Answer:
Reason:- We use cotton to make the wick of a spirit lamp because cotton has thread strands which act like fine capillaries and help in drawing up a steady supply of oil in the lamp for burning by capillary action
Explanation:
If the spring constant is 10 N/m and the spring is stretched 1 m, what is the Force?
Answer:
10N
Explanation:
Applying the Hooke law:
F = kx
F: Force
k: stiffness coefficient
x: stretched distance
F = 10N/m x 1m = 10N
You and your family are going on a trip in Europe. Calculate the speed in the following scenario. State how you calculated your answer and include correct units. A car travels 240 kilometers in 3 hours; What is the speed of the car during that time?
Answer:
22.2 m/s or 80 km/h
Explanation:
Given that
Distance travelled by the car, d = 240 km
Time taken by the car, t = 3 hours.
Speed of the car, v = ? m/s
for easy calculations, we will be converting the units to meters and seconds respectively.
240 km to meters would be
240 * 1000 m = 240000 m
3 hrs to seconds would be
3 * 60 mins * 60 seconds = 10800 s
now, we have our distance and time to be
d = 240000 m
t = 10800 s
speed is defined as the ratio of distance with respect to time taken, effectively,
Speed = distance/time
speed, v= 240000 / 10800
v = 22.2 m/s
therefore, the speed of the car during the time is 22.2 m/s, or if the speed is needed in km/h, we can convert it
22.2 * 3600/1000 =
80 km/h
Which of the following best describes a consumer?
0. a business owner who sells clothes
0. someone who studies economics
O. a farmer who sells his crops
O. a person who buys goods and services
Answer:
a business who buys goods and services
wholesale market definition
Answer:
Wholesale Market. 1. The market for the sale of goods to a retailer. That is, a wholesaler receives large quantities of goods from a manufacturer and distributes them to stores, where they are sold to consumers. ... The market for the sale of securities to institutional investors rather than individuals.
An 8.0g bullet, moving at 400 m/s, goes through a stationary block of wood in 4.0 x 10^-4s, emerging at a speed of 100 m/s. (a) what average force did the wood exert on the bullet? (b) how thick is the wood?
Answer:
Explanation:
Initial velocity (u) of the Bullet = 400 m/sec
Final velocity (v) of the Bullet = 100 m/sec
Bullet passed through the block in (t) = 0.0004 sec
Using 1st Equation of motion :
400 m/s = 100 m/s - a (0.0004)
Deceleration of Bullet = 750,000 m/sec^2
(a) F (force exerted by the wooden block on the bullet) = F (force exerted by the bullet on the wooden block)
F = m * a = 0.008 * 750,000 = 6000 N
(b) Using 3rd Equation of motion :
[tex]v^{2} = u^{2} - 2aS[/tex]
10000 = 160000 - 2 * 750,000 * S
Thickness of wood (S) = 0.1 m
If the mass of a ball is 50g on a height of 8m. Calculate the kinetic energy when it has a velocity of 3m/s.
Answer:
kinetic energy is 1/2mv^2.
which is 1/2×0.05×3^2
1/2×0.05×9.
1/2×0.45=
0.45÷2=0.225~0.23J
A laser beam is incident on two slits with a separation of 0.210 mm, and a screen is placed 5.05 m from the slits. If the bright interference fringes on the screen are separated by 1.59 cm, what is the wavelength of the laser light?
Answer:
0.66*10^-6m
Explanation:
We know that the bright fringes are placed on the screen as follows
Ym= m*(lambda xL/d)
But we are given
L= 5.05
Deta Y= 1.59
d = 0.21
1.59* 10^-2m= lambda * 5.05m/2.1*10^-4m
So lambda=
1.59* 10^-2m x 2.1*10^-4m/ 5.05m
= 0.66*10^-6m
element x has two isotopes: x-27 and x-29. x-27 has an atomic mass of 26.975 and a relative abundance of 82.33%, and x-29 has an atomic mass of 29.018 and a relative abundance of 17.67%. calculate the atomic mass od element x. show your work
Answer:
27.336
Explanation:
The atomic mass is the weighted average of the atomic masses of the isotopes. Simply multiply each isotopes's atomic mass by its relative abundance, then sum the results.
m = 0.8233 × 26.975 + 0.1767 × 29.018
m = 27.336
Which value would complete the last cell?
(1 point)
3.0
100.0
25.0
4.0
Answer:
4.0
Explanation:
The following data were obtained from the question:
Force (F) = 20 N
Mass (m) = 5 kg
Acceleration (a) =.?
Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as
Force (F) = mass (m) x acceleration (a)
F = ma
With the above formula, we can obtain th acceleration of the body as follow:
Force (F) = 20 N
Mass (m) = 5 kg
Acceleration (a) =.?
F = ma
20 = 5 x a
Divide both side by 5
a = 20/5
a = 4 m/s²
Therefore, the value that will complete the last cell in the question above is 4.
how do you find average velocity
Answer:
find the sum of the inital and final velocitys and divide by 2 to find the average
Velocity is a description of an object’s _____.
Answer:
speed
Explanation:
6. Match the statements given in column 'A' with those in column 'B':
alse, (un) False, (ve
Column A
1. Urea
2. Combines
3. Silos
4. Seed drills
5. Irrigation
6. Tilling
Column 'B'
(a) Sowing of seeds
(b) Storage of grains
(c) Harvesting and threshing
(d) Fertilizer
(e) Preparation of soil
(f)Sprinklers
Answer:
1. Urea, (d)Fertilizer
2. Combines, (c) Harvesting and threshing
3. Silos, (b) Storage of grains
4. Seed drills, (a) Sowing seeds
5. Irrigation, (f) Sprinklers
6. Tilling, (e) Preparation of soil
Explanation:
1) Urea is a widely used and important fertilizer in the agricultural industry
2) The combine harvester combines three categories of harvesting grain drops such as threshing reaping and winnowing
3) Silos are used to store grains
4) A seed drill is a seed planting mechanism for burying seeds to a particular depth during seed planting
5) Irrigation is the application of required volume of water to plants
6) Tilling is the digging, turning, and staring operations meant to prepare the soil.
fill in the blanks
1.)Seed drill is used for ____ of the seeds.
2.)ploughing helps the_____of roots of the growing plants.
3.)Tilling of the soil is also called a ________.
4.)Manure and fertilizers are use ti maintain the______of the soil.
5.)A most common weedicide is________.
6.)After harvesting,grains are separated from the chaffand hay by _______ or by using ______.
7.)The economial methods of irrigation are_____and____.
8.)The wild plants which grow along with the main crop are called_________.
9.) Shifting of tiny plants from a nursery to the main field is called______.
10.) Excess water and wet soil do not permit proper_____of the seeds or roots of the plants.
Answer:
1.) Sowing
2.) Respiration
3.) Soil preparation or cultivation or ploughing
4.) Fertility
5.) 2, 4 -D
6.) winnowing threshers
7.) Surface irrigation and sprinkler irrigation
8.) Weeds
9.) Transplantation
10.) Aeration
Explanation:
1.) Seed drill sows crop seed
2.) Ploughing assist in the respiration and penetration of the roots of a growing plants
3.) Tilling the soil is breaking of the soil lumps and turning of the soil
4.) Manure and fertilizers supply nutrient to the soil for the uptake by plant in food production
5.) 2, 4 -D are a range of weedicide containing 2,4-D as the active ingredient
6.) Winnowing is the separation of grain from straw
Threshers remove seeds from husks and stalks
7.) Surface irrigation -gravity enables the flow of the water
and sprinkler irrigation- Use of preset tools for irrigation
8.) Weeds are the unwanted, in situ, growing plants close to the crops
9.) Transplantation is the method of relocating plants
10.) Excess water limits access of the roots and seeds to atmospheric oxygen
predict the reading of the spring balance when the wooden block is pulled on the sandpaper. Explain your answer.
Answer:
* if the spring force is greater than the maximum of the static friction force,
Fe = m (a + μ_k g)
* If the elastic force is less than or equal to the static friction force, the result is with static friction coefficient
Fe =μ_s m g
Explanation:
For this exercise we must apply Newton's second law to the system
X axis
Fe -fr = m a
Fe = m a + fr
Y axis
N-W = 0
N = W = mg
the roe force is given by
fr = μ N
fr = μ mg
we substitute
Fe = m a + μ m g
Ee = m (a + μ g)
Let's analyze the solution. We have several possibilities
* if the spring force is greater than the maximum of the static friction force, the system acquires an acceleration and the result is with the kinetic friction coefficient
Fe = m (a + μ_k g)
* If the elastic force is less than or equal to the static friction force, the result is with static friction coefficient
Fe =μ_s m g
Determine the magnitude of the force that must be applied to a wooden block whose weight has a magnitude of 8N, so that it acquires an acceleration of 0.5 m / s²
Answer:
0.4 N
Explanation:
The weight mg is 8 N, so the mass is:
mg = 8 N
m = 8 N / g
m = 8 N / (10 m/s²)
m = 0.8 kg
The force needed to accelerate it to 0.5 m/s².
F = ma
F = (0.8 kg) (0.5 m/s²)
F = 0.4 N
A 5000 g toy car starts from rest and moves a distance of 300 cm in 3 s under the action of a single constant force. Determine the magnitude of the force? help good answer please
Answer:
3.33 N
Explanation:
First, find the acceleration.
Given:
Δx = 3 m
v₀ = 0 m/s
t = 3 s
Find: a
Δx = v₀ t + ½ at²
3 m = (0 m/s) (3 s) + ½ a (3 s)²
a = ⅔ m/s²
Use Newton's second law to find the force.
F = ma
F = (5 kg) (⅔ m/s²)
F ≈ 3.33 N
A foot is 12 inches and a mile is 5280 ft, exactly. A centimeter is exactly 0.01m or mm. Sammy is 5 feet and 5.3 inches tall. What is Sammy's Height in inches?
The answer is 65.3 inches tall
Explanation:
To know the heigh of Sammy in inches it is necessary to convert the 5 feet to inches and add this number to 5.3 inches as the statement mentions "Sammy is 5 feet and 5.3 inches tall". Additionally, it is known each foot is equal to 12 inches ( 1 foot = 12 inches). According to this, the simplest method to convert feet to inches is to multiply the feet given by 12. The process is shown below:
1 foot = 12 inches
feet to inches = number of feet x 12
5 feet x 12 = 60 inches
This means 5 feet is equal to 60 inches. Now, 60 inches + 5.3 inches = 65.3 inches (total height of Sammy in inches)
Self-Check
por Learning
A truck mass 8000 kg and a car a mass 1000
kg are travelling at the same velocity. Which one has greater kinetic energy ? Why?
Answer:
K.E of truck > K.E of car
Explanation:
Mass of the truck = 8000Kg
K.E=[tex]\frac{1}{2} mv[/tex]
K.E =[tex]\frac{1}{2}*8000*v\\ 4000v[/tex]
Mass of the car = 1000 Kg
K.E of the car =[tex]\frac{1}{2}*1000*v\\ 500v[/tex]
Therefore Kinetic energy of the truck is greater than that of the car
A magnet pulls a piece of iron with a force of 1 N. What is the force that the iron piece exerts on the magnet?
The iron piece exerts a force of 1 N divided by the ratio of the weight of the iron piece to the weight of the magnet in the same direction.
The iron piece exerts a force of 1 N on the magnet in the opposite direction.
The iron piece exerts a force of 1 N divided by the ratio of the weight of the iron piece to the weight of the magnet in the opposite direction.
The iron piece exerts a force of 1 N on the magnet in the same direction.
Answer:
the final statements the correct one is. The second
The iron piece exerts a force of 1 N on the magnet in the opposite direction
Explanation:
In this exercise they give us the force exerted by a magnet on an iron bar and ask us the force that the iron bar exerts on the magnet. We can see that these are action and reaction forces, which by Newton's third law must be of equal magnitude and opposite direction, each applied to one of the bodies.
the final statements the correct one is. The second
The iron piece exerts a force of 1 N on the magnet in the opposite direction
A stationary siren creates an 894 Hz
sound. When a motorcyclist is driving
toward it, she hears a 926 Hz sound
How fast is she driving?
(Speed of sound = 343 m/s)
(Unit = m/s)
Answer:
12.3 m/s
Explanation:
The Doppler equation describes how sound frequency depends on relative velocities:
fr = fs (c + vr)/(c + vs),
where fr is the frequency heard by the receiver,
fs is the frequency emitted at the source,
c is the speed of sound,
vr is the velocity of the receiver,
and vs is the velocity of the source.
Note: vr is positive if the receiver is moving towards the source, negative if away.
Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.
Given:
fs = 894 Hz
fr = 926 Hz
c = 343 m/s
vs = 0 m/s
Find: vr
926 = 894 (343 + vr) / (343 + 0)
vr = 12.3
The speed of the car is 12.3 m/s.
If a body is moving in the horizontal axis with a velocity Vx= 6m/s and in the vertical axis Vy=8m/s What is the angle Theta above the horizontal axis of the velocity of the body V? A. Theta = 45.0 degrees B.Theta = 63.3 degrees C. Theta = 53.1 degrees D. Theta = 43.7 degrees
Answer: C
Explanation: It's a lot of math.
The option that gives the correct value for the angle theta above the horizontal axis of the velocity of the body, v is option C.
C. 53.1°
The given parameters are;
The velocity of the body relative to the horizontal axis, vₓ = 6 m/s
The velocity of the body relative to the vertical axis, [tex]v_y[/tex] = 8 m/s
Required;
The measure of the angle theta above above the horizontal axis of the velocity of the body, v
Solution:
The velocity of the body can be represented vectorially as follows;
v = 6·i + 8·j
The vectoral form gives the legs of the right triangle that has the magnitude and direction as the hypotenuse side
Therefore;
[tex]\theta = arctan \left(\dfrac{8}{6} \right) \approx \underline{53.1^{\circ}}[/tex]
Learn more about the vectors here:
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what energy is used when we drink a sip of juice?
Answer:
mechanical energy or chemical energy
The period of a pendulum is the time it takes the pendulum to swing back and forth once. If the only dimensional quantities that the period depends on are the acceleration of gravity, g, and the length of the pendulum, ℓ, what combination of g and ℓ must the period be proportional to? (Acceleration has SI units of m • s-2.)
Answer: √(L/g)
Explanation:
Here we only work with the units:
The unit of the period is units of time, so we have:
[T] = [s]
Now, the units of the length of the pendulum are units of distance:
[L] = [m]
And the units of the acceleration are:
[g] = [m/s^2]
Now, we want to work with those two in such way that the end result is only in seconds.
First, we can see that in g we have seconds square, so we know that we should use a square root.
Then we can divide L by g in order to remove the distance unit, and to have the time unit in the numerator
[L/g] = [m*s^2/m] = [s^2]
Now we apply the square root:
[√(L/g)] = [√s^2] = [s]
Then the combination is: √(L/g)
T = k*√(L/g)
where k is the constant of proportionality.
Distinguish between concave mirror and convex mirror
Answer:
Concave mirror makes someone looking at it look dwarf or short, while convex mirror stretches the person making the person look weird.
What is necessary for a ball to be in translational equilibrium?
Answer:
In order to be in translational equilibrium, the net force (sum of the forces) must be 0.
The Coulomb force between two charges q1 and q2 at separation r in air is F. If half of the separation is filled with medium of dielectric constant 9, what will be the value of new coulomb force?
Answer:
The new Coulomb force is q₁q₂/9πε₀r²
Explanation
The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².
Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.
Since we have air between q₂ and q₃, the coulomb force between them is
F' = q₂q₃/4πε₀d²
= q₂(q₁/κ)/4πε₀(r/2)²
= 4q₂q₁/κ4πε₀r²
= 4/κ(q₂q₁/4πε₀r²)
= 4/9 × (q₂q₁/4πε₀r²)
= q₁q₂/9πε₀r²
So, the new Coulomb force is q₁q₂/9πε₀r²
Tita= 55°
Answer and proper explanation pls in English
Answer:
the photo is a bit blur
Be careful of the wire size application chart you use, because many of them allow up to a ____ voltage drop over the length of the wire, which is more than is allowed in most automotive circuits. Group of answer choices
Answer: 0.1
Explanation: The wire size is very important when making decisions on the wiring of any equipment,house and other things. It has also been found that the size of the wire determines the load that can be allowed through it.
The right wire size application chart should always be considered before selecting the wiring diagram or system for any building or equipment as it can help to determine the amount of voltage that can be effectively carried through it.
Express the time spent to daily life activities during holidays as a fraction of whole day 1. Represent the fractions in pictorial form. 2. Write the fractions in simplest form. 3. Arrange them in ascending order.
Answer:
(II). The fractions in simplest form
[tex]\dfrac{31}{35}[/tex], [tex]\dfrac{91}{165}[/tex] and [tex]\dfrac{13}{5}[/tex]
(III). The fractions in ascending order
[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]
Explanation:
Given that,
(I). Represent the fractions in pictorial form
(II). Write the fractions in simplest form.
(III). Arrange them in ascending order.
Suppose, The fractions in pictorial form
(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}[/tex]
(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}[/tex]
(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}[/tex]
We need to write in simplest form
Using given fraction
(a). [tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{3\times7}{5\times7}+\dfrac{2\times5}{7\times5}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21}{35}+\dfrac{10}{35}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}[/tex]
[tex]\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{31}{35}[/tex]
(b). [tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{9\times15}{11\times15}-\dfrac{4\times11}{15\times11}[/tex]
[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{135-44}{165}[/tex]
[tex]\dfrac{9}{11}-\dfrac{4}{15}=\dfrac{91}{165}[/tex]
(c). [tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{2\times2}{5\times2}+\dfrac{3\times5}{5\times2}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7}{10}+\dfrac{4+15}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{7+4+15}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{26}{10}[/tex]
[tex]\dfrac{7}{10}+\dfrac{2}{5}+\dfrac{3}{2}=\dfrac{13}{5}[/tex]
We need to arrange them in ascending order
Using simplest form
The simplest fraction in ascending order
[tex]\dfrac{91}{165}<\dfrac{31}{35}<\dfrac{13}{5}[/tex]
Hence, This is required solution.
Una partícula se mueve en el plano XY efectúa un desplazamiento mientras actúa sobre ella una fuerza constante. X= (4i + 3j) m, F = (16i + 12j) N a) Calcule la magnitud del desplazamiento y la de la fuerza. B) Calcule el trabajo realizado por la fuerza F c) Calcule el ángulo entre F y x.
Answer:
a) La magnitud del desplazamiento es de 5 m
La magnitud de la fuerza es 20 N
b) El trabajo realizado por la fuerza es de 100 J
c) El ángulo entre la fuerza y el plano es 0 °
Explanation:
a) La magnitud del desplazamiento se encuentra por la relación;
[tex]\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}[/tex]
Lo que da;
[tex]\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m[/tex]
De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;
[tex]\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}[/tex]
Lo que da;
[tex]\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N[/tex]
b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X
∴ Ancho = 20 N × 5 m = 100 N · m = 100 J
c) La dirección de la fuerza viene dada por la siguiente fórmula;
[tex]tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right ) = 38.9^{\circ}[/tex]
La dirección del plano viene dada por la siguiente fórmula;
[tex]tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right ) = 38.9^{\circ}[/tex]
Por tanto, el ángulo entre la fuerza y el plano = 0 °
La fuerza actúa a lo largo del plano.
