Solve x∕3 < 5 Question 5 options: A) x ≥ 15 B) x > 15 C) x < 15 D) x ≤ 15

Answer:

A.

Step-by-step explanation:

Each mark is worth two. We are inbetween the first mark and 0 on the left. Half of two is one. and since we are in the left quadrant we know it to be negative. Looking down, we see that we are exactly one mark down. As a mark is two, ans that we are going down, this will be a negative two. That leaves us with the answer of (-1, -2)

Answer:

A. (-1,-2)

Step-by-step explanation:

just trust me...I promise it right

Answer:

Option C (25%) is the correct answer.

Step-by-step explanation:

Given:

Number of students,

= 120

Students responded high interest,

= 30

Students responded medium interest,

= 50

Students responded low interest,

= 40

Now,

The relative frequency will be:

= [tex]\frac{30}{120}[/tex]

= [tex]0.25[/tex]

or,

= [tex]25[/tex]%

The expression cos240 degrees is equivalent to cos120 degrees

Answer: B. cos240°

Step-by-step explanation:

Took the Test/Exam on Edge

Answer:

28.0125 cm^2 rounded to 28.0 cm^2

Step-by-step explanation:

Area = a*b*sin(c)*1/2

Area = 7 * 13 * sin(38) * 1/2

Area = 91/2 * 0.61566...

Area = 28.0125...

Answer:

no solution?

Step-by-step explanation:

2(5)-5=5(5)+7+3(5)        <-- plug in 5

10−5=25+7+15

5=32+15

5=47

[tex] \underline{ \huge \mathcal{ Ànswér} } \huge: - [/tex]

Average of b and c is 8, that is

[tex]➢ \: \: \dfrac{b + c}{2} = 8[/tex]

[tex]➢ \: \: b + c = 16[/tex]

[tex]➢ \: \: c = 16 - b[/tex]

now let's solve for average of c and d :

[tex]➢ \: \: \dfrac{c + d}{2} [/tex]

[tex]➢ \: \: \dfrac{16 - b + 3b - 4}{2} [/tex]

[tex]➢ \: \: \dfrac{12 + 2b}{2} [/tex]

[tex]➢ \: \: \dfrac{2(6 + b)}{2} [/tex]

[tex]➢ \: \: b + 6[/tex]

Therefore, the average of c and d, in terms of b is : -

[tex] \large \boxed{ \boxed{b + 6}}[/tex]

[tex]\mathrm{✌TeeNForeveR✌}[/tex]

Answer:

b+6

Problem:

If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?

Step-by-step explanation:

We are given (b+c)/2=8 and d=3b-4.

We are asked to find (c+d)/2 in terms of variable, b.

We need to first solve (b+c)/2=8 for c.

Multiply both sides by 2: b+c=16.

Subtract b on both sides: c=16-b

Now let's plug in c=16-b and d=3b-4 into (c+d)/2:

([16-b]+[3b-4])/2

Combine like terms:

(12+2b)/2

Divide top and bottom by 2:

(6+1b)/1

Multiplicative identity property applied:

(6+b)/1

Anything divided by 1 is that anything:

(6+b)

6+b

b+6

Answer:

28 are in the larger class.

Step-by-step explanation:

50/2 = 25 xy

25+ 3 = 28 larger

25-3 = 22 smaller

x = 28

The larger class has 28 students, and the correct option is 28.

Let's assume the number of students in one class is x.

According to the given information, the other class has 6 more students than this class, which means the number of students in the other class is x + 6.

To find the total number of students, we add the number of students in both classes: x + (x + 6) = 50.

Combining like terms, we have: 2x + 6 = 50.

Next, we subtract 6 from both sides of the equation: 2x = 44.

Finally, we divide both sides of the equation by 2 to solve for x: x = 22.

So, there are 22 students in one class, and the other class has 22 + 6 = 28 students.

Therefore, the larger class has 28 students, and the correct option is 28.

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Answer:

its the 4 one

Step-by-step explanation:

Answer:

There are 75 ways to form the committee.

Step-by-step explanation:

The order in which the people are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

Considering the eldest has to be there, 2 men from a set of 6 and 4 boys from a set of 5(excluding the youngest), so:

[tex]T = C_{6,2}C_{5,4} = \frac{6!}{2!4!} \times \frac{5!}{1!4!} = 3*5*5 = 75[/tex]

There are 75 ways to form the committee.

Answer:

1. >

2. <

3. =

4. <

Step-by-step explanation:

23.197 > 23.179

3 2/10 which is the same as,

3.2 < 3.243

30.423 = 30 423/1000

18.546 < 18 56/100

Answer:

The ratio between two values A and B is just the quotient between these two values:

ratio = A/B

a) $280 in 7m

Here the ratio is:

$280/7m = $40/m

This also can be read as:

$40 per meter.

b) 105 miles in 2 hours

Here the ratio is:

105mi/2h = 52.5 mi/h

This also can be read as:

52.5 miles per hour

c) $33 for 5lb

The ratio is:

$33/5lb = $6.6/lb

This can be read as:

$6.6 per pound.

d) 50 pages in 2 hours

the ratio is:

(50 pages)/2h = 25 pages/h

this can be read as:

25 pages per hour.

Answer:

The p-value of the test statistic is 0.2019.

Step-by-step explanation:

Test if there is evidence at the 0.02 level that the medicine relieves pain in more than 384 seconds.

At the null hypothesis, we test if it relieves pain in at most 384 seconds, that is:

[tex]H_0: \mu \leq 384[/tex]

At the alternative hypothesis, we test if it relieves pain in more than 384 seconds, that is:

[tex]H_1: \mu > 384[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

384 is tested at the null hypothesis:

This means that [tex]\mu = 384[/tex]

For a sample of 41 patients, the mean time in which the medicine relieved pain was 387 seconds. Assume the population standard deviation is 23.

This means that [tex]n = 41, X = 387, \sigma = 23[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{387 - 384}{\frac{23}{\sqrt{41}}}[/tex]

[tex]z = 0.835[/tex]

P-value of the test:

The p-value of the test is the probability of finding a sample mean above 387, which is 1 subtracted by the p-value of z = 0.835.

Looking at the z-table, z = 0.835 has a p-value of 0.7981.

1 - 0.7981 = 0.2019

The p-value of the test statistic is 0.2019.

Answer:

Step-by-step explanation:

Total number of outcome are  

1320

.

Explanation:

It is apparent that there are  

12

ways in which the post of President can be filled. Once President's post is filled, there are  

11

ways to fill the post of Vice President and then  

10

ways to fill the post of Secretary,

Hence a total of  

12

⋅

11

⋅

10

or  

1320

ways or outcomes.

Answer:

1320

Step-by-step explanation:

Answer:

0.9842 = 98.42% probability that at least six of them find employment in their chosen field within three months.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they found employment, or they did not. The probability of a student finding employment is independent of any other student, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

88% of students who graduate from the university successfully find employment in their chosen field within three months of graduation.

This means that [tex]p = 0.88[/tex]

Nine randomly selected students

This means that [tex]n = 9[/tex]

What is the probability that of nine randomly selected students who have graduated from this university, at least six of them find employment in their chosen field within three months?

This is:

[tex]P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 6) = C_{9,6}.(0.88)^{6}.(0.12)^{3} = 0.0674[/tex]

[tex]P(X = 7) = C_{9,7}.(0.88)^{7}.(0.12)^{2} = 0.2119[/tex]

[tex]P(X = 8) = C_{9,8}.(0.88)^{8}.(0.12)^{1} = 0.3884[/tex]

[tex]P(X = 9) = C_{9,9}.(0.88)^{9}.(0.12)^{0} = 0.3165[/tex]

Then

[tex]P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) = 0.0674 + 0.2119 + 0.3884 + 0.3165 = 0.9842[/tex]

0.9842 = 98.42% probability that at least six of them find employment in their chosen field within three months.

Answer:

[tex] \displaystyle 4[/tex]

Step-by-step explanation:

we are given that A vegetable garden and a surrounding as a shaped like a square that together a 11 ft wide. The path is 2 feet wide.since together the width of Vegetable garden and path is 11 ft, the width of the vegetables garden will be the difference between the total width and the width of path Thus,

[tex] \displaystyle \rm W _{ garden} = 11 - 2[/tex]

simplify substraction:

[tex] \displaystyle \rm W _{ garden} = 9[/tex]

recall that, every single side of a square is equal to each other therefore the the area of the garden will be

[tex] \displaystyle {9}^{2} [/tex]

simplify square:

[tex] \displaystyle 81[/tex]

together the garden and path makes a square of every side length 11 ft saying that the area will be:

[tex] \displaystyle {11}^{2} [/tex]

simplify square:

[tex] \displaystyle 121[/tex]

the area of path will be the difference between the total area and the garden area therefore,

[tex] \displaystyle 121 - 81[/tex]

simplify addition:

[tex] \displaystyle 40[/tex]

to figure out how many bags are needed to cover the path. we just need to divide the area of the path by the area of a bag of gravel and that yields:

[tex] \displaystyle \frac{40}{10} [/tex]

simplify division:

[tex] \displaystyle \boxed{\rm4}[/tex]

hence,

4 bags are needed to cover the path.

Answer:

r=-4+2[tex]\sqrt{5}[/tex], r=-4-2[tex]\sqrt{5}[/tex]

Answer:

r=-4+2[tex]\sqrt{5}[/tex], r=-4-2[tex]\sqrt{5}[/tex]

Step-by-step explanation:

It was right for me

Answer:

e. All of the above statements are correct.

Option e is correct. All of the above statements are correct.

Data science is an interdisciplinary academic field that uses statistics, scientific computing, scientific methods, processes, algorithms and systems to extract or extrapolate knowledge and insights from noisy, structured and unstructured data

Data Scientist makes value out of data, he is expert in various tools and technologies like machine learning, deep learning, artificial intelligence and he solve business problems by presenting a model to predict business future.

During data preparation, data scientists and DBAs aggregate the data and merge them from different sources. During data preparation, data scientists and DBAs define the variables to be used in the model.

Hence, All of the above statements are correct, Option e is correct.

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Answer:

The p-value of the test is 0.0139 < 0.05, which means that these data indicates that the population proportion of voter turnout in Colorado is higher than that in California.

Step-by-step explanation:

Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

California:

Sample of 296 voters, 146 voted. This means that:

[tex]p_{Ca} = \frac{146}{296} = 0.4932[/tex]

[tex]s_{Ca} = \sqrt{\frac{0.4932*0.5068}{296}} = 0.0291[/tex]

Colorado:

Sample of 215 voters, 127 voted. This means that:

[tex]p_{Co} = \frac{127}{215} = 0.5907[/tex]

[tex]s_{Co} = \sqrt{\frac{0.5907*0.4093}{215}} = 0.0335[/tex]

Test if the population proportion of voter turnout in Colorado is higher than that in California:

At the null hypothesis, we test if it is not higher, that is, the subtraction of the proportions is at most 0. So

[tex]H_0: p_{Co} - p_{Ca} \leq 0[/tex]

At the alternative hypothesis, we test if it is higher, that is, the subtraction of the proportions is greater than 0. So

[tex]H_1: p_{Co} - p_{Ca} > 0[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{s}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.

0 is tested at the null hypothesis:

This means that [tex]\mu = 0[/tex]

From the two samples:

[tex]X = p_{Co} - p_{Ca} = 0.5907 - 0.4932 =  0.0975[/tex]

[tex]s = \sqrt{s_{Co}^2+s_{Ca}^2} = \sqrt{0.0291^2+0.0335^2} = 0.0444[/tex]

Value of the test statistic:

[tex]z = \frac{X - \mu}{s}[/tex]

[tex]z = \frac{0.0975 - 0}{0.0444}[/tex]

[tex]z = 2.2[/tex]

P-value of the test and decision:

The p-value of the test is the probability of finding a difference above 0.0975, which is 1 subtracted by the p-value of z = 2.2.

Looking at the z-table, z = 2.2 has a p-value of 0.9861.

1 - 0.9861 = 0.0139.

The p-value of the test is 0.0139 < 0.05, which means that these data indicates that the population proportion of voter turnout in Colorado is higher than that in California.

Answer:

[tex]x=216 salads[/tex]

Step-by-step explanation:

One Hour:

Salad=40

Sandwich=19

Total work time[tex]T=7[/tex]

Generally

Time to make 30 sandwiches is

[tex]T_s=\frac{30}{19}[/tex]

[tex]T-s=1.6hours[/tex]

Therefore

Bill has 7-1.6 hours to make salads and can make x about of salads in

[tex]x=(7-1.6)*40[/tex]

[tex]x=5.4*40[/tex]

[tex]x=216 salads[/tex]

Answer:

(in attachment)

Step-by-step explanation:

you can find the points by inputting the x-values into the equation to solve for the y-values, then connecting the plotted points to create the line.

When x=-4

y=1/2(-4)

y=-2

(-4,-2)

Repeat for all values.

Answer:

Step-by-step explanation:

A relation may or may not represent a function.

Table (a), (c) and (d) represent a function

The tables represent a relation

For a relation to be a function, then:

The y values must have unique (or distinct) x-values.

From the list of tables, we have the following observations

Hence, all the tables represent a valid function, except table (b)

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Answer:

◦•●◉these are related functions

Answer:

C.

Step-by-step explanation:

1) note, the point "а" belongs to the given interval only, then

2) the correct answer is C) a.

Answer:

as we can see here point {\color{Red}a} lies on the interval (-2, -1)

so option A is correct

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

96n = 520 + 31n

65n=520

n=8

Hope this helps :)

Answer:

[tex]P=8.869[/tex]

Step-by-step explanation:

From the question we are told that:

Mean [tex]\=x =38[/tex]

Variance [tex]\sigma=52[/tex]

Sample size [tex]n=16[/tex]

[tex]X=(33, 43)[/tex]

Generally the equation for Chebyshev's Rule  is mathematically given by

[tex]A=(1-\frac{1}{k^2})*100\%[/tex]

Where

[tex]k=\frac{\=x-\mu}{\frac{\sigma}{\sqrt n}}}}[/tex]

[tex]k=\frac{43-38}{\frac{52}{\sqrt 16}}}}[/tex]

[tex]k=2.77[/tex]

Therefore

Probability

[tex]P=(1-\frac{1}{2.77^2})[/tex]

[tex]P=8.869[/tex]

Answer:

75

Step-by-step explanation:

For non-normal distributions, we use Chebyshev's Theorem.

Chebyshev Theorem

The Chebyshev Theorem states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

In this question:

Within 2 standard deviations of the mean, so 75%.

Answer:

a. best score to guess would be 33

b. Standard deviation simplifies the square root of the mean so makes it closer to 1 has more consistency as the mean of 32 when squared is sqrt 32  is Class A as class a = 4 and is closer to 5.65685425

as 5.65685425^2 = 32

Step-by-step explanation:

If you are comparing two normally-distributed variables on the same measurement scale then yes, you can regard the standard deviation as an indicator of how reliable the mean is--the smaller the standard deviation, the better able you are to "zero in" on the actual population mean.

a. proofs;

We find  32/6 = 5.333 and 32/5 = 6.4 and 6.4 is closer to both sd 4 and 8 than 5.33 is. As 6.4 it is closer to 6

But when we use 33/6 = 5.5 and therefore shows close range 6

therefore the two sd  proves it is slightly high 32 score average for both classes A + B when joined and high 32 = 33 mean when classes A+B are joined or you could say 32/8 = 4 is class B becomes lower tests scores as 32/4 = 8 of class A that has higher test scores.

In this exercise we have to use probability and statistics to organize the students' grades, so we have:

A) best score is  33

B) Class A

In the first part of the exercise we have to analyze the grades of each class, like this:

A)Class A: 32/4

Class B: 32/8

Dividing each of them we have:

[tex]32/4=8 \\32/8=4[/tex]

B) With the information given above, we can say that the best class is A.

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