Solve the equation n3 = 8/125 for n n=______

Answer:

25

Step-by-step explanation:

Moving it down does not change the length.

Answer:

(3p+10q)

Step-by-step explanation:

9p^2 - 100q^2

Rewriting

(3p)^2 - (10q)^2

This is the difference of squares

a^2 - b^2 = (a-b)(a+b)

(3p-10q) (3p+10q)

Answer:

( 3p + 10 q)

Step-by-step explanation:

9 p ² - l00 q ²

(3p)² - ( 10 q) ²

( a ² - b ² = ( a + b) ( a - b) )

( 3p - 10 q) ( 3 p + 10 q)

it should be

9x+1y+8

      ^it could be just y instead of 1y

Answer:

the answer is = 9x+y+8

Step-by-step explanation:

...

Answer:

I think it would be 36, if you use Area=Length×Width×Height

Answer:

274

Step-by-step explanation:

202 + 6(9 + 3) =

PEMDAS says parentheses first

202 + 6(12) =

Then multiply

202 +72

Then add

274

Answer:

274

Step-by-step explanation:

202 + 6(9 + 3)

202 + 6(12)

202 + 72

274

Answer: a. -6x

b. 3a; -3a2 (square) ; - 6

Step-by-step explanation:

Answer:

4*4=16+7=23

Step-by-step explanation:

4 inches x 4 weeks is 16 inches

7 + 16 = 23

Answer:

Es ydjwj rjsbt djeiweke

Answer:

B'(2,4) & C'(1,0)

Step-by-step explanation:

According To the Question,

Given, We have an ∆ABC that has coordinates A(3, 1), B(5, 5) and C(4, 1).

Now, After a translation, the coordinates of A' are (0,0) .

Then, the coordinate of B' & C' Also changes the same as like A' .

A(3,1) ⇒ A'(0,0)      {here from x-axis it reduce 3 and from y-axis it reduce 1}

Same as Above,

B(5,5) ⇒ B'(2,4)

&, C(4,1) ⇒ C'(1,0) .

Answer: y = 1x + 3

Step-by-step explanation:

If you plot it, you see the slope is 1/1, and the y-intercept is at (0, 3).

[tex]\longrightarrow{\green{π=3.14}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \sqrt{ {\pi}^{2} } \\ \\ = \pi \\ \\ = \frac{22}{7} \\ \\ ( \: or \: ) \\ \\ = 3.14 \\ \\ (∵ \sqrt{( {a})^{2} } = a)[/tex]

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

[tex]\pi = 3.14 \\ \\ \sqrt{\pi {}^{2} } \\ \sqrt{ {3.14}^{2} } \\ |3.14| \\ \\ = 3.14[/tex]

Final Answer: 3.14

Step By Step Explanation:

Alternate Forms:

Answer:

top answer, domain and range have no restrictions

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Marginal cost is the change in total cost as a result of increasing output by one unit

Marginal cost  = Δcost / Δquantity

0.2 / 0.25 = 0.8

The marginal cost would decrease because the change in output is higher than the change in total cost

Marginal benefit would increase

Opportunity cost is the cost of the opportunity forgone when one alternative is chosen over other alternatives. There is no enough information given to determine the impact on opportunity cost

Answer:

43 hours

Step-by-step explanation:

[tex]\frac{y}{1} :\frac{408}{9.5}[/tex]

y × 9.5 = 408 × 1

9.5y = 408

9.5y ÷ 9.5 = 408 ÷ 9.5

[tex]y=42\frac{18}{19}[/tex]

43 hours

Answer:

B.

Step-by-step explanation:

1) the area of the given circle is: A=π*r²=256π (in²).

2) the part of the shaded sector is 110/360=11/36, it means that the required area of the shaded sector is: 11/36 * A = 256* π * 11 / 36≈246 (in²).

Answer:

i beleive its option number 1

Answer:

first graph

Step-by-step explanation:

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Then g(x) = | x | - 4 is the graph of f(x) shifted down by 4 units

This is represented by the first graph on the left

Answer:

Last option

Step-by-step explanation:

First method :

Red Line:

Take 2 coordinates through which the line passes. Let it be (0, 7) and (14, 0).

[tex]slope, m=\frac{ 0-7}{14-0} = -\frac{7}{14} = -\frac{1}{2}[/tex]

[tex]Equation : (y - 7) = -\frac{1}{2}(x)[/tex]

                [tex]2y - 14 = -x\\2y + x = 14\\4y + 2x = 28[/tex]                  [tex][ multiply \ by \ 2 \ on \ both \ sides][/tex]

Blue Line:

Take coordinates through which the line passes.

Let it be (-4, -12) and (-10, -9).

[tex]slope, m = \frac{-9 + 14}{-10} = \frac{5}{-10} = -\frac{1}{2}[/tex]

[tex]equation : (y + 12) = -\frac{1}{2} (x+4)\\[/tex]

              [tex]y = -\frac{1}{2}x - 2 - 12\\\\y = -\frac{1}{2}x -14\\\\2y = -x - 28\\\\-2y = x +28[/tex]

Second Method:

From the graph it is clear the lines are parallel. The slopes of line parallel to each other are equal. So convert each equation into standard line equation form :y = mx + b

And check for set of equation whose slope are same.

First set :

[tex]y = 10x - 15 \\\\=> slope = 10\\\\-9x + 2y = 10\\2y = 9x + 10\\\\y = \frac{9}{2}x + 5 => slope = \frac{9}{2}[/tex]

Slopes are not equal.

Second set :

[tex]2y = 2x + 5\\y = x + \frac{5}{2}\\slope = 1\\\\\\3x -4y = -5\\4y = 3x + 5\\\\\y = \frac{3}{4}x + \frac{5}{4}\\\\slope = \frac{3}{4}[/tex]

Slopes are not equal.

Third set :

[tex]y = 3x +10 \\slope = 3\\\\\\2x - 3y = -6\\3y = 2x +6\\\\y = \frac{2}{3}x + 2\\\\slope = \frac{2}{3}[/tex]

Slopes are not equal.

Fourth set :

[tex]2x + 4y = 28\\4y = -2x +28\\\\y = -\frac{1}{2}x + 7\\\\slope = -\frac{1}{2}\\\\\\-2y = x + 28\\\\y = -\frac{1}{2}x - 14\\\\slope = -\frac{1}{2}[/tex]

Slopes are same.

Answer:

$1.44

Step-by-step explanation:

Tax is a compulsory sum levied by the government. it increases the price of the good

tax paid = tax rate x price of the book

18 x 8%

18 x 0.08 = $1.44

Answer:

B. Evidence

Step-by-step explanation:

Reference: like when your drawing something and you want to make sure that you draw the hair the same way some other person did.

Cite: That’s when you give the credits to someone or something 90% sure

Hope this helps :)

Answer:

huh???

Step-by-step explanation:

Answer:

SA= 882cm^2

Step-by-step explanation:

SA=2( width*length + hight*length + hight*width )

SA=2( 9*20+ 9*20+ 9*9)

SA= 2*441

SA=882cm^2

Answer:

SMALLER NUMBER = 14

BIGGER NUMNER = 34

Step-by-step explanation:

Two equations can be derived from the question

a + 2b = 62 equation 1

3a - b = 116  equation 2

a = bigger number

b = smaller number

multiply equation 1 by 3

3a + 6b = 186 equation 3

subtract equation 2 from 3

5b = 70

b = 14

substitute for b in equation 1

a + 28 = 62

a = 34

Answer:

The percentage change is 140%

Step-by-step explanation:

Given

[tex]L= 3W_1[/tex] ---- initial dimension

[tex]W_2 = 6m[/tex] --- new width

[tex]A_2 = 45m^2[/tex] --- new dimension

Required

The percentage increment

The length remains constant because only the width is extended.

The new area is:

[tex]Area =Length * Width[/tex]

[tex]A_2=L * W_2[/tex]

Make L the subject

[tex]L = \frac{A_2}{ W_2}[/tex]

Substitute values for A and W

[tex]L = \frac{45m^2}{6m}[/tex]

[tex]L = \frac{45m}{6}[/tex]

[tex]L = 7.5m[/tex] --- this is the length of the garden

Calculate the initial width:

[tex]L= 3W_1[/tex]

Make W1 the subject

[tex]W_1 = \frac{1}{3} * L[/tex]

[tex]W_1 = \frac{1}{3} * 7.5[/tex]

[tex]W_1 = 2.5[/tex]

So, the initial area is:

[tex]A_1 = L_1 * W_1[/tex]

[tex]A_1 = 2.5 * 7.5[/tex]

[tex]A_1 = 18.75[/tex]

The percentage change in area is:

[tex]\%A = \frac{A_2 - A_1}{A_1}[/tex]

[tex]\%A = \frac{45 - 18.75}{18.75}[/tex]

[tex]\%A = \frac{26.25}{18.75}[/tex]

[tex]\%A = 1.4[/tex]

Express as percentage

[tex]\%A = 1.4*100\%[/tex]

[tex]\%A = 140\%[/tex]

Answer:

B ) Pharming

Step-by-step explanation:

When the user types in a URL they are directed to a fake website this is known as Pharming. This is one of many cyber attacks and usually occurs from a virus that has found it's way into your personal computer or server. The harmful virus basically waits until you open your internet browser and type in a URL to a specific website. Instead of taking you to that correct website it will take you to a replica site which will send all the information that you input, back to the creator of the virus. This is done so that they can obtain all of your personal information including bank details.

Answer:

23

Step-by-step explanation:

The absolute value of any number is just the positive version of that number. For example the absolute value of -12 is 12.

Hope this helps! :)

Answer:

30°

Step-by-step explanation:

it is the alternating angle.

Answer:

8r6s3 – 13r5s4 + r4s5 – 5r3s6 it is D

Step-by-step explanation:

The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.

Given that;

The expression is,

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

Now, We can find the difference as;

⇒ (8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵) – (2r⁴s⁵ – 5r³s⁶ – 4r⁵s⁴)

⇒ (8r⁶s³ – 9r⁵s⁴ – 4r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ – 5r³s⁶

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Thus, The value of the difference of the polynomials is,

⇒ 8r⁶s³ - 13r⁵s⁴ + r⁴s⁵ - 5r³s⁶

Learn more about the subtraction visit:

https://brainly.com/question/17301989

#SPJ7

Answer:

[tex]\int\limits {\int\limits_R {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]

Step-by-step explanation:

Given

[tex]x - y = 0[/tex]

[tex]x - y = 7[/tex]

[tex]x + y = 0[/tex]

[tex]x + y = 6[/tex]

Required

Evaluate [tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex]

Let:

[tex]u=x+y[/tex]

[tex]v =x - y[/tex]

Add both equations

[tex]2x = u + v[/tex]

[tex]x = \frac{u+v}{2}[/tex]

Subtract both equations

[tex]2y = u-v[/tex]

[tex]y = \frac{u-v}{2}[/tex]

So:

[tex]x = \frac{u+v}{2}[/tex]

[tex]y = \frac{u-v}{2}[/tex]

R is defined by the following boundaries:

[tex]0 \le u \le 6[/tex]  ,  [tex]0 \le v \le 7[/tex]

[tex]u=x+y[/tex]

[tex]\frac{du}{dx} = 1[/tex]

[tex]\frac{du}{dy} = 1[/tex]

[tex]v =x - y[/tex]

[tex]\frac{dv}{dx} = 1[/tex]

[tex]\frac{dv}{dy} = -1[/tex]

So, we can not set up Jacobian

[tex]j(x,y) =\left[\begin{array}{cc}{\frac{du}{dx}}&{\frac{du}{dy}}\\{\frac{dv}{dx}}&{\frac{dv}{dy}}\end{array}\right][/tex]

This gives:

[tex]j(x,y) =\left[\begin{array}{cc}{1&1\\1&-1\end{array}\right][/tex]

Calculate the determinant

[tex]det\ j = 1 * -1 - 1 * -1[/tex]

[tex]det\ j = -1-1[/tex]

[tex]det\ j = -2[/tex]

Now the integral can be evaluated:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA[/tex] becomes:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{x^2 - y^2}} \, *\frac{1}{|det\ j|} * dv\ du[/tex]

[tex]x^2 - y^2 = (x + y)(x-y)[/tex]

[tex]x^2 - y^2 = uv[/tex]

So:

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{|det\ j|}\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *|\frac{1}{-2}|\, dv\ du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \int\limits^6_0 {\int\limits^7_0 {7ue^{uv}} *\frac{1}{2}\, dv\ du[/tex]

Remove constants

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 {\int\limits^7_0 {ue^{uv}} \, dv\ du[/tex]

Integrate v

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 \frac{1}{u} * {ue^{uv}} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 e^{uv} |\limits^7_0 du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{u*7} - e^{u*0}]du[/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2}\int\limits^6_0 [e^{7u} - 1]du[/tex]

Integrate u

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7u} - u]|\limits^6_0[/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -(\frac{1}{7}e^{7*0} - 0)][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * ([\frac{1}{7}e^{7*6} - 6) -\frac{1}{7}][/tex]

Open bracket

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} - 6 -\frac{1}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{7*6} -\frac{43}{7}][/tex]

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{7}{2} * [\frac{1}{7}e^{42} -\frac{43}{7}][/tex]

Expand

[tex]\int\limits {\int\limits {7(x + y)e^{x^2 - y^2}} \, dA = \frac{1}{2}e^{42} -\frac{43}{2}[/tex]