Sofia is driving to Texas. She travels at 70 kilometers per hour for 2 hours, and 63 kilometers per hours for 5 hours. Over 7 hours time period what was sofia's average speed ?

Answers

Answer 1

Answer:

65 kph

Step-by-step explanation:

There were a total of 7 hours. So two hours were at 70 and the other 5 hours at 63: the equation would be: (70+70+63+63+63+63+63)/7=65


Related Questions

An object is dropped off a building that is 144 feet tall. After how many seconds does the object hit the ground? (d=16t^2)
wrong= reported.
ty<3

Answers

Answer:

after 3 seconds, the object hits the ground.

Hope this helps :)

Charlie borrowed $500 from his aunt. He has already paid back $75. His aunt doesn't charge
any interest and he is planning on making $15 payments each friday

Answers

Answer:

555

Step-by-step explanation:

because it is tyeesgghhhhfdfhf

Solve 4(x + 1) = 4x + 4

Answers

Answer:

x is all real numbers

Step-by-step explanation:

4(x + 1) = 4x + 4

Distribute

4x+4 = 4x+4

Subtract 4x from each side

4x+4-4x = 4x+4-4x

4=4

This is always true so there are infinite solutions

x is all real numbers

What is answer to 3+2•5•8

Answers

the answer it’s 200 luv

The cost of renting the Party Barn is $150 flat fee plus an additional $50 per hour. Manny can spend up to $325 to rent
the Party Barn for his birthday party. What are the possible hours that Manny could rent the Party Barn?

Answers

150$ flat fee means that 325-150= 175$ he can spend by the hour. Since it is 50$ and hour, he can spend no more than 3.5 hours in there as 175\50 = 3.5 . If it is by the whole hour, then 3 because he cannnot round up and afford 4.

If P={2,3,4} and Q={1,5} find and represent it in set builder form​

Answers

Step-by-step explanation:

Solution,

P={2,3,4}

P={x:x ∈ N between 1 and 5}

Q={1,5}

Q={x:x ∈ factors of 5}

I hope you were asking for the same answer .

I hope it helped U

stay safe stay happy

2. Find the domain of the function (f/g)(x) where f (x)= x^2 – 9 and g(x)= x^2 - 4x+3

A (-infinity, infinity)
B (-infinity, 1) (1, infinity)
C (infinity, 1) (1,3) (3, infinity)
D (-infinty, -3) (-3,-1)(-1, infinity)

Answers

Answer:

I think you mean C.

Step-by-step explanation:

f(x) / g(x) = (x + 3)(x - 3)

                ==========

                  (x - 3)(x - 1)

f(x)/g(x) = (x+3) / (x - 1)

- ∞ < 1 U 1 < 3 U 3 < ∞  

is a=3 b=4 c=2 and d=-2 find the value of 3b²c-2ad
And ac-bd/7​

Answers

3b^2c-2ad=3*16*2-(2*3*-2)=108
ac-bd/7=3*2-(4*-2)/7=50/7 but if you mean (3*2-(4*-2))/7=2

Step-by-step explanation:

remember : calculations are usually done from left to right, but multiplications and divisions come before + and -.

and exponents come before multiplications and divisions.

and minus a negative number always turns into plus a positive number.

so,

3b²c - 2ad = 3×4²×2 - 2×3×-2 = 96 - -12 = 96 + 12 = 108

and

ac - bd/7 = 3×2 - 4×-2/7 = 6 - -8/7 = 6 + 8/7 = 7 1/7 ≈ 7.143

A ball is thrown into the air with an upward velocity of 32 ft/s. It’s height h in feet after t seconds is given by the function h = -16t + 32t + 6 in how many seconds does the ball reach it maximum height? Round to the nearest hundredth if necessary

Answers

Answer:

gfxdg

Step-by-step explanation:

select the correct answer
which of these graphs represents a function?

Answers

Answer:WHope this helps!! <3

I NEED HELP ITS DUE TODAY I WILL GIVE BRAINliST PLZz

Answers

Answer:

49

Step-by-step explanation:

the marked price of a watch is rs 2700.If allowing 2V% discount on the marked price and adding V% vat, the value of the watch will be rs 2376.Find the rate of vat.​

Answers

The answer is 24%
Step one:
given data
The marked price of a watch is Rs.2700
The value of the watch after adding VAT is Rs.2376
let us find the discount
= 2700-2376
=324
then the percentage discount is
=324/2700*100
=0.12*100
=12%

(5m-4)/6 -1 = 4m - (3m+10)/2
pls answer fast​

Answers

Answer:

m = 2

Step-by-step explanation:

[tex] \frac{(5m - 4)}{6} - 1 = 4m - \frac{(3m + 10)}{2} [/tex]

[tex] = > \frac{5m - 4 - 6}{6} = \frac{8m - 3m - 10}{2} [/tex]

[tex] = > \frac{5m - 10}{6} = \frac{5m - 10}{2} [/tex]

[Cross Multiplication]

=> 2(5m - 10) = 6(5m - 10)

=> 10m - 20 = 30m - 60

=> 60 - 20 = 30m - 10m

=> 40 = 20m

[tex] = > m = \frac{40}{20} [/tex]

=> m = 2 (Ans)

Find f(-3) if f(x) = -2x^2 + x + 3 and g(x) = -2x + 1

HELP please explain how to do it

Answers

Since you're trying to find f(-3), your function that you have to plug -3 into will be f(x).

f(-3) = -2(-3)^2+(-3)+3

f(-3) = -2(9)+(-3)+3

f(-3) = -18-3+3

f(-3) = -18 is your final answer

Find the value of x. Round to the
nearest tenth.
35
Х
12
x = [ ? ]

Answers

Answer:

Step-by-step explanation:

[tex]Tan 35 = \dfrac{opposite \ side}{adjacent \ side}\\\\0.7=\dfrac{12}{x}\\\\0.7*x=12\\\\x=\dfrac{12}{0.7}\\\\x=17.1[/tex]

-18 divided by 9
-5x(-7)

Answers

Answer:

1) -18 divided by 9 is -2

2) -5x(-7) is 35x

Step-by-step explanation:

[tex] - 18 \div 9[/tex]

[tex] = - (18 \div 9)[/tex]

[tex] = - 2[/tex]

‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐‐

[tex] - 5x( - 7)[/tex]

[tex] = 5x \times 7[/tex]

[tex] = 35x[/tex]

an elevator in a tall building goes up 7 floors, then down 9 floors, down 4 floors, up 8 floors, anddown 2 floors. now it is on floor 14 on what floor did the elevator start

Answers

Answer:

It started on the same floor, floor 14

Step-by-step explanation:

if it went up 7 then down 9, so negative 2 kinda, then down another 4, so negative 6, then up 8 so positive 2, then down 2, it would've started on floor 14

Answer:

14

Step-by-step explanation:

Let the floor started be 'x'

Equation:-  

=> x + 7 - 9 - 4 + 8 - 2= 14

x + (+7) + (-9) + (-4) + (+8) + (-2) = 14  

x + 7 - 9 - 4 + 8 - 2 = 14  

x + 15 - 15 = 14  

x = 14

Therefore, elevator started from 14th level.  

Can someone help me with problem 6 and 7? Please explain I am confused

Answers

This is interesting. You cannot turn 1/4 or 2/4 or 3/4 into a mixed number because they are proper fractions. Perhaps ask your teacher about it? Or just rewrite the fractions as is and state they are in proper form.

Same with 7. They are each simplified already. I would suggest asking your teacher.

Sameer had $600 in his savings account. He wants to have at least $100 in the account
by the end of the year. He withdraws $20 a week for expenses. How many weeks can
Sameer withdraw money? Important! When you multiply or divide by a negative
number, the inequality sign reverses.>+<
amounts in savings - amount per week x number of weeks 2 amount of money at the
end of the year
30 weeks
25 weeks
O
5 weeks
20 weeks

Answers

Answer:

The answer is 25 weeks

Step-by-step explanation:

Let, Number of weeks = x

Now, the required expression is

∴[tex]600-20x\geq 100\\=>-20x\geq -500\\=>20x\leq 500\\x\leq 25[/tex]

Hope you have understood this.....

ask me if you have any confusion.....

if you liked it pls mark it as the brainliest

You have $200 in a savings account and $100 in a checking
account. Each week, you add $50 to your savings account and $30 to your
checking account.
a. Write algebraic expressions that represent the amount of money in each
bank account after w weeks.
b. Write an expression in simplest form that represents the total amount of
money in both accounts after w weeks.
c. How much money do you have in both accounts after 5 weeks?

Answers

Answer:

a. Savings account: 200 + 50w Checking account: 100 + 30w

b. 300 + 80w

c. 700

Step-by-step explanation:

b. 200 + 50w + 30w + 100 Combine like terms. 300 + 80w

c. 300 + 80w. w=5. 300 + (80*5) = 300 + 400 = 700

what is (2x+30)° and (3x+20)°​

Answers

Answer:

solution:

here,

or, (2x+30)°=(3x+20)°

or,2x+30°=3x+20°

or, 2x+3x=30°+20°

or, 5x=50°

or, x=50°÷5

so that: x=10° ans

If m ZABD = 83º, what are mZABC and m ZDBC?
3x+33° D
(Ex-6)°
B
mZABC = °

Answers

Answer:

∠ ABC = 48°

Step-by-step explanation:

∠ ABC + ∠ DBC = ∠ ABD , that is

6x - 6 + 3x + 8 =  83

9x + 2 = 83 ( subtract 2 from both sides )

9x = 81 ( divide both sides by 9 )

x = 9

Then

∠ ABC = 6x - 6 = 6(9) - 6 = 54 - 6 = 48°

what is the LCM of 4489​

Answers

Answer:

plz mark me brainliest

Step-by-step explanation:

thanks for question

pretty sure this is algebra

Answers

Answer :

[tex] \boxed{ \boxed{ \: \: \: \: 1.4 \: \: \: \: }}[/tex]

let's solve :

[tex] \hookrightarrow \: \dfrac{2a + 3b}{3b} [/tex]

[tex] \hookrightarrow \: \dfrac{2a}{3b} + \dfrac{3b}{3b} [/tex]

[tex] \hookrightarrow \: \dfrac{2a}{3b} + 1[/tex]

[tex] \hookrightarrow \: \big(\dfrac{2}{3} \times \dfrac{a}{b} \big) + 1 [/tex]

[tex] \hookrightarrow \: \big(\dfrac{2}{3} \times 0.6 \big) + 1[/tex]

[tex] \hookrightarrow \:( 2 \times 0.2) + 1[/tex]

[tex] \hookrightarrow \: 0.4 + 1[/tex]

[tex] \hookrightarrow \: 1.4[/tex]

Trapezoid p is the image of trapezoid P after a translation. Y 7+ . р на дъл от - 1 -7-6-5-4-3-2-1 -2+ 11 2 3 4 5 6 7 1 PY 1 - - -51 -67 Which statement correctly describes the translation of trapezoid P to create the image Pl? A. 3 units to the right and 5 units down B. 4 units to the right and 1 units down O C. 8 units to the right and 5 units down D. 9 units to the right and 6 units down​

Answers

Answer:

C. 8 units right and 5 units down

Step-by-step explanation:

since it's only a translation, take one point as an example. lets say the bottom right point on trapezoid P is point A, and the translated point on P' is A'. the coordinates of A are (-3,2) while the coordinates of A' are (5,-3). (-3+x,2+y)=(5,-3). -3+x=5, x=8; 2+y=-3, y=-5

write 12:57 a.m in 24 hour time

Answers

Answer:

Here is your answer . Hope this is helpful to you.

Find the values of a and b that complete the mapping diagram

Answers

Answer:

A=0

B=1

Step-by-step explanation:

Just did it (:

Answer: A = 0, and B = 1.

Step-by-step explanation: I put 0, and 1, and it was the perfect answer.

Find the y-intercept of the line: 6x – 3y +6=0

Answers

Answer:

Step-by-step explanation:

The y-intercept exists where the x coordinate is 0. Therefore, we can find it by plugging in a 0 for x and solving for y:

6(0) - 3y + 6 = 0 and

-3y + 6 = 0 and

-3y = -6 so

y = 2

If the perimeter of a rectangle
is 124m & the width is 35m,
what is the length?

Answers

Let length be x

ATQ

[tex]\\ \sf\longmapsto 2(Length+Width)=124[/tex]

[tex]\\ \sf\longmapsto 2(x+35)=124[/tex]

[tex]\\ \sf\longmapsto 2x+70=124[/tex]

[tex]\\ \sf\longmapsto 2x=124-70[/tex]

[tex]\\ \sf\longmapsto 2x=54[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{54}{2}[/tex]

[tex]\\ \sf\longmapsto x=27m[/tex]

Suppose the function H(t) gives the heart rate of a runner at various points in time during a 20 mile run. Describe an appropriate domain of this function. Include a description of the kinds of numbers in the domain as well as any limitations on their values.

Answers

.....................

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