solve on the interval [0,2pi] 3(sec x)^2 -4=0

Answer:

the lines arent parallel, so you cant use corresponding angles theorem

The error is corresponding property does not apply.

Parallel lines are those lines that are equidistant from each other and never meet, no matter how much they may be extended in either directions. For example, the opposite sides of a rectangle represent parallel lines.

We know that when two lines are parallel they the following property:

As, there is no parallel lines line.

So, the measurement if <1 = 88 can't be true because corresponding doesn't apply.

Learn ore about parallel lines here:

https://brainly.com/question/12860077

#SPJ2

Answer:

4

Step-by-step explanation:

ln(e)=1 since ln= log_e

log(x^y)=y*log(x) so ln(e^4)=4*ln(4)=4*1=4

Answer:

D

Step-by-step explanation:

ln(e^4)

The 4 comes down in front of the natural log (ln). You get 4 ln(e)

The natural log of e (ln e )  is 1.

So the answer is 4 * 1 = 4

That may not be clear to you. We could try it another way.

e = 2.718281828

ln (2.718281828) = 1

ln(2.718281828)^4 = 4.  The calculator gags until you get it right.  You need the y^x key (or the x^y key of ^) It does come back with 4.

You have to monkey around with the calculator to get this to happen.  

Answer:

x = 8cm

Step-by-step explanation:

17² = 15² + x²

289 = 225 + x²

- x² = 225 - 289

x² = 64

x = √64

x = 8

[tex]{ \boxed{ \sf \color{blue}{answer}}}[/tex]

x = 8 cm

Step-by-step explanation:

17² = 15² + x²

289 = 225 + x²

x² = 225 - 289

x² = 64

x = √64

x = 8

Teorema pythagoras

Answer:

1980

Step-by-step explanation:

13 sides

Number of sides n=13

The sum of interior angles of polygon =(2n−4)×90o

=(2×13−4)×90o

=(26−4)×90o

=22×90o

We get,

=1980

Answer:

(x+2)^2 + (y-15)^-1 = 64

Step-by-step explanation:

plz mark brainlist

the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h

Let's define the variables:

B = speed of the boat in still water.

S = speed of the stream.

When the boat travels downstream, the total speed of the boat will be equal to the sum of the speed of the stream and the speed of the boat in still water:

speed = B + S

When the boat goes downstream, the speed will be:

speed = B - S

Now, also remember the relation:

speed*time = distance.

The given information is:

In 8 hours the boat can:

go 12 km upstream and 40km downstream.

We now need to define another variable, T, as the time that the boat travels upstream.

Then we can write this as:

12km = (B - S)*T

If the boat travels T hours upstream, and travels for a total of 8 hours, then the amount of time that travels downstream is 8h - T, then we can write:

40km = (S + B)*(8h - T)

Similarly, when we have:

"it can go 16 km upstream and 32 km downstream in the same time."

we can define a new variable T', and write:

16km = (B - S)*T'

32km = (S + B)*(8h - T')

Then we have a system of 4 equations:

16km = (B - S)*T'

32km = (S + B)*(8h - T')

40km = (S + B)*(8h - T)

12km = (B - S)*T

And we need to solve this for S and B.

To do it, we need to isolate one of the variables in one of the equations.

Let's isolate T in the last equation:

T = 12km/(B - S)

now we can replace that in the third equation to get:

40km = (S + B)*(8h - 12km/(B - S))

So now we have 3 equations:

16km = (B - S)*T'

32km = (S + B)*(8h - T')

40km = (S + B)*(8h - 12km/(S - B))

Now we need to do the same thing, this time let's isolate T' in the first equation and replace it in the second one:

T' = 16km/(B - S)

Replacing it in the second equation we get:

32km = (S + B)*(8h - T')

32km = (S + B)*(8h - 16km/(B - S))

So now we have two equations:

40km = (S + B)*(8h - 12km/(B - S))

32km = (S + B)*(8h - 16km/(B - S))

Let's simplify these:

40km = 8h*(S + B) - 12km*(S + B)/(B - S)

32km = 8h*(S + B) - 16km*(S+ B)/(B - S)

Now we can multiply both equations by (B - S) to get:

40km*(S - B) = 8h*(S + B)*(B - S) - 12km*(S + B)

32km*(S - B) = 8h*(S + B)*(B - S) - 16km*(S+ B)

Let's keep simplifying this:

40km*(B - S) + 12km*(S + B) =  8h*(S + B)*(B - S)

32km*(B - S)  + 16km*(S+ B) = 8h*(S + B)*(B - S)

Now we get:

52km*B - 28km*S = 8h*(S^2 + B^2)

48km*B - 16km*S = 8h*(S^2 + B^2)

Notice that the right side of these equations is the same thing, then we can write:

52km*B - 28km*S = 48km*B - 16km*S

(52km - 48km)*B = (28km - 18km)*S

4km*B  =  10km*S

B = (10/4)*S

B = (5/2)*S

Now we can replace this in one of our two equations, let's use the first one:

48km*B - 16km*S = 8h*(S^2 + B^2)

48km*(5/2)*S - 16km*S = 8h*( S^2 + ( (5/2)*S)^2)

Now we can solve this for S

104km*S = 8h*( S^2 + 25/4*S^2)

104km*S = 8h*(29/4*S^2) = 48h*S^2

104km*S = 48h*S^2

dividing at both sides by S we get:

104km = 48h*S

104km/48h = S = 2.167 km/h

And using B = (5/2)*S

We can find the speed of the boat:

B = (5/2)*2.167 km/h = 5.418 km/h

Then:

the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h

If you want to learn more about this topic, you can read:

https://brainly.com/question/17300107

Answer:

Since all the three sides of the triangle are of equal length, we can find the perimeter by multiplying the length of each side by 3. 20 + 20 + 20 = 3 × 20 = 60 cm.

Answer:

you can ask from it will be easy for you actually I don't know answern

Answer:

9

Step-by-step explanation:

We know that a^b / a^c = a^(b-c)

9^8 / 9^7

9^(8-7)

9^1

9

there are two solutions:

a) y = [tex]\frac{-6+2\sqrt{6} }{5}[/tex]

b) [tex]y = \frac{-6-2\sqrt{6} }{5}[/tex]

Answer:

it's A

Step-by-step explanation:

Trust me I got the question right on the quiz

Answer:

x = 28.4°

Step-by-step explanation:

The cos(x) = 15/17 ≈ 0.88

The acos(0.88) = 28.4°

Answer:

70.875

Step-by-step explanation:

Area of park=Area of rectangle+Area of triangle

Area of park=13.5*4.8+(0.5)*(13.5)*0.9=70.875

Answer:

The question is asking for the perimeter. There are three ways to answer this depending on the assumptions though so I'll let you choose.

Assumptions are basically the different scenarios

1st scenario being the trim covers the carpet and the tile, they'd need 48m of trim (12+12+4+8+8+4)

2nd scenario in which the trim covers the carpet but not the tiled area, they'd need 44m of trim (12+12+4+8)

3rd scenario where the trim only covers the the tiled area, 4m of trim

(just 4 since the tile only touches 4m of the wall)

Hope this helps!

Step-by-step explanation:

trim is just the perimeter since it covers the base of the wall

Answer:here’s the table

Step-by-step explanation:

Celina -3

Jannie 3

Sami 1

Ted 4

Travis ??

Answer:

Step-by-step explanation:

-5

Answer:

x=1

Step-by-step explanation:

3x+9 = 12

Subtract 9 from each side

3x+9-9=12-9

3x = 3

Divide by 3

3x/3 = 3/3

x=1

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = 1[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the answer...}}\\\\3x + 9 = 12\\-------------\\\rightarrow 3x + 9 - 9 = 12 - 9\\\\\rightarrow 3x = 3\\\\\rightarrow \frac{3x=3}{3}\\\\\rightarrow \boxed{x=1}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

y = x^2 - 8x + 3

y - 3 = x^2 - 8x + 3 - 3

y - 3 = x^2 - 8x + ___

c = (8/2)^2 = 16

y - 3 + 16 = x^2 - 8x + 16

y + 13 = (x - 4)^2

y + 13 - 13 = (x - 4)^2 - 13

y = (x - 4)^2 - 13

Vertex: (4, -13)

Hope this helps!

Answer:

M ≤ μ (=78)

Here μ denotes the means of the population

And, M denotes the sample mean

Step-by-step explanation:

The computation of the  null hypothesis, in both words and symbols is given below:

Null Hypothesis(H0) is

M ≤ μ (=78)

This means that the study application does not improve the grades

Also

Alternative hypothesis (H1): M> μ

Here μ denotes the means of the population

And, M denotes the sample mean

Answer:

12

Step-by-step explanation:

because it's true we need to know the full proce

Answer:

2-\sqrt{3} \\

Step-by-step explanation:

2-\sqrt{3} \\

Answer:

0'=(0,3)

Step-by-step explanation:

P'=(-5+5,7-5)=(0,3)

Answer:

see below

Step-by-step explanation:

2^30

-------

8^9

Rewriting

8^9

2^3 ^ 9

We know a^b^c = a^(b*c)

2^(3*9) = 2^27

2^30

-------

2^27

We know a^b / a^c = a^(b-c)

2^(30-27) = 2^3

Assuming you mean 2^x

2^3 = 2^x

x=3

If you mean 2x

2^3 = 8

8 = 2x

Divide by 2

4 =x

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{\dfrac{2^{30}}{8^9}=2x}[/tex]

[tex]\mathsf{2^{30}}\\\mathsf{= \bf 1,073,741,824}\\\\\mathsf{8^9}\\\mathsf{= \bf 134,217,728}[/tex]

[tex]\mathsf{\rightarrow \dfrac{1,073,741,824}{134,217,728}= 2x}\\\\\\\mathsf{\dfrac{1,073,741,824}{134,217,728}= \bf 8}\\\\\\\mathsf{\rightarrow \ 8 = 2x}\\\\\\\\\large\textsf{TURN\ the\ EQUATION\ around}\\\\\\\mathsf{\rightarrow\ 2x = 8}\\\\\\\large\textsf{DIVIDE 2 to BOTH SIDES}\\\\\\\mathsf{\dfrac{2x}{2}=\dfrac{8}{2}}\\\\\\\large\textsf{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\textsf{ because it gives you 1}\\\\\\\large\textsf{KEEP: }\mathsf{\dfrac{8}{2}}\large\textsf{ because it gives you the answer of x}[/tex]

[tex]\mathsf{x = \dfrac{8}{2}}\\\\\\\mathsf{x = 8\div 2}\\\\\\\mathsf{x = \bf 4}\\\\\\\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 4}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

Multiply 800 by 1.022^7 because 1.022^(n-1)

Step-by-step explanation:

Series and sequences.

Answer:

answer of this question is A

The equation in point slope form is y - 6 = 2(x + 3)

This is from the general point slope template of [tex]y - y_1 = m(x - x_1)[/tex]

The m is the slope, which in this case is m = 2. The [tex](x_1,y_1)[/tex] is the point the line goes through. In this case, [tex]x_1 = -3 \text{ and } y_1 = 6[/tex]

If you were to solve that equation in bold for y, then you should get y = 2x+12 which is now in y = mx+b form, aka slope intercept form.

Answer:

The length is 12metres, the width is 6metres

Step-by-step explanation:

Suppose the width is x, the length is x+6

The square is 72. The square of rectangular field is equal to product of length and width.

so x(x+6)=72

x^2+6x-72=0

a=1 b=6 c=-72

D= b^2-4ac= 6*6+288= 36+288= 324

sqrtD= 18

x1= (-b-sqrtD)/2a=(-6-18)/2= -12 (it is negative, but width is only positive. So this root doesn't match)

x2=(-b+sqrtD)/2a= (-6+18)/2= 12/2=6 - the width

The length is 6+6=12

Answer:2 and 6

Step-by-step explanation:

Given

In 4 years Craston's age will be the same as Terrins age is now

Suppose the present of Craston's and Terrins are [tex]x[/tex] and [tex]y[/tex] respectively

According to the question

[tex]\Rightarrow x+4=y\\\Rightarrow y-x=4\quad \ldots(i)[/tex]

In 2 years Terrin will be twice as old  as craston

[tex]\Rightarrow (y+2)=2(x+2)\\\Rightarrow y-2x=4-2\\\Rightarrow y-2x=2\quad \ldots(ii)\\[/tex]

Solving (i) and (ii) we get

[tex]x=2,y=6[/tex]

Thus, the present age of Craston and Terrins are [tex]2[/tex] and [tex]6[/tex]

Answer:

x = 0

y = -2

Step-by-step explanation:

2304.06 is written in expanded form

4 is unit place. So, 4 *10⁰ = 4 * 1 = 1    {Any integer to the power of 0 is 1}

x = 0

6 is hundredth place = 6 * 1/100 = 6*10⁻²

y= -2

Answer:

Step-by-step explanation:

I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:

[tex]x-9=\sqrt{x}+3[/tex] then subtract 3 from both sides to get

[tex]x-12=\sqrt{x}[/tex] and then square both sides to get

[tex]x^2-24x+144=x[/tex] and get everything on one side to solve for x by factoring:

[tex]x^2-25x+144=0[/tex] and factor that however it is you have learned to factor second-degree polynomials to get that

x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:

[tex]\frac{16-9}{\sqrt{16}+3 }=1[/tex]  If 16 is a solution, then this statement will be mathematically true.

[tex]\frac{7}{4+3}=1[/tex]  and   [tex]\frac{7}{7}=1[/tex] so 16 works. Let's try 9:

[tex]\frac{9-9}{\sqrt{9}+3 }=1[/tex]  We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.

x = 16 is the only solution.

Answer:

x =  16

Step-by-step explanation:

[tex]\frac{x-9}{\sqrt{x}+3}=1[/tex]

Cross multiply,

x - 9 = √x + 3

Subtract 3 from both sides

x - 9 - 3 = √x

x - 12 = √x

Square both sides

(x -12)² = (√x)²

x² - 2 * x*12 + 12² = x

x² - 24x + 144 = x

x² - 24x + 144 - x = 0

x² - 25x + 144 = 0

Sum = -25

Product = 144

Factors = -9 , -16            {(-9)+(-16) = -25  & (-)*(-16) = 144}

x² - 25x + 144 = 0

x² - 16x - 9x + (-9)*(-16) = 0

x(x - 16) - 9(x - 16) = 0

(x - 16) (x - 9) = 0

x - 16 = 0     ; x - 9 = 0

x = 16          ; x = 9

x = 9 is  an extraneous solution.

When we plug in 9 in the LHS of the equation,

LHS = [tex]\frac{9-9}{\sqrt{9}+3}[/tex]

       [tex]= \frac{0}{3+3}[/tex]

        = 0 ≠ RHS

So, x = 16 is the only  solution