Suppose a life insurance company sells a $240,000 one-year term life insurance policy to a 19-year-old female for $240. The probability that the female survives the year is 0.999578. Compute and interpret the expected value of this policy to the insurance company. The expected value is $ (Round two decimal places as needed.)

Answers

Answer 1

Answer:

$138.72

Step-by-step explanation:

(1-0.999578)*$240,000 = $101.28

$240 - $101.28 = $138.72


Related Questions

A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)e^kt, where m(0) is the initial mass and k is a negative constant. The mean life M of an atom in the substance is
[infinity]
M = âk â« te^kt dt.
0

For the radioactive carbon isotope, 14C, used in radiocarbon dating, the value of k is -0.000121. Find the mean life of a 14C atom.

Answers

Answer:

mean life = 8264.5 s

Step-by-step explanation:

k = - 0.000121

The relation is given by

[tex]m = mo e^{kt}[/tex]

Now, the mean life is the life time for which the sample retains.

The mean life is the reciprocal of the decay constant.  

The relation between the mean life and the decay constant is

[tex]\tau =\frac{1}{k}\\\\\tau = \frac{1}{0.000121} = 8264.5 seconds[/tex]

The ocean surface is at 0 ft elevation. A diver is underwater at a depth of 138 ft. In this area, the ocean floor has a depth of 247 ft. A rock formation rises to a peak 171 ft above the ocean floor. How many feet below the top of the rock formation is the diver?

Answers

Answer:

The ocean surface is at 0 ft elevation. A diver is underwater at a depth of 138 ft. In this area, the ocean floor has a depth of 247 ft.

Step-by-step explanation:

1. You measure 24 textbooks' weights, and find they have a mean weight of 75 ounces. Assume the population standard deviation is 3.3 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight.
2. You measure 37 backpacks' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 10.1 ounces. Based on this, construct a 95% confidence interval for the true population mean backpack weight.
3. You measure 30 watermelons' weights, and find they have a mean weight of 37 ounces. Assume the population standard deviation is 4.1 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean watermelon weight.
4. A student was asked to find a 99% confidence interval for widget width using data from a random sample of size n = 16. Which of the following is a correct interpretation of the interval 11.8 < μ < 20.4?
A. There is a 99% chance that the mean of a sample of 16 widgets will be between 11.8 and 20.4.
B. The mean width of all widgets is between 11.8 and 20.4, 99% of the time. We know this is true because the mean of our sample is between 11.8 and 20.4.
C. With 99% confidence, the mean width of all widgets is between 11.8 and 20.4.
D. With 99% confidence, the mean width of a randomly selected widget will be between 11.8 and 20.4.
E. There is a 99% chance that the mean of the population is between 11.8 and 20.4.
5. For a confidence level of 90% with a sample size of 23, find the critical t value.

Answers

Answer:

(73.845 ; 76.155) ;

(41.633 ; 48.367) ;

1.273 ;

C. With 99% confidence, the mean width of all widgets is between 11.8 and 20.4. ;

1.717

Step-by-step explanation:

1.)

Given :

Mean, xbar = 75

Sample size, n = 24

Sample standard deviation, s = 3.3

α = 90%

Confidence interval = mean ± margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 90% ; df = 24 - 1 = 23

Tcritical = 1.714

Margin of Error = 1.714 * 3.3/√24 = 1.155

Confidence interval = 75 ± 1.155

Confidence interval = (73.845 ; 76.155)

2.)

Given :

Mean, xbar = 45

Sample size, n = 37

Sample standard deviation, s = 10.1

α = 95%

Confidence interval = mean ± margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 95% ; df = 37 - 1 = 36

Tcritical = 2.028

Margin of Error = 2.028 * 10.1/√37 = 3.367

Confidence interval = 45 ± 3.367

Confidence interval = (41.633 ; 48.367)

3.)

Given :

Mean, xbar = 37

Sample size, n = 30

Sample standard deviation, s = 4.1

α = 90%

Margin of Error = Tcritical * s/√n

Tcritical at 90% ; df = 30 - 1 = 29

Tcritical = 1.700

Margin of Error = 1.700 * 4.1/√30 = 1.273

5.)

Sample size, n = 23

Confidence level, = 90%

df = n - 1 ; 23 - 1 = 22

Tcritical(0.05, 22) = 1.717

would someone mind looking over my answers to geometry!!

Answers

Answer:

Question 1: x = 6

Question 2: Correct!

Question 3: x = 11

Question 4: Correct!

Step-by-step explanation:

Question 1:

Angle 22x - 2 DOESN'T equal 50 degrees. Only Alternate Interior Angles will equal each other. These two angles are Same Side Interior Angles, meaning if you added them together, they would equal 180 degrees.

Knowing that adding 22x - 2 and 50 will equals 180 degrees, here's how we solve for x:

First, subtract 50 from 180 to find what angle 22x - 2 will equal:

180 - 50 = 130

130 = 22x - 2

Now use basic algebra to solve for x:

130 = 22x - 2

(add 2 to both sides)

132 = 22x

(divide both sides by 22)

x = 6

Question 3:

Angle 5x + 15 DOESN'T equal 9x + 11. They make up a line, which is 180 degrees, so they are supplementary angles.

With that in mind, to solve for x, add the two equations and set it equal to 180:

5x + 15 + (9x + 11) = 180

Now use basic algebra to solve for x:

5x + 15 + 9x + 11 = 180

(add like terms)

14x + 26 = 180

(subtract 26 from both sides)

14x = 154

(divide 14 from both sides)

x = 11

Hope it helps (●'◡'●)

Yess again pls help!
Tyyy

Answers

Umm I need more info to help u?

I need help solving this problem .

Answers

Step-by-step explanation:

here is the answer to your question

What is the equation of a parabola with its vertex at the origin and its focus at (–2, 0)?

Answers

Step-by-step explanation:

this is the answerI hope it helps

In one state lottery​ game, you must select four digits​ (digits may be​ repeated). If your number matches exactly the four digits selected by the lottery​ commission, you win.

​1) How many different numbers may be​ chosen?
​2) If you purchase one lottery​ ticket, what is your chance of​ winning?
​3) There are ___ different numbers that can be chosen. ​(Type a whole​ number.)
​4) There is a ___ chance of winning.*

*The answer choices for number 4 are:
1 in 10,000
1 in 6,561
1 in 100
1 in 1,000
1 in 9,999

Answers

Answer:

Part 1)

10,000 different numbers.

Part 2)

A) 1 in 10,000.

Step-by-step explanation:

Part 1)

Since there are four digits and there are ten choices for each digit (0 - 9) and digits can be repeated, then we will have:

[tex]T=\underbrace{10}_{\text{Choices For First Digit}}\times\underbrace{10}_{\text{Second Digit}}\times\underbrace{10}_{\text{Third Digit}}\times \underbrace{10}_{\text{Fourth Digit}} = 10^4=10000[/tex]

Thus, 10,000 different numbers are possible.

Part 2)

Since there 10,000 different tickets possible, the chance of one being the correct combination will be 1 in 10,000.

This is equivalent to 0.0001 or a 0.01% chance of winning.

You and a friend were invited to a
party. You both were asked to bring
pizzas and chips. Your friend brought
three pizzas and four bags of chips
and spent $48.05. You brought five
pizzas and two bags of chips and
spent $67.25. What is the cost of
each? Answer should be in (Pizza, Chips)

Answers

Answer:

Pizza = 12.35

Chips = 2.75

Step-by-step explanation:

Let :

Pizza = x

chips = y

3x + 4y = 48.05 - - - (1)

5x + 2y = 67.25 - - - (2)

Multiply (1) by 5 and (2) by 3

15x + 20y = 240.25

15x + 6y = 201.75

Subtract :

20y - 6y = 240.25 - 201.75

14y = 38.50

y = 38.50/ 14

y = 2.75

Put y = 2.75 in (1)

3x + 4(2.75) = 48.05

3x + 11 = 48.05

3x = 48.05 - 11

3x = 37.05

x = 37.05 / 3

x = 12.35

Pizza = 12.35

Chips = 2.75

A town recently dismissed 5 employees in order to meet their new budget reductions. The town had 4 employees over 50 years of age and 16 under 50. If the dismissed employees were selected at random, what is the probability that no more than 1 employee was over 50

Answers

Answer:

0.7513 = 75.13% probability that no more than 1 employee was over 50

Step-by-step explanation:

The employees are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

4 + 16 = 20 employees, which means that [tex]N = 20[/tex]

4 over 50, which means that [tex]k = 4[/tex]

5 were dismissed, which means that [tex]n = 5[/tex]

What is the probability that no more than 1 employee was over 50?

Probability of at most one over 50, which is:

[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]

In which

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,20,5,4) = \frac{C_{4,0}*C_{16,5}}{C_{20,5}} = 0.2817[/tex]

[tex]P(X = 1) = h(1,20,5,4) = \frac{C_{4,1}*C_{16,4}}{C_{20,5}} = 0.4696[/tex]

Then

[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.2817 + 0.4696 = 0.7513[/tex]

0.7513 = 75.13% probability that no more than 1 employee was over 50

A multiple regression model is ^Y = 8.114 + 2.005X1 + 0.774X2. Which of the following values is the estimate for the intercept parameter?
a. 0.774.
b. 8.114.
c. 1.000.
d. 2.005.

Answers

Answer:

B. 8.114

Step-by-step explanation:

The intercept parameter is the zero-grade component of the multilinear equation, that is, the component independent from [tex]x_{1}[/tex] and [tex]x_{2}[/tex]. Hence, the intercept parameter of the multilinear regression is 8.114. (Correct answer: B)

The time for a professor to grade a student’s homework in statistics is normally distributed with a mean of 13.3 minutes and a standard deviation of 2.0 minutes. What is the probability that randomly selected homework will require less than 17 minutes to grade?

Answers

Answer:

0.96784

Step-by-step explanation:

17-13.3/2

=1.85

p(x<1.85)

=0.96784

The probability that randomly selected homework will require less than 17 minutes to grade is 0.9678.

Mean [tex]\mu[/tex]=13.3 minutes

Standard deviation[tex]\sigma[/tex]=2 minutes

What is a z-score?

The value of the z-score tells you how many standard deviations you are away from the mean.

So, the z-score of the above data

[tex]z=\frac{x-\mu}{\sigma}[/tex]

[tex]z=\frac{17-13.3}{2}[/tex]

[tex]z=1.85[/tex]

From the standard normal table, the p-value corresponding to z=1.85

Or, p(x<1.85)=0.9678 or 96.78%

Hence, the probability that randomly selected homework will require less than 17 minutes to grade is 0.9678.

To get more about the z-score visit:

https://brainly.com/question/25638875

Which of the following is equivalent to the expression log2⁡a=r? 2a = r logr⁡2 = a 2r = a log2⁡r = a

Answers

9514 1404 393

Answer:

  (c)  2^r = a

Step-by-step explanation:

The relationship between log forms and exponential forms is ...

  [tex]\log_2(a)=r\ \Leftrightarrow\ 2^r=a[/tex]

__

Additional comment

I find this easier to remember if I think of a logarithm as being an exponent.

Here, the log is r, so that is the exponent of the base, 2.

This equivalence can also help you remember that the rules of logarithms are very similar to the rules of exponents.

Answer: Choice C)  [tex]2^r = a[/tex]

This is the same as writing 2^r = a

==========================================================

Explanation:

Assuming that '2' is the base of the log, then we'd go from [tex]\log_2(a) = r[/tex] to [tex]2^r = a[/tex]

In either equation, the 2 is a base of some kind. It's the base of the log and it's the base of the exponent.

The purpose of logs is to invert exponential operations and help isolate the exponent. A useful phrase to help remember this may be: "if the exponent is in the trees, then we need to log it down".

The general rule is that [tex]\log_b(y) = x[/tex] converts to [tex]y = b^x[/tex] and vice versa.

A loan of £1000 has a compound interest rate of 2.7% charged monthly. Express the original loan as a percentage of the total amount awed after 2 months if no payment are made

Answers

Answer:

£1054.729

Step-by-step explanation:

To find compound interest you need to use the equation 1000(1.027)^x.

To find the interest rate (1.027):

100 + 2.7 = 102.7

102.7 / 100 = 1.027

The value of x is the amount of months if no payment is made in this situation, so 2 would be the x value for this problem.

Hope this helps!  

Write an equation that expresses the following relationship.

d varies directly with w and inversely with p.

In your equation, use k as the constant of proportionality.

Answers

9514 1404 393

Answer:

  d = kw/p

Step-by-step explanation:

When d varies directly with w, the equation is ...

  d = kw

When d varies inversely with p, the equation is ...

  d = k/p

When d does both, the equation is ...

  d = kw/p

(-3).(+9)-(-24)-(+6).(+2)

Answers

The answer is -15 if you want it solved

A bricklayer needs to order 6 300 kg of building sand.

a) Write 6 300 kg in grams, giving your answer in standard form.

One grain of this sand approximately weighs 7 x 10°g.

b) How many grains of sand are there in 6 300 kg of sand? Give your answer in standard from.

Answers

Answer:

It would be 6300000. I can't write this in standard form.

Step-by-step explanation:

Answer:

6.3 x 10^6

Step-by-step explanation:

Can you please help me with this question

Answers

Hirap nyan ah hahahahah

Which choice is equivalent to(√6)( √8). How do you solve
A. 4√6
B. 4√3
C. 16√3
D. 3√16

Answers

Answer:

B

Step-by-step explanation:

(6)^1/2 × (8)^1/2

6^1/2 × 2 (2)^1/2

4 (3)^1/2

In a pool of water filled to a depth of 10 ft, calculate the fluid force on one side of a 3 ft by 4 ft rectangular plate if it rests vertically on its 4 ft edge at the bottom of the pool. Remember that water weighs 62.4 lb/ft3

Answers

9514 1404 393

Answer:

  6,364.8 lb

Step-by-step explanation:

The centroid of the plate is its center, so is 1.5 ft above the bottom of the pool, or 8.5 ft below the surface. The area of the plate is (3 ft)(4 ft) = 12 ft². Then the fluid force is ...

  (62.4 lb/ft³)(8.5 ft)(12 ft²) = 6,364.8 lb

Find the perimeter of the
polygon if ZB = D.
3 om
B
4 cm
D
5 cm
C
P = [?] cm

Answers

Answer:

16 cm

Step-by-step explanation:

4 + 4 + 3 + 5 = 16

The = sign means that B (which is 4 cm) is equal to D (which had no number)

And because it says that B = D (with the squiggly line (or a tilde)) And the L's (which means that the letters represent an angle) All you have to do is add the numbers together, and you get 16.

Sorry if I explained it badly, you at least got the answer.

(And also, if I'm wrong, please tell me.)

Answer:

P = 32 cm

Step-by-step explanation:

Im just putting the right answer up so you don't accidentally put in the wrong one.

What are the solutions to the system of equations graphed below?

Answers

Answer:

D

Step-by-step explanation:

solution is the points where the two graphs intersect.

they intersect at (-3,-3) and (0,6)

Which division problem does the diagram below best illustrate?


A diagram with 8 ovals containing 4 squares each.

O 16 divided by 4 = 4

O 32 divided by 4 = 8

O 36 divided by 4 = 9

O 8 divided by 2 = 4

Answers

Answer:

The answer is 32 divided by 4

Step-by-step explanation:

Because in each box there is 4. There are 8 ovals all together. So 8×4, you get 32 and divide it by the number of squares in an oval which is 4

Answer:

the answer is 32 divided by 4=8

Step-by-step explanation:

because when you look at the ovals there's eight ovals and in side there's four squares..

HOPE THIS HELPS!!!!!

Square Footage Frequency
0-499 5
500-999 17
1000-1499 36
1500-1999 115
2000-2499 125
2500-2999 81
3000-3499 47
3500-3999 45
4000-4499 22
4500-4999 7
The accompanying frequency distribution represents the square footage of a random sample of 500 houses that are owner occupied year round. Approximate the mean and standard deviation square footage.

Answers

Answer:

2424.5

904.16

Step-by-step explanation:

the mean = ∑frequency /n

∑f = 5+17+36+115+125+81+47+45+22+7 = 500

∑xf = 1212250

∑x²f = 3347037625

sample mean = 1212250/500

= 2424.5

variance = 1/500-1[3347037625 - 1212250²]

= 815710.02

standard deviation is = √variance

standard deviation = √815710.02

= 904.16

Levi makes the minimum salary for actuary. Andres maybe the median salary for cpa. Who makes more money

Answers

Answer:

Andres

why?

Because he is median salary for cpa

4
5

start fraction, 5, divided by, 4, end fraction hour ==equals
minutes

Answers

Answer:

1.25. It would be 1.25 if ur just talking about dividing in general which is pretty tough

Answer:

\dfrac54=-4c+\dfrac14 4 5 ​ =−4c+ 4 1 ​ start fraction, 5, divided by, 4, end fraction, equals, minus, 4, c, plus, start fraction, 1, divided by, 4, end fraction

Step-by-step explanation:

A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. The numbers y of cell sites from 1985 through 2011 can be modeled byy = 269573/1+985e^-0.308t where t represents the year, with t = 5 corresponding to 1985. Use the model to find the numbers of cell sites in the years 1998, 2003, and 2006.

Answers

Answer:

(a) 3178

(b) 14231

(c) 33152

Step-by-step explanation:

Given

[tex]y = \frac{269573}{1+985e^{-0.308t}}[/tex]

Solving (a): Year = 1998

1998 means t = 8 i.e. 1998 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*8}}[/tex]

[tex]y = \frac{269573}{1+985e^{-2.464}}[/tex]

[tex]y = \frac{269573}{1+985*0.08509}[/tex]

[tex]y = \frac{269573}{84.81365}[/tex]

[tex]y = 3178[/tex] --- approximated

Solving (b): Year = 2003

2003 means t = 13 i.e. 2003 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*13}}[/tex]

[tex]y = \frac{269573}{1+985e^{-4.004}}[/tex]

[tex]y = \frac{269573}{1+985*0.01824}[/tex]

[tex]y = \frac{269573}{18.9664}[/tex]

[tex]y = 14213[/tex] --- approximated

Solving (c): Year = 2006

2006 means t = 16 i.e. 2006 - 1990

So:

[tex]y = \frac{269573}{1+985e^{-0.308*16}}[/tex]

[tex]y = \frac{269573}{1+985e^{-4.928}}[/tex]

[tex]y = \frac{269573}{1+985*0.00724}[/tex]

[tex]y = \frac{269573}{8.1314}[/tex]

[tex]y = 33152[/tex] --- approximated

A large container holds 4 gallons of chocolate milk that has to be poured into bottles. Each bottle holds 2 pints.
If the ratio of gallons to pints is 1: 8,
bottles are required to hold the 4 gallons of milk.

Answers

Answer:

64 Bottles

Step-by-step explanation:

that is the procedure above

Cole biked at 5 mph for 1 hours. Which of the following choices show how far he biked?
A=5.5 miles
B=6.5 miles
C=7.5 miles
D=10 miles

Answers

Answer:

Most Likely A, 5.5 Miles

Step-by-step explanation:

However the question doesn't make sense as the logical answer is simply 5 miles, but the safest choice is 5.5

The answer is A the answer kinda confusing

The thickness X of aluminum sheets is distributed according to the probability density function f(x) = 450 (x2 - x) if 6 < x < 12 0 otherwise 5-1 Derive the cumulative distribution function F(x) for 6 < x < 12. The answer is a function of x and is NOT 1! Show the antiderivative in your solution. 5-2 What is E(X) = {the mean of all sheet thicknesses)? Show the antiderivative in your solution.

Answers

Solution :

Given :

[tex]f(x) = \left\{\begin{matrix}\frac{1}{450}(x^2-x) & \text{if } 6 < x < 12 \\ 0 & \text{otherwise}\end{matrix}\right.[/tex]

1. Cumulative distribution function

[tex]$P(X \leq x) = \int_{- \infty}^x f(x) \ dx$[/tex]

              [tex]$=\int_{- \infty}^6 f(x) dx + \int_{6}^x f(x) dx $[/tex]

             [tex]$=0+\int_6^x \frac{1}{450}(x^2-x) \ dx$[/tex]

             [tex]$=\frac{1}{450} \int_6^x (x^2-x) \ dx$[/tex]

             [tex]$=\frac{1}{450}\left[\frac{x^3}{3}-\frac{x^2}{2}\right]_6^x$[/tex]

             [tex]$=\frac{1}{450}\left[ \left( \frac{x^3}{3} - \frac{x^2}{2}\left) - \left( \frac{6^3}{3} - \frac{6^2}{2} \right) \right] $[/tex]

            [tex]$=\frac{1}{450}\left[\frac{x^3}{3} - \frac{x^2}{2} - 54 \right]$[/tex]

2.  Mean [tex]$E(x) = \int_{- \infty}^{\infty} \ x \ f(x) \ dx$[/tex]

                       [tex]$=\int_{6}^{12}x . \left( \frac{1}{450} \ (x^2-x)\right)\ dx$[/tex]

                     [tex]$=\frac{1}{450} \int_6^{12} \ (x^3 - x^2) \ dx$[/tex]

                     [tex]$=\frac{1}{450} \left[\frac{x^4}{4} - \frac{x^3}{3} \right]_6^{12} \ dx$[/tex]

                     [tex]$=\frac{1}{450} \left[ \left(\frac{(12)^4}{4} - \frac{(12)^3}{3} \right) - \left(\frac{(6)^4}{4} - \frac{(6)^3}{3} \right) $[/tex]

                     [tex]$=\frac{1}{450} [4608 - 252]$[/tex]

                    = 17.2857

Other Questions
Select the correct answer.What is the tone of the second paragraph?From inaugural address Drag numbers to the table so it shows a proportional relationship between x and y. A rope, under a tension of 221 N and fixed at both ends, oscillates in a second-harmonic standing wave pattern. The displacement of the rope is given by y = (0.10 m)(sin x/2) sin 12t, where x = 0 at one end of the rope, x is in meters, and t is in seconds. What are: a. the length of the rope. b. the speed of the waves on the ropec. the mass of the roped. If the rope oscillates in a third-harmonic standing wave pattern, what will be the period of oscillation. When your vehicle turns a corner, the tracks made by the rear tires are always: a) Outside of those made by your front tires b) Inside of those made by your front tires c) On top of those made by your front tires d) None are correct Solve this equation log3X + log3(x-6) = log3 7 WILL GIVE BRAINLIEST AND 20 POINTS!PLEASE SHOW WORK1f={(2,5),(3,1),(1,1)} and g={(1,1),(1,2),(4,1),(3,1)}Find (f+g)(1). the prime mover of inspiration is the blank during normal quiet breathing expiration is a passive process as this muscle relaxes into its original dome shape. provide conditions when expiration becomes an active process or forced. explain True/False Questions - one attempt tor each questionIf f is a decreasing function on an interval, then f'(x) > 0 on that interval.TrueFalseSubmit Question Determine the intercepts of the line Y -,-X-,- Four graphs are shown below:Scatter plot A shown with data points that move in an upward direction and are located at 1 and 0.3, 2 and 1, 3 and 2, 4.1 and 4, 5.2 and 6.1, 5.9 and 9.5. Additional points are located at 4.6 and 5, 5.8 and 7.4, 5.2 and 7.1. Scatter plot B is shown with data points that move in an upward direction and are located at 1 and 3, 2 and 4, 3 and 5, 4 and 6, 5 and 6, 6, and 7, 7 and 8, 8 and 9. Scatter plot C is shown with data points that move in a downward direction and are located at 1 and 8.7, 4 and 5.6, 5 and 4.3, and 6 and 0.5. Additional points are located at 5.9 and 1.5, 5.5 and 3.5. Scatter plot D is shown with data points that move in a downward direction and are located at 0 and 7, 1 and 6, 2, and 5, 3 and 4, 4 and 3, 5 and 4, 6, and 5.Which graph represents a negative linear association between x and y? Graph A Graph B Graph C Graph D A 10 kg stone is lifted to a height of 2 meters. What is the potential energy at this position?(Note: PE = mgh; g = 9.8 m/s2, J = Joules)A. 5 JoulesB. 49 JoulesC. 196 JoulesD. 20 Joules What are the benefits of giving a persuasive speech rather than publishing an article? Can I get the answer for those A major component of gasoline is octane when octane is burned in air it chemically reacts with oxygen to produce carbon dioxide and water what mass of carbon dioxide is produced by the reaction of oxygen In the image below, what molecule is being released by cellular respirationand used in photosynthesis?A. 02B. CO2C. H20D. C6H1206 What does the second part of declaration contain "A twenty-two," [Rainsford] remarked. "That's odd. It must have been a fairly large animal too. The hunter had his nerve with him to tackle it with a light gun. It's clear that the brute put up a fight. I suppose the first three shots I heard was when the hunter flushed his quarry and wounded it. The last shot was when he trailed it here and finished it."He examined the ground closely and found what he had hoped to find the print of hunting boots. They pointed along the cliff in the direction he had been going. Eagerly he hurried along, now slipping on a rotten log or a loose stone, but making headway; night was beginning to settle down on the island. "The Most Dangerous Game,"Richard ConnellWhat can be concluded about Rainsford from his dialogue? What does Rainsford say that indicates he admires the hunter? What can be concluded about Rainsford from the narration? What word does the narrator use that helps the reader draw this conclusion? Which sentence best describes one effect of the poets use of figurative language in this excerpt? Suppose that you and a friend are playing cards and you decide to make a friendly wager. The bet is that you will draw two cards without replacement from a standard deck. If both cards are diamonds, your friend will pay you $296. Otherwise, you have to pay your friend $17.What is the expected value of your bet? What academic subset of oceanography studies seafloor features and the processes that form them?