solve for x. round to the nearest tenth,if neccessary.​

Answer:

4

Explanation:

Answer:

20cm

Step-by-step explanation:

a square has 4 equally long sides.

when we know its perimeter, that means we know the sum of all 4 sides.

since all sides are equality long, we only need to divide the perimeter by 4 to get the length of an individual side.

80/4 = 20cm

Answer:

1.)36

2.)54

Step-by-step explanation:

sana po makatulong gehehe

Answer:

f(x) is shrinked

Step-by-step explanation:

Given

[tex]f(x) = 4^x[/tex]

[tex]g\left(x\right)=\frac{1}{3}\cdot4^x[/tex]

Required

The effect of dilation on f(x)

From the given parameters, we have:

[tex]f(x) = 4^x[/tex]

[tex]g\left(x\right)=\frac{1}{3}\cdot4^x[/tex]

On a general term;

[tex]g(x) = k * f(x)[/tex]

So by comparison:

[tex]k = \frac{1}{3}[/tex]

When scale of dilation is less than 1, it means the function is reduced. Hence, the specific effect on f(x) is shrink

Answer:

B) 1.4

Step-by-step explanation:

The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.

sin(B)=opp/hyp

The maximum length of the seesaw is 1.4 meters

Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.

Let h represent the length of the seesaw, hence using trigonometric ratio:

sin(45) = 1 / h

h = 1.4 meters

The maximum length of the seesaw is 1.4 meters

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Given:

[tex]Domain\neq -1[/tex]

[tex]Range\neq 2[/tex]

To find:

The function for the given domain and range.

Solution:

A function is not defined for some values that makes the denominator equals to 0.

The denominator of functions in option A and C is [tex](x-1)[/tex].

[tex]x-1=0[/tex]

[tex]x=1[/tex]

So, the functions in option A and C are not defined for [tex]x=1[/tex] but defined for [tex]x=-1[/tex]. Therefore, the options A and C are incorrect.

In option B, the denominator is equal to [tex]x+1[/tex].

[tex]x+1=0[/tex]

[tex]x=-1[/tex]

So, the function is not defined for [tex]x=-1[/tex]. Thus, [tex]Domain\neq -1[/tex].

If degree of numerator and denominator are equal then the horizontal asymptote is [tex]y=\dfrac{a}{b}[/tex], where a is the leading coefficient of numerator and b is the leading coefficient of denominator.

In option B, the leading coefficient of numerator is 2 and the leading coefficient of denominator is 1. So, the horizontal asymptote is:

[tex]y=\dfrac{2}{1}[/tex]

[tex]y=2[/tex]

It means, the value of the function cannot be 2 at any point. So, [tex]Range\neq 2[/tex].

Hence, option B is correct.

Answer:

A. 4x² + 9x/4 - 7

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = x/4 - 3

g(x) = 4x² + 2x - 4

(f + g)(x) is f(x) + g(x)

Step 2: Find

Answer:

Step-by-step explanation:

r=5 cm

area=πr²

perimeter=2πr

substitute the value of r and calculate.

Answer:

78.54 [tex]cm^{2}[/tex] Area

31.42 cm   Circumference/perimeter

Step-by-step explanation:

A = [tex]\pi r^{2}[/tex]

C = 2[tex]\pi[/tex]r

A = [tex]\pi[/tex][tex]5^{2}[/tex]

A = 25[tex]\pi[/tex]

A = 78.54

C = 2[tex]\pi[/tex](5)

C = 10[tex]\pi[/tex]

C = 31.42

Answer:

(3)11

Step-by-step explanation:

We are given that

[tex](x^2-12x+35)(x^2+10x+24)=504[/tex]

We have to find the sum of positive roots of the equation.

[tex]x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504[/tex]

[tex]x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504[/tex]

[tex]x^4-2x^3-61x^2+62x+840-504=0[/tex]

[tex]x^4-2x^3-61x^2+62x+336=0[/tex]

Factor of 336

2,3,4,6,8,7,

Let x=2

[tex]2^4-2^4-61(2^2)+62(2)+336\neq0[/tex]

x=2 is not the root of equation

x=-2

[tex](-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0[/tex]

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

[tex]3^4-2(3^3)-61(3^2)+62(3)+336=0[/tex]

Therefore, x=3  is the root of equation.

[tex](x+2)(x-3)(x^2-x-56)=0[/tex]

[tex](x+2)(x-3)(x^2-8x+7x-56)=0[/tex]

[tex](x+2)(x-3)(x(x-8)+7(x-8))=0[/tex]

[tex](x+2)(x-3)(x-8)(x+7)=0[/tex]

[tex]x-8=0\implies x=8[/tex]

[tex]x+7=0\implies x=-7[/tex]

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

[tex]\displaystyle\bf 2x=84\\\\x=84:2=42\\\\\boxed{x=42}[/tex]

Answer:

2 : 1

Step-by-step explanation:

Supplementary angles are two angles whose measures add up to 180°

If one of the angle = 120°

The other angle = sum of supplementary angle - one of the angle

= 180° - 120°

= 60°

The other angle = 60°

ratio of pair of supplementary aangle = 120° : 60°

= 120° / 60°

= 2/1

= 2 : 1

ratio of pair of supplementary aangle = 2 : 1

Answer:

C=20

Step-by-step explanation:

Answer:

Step-by-step explanation:

The absolute value of a number is defined as the positive of either a positive or a negative number. By that I mean that

| 1 | = 1 and | -1 | = 1.  Right?

We use that idea here. Either:

6x + 3 = 27     OR      6x + 3 = -27 and solve both equations.

6x = 24 so x = 4 OR

6x = -30 so x = -5

Choice D is the one you want.

Answer:

194

Step-by-step explanation:

Rectangles :

7 x 10 = 70

6 x 10 = 60

4 x 10 = 40

Triangles

[tex]\frac{6x4}{2}[/tex] = 12   (two of them = 24)

70 + 60 + 40 + 24 = 194

Answer:

Step-by-step explanation:

total number of students=22

number of female students=7

number of male students=22-7=15

number of male students not having A=3

Number of male students having A=15-3=12

P(male student having A)=12/22=6/11

The probability that a student who has an A is male is approximately 0.632

We can use the formula for conditional probability:

P(Male | A) = P(Male and A) / P(A)

We are given that there are 3 male students who do not have an A, so there are 22 - 3 = 19 students who have an A. Of these 19, we do not know how many are male. However, we do know that there are 7 female students, so the number of male students who have an A is:

19 - 7 = 12

Therefore, the probability that a student who has an A is male is:

P(Male | A) = 12 / 19

We can simplify this fraction by dividing the numerator and denominator by their greatest common factor (which is 1 in this case):

P(Male | A) = 12 / 19

So the probability that a student who has an A is male is approximately 0.632.

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Respuesta:

15%

Explicación paso a paso:

Dado :

Precio de compra = $ 4000

Precio de venta = $ 4600

El beneficio obtenido por la venta del artículo:

Precio de venta - precio de compra

$ (4600-4000) = $ 600

El porcentaje de beneficio obtenido:

Beneficio / precio de compra * 100%

600/4000 * 100%

600/4000 * 100%

0,15 * 100%

= 15%

Answer:

QPR=PRS(Being alternative Angel)

Answer:

Savings total for both = 24x + 24

Step-by-step explanation:

Rick has 8x to start with

Let w = the number of weeks he will save.

Savings = 8x + 3*w  

Let w = 4

Savings = 8x + 3*4

Savings = 8x + 12

Helen

Let w = the number of weeks she will save.

Savings = 16x + 3*w

Let w = 4

Savings = 16x + 12

Now we come to the question. It seems to want the total combining both of them.

Rick + Helen = 8x + 12 + 16x + 12 = 24x + 24

The only other possible answer is

Rick = 8x + 12

Helen = 16x + 12

Answer:

_____________________________

2 x 5 = 10

2 x 4 = 8

10 + 8 = 18

______________________________

5 + 4 = 9

_______________________________

_ 9 = 18

18 : 9 = 2

Answer:

(a): 6 centimeters

(b): 72 inches

Step-by-step explanation:

Rule: From centimeters to inches, multiply centimeters × 8

so from inches to centimeters, divide inches by 8

Scale:

1 cm : 8 in

? cm : 48 in

6 cm : 48 in

Scale:

? in : 9 cm

72 in : 9 cm

Answer:

kids at playground

children are too young to know calorie count and the health benefits of certain foods. So they would simply choose the one they think tastes best

Answer:

The length of the shortest side of the triangle is 10 units.

Step-by-step explanation:

Let a be the shortest side of the isosceles triangle and b be the two congruent sides.

The congruent sides b are each one unit longer than the shortest side. Hence:

[tex]b=a+1[/tex]

The perimeter of the isosceles triangle is given by:

[tex]\displaystyle P_{\Delta}=b+b+a=2b+a[/tex]

This is equivalent to the perimeter of a square whose side lengths are two units shorter than the shortest side of the triangle. Let the side length of the square be s. Hence:

[tex]s=a-2[/tex]

The perimeter of the square is:

[tex]\displaystyle P_{\text{square}}=4s=4(a-2)[/tex]

Since the two perimeters are equivalent:

[tex]2b+a=4(a-2)[/tex]

Substitute for b:

[tex]2(a+1)+a=4(a-2)[/tex]

Solve for a. Distribute:

[tex]2a+2+a=4a-8[/tex]

Simplify:

[tex]3a+2=4a-8[/tex]

Hence:

[tex]a=10[/tex]

The length of the shortest side of the triangle is 10 units.

Answer:

B 720

Step-by-step explanation:

same process as the previous image I sent ya

Answer:

B) 720.

Step-by-step explanation:

We can use the Binomial Expansion Theorem:

[tex]\displaystyle (a+b)^n=\sum_{k=0}^{n}\binom{n}{k}a^kb^{n-k}[/tex]

We have the expression:

[tex]\displaystyle (2x-3)^5[/tex]

Therefore, a = 2x, b = -3, and n = 5.

We want to find the coefficient of x³. To get x³, we can cube a. Therefore, we can find our coefficient by letting k = 3. Hence:

[tex]\displaystyle \binom{5}{3}(2x)^3(-3)^{5-3}[/tex]

Evaluate:

[tex]\displaystyle =10(8x^3)(9)=720x^3[/tex]

Our answer is B.

Answer:

A. x² + 3x - 1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 3x - 2

g(x) = x² + 1

(f + g)(x) is f(x) + g(x)

Step 2: Find

Answer:

D. x² + 3x + 1

Step-by-step explanation:

Given :- f ( x ) = 3x - 2 ɑnd g( x) = x² + 1

Find :- ( f + g ) ( x )

Solution :-

( f + g ) ( x ) = ( ( 3x - 2 ) + ( x² + 1))

( f + g ) ( x ) = ( 3 x - 2 + x² + 1 )

( f + g ) ( x ) = ( x² + 3x - 1 )

Answer:

[tex]{ \bf{f(x) = {x}^{3} + {ax}^{2} - 1 }} \\ { \tt{f( - 1) : {( - 1)}^{3} + a {( - 1)}^{2} - 1 = 0}} \\ { \tt{f( - 1) : a - 2 = 0}} \\ a = 2[/tex]

The polynomial function [tex]$x^3 + ax^2 -1[/tex] will have -1 as a root at the value of

a = 2.

A polynomial function exists as a function that applies only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.

Given: A root exists at a value of x such that the polynomial exists equivalent to zero.

Let, the polynomial equation be [tex]$x^3 + ax^2 -1[/tex]

then [tex]$\mathbf{f}(\mathbf{x})=\mathbf{x}^{3}+a \mathbf{x}^{2}-\mathbf{1}$[/tex]

Put, x = -1, then we get

[tex]$\mathbf{f}(-1)=(-1)^{3}+\mathrm{a}(-1)^{2}-1=0$[/tex]

f(-1) = a - 2 = 0

a = 2

Therefore, the value of a = 2.

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Answer:

check footprints and then check finger print the finger print pour powder on it and Trace

Answer:

5.28

Step-by-step explanation:

we use the formula

H²=B²+P²

and we will get the answer

branliest if it is helpful

Answer:

Angle BXY

using pythogoras theory which is

hyp*2= opp*2 +adj*2

hypothenus being the longest part of the angle BX=?

Step-by-step explanation:

hyp= 4.2*2+ 3.2*2

hyp*2 =17.64 + 10.24

hyp*2 = 27.88

hyp =√27.88

hyp=5.28...Ans

note *2...square

Answer:

[tex]\angle DFE = \angle DFG[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required

What makes DEF and DGF congruent

We have:

[tex]EF = GF[/tex] --- this is indicated by the single line on both sides

Also:

[tex]DF = DF[/tex] --- both triangle share same side

For SAS to be true;

2 sides and 1 angle must be equal in either triangles

So far, we have:

[tex]EF = GF[/tex] ---- S

[tex]DF = DF[/tex] ---- S

The additional to complete the proof is:

[tex]\angle DFE = \angle DFG[/tex] ---- angle between the above sides

Reflection is a type of rigid transformation which requires the turning of an object, shape or figure about a reference point or line. Therefore, the needed additional information is ∠DFE ≅ ∠ DFG. Option B.

Reflection implies turning the given triangle DEF about its side DF, so as to produce an image with the same dimensions but different orientation.

The required proof by Side-Angle-Side (SAS) implies that the relations will be in respect of two of its sides and their included angle.

So that,

GF ≅ FE (given)

DF is the common side to triangles DEF and DFG.

DFG is the included side.

Thus;

∠DFE ≅ ∠ DFG (Side-Angle-Side postulate, SAS)

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