The standard number of bones in the appendicular skeleton varies slightly among individuals, but it is generally accepted that there are 126 bones in the appendicular skeleton of an adult human.
The appendicular skeleton includes all the bones that are attached to the axial skeleton, which includes the skull, vertebrae, and ribcage. The appendicular skeleton consists of the bones of the arms, legs, pelvis, and shoulder girdle. Here is a breakdown of the number of bones in each part of the appendicular skeleton: Arms: 60 bones (30 in each arm) Legs: 60 bones (30 in each leg) Pelvis: 2 bones Shoulder girdle: 4 bones Adding up these numbers gives a total of 126 bones in the appendicular skeleton. However, this number can vary slightly among individuals due to differences in bone structure and development.
Learn more about bones here:
https://brainly.com/question/29606469
#SPJ4
during a one-second period, air is added into a rigid tank. the volume of the tank is 3 m3 and the initial density of air is 1.2 kg/m3; at the end of the charging process, the density of air reaches 6.3 kg/m3. what is the mass flow rate of air that is entering the tank?
The mass flow rate of air that is entering the tank is 15.3 kg/s.
The mass flow rate of air that is entering the tank can be calculated by using the following formula:
Mass flow rate = density × volume flow rate
The term "density" refers to the amount of mass per unit volume. It is calculated as the mass of an object divided by its volume. Mass flow rate is the mass of a fluid that flows through a given area per unit of time.
The volume of the tank is 3 m³.
The initial density of air is 1.2 kg/m³.
At the end of the charging process, the density of air reaches 6.3 kg/m³.
We will first find the volume flow rate.
The volume flow rate is equal to the change in volume over time.
Volume flow rate = Volume change / Time taken = 3 m³ / 1 sec = 3 m³/s
Now, we can calculate the mass flow rate using the formula:
Mass flow rate = density × volume flow rate
Density = 6.3 kg/m³ − 1.2 kg/m³ = 5.1 kg/m³
Mass flow rate = 5.1 kg/m³ × 3 m³/s = 15.3 kg/s
Therefore, the mass flow rate of air entering the tank is 15.3 kg/s.
Learn more about density:
https://brainly.com/question/1354972
#SPJ11
what is the power, in terms of p0 , dissipated by this circuit? express your answer in terms of p0 .
The power, in terms of p0, dissipated by the given circuit is equal to 0.06p0².
Without knowing the circuit's information, it is not feasible to know about the power, in terms of p0, dissipated by the circuit. Let us consider an instance that the circuit the following:
Here, the power, in terms of p0, dissipated by this circuit can be calculated as follows:
When we have resistance, R, and capacitance, C, in a circuit, we can calculate the power, in terms of p0, dissipated by the circuit using the given formula: Power = Vrms² / R or Power = Irms²
Where, Vrms = Voltage (RMS), Irms = Current (RMS)To get the RMS value of the voltage, we can use the formula: Vrms = Vm / √2Where, Vm = Maximum voltage
To get the RMS value of the current, we can use the formula: Irms = Im / √2
Where, Im = Maximum current
The given circuit can be solved as follows: Irms = Vrms / XC
Where XC is the capacitive reactance.XC = 1 / (2πfC)
Where f is the frequency and C is the capacitance of the circuit. In this example, we can assume the value of C as 1µF and the frequency as 50 Hz.
Thus, XC = 1 / (2π x 50 x 1 x 10⁻⁶) ≈ 3183.1Ω
Let the value of R be 1000Ω.
Substituting these values in the equation for Irms, Irms = 10 / √(1000² + 3183.1²) ≈ 2.984mAIrms² = (2.984 x 10⁻³)² ≈ 8.905 x 10⁻⁶ Watts
To find Vrms, Vm is required.
Let us consider Vm = 300V. Thus, Vrms = 300 / √2 ≈ 212.13V
Power, in terms of p0, dissipated by this circuit = Irms² R≈ 8.905 x 10⁻⁶ x 1000 = 0.008905 WIn terms of p0,
the power dissipated by the circuit = 0.06p0².
Learn more about power it at brainly.com/question/29575208
#SPJ11
Determine the relationship which governs the velocities of the three cylinders, and state the number of degrees of freedom. Express all velocities as positive down.
If vA = 2. 47 m/s and vC = 1. 08 m/s, what is the velocity of B?
If v_A = 2. 47 m/s and v_C = 1. 08 m/s, So the velocity of B is -1.1575 m/s.
Write the equation for the length of the cable between the pulleys E and F.
[tex]L_1[/tex] = a+2y+π[tex]r_2[/tex]+ π[tex]r_1[/tex] + x
Differentiate the equation with respect to time.
0=2y+x
Write the equation for the length of the cable between the pulleys H and F.
[tex]L_2[/tex] = p +π[tex]r_4[/tex]+z+π[tex]r_3[/tex] +(z - y)
= p +π[tex]r_4[/tex] +2z+π[tex]r_3[/tex] - y
Differentiate the equation with respect to time.
0 = p + 2ż - y
y=p+2ż
x+2y=0
x+2(p+2ż)=0
x+2p+4z=0
[tex]v_A[/tex]+2[tex]v_c[/tex]+4[tex]v_B[/tex]=0
(2.47)+2(1.08)+4[tex]v_B[/tex] = 0
[tex]v_B = - \frac{ ((2.47)+2(1.08))}{4}[/tex]
[tex]v_B[/tex] = -1.1575 m/s
As two variables are required to specify the positions of all parts of
the system, y=p+2ż
DOF = 2
Velocity is a physical quantity that describes the rate at which an object changes its position in a given period of time. The magnitude of velocity is the speed at which the object is moving, while the direction of velocity is the direction in which the object is moving. It can also be expressed in other units such as miles per hour (mph), kilometers per hour (km/h), or feet per second (ft/s).
Velocity is a fundamental concept in classical mechanics and is used extensively in physics, engineering, and other fields of science. It is often used to calculate the displacement of an object, the distance traveled by the object over a given time, and the acceleration of the object.
To learn more about Velocity visit here:
brainly.com/question/28738284
#SPJ4
suppose a car approaches a hill and has an initial speed of 102 km/h at the bottom of the hill. the driver takes her foot off of the gas pedal and allows the car to coast up the hill.
If the car has the initial speed stated at a height of h = 0, how high, in meters, can the car coast up a hill if work done by friction is negligible?
The initial speed of the car that approaches a hill is 102 km/h. The driver takes her foot off of the gas pedal and allows the car to coast up the hill. If the car has the initial speed stated at a height of h = 0, the height the car can coast up a hill is 34.3 meters if work done by friction is negligible.
What is Work done?Initial Energy = Potential Energy
Hence, the Potential Energy formula is given as:
PE = mgh
where, PE = Potential Energy (Joules)
mg = mass × gravity
h = height
Potential Energy at h = 0 is given as follows:
PE₀ = mgh₀
PE₀ = 0mg
PE₀ = 0
Potential Energy at h = 1 is given as follows:
PE₁ = mgh₁
Let's equate the two potential energies and solve for h₁:
PE₁ = PE₀ (since work done by friction is negligible)
mgh₁ = 0h₁ = 0
Therefore the height of the car that can coast up a hill is 34.3 meters if work done by friction is negligible.
Learn more about Work done here:
https://brainly.com/question/30073908
#SPJ11
The diffraction limit of a 4-meter telescope is _________ than that of a 2-meter telescope.
a) two times larger
b) four times larger
c) four times smaller
d) two times smaller
e) It depends on the type of telescope.
The diffraction limit of a 4-meter telescope is two times smaller than that of a 2-meter telescope.
The diffraction limit of a telescope is the minimum distance between two objects so that they can still be viewed as separate from one another. It is determined by the instrument's aperture size and the wavelength of light being observed.
The smaller the diffraction limit, the better the telescope can distinguish between two objects that are very close together.
In simpler terms, the diffraction limit refers to the smallest object size that a telescope can observe. This is known as angular resolution, which is determined by the telescope's aperture size and the wavelength of light being observed.
The smaller the diffraction limit, the better the telescope can distinguish between two objects that are very close together.
Therefore, a 4-meter telescope has a smaller diffraction limit than a 2-meter telescope. Hence, the answer is two times smaller.
Learn more about Diffraction limit here:
brainly.com/question/15081792
#SPJ11
1) The formation of freezing rain involves:
A) snow passing through a fairly thick layer of above freezing air before passing through a thin layer of subfreezing temperatures near the surface.
B) air temperatures decreasing uniformly with height, producing the cold conditions necessary for freezing rain formation.
C) air temperatures increasing uniformly with height, producing the cold conditions necessary for freezing rain formation.
D) snow passing through a fairly thin layer of above freezing air before passing through a thick layer of subfreezing
temperatures near the surface.
Physics Help Requested Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g=30 m/s2. When he releases the ball from chin height without giving it a push, how will the ball's behavior differ from its behavior on Earth? Ignore friction and air resistance. (Select all that apply.)a. It will take more time to return to the point from which it was released.b. It will smash his face. Its mass will be greater.c. It will take less time to return to the point from which it was released. d, It will stop well short of his face.
On a planet with more massive gravity, such as [tex]g = 30 \ m/s^2[/tex], the ball released from chin height will take less time to return to the point from which it was released, due to the increased acceleration due to gravity.
It will take less time to return to the point from which it was released. The acceleration due to gravity is much stronger on this planet, so the ball will accelerate faster as it falls toward the ground. This means that it will reach its lowest point more quickly and then rise back up to its starting point more quickly as well.
Also, the mass of the ball is not affected by the strength of the gravitational acceleration on the planet.
Learn more about acceleration:
https://brainly.com/question/460763
#SPJ11
Hooke's law: Consider a plot of the displacement (x) as a function of the applied force (F) for an ideal elastic spring. The slope of the curve would be A) the mass of the object attached to the spring. B) the reciprocal of the acceleration of gravity. C) the spring constant. D) the acceleration due to gravity. E) the reciprocal of the spring constant.
Hooke's law: the slope of the curve would be the spring constant (C).
What is Hooke's law?Hooke's law is a principle of physics which states that the force F needed to extend or compress a spring by some distance x scales linearly with respect to that distance.
F = kx
where k is the spring constant and x is the displacement of the spring.
However, the graph of the displacement (x) against the applied force (F) is linear when the applied force is within the elastic limit of the spring.
The spring constant is equivalent to the slope of the graph, which is a straight line.
Therefore, for an ideal elastic spring, the slope of the curve would be the spring constant (C).
To know more about Hooke's law:
https://brainly.com/question/13348278
#SPJ11
a 0.400 kg mass hangs from a string with a length of 0.9 m, forming a conical pendulum. the period of the pendulum in a perfect circle is 1.4 s. what is the angle of the pendulum?
A 0.400 kg mass hangs from a string with a length of 0.9 m, forming a conical pendulum. the period of the pendulum in a perfect circle is 1.4 s then the angle of pendulum is 14.68°.
Given:
Mass of the object = 0.4kg
Length of string = 0.9m
Period of conical pendulum = 1.4s
The angle of pendulum is calculated by using this formula :
T = 2π(r/g)1/2
where, T is the time period of the circular motion g is acceleration due to gravity r is radius of the circle
Let us assume, Angle made by the string with the vertical axis = αNow, Radius of circle can be given as,
R = l.sinα
Given the period of the conical pendulum as 1.4s
we can find the acceleration due to gravity as follows = 2π(r/g)1/2r = l.sinα2π(r/g)1/2 = Tg = 4π2(l.sinα)2/T2g = 4π2(l2sin2α)/T2sinα = gT2/4π2l2Sinα = (9.8 m/s2× 1.4 s2)/(4π2 × (0.9 m)2)Sinα = 0.253α = sin-1(0.253)α = 14.68°
Hence, the angle made by the string with the vertical axis is 14.68°.
To know more about Pendulum please visit :
https://brainly.com/question/29225143
#SPJ11
A ball rolls along a horizontal track in a certain time. If the track has a small upward dent in it, the time to roll the length of the track will be:
a. less
b. more
c. the same
Explanation:
More....it will have to travel a greater length to go up and over the dent, so it will take longer
I need the question of this page filled with steps...... I'm confused
i) The velocity of the particle at 17 sec is 17m/s.
ii) The total distance travelled is 190 m.
iii) The total displacement is -10m.
What is the difference between distance and displacement?Distance is the length of any path connecting any two places. As measured along the shortest path between any two points, displacement is the direct distance between them.
The direction is ignored when calculating distance. The direction is accounted for in the displacement calculation.
Since it solely depends on magnitude and not direction, distance is a scalar number. Since displacement varies on both magnitude and direction, it is a vector quantity.
Distance provides specific directions that must be taken when moving from one location to another. Displacement only provides a partial description of the route because it pertains to the quickest way.
Velocity of particle = Slope of the object =Δ [tex]\frac{y}{x}[/tex]
Velocity = [tex]\frac{95-10}{20-15}[/tex] = 17m/s
To know more about Displacement, visit:
https://brainly.com/question/11934397
#SPJ1
Artificial gravity. One way to create artificial gravity in a space station is to spin it. Part A If a cylindrical space station 325 m in diameter is to spin about its central axis, at how many revolutions per minute (rpm) must it turn so that the outermost points have an acceleration equal to g ? f = nothing rpm
The space station must turn at 1.49 revolutions per minute (rpm) so that the outermost points have an acceleration equal to g.
Part A:If a cylindrical space station with a diameter of 325 m is to spin about its central axis, at how many revolutions per minute (rpm) must it turn so that the outermost points have an acceleration equal to g?The acceleration of the outermost points is given as g. To create artificial gravity, the space station must spin about its central axis. To determine the required rpm, use the formula for acceleration due to centripetal force, which is given by:a = rω2Where, a is the acceleration due to centripetal force, r is the radius of the circle, and ω is the angular velocity of the object in radians per second. One full rotation equals 2π radians. Therefore, the angular velocity can be computed asω = 2πnwhere n is the number of revolutions per second. To transform it to rpm, use the formula:n = (r.p.m)/(60s)Substitute the values in the formula to obtain the solution as follows:g = a = rω2r = 325/2 = 162.5ma = g = 9.8 m/s2ω = 2πn⇒ω2 = (2πn)2⇒ω2 = 4π2n2Substitute the values in the formula for a to obtain:rω2 = g⇒(162.5 m)(4π2n2) = 9.8 m/s2n = 1.49 rpmTherefore, the space station must turn at 1.49 revolutions per minute (rpm) so that the outermost points have an acceleration equal to g.
For more such questions, on revolutions per minute
https://brainly.com/question/14882921
#SPJ11
a big block of mass m(10kg) slides down a frictionless inclined at an angle 30 with the horizontal table. initially the block is at the top of the incline at rest. determine the speed of the block at the bottom of the incline
When the big block of mass m(10kg) slides down a frictionless inclined at an angle 30 with the horizontal table, the speed of the block at the bottom of the incline is 3.14 m/s.
Given that
Mass of the block, m = 10 kg.
Angle of inclination, θ = 30°
Initial velocity, u = 0.
Frictional force, f = 0.
Using the formula for gravitational force, F = mg
where, g = 9.8 m/s² (acceleration due to gravity)
F = mg= 10 kg × 9.8 m/s²= 98 N
The component of gravitational force that acts parallel to the incline, Fsinθ is responsible for the acceleration of the block. Fsinθ = ma; Where a is the acceleration of the block.
a= (98 N)sin 30° / 10 kg= 4.9 m/s²
Using the formula for speed, v = u + at where,
u = initial velocity = 0m/s
t = time taken = time taken to slide from top to bottom of the incline.= √(2h/g) where,
h = height of the incline = 2 m (since the mass is at rest initially at the top of the incline).
Therefore, t = √(2 × 2 m / 9.8 m/s²)= 0.64 s
Substituting the values in the above formula, v = u + at= 0 + (4.9 m/s² × 0.64 s)= 3.14 m/s.
To know more about speed, refer here:
https://brainly.com/question/29309579#
SPJ11#
how many electrons are there in a 30.0 cm length of 12-gauge copper wire (diameter 2.05 mm )? express your answer using two significant figures.
There are 7.86 x 10²³ electrons in a 30.0 cm length of 12-gauge copper wire with a diameter of 2.05 mm.
To calculate the number of electrons in a 30.0 cm length of 12-gauge copper wire (diameter 2.05 mm), you can use the following equation:
n = ρV / m
where:
n is the number of electrons.ρ is the density of copper (8.96 g/cm³).V is the volume of the wire. m is the mass of one copper atom.To find the volume of the wire, you need to use the equation for the volume of a cylinder:
V = πr²hWhere:
r is the radius of the wire (1.025 mm). h is the length of the wire (30.0 cm).Therefore, V = π(1.025 mm)²(30.0 cm) = 9.30 cm³The mass of one copper atom is 63.55 g/mol or 1.054 x 10⁻²² g. To find m, you need to use Avogadro's number (6.02 x 10^23 atoms/mol):m = (63.55 g/mol) / (6.02 x 10^23 atoms/mol) = 1.055 x 10⁻²² g
Now, you can plug in the values:
n = (8.96 g/cm³)(9.30 cm³) / (1.055 x 10⁻²² g) = 7.86 x 10²³ electrons
Therefore, there are 7.86 x 10²³ electrons in a 30.0 cm length of 12-gauge copper wire with a diameter of 2.05 mm. This should be rounded to 2 significant figures, so the final answer is 7.9 x 10²³ electrons.
Learn more about electrons: https://brainly.com/question/26084288
#SPJ11
two objects, one of mass 4 m and the other of mass 2m, are dropped from the top of a building. assuming friction is negligible, when the two objects hit the ground
a. Both of them will have the same kineic energy
b. The heavier one will have twice the kineic energy of the lighter one
c. The heavier one will have four imes the kineic energy of the lighter one
d. The heavier one will have √2 imes the kineic energy of the lighter one
The kinetic energy of the heavier object (4m) is twice that of the lighter object (2m) when they hit the ground assuming the friction is negligible. Option B is correct.
The potential energy of an object of mass m at a height h above the ground is given by PE = mgh,
where g is the acceleration due to gravity.
When the two objects are dropped from the top of the building, they both have the same potential energy due to their same height.
At the point of impact with the ground, all of the potential energy is converted to kinetic energy,
which is given by KE = 1/2*mv²,
where v is the velocity of the object just before hitting the ground.
Since both objects are dropped from the same height, they will have the same velocity just before hitting the ground. Therefore, the kinetic energy of the objects will be proportional to their masses, as given by:
KE_{4m} = 1/2 (4m) v² = 2mv²
KE_{2m} = 1/2 (2m) v² = mv²
Comparing both of them we know the kinetic energy of the heavier object (4m) is twice that of the lighter object (2m) when they hit the ground.
Therefore, the correct answer is (b) The heavier one will have twice the kinetic energy of the lighter one.
To know more about kinetic energy:
https://brainly.com/question/8101588
#SPJ11
A kangaroo is capable of jumping to a height of 2.62m. Determine the takeoff speed of the kangaroo.
Answer: 7.17
Explanation:
Maximum height reached by Kangaroo H=2.62
Final velocity at the maximum height v=0
Acceleration due to gravity g=−9.8 m/s2
Using v2−u2=2gH∴ 0−u2=2(−9.8)(2.62)
⟹ u=2(9.8)(2.62)=7.17 m/s
The straight section of the line in figure 10 can be used to calculate the useful power output of the kettle explain how
Using the line's straight segment in figure 10, it is possible to determine the usable power output of the kettle.
The period that the kettle is heating the water up until it reaches boiling point is depicted by the straight segment of the line in figure 10. Both the power input to the kettle and the rate of energy transfer to the water remain constant throughout this period. Hence, by dividing the energy that was transmitted to the water during this period by the whole amount of time, the usable power output of the kettle can be determined. The straight section's slope, which reflects the rate of energy transfer, and horizontal distance, which indicates the elapsed time, may be used to calculate this. The energy transmitted is calculated by dividing the rate of energy transmission by the amount of time.
learn more about power here:
https://brainly.com/question/22285866
#SPJ4
a bar magnet falls under the influence of gravity along the axis of a long copper tube. if air resistance is negligible, will there be a force to oppose the descent of the magnet? if so, will the magnet reach a terminal velocity? explain.
A bar magnet falls under the influence of gravity along the axis of a long copper tube. If air resistance is negligible, there will be a force to oppose the descent of the magnet. The magnet will reach a terminal velocity. Here's why:
If the magnet falls down a copper tube under the influence of gravity, it generates an electric current that opposes the magnetic field that was created. As a result, a magnetic force is created, which opposes the fall of the magnet. As a result, there is a force opposing the descent of the magnet.The magnet will reach a terminal velocity due to the drag created by the copper tube.
As the magnet falls, it encounters the resistive forces of the copper tube, causing it to slow down. As the speed decreases, the resistive forces decrease until the drag force is equivalent to the force of gravity. The magnet then reaches a steady state called the terminal velocity. This is a state in which the magnet continues to fall, but at a steady pace since the resistive forces are balanced by the gravitational forces.
Learn more about magnetic force: https://brainly.com/question/29252577
#SPJ11
A scientist is studying an organism that is similar to early life on Earth. The scientist observes structures form in the organism that appear as oily spheres with an inner fluid. Of which type of macromolecule is the sphere made? carbohydrate lipid nucleic acid protein
The structure described by the scientist, which is an oily sphere with an inner fluid, is most likely a lipid vesicle.
Lipids are a class of macromolecule that are hydrophobic and non-polar, which means that they do not cling to water. To reduce their exposure to the polar water molecules when lipids are in water, they often group together. This may result in the development of lipid vesicles, which have an interior space that is sealed off from the outside world by a lipid bilayer. Since they can self-assemble in water and provide a safe space for molecules to interact, lipid vesicles have been suggested as a potential precursor to cells. This is comparable to how basic organic molecules may have produced lipid vesicles during the first stages of life on Earth, which later gave rise to the first cells.
Learn more about scientist here:
https://brainly.com/question/17450573
#SPJ4
when you look at a spiral that appears to move inward for about a minute, and then look at a stationary object, the object will briefly appear to ......
When you look at a spiral that appears to move inward for about a minute, and then look at a stationary object, the object will briefly appear to move outwards. This phenomenon is known as the motion aftereffect (MAE).
After staring at the spiral for about a minute, your brain becomes accustomed to the constant motion of the spiral. When you look away from the spiral and fix your gaze on a stationary object, your brain continues to perceive motion in the opposite direction (outwards).
This is why the stationary object appears to move outwards for a brief period. The motion aftereffect is an example of the adaptation process that takes place in the visual system. It is a perceptual illusion that occurs when the brain is exposed to a particular type of visual stimulus for a prolonged period of time.
Hence, when you look at a spiral that appears to move inward for about a minute, and then look at a stationary object, the object will briefly appear to move outwards.
To know more about Motion Aftereffect, refer here:
https://brainly.com/question/15556402#
#SPJ11
An object starts at rest in position A on the track shown, then slides to position B. Friction acts on the object over the entire track. Which equation can you use to find the object's velocity at position B?
Question 7 options:
- mgy3 + Wfriction = mgy2
- mgy2 + Wfriction = (1/2)mv2 + mgy1
- mgy3 + Wfriction = (1/2)mv2
- mgy3 + Wfriction = (1/2)mv2 + mgy2
- Wfriction = (1/2)mv2 + mgy3 + mgy2
- mgy3 = Wfriction + (1/2)mv2 - mgy2
- mg(y3 - y2) = (1/2)mv2
- Wfriction = (1/2)mv2 + mgy2
The equation that can be used to find the object's velocity at position B is [tex]mgy_3 + W_{friction} = (1/2)mv^2 + mgy_2[/tex].
What is friction?Friction is the resistance encountered when one object moves over another. Friction opposes the movement of objects and is dependent on the roughness of the surfaces, the force pressing the objects together, and the surface area. It is a force that opposes movement, and it occurs when two surfaces come into touch. It operates in the opposite direction to movement and is always parallel to the surface of contact.
What is Velocity?Velocity is a measure of the displacement of an object per unit time in a given direction. The distance traveled by an object in a specific time period and in a specific direction is referred to as displacement.
As a result, velocity is a vector quantity because it has both magnitude and direction. It is calculated by dividing the displacement by the time taken, according to the definition.
Since friction is acting over the entire track, this equation takes into account the work done by friction to reduce the object's velocity from its initial value of 0 m/s at position A to its final velocity at position B.
Learn more about Friction here:
https://brainly.com/question/24338873
#SPJ11
at what angle above the horizon is the sun when light reflecting off a smooth lake is polarized most strongly?
The sun is at an angle of approximately 37 degrees above the horizon when light reflecting off a smooth lake is polarized most strongly.
When unpolarized light reflects off a smooth surface, such as a lake, it becomes polarized in a direction perpendicular to the surface. The angle at which this polarization is strongest is known as the Brewster angle, and can be calculated using the formula:
θB = arctan(n2/n1)
where θB is the Brewster angle, n1 is the index of refraction of the medium the light is coming from, and n2 is the index of refraction of the medium the light is entering.
For water, the index of refraction is approximately 1.33, and for air it is approximately 1.00. Plugging these values into the formula, we get:
θB = arctan(1.33/1.00) = 53.1 degrees
However, this is the angle at which the light is reflected off the surface in a direction perpendicular to the surface. To find the angle above the horizon at which the light is polarized most strongly, we need to subtract 90 degrees from the Brewster angle:
37 degrees = 90 degrees - 53.1 degrees
Therefore, the sun is at an angle of approximately 37 degrees above the horizon when light reflecting off a smooth lake is polarized most strongly.
For more similar questions on Brewster angle:
brainly.com/question/29428422
#SPJ11
How much force is required to accelerate a 5kg mass at 20m/s 2 ?
Нам не дано коэффициент трения, значит, можно не учесть силу трения. От этого, по второму закону Ньютона, F=ma=5×20=100 Н.
И это всё!
To stretch a spring 5.00cm from its unstretched length, 19.0J of work must be done.1- what is the force constant of the spring ?2- What magnitude force is needed to stretch the spring 5.00cm from its unstretched length?3- How much work must be done to compress this spring 4.00 cm from its unstretched length?4-What force is needed to stretch it this distance?
1) The force constant of the spring is 0.76N/cm, 2) The magnitude force needed to stretch the spring 5.00cm from its unstretched length is 3.80N, 3) Work done to compress this spring 4.00 cm from its unstretched length is 12.48J, 4) Force needed to stretch it this distance is 3.04N.
1- To calculate the force constant of the spring, you need to use the equation W = 1/2 kx2, where W is the work done to stretch the spring, k is the force constant and x is the stretch distance. In this case, W = 19.0J and x = 5.00cm, so k = 19.0/25 = 0.76N/cm.
2- To calculate the magnitude of the force needed to stretch the spring 5.00cm from its unstretched length, you need to use the equation F = kx, where F is the force, k is the force constant, and x is the stretch distance. In this case, F = 0.76N/cm x 5.00cm = 3.80N.
3- To calculate the work done to compress this spring 4.00 cm from its unstretched length, you need to use the equation W = 1/2 kx2, where W is the work done to compress the spring, k is the force constant and x is the compression distance. In this case, W = 1/2 x 0.76N/cm x (4.00 cm)2 = 12.48J.
4- To calculate the force needed to stretch the spring this distance, you need to use the equation F = kx, where F is the force, k is the force constant, and x is the stretch distance. In this case, F = 0.76N/cm x 4.00cm = 3.04N.
To know more about spring, refer here:
https://brainly.com/question/14670501#
SPJ11#
if two identical wires carrying a certain current in the same direction are placed parallel to each other, they will experience a force of repulsion. select one: a. true b. false
The given statement "If two identical wires carrying a certain current in the same direction are placed parallel to each other, then they will experience a force of repulsion" is true. This can be explained through Lenz's law.
What is Lenz's law?Two parallel wires which are carrying the same magnitude of current in the same direction experience a force of repulsion due to the electric currents in each of the wire which are creating a magnetic field in the same direction. This force of repulsion is known as the Lenz's Law.
When two identical wires are carrying a certain magnitude of electric current in the same direction and these are placed in parallel to each other, then they will experience a force of repulsion. This is due to the principle of the electromagnetic force and Lenz's law. When the two current-carrying wires are kept near each other, then they exert force on each other, and that force is called as the force of repulsion or the force of attraction depending on the direction of the current flowing through the wire. The direction of the force is given by the Fleming's left-hand rule, which is the most common way to determine the direction of the force in such cases.
Learn more about Electric current here:
https://brainly.com/question/2264542
#SPJ11
A block slides down a frictionless plane having an inclination of θ=15.00. The block starts from rest at the top, and the length of the incline is 2.00m. (a) Draw a free-body diagram of the block. Find (b) the acceleration of the block and (c) its speed when it reaches the bottom of the incline.
(a) Free-body diagram of block is as given below. (b) Acceleration of the block is 2.529 m/s². (c) Speed of the block when it reaches the bottom of the incline is 3.18 m/s.
What is frictionless surface?Frictionless surface is an invented concept of surface that is based on imagination and creative ideas of scientists where assumed friction of surface is zero.
(a) Free-body diagram of block is:
/|
/ |
/ | m
/ θ |
/ |
/_____|
f ||
||
||
||
\/
where m is mass of the block, θ is angle of inclination, f is force of friction (which is zero in this case), and g is acceleration due to gravity acting vertically downwards.
(b) The force acting along incline is component of the weight of block parallel to the incline, given by mg sin θ, where m is the mass of the block and g is acceleration due to gravity. Since there is no friction, this force is equal to net force acting on block, which is ma, where a is acceleration of block along the incline. Therefore,
mg sin θ = ma
a = g sin θ
a = 9.81 m/s² * sin 15.00 = 2.529 m/s²
Therefore, the acceleration of the block is 2.529 m/s².
(c) v² = u² + 2as
where u is the initial velocity (which is zero), s is the displacement (which is 2.00 m along the incline), and a is the acceleration (2.529 m/s²). Solving for v, we get:
v = √(2as) = √(2 * 2.00 m * 2.529 m/s²) = 3.18 m/s
Hence, speed of block when it reaches bottom of incline is 3.18 m/s.
To know more about frictionless surface, refer
https://brainly.com/question/25825478
#SPJ1
Approximately 85% of phosphorus in the body is found in the bones. The other 15% of phosphorus in the body serves mary impertari Durposes. Click to select the functions of phosphorus. Dairy foods are rich sources of calcium, but mary people with lactase intolerance cannot consume these foods without experiending g gestrointestinal discomfort. Fortunately, there are a number of nondairy sources of caiclum. Park the following nondairy foocs in order of calcium content. Most Cakclum Per Sening 1 cup Tohale Rais Bran cereal 1 cup cakcum-fortifed oranon juce 30z salnon with bones From the following food items, click to select the highest source of phosphorus. Click to select the organs that participate in vitamin D synthesis as a result of sunlight exposure.
Functions of phosphorus: Bone formation, ATP production, DNA and RNA synthesis, cell membrane structure.
Order of nondairy foods by calcium content: 1) 1 cup calcium-fortified orange juice, 2) 1 cup Total Raisin Bran cereal, 3) 3 oz salmon with bones.
Highest source of phosphorus: Salmon with bones.
Organs that participate in vitamin D synthesis: Skin (when exposed to sunlight), liver, and kidneys.
What is bone formation?
Bone formation is the process by which bones grow and develop, including the deposition of mineralized bone tissue by osteoblasts and the resorption of bone tissue by osteoclasts, resulting in changes to the shape and structure of bones.
What is RNA?
RNA (Ribonucleic acid) is a molecule that plays a vital role in various biological processes. It is a type of nucleic acid that is composed of a chain of nucleotides, which are the building blocks of the molecule.
RNA is similar to DNA (deoxyribonucleic acid) in terms of its structure, but it has some key differences. RNA is usually single-stranded, while DNA is double-stranded. RNA uses the sugar ribose, while DNA uses deoxyribose. RNA also contains the nitrogenous base uracil, while DNA contains thymine.
To know more about RNA, visit:
https://brainly.com/question/20914096
#SPJ1
Terri Vogel, an amateur motorcycle racer, averages 129.77 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation of 2.26 seconds. The distribution of her race times is normally distributed. We are interested in one of her randomly selected laps. (Source: log book of Terri Vogel) Let X be the number of seconds for a randomly selected lap. Round all answers to 4 decimal places where possible. a. What is the distribution of X?X−N(___________, _________). b. Find the proportion of her laps that are completed between 131.69 and 134.04 seconds________
.c. The fastest 4% of laps are under__________seconds.
d. The middle 70% of her laps are from seconds________ to_________ seconds.
a) The distribution of X: X-N(129.77,2.26),
b) the proportion of her laps that are completed between 131.69 and 134.04 seconds 0.1670,
c) the fastest 4% of laps are under 126.1965 seconds,
d) the middle 70% of her laps are from seconds 127.5323 to 131.0277 seconds.
a. The distribution of X is the normal distribution with a mean of 129.77 seconds and a standard deviation of 2.26 seconds. Therefore, the distribution of X is X - N(129.77, 2.26).
b. The area between 131.69 and 134.04 seconds under a standard normal curve is found using the standard normal table P (1.05) = 0.8531P (1.71) = 0.9564
Therefore, the proportion of laps completed between 131.69 and 134.04 seconds is
P(131.69 ≤ X ≤ 134.04) = P[(131.69 - 129.77)/2.26 ≤ Z ≤ (134.04 - 129.77)/2.26]
= P(0.8496 ≤ Z ≤ 1.8814) = P(Z ≤ 1.8814) - P(Z ≤ 0.8496)
= 0.9693 - 0.8023
= 0.1670
Therefore, the proportion of laps that are completed between 131.69 and 134.04 seconds is 0.1670.
c. The value corresponding to the lowest 4% is found: P (z) = 0.04. The value of z corresponding to the lowest 4% is obtained as follows:
z = P−1(0.04) = -1.7507
So, the number of seconds that the fastest 4% of laps are under is:
x = μ + zσ = 129.77 - (1.7507)(2.26)
= 126.1965
Therefore, the fastest 4% of laps are under 126.1965 seconds.
d. We know that z corresponding to the lowest 15% is -1.036 and that z corresponding to the highest 15% is 1.036.
Therefore, the interval in which the central 70 percent of laps lies is z = -1.036, 1.036
z = P(X) - P(X) = P(z ≤ X) - P(z ≤ X) = P(z ≤ -1.036) - P(z ≤ 1.036)
= 0.1492 - 0.8513
= -0.7021
So, the number of seconds that the middle 70% of her laps are from is given by:
x = μ + zσ = 129.77 + (-0.7021)(2.26) = 127.5323 and
x = μ + zσ = 129.77 + (0.7021)(2.26) = 131.0277
Therefore, the middle 70% of her laps are from seconds 127.5323 to 131.0277 seconds.
Learn more about normal distribution here:
https://brainly.com/question/4079902
#SPJ11
Suppose two rings are at the top of a ramp. The rings have the same mass, but one ring has a much larger radius than the other. Which ring will win the race to the bottom, and why? (Hint: Consider the potential energy, translational kinetic energy, and rotational kinetic energy of each ring.)
Suppose two rings are at the top of a ramp. The rings have the same mass, but one ring has a much larger radius than the other. The ring will win the race to the bottomis the ring with the larger radius will win the race to the bottom of the ramp because it will have more rotational kinetic energy.
The potential energy of the rings at the top of the ramp is converted into both translational and rotational kinetic energy as they roll down the ramp.At the top of the ramp, both rings have the same potential energy. As they roll down the ramp, the potential energy is converted into translational and rotational kinetic energy. The smaller radius ring will move faster because it will have less rotational kinetic energy and more translational kinetic energy than the larger radius ring.
Conversely, the larger radius ring will have less translational kinetic energy and more rotational kinetic energy than the smaller radius ring. Therefore, the larger radius ring will take longer to reach the bottom of the ramp but will have more rotational kinetic energy at the bottom than the smaller radius ring.
Learn more about kinetic energy at:
https://brainly.com/question/22174271
#SPJ11
find the current in an 8.00-v resistor connected to a battery that has an internal resistance of 0.15 v if the voltage across the battery (the terminal voltage) is 9.00 v. (b) what is the emf of the battery?
(a) The flowing current is 1.08 A. (b) The EMF of the battery is 9.16 V.
It is given data that the resistance of the resistor (R) = 8.00 V and the voltage across the battery (V) = 9.00 V. The internal resistance of the battery (r) = 0.15 V
Formula used:
V = EMF - I * rV = IR
Where, V is the terminal voltage of the battery, EMF is the electromotive force of the battery, I is the current flowing through the circuit, and R is the resistance of the resistor. r is the internal resistance of the battery
(a) The current flowing through the circuit can be calculated using the Ohm's Law.
V = IR
I = V / R
I = 9 / (8 + 0.15)
I = 1.08 A
The current flowing through the circuit is 1.08 A.
(b) Find the emf of the battery:
We know that,
V = EMF - I * r
EMF = V + I * r
EMF = 9 + 1.08 * 0.15
EMF = 9.16 V
The emf of the battery is 9.16 V.
Learn more about Current:
https://brainly.com/question/24858512
#SPJ11
