Students were having a catapult contest, launching a tennis ball with their home built devices. The winner launched a ball at 30 degrees from the ground at 6.0 m/s. How high does the ball go?

Answer:

The gravitational potential energy (gpe) possessed by an object or body is directly proportional to the height of the object or body.

Explanation:

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Generally, the gravitational potential energy (gpe) of an object or body is directly proportional to the height of the object or body. Thus, the gravitational potential energy of a body increases as the height of the body increases.

In conclusion, an object with a higher height would have a higher gravitational potential energy.

Answer:

F = 0.414 N

Explanation:

Given that,

Magnetic flux density,[tex]B=3.6\times 10^{-2}\ T[/tex]

The length of the wire, l = 24 m

Current, I = 0.48 A

We need to find the force acting on the wire. The formula for the force is given by:

[tex]F=ILB[/tex]

Put all the values,

[tex]F=0.48\times 24\times 3.6\times 10^{-2}\\\\F=0.414\ N[/tex]

So, the force acting on the copper wire is equal to 0.414 N.

The magnetic force of the copper wire is  41.472 N.

The magnetic force of the copper wire is calculated by applying the following equation.

F = BIL x sinθ

Where;

F = (3.6 x 10⁻²) x (48) x 24 x sin(90)

F = 41.472 N

Thus, the magnetic force of the copper wire is  41.472 N.

Learn more about magnetic force here:  https://brainly.com/question/13277365

Answer:

the correct answer is B

Explanation:

To solve the system they must have the same amount of unknowns as equations,

a) If the system does not have friction, we must write the x-axis equation for each body, therefore we need to write N equations

b) if the system has friction, two equations are needed for each particle

therefore the correct answer is B

Answer:

A

Explanation:

The first thing you have to do is go back and list the resistances correctly. R1 = 20 R2 = 30 and R3 = 10.

Leave the units off if you can't make an omega.

The resistance of a series circuit (that's what this is) is r1 + r2 + r3 = 10 + 20 + 30 = 60 ohms

Now use ohms law.

R = 60 ohms

V = 110 volts.

I = V / R

I = 110/60

I = 1.833 to the nearest 1/10 = 1.8

Answer:

Explanation:

1)Melting:

Melting is the process by which a substance changes from the solid phase to the liquid phase. ... Melting occurs when the internal energy of a solid increases, usually through the application of heat or pressure, such that the molecules become less ordered.

2) liquefication:

In physics and chemistry, the phase transitions from solid and gas to liquid (melting and condensation, respectively) may be referred to as liquefaction. The melting point (sometimes called liquefaction point) is the temperature and pressure at which a solid becomes a liquid.

3) vaporization:

Vaporization, conversion of a substance from the liquid or solid phase into the gaseous (vapour) phase. If conditions allow the formation of vapour bubbles within a liquid, the vaporization process is called boiling. Direct conversion from solid to vapour is called sublimation.

4) Sublimation occurs as molecules of a substance in the solid state go to the vapor state directly, rather than through the liquid state. ... ⭕In terms of the kinetic molecular theory, we know that molecules are in constant random motion, even when the substance is below the melting point.

Explanation:

soln,

weight=600N

mass=?

gravity=9.8 m/s²

now,

hope it helps.

Answer:

m = 61.22 kg

Explanation:

F = 600 N

g = 9.8 m/s²

m = ?

F = mg

600 = m(9.8)

---> m = 61.22 kg

Explanation:

[tex]we \: know \: that \: joule \: is \: the \: unit \: of \\ energy \: we \: have \: energy = \frac{1}{2} m {v}^{2} \\ unit \: of \: this \: is \\ joule = kg {( \frac{m}{ s }) }^{2} \\ thank \: you[/tex]

Answer:

2.38m

Explanation:

Use potential energy

PE= mgh

42= 1.8*9.8*h

solve for h

to get h= 2.38 m

Answer:

The assertion is true and reason is false.

Explanation:

Assertion: I P+ Q I = I P- QI, then P must be perpendicular to Q.

Reason : The relation will hold even when Q is a null vector.

Now

[tex]\left | P + Q \right |=\left | P - Q \right |\\\\P^2 + Q^2 + 2 P Q cos \theta =P^2 + Q^2 - 2 P Q cos \theta\\\\4 P Q cos \theta = 0 \\\\cos \theta = 0 \\\\\theta = 90 degree[/tex]

So, P and Q are perpendicular to each other.

So, the assertion is true.

Reason is false.

Answer:

Large spherical regions from which no light is detected

Explanation:

A black hole is an object that has an extremely high density such that it possesses very powerful gravitational force that prevents the escape of all objects including light from it, and consumes nearby objects.

Due to the power of the gravitational force of a black hole, at the center, objects are infinitesimally compressed resulting in the inapplicability of the concept of space and time and the location is known as a singularity

Therefore, the search for black holes involves searching for large spherical regions from which no light is detected.

Answer:

40 kW

Explanation:

A railcar has a continuous 1000 N decelerating force any time it is in motion. If no braking occurs, how much power would be required to keep the railcar moving at 40 m/s

Solution:

Power in Physics is the rate of doing work and the work can be mechanical, electrical, etc. The S.I unit of power is the watts (W).

The power required to keep the car moving must match the work done by the friction force (decelerating force) that tends to slow down the railcar.

Work done = Force * displacement

Power = Work done / time = (Force * displacement) / time

Power = Force * (displacement / time)

Power = force * velocity = 1000 N * 40 m/s = 40000 W

Power = 40 kW

Answer:

Explanation:

As far as the displacement goes, we have 2 displacement vectors. If we didn't have the angles to deal with, this would be a much simpler process, but then that wouldn't be any fun at all, would it? I'll deal with the average speed first, then the displacement, which is a vector addition problem.

The average speed is found by adding together the distances the student traveled and then dividing this sum by the total time he spent traveling. If we are told that the student runs at 4.5 m/s for 3.0 minutes, we can use this to find out the distance he ran during that time interval. However, the units are not the same. We will find the distance the student traveled by convering the time to seconds.

3.0 minutes = 180 seconds, and

4.1 minutes = 246 seconds.

That means that the distance he ran in 180 seconds is found by multiplying this time be the speed at which he ran:

4.5 m/s(180 s) = 810 m and

3.5 m/s(246 s) = 860 m (rounded to follow the rules of sig dig).

This makes the speed equation look like this:

[tex]s=\frac{810+861}{180+246}=\frac{1671}{426}=3.9\frac{m}{s}[/tex] That's the average speed, which is NOT at all the same as the displacement. Displacement is where he ended up in reference to where he started. The angles play a huge part in this math (that is very involved, to say the least). We begin by restating the displacement of each "leg" of this journey.

The first leg took him 810 m at 207 degrees and

the second leg took him 860 m at 325 degrees

To find the x and y components of these 2 legs, or parts, we have to use the cos and sin formulas. We will call the first leg A and the second leg B. First the x components of both A and B:

[tex]A_x=810cos207[/tex] and

[tex]A_x=-720[/tex]

[tex]B_x=860cos325[/tex] and

[tex]B_x=704[/tex] and we add these to get the x-component of the resultant vector, C:

  -720

+  704

   -10 (rounded, as needed, to the tens place).

Now for the y-components of the resultant vector:

[tex]A_y=810sin207[/tex] and

[tex]A_y=-370[/tex]

[tex]B_y=860sin325[/tex] and

[tex]B_y=-490[/tex] and we add these to get the y-component of the resultant vector, C:

  -370

+ -490

 -860

Since the x component is negative and so is the y, we are in QIII, so when we finally find our angle, we will have to add 180 to it.

For the magnitude of the displacement vector, in m:

[tex]C_{mag}=\sqrt{(-10)^2+(-860)^2}[/tex] which gives us

[tex]C_{mag}=860m[/tex]

Now, because displacement is vector, we also need the angle. We find that is the formula

[tex]\theta=tan^{-1}(\frac{C_y}{C_x})[/tex] and filling in:

[tex]\theta=tan^{-1}(\frac{-860}{-10})=90[/tex] (rounded correctly), and then we add 180 to give us a final direction of 270 degrees.

So the final displacement of the student is 860 m at 270 degrees

Answer:

[tex]V.E=498.02m/s^2[/tex]

Explanation:

From the question we are told that:

Radius [tex]r=301Km[/tex]

Gravitational acceleration [tex]g=0.412 m/s^2[/tex]

Generally the equation for Escape velocity is mathematically given by

 [tex]V.E^2=2gr[/tex]

 [tex]V.E^2=2*0.412m/s^2*301000[/tex]

 [tex]V.E^2=248024[/tex]

 [tex]V.E=\sqrt{248024}[/tex]

 [tex]V.E=498.02m/s^2[/tex]

Answer:

Yes.⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Answer:

The angle is 16 degree.

Explanation:

A uniformly charged infinite plane, density σ = 4.10-9 C/cm2, is placed vertically in air. A small ball of mass 8 g, with charge q = 10-8 C, hangs close to the plane, so that the string is initially parallel to the plane. Take g = 9.8m/s2 . In equilibrium, by what angle does the string hanging from the ball make an angle with the plane?

Surface charge density,   σ = 4 x 10^-9 C/m^2

charge, q = 10^-8 C

mass, m = 0.008 kg

Let the tension is the string is T and the angle is A.

[tex]T sin A = q E....(1)\\\\T cos A = m g .... (2)\\\\Divie (1) by (2)\\\\tan A =\frac{q E}{m g}\\\\tan A = \frac{10^{-8}\times 4\times 10^{-5}}{2\times 8.85\times 10^{-12}\times 0.008\times9.8}\\\\tan A = 0.288\\\\A = 16 degree[/tex]

Answer:

D. The number of winter coats sold and the temperature outside.

Explanation:

A negative correlation can be described as a relationship existing between two variables such that as one of these variables goes up, the other variable would go down and vice versa.

With this explanation in mind, as the temperature outside increases, less winter coats would be sold because an increase in temperature would mean more heat and hotness. People would be uncomfortable wearing thick clothing.

Answer:

Yes it would be different on Earth and the moon

Answer:

yes

Explanation:

Answer:

B. have a lower ionization energy

D. are metals

Explanation:

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.

Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.

Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.

Valency can be defined as a measure of the combining power of a chemical element with other atoms to form a molecule or chemical compound.

Typically, valency is measured by the amount of hydrogen atoms that a chemical element can combine with or displace to form a molecule or chemical compound.

Ionization energy can be defined as the minimum energy required to remove or detach an electron from a neutral atom in a gaseous state.

Generally, the ionization energy of chemical elements tend to increase from left to right across a period on the periodic table. This increase is due to the fact that the atomic radius of chemical elements generally decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon) i.e from left to the right of the periodic table. Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).

This ultimately implies that, atoms with relatively large atomic radii tend to have a low electron affinity and a low ionization energy.

In conclusion, chemical elements that typically give up electrons are metals because their outermost shell contains excess electrons and have a lower ionization energy.

Answer:

In coin card experiment smooth card is used so that the card can slide easily from glass

Answer:

Explanation:

mass and distance

the order of vector addition doesn't affect the resultant vector and grouping or order of pair doesn't effect the sum.

Answer:

Explanation:

Assuming the squirrel is jumping off the ground, here's what we know but don't really know...

v₀ = 4.0 at 50.0°

So that's not really the velocity we are looking for. We are dealing with a max height problem, which is a y-dimension thing. Therefore, we need the squirrel's upward velocity, which is NOT 4.0 m/s. We find it in the following way:

[tex]v_{0y}=4.0sin(50.0)[/tex] which gives us that the upward velocity is

v₀ = 3.1 m/s

Moving on here's what we also know:

a = -9.8 m/s/s and

v = 0

Remember that at the very top of the parabolic path, the final velocity is 0. In order to find the max height of the squirrel, we need to know how long it took him to get there. We are using 2 of our 3 one-dimensional equations in this problem. To find time:

v = v₀ + at and filling in:

0 = 3.1 - 9.8t and

-3.1 = -9.8t so

t = .32 seconds.

Now that we know how long it took him to get to the max height, we use that in our next one-dimensional equation:

Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] and filling in:

Δx = [tex]3.1(.32)+\frac{1}{2}(-9.8)(.32)^2[/tex] and using the rules for adding and subtracting sig fig's correctly, we can begin to simplify this:

Δx = .99 - .50 so

Δx = .49 meters

Answer:

[tex]v=-4.93\times 10^{5}~m/s[/tex] [negative sign denotes that it is moving away]

Explanation:

Actual wavelength of hydrogen spectral lines, [tex]\lambda=121.6~nm[/tex]

Apparent wavelength of hydrogen spectral lines from a star, [tex]\lambda'=121.8~nm[/tex]

So, shift in wavelength:

[tex]\Delta \lambda=\lambda'-\lambda[/tex]

[tex]\Delta \lambda=121.8-121.6[/tex]

[tex]\Delta \lambda=0.2~nm[/tex]

Using Doppler's shift:

[tex]\frac{\Delta \lambda}{\lambda} =-\frac{v}{c}[/tex]

[tex]\frac{0.2}{121.6} =-\frac{v}{3\times 10^8}[/tex]

[tex]v=-4.93\times 10^{5}~m/s[/tex] [negative sign denotes that it is moving away]

Answer:

below

Explanation:

that is the procedure above

Answer:

b)3:2

Explanation:

The dispersive power is the reciprocal of the focal length:

[tex]P=\frac{1}{f}[/tex]

Given the ratio of focal lengths:

[tex]\frac{f_1}{f_2} = \frac{2}{3}\\\\\frac{\frac{1}{P_1}}{\frac{1}{P_2}}=\frac{2}{3}\\\\\frac{P_2}{P_1}=\frac{2}{3}\\\\\frac{P_1}{P_2}=\frac{3}{2}[/tex]

Therefore,

P₁ : P₂ = 3 : 2

Hence, the correct option is:

b)3:2

The Torque is only produced when the force is applied perpendicular to the moment arm.

The equal and opposite force acting at a point from the axis of rotation is called the moment.

M = F x r

Moment of force is also called as Torque.

Moment arm is the distance of the point of application of force from the axis of rotation of the body.

Thus, the perpendicular component only, produces the torque.

Learn more about moment of force.

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Answer:

[tex]N_B-W_B = 0[/tex]

Explanation:

There are two forces acting on object B. If we consider the law of equilibrium, then the two forces must be equal in magnitude, for the object to remain in equilibrium position:

[tex]N_B = W_B\\\\N_B-W_B = 0[/tex]

Therefore, the correct answer of the given question, from the given choices, is:

[tex]N_B-W_B = 0[/tex]

The amount of energy required for a unit mass of a substance to undergo a phase change from liquid to gas.