Suppose a rocket is fired vertically upward from the surface of the earth with one-half of the esacpe speed. How far from the center of the earth will it reach vefore it begins to fall back?
(let g = 9.8 m/s^2 and Re = 6370 km)
A. 1.3 * 104 km
B. 8.5 * 103 km
C. 9.6 * 103 km
D. 2.6 * 104 km
E. 1.9 * 104 km
The correct answer: B.
I do not understand why I am not getting the correct answer.

Answers

Answer 1

The distance before it falls back to the earth is 8.5 * 103 km. Option B

What is the escape velocity?

We know that the escape velocity has to do with the velocity that has to be supplied to a material so that the material can be able to escape from the earth's gravitational pull. Let us recall that the whole earth is a large gravitational field. If we throw an object up then the object would have to certainly fall doen to the ground under the influence of gravity.

It is therefore clear that gravity is the force that draws any object that  goes upwards down back to the ground. Given that we have been told here that the speed is  one-half of the escape speed, then then the magnitude of the speed is 5590.3 m/s.

Given that;

v^2 = u^2 - 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Then;

u^2 = 2gh

h = u^2/2g

h = ( 5590.3)^2/2 * 9.8

=  8.5 * 103 km

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Related Questions

what should be the value of 'x' such that the mass то exerts a force of mg on the inclined surface at P. (N=mg)​

Answers

The value of 'x' such that the mass то exerts a force of mg on the inclined surface at P. (N=mg)​ is given by

x = N / (mg cos θ)

What is value of 'x'?

Generally, To determine the value of 'x', you need to know the angle of inclination of the surface and the mass of the object. The force of gravity (N) acting on the object is equal to the mass of the object (m) multiplied by the acceleration due to gravity (g). The force of gravity is also equal to the normal force (N) exerted by the surface on the object, which is perpendicular to the surface.

If the surface is inclined at an angle θ with respect to the horizontal, the normal force will be equal to the component of the force of gravity along the surface. This component can be calculated using the formula N = mg cos θ, where θ is the angle of inclination and m is the mass of the object.

Therefore, to determine the value of 'x', you need to solve the equation N = mg cos θ for 'x'. To do this, you can rearrange the equation to solve for x:

x = N / (mg cos θ)

Substituting the values of N, m, and θ into this equation will give you the value of 'x' that you are looking for.

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if an object producing sound is moving away from you, you would observe a wavelength than an object moving toward you. group of answer choices

Answers

If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.

What is the Doppler effect?

The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.

The equation of the Doppler effect is

f₀ = [(v ± v₀)/(v ± vs)] × fs

Where

f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound waves

Note:

v₀ (+) if the observer moves closer to the sound source.vs (+) if the sound source moves away from the observer.

When an object producing sound is moving away from us, the frequency of the sound we heard changed.

Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).

With the Doppler's effect, we get

f₀ = [(v+0) / (v+vs)] × fs

f₀/fs = v/(v+vs)

v < v+vs

f₀ < fs

The frequency of sound we heard is lower that the actual frequency.

The wavelength is inversely proportional to the frequency. It is described in the equation:

λ = c/f

It means that the lower the frequency, the longer the wavelength.

Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.

Here is the group of answer choices:

(a) Band width

(b) Doppler's effect

(c) Sound refraction

(d) Vibrations

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aphasia
Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience:

Answers

Due to an automobile accident, Jenny suffered damage to her cerebral cortex in Broca's area. Jenny is most likely to experience: aphasia.

Aphasia is the inability to understand or form language due to damage to certain areas of the brain The main causes are stroke and head trauma. Although the prevalence is difficult to determine, aphasia due to stroke is estimated at 0.1-0.4% in the Global North. Aphasia can also be the result of a brain tumor, brain infection, or neurodegenerative disease (such as dementia).

To be diagnosed with aphasia, communication after an acquired brain injury Speech or language must be significantly impaired in one (or more) of the four aspects of Alternatively, in the case of progressive aphasia, it must have decreased significantly over a short period of time. The four dimensions of communication are auditory comprehension, verbal expression, reading and writing, and functional communication.

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What is the Force of Gravity acting on the object in the diagram?

Answers

The force of gravity acting on the 23 Kg object in the diagram is 225.4 N

How do I determine the force of gravity?

The force of gravity is defined as follow:

Force of gravity (F) = mass (m) × acceleration due to gravity (g)

Using the above formula, we can easily obtain the force gravity acting on the 23 Kg object. This is shown below:

Mass (m) = 23 KilogramsAcceleration due to gravity (g) = 9.8 m/s²Force of gravity (F) =?

Force of gravity (F) = mass (m) × acceleration due to gravity (g)

Force of gravity = 23 Kg × 9.8 m/s²

Force of gravity = 225.4 N

Thus, from the calculation made above, we can conclude that the gravitaional force is 225.4 N

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Which of the following is an important difference between the infinite square-well potential and the finite square-well potential?a. The number of energy levels is limited in the infinite square-well potential but not limited in the finite square-well potential.b. The infinite square-well potential utilizes Schrödinger's equation to describe particle motion while the finite square-well potential does not.c. The energy levels are quantized only in the finite square-well potential.d. Particles can exist in classically forbidden regions outside the finite square-well potential.e. Only the energy levels in the finite square-well potential depend on Planck's constant.

Answers

Particles can exist in classically forbidden regions outside the finite square-well potential.

The correct option is D.

What if Planck's constant was zero?

In the absence of quantum effects, everything would be continuous, smooth, and completely predictable in the Newtonian sense. However, we may not be here to get bored with this if Planck's constant were 0.

What use does Planck's constant serve?

At the atomic scale, the behavior of both particles and waves is described by Planck's constant. One of the factors that led to the creation of quantum mechanics is Planck's constant. It was a surprise when those boundaries also turned to represent the limits where known rules of physics applied since the Planck scaled was developed as an universal set of units.

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find the amplitude, frequency, and period of motion for an object vibrating at the end of a horizontal spring if the equation for its position as a function of time is the following.

Answers

The amplitude is 0.25s.

Calculation:

Amplitude = A = 0.225 m

Angular frequency = w = 8π rad/s.

Frequency = f = w/2π = 8π/2πHZ = 4 HZ

Time period = T = 1/f = (1/4)s = 0.25s.

The maximum displacement or distance traveled by a point on an oscillating body or shaft, measured from the equilibrium position. This corresponds to half the length of the vibration path. Amplitude difference between a rest position and maximum shaft deflection.

Frequency The number of waves passing a particular point per second. Duration  How long it takes for a wave cycle to complete. Sound wave amplitude is a measure of wave height. The amplitude of a sound wave can be defined as the magnitude or loudness of the maximum displacement from the average position of the vibrating particles in the medium when the sound was produced.

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apply the loop rule to loop 2 (the smaller loop on the right). sum the voltage changes across each circuit element around this loop going in the direction of the arrow. remember that the current meter is ideal.express the voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.

Answers

The voltage drops in terms of vb , i2 , i3 , the given resistances, and any other given quantities.ΣΔV = 0 = I3 ⋅ R3 - I2 ⋅ R2.

When applying Kirchhoff's second rule the loop rule we need to identify closed loops and decide whether to loop clockwise or counterclockwise. For example, in Figure 3 the loop was traversed in the same direction as the current.

Loop 1 is the full loop and Loop 2 is the small loop on the right. To apply the loop rule, add all those voltage changes. Kirchhoff's Second Law, also known as Kirchhoff's Voltage Law states that the sum of all voltages around the closed loop of any circuit must be zero. This is a result of charge conservation and energy conservation.

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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3

Answers

To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo

[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]

The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]

The given parameters:

- Applied force on the spring [tex]$=F$[/tex]

- Extension of the spring [tex]$=x_0$[/tex]

The work done by stretching the spring to the given distance is calculated as follows;

[tex]W=\frac{k x_0}{3}[/tex]

[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]

Thus, the work done by stretching the spring to the given distance is

[tex]W=\frac{k x_0}{3}[/tex]

measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

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five coins are stacked in the smooth plastic container. if each coin weighs 0.0235 lb, determine the normal reactions of the bottom coin on the container at points a and b.

Answers

The smooth plastic jar has five pennies placed inside of it. The normal reactions of the bottom coin on the container at locations a and b will be 0.0705 lb and 0.1175 lb respectively if each coin weighs 0.0235 lb.

What does normal force mean?

A contact force, the normal force is often referred to as the normal reaction force. On two surfaces that are not attached to one another, a normal force cannot be applied.

What normal force is present during deceleration?

The body's weight determines the usual deceleration force. A body's position relative to the ground tells us when it is about to fall. The normal force is the portion of a force that is perpendicular to any contact surface.

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what is the length of the y component shown below?

Answers

The length of the y component shown is C. 2.0.

How to find the length ?

We are given the angle of the vector, and the length of one of the components of the vetor. Given the angle we have, the available component is the hypotenuse. The y component that we are to find, will then be the opposite or perpendicular component.

To solve for the length of the y - component therefore, the useful operation would be the Sin function.

The length of the y - component would be:
Sin 42 ° = Opposite / Hypotenuse

Sin 42 ° = y component / Hypotenuse

y - component = Sin 42 ° x Hypotenuse

y - component = Sin 42 ° x 3

y - component = 0. 6691 x 3

y - component = 2. 0

In conclusion, the y - component is 2.0.

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Full question is:

What is the length of the y-component of the vector shown below?

A. 2.2 B. 3 c. 2.0 D. 2.7

for the circuit below all values are rms with a source frequency of 60 hertz. the generator impedance is negligible (0 w). calculate the value of ib and and determine the value of vb-n. now, calculate the rms values of apparent, real and reactive power of zb. (show units for all)

Answers

The reactive power of the branch (Qb) can be calculated from its voltage and current 676.16 VA.

What is reactive power?

Reactive power is the power in an AC circuit that is required to establish and maintain a voltage across a load. It is associated with the storage and release of energy in the form of electric and magnetic fields. Reactive power does not contribute to the actual work output of a system and is measured in Volt-amperes reactive (VARs). Power factor is a measure of reactive power relative to the total power in a system.

Source frequency = 60 Hz
Generator impedance = 0 W
Circuit:
Vg = 170 V
R1 = 10 Ω
R2 = 20 Ω
Zb = 20 + j10 Ω

The current flowing through the generator (Ig) and the branch (Ib) can be calculated from Ohm's Law:
Ig = Vg/R1 + Vg/R2 = 170/10 + 170/20 = 17 A
Ib = Ig - Vg/Zb = 17 - 170/(20 + j10) = 17 - 16.4 + j4.4 = 0.6 + j4.4 A
Since Ib is a complex number, we can find its magnitude (|Ib|) and angle (θ):
|Ib| = √(0.6² + 4.4²) = 4.46 A
θ = tan⁻¹(4.4/0.6) = 80.16°
The voltage across the branch (Vb-n) can be calculated using Ohm's Law:
Vb-n = Ib × Zb = (0.6 + j4.4) × (20 + j10) = -8.4 + j74.4 V
The apparent power of the branch (Sb) can be calculated from its voltage and current:
Sb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = -45.48 + j367.04 VA
The real power of the branch (Pb) can be calculated from its voltage and current:
Pb = Vb-n × Ib = (-8.4 + j74.4) × (0.6 + j4.4) = -45.48 - j367.04 W
The reactive power of the branch (Qb) can be calculated from its voltage and current:
Qb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = 676.16 VA

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One of the most controversial ideas to come out of instinct theories of aggression was Lorenz's proposal that society provide acceptable ways of permitting , or the process of discharging built-up aggressive energy.

Answers

The general instinct hypothesis, which contends that people are physiologically predisposed to or possess inclinations for violent behaviours, is known as the instinct theory of aggression in psychology.

This theory is more focused on aggression. The instinct theory of aggressiveness holds that human aggression is akin to sex and hunger, and that it can only be regulated rather than eradicated.

In an effort to understand why we become aggressive and whether that behaviours can be altered, psychologists have developed three primary theories of aggression. Although many hypotheses have been put out, these three have proven most reliable and are crucial to comprehending the origins of violence. These hypotheses comprise as,

Adversity theory based on instinctTheory of Frustration and AggressionTheory of Social Learning

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(1) A table tennis ball is dropped
onto the floor from a height of
4m and it rebounds to a height of
3m. If the time of contact with the floor is 0.01s, what is the magnitude and direction of the acceleration during the contact.

Answers

Answer:

Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1

:. acceleration, a=v2+v1Δt ..(i)

When body falls from height h1,

then u=o,v1,a=gandS=h1

As, v21=u2+2aS,

:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1

Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2

As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2

Putting values in (i) we get,

a=2–√gh2+2–√gh1Δt)

a=2–√×9.8×3+2–√×9.8×40.01

= 1652m/s2.

Explanation:

which of the following sequences lists methods for determining distance in the correct order from nearest to farthest?

Answers

Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.

Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.

Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.

Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.

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based on the graphic, in what part of the electromagnetic spectrum does vegetation have the strongest response?

Answers

Between 400 nm and 700 nm of the electromagnetic spectrum, vegetation has the strongest response.

The electromagnetic spectrum travels in waves and spans an extensive spectrum from very long radio waves to very brief gamma rays. The human eye can simplest come across only a small portion of this spectrum called visible light.

In order from maximum to lowest power, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible mild, infrared radiation, and radio waves.

In a tumbler, the purple mild travels the fastest, and the violet light travels the slowest of all seven hues. Velocity and wavelength are without delay proportional.

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A uniform plane wave with parallel polarization is propagating in a lossless dielectric medium (l is € 1), and is incident obliquely onto a plane boundary with another lossless dielectric medium (u 2, E 2). (30%) (a) Derive the Snell's laws of reflection and refraction in terms of the refractive indices and angles. (b) Derive the general expressions for the reflection and the transmission coefficients of the EM field. Find such expressions in terms of the refractive indices if both media are nonmagnetic, i.e., M F M 240. (c) Derive the general expression for the Brewster angle. Find such an expression in terms of the refractive indices if both media are nonmagnetic. (d) Prove that, under the condition of no reflection, the sum of the Brewster angle and the angle of refraction is 90° if both media are nonmagnetic. (e) For total reflection to occur, find the condition for the medium property and the critical angle.

Answers

Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2

The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.

The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.

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