Solve 2(x - 1) + 3 = x - 3(x + 1) (make sure to type the number only)

Answer:

f(1/3) = 6

Step-by-step explanation:

f(x) =-3x+7

Let x = 1/3

f(1/3) =-3*1/3+7

        = -1 +7

       = 6

Answer:

f(1/3) = 6

Step-by-step explanation:

The function is:

● f(x) = -3x+7

Replace x by 1/3 to khow the value of f(1/3)

● f(1/3) = -3×(1/3) +7 = -1 +7 = 6

Answer:

2+4+6+8

Step-by-step explanation:

We have the sum of 2n  where n runs from 1 to 4

n=1  2(1) = 2

n=2  2(2) = 4

n=3  2(3) = 6

n=4  2(4) = 8

The sum is add

2+4+6+8

Answer:

132 degrees

Step-by-step explanation:

Looking at angle A and angle B, they are alternate interior angles. That means they are congruent to one another. Knowing that, we can set up an equation A=B

We can now fill A and B with their given equations

5x-18=3x+42

Now we solve

2x=60

x=30

Now that we know x is 30, we can replace it in the equation for A

5x-18

5(30)-18

150-18

132 degrees

Answer:

132

Step-by-step explanation:

ANGLE A = ANGLE B

(INTERIOR ALTERNATE ANGLES)

5x - 18 = 3x  + 42

2x = 60

x = 30

angle a = 150 - 18

= 132

Answer:

a² + b² = c²

13² + 13² = c²

169 + 169 = c²

338 = c²

c = √338 or 18.385 or 13√2

Answer:

18.4

Step-by-step explanation:

13² + 13² = x²

169 + 169 = x²

338 = x²

x = 18.38477....

Answer:

work is pictured and shown

Answer:

86.28 ft²

Step-by-step explanation:

The figure given consists of a rectangle and a semicircle.

The area of the figure = area of rectangle + area of semicircle

Area of rectangle = [tex] l*w [/tex]

Where,

l = 10 ft

w = 8 ft

[tex] area = l*w = 10*8 = 80 ft^2 [/tex]

Area of semicircle:

Area of semicircle = ½ of area of a circle = ½(πr²)

Where,

π = 3.14

r = ½ of 8 = 4 ft

Area of semi-circle = ½(3.14*4) = 6.28 ft²

Area of the figure = area of rectangle + area of semi-circle = 80 + 6.28 = 86.28 ft² (nearest hundredth)

Answer:

the area of the figrue is 105.12

Step-by-step explanation:

Answer:

38 = JKL

Step-by-step explanation:

JKM = JKL + LKN + NKM

Substituting what we know

104 = JKL + LKN +33

KN  bisects LKM so NKM =  LKN

33 =  LKN

104 = JKL + 33 +33

104 = JKL + 33 +33

Combine like terms

104 = JKL +66

104 - 66 = JKL

38 = JKL

Answer:  ∡JKL=38°

Step-by-step explanation:

KN bidects ∡LKM => ∠KLN=∡NKM=33°

=> ∡LKM=∠KLN+∡NKM=33°+33°=66°

=>∡JKL= ∡JKM-∡LKM= 104°-66°=38°

∡JKL=38°

Answer:

[tex]V_2=305.14\ \text{inch}^3[/tex]

Step-by-step explanation:

The volume of a gas in a container varies inversely as the pressure on the gas.

[tex]V\propto \dfrac{1}{P}\\\\V_1P_1=V_2P_2[/tex]

If V₁ = 356 inch³, P₁ = 6 pounds/in², P₂ = 7 pounds/in², V₂ = ?

So, using the above relation.

So,

[tex]V_2=\dfrac{V_1P_1}{P_2}\\\\V_2=\dfrac{356\times 6}{7}\\\\V_2=305.14\ \text{inch}^3[/tex]

So, the new volume is [tex]305.14\ \text{inch}^3[/tex].

Answer:

-1

Step-by-step explanation:

Twice a number of 4 equals 8

4×2=8

less than 9 of the quotient (answer) of twice a number of 4, is -1

8-9= -1

The required expression for Nine less than the quotient of twice a number and four gives the equation, y =2x/4 - 9.

An expression Nine less than the quotient of twice a number and four. is to be determined.

The process in mathematics to operate and interpret the function to make the function simple or more understandableis called simplify and the process is called simplification.

The quotient is the result when one value gets divided by some other value.

Using simple arithmetic,
Let the number be x,
A number y is equal to nine less than the quotient of twice of x and four. So,
y = quotient of 2x and four - 9
y = 2x/4 - 9

Thus, the required expression for Nine less than the quotient of twice a number and four gives the equation, y =2x/4 - 9.

Learn more about simplification here: https://brainly.com/question/12501526

#SPJ5

Answer:

[tex]g(x) = 0.5^{(x+3)}[/tex]

Step-by-step explanation:

Assuming f(x) = [tex]0.5^{x}[/tex] is a correct interpretation of f(x),

the way to translate three units to the left is to change x to x+3.  This gives our answer:   [tex]g(x) = 0.5^{(x+3)}[/tex]

Answer:

B. g(x) = (1/2)⁽ˣ⁺³⁾

Hope this helps!

Step-by-step explanation:

a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,

6! = 6 [tex]*[/tex] 5

= 30 [tex]*[/tex] 4

= 360 [tex]*[/tex] 2 = 720 possible ways to order 6 people in a row

b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.

5! = 5 [tex]*[/tex] 4

= 20 [tex]*[/tex] 3

= 120 [tex]*[/tex] 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.

In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )

c. With each husband on the left, there are 3 people left, all women, that we have to consider here.

3!  = 3 [tex]*[/tex] 2 6 ways to arrange 3 couples in a row, the husband always to the left

(a) The average value of f(x) on the closed interval [0, π] is

[tex]\displaystyle\frac1{\pi-0}\int_0^\pi f(x)\,\mathrm dx = \frac1\pi\int_0^\pi(8\sin(x)-4\sin(2x))\,\mathrm dx = \boxed{\frac{16}\pi}[/tex]

(b) By the mean value theorem, there is some c in the open interval (0, π) such that f(c) = 16/π. Solve for c :

8 sin(c) - 4 sin(2c) = 16/π

8 sin(c) - 8 sin(c) cos(c) = 16/π

sin(c) - sin(c) cos(c) = 2/π

Use a calculator to solve this. You should get two solutions, c ≈ 1.2382 and c ≈ 2.8081.

Answer:

5

Step-by-step explanation:

This shape is formed by two right triangles.

Let's start by the little one.

Let y be the third side.

Using the Pythagorian theorem we get:

y^2 = 6^2 + 3^2

y^2 = 36 + 9

y^2 = 45

y = 3√(5)

●●●●●●●●●●●●●●●●●●●●●●●●

Now let's focus on the second triangle. Let z be the third side.

The Pythagorian theorem:

6^2 + x^2 = z^2

Using the Pythagorian theorem on the big triangle :

[3√(5)]^2 + z^2 = (3+x)^2

45 + z^2 = 3x^2 + 6x + 9

36 +z^2 = 3x^2 +6x

So we have a system of equations.

36+ x^2 = z^2

36 +z^2 = 3x^2 +6x

We want to khow the value of x so we will eliminate z .

Add (36+x^2 -z^2 =0) to the second one.

36 + x^2-z^2+36+z^2 = 3x^2+6x

72 + x^2 = 3x^2 +6x

72 - 2x^2 -6x = 0

Multipy it by -1 to reduce the number of - signs

2x^2 + 6x -72 = 0

This is a quadratic equation

Let A be the discriminant

● a = 2

● b = 6

● c = -72

A = b^2-4ac

A = 36 -4*2*(-72) = 36 + 8*72 =612

So this equation has two solutions

The root square of 612 is approximatively 25.

● (-6-25)/4 = -31/4 = -7.75

● (-6+25)/4 = 19/4 = 4.75 wich is approximatively 5

A distance cannot be negative so x = 5

Answer:

no of new computers sold : 8

no. of refurbished computer sold : 12

Step-by-step explanation:

Let the no. of new computers sold be x

let the no. of refurbished computers sold be y

Given

In March, the store sold 20 computers

x + y = 20

y = 20-x ----- equation 2

selling price of new computer = $500

selling price of x new computer = 500*x = 500x

selling price of refurbished computer = $200

selling price of y refurbished computer = 200*y = 200y

Total selling price of x new computer and y refurbished computers = 500x+200y

given that

total prioce of computer is $6400

thus

500x+200y = 6400

using y = 20-x  from equation 2

500x+200(20-x) = 6400

=> 500x+ 4000 - 200x = 6400

=> 300x = 6400 - 4000 = 2400

=> x = 2400/300 = 8

Thus,

no of new computers sold = 8

no. of refurbished computer sold = 20 -8 = 12

Answer:

3^x( 2-3^x)

Step-by-step explanation:

f(x) = 3^x and g(x) = 3^2x - 3^x

h(x) = f(x) - g(x)

       3^x - ( 3^2x - 3^x)

Distribute the minus sign

         3^x - 3^2x + 3^x

     2 * 3^x - 3 ^ 2x

Rewriting

We know that 3^2x = 3^x * 3^x

2 * 3^x - 3^x* 3^x

Factoring out 3^x

3^x( 2-3^x)

Answer:

if he needs to walk, we can see that between the street and his house he must walk 4 times a distance of 0.5km, so this is a total of 4¨*0.5km = 2km.

Now he has a jet-pack, he can ignore the buildings and just travel in the shorter path, so we can draw a triangle rectangle, in such a way that the hypotenuse of this triangle is the distance between the home and the school.

One of the cathetus is the vertical distance, in this case, is 1km, and the other one is the horizontal distance, also 1km.

So the actual distance is given by the Pythagorean's theorem:

A^2 + B^2 = H^2

Where A and B are the cathetus, and H is the hypotenuse, then:

H^2 = 1km^2 + 1km^2

H = (√2)km = 1.41km.

Now, in the case that he has a jet-pack, he can actually go to the school using this hypotenuse line as his path, so in this case the distance and the displacement would be the same.

Distance: "how much ground an object has covered"

Displacement: "Difference between the final position and the initial position"

When he walks, the distance is 2km, but the displacement is 1.41km

When he uses the jet-pack, both the distance and the displacement are 1.41km

Answer and Step-by-step explanation:

The first thing is we can see in the image, when he walks, that between the house and his school he has to walk four times a distance of 0.5 km.  The result of this is a total of 4¨*0.5 km = 2 km.  The second thing is that he must walk 2 kilometers.  On the other hand, if he has a jetpack, he can simply take the shorter path by ignoring all the buildings.  This idea is where we can draw a triangular rectangle on the map in a way so that the hypotenuse of the triangle is the distance between the school and the home.  As for the Catheti, it is a vertical distance which in this case is two blocks of 0.5 km.  The result is that these catheti have a length of 2*0.5 km = 1 km.  The other is the distance of the horizontal line, which is 1 km.  The absolute distance of this path is given by Pythagorean's theorem, which is A^2 + B^2 = H^2.  Here, A and B are the cathetus, and H is the hypotenuse, then, H^2 = 1 km^2 + 1 km^2.  As well, H = (√2)km = 1.41 km.  Currently, in the situation where he has a jetpack, he can literally fly to the school utilizing this hypotenuse line for the path he would need to follow.  For this specific situation, the displacement, and the distance would be the exact same.  The reason for this is that the definitions of displacement and distance are displacement is the difference between the final position and the initial position and distance is how much area an item has covered.  Also, when he walks, the distance is 2 km and the displacement is 1.41 km.  Also, when he utilizes the jet pack, the distance is equal to the displacement.  Both of these are 1.41 km.

Answer:

The 99% confidence interval is  [tex]71.67 < \mu < 78.33[/tex]

Step-by-step explanation:

From the question we are told that

     The sample  size  is  [tex]n = 15[/tex]

      The  sample  mean is  [tex]\= x = 75[/tex]

        The  standard deviation is  [tex]s = 5[/tex]

 Given that confidence is  99%  then the level of significance is mathematically represented as

              [tex]\alpha = 100 - 99[/tex]

             [tex]\alpha = 1\%[/tex]

             [tex]\alpha = 0.01[/tex]

Next we obtain the critical values of  [tex]\frac{ \alpha }{2}[/tex] from the normal distribution table

   The  value is

                  [tex]Z_{\frac{ \alpha }{2} } = 2.58[/tex]

Generally the margin for error is mathematically represented as

            [tex]E = Z_{\frac{ \alpha }{2} } * \frac{ s}{ \sqrt{n} }[/tex]

=>         [tex]E = 2.58 * \frac{ 5}{ \sqrt{15} }[/tex]

=>         [tex]E = 3.3307[/tex]

   The  99% confidence interval is mathematically represented as

             [tex]\= x -E < \mu < \= x +E[/tex]

=>          [tex]75 - 3.3307 < \mu <75 + 3.3307[/tex]

=>          [tex]71.67 < \mu < 78.33[/tex]

Answer:

75 yards long and 90 yards wide.

Step-by-step explanation:

Let's first find the perimeter of the main rectangle:

100x2 + 65x2 =

330

_________________________________________

Next we need to find two numbers that match:

75 and 90

75x2 + 90x2 =

330

_________________________________________

75x90 is 6750 (More Area)

100x60 is 6500 (Less Area)

Answer:

106.68 centimeters

Step-by-step explanation:

40.64 cm/16 in = x cm/42 in

Cross multiplying, we get:

16x = 40.64(42)

16x = 1706.88

x = 106.68 centimeters

Answer:

7). x = 3.2, AC = 42.8

8). a = 6, YZ = 38

Step-by-step explanation:

It is given in the question that a point B is between A and C of the line segment AC.

⇒ AB + BC = AC

By substituting the values of segments,

5x + (9x - 2) = (11x + 7.6)

14x - 2 = 11x + 7.6

14x - 11x = 7.6 + 2

3x = 9.6

x = 3.2

Therefore, AC = 11x + 7.6

                        = 11(3.2) + 7.6

                        = 35.2 + 7.6

                        = 42.8

Question (8).

If Y is a point between X and Z,

⇒ XY + YZ = XZ

By substituting the measures of these segments given in the question,

(3a - 4) + (6a + 2) = (5a + 22)

9a - 2 = 5a + 22

9a - 5a = 22 + 2

4a = 24

a = 6

Since, length of segment YZ = 6a + 2

                                                = 6(6) + 2

                                                = 38

Answer:

Reserve rate = 9%

Step-by-step explanation:

Reserve ratio/rate is the percentage of deposits which commercial banks are required to keep as cash, as directed by the central banks.

first, let us calculate the reserve amount as follows:

Reserve = Deposit - (free amount to lend out)

Reserve = 28,000 - 25,480 = $2,520

[tex]Reserve\ rate = \frac{Reserves}{Deposits} \times100\\Reserve\ rate = \frac{2520}{28000} \times100\\=\frac{252000}{28000} =9\%[/tex]

Therefore the reserve rate = 9%

Answer:

[tex] - 24 + 16i + 45i + 15 = 9 + 61i[/tex]

Answer:

Step-by-step explanation:

The first thing you want to do is to factor in any quadratic equation.

So, -10(x^2-25)

Now, we see this is a special case, whenever we see a equation in this case, x^2 - b^2, we factor it to this (x+b)(x-b)

So, -10(x+5)(x-5)

x = -5 and x = 5

Answer:

C. $37.76

Step-by-step explanation:

30% of $49.95

=30/100×49.95

=$14.99

selling price = 49.95 -14.99

= $34.96

8% sales tax included

=8/100×34.96

=$2.80

new price= 34.96+2.80

=$37.76

Answer:

Option (D)

Step-by-step explanation:

By applying Sine rule in the right ΔABD,

Sin(A) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

Sin(60)° = [tex]\frac{\text{BD}}{\text{AB}}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{\text{BD}}{7\sqrt{3}}[/tex]

BD = [tex]7\sqrt{3}\times \frac{\sqrt{3} }{2}[/tex]

     = [tex]\frac{21}{2}[/tex]

Now by applying Cosine rule in the right ΔBDC,

Cos(45)° = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2}}=\frac{\frac{21}{2}}{x}[/tex]

x = [tex]\frac{21}{2}\times \sqrt{2}[/tex]

x = [tex]\frac{21\sqrt{2}}{2}[/tex]

Therefore, Option (D) is the correct option.

*Correct Question:

Which relationships have the same constant of proportionality between y and x as the equation 3y=27x?

Answer:

A, B, C

Step-by-step explanation:

Given that [tex] 3y = 27x [/tex] , we can simplify to get a proportionality statement that exists between X and y. Thus

[tex] 3y = 27x [/tex]

Divide both sides by 3

[tex] \frac{3y}{3} = \frac{27x}{3} [/tex]

[tex] y = 9x [/tex]

Thus, we can say, y would always be 9 times the quantity of x.

From the options given, examine which options have this proportionality statement as well.

Option A, y = 9x is same as the statement.

Option B, 2y = 18x, conforms to the same statement. If we simply further, we would have y = 9x

Option C, the graph shows that when x = 1, y = 9. This also confirms to the same constant of proportionality in the given equation.

Option D and E do not have same constant of proportionality.

The right options are A, B, and C.

Answer:

6720 in ^3

Step-by-step explanation:

Volume = length * width * height

            = 30*16*14

                =6720 in ^3

Answer:

Answer is D.

Step-by-step explanation:

do 4 times every value in the ( )

Answer:

[tex]\boxed{\sf D}[/tex]

Step-by-step explanation:

The area is given by the integral

[tex]\displaystyle A=2\pi\int_Cx(t)\,\mathrm ds[/tex]

where C is the curve and [tex]dS[/tex] is the line element,

[tex]\mathrm ds=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt[/tex]

We have

[tex]x(t)=t+\sqrt 2\implies\dfrac{\mathrm dx}{\mathrm dt}=1[/tex]

[tex]y(t)=\dfrac{t^2}2+\sqrt 2\,t+1\implies\dfrac{\mathrm dy}{\mathrm dt}=t+\sqrt 2[/tex]

[tex]\implies\mathrm ds=\sqrt{1^2+(t+\sqrt2)^2}\,\mathrm dt=\sqrt{t^2+2\sqrt2\,t+3}\,\mathrm dt[/tex]

So the area is

[tex]\displaystyle A=2\pi\int_{-\sqrt2}^{\sqrt2}(t+\sqrt 2)\sqrt{t^2+2\sqrt 2\,t+3}\,\mathrm dt[/tex]

Substitute [tex]u=t^2+2\sqrt2\,t+3[/tex] and [tex]\mathrm du=(2t+2\sqrt 2)\,\mathrm dt[/tex]:

[tex]\displaystyle A=\pi\int_1^9\sqrt u\,\mathrm du=\frac{2\pi}3u^{3/2}\bigg|_1^9=\frac{52\pi}3[/tex]