Solve for X answer asap thanks

Answer:

PY = 14.5

Step-by-step explanation:

The diagonals of a rectangle are congruent and bisect each other, thus

XZ = WY , that is

4x - 1 = x + 7 + x + 7

4x - 1 = 2x + 14 ( subtract 2x from both sides )

2x - 1 = 14 ( add 1 to both sides )

2x = 15 ( divide both sides by 2 )

x = 7.5

Thus

PY = x + t = 7.5 + 7 = 14.5

Step-by-step explanation:

x+7+x+7= 4x-1

2x+14=4x-1

14= 2x-1

15= 2x (divide)

x = 7.5

wp= 7.5cm

not really sure

Answer:

k) the product of ant 2 odd numbers is odd

I don't know.

Let's check um out.

For each choice, I'll try to find an example to show that it's false.

F. The sum of any 2 even numbers is odd.  

    2+2=4. 4 is even. This one is false.

G. The sum of any 2 odd numbers is ood.

    3+3=6.  6 is even.  This one is false.

H. The quotient of any 2 even numbers is odd.

    8÷4=2. 2 is even. 10÷4=2.5.  2.5 is neither odd nor even. This one is false.

J. The quotient of any 2 even numbers is even.

   10÷2=5.  5 is odd.  This one is false.

K. The product of any 2 odd numbers is odd.

    I can't find an example where this is false.

    So I'm gonna say that this is the true one.

Answer:  A & C

Step-by-step explanation:

HL is Hypotenuse-Leg

A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   a leg from ΔABC ≡ a leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

B) a leg from ΔABC ≡ a leg from ΔFGH

   the other leg from ΔABC ≡ the other leg from ΔFGH

   Therefore LL (not HL) Congruency Theorem can be used.

C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   at least one leg from ΔABC ≡ at least one leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

D) an angle from ΔABC ≡ an angle from ΔFGH

   the other angle from ΔABC ≡ the other angle from ΔFGH

   AA cannot be used for congruence.

Answer:

2/5 =x

Step-by-step explanation:

4/10 = x/1

4/10 =x

Simplify

2/5 =x

Answer:

x=0.4

Step-by-step explanation:

4/10=0.4

x/1 has to equal 0.4 too

0.4/1

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

       ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                      PEACE!

Answer:

Which term is a term in this expression?

Step-by-step explanation:

Which term is a term in this expression?Which term is a term in this expression?Which term is a term in this expression?Which term is a term in this expression?Which in this expression?Which term is a term in this expression?

Answer:

  28 inches

Step-by-step explanation:

The point of intersection of the angle bisectors is the incenter. It is the center of a circle tangent to the three sides of the triangle. The circle has radius 2.

In the attached figure, we have labeled the points of tangency D, E, and F. We know that CE and CF are both of length 2, and we know that the points of tangency are the same distance from an external point where the tangents intersect. That means DA = FA and DB = EB.

The perimeter of the triangle is ...

  P = DA +DB +FA +EB +CF +CE

Using the above relations, this can be written as ...

  P = DA +DB +DA +DB +CF +CE = 2(DA +DB) +2(CE)

We are told that AB is 12 inches, so DA +DB = 12 inches. We also know that CE = 2 inches, so the perimeter is ...

  P = 2(12 in) + 2(2 in) = 28 in

The perimeter of triangle ABC is 28 inches.

Problem 1

The circumference is the full perimeter around the circle. You can think of it as the combination of "circle" and "fence" to get "circumference", but there might be other tricks to remember the term.

Anyways, the formula to get the circumference of a circle is

C = 2*pi*r

In this case, r = 14 is our radius so,

C = 2*pi*r

C = 2*pi*14

C = 28pi .... exact circumference in terms of pi

We only want a portion of this circumference as shown by the piece of the circle darkened. The fractional portion we want is 135/360 of a circle. Divide the angle by 360 to get the fractional portion you want. If the angle was say 180 degrees, then 180/360 = 1/2 is the fractional portion.

So we take 135/360 and multiply it by the value of C found earlier

arc length = (fractional portion)*(circumference)

arc length = (135/360)*28pi

arc length = 10.5pi

That's the exact arc length in terms of pi. Use a calculator to find that

10.5pi = 32.9867228626929

Or you could use pi = 3.14 to say

10.5*pi = 10.5*3.14 =  32.97

Which is fairly close to what the calculator is saying

-----------------

Exact arc length = 28pi

Approximate arc length (using calculator) = 32.9867228626929

Approximate arc length (using 3.14 for pi) = 32.97

Units are in feet

When I write "using calculator", I mean using the calculator's stored version of pi, instead of pi = 3.14

======================================================

Problem 2

We could use the same idea as problem 1, or we could use the formula below. The formula is just a quick way of encapsulating what I discussed earlier.

L = arc length

x = central angle

L = (x/360)*2*pi*r

L = (150/360)*2pi*13

L = (65/6)pi .... exact arc length

L = 34.0339204138894 .... approx arc length (using calculator)

L = 34.0166666666667 .... approx arc length (using 3.14 for pi)

-----------------

Exact arc length = (65/6)pi

Approximate arc length (using calculator) = 34.0339204138894

Approximate arc length (using 3.14 for pi) = 34.0166666666667

Units are in meters

Answer:

  range = {5, 2, -1, -4}

Step-by-step explanation:

Maybe you want the corresponding range.

  f({-1, 0, 1, 2}) = 2 -3{-1, 0, 1, 2} = 2 +{3, 0, -3, -6} = {5, 2, -1, -4}

false. range of [tex] \cos^{-1}(x)[/tex] is $[0,\pi]$

Answer:

D. sum of these edges is increased by 24 inches -- True

Step-by-step explanation:

Given a cube and its edge is increased by 2 inches.

To study the effect of this increase in the Volume, area of each face, diagonal and sum of edges.

Solution:

Let the side of original cube = a inches.

Formula for volume of cube:

[tex]V =side^3 = a^3[/tex]

If the side is increased by 2 inches, the side becomes (a+2) inches.

So, new volume, [tex]V' = (a+2)^3[/tex]

Using the formula:

[tex](x+y)^3 =x^3+y^3+3xy(x+y)[/tex]

[tex]V' = (a+2)^3 = a^3+8+3\times 2 \times a(a+2)=a^3+8+6a(a+2)[/tex]

So, [tex]V' = V + 8+6a(a+2)[/tex]

Volume increased by 8+6a(a+2) [which is not equal to 8]

So, statement is false:

A. volume is increased by 8 cubic inches  -- False

Each face in a cube is a square.

Area of each face, A = [tex]side^2 = a^2[/tex]

New area, A' = [tex](a+2)^2[/tex]

Using the formula: [tex](x+y)^2 =x^2+y^2+2xy[/tex]

[tex]A' = a^2+4+4a[/tex]

Area increased by 4+4a [which is not equal to 4 sq inches]

B. area of each face is increased by 4 square inches -- False

Diagonal of each face = [tex]a\sqrt2[/tex]

Increase of 2 in the edge:

New diagonal = [tex](a+2)\sqrt2 = a\sqrt2+2\sqrt2[/tex]

So, increase of [tex]2\sqrt2[/tex] not 2.

C. diagonals of each face is increased by 2 inches -- False

There are 12 number of edges in a square.

So sum of all 12 edges  = 12a

When edge is increased by 2, sum of all edges = 12(a+2) = 12a + 24

An increase of 24.

D. sum of these edges is increased by 24 inches -- True

Answer:

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

Step-by-step explanation:

Let the number of mangoes bought by the grocery store be n. Also let the number of mango sold for $3 in one stack be x and the number of mango sold for $6 in the second stack be y.

Therefore:

x + y = z                                  (1)

Also, the mangoes was sold at break even price, that is the cost of the mango and the price it was sold for was the same. Therefore:

Cost of buying = Price it was sold for

The cost of the mango = 5z and the price it was sold for = 3x + 6y

3x + 6y = 5z                            (2)

Substituting z = x + y in equation 1

3x + 6y = 5(x + y)

3x + 6y = 5x + 5y

6y - 5y = 5x - 3x

y = 2x

x / y = 1/ 2 = 1 : 2

The ratio of the number of mangoes in the $3 stack to those in the $6 stack is 1 : 2

Answer:

Hey there!

Part A. This is a proportional relationship because the amount of dollars she earns per hour is constant. We can divide her total income by the number of hours she works to find that she earns 12.50 dollars per hour.

Part B. Joslyn will always earn more money than Kate because she earns more money per hour, and the slope of Joslyn's line is greater.

Let me know if this helps :)

Answer:

1232.000

Step-by-step explanation:

Estimated distance across the river=1,232 meters

Find the approximate distance across the river to

the nearest thousandth of a meter

Note: Thousandth is having 3 values after the decimal point

This means we will round 1,232 meters to the nearest thousandth

1,232 is an whole number and decimal point can only be added at the end like this 1,232.

So we need 3 values after the decimal point.

We must add only values that wouldn't change the original 1,232 meters.

Therefore, zero (0) will be added

1232.000

Is to the nearest thousandth

Answer:

Step-by-step explanation:

The triangle inequality theorem states that the sum of any two sides of a triangle os greater than the third side.

■■■■■■■■■■■■■■■■■■■■■■■■■■

First triangle:

Let a,b and c be the sides of the triangle:

● a = 10

● b = 20

● c = 30

Now let's apply the theorem.

● a+b = 10+20=30

That's equal to the third side (c=30)

●b+c = 50

That's greater than a.

● a+c = 40

That's greater than b.

These aren't the sides of a triangel since the first inequality isn't verified.

■■■■■■■■■■■■■■■■■■■■■■■■■

Second triangle:

● a = 122

● b = 257

● c = 137

Let's apply the theorem.

● a+b = 379

That's greater than c

● a+c = 259

That's greater than b

● b+c = 394

That's greater than a

So 122,257 and 137 can be sides of a triangle.

■■■■■■■■■■■■■■■■■■■■■■■■■■

The third triangle:

● a = 8.6

● b = 12.2

● c = 2.7

Let's apply the theorem:

● a+b = 20.8

That's greater than c

● b+c = 14.9

That's greater than a

● a+c = 11.3

That isn't greater than b

So theses sides aren't the sides of triangle.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● a = 1/2

● b = 1/5

● c = 1/6

Let's apply the theorem.

● a+b = 7/10

That's greater than c

● a+c = 2/3

That's greater than b

● b+c = 11/30

That isn't greater than a

So these can't be the sides of a triangle.

Answer:

275 miles

Step-by-step explanation:

I assume all towns are on the same line. Then, town C is 5.5 cm from town A on the map since 3.5 cm + 2 cm = 5.5 cm.

The real distance can be calculated with a proportion.

2/100 = 5.5/x

2x = 5.5 * 100

2x = 550

x = 275

Answer: 275 miles

Answer:

is it 2

Step-by-step explanation:

Answer:

[tex]\boxed{y=2x-2}[/tex]

Step-by-step explanation:

Pick values from the table.

When x = 1, y = 0.

The third option seems right.

[tex]y=2(1)-2[/tex]

[tex]y=2-2[/tex]

[tex]y=0[/tex]

True.

Answer:

Step-by-step explanation:

70% of students are female

70/100* 75%= you get your answer

then subtract the percentage of the males and the females and then you get your answer

Answer:

18 feet

Step-by-step explanation:

to find the frame around the widow means need to find the perimeter around the window:

P=2l+2w

P= 2(5+4)

P=18 feet

Answer:

As property of a rectangle:

1. AC = 13

AC = 2 x EC (E is midpoint of AC and BD)

13 = 2 x (3x - 11)

13 = 6x - 22

35 = 6x

x = 35/6 m

2. DB = AC = 13 m( two diagonals are equal)

3. BAE = ABE = 40 degree

4. BDA = 90 - ABE = 90 - 40 = 50 (triangle ABD is a right triangle at A)

5. BC = AD = 5m (two opposite sides are equal)

6. AB = sqrt(BD^2 - AD^2) = sqrt(13^2 - 5^2) = sqrt(144) = 12 m

Perimeter = 2 x (AD + AB) = 2 x (5 + 12) = 2 x 17 = 34 m

7. Area= AD x AB = 5 x 12 = 60 m2

Answer:

[tex]\Large \boxed{\mathrm{78 \ units^2 }}[/tex]

Step-by-step explanation:

The area of the trapezoid can be found by adding the area of the triangle and the area of the rectangle.

Area of rectangle = base × height = 2 × 12 = 24 units²

Area of triangle = base × height × 1/2

The base is missing for the triangle. Apply Pythagorean theorem to solve for the base.

12² + b² = 15²

b = 9

9 × 12 × 1/2 = 54 units²

Adding the areas.

54 units² + 24 units² = 78 units²

Answer:

its 78 units on khan academy :)))

Step-by-step explanation:

[tex]f(x)[/tex] passes through origin, i.e. $(0,0)$

if you move 5 units up, it should pass through $(0,5)$

so you'll add 5 to $y$ i.e. $y+5=x^2$ this satisfies $(0,5)$

and to move right, it should pass through $(7,0)$ so you'll subtract $7$ from $x$ i.e. $y=(x-7)^2$

now combine both translations

$g(x)=(x-7)^2-5=x^2-14x+45$

Answer:

From scatter plot companies can predict future sales, and what will happen next. To help with this predictions most companies draw a line through the scattered plot called best-fit line. This line should be close to most of the points on the scattered line. Approximately half the point on the top of the line and half on the bottom.In this case the company will ignore the points tat far away from the line.

Scatter plots are useful to compare two variables to see how they relate to one another (if there is any relationship at all). One example could be comparing the temperature outside versus the sales of ice cream. The general trend is that the warmer it gets, the more sales you'll have. So there's an upward trend. We can also say there's a positive correlation as both variables go up together (or go down together).

Contrast this with negative correlation where one variable goes up and the other goes down (eg: hours spent watching tv versus exam score).

Of course, the ice cream example could be too simple and often overused, so it might be better to use something more specific to the company in question. If you picked a company dealing with health/medicine, then you could look at something like height versus weight and see if there's a correlation going on.

===================================

Explanation:

Start with the parent function [tex]y = |x|[/tex]

Replacing x with x-1 shifts the graph 1 unit to the right

Tack a -1 at the end to get [tex]y = |x-1|-1[/tex] which will shift everything down 1 unit.

The vertex started at (0,0) and moved to (1,-1)

Answer:

The correct option is;

D. 6,5

Step-by-step explanation:

TS and TU are midsegments

Segment PR = 18.2

Segment TS = 6.5

Given that TS is the midsegment of PR and PQ, therefore, TS = 1/2×QR

Which gives;

Segment QR = 2×TS = 2 × 6.5 = 13

Segment QR = 13

Given that TU is a midsegment to PQ and QR, we have that QU = UR

Segment QR = QU + UR (segment addition postulate)

Therefore, QR = QU + QU (substitute property of equality)

Which gives;

QR = 2×QU

13 = 2×QU

Segment QU = 13/2 = 6.5

The length of segment QU is 6.5.

Answer: Hi!

Okay. So this equation we will solve using something called the distributive property. We use the distributive property to multiply the terms inside the parentheses (x and -2) by the term outside and in front of the parentheses (4). First, we would multiply 4 * x, which is 4x. Then, we would multiply 4 * -2, which is -8. Out equation now looks like this:

4x - 8 = 14

Our goal is to isolate the x, so now we'll use inverse operations to remove the -8 from the equation. The inverse operation for subtraction is addition, so we would add 8 to both sides:

4x - 8 = 14

   + 8  + 8

The eights cancel out, so we're left with this equation:

4x = 22

Last step! We're almost done. All we have to do now is divide 4 on both sides; in the term 4x, 4 is being multiplied by x, so the inverse operation would be division.

4x ÷ 4 = x

22 ÷ 4 = 5.5

Our equation now looks like this:

x = 5.5

So, 5.5 is equal to x! This would be your answer!

Hope this helps!

Hi there! :)

Answer:

[tex]\huge\boxed{m\leq 2}[/tex]

Equation:

8m - 6 ≤ 10

Add 6 to both sides:

8m ≤ 16

Divide both sides by 8:

8m/8 ≤ 16/8

m ≤ 2

Answer:

8m - 6≤ 10

m≤2

Step-by-step explanation:

8m - 6≤ 10

Add 6 to each side

8m - 6+6≤ 10+6

8m ≤ 16

Divide each side by 8

8m/8 ≤16/8

m≤2

Answer:

When radius is doubled:

Circumference becomes double.

Area becomes four times.

When diameter is doubled:

Circumference becomes double.

Area becomes four times.

Step-by-step explanation:

Given that

Radius of a circle is doubled.

Diameter of circle is doubled.

To study:

The effect on circumference and area on doubling the radius and diameter.

Solution/explanation:

Let us discuss about the formula for circumference and area.

Formula for Circumference of a circle in form of radius:

[tex]C =2\pi r[/tex]

It is a linear equation in 'r'. So by doubling the radius will double the circumference.

Formula for Area of a circle in form of radius:

[tex]A =\pi r^2[/tex]

It is a quadratic equation in 'r'. So by doubling the radius will make the area as four times the earlier area.

Testing using example:

Let the initial radius of a circle = 7 cm

Initial circumference = [tex]2 \times \frac{22}{7} \times 7 = 44 cm[/tex]

Initial area = [tex]\frac{22}{7} \times 7 \times 7 =154 cm^2[/tex]

After doubling:

Radius = 14 cm

circumference = [tex]2 \times \frac{22}{7} \times 14 = 88 cm[/tex]   (Twice the initial circumference)

area = [tex]\frac{22}{7} \times 14 \times 14 =616 cm^2[/tex] (4 times the initial area)

------------------------------------

Formula for Circumference of a circle in form of Diameter:

[tex]C =\pi D[/tex]

It is a linear equation in 'D'. So by doubling the diameter will double the circumference.

Formula for Area of a circle in form of diameter:

[tex]A =\dfrac{1}{4}\pi D^2[/tex]

It is a quadratic equation in 'D'. So by doubling the Diameter will make the area as four times the earlier area.

Testing using example:

Let the initial diameter of a circle = 28 cm

Initial circumference = [tex]\frac{22}{7} \times 28 = 88 cm[/tex]

Initial area = [tex]\frac{1}{4}\times \frac{22}{7} \times 28 \times 28 =616cm^2[/tex]

After doubling:

Diameter = 56 cm

circumference = [tex]\frac{22}{7} \times 56= 176 cm[/tex]   (Twice the initial circumference)

area = [tex]\frac{1}{4}\times \frac{22}{7} \times 56 \times 56 =2464cm^2[/tex] (4 times the initial area)

So, the answer is justified:

When radius is doubled:

Circumference becomes double.

Area becomes four times.

When diameter is doubled:

Circumference becomes double.

Area becomes four times.

Answer:

6

Step-by-step explanation:

the solution in photo :)

Answer:

6

Step-by-step explanation:

→ Prime factorise each number

12 = 2² × 3 ⇒ 2 × 2 × 3

18 = 2 × 3² ⇒ 2 × 3 × 3

24 = 2³ × 3 ⇒ 2 × 2 × 2 × 3

→ Find which number there are in each one

2 and 3

→ Multiply them together

2 × 3 = 6