Answer:
0.8989
Step-by-step explanation:
Using the Newton's Raphson approximation formula.
Xn+1 = Xn - f(Xn)/f'(Xn)
Given f(x) = x³-2x+2
f'(x) = 3x²-2
If the initial value X1 = 2
X2 = X1 - f(X1)/f'(X1)
X2 = 2 - f(2)/f'(2)
f(2) = 2³-2(2)+2
f(2) = 8-4+2
f(2) = 6
f'(2) = 3(2)²-2
f'(2) = 10
X2 = 2- 6/10
X2 = 14/10
X2 = 1.4
X3 = X2 - f(X2)/f'(X2)
X3 = 1.4 - f(1.4)/f'(1.4)
f(1.4) = 1.4³-2(1.4)+2
f(1.4) = 2.744-2.8+2
f(1.4) = 1.944
f'(1.4) = 3(1.4)²-2
f'(1.4) = 3.880
X3 = 1.4- 1.944/3.880
X3 = 1.4 - 0.5010
X3 = 0.8989
Hence the value of X3 is 0.8989
Two brothers, Tom and Allen, each inherit $39000. Tom invests his inheritance in a savings account with an annual return of 2.9%, while Allen invests his inheritance in a CD paying 5.7% annually. How much more money than Tom does Allen have after 1 year?
Answer:
Tom:
initial money = $ 39000
% increased per annum = 2.9%
money gained per annum = 39000 * 2.9/100 = $1131
Allen:
initial money = $ 39000
% increased per annum = 5.7 %
money gained per annum = 39000 * 5.7/100 = $2223
Allen has $ (2223 - 1131) = $ 1192 more than Tom
You have a jar containing 55 coins, consisting entirely of nickels and quarters, worth a
total of $7.15. How many quarters are in the jar?
Answer: 22 quarters
Step-by-step explanation:
Let N be the number of nickels.
Then the number of quarters is (55-N)
The nickels contribute 5N cents to the total.
The quarters contribute 25*(55-N) cents to the total.
5N + 25*(55-N) = 715
5N + 1375 - 25N = 715
-20N = 715 - 1375 = -660
[tex]N=\frac{-660}{-20}[/tex]
[tex]=33[/tex]
[tex]55-33=22[/tex]
So there is 22 quarters inside the jar.
Check to see if my answer is correct-
33*5 + 22*25 = 715 cents
A linear regression analysis uses two distinct types of data. The first are variables that are at least nominal level.
a) true
b) false
Answer:
The answer is
A. True
Step-by-step explanation:
In linear regression, Linear models make a prediction using a linear function of the input features, with one being
For regression, the general prediction formula for a linear model looks as follows:
ŷ = w[0] * x[0] + w[1] * x[1] + ... + w[p] * x[p] + b
Here, x[0] to x[p] denotes the features (in this example, the number of features is p)
of a single data point, w and b are parameters of the model that are learned, and ŷ is
the prediction the model makes. For a dataset with a single feature, this is
ŷ = w[0] * x[0] + b
which you might remember from high school mathematics as the equation for a line.
Here, w[0] is the slope and b is the y-axis offset. For more features, w contains the
slopes along each feature axis. Alternatively, you can think of the predicted response
as being a weighted sum of the input features, with weights (which can be negative)
given by the entries of w.
7.19 We are given the following probability distribution. x P(x) b. c. d. 0 1 2 3 .1 .4 .3 .2 a. Calculate the mean, variance, and standard deviation.
Answer:
Mean = 1.6
Variance = 0.84
Standard deviation = 0.916
Step-by-step explanation:
We are given the following probability distribution below;
X P(X) [tex]X \times P(X)[/tex] [tex]X^{2} \times P(X)[/tex]
0 0.1 0 0
1 0.4 0.4 0.4
2 0.3 0.6 1.2
3 0.2 0.6 1.8
Total 1.6 3.4
Now, the mean of the probability distribution is given by;
Mean, E(X) = [tex]\sum X \times P(X)[/tex] = 1.6
Also, the variance of the probability distribution is given by;
Variance, V(X) = [tex]\sum X^{2} \times P(X) - (\sum X \times P(X))^{2}[/tex]
= [tex]3.4 - (1.6)^{2}[/tex]
= 3.4 - 2.56 = 0.84
And the standard deviation of the probability distribution is given by;
Standard deviation, S.D. (X) = [tex]\sqrt{Variance}[/tex]
= [tex]\sqrt{0.84}[/tex] = 0.916.
When ________ angles made by two lines and a transversal are supplementary, the lines are parallel. Question 20 options: A) corresponding B) same side interior C) alternate exterior D) alternate interior
Answer:
B) same side interior
Step-by-step explanation:
Supplementary angles are angles that can add up to the sum of angles on a straight line, [tex]180^{0}[/tex]. While a transversal in a line that passes through two parallel lines at two points.
If two lines are parallel to each other and a transversal through the lines, the sum of either same side interior angles would be supplementary.
The correct option for the given question is B, same side interior.
Answer:
B
Step-by-step explanation:
36 minus 20 minus 32 times 1/4
Answer:
6
Step-by-step explanation:
36 - 20 - 32 x 1/4
=> 36 - 20 - 32/4
=> 36 - 20 - 8
=> 36 - 28
=> 6
1. Find the conditional probability of the indicated event when two fair dice (one red and one green) are rolled. The sum is 6, given that the green one is either 4 or 1.
2. Find the conditional probability of the indicated event when two fair dice (one red and one green) are rolled. The red one is 6, given that the sum is 11.
Answer:
1. 1/6
2. 1/6
Step-by-step explanation:
Let A be the event that the sum of the two die is 6 and B be an event that the green die is either 4 or 1.
The conditional probability will be given by P (A/B) = P (A∩B)/ P (B).
Now the total sample space consists of 36 outcomes .
And to find (A∩B) we need to find the outcomes in which green die is either 4 or 1 and the sum of the two die is 6.
So when green is 1 red must be 5
So when green is 4 red must be 2
So there are two ways in which green die is either 4 or 1 and the sum of the two die is 6.
Therefore the probability of (A∩B)= P (A∩B)= 2/36= 1/18
Now we find the probability of green die having 4 or 1
So when green is 4 red can have all the numbers from 1- 6
And when green is 1 red can have all the numbers from 1- 6
The total number would be 12 .
So probability of green die having 1 or 4 is given by = P (B)= 12/36
Now the conditional probability = P (A/B) = P (A∩B)/ P (B)=1/18/ 1/3
= 3/18= 1/6
2. Similarly we find the conditional probability of the two die when the red one is 6, given that the sum is 11.
When red is 6 the green must be 5 to get 11. So the probability
=P (A∩B)= 1/36
Now we find the probability of red die having 6 =P(B)= 6/36
Now the conditional probability = P (A∩B)/P(B) = 1/36/ 6/36= 1/6
Answer 1:
Let A be the event that the sum of the two die is 6 Let B be an event that the green die is either 4 or 1.
Conditional probability Formula :
P (A/B) = P (A∩B)/ P (B).
Total sample space=36 outcomes
Conditions are :
So when green is 1 red must be 5 So when green is 4 red must be 2 So there are two ways in which green die is either 4 or 1 and the sum of the two die is 6.
The probability of (A∩B)= P (A∩B)= 2/36= 1/18
Now we find the probability of green die having 4 or 1
When green is 4 red can have all the numbers from 1- 6
And when green is 1 red can have all the numbers from 1- 6
Total number = 12
P (B)= 12/36
Therefore, conditional probability = P (A/B)
P (A/B) = P (A∩B)/ P (B) P (A/B)=1/18/ 1/3 P (A/B)= 3/18 P (A/B)= 1/6
The conditional probability of the indicated event when two fair dice are rolled will be 1/6.
Answer 2:
Let A be the event that the sum of the two die is 6 Let B be an event that the green die is either 4 or 1. The sum is 11.
Condition :
When red is 6 the green must be 5 to get 11.
P (A∩B)= 1/36
The probability of red die having 6 =P(B)= 6/36
The conditional probability= P (A∩B)/P(B)
P (A∩B)/P(B) = 1/36/ 6/36P (A∩B)/P(B)= 1/6The conditional probability of the indicated event when two fair dice are 1/6.
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PLZ HELPPPPPP. 25 POINTS.
A store sells books for $12 each. In the proportional relationship between x, the number of books purchased, and y, the cost per books in dollars" to "y, the total cost of the books in dollars, the constant of proportionality is 12. Which equation shows the relationship between x and y?
A. y=12/x
B. y=12x
C. y=12+x
D. y=12−x
Answer:
b
Step-by-step explanation:
because its right dummy
Which angle of rotation is determined by the matrix below?{1/2 -sqrt3/2 sqrt3/2 1/2] 30° 60° 120° 300°
Answer:
60°
Step-by-step explanation:
You have the rotation matrix ...
[tex]\left[\begin{array}{cc}\cos{\theta}&-\sin{\theta}\\\sin{\theta}&\cos{\theta}\end{array}\right]=\left[\begin{array}{cc}\dfrac{1}{2}&-\dfrac{\sqrt{3}}{2}\\\dfrac{\sqrt{3}}{2}&\dfrac{1}{2}\end{array}\right][/tex]
This tells you the angle of rotation is ...
[tex]\tan{\theta}=\dfrac{\sin{\theta}}{\cos{\theta}}=\dfrac{\left(\dfrac{\sqrt{3}}{2}\right)}{\left(\dfrac{1}{2}\right)}=\sqrt{3}\\\\\theta=\arctan{\sqrt{3}}=60^{\circ}[/tex]
The angle of rotation is 60°.
Answer:
B----- 60
Step-by-step explanation:
Twice one number added to another number is 18. if the 2nd number is equaled to 12 less than 4 times the 1st number, find the two numbers
2x + y= ? ; y= ?x - ?
Answer:
8
Step-by-step explanation:
Math Word Problem: Twice one number added to another number is 18. Four times the first number minus the other number is 12. Find the number.?
Let the two numbers be x and y
As per statement twice one number added to another number is 18.
2x + y = 18
y = 18 - 2x…Eq..1
Four times the first number minus the other number is 12.
4x - y = 12…Eq..2
Now substituting the value of y from Eq..1 to Eq..2
4x - y = 12
4x - (18 - 2x) = 12
4x - 18 + 2x = 12
4x + 2x = 12 + 18
6x = 30
x = 30 / 6
x = 5
Thus one number is 5. Now calculating the other number by putting the value of x in Eq. 1
y = 18 - 2x
y = 18 - 2×5
y = 18 - 10
y = 8
Other number is 8
Answer the two numbers are 5 and 8
Let us check the correctness of answer by putting the value of x and y in Eq. 1
y = 18 - 2x
8 = 18 - 2 × 5
8 = 18 - 10
8 = 8
Means answer is correct
find x, if sq.root(x) +2y^2 = 15 and sq.root(4x) - 4y^2=6
Answer:
Example: solve √(2x−5) − √(x−1) = 1
isolate one of the square roots:√(2x−5) = 1 + √(x−1) square both sides:2x−5 = (1 + √(x−1))2 ...
expand right hand side:2x−5 = 1 + 2√(x−1) + (x−1) ...
isolate the square root:√(x−1) = (x−5)/2. ...
Expand right hand side:x−1 = (x2 − 10x + 25)/4. ...
Multiply by 4 to remove division:4x−4 = x2 − 10x + 25.
Answer:
Step-by-step explanation:
ewrerewrwrwerrwer
If In (x) = 3.53, what is the value of x ?
Finding Side Lengths in a Right Triangle
What is the value of s?
15 units
С
5
B
15
S
D
Answer:
maybe it's 10.because c is 10,b is 10,and so as s.
hence s is 10 also.
PLEASE HELP SOON! A 2011 study by the National Safety Council estimated that there are nearly 5.7 million traffic accidents year. At least 28% of them involved distracted drivers using a cell phones or texting. The data showed that 11% of drivers at any time are using cell phones. Car insurance companies base their policy rates on accident data that shows drivers have collisions approximately once every 19 years. That's a 5.26% chance per per year. Given.
A - Let dc= event that a randomly selected driver is using a cell phone. what is P(DC)? B - Let ta = event that a randomly selected driver has a traffic accident. what is P(ta) C - how can you determine if cell phone use while driving and traffic accidents are related? D - Give that the driver has an accident, what is the probability that the driver was distracted by a cell phone? Write this event with the correct conditional notation.
Answer:
(A) 0.11
(B) 0.0526
(C) Related
(D) 0.28
Step-by-step explanation:
The data provided is:
DC = event that a randomly selected driver is using a cell phone
TA = event that a randomly selected driver has a traffic accident
(A)
From the provided data:
P (DC) = 0.11
(B)
From the provided data:
P (TA) = 0.0526
(C)
To determine whether the events DC and TA are dependent, we need to show that:
[tex]P(DC\cap TA)\neq P(DC)\times P(TA)[/tex]
The value of P (DC ∩ TA) is,
[tex]P(DC\cap TA)=P(DC|TA)\time P(TA)[/tex]
[tex]=0.28\times 0.0526\\=0.014728[/tex]
Now compute the value of P (DC) × P (TA) as follows:
[tex]P (DC) \times P (TA)=0.11\times 0.0526=0.005786[/tex]
So, [tex]P(DC\cap TA)\neq P(DC)\times P(TA)[/tex]
Thus, cell phone use while driving and traffic accidents are related.
(D)
The probability that the driver was distracted by a cell phone given that the driver has an accident is:
P (DC | TA) = 0.28
Find the P-value in a test of the claim that the mean IQ score of acupuncturists is equal to 100, given that the test statistic is z2.00.
Answer:
P-value = 0.0455
Step-by-step explanation:
In this question, we are concerned with calculating the P- value in a test.
Mathematically we know that;
P-value = 2 * P(Z > |z|)
Please check attachment for complete solution and by step explanation
A survey of undergraduates revealed the follwoing information: WOMEN MENsample mean weight 124.7 183.3sample standard deviation of weight 23.32 25.41sample proportion Roman Catholic 0.40 0.32Sample mean GPA 3.34 3.24Sample standard deviation of GPA 0.35 0.44Sample size 20 25Assume the populations are normally distributed. Suppose you want to determine whether the proportion of SCU women who are Roman Catholic is greater than the proportion of SCU men that are Roman Catholic.a. What are the null and alternative hypothesis to run this test?b. What is the calculated value of the test statistic?c. What is the p-value of the calculated test statistic?d. What is the conclusion of the hypothesis test, at 5% the significance level?
Answer:
the answers are below:
Step-by-step explanation:
a. null hypothesis:
H0: Pw - Pm = 0 (so Pw = Pm)
alternate hypothesis:
H1: Pw - Pm > 0 (so Pw > Pm)
where Pw is the proportion of women
Pm is the proportion of men
b.) proportion of women = o.40
proportion of men = 0.32
sample size of women = 20
sample size of men = 25
[tex]z = 0.4 - 0.32/ \sqrt{((0.4 *0.6)/20) * (0.32 * 0.68)/25)}[/tex]
[tex]z = 0.56[/tex]
c.) p value =
p(z>0.56)
= 0.7123
= 1 - 0.7123
= o.2877 which can be approximated to be 0.288
d. alpha value was set at 0.05
the p value is greater than alpha.
therefore it is not statistically significant.
we conclude that the proportion of roman catholic women is not greater than men.
Which expression is equivalent to 73 ⋅ 7−5? 72 77 1 over 7 to the 2nd power 1 over 7 to the 7th power
Answer:
1/7^2
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
__
Then your expression simplifies to ...
[tex]7^3\cdot 7^{-5}=7^{3-5}=7^{-2}=\boxed{\dfrac{1}{7^2}}[/tex]
Answer:
The answer is 1/7^2
Step-by-step explanation:
I took the test lol
write a letter to your friend in Ghana stating your experience in your presentation school in nigeria
Answer:
hi Ghana how are you doing I am fine here. I really miss u and my friends in the old.U know what in Nigeria this school is really awesome and fantastic we have a swimming pool here and we can go to trip and we can have many things here I really loved this school.
at starting I was not have any friends and know I have many friends. But I really miss u this is what about our . Come to my house I can show you my school it is very near to my house .
Ur friend
writ ur name
I will mark u brainleiest if u help me and 5 stars
Answer:
[tex]\boxed{50}[/tex]
Step-by-step explanation:
Because the initial temperature is 40 degrees and it increases by 10, add the two values together to get the final temperature.
40 + 10 = 50
Therefore, the final answer is 50 degrees.
Answer:
50
Step-by-step explanation:
If it starts at 40 degrees and increases 10 degrees, it is going to be 50 degrees. Increases means adding, so it is asking you to add 10 to 40 which is 50. If it asks decreases in the future you will have to subtract.
1. Transform the polar equation to a Cartesian (rectangular) equation: 2. Transform the Cartesian (rectangular) equation to a polar equation: y^2 = 4x
Answer:
Attachment 1 : 5x + 6y = 5, Attachment 2 : 4cotθcscθ
Step-by-step explanation:
Remember that we have three key points in solving these types of problems,
• x = r cos(θ)
• y = r sin(θ)
• x² + y² = r²
a ) For this first problem we need not apply the third equation.
( Multiply either side by 5 cos(θ) + 6 sin(θ) )
r [tex]*[/tex] ( 5 cos(θ) + 6 sin(θ) ) = 5,
( Distribute r )
5r cos(θ) + 6r sin(θ) = 5
( Substitute )
5x + 6y = 5 - the correct solution is option c
b ) We know that y² = 4x ⇒
r²sin²(θ) = 4r cos(θ),
r = 4cos(θ) / sin²(θ) = 4 cot(θ) csc(θ) = 4cotθcscθ - again the correct solution is option c
Using the constant of proportionality, determine how much water will be in the bathtub after 2.5 minutes.
Answer:
[tex]\boxed{41.25}[/tex]
Step-by-step explanation:
Hey there!
Well we know the constant of proportionality is 16.5 because on the table it states 1 minute is 16.5 gallons.
So we can set up the following,
W = 2.5*16.5
W = 41.25
Hope this helps :)
Answer:
The amount of water in the bathtub after 1 minute is 16.5 gallons. So, the amount of water in the tub after 2.5 minutes of filling will be
2.5 minutes × 16.5 gallons per minute = 41.25 gallons.
There will be 41.25 gallons of water in the bathtub after 2.5 minutes.
Step-by-step explanation:
120 meals to 52 meals what is the percentage change?
Answer: The percentage change is 56.67%.
Step-by-step explanation:
From 120 meals to 52 meals, change in meals = ( 120- 52) meals
= 68 meals
The percentage change = [tex]\dfrac{\text{change in meals}}{\text{Original quantity of meals}}\times100[/tex]
[tex]=\dfrac{68}{120}\times100\\\\=56.67\%[/tex]
Hence, the percentage change is 56.67%.
If the occurrence of one event does not influence the outcome of another event, then two events are:
A. conditional
B. disjoint
C. independent
D. interdependent
Answer:
C. Independent
Step-by-step explanation:
Independent events are events that have no impact on each other.
So, if the occurrence of an event doesn't influence the outcome of another, this means that they are independent because they do not impact each other.
This must mean C is correct because the two events have to be independent.
Find the particular solution of the differential equation that satisfies the initial condition. f '(x) = −8x, f(1) = −3
Step-by-step explanation:
f(x) = integral (-8x) dx = -4x^2 + C
f(1) = -3 = -4 + C
C = 1
f(x) = -4x^2 + 1
The particular solution of the differential equation f'(x) = -8x that satisfies the initial condition f(1) = -3 is: f(x) = -4x² + 1.
Here, we have,
To find the particular solution of the differential equation f'(x) = -8x that satisfies the initial condition f(1) = -3,
we can integrate the equation and use the initial condition to determine the constant of integration.
First, integrate both sides of the equation with respect to x:
∫ f'(x) dx = ∫ -8x dx
Integrating, we get:
f(x) = -4x² + C
Now, we can use the initial condition f(1) = -3 to find the value of the constant C.
Substituting x = 1 and f(x) = -3 into the equation, we have:
-3 = -4(1)² + C
-3 = -4 + C
C = -3 + 4
C = 1
Therefore, the particular solution of the differential equation f'(x) = -8x that satisfies the initial condition f(1) = -3 is:
f(x) = -4x² + 1
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2,17,82,257,626,1297 next one please ?
The easy thing to do is notice that 1^4 = 1, 2^4 = 16, 3^4 = 81, and so on, so the sequence follows the rule [tex]n^4+1[/tex]. The next number would then be fourth power of 7 plus 1, or 2402.
And the harder way: Denote the n-th term in this sequence by [tex]a_n[/tex], and denote the given sequence by [tex]\{a_n\}_{n\ge1}[/tex].
Let [tex]b_n[/tex] denote the n-th term in the sequence of forward differences of [tex]\{a_n\}[/tex], defined by
[tex]b_n=a_{n+1}-a_n[/tex]
for n ≥ 1. That is, [tex]\{b_n\}[/tex] is the sequence with
[tex]b_1=a_2-a_1=17-2=15[/tex]
[tex]b_2=a_3-a_2=82-17=65[/tex]
[tex]b_3=a_4-a_3=175[/tex]
[tex]b_4=a_5-a_4=369[/tex]
[tex]b_5=a_6-a_5=671[/tex]
and so on.
Next, let [tex]c_n[/tex] denote the n-th term of the differences of [tex]\{b_n\}[/tex], i.e. for n ≥ 1,
[tex]c_n=b_{n+1}-b_n[/tex]
so that
[tex]c_1=b_2-b_1=65-15=50[/tex]
[tex]c_2=110[/tex]
[tex]c_3=194[/tex]
[tex]c_4=302[/tex]
etc.
Again: let [tex]d_n[/tex] denote the n-th difference of [tex]\{c_n\}[/tex]:
[tex]d_n=c_{n+1}-c_n[/tex]
[tex]d_1=c_2-c_1=60[/tex]
[tex]d_2=84[/tex]
[tex]d_3=108[/tex]
etc.
One more time: let [tex]e_n[/tex] denote the n-th difference of [tex]\{d_n\}[/tex]:
[tex]e_n=d_{n+1}-d_n[/tex]
[tex]e_1=d_2-d_1=24[/tex]
[tex]e_2=24[/tex]
etc.
The fact that these last differences are constant is a good sign that [tex]e_n=24[/tex] for all n ≥ 1. Assuming this, we would see that [tex]\{d_n\}[/tex] is an arithmetic sequence given recursively by
[tex]\begin{cases}d_1=60\\d_{n+1}=d_n+24&\text{for }n>1\end{cases}[/tex]
and we can easily find the explicit rule:
[tex]d_2=d_1+24[/tex]
[tex]d_3=d_2+24=d_1+24\cdot2[/tex]
[tex]d_4=d_3+24=d_1+24\cdot3[/tex]
and so on, up to
[tex]d_n=d_1+24(n-1)[/tex]
[tex]d_n=24n+36[/tex]
Use the same strategy to find a closed form for [tex]\{c_n\}[/tex], then for [tex]\{b_n\}[/tex], and finally [tex]\{a_n\}[/tex].
[tex]\begin{cases}c_1=50\\c_{n+1}=c_n+24n+36&\text{for }n>1\end{cases}[/tex]
[tex]c_2=c_1+24\cdot1+36[/tex]
[tex]c_3=c_2+24\cdot2+36=c_1+24(1+2)+36\cdot2[/tex]
[tex]c_4=c_3+24\cdot3+36=c_1+24(1+2+3)+36\cdot3[/tex]
and so on, up to
[tex]c_n=c_1+24(1+2+3+\cdots+(n-1))+36(n-1)[/tex]
Recall the formula for the sum of consecutive integers:
[tex]1+2+3+\cdots+n=\displaystyle\sum_{k=1}^nk=\frac{n(n+1)}2[/tex]
[tex]\implies c_n=c_1+\dfrac{24(n-1)n}2+36(n-1)[/tex]
[tex]\implies c_n=12n^2+24n+14[/tex]
[tex]\begin{cases}b_1=15\\b_{n+1}=b_n+12n^2+24n+14&\text{for }n>1\end{cases}[/tex]
[tex]b_2=b_1+12\cdot1^2+24\cdot1+14[/tex]
[tex]b_3=b_2+12\cdot2^2+24\cdot2+14=b_1+12(1^2+2^2)+24(1+2)+14\cdot2[/tex]
[tex]b_4=b_3+12\cdot3^2+24\cdot3+14=b_1+12(1^2+2^2+3^2)+24(1+2+3)+14\cdot3[/tex]
and so on, up to
[tex]b_n=b_1+12(1^2+2^2+3^2+\cdots+(n-1)^2)+24(1+2+3+\cdots+(n-1))+14(n-1)[/tex]
Recall the formula for the sum of squares of consecutive integers:
[tex]1^2+2^2+3^2+\cdots+n^2=\displaystyle\sum_{k=1}^nk^2=\frac{n(n+1)(2n+1)}6[/tex]
[tex]\implies b_n=15+\dfrac{12(n-1)n(2(n-1)+1)}6+\dfrac{24(n-1)n}2+14(n-1)[/tex]
[tex]\implies b_n=4n^3+6n^2+4n+1[/tex]
[tex]\begin{cases}a_1=2\\a_{n+1}=a_n+4n^3+6n^2+4n+1&\text{for }n>1\end{cases}[/tex]
[tex]a_2=a_1+4\cdot1^3+6\cdot1^2+4\cdot1+1[/tex]
[tex]a_3=a_2+4(1^3+2^3)+6(1^2+2^2)+4(1+2)+1\cdot2[/tex]
[tex]a_4=a_3+4(1^3+2^3+3^3)+6(1^2+2^2+3^2)+4(1+2+3)+1\cdot3[/tex]
[tex]\implies a_n=a_1+4\displaystyle\sum_{k=1}^3k^3+6\sum_{k=1}^3k^2+4\sum_{k=1}^3k+\sum_{k=1}^{n-1}1[/tex]
[tex]\displaystyle\sum_{k=1}^nk^3=\frac{n^2(n+1)^2}4[/tex]
[tex]\implies a_n=2+\dfrac{4(n-1)^2n^2}4+\dfrac{6(n-1)n(2n)}6+\dfrac{4(n-1)n}2+(n-1)[/tex]
[tex]\implies a_n=n^4+1[/tex]
1+3^2⋅2−5 order of operations
Answer:
Below
Step-by-step explanation:
● 1 + 3^2 × 2 -5
Start by calculating 3^2 wich is 9
● 1 + 9 × 2 -5
Multiply 2 by 9 (9×2=18)
● 1 + 18 -5
Add 1 to 18 (1+18 = 19)
● 19 -5
Substract 5 from 19 (19-5 = 14 )
● 14
Write the polar form of a complex number in standard form for [tex]8[cos(\frac{\pi}{2}) + isin(\frac{\pi}{2})][/tex]
Answer:
Solution : 8i
Step-by-step explanation:
We can use the trivial identities cos(π / 2) = 0, and sin(π / 2) = 1 to solve this problem. Let's substitute,
[tex]8\left[cos\left(\frac{\pi }{2}\right)+isin\left(\frac{\pi \:}{2}\right)\right][/tex] = [tex]8\left(0+1i\right)[/tex]
And of course 1i = i, so we have the expression 8(0 + i ). Distributing the " 8, " 8( 0 ) = 0, and 8(i) = 8i, making the fourth answer the correct solution.
name all the pairs of angles which are vertical angles , alternate interior angles , alternate exterior angles , co interior angles , co exterior angles , and corresponding angles from the given figure . (co interior - interior angles on the same side of transversal)
Answer:
Step-by-step explanation:
Since m and k are the parallel lines and a transverse 'l' is intersecting these lines at two different points.
- Opposite angles at the point of intersection of parallel lines and the transverse will be the vertical angles.
∠1 ≅ ∠3, ∠2 ≅ ∠4, ∠5 ≅ ∠8 and ∠6 ≅ ∠7 [Vertical angles]
- Pair of angles between parallel lines 'k' and 'm' but on the opposite side of the transversal are the alternate interior angles.
∠4 ≅ ∠6 and ∠3 ≅ ∠5 [Alternate interior angles]
- Angles having the same relative positions at the point of intersection are the corresponding angles.
∠2 ≅ ∠6, ∠3 ≅ ∠8, ∠4 ≅ ∠7 and ∠1 ≅ ∠5 [Corresponding angles]
- Co interior angles are the angles between the parallel lines located on the same side of the transversal.
∠4 and ∠5, ∠3 and ∠6 [Co interior angles]
- Co exterior angles are the angles on the same side of the transverse but outside the parallel lines.
∠2 and ∠8, ∠1 and ∠7 [Co exterior angles]
what are the next terms in the number pattern -11, -8, -5, -2, 1
Answer:
4, 7, 10, 13
Step-by-step explanation:
Hey there!
Well in the given pattern,
-11, -8, -5, -2, 1
we can conclude that the pattern is +3 every time.
-11 + 3 = -8
-8 + 3 = -5
-5 + 3 = -2
-2 + 3 = 1
And so on
4, 7, 10, 13Hope this helps :)
Solve the following equations
x-1=6/x
[tex]x-1=\dfrac{6}{x}\qquad(x\not=0)\\\\x^2-x=6\\x^2-x-6=0\\x^2+2x-3x-6=0\\x(x+2)-3(x+2)=0\\(x-3)(x+2)=0\\x=3 \vee x=-2[/tex]
