Solve by factorisation.
3x² + 10x - 8 = 0

Answers

Answer 1

Answer:

3x²+12x-2x-8. = 0

3x(X+4)-2(X+4) = 0

(x+4)(3x-2) =0

[tex]x = (- 4) \: or \: x = \frac{2}{3} \: are \: the \: solutions[/tex]


Related Questions

if possible help me in this. I need to find the two odd numbers...​

Answers

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

Answer:  x+2

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

Answer: x^2 + (x+2)^2 = 394

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\[/tex]

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

Answer: Either 13, 15  or  -15, -13

In a right angle triangle ABC angle B=90⁰ and AB+BC= 31cm AB-BC=17 cm the find sinA,cosA,sinC,cosC.​

Answers

Answer:

see explanation

Step-by-step explanation:

Given

AB + BC = 31

AB - BC = 17

Add the 2 equations

2AB = 48 ( divide both sides by 2 )

AB = 24

Substitute AB = 24 into the first equation

24 + BC = 31 ( subtract 24 from both sides )

BC = 7

Using Pythagoras' identity to find the hypotenuse AC

AC² = AB² + BC² = 24² + 7² = 576 + 49 = 625 ( take square root of both sides )

AC = [tex]\sqrt{625}[/tex] = 25

Then

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{7}{25}[/tex]

cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{24}{25}[/tex]

sinC = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{24}{25}[/tex]

cosC = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{7}{25}[/tex]

A lemonade recipe calls for 1/4 cups of lemon juice for every cup of water.

Plot the pairs in the table in a coordinate plane

Answers

Answer:

they are in order cross x with the y across from it

Step-by-step explanation:

which one is the right answers

Answers

Answer:

B

Step-by-step explanation:

n is the number of litres.

if you substitute 1 for 'n' then you will get :

C = 8 + 1.5(1)

C = $9.5

$9.50 for every litre

Answer:

C is correct

Step-by-step explanation:

The $8 charge is only once regardless of how many liters are ordered, so only answer C works.

Suppose a triangle has two sides of length 32 and 35, and that the angle
between these two sides is 120°. Which equation should you solve to find the
length of the third side of the triangle?
A. C2 = 322 + 352 – 2(32)(35)sin120°
B. sin32
sin35
b
120
C. C= 32 + 35 - 2(32)(35)cos120°
D. 2 = 322 + 352 - 2(32)(35)cos120°

Answers

Answer:

D

Step-by-step explanation:

It is the law of cos

C^2= A^2+B^2-2*A*B*cosL where L is the angle between A and B

so C = 32^2 + 35^2 - 2(32)(35)cos120°

what is the bionomial expansion of (x-1y)^2​

Answers

Answer:

[tex] {(x - y)}^{2} \\ = (x - y)(x - y)[/tex]

open the brackets:

[tex] = ( {x}^{2} - xy - xy + {y}^{2} ) \\ = {x}^{2} - 2xy + {y}^{2} [/tex]

Given two consecutive integers whose sum is 92, find the larger of the two integers.

Answers

Maybe i can help u (x+2)

56 = h/9
k/5 - 10 = 3
3t + 5 =2

Answers

Answer:

h = 504, k = 65, t = -1

Step-by-step explanation:

56 = h/9

h = 56 x 9

h = 504

k/5 - 10 = 3

k/5 = 3 + 10

k/5 = 13

k = 13 x 5

k = 65

3t + 5 = 2

3t = 2 - 5

3t = -3

t = -3/3

t = -1


Solve the inequality.
q + 12 - 2(q - 22) > 0

a.)9 <-32

b.)9 < 56

c.)9> -32

d.)9 > 56

Answers

[tex]\\ \sf\longmapsto q+12-2(q-22)>0[/tex]

[tex]\\ \sf\longmapsto q+12-2q+44>0[/tex]

[tex]\\ \sf\longmapsto q-2q+12+44>0[/tex]

[tex]\\ \sf\longmapsto -q+56>0[/tex]

[tex]\\ \sf\longmapsto -q>-56[/tex]

[tex]\\ \sf\longmapsto q<56[/tex]

Please Help and thank you so much!!

Answers

The probably of getting prime is 50%=0.5=1/2

Need helppppp asappppppp

Answers

Answer:

162

Step-by-step explanation:

because this is a parallelogram :

m<2 = m<4 so

4x - 22 = 3x - 12

4x - 3x = 22 - 12

x = 10 replace x with 10 in the equation for m<4

3x - 12 is 30 - 12 = 18

m<4 and m<1 are supplementary and their sum is equal to 180

m<4 + m<1 = 180

m<1 = 180 - 18

m<1 = 162

f(x)=-4+7, what is f(2)

Answers

Answer:

3

Step-by-step explanation:

7-4

please help me Find DE.

Answers

Answer:

DE = 11

Step-by-step explanation:

DF = DF +EF

4x+2 = x+7 + 7

Combine like terms

4x+2 = x+14

Subtract x from each side

4x+2-x = x+14-x

3x+2 = 14

Subtract 2 from each side

3x+2-2 =14-2

3x=12

Divide by 3

3x/3 = 12/3

x = 4

DE = x+7 = 4+7 =11

Answer:

DE is 11

Step-by-step explanation:

[tex]DE = DF - EF \\ DE = (4x + 2) - 7 \\DE = 4x - 5 [/tex]

But for x:

[tex]4x + 2 = (x + 7) + 7 \\ 4x + 2 = x + 14 \\ 3x = 12 \\ x = 4[/tex]

Therefore:

[tex]DE = (4 \times 4) - 5 \\ = 16 - 5 \\ = 11[/tex]

28. find the range…
please help!!!

Answers

Answer:

A

Step-by-step explanation:

lm‎ao this problem is b‎u‎l‎ls‎h‎‎‎i‎t because the actual answer would be [2, 2] U (7, infty) but thats literally not there, so ig the closest one would be [2, infty) which is A

if it was asking for the domain on the other hand, then it would be B lm‎ao

but I would go with A

Find the area of the rectangle with the length 2x-4 and height of -3

Answers

Answer:

-3(2x-4) or -6x+12

Step-by-step explanation:

Area is H*W

theres no value for x so that would be it, unless there is then all you do is plug that into the answer I put.

Find the equation of the line:
through (5, -1) and (2, 2).

Answers

Answer:

y = -x + 4

Step-by-step explanation:

(x₁,y₁)= (5, - 1)    & (x₂,y₂)= (2 , 2)

Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

         [tex]\frac{2-[-1]}{2-5}\\\\=\frac{2+1}{-3}\\\\=\frac{3}{-3}\\\\= -1[/tex]

m = -1

Equation of the line y - y₁ = m(x - x₁)

y  - [-1] = (-1)*(x - 5)

y + 1 = -x + 5      {-1 is distributed}

y = -x + 5 - 1

y = -x + 4

Which expressions are equivalent to
3(6+b) + 2b+1?
Select 2 answers.
Step 1 - Use the distributive property and pick your first
answer
Step 2 - Combine like terms and pick your second
answer

Answers

Step-by-step explanation:

3(6+b)+2b+1

18+3b+2b+1

5b+19

Once we distribute 3(6+b), 18 + 3b + 2b + 1. Our first answer is B. Next, we can combine like terms. This gives us 5b + 19. The other answer is C.

What are the domain and range of f(x) = |x + 6|? Domain: (negative infinity, infinity); range: f(x) > 0 domain: x < -6; range: (negative infinity, infinity) domain: x > -6; range: (negative infinity, infinity) domain: (negative infinity, infinity) ; range: f(x) < 0

Answers

Answer:

Domain: [tex](-\infty,\infty)[/tex]

Range: [tex]f(x) \ge 0[/tex]

Step-by-step explanation:

Given

[tex]f(x) = |x + 6|[/tex]

Required

The domain and the range

First, we calculate the domain

[tex]f(x) = |x + 6|[/tex]

The above function does not have roots or fraction, where x is the denominator. This means that the domain is all real numbers, i.e. [tex](-\infty,\infty)[/tex]

The range

The function is an absolute function; So, the minimum value is 0.

Hence, the range is:

[tex]f(x) \ge 0[/tex]

Answer:

A

Step-by-step explanation:

on edge

Christa needs to make a painting for art class.
She can only choose two of the eight colors listed
in the table above. What is the probability the two
colors she chooses are green and purple?

Answers

1/64
Because it is a
1/8 she gets green and a 1/8 she gets purple after so u multiply and get 1/64

If 24n-¹ + 3 = 7 What is the value of n​

Answers

Answer:n=6

Step-by-step explanation:

WILL GIVE BRAINLIEST PLS HELP

Answers

Answer:

Hello

Step-by-step explanation:

[tex]y=2x^2-12x+19\\=2(x^2-6x)+19\\=2(x^2-2*3*x+9)+19-18\\=2(x-3)^2+1\\\\Vertex\ is\ (3,1)\\\\Axis\ of\ symmetry\ is\ x=3\\\\y-intercept\ is \\\\y=2(0-3)^2+1=19\\[/tex]

Rewrite in simplest terms (-9x-2y)+(4x-5y)

Answers

Answer:

-5x - 7y

Step-by-step explanation:

-5x - 7y is the simplified answer to this question. Pls leave a thanks!

Brady scored a total of 320 points last season for his basketball team. This season, the team
added 2 extra games to the schedule. Brady thinks this will allow him to increase the total
number of points he scores by 5%. How many points is Brady expecting to score this season?

a. 336
b. 325
c. 304
d. 16

Answers

Brady is expecting 325 points this season.

In January Mr.Tan's students read 20 books. In February, they read 15 books. What is the percent increase or decrease in the number of books the read?

Answers

Answer:

there is a 25% decrease in books being read

Find the area of the circle.
Use 3.14 for it. Do not round your answer.
Hint: A = Tira
14 inches
Area = [?] inches?
Enter the number that
belongs in the green box.

Answers

Use the formula given. R is half the diameter

R = 14/2 = 7 inches.

Area = 3.14 x 7^2

Area = 153.86 inches^2

Answer:

Does the answer help you?

Banners at the school’s store we’re on sale for $4 off the regular price. Mike brought 5 banners on sale and paid a total of $20. Write and solve an equation to find the regular price of one banner.

Answers

Answer:

$8

Step-by-step explanation:

Let the regular price is x, then:

(x - 4)*5 = 20x - 4 = 20/5x - 4 = 4x = 4 + 4x = 8

Multiply the polynomial by distribution. Show your work and explain the steps you used to solve.
- 8x(x^2 – 8x + 3)

Answers

Answer:

-8x^3 + 64x^2 - 24x

Step-by-step explanation:

To distribute, we must multiple -8x to each term:

-8x(x^2) - 8x(-8x) - 8x(3)

-8x^3 + 64x^2 - 24x

Step-by-step explanation:

[tex] - 8x( {x}^{2} - 8x + 3) \\ = ( - 8x \times {x}^{2}) - ( - 8x \times 8x) + ( - 8x \times 3) \\ = - 8 {x}^{3} + 64 {x}^{2} - 24x[/tex]

distribute -8x to each term in the perenthesis i.e. multiply each term by -8x

which is odd one out 4:10 12:25 20:50 8:20​

Answers

Answer:

All of them except 12:25 simply to 2:5. So 12:25 is the odd one out.

what is the difference of the fractions?
-2 1/2 - (-1 3/4)​

Answers

Answer:

-3/4

Step-by-step explanation:

First, let's convert the mixed numbers into improper fractions in an effort to make this problem easier to solve.

-2 1/2 as a mixed number is -5/2 and -1 3/4 as a mixed number is -7/4.

Our problem is now -5/2 - (-7/4).

We still can't solve this because the two fractions do not share a common denominator. 4 can serve as one, so -5/2 with a denominator of 4 would be -10/4.

The problem is now -10/4 - (-7/4).

Two negatives make a positive so the problem can be rewritten as -10/4 + 7/4. The final answer is -3/4.

PLEASE HELP QWQ AsAp with these 4 questions

Answers

Answer:

Step-by-step explanation:

I can't believe I'm doing this for 5 points, but ok!

For the first 3, we are going to multiply to find the value of that 3 x 3 matrix by picking up the first 2 columns and plopping them down at the end and then multiplying through using the rules for multiplying matrices:

[tex]\left[\begin{array}{ccccc}7&4&6&7&4\\-4&8&9&-4&8\\1&8&7&1&8\end{array}\right][/tex]  and from there find the sum of the products of the main axes minus the sum of the products of the minor axes, as follows (I'm not going to state the process in the next 2 problems, so make sure you follow it here. This is called the determinate. The determinate is what you get when you evaluate or find the value of a matrix. Just so you know):

[tex](7*8*7)+(4*9*1)+(6*-4*8)-[(1*8*6)+(8*9*7)+(7*-4*4)][/tex] which gives us:

392 + 36 - 192 - [48 + 504 - 112] which simplifies to

236 - 440 which is -204

On to the second one:

[tex]\left[\begin{array}{ccccc}-8&-4&-1&-8&-4\\1&7&-3&1&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us

[tex](-8*7*9)+(-4*-3*8)+(-1*1*9)-[(8*7*-1)+(9*-3*-8)+(9*1*-4)][/tex] which gives us:

-504 + 96 - 9 - [-56 + 216 - 36] which simplifies to

-417 - 124 which is -541, choice c.

Now for the third one:

[tex]\left[\begin{array}{ccccc}-2&-2&-5&-2&-2\\2&7&-3&2&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us

[tex](-2*7*9)+(-2*-3*8)+(-5*2*9)-[(8*7*-5)+(9*-3*-2)+(9*2*-2)][/tex] which gives us:

[tex]-126+48-90-[-280+54-36][/tex] which simplifies to

-168 - (-262) which is 94, choice c again.

Now for the last one. I'll show you the set up for the matrix equation; I solved it using the inverse matrix. So I'll also show you the inverse and how I found it.

[tex]\left[\begin{array}{cc}-4&-5&\\-6&-8\\\end{array}\right][/tex] [tex]\left[\begin{array}{c}x\\y\\\end{array}\right][/tex] = [tex]\left[\begin{array}{c}-5\\-2\\\end{array}\right][/tex] and I found the inverse of the 2 x 2 matrix on the left.

Find the inverse by:

* finding the determinate

* putting the determinate under a 1

* multiply that by the "mixed up matrix (you'll see...)

First things first, the determinate:

|A| = (-4*-8) - (-6*-5) which simplifies to

|A| = 32 - 30 so

|A| = 2; now put that under a 1 and multiply it by the mixed up matrix. The mixed up matrix is shown in the next step:

[tex]\frac{1}{2}\left[\begin{array}{cc}-8&5\\6&-4\end{array}\right][/tex]  (to get the mixed up matrix, swap the positions of the numbers on the main axis and then change the signs of the numbers on the minor axis). Now we multiply in the 1/2 to get the inverse:

[tex]\left[\begin{array}{cc}-4&\frac{5}{2}\\3&-2\\\end{array}\right][/tex] Multiply that inverse by both sides of the equation. This inverse "undoes" the matrix that's already there (like dividing the matrix that's already there by itself) which leaves us with just the matrix of x and y. Multiply the inverse matrix by the solution matrix:

[tex]\left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{cc}-4&\frac{5}{2} \\3&-2\end{array}\right] *\left[\begin{array}{c}-5&-2\\\end{array}\right][/tex] and that right side multiplies out to

x = 20 - 5 which is

x = 15 and

y = -15 + 4 which is

y = -11

(It works, I checked it)

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