Solve for 0 or x, round to the nearest tenth.

Answer:

2x+5x^2=1

2x+5x*5x=1

2x+25x=1

27x=1

1/27=x

Hope This Helps!!!

Answer:

D. 24

Hope it helps!

Answer:

3/2

Step-by-step explanation:

formula k = y/x

comes from

y = kx

k = constant of variation

when y = 3 , x = 2

k = 3/2

Answer:

Step-by-step explanation:

Perimeter of the rectangle = P

Base = b

Height = h

Area = A

P = 2b + 2h

P = 66

STEP 1:

2(2x + 1) + 2(x + 5) = 66

Distribute

4x + 2 + 2x + 10 = 66

STEP 2:

Combine like terms and isolate the variable

6x + 12 = 66

6x = 54

x = 9

STEP 3:

Plug in x

A = (2(9) + 1) * (9 + 5)

STEP 4:

Simplify

A = (18 + 1) * (14)

A = (19)(14)

A = 266

[tex]\displaystyle\bf P=2(2x+1+x+5)=66\\\\6x+12=66\\\\6x=54\\\\\boxed{x=9}\\\\2x+1=19\\\\x+5=14 \\\\S=ab=14\cdot19=266 cm^2[/tex]

Answer:

(f + g)(x) = 3^x + 12x -4

Step-by-step explanation:

Here, we want to get the value of (f + g)(x)

Mathematically, we have this as;

(f + g)(x) = f(x) + g(x)

= 3^x + 10x + 2x-4

= 3^x + 12x -4

Answer:

B.

Step-by-step explanation:

Hello again,

"katie deleted your answer to the question Hello,a=2, b=8, c=-1Indeed,y=f(x)=ax...

You've been warned"

Answer is a=2, b=8 and c=-1

Indeed:

y=f(x)=ax²+bx+c

Since (-2,-9) is the vertex,

y=k*(x+2)²-9

Or f(-1)=-7 ==> -7=k*(-1+2)²-9 ==> k=2

f(x)=2(x+2)²-9=2*(x²+4x+4)-9=2x²+8x+8-9

f(x)=2x²+8x-1

A proof: the picture is following.

Within similar triangles, the angles are the same. So, we need to look at the side lengths then.

72 to 12

66 to 11

42 to 7

In each pair of corresponding side lengths, the original side length from triangle ABC is divided by 6 (or multiplied by 1/6) to get the smaller side length on triangle DEF.

The scale factor from ABC to DEF is 1/6.

Hope this helps!

Answer:

Mean = 2.33

Step-by-step explanation:

Given that,

conceded goals : 0 1 2 3 4

Frequency : 2 8 4 10 6

Mean,

[tex]M=\dfrac{\Sigma fx}{\Sigma f}\\\\M=\dfrac{0\times 2+1\times 8+2\times 4+3\times 10+4\times 6}{2+8+4+10+6}\\\\=\dfrac{70}{30}\\\\M=2.33[/tex]

So, the required mean is 2.33.

Answer:

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Step-by-step explanation:

The given expression to us is ,

[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]

Now take the LCM as ( x - 1 ) and Simplify , we have ,

[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]

Simplifying further , we get ,

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Hence the second option is correct.

Answer:

[tex] \frac{ \frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1)}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2} \\ \frac{ - 4x + 7}{2(x - 1)} \\ option \: b \: is \: your \: answer \\ thank \: you[/tex]

Answer:

Step-by-step explanation:

Answer:

x ≤ 3

Step-by-step explanation:

2(4+2x)≥5x+5

8+4x≥5x+5

4x-5x≥5-8

-x≥-3

x ≤ 3

[tex]\tt\displaystyle\2(4+2x)\geq 5x+5\\\\8+4x\geq 5x+5\\\\4x-5x\geq 5-8\\\\-x\geq -3\\\\x\leq 3 \\\\Answer: x\leq 3 \quad or \quad x\in(-\infty;3][/tex]

Answer:

Probably 10

Step-by-step explanation:

10/5=2

Answer:

Traversable because it has exactly two odd nodes

Step-by-step explanation:

There is a rule that says it is traversable if it has exactly 2 odd nodes. The are other rule where it can be traversable is if has no odd nodes.

Also if we let the starting point be D and the ending point be B we can travel the network in such way that each edge is only traveled once which is the definition that the network is traversable.

So I will do this by starting at D, then travel to A using the outside edge, then travel to back to D using inside edge, then travel to C, then travel to B, then travel to A using outside edge, and then back to B from A using inside edge.

Answer:

x= -5 + 5[tex]\sqrt{97}[/tex], x= -5 - 5[tex]\sqrt{97}[/tex]

Step-by-step explanation:

Since this quadratic is set to zero, we can use the quadratic formula to solve this.

x^2 + 10x - 2400 = 0​

Quadractic formula =  x= -b +- [tex]\sqrt{b^2 - 4ac}[/tex] /2a

For this equation:

a= 1, b=10, c=-2400

Plug these numbers into the equation and solve.

x= -10 +- [tex]\sqrt{10^2 - 4(1)(-2400}[/tex])/2(1)

x= -10 +- [tex]\sqrt{100 + 9,600}[/tex]/2

x= -10 +- [tex]\sqrt{9,700}[/tex]/2

x= -10 +- [tex]\sqrt{2^2 * 5^2 * 97}[/tex]/2

x= -10 +- 5 * 2[tex]\sqrt{97}[/tex]/2

x= -10 +- 10[tex]\sqrt{97}[/tex] / 2

Divide by 2.

x= -5 +- 5[tex]\sqrt{97}[/tex]

Answer:

x= -5 + 5[tex]\sqrt{97}[/tex] or x= -5 - 5[tex]\sqrt{97}[/tex]

Answer:

In picture

Step-by-step explanation:

Brainliest please~

[tex](0,3)[/tex] and [tex](1,-2)[/tex]

Equation: (refer the image below)

Slope:

[tex]m=\frac{3+2}{0-1}[/tex]

[tex]m=-5[/tex]

Equation:

[tex]y=5x-b[/tex]

[tex]3=b[/tex]

Substitute (0,3)

Point: [tex](1,-2)[/tex]

Answer:

38

Step-by-step explanation:

6⅓÷⅙

change 6⅓ to improper fraction

19/3÷1/6

keep the first fraction, change the division sign to multiplication and reciprocate/flip the second fraction

19/3× 6/1

the denominator 3 and numerator 6 will simplify/cancel each other

the new fraction is now: 19/1 × 2/1

there is no need to multiply the denominators because it will still be equal to 1 so we just need to multiply the numerators by each other

19×2=38 OR 38/1 (both answers are the same)

Step-by-step explanation:

hope it helps you..........

Answer:

[tex](\frac{2}{5} )^{3}[/tex] = [tex]\frac{8}{125}[/tex] [tex]cm^{3}[/tex]

Step-by-step explanation:

Answer:

F

Step-by-step explanation:I just took the test

Answer:

x = 9

Step-by-step explanation:

The ratios of corresponding sides are equal, that is

[tex]\frac{BC}{MN}[/tex] = [tex]\frac{AB}{LM}[/tex] , substitute values

[tex]\frac{x}{15}[/tex] = [tex]\frac{6}{10}[/tex] ( cross- multiply )

10x = 90 ( divide both sides by 10 )

x = 9

Answer:

x = 5

Step-by-step explanation:

Sides of large triangle: 4x and 15

Corresponding sides of small triangle: 3x + 1 and 12

[tex] \dfrac{4x}{15} = \dfrac{3x + 1}{12} [/tex]

[tex] 60 \times \dfrac{4x}{15} = 60 \times \dfrac{3x + 1}{12} [/tex]

[tex] 16x = 15x + 5 [/tex]

[tex] x = 5 [/tex]

The polynomials f(x) = x^2 + bx + 400 have -20 as its only zero then the value of b is 40.

The polynomials f(x) = x^2 + bx + 400 have -20 as its only zero

Then x=-20

The zeros of a polynomial p(x) are all the x-values that make the polynomial equal to zero.

x=-20 is the zero of the given polynomial

Therefore it satisfies the given polynomial

[tex]f(-20)=(-20)^2+b(-20)+400[/tex]

[tex]0=400-20b+400\\800-20b=0\\-20b=-800\\b=\frac{-800}{-20} \\b=40[/tex]

Therefore the value of b is 40.

To learn more about the zeros of the polynomials visit:

https://brainly.com/question/12461081

Answer:

y = 4x² - 43x + 178

Step-by-step explanation:

Given that data:

1 __ 137

2 __ 110

3 __ 93

4 __ 70

5 __ 65

6 __ 77

Usibg technology, the quadratic regression equation obtained is written in the form:

Ax² + Bx + C

A = 4.34 = 4 ( nearest whole number)

B = - 43.46 = - 43 (nearest whole number)

C = 178.3 = 178 ( nearest whole number)

Hence, the quadratic model is

y = 4x² - 43x + 178

By rounding the coefficients to the nearest whole number, the quadratic function that models the data is[tex]f(x) = 5x^2 - 42x + 174[/tex]

To find a quadratic function that models the data,  use a quadratic equation of the form:

[tex]f(x) = ax^2 + bx + c[/tex]

Let's use the given data points to form a system of equations and solve for the coefficients a, b, and c.

Using the first data point (month 1 with 137 births):

[tex]f(1) = a(1)^2 + b(1) + c = 137[/tex]

a + b + c = 137 (Equation 1)

Using the second data point (month 2 with 110 births):

[tex]f(2) = a(2)^2 + b(2) + c = 110[/tex]

4a + 2b + c = 110 (Equation 2)

Using the third data point (month 3 with 93 births):

[tex]f(3) = a(3)^2 + b(3) + c = 93[/tex]

This simplifies to:

9a + 3b + c = 93 (Equation 3)

Solve this system of equations will give us the values of a, b, and c.

Subtract Equation 1 from Equation 2

3a + b = -27 (Equation 4)

Subtract Equation 1 from Equation 3

8a + 2b = -44 (Equation 5)

Now  solve Equations 4 and 5 simultaneously.

Multiply Equation 4 by 2 and subtracting it from Equation 5:

8a + 2b - (6a + 2b) = -44 - (-54)

2a = 10

Divide both sides by 2:

a = 5

Now substitute the value of a back into Equation 4:

3(5) + b = -27

15 + b = -27

Subtract 15 from both sides:

b = -42

Finally, substitute the values of a and b into Equation 1

5 + (-42) + c = 137

-37 + c = 137

Add 37 to both sides:

c = 174

Therefore, the quadratic function that models the data is:

[tex]f(x) = 5x^2 - 42x + 174[/tex]

Rounding the coefficients to the nearest whole number, the quadratic function becomes:

[tex]f(x) = 5x^2 - 42x + 174[/tex]

Learn more on quadratic on https://brainly.com/question/1214333

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Answer:

x = 3

Step-by-step explanation:

Step-by-step explanation:

3(8x-8)/2=64

3(8x-8)=64×2

24x-24=128

24x=128+24

24x=152

24x/24=152/24

x=6.3

Answer:

5 years

Step-by-step explanation:

(x+15)=4x

15=4x-x

15=3x

5=x

Answer:

The probability of a person getting their own hat is 1/5 or 20%.

Step-by-step explanation:

If each person has one hat the chances (the probability) of them getting their own hat would be 20%. The chances (the probability) of them getting a hat that belongs to one of the other four students would be 80%. Due to there being 5 hats each person owns 1 hat so there would be a 1 out of 5 chance of them getting their own hat.

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3

Answer:

Step-by-step explanation:

If the product of 2 integers is -12, then that equation looks like this:

xy = -12

If the sum of those same 2 integers in 1, then that equation looks like this:

x + y = 1

Let's solve the second equation for x and plug it into the first equation. Solving the second equation for x gives us

x = 1 - y and plug that into the first equation in place of x to get:

(1 - y)y = -12 and

[tex]y-y^2=-12[/tex] Now move everything over to one side and factor to find y:

[tex]-y^2+y+12=0[/tex] and the 2 values for y are

y = -3 and y = 4. Let's see what happens when we solve for x.

If xy = -12 and y is -3:

x(-3) = -12 so

x = 4

If xy = -12 and y is4:

x(4) = -12 so

x = -3

So it looks like the 2 integers are -3 and 4

Answer:

If you are talking about inequalities, t < r.

Step-by-step explanation:

Since s is bigger than t and r is bigger than s,

r should be bigger than t obviously.

[tex]\sf \bf {\boxed {\mathbb {GIVEN:}}}[/tex]

Sum of three consecutive odd integers = [tex]27[/tex]

[tex]\sf \bf {\boxed {\mathbb {TO\:FIND:}}}[/tex]

The values of the three integers.

[tex]\sf \bf {\boxed {\mathbb {SOLUTION:}}}[/tex]

[tex]\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

Let us assume the three consecutive odd integers to be [tex]x[/tex], [tex](x+2)[/tex] and [tex](x+4)[/tex].

As per the condition, we have

[tex]Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27[/tex]

[tex]➺ \: x + (x + 2) + (x + 4) = 27[/tex]

[tex]➺ \: x + x + 2 + x + 4 = 27[/tex]

Now, collect the like terms.

[tex]➺ \: (x + x + x) + (2 + 4) = 27[/tex]

[tex]➺ \: 3x + 6 = 27[/tex]

[tex]➺ \: 3x = 27 - 6[/tex]

[tex]➺ \: 3x = 21[/tex]

[tex]➺ \: x = \frac{21}{3} \\[/tex]

[tex]➺ \: x = 7[/tex]

Therefore, the three consecutive odd integers whose sum is [tex]27[/tex] are [tex]\boxed{ 7 }[/tex], [tex]\boxed{ 9 }[/tex] and [tex]\boxed{ 11 }[/tex] respectively.

[tex]\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}[/tex]

[tex]⇢ 7 + 9 + 11 = 27[/tex]

[tex]⇢ 27 = 27[/tex]

⇢ L. H. S. = R. H. S.

[tex]\sf\blue{Hence\:verified.}[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]