Solve the system by substitution.
y + 4 = x
10x + 2y = 16

Answer:

f(x) = 2(3) + 5

= 6 + 5 = 11

y = 11

x = 3

hope it helps.

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Answer:

2

Step-by-step explanation:

Answer:

95.73%

Step-by-step explanation:

Given data:

mean μ= 95

standard deviation, σ = 11

to calculate, the probability that a randomly selected firm will earn less than 114 million dollars;

Use normal distribution formula

[tex]P(X<114)=P(Z<\frac{X-\mu}{\sigma} )[/tex]

Substitute the required values in the above equation;

[tex]P(X<114)=P(Z<\frac{114-95}{11} )\\P(X<114)=P(Z<1.7272)\\P(X<114)=0.9573[/tex]

Therefore, the probability that a randomly selected firm will earn less than 114 million dollars = 95.73%

Answer:

20

Step-by-step explanation:

6 + 2 = 8

8 + 3 = 11

11 + 4 =15

15 + 5 =20

Answer:

20

Step-by-step explanation:

the pattern is increase the number by one more than the increase before. so 6,8=2 greater

8-11=3 greater. 11-15=4 greater. so, 15+5=20 (with this answer being 5 greater continuing the pattern.)

Answer:

7/30

Step-by-step explanation:

P = 1/15 + 1/6 = (2+5)/30 = 7/30

Answer:

Step-by-step explanation:

It’s G

Given:

The graph that represents the enrollment for college R between 1950 and 2000.

To find:

The average rate of increase in enrollment per decade between 1950 and 2000?

Solution:

The average rate of change of function f(x) over the interval [a,b] is:

[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]

So, the average rate of increase in enrollment per year between 1950 and 2000 is:

[tex]m=\dfrac{f(2000)-f(1950)}{2000-1950}[/tex]

[tex]m=\dfrac{7-4}{50}[/tex]

[tex]m=\dfrac{3}{50}[/tex]

[tex]m=0.06[/tex]

It is given average rate of increase in enrollment per year between 1950 and 2000 is 0.06.

We need to find the average rate of increase in enrollment per decade between 1950 and 2000, So, multiply the average rate of increase in enrollment per year by 10.

[tex]0.06\times 10=0.6[/tex]

Therefore, the average rate of increase in enrollment per decade between 1950 and 2000 is 0.6.

Answer:

D

Step-by-step explanation:

The symbol ~ means similarity (same shapes, not same size)

Answer:

[tex]y = - 9 + 2x[/tex]

Step-by-step explanation:

Objective: Use the rules of Algebra to isolate y.

[tex]4x - 2y = 18[/tex]

[tex] - 2y = 18 - 4x[/tex]

[tex]y = \frac{18 - 4x}{ - 2} [/tex]

[tex]y = - 9 + 2x[/tex]

Answer:

She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.

Step-by-step explanation:

Let x represent the number of times that she travels using the train and let y represent the number of times she travels using the bus. Since she makes at least 8 trips to the place, hence:

x + y ≥ 8

Also, she plans to spend no more than 9 hr in travel time. Hence:

x + 1.5y ≤ 9

x ≥ 0, y ≥ 0.

Plotting the above equations on geogebra online graphing tool, the solution is (6, 2), (8, 0) and (9, 0).

If a train trip costs ​$6 and a bus trip costs ​$5, The cost equation (C) is:

C = 6x + 5y

At point (6, 2): C = 6(6) + 5(2) = $46

At point (8, 0): C = 6(8) + 5(0) = $48

At point (9, 0): C = 6(9) + 5(0) = $54

Therefore the minimum cost is at (6, 2). She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.

Answer:

2x + 2y = 4 and 4x + 4y = 16

Step-by-step explanation:

For two lines to be parallel, they must have the same slope.

To determine the correct answer to the question, we shall determine the slope of each equation in the given options to see which have the same slope. This can be obtained as follow:

1st option:

3x + 2y = 45 and 8x + 4y = 135

We shall rearrange the above equations to look like y = mx + c

NOTE: m is the slope.

3x + 2y = 45

rearrange

2y = –3x + 45

Divide both side by 2

y = –3x/2 + 45/2

Slope (m) = –3/2

8x + 4y = 135

Rearrange

4y = –8x + 135

Divide both side by 4

y = –8x/4 + 135/4

Slope (m) = –8/4 = –2

The two equation has different slopes. Thus, they are not parallel.

2nd option:

x + y = 25 and 2x + y = 15

x + y = 25

Rearrange

y = –x + 25

Slope (m) = –1

2x + y = 15

Rearrange

y = –2x + 15

Slope (m) = –2

The two equations has different slopes. Thus, they are not parallel.

3rd option:

2x + 2y = 50 and 4x + 2y = 90

2x + 2y = 50

Rearrange

2y = –2x + 50

Divide both side by 2

y = –2x/2 + 50/2

Slope (m) = –2/2 = –1

4x + 2y = 90

Rearrange

2y = –4x + 90

Divide both side by 2

y = –4x/2 + 90/2

Slope (m) = –4/2 = –2

The two equations has different slopes. Thus, they are not parallel.

4th option:

2x + 2y = 4 and 4x + 4y = 16

2x + 2y = 4

Rearrange

2y = –2x + 4

Divide both side by 2

y = –2x/2 + 4/2

Slope (m) = –2/2 = –1

4x + 4y = 16

Rearrange

4y = –4x + 16

Divide both side by 4

y = –4x/4 + 16/4

Slope (m) = –4/4 = –1

The two equations have the same slopes. Thus, they are parallel.

Answer:

The slope is the cost per hour.

$5 per hour

Answer:

(5 a^2 - 4) (25 a^4 + 20 a^2 + 16)

Step-by-step explanation:

Since both terms are perfect cubes, factor using the difference of cubes formula,  

a^3  −  b^ 3 = (a − b) (a^2 + a b + b^2) where a = 5a^2   and  b = 4 .

Answer:

45.9

Step-by-step explanation:

======================================================

Work Shown:

We can apply the law of cosines

a^2 = b^2+c^2-2*b*c*cos(A)

(sqrt(5))^2 = (sqrt(2))^2+(3)^2-2*(sqrt(2))*(3)*cos(A)

5 = 2+9-6*(sqrt(2))*cos(A)

5 = 11-6*(sqrt(2))*cos(A)

11-6*(sqrt(2))*cos(A) = 5

-6*(sqrt(2))*cos(A) = 5-11

-6*(sqrt(2))*cos(A) = -6

(sqrt(2))*cos(A) = -6/(-6)

(sqrt(2))*cos(A) = 1

cos(A) = 1/(sqrt(2))

cos(A) = sqrt(2)/2

A = 45 degrees

Use the unit circle for the last step.

Interestingly, this triangle has only one angle that is a whole number. The other two angles are approximate decimal values.

Answer:

the degree is the value of the biggest exponent = 5 (fifth degree)

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Since the highest power of x is 5, the degree of the polynomial x

3

−9x+3x

5

is 5.

Answer:

The answer is "sometimes".

Step-by-step explanation:

A one-way ANOVA was merely performed on one collected data and the null hypothesis was rejected after an ANOVA F test. Assume we could randomize ANOVA block design with the same information. This null hypothesis for full equality is sometimes rejected for the randomized complete block design ANOVA. Therefore we understand the use of randomized ANOVA block if the null hypothesis is denied of a one-way ANOVA but the rejection of a null RBD ANOVA hypothesis isn't conditional mostly on denial of the yet another ANOVA null.

Answer:

0.0002

Step-by-step explanation:

4 decimal places means tenths, hundredths, thousandths, and ten thousandths places. If we count 4 decimal places, we come to 0.0002. The number next to it, 3, rounds down, so the answer should be 0.0002.

Answer:

64 Bottles

Step-by-step explanation:

that is the procedure above

Answer:

[tex]3x^{2} -3x-11 = 0[/tex]

Step-by-step explanation:

Answer:

the number of flight lines needed is approximately 72

Step-by-step explanation:

Given the data in the question;

Aerial photography is to be taken of a tract of land that is 8 x 8 mi²

L × B = 8 x 8 mi²

Flying height H = 4000 ft = ( 4000 × 12 )inches = 48000 in

focal length f = 6 in

[tex]l[/tex] × b = 9 × 9 in²

side overlap = 30% = 0.3

meaning remaining side overlap = 100% - 30% = 70% = 0.7

{ not end to end overlap }

we take 100% { remaining overlap }

[tex]l[/tex]' = 9 × 100% = 9 in

b' = 9 × 70% = 6.3 in

Now the scale will be;

Scale = f/H

we substitute

Scale = 6 in /  48000 in = 1 / 8000

so our scale is; 1 : 8000

⇒ 1 in = 8000 in

⇒ 1 in = (8000 / 63360)mi

⇒ 1 in = 0.126 mi

so since

L × B = 8 x 8 mi²

[tex]l[/tex]' = ( 9 × 0.126 mi ) = 1.134 mi

b' = ( 6.3 × 0.126 mi ) = 0.7938 mi

Now we get the flight lines;

N = ( L × B ) / ( [tex]l[/tex]' × b' )

we substitute

N = ( 8 mi × 8 mi ) / ( 1.134 mi × 0.7938 mi )

N = 64 / 0.9001692

N = 71.0977 ≈ 72

Therefore, the number of flight lines needed is approximately 72

Answer:

There are 824 deer in the preserve.

Step-by-step explanation:

Since to determine the number of deer in a game preserve, a conservationist catches 412 deer, tags them and lets them loose, and later, 316 deer are caught, 158 of them are tagged, to determine how many deer are in the preserve you must perform the following calculation:

316 = 100

158 = X

158 x 100/316 = X

50 = X

50 = 412

100 = X

824 = X

Therefore, there are 824 deer in the preserve.

Answer:

45 miles per hour

Step-by-step explanation:

d=distance in miles

r=rate miles/hr

t = time in hours

t = 352/(r+3)

330/r = 352/(r+3)

352r = 330r + 990

22r = 990

r = 45

Answer:

1. Convert all measurements to meters:

2.5km * 1,000 = 2,500m;.250km * 1,000 = 250m; 2,500cm / 100 = 25m

25,000cm / 100 = 250m; 250mm / 1,000 =.25m

2.) Compare the converted measurements. Therefore, the quantities that are equivalent to 250m are:

.250km; 25,000cm

Step-by-step explanation:

Answer:

Here's your answer.

Step-by-step explanation:

Just multiply in

Answer:

0.0756

Step-by-step explanation:

p(success), p = 70% = 0.7

Nunber of trials, n = 4

q = 1 - p = 1 - 0. 7 = 0.3

x = 1

The question meets the requirements of a binomial probability distribution :

P(x = x) = nCx * p^x * q^(n-x)

P(x = 1) = 4C1 * 0.7^1 * 0.3^(4-1)

P(x = 1) = 4C1 * 0.7 * 0.3^3

P(x = 1) = 4 * 0.7 * 0.027

P(x = 1) = 0.0756

Answer:

not true....

assume $100 start.

in year 1 you are at $108 (up 8%)

in year 2  $108(.98) ... that is 2% down = 105.84...

thus your profit is up only 5.84% over the two years

Step-by-step explanation: