe D₃ is 1.13D
A slab-milling operation is performed on a 0.7 m long, 30 mm-wide cast-iron block with a feed of 0.25 mm/tooth and depth of cut of 3 mm. The cutter has a diameter of 75 mm, has 8 cutting teeth, and rotates at 200 rpm. Calculate the cutting time and material removal rate.
Answer:
a) [tex]T_m=1.787min[/tex]
b) [tex]MRR=35259.7mm^3/min[/tex]
Explanation:
From the question we are told that:
Cast-iron block Dimension:
Length[tex]l=0.7m=>700mm[/tex]
Width [tex]w=30mm[/tex]
Feed[tex]F=0.25mm/tooth[/tex]
Depth [tex]dp=3mm[/tex]
Diameter [tex]d=75mm[/tex]
Number of cutting teeth [tex]n=8[/tex]
Rotation speed [tex]N=200rpm[/tex]
Generally the equation for Approach is mathematically given by
[tex]x=\sqrt{Dd-d^2}[/tex]
[tex]X=\sqrt{75*3-3^2}[/tex]
[tex]X=14.69mm[/tex]
Therefore
Effective length is given as
[tex]L_e=Approach +object Length[/tex]
[tex]L_e=700+14.69[/tex]
[tex]L_e=714.69mm[/tex]
a)
Generally the equation for Machine Time is mathematically given by
[tex]T_m=\frac{L_e}{F_m}[/tex]
Where
[tex]F_m=F*n*N[/tex]
[tex]F_m=0.25*8*200[/tex]
[tex]F_m=400[/tex]
Therefore
[tex]T_m=\frac{714.69}{400}[/tex]
[tex]T_m=1.787min[/tex]
b)
Generally the equation for Material Removal Rate. is mathematically given by
[tex]MRR=\frac{L*B*d}{t_m}[/tex]
[tex]MRR=\frac{700*30*3}{1.787}[/tex]
[tex]MRR=35259.7mm^3/min[/tex]
The transfer function of a linear system is defined as the ratio of the Laplace transform of the output function y(t) over the ratio of the Laplace transform of the input function g(t) when all initial conditions are zero. Determine the transfer function H(s)=Y(s)G(s)H(s)=Y(s)G(s)for the system y′′(t)+8y′(t)+6y(t)=g(t),t>0
Answer:
H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)
Explanation:
Since we are required to determine the transfer function G(s) and Y(s) = G(s)H(s). So, H(s) = Y(s)/G(s).
Since our system is given as y′′(t) + 8y′(t) +6y(t) = g(t), t>0 with all initial condition zero, that is, y(0) = 0, y"(0) = 0 and g(0) = 0.
Taking the Laplace transform of both the left hand side and right hand side of the equation, we have
y′′(t) + 8y′(t) +6y(t) = g(t),
L{y′′(t) + 8y′(t) +6y(t)} = L{g(t)}
L{y′′(t)} + L{8y′(t)} + L{6y(t)} = L{g(t)}
L{y′′(t)} + 8L{y′(t)} + 6L{y(t)} = L{g(t)}
[s²Y(s) - sy(0) - y'(0)] + 8[sY(s) - y(0)] + 6Y(s) = G(s)
[s²Y(s) - s(0) - 0] + 8[sY(s) - 0] + 6Y(s) = G(s)
s²Y(s) + 8sY(s) + 6Y(s) = G(s)
(s² + 8s + 6)Y(s) = G(s)
Y(s)/G(s) = 1/(s² + 8s + 6)
So, H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)
