Solve for x Enter your answer, as one inequality,in the box

Answer:

Step-by-step explanation:

6)b) Sin A - x Cos A = 0

Sin A = x Cos A

[tex]\dfrac{Sin \ A}{Cos \ A} = x[/tex]

[tex]\dfrac{1}{x}=\dfrac{1}{\dfrac{Sin \ A }{Cos \ A}}=1*\dfrac{Cos \ A}{Sin \ A}=\dfrac{Cos \ A}{Sin \ A}[/tex]

[tex]RHS = x +\dfrac{1}{x}\\\\\\[/tex]

         [tex]= \dfrac{Sin \ A}{Cos \ A}+\dfrac{Cos \ A}{Sin \ A}\\\\\\=\dfrac{Sin \ A*Sin \ A}{Cos \ A*Sin \ A}+\dfrac{Cos \ A * Cos \ A}{Sin \ A* Cos \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Cos \ A*Sin \ A}+\dfrac{Cos^{2} \ A}{Cos \ A* Sin \ A}\\\\= \dfrac{Sin^{2} \ A+Cos^{2} \ A}{Cos \ A*Sin \ A}\\\\=\dfrac{1}{Cos \A*Sin \ A}\\\\= \dfrac{1}{Cos \ A}*\dfrac{1}{Sin \ A}\\\\=Sec \ A * Cosec \ A[/tex]

          = LHS

7a) 1 - Sin A = 1/2

     [tex]1 = \dfrac{1}{2}+ Sin \ A\\\\1-\dfrac{1}{2}=Sin \ A\\\\\dfrac{1}{2}=Sin \ A\\[/tex]

⇒ A = 30°

Sec² A = Sec² 30° = [tex](\frac{2}{\sqrt{3}})^{2}=\frac{2^{2}}{(\sqrt{3)^{2}}}=\frac{4}{3}[/tex]

[tex]tan^{2} \ A = tan^{2} 30 = (\dfrac{1}{\sqrt{3}})^{2} = \dfrac{1}{3}[/tex]

LHS = 6 Sec² A + 9 tan² A

       [tex]= 6*\dfrac{4}{3}+9*\dfrac{1}{3}\\\\\\=2*4 + 3*1\\\\\\= 8 + 3\\\\= 11 = RHS[/tex]

Answer:

a = 9

b = 2

Step-by-step explanation:

Given : a = 9

a = b + 7

9 = b + 7

b = 9 - 7 = 2

If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you know that

it is a type of active transport.

What do pinocytosis and phagocytosis have in common?

They are both forms of endocytosis.

Answer:

x=1

Step-by-step explanation:

x = -4 + 6 + (11 + 4(-3)).

First get the numbers in the parentheses

x = -4 + 6 + (11 - 12)

Since 11 - 12 = -1. We can replace (11-12) with -1

x = -4 + 6 -1

Now add and subtract

x = 1

Hope it helps you and have a great day

Answer:

64w^2

Step-by-step explanation:

Because 8w is in parentheses, you must apply the exponent to both the 8 and w.

So, it becomes (8*8)(x*x) which equals (64)(x^2).

Which then gives you your final answer, 64x^2.

   If the points P, Q, V and K are collinear, they will follow the segment addition postulate.

Measure of segment VP will be 214 units.

   It's given in the question,

By segment addition postulate,

            KQ + VQ + VP = KP

Substitute the values in the expression,

(11x + 5) + (17x + 6) + (14x + 4) = x + 630

(11x + 17x + 14x) + (5 + 6 + 4) = x + 630

42x + 15 = x + 630

42x - x = 630 - 15

41x = 615

x = [tex]\frac{615}{41}[/tex]

x = 15

Therefore, measure of VP = (14x + 4)

                                           = 14(15) + 4

                                          = 214 units

Measure of segment VP will be 214 units.

Learn more,

https://brainly.com/question/628239

Step-by-step explanation:

x = elsie ticket

[tex] \frac{2}{3} x + 10 = 21[/tex]

Answer:

No I am pretty sure it is the 4th answer my guy.

Step-by-step explanation:

2/3x-10=21

Step-by-step explanation:

365.892

365.895

365.899

365.902

365.905

365.909

Answer:

Putting x= 2

[tex]( - 5) \times 2 = - 10 \\ - 10 = - 10[/tex]

putting x = -2

[tex]( - 5) \times ( - 2) = - 10 \\ 5 \times 2 = - 10 \\ 10 = - 10 \\ this \: is \: not \: correct \: equation[/tex]

putting x = 50

[tex]( - 5) \times 50 = - 10 \\ - 250 = - 10 \\ this \: is \: also \: not \: correct \: equation[/tex]

so, x = 2 is applicable.

Answer:

875

Step-by-step explanation:

Answer:

D. $11,700

Step-by-step explanation:

Answer:

4 horses

Step-by-step explanation:

Answer:

According to my equation it's 20°

Answer:

This should be all of them

Step-by-step explanation:

Answer:

n ≤ − 28

Step-by-step explanation:

Multiply to remove the fraction, then set equal to  

0  and solve.

Answer:

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Answer:

77 cm²

Step-by-step explanation:

We know that

Area of trapezium = ½ (a + b) × h

Area = ½ × (10 + 12) × 7

Area = ½ × 22 × 7

Area = 11 × 7

Area = 77 cm²

Length of parallel sides = 10 cm and 12 cm

Height = 7 cm

Area of trapezium

[tex]\begin{gathered} {\underline{\boxed{ \rm {\red{Area \: of \: trapezium \: = \: \frac{1}{2} \: \times \: (a \: + \: b) \: \times \:Height }}}}}\end{gathered}[/tex]

Where ,

[tex] \begin{cases} \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \: \frac{1}{2} \: \times \: (10 \: + \: 12) \: \times \:7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \: \frac{1}{2} \: \times \: 22\: \times \:7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \: \frac{1}{ \cancel2} \: \times \: \cancel{22} \: ^{11} \: \times \:7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \:11 \: \times \: 7 \\ \\ \large\bf\purple{ \implies} \rm \:Area \: of \: trapezium \: = \:77 \: {cm}^{2} \end{cases}[/tex]

Answer:

y = 17

Step-by-step explanation:

3x = y - 5, for x = 4

=> 3(4) = y - 5

=> 12 = y - 5

=> 12 + 5 = y

=> 17 = y

Answer:

a=24

b=7

now

24+(7-4)

24+3

27

so the answer is 27

Answer:

The balance would be $160 from whatever it was before the 4 months.

Step-by-step explanation:

Since the bank balance is being added by 40 for each month for 4 months, 4 * 40 is just 4*4 with an extra zero on the end. so that would be $160.

So if the balance before was $40, then the new balance after 4 months would be $200.

If there's no money previously, then there is now $160 after 4 months.

If there's a value before the $40 for 4 months, let me know and I will explain and tell you what it is.

First, let's write down what we know.

AB = 3x

AC = 5x+21

Since B is the midpoint, AB is half the length of AC. The sum of AB + AB is equal to the length of AC.

AB + AB = AC

Let's plug in our values.

3x + 3x = 5x + 21

Simplify the left side.

6x = 5x + 21

Subtract 5x from both sides.

x = 21

Now, let's plug in 21 for x in AB

AB = 3x = 3(21) = 63

Step-by-step explanation:

Factoring a polynomial is the process of decomposing a polynomial into a product of two or more polynomials. For example, f ( x ) = x 2 + 5 x + 6 f(x) = x^2 + 5x + 6