Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and is equal to 1

Answer:

Ascending- 10%, 0.2, 1/4, 30%

Descending- 30%, 1/4, 0.2, 10%

Step-by-step explanation:

0.2 = 2/10 = 4/20

1/4 = 5/20

30% = 30/100 = 6/20

10% = 10/100 = 2/20

Ascending

-2/20, 4/20, 5/20, 6/20

- 10%, 0.2, 1/4, 30%

Descending

- 6/20, 5/20, 4/20, 2/20

- 30%, 1/4, 0.2, 10%

Answer:

equation of the line would be y=-3x+7

Step-by-step explanation:

because the line goes 3 up and 1 behind for the next point ad the line is not y intercept 7

Step-by-step explanation:

the answer is -1. I have a picture, take a lot at it

Answer: 3x+3

Step-by-step explanation:

4x+3-x

= (4x-x) + 3

= 3x+3

Answer:

D. X + 9​

Step-by-step explanation:

x² + 2x - 63

What 2 numbers multiply to -63 and add to 2

9 * -7 = -63

9+-7 = 2

(x+9)(x-7)

Answer:

29.

Step-by-step explanation:

We know that all functions of any angle must add up to be 180 degrees. using this knowledge we take 54 and subtract it by 180.

That leaves us with 126.

We can safely assume the measurement of angle B, using the angle measured as 97.

This is due to the law of corresponding angles.

97 and angle B; correspond, so they must measure the same.

our sum of 126 subtracted by angle B (97) leaves us with the sum of 29.

Answer:

4.5

Step-by-step explanation:

let,

k×9²=300

k = 300/81

or, k = 100/27

as two triangles are similar,

if smaller triangle's corresponding side is x (let), then,

kx²=75

100x²/27=75

x²=75×27/100

x=√81/4

x=9/2

x=4.5

Given:

The equation is:

[tex]y=\sqrt[3]{x}[/tex]

To find:

The graph of the given equation.

Solution:

We have,

[tex]y=\sqrt[3]{x}[/tex]

The table of values is:

x                 y

-8              -2

-1                -1

0               0

1                 1

8                8

Plot these points on a coordinate plane and connect them by a free hand curve as shown in the below graph.

Answer:

D

Step-by-step explanation:

edge 2020

Answer: 804 is divisible by 1, 2, 3, 4, 6, 12 ,67 ,134 ,201, 268, 402 ,804

Answer:

The factors of 804 are: 1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402,804.

Step-by-step explanation:

Answer:

where m= slope m= -7/3

Step-by-step explanation:

Answer:

21 letters

Step-by-step explanation:

A, B, C, D, E, F, G, H, I, J, K, L, M, NO, P, Q, R, S, T, U

Answer:

P = 1,-10

Q=1,-1

R=7,-1

S=7,-10

Answer:

A

Step-by-step explanation:

Recall that the sum of an arithmetic series is given by:

[tex]\displaystyle S = \frac{n}{2}\left(a + x_n\right)[/tex]

Where n is the number of terms, a is the first term, and x_n is the last term.

We know that the initial term a is 13, the common difference is 7, and the total sum is 2613. Since we want to find the number of terms, we want to find n.

First, find the last term. Recall that the direct formula for an arithmetic sequence is given by:

[tex]x_n=a+d(n-1)[/tex]

Since the initial term is 13 and the common difference is 7:

[tex]x_n=13+7(n-1)[/tex]

Substitute:

[tex]\displaystyle S = \frac{n}{2}\left(a + (13+7(n-1)\right)[/tex]

We are given that the initial term is 13 and the sum is 2613. Substitute:

[tex]\displaystyle (2613)=\frac{n}{2}((13)+(13+7(n-1)))[/tex]

Solve for n. Multiply both sides by two and combine like terms:

[tex]5226 = n(26+7(n-1))[/tex]

Distribute:

[tex]5226 = n (26+7n-7)[/tex]

Simplify:

[tex]5226 = 7n^2+19n[/tex]

Isolate the equation:

[tex]7n^2+19n-5226=0[/tex]

We can use the quadratic formula:

[tex]\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = 7, b = 19, and c = -5226. Substitute:

[tex]\displaystyle x =\frac{-(19)\pm\sqrt{(19)^2-4(7)(-5226)}}{2(7)}[/tex]

Evaluate:

[tex]\displaystyle x = \frac{-19\pm\sqrt{146689}}{14} = \frac{-19\pm 383}{14}[/tex]

Evaluate for each case:

[tex]\displaystyle x _ 1 = \frac{-19+383}{14} = 26\text{ or } x _ 2 = \frac{-19-383}{14}=-\frac{201}{7}[/tex]

We can ignore the second solution since it is negative and non-natural.

Therefore, there are 26 terms in the arithmetic series.

Our answer is A.

Answer:

Step-by-step explanation:

We need to create a system of equations here, one for the NUMBER of tickets sold and one for the COST of the tickets. They are very much NOT the same thing.

We have that the total number of tickets is 5, and that that total is made up of adult tickets and child tickets. The equation for the NUMBER of tickets, then, is:

a + c = 5

Now for the money.

If a child ticket costs Rc 500, the expression that represents that that is in fact the cost of the child ticket is 500c;

likewise for the adult ticket. If the adult ticket costs Rc 700, the expression that represents that is 700a.

And we know that a total of Rs 1300 was spent on the tickets. The equation for the COST is

700a + 500c = 1300

Now go back to the first equation and solve it for either a or c, it doesn't matter which. I solved for a:

a = 5 - c  and we will sub that into the second equation for a:

700(5 - c) + 500c = 1300 and

3500 - 700c + 500c = 1300 and

-200c = -400 so

c = 2 tickets. That means that there were

a = 3 tickets sold for the adults.

Answer:

if the diameter is 11, them the answer is 47.52275cm

Answer:

Step-by-step explanation:

I used calculus for this, as I'm not sure there's any other way to do it and to do it as easily. This is the volume of a solid found by using the disk method of rotation:

[tex]V=\pi\int\limits^a_b {[R(x)]^2-[r(x)]^2} \, dx[/tex]

where R(x) is the outer shell of the solid and r(x) is the space inbetween the solid and the axis of rotation. There is no space between the solid and the axis of rotation, so r(x) = 0. R(x) is the height of the solid which is 3. Therefore, f(x) = 3 and that's the function we put into the formula with the lower bound of 3 and the upper bound of 5:

[tex]V=\pi\int\limits^5_3 {3^2}-0^2 \, dx[/tex]  and

[tex]V-\pi\int\limits^5_3 {9} \, dx[/tex]  and integrating:

[tex]V=\pi(9x\left \} {{5} \atop 3}} \right.[/tex] and using the First Fundamental Theorem of Calculus:

V = π(9(5) - 9(3)) and

V = π(45 - 27) so

V = 18π units cubed or in decimal format,

V = 56.549 units cubed

Answer:

Step-by-step explanation:

m1 = 300

m2= 300(1+.05) = 300(1.05)

m3 = 300(1.05)(1.05)

m4= 300(1.05)(1.05)(1.05)

each subsequent month is the previous month times "1 + .05"

the "one" preserving the running total, and the extra ".05" adding the 5%

the repeating (1.05)(1.05)(1.05) is notational simplified using exponents

(1.05)(1.05)(1.05) = [tex](1.05)^{3}[/tex]

Answer:

Step-by-step explanation:

This requires some serious work before we even begin. First off, we will convert the km to meters:

32 km = .032 m

46 km = .046 m

And then we have to deal with the angle given as 40 degrees west of north. An angle 40 degrees west of north "starts" at the north end of the compass and moves towards the west (towards the left in a counterclockwise manner) 40 degrees. That means that the angle that is made with the negative x axis is a 50 degree angle. BUT the way angles are measured in standard form are from the positive x-axis, therefore:

40 degrees west of north = 50 degrees with the negative x axis = 130 degrees with the positive x axis. 130 is the angle measure we use. Phew! Now we're ready to start. Adding vectors requires us to use the x and y components of vectors in order to add them.

[tex]A_x=.032cos90.0[/tex] so

[tex]A_x=0[/tex] (the 90 degrees comes from "due north")

[tex]B_x=.046cos130[/tex] so

[tex]B_x=-.030[/tex] and if we add those to get the x component of the resultant vector, C:

[tex]C_x=-.030[/tex]   And onto the y components:

[tex]A_y=.032sin90.0[/tex] so

[tex]A_y=.032[/tex]

[tex]B_y=.046sin130[/tex] so

[tex]B_y=.035[/tex] and if we add those together to get the y component of the resultant vector, C:

[tex]C_y=.067[/tex]  Note that since [tex]C_x[/tex] is negative and [tex]C_y[/tex] is positive, the resultant angle (the direction) will put us into QII.

We find the magnitude of C:

[tex]C_{mag}=\sqrt{(-.030)^2+(.067)^2}[/tex]

We will round this after we take the square root to the thousandths place.

[tex]C_{mag}=.073m[/tex] and now for the angle:

[tex]\theta=tan^{-1}(\frac{.067}{-.030})[/tex] which gives us an angle measure of -67, but since we are in QII, we add 180 to that to get that, in sum:

The magnitude of the resultant vector is .073 m at 113°

Answer:

or, -4a - 2a -7 = 11

or, -4a -2a =11 +7

or, - 6a = 18

or, a= 18÷ -6

a= -3

Answer:

M<C = 20°

Step-by-step explanation:

Because they’re vertical angles, that means they’re equal to each other so:

m<C = m<D

x = -3x + 80

x + 3x = 80

4x = 80

x = 20

Since m<C equals x, that means m<C is 20°

Answer:Hey I'm sorry I didn't get to answer your question it's just that I need the points because I don't have enough to get help with my question. I hope you get the answer that you need for you question. Good Luck :)

Step-by-step explanation:

Answer:

[tex]2\pi \times r = c[/tex]

[tex]\pi \times {r}^{2} = a[/tex]

A=5257.76

Step-by-step explanation:

Or use a calculator online.

Answer:

[tex]2(x^{2} -2x+4)[/tex]

Step-by-step explanation:

[tex]2x^{2} -4x+8[/tex]

= [tex]2x^{2} -2*2x+2*4[/tex]

= [tex]2(x^{2} -2x+4)[/tex]

Answer:

bạn cực ngu

Step-by-step explanation:

bạn cực kì ngu

Answer:

20.53 minutes

Step-by-step explanation:

Speed = Distance/Time = 30/7

Time = Distance / Speed

= 5280/30/7

= 1232 seconds / 60 = 20.53 minutes

Answered by Gauthmath

Answer:

Given:

i) Since DN and BC are transversals, we have:

As two angles and one side is congruent, the triangles are also congruent:

So their areas are same.

ii)

The quadrilateral has area of:

And the triangle has area of:

Since the areas of triangles DCM and NBM are same, the quadrilateral ADCB has same area as triangle ADN.

Answer:

I think I have proved it before you asked this question before also.

Step-by-step explanation:

SEE the image for solution.

HOPE it helps

Have a great day