Suppose that 17 inches of wire costs 68 cents,
At the same rate, how much (in cents) will 39 inches of wire cost?
cents
?

Answer:

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 5,500 and standard deviation 1,000.

This means that [tex]\mu = 5500, \sigma = 1000[/tex]

What is the probability that the call center will get between 4,800 and 5,000 calls in a day?

This is the p-value of Z when X = 5000 subtracted by the p-value of Z when X = 4800. So

X = 5000

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5000 - 5500}{1000}[/tex]

[tex]Z = -0.5[/tex]

[tex]Z = -0.5[/tex] has a p-value of 0.3085.

X = 4800

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4800 - 5500}{1000}[/tex]

[tex]Z = -0.7[/tex]

[tex]Z = -0.7[/tex] has a p-value of 0.2420.

0.3085 - 0.2420 = 0.0665

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

Answer:

The correct answer is "[tex]2.633< \sigma < 4.480[/tex]".

Step-by-step explanation:

Given:

n = 21

s = 3.3

c = 0.9

now,

[tex]df = n-1[/tex]

    [tex]=20[/tex]

⇒ [tex]x^2_{\frac{\alpha}{2}, n-1 }[/tex] = [tex]x^2_{\frac{0.9}{2}, 21-1 }[/tex]

                  = [tex]31.410[/tex]

⇒ [tex]x^2_{1-\frac{\alpha}{2}, n-1 }[/tex] = [tex]10.851[/tex]

hence,

The 90% Confidence interval will be:

= [tex]\sqrt{\frac{(n-1)s^2}{x^2_{\frac{\alpha}{2}, n-1 }} } < \sigma < \sqrt{\frac{(n-1)s^2}{x^2_{1-\frac{\alpha}{2}, n-1 }}[/tex]

= [tex]\sqrt{\frac{(21-1)3.3^2}{31.410} } < \sigma < \sqrt{\frac{(21.1)3.3^2}{10.851} }[/tex]

= [tex]\sqrt{\frac{20\times 3.3^2}{31.410} } < \sigma < \sqrt{\frac{20\times 3.3^2}{10.851} }[/tex]

= [tex]2.633< \sigma < 4.480[/tex]

Answer:

B

Step-by-step explanation:

Given

[tex]\sqrt{ab}[/tex] = [tex]\sqrt{bc}[/tex] ( square both sides )

ab = bc ( divide both sides by b ) , then

a = c

Given

[tex]\sqrt{ac}[/tex] = [tex]\sqrt{4c^4}[/tex] ( square both sides )

ac = 4[tex]c^{4}[/tex] ( but a = c) , so

4[tex]c^{4}[/tex] = c² ( subtract c² from both sides )

4[tex]c^{4}[/tex] - c² = 0 ← factor out c² from each term on the left side

c²(4c² - 1) = 0 ← 4c² - 1 is a difference of squares

c²(2c - 1)(2c + 1) = 0

Equate each factor to zero and solve for x

c² = 0 ⇒ c = 0

2c - 1 = 0 ⇒ 2c = 1 ⇒ c = [tex]\frac{1}{2}[/tex]

2c + 1 = 0 ⇒ 2c = - 1 ⇒ c = - [tex]\frac{1}{2}[/tex]

But c > 0 , then c = [tex]\frac{1}{2}[/tex] → B

Answer:

3y-a

3.3-7

9-7

2

Step-by-step explanation:

first we have to do multiply by replacing the value of y and the subtract by using the value of a.

Hope this will be helpful for you

9514 1404 393

Answer:

  87.5 km

Step-by-step explanation:

Actual distance is 250000×35 cm = 87.5×10^5 cm = 87.5 km

_____

There are 100 cm in 1 m, and 1000 m in 1 km, so 100,000 cm = 10^5 cm in 1 km

Answer:

b) By analyzing data, we may be able to identify connections and relationships in our data.

Step-by-step explanation:

Answer:

the answer is option D because it cant be division or multiplication and minus does not work

Answer:

log 1/9 * log k

Step-by-step explanation:

[tex]\frac{1}{9} /k[/tex] = 1/9 * k/1 = 1/9 * k

Answer:

Choice A.

Step-by-step explanation:

Every other choice has multiple of the same x-values that have different corresponding y-values.

Answer:

x=60

Step-by-step explanation:

There are different ways to find x but this is what I found easiest.

To solve first note that AOD and CFB are vertical angles; this means that they are congruent. AOD consists of two angles with the measurements of 90 and x. CFB consists of two angles with the measurements of 30 and 2x. So, to find x set add the adjacent angles and set them equal to the other pair of angles. The equation would be [tex]90+x=30+2x[/tex]. First, subtract x from both sides; this makes the equation [tex]90=30+x[/tex]. Then, subtract 30 from both sides. This gives the final answer, x=60.

Answer:

(-2, 13) (-1,8) (0, 5) (1, 4) (2, 5) (3, 8)

(2.4 , 6) or (-0.4, 6)

Step-by-step explanation:

Graph y = 6 on top of y = [tex]x^{2}[/tex] -2x + 5 and use the points where the two lines meet.

Answer:

0

Step-by-step explanation:

Hello!

[tex]\bf [ (-10) + (-2) ] = 12 [/tex]

[tex]\bf [ (-10) - 2 ] = 12 [/tex]

[tex]\bf -10 - 2 = 12 [/tex]

[tex]\bf -12 ≠ 12 [/tex]

Answer: Wrong

Good luck! :)

Answer:000

Step-by-step explanation:000

Answer:

(-2/3, -13/3)

Step-by-step explanation:

Given the expressions;

[tex]y= 2x - 3\\y = (\frac{1}{2} )x - 4[/tex]

Equating both expressions;

[tex]y=y\\2x-3=\frac{1}{2}x-4\\[/tex]

Collect the like terms:

[tex]2x-\frac{1}{2}x=-4+3\\\frac{3x}{2}=-1\\3x=-2\\x=\frac{-2}{3}[/tex]

Substitute [tex]x=\frac{-2}{3}[/tex] into any of the expressions to get 'y'

[tex]Recall\ y= 2x-3\\y=2(\frac{-2}{3} )-3\\y=\frac{-4}{3}-3\\y=\frac{-4-9}{3} \\y=\frac{-13}{3}[/tex]

Hence the solution to the equation is (-2/3, -13/3)

Answer:

The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Step-by-step explanation:

We are given that

Standard deviation, [tex]\sigma=0.2[/tex]ounces

We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.

[tex]P(x\geq 10)=0.99[/tex]

Assume the bag weight distribution is bell-shaped

Therefore,

[tex]P(\frac{x-\mu}{\sigma}\geq 10)=0.99[/tex]

We know that

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Using the value of z

Now,

[tex]\frac{10-\mu}{0.2}=0.99[/tex]

[tex]10-\mu=0.99\times 0.2[/tex]

[tex]\mu=10-0.99\times 0.2[/tex]

[tex]\mu=9.802[/tex]

Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802

Answer:

y = 3.6

Step-by-step explanation:

Since the triangles are similar, we can write the following proportion:

[tex]\frac{y}{6.3} = \frac{2.4}{4.2} = \frac{2.8}{x}[/tex]

We don't need the fraction on the left because it is not necessary to solve for y. Instead, we can simplify the rest:

[tex]\frac{y}{6.3} = \frac{2.4}{4.2}[/tex]

[tex]\frac{y}{6.3} = \frac{0.4}{0.7}[/tex]

Now, we can cross-multiply:

[tex]0.7y = 6.3 * 0.4[/tex]

[tex]0.7y = 2.52[/tex]

[tex]y = 3.6[/tex]

Given:

The length of both triangle are in the same ratio,

2.4:2.8:y = 4.2:x:6.3

To find:

The value of 'y'

Steps:

Since 2.4 : y = 4.2 : 6.3, we can find the value of 'y'

    2.4/y = 4.2/6.3

2.4 * 6.3 = 4.2 * y

     15.12 = 4.2y

15.12/4.2 = y

        3.6 = y

            y = 3.6

Therefore, the value of y is 3.6

Happy to help :)

If you want help, feel free to ask

Answer:

Step-by-step explanation:

7/18=7/18

it cant be divided agian

1/3=1/3

it cant be divded agian

1/5=1/5

it cant be divded agian

1/10=1/10

it cant be divded agian

3 1/2=3/2

2 5/9 =10/9

i am not sure if this is what you wanted ...

Answer:

0.375 = 38%

Step-by-step explanation:

Just divide 3 from 8 and that will give you 0.375

Then you round that to the nearest  one which is 38 and

that will get your percentage

Answer: 37.5%

Step-by-step explanation: I just divided 3 by 8 then once I got my answer I moved the decimal point over to the right by 2.

Answer:

-30u+20w+10

Step-by-step explanation:

multiple each term inside the parenthesis by -5. remember negative times negative = positive

Answer:

1/64

Step-by-step explanation:

4^ (-11/3) ÷ 4 ^ (-2/3)

We know a^b ÷a^c = a^(b-c)

4 ^(-11/3 - - 2/3)

4^(-11/3 +2/3)

4^(-9/3)

4^ -3

We know a^-b = 1/a^b

1/4^3

1/64

Answer:

A proportion equation is something like:

[tex]\frac{A}{B} = \frac{x}{C}[/tex]

Where A, B, and C are known numbers, and we want to find the value of x.

Now we want two cases where in one of the numerators we have a mixed number, where a mixed number is something like:

1 and 1/3

which actually should be written as:

1 + 1/3

1) a random problem can be:

[tex]\frac{1 + 1/3}{4} = \frac{x}{5}[/tex]

We can see that the numerator on the left is a mixed number.

First, let's rewrite the numerator then:

1 + 1/3

we need to have the same denominator in both numbers, so we can multiply and divide by 3 the number 1:

(3/3)*1 + 1/3

3/3 + 1/3 = 4/3

now we can rewrite our equation as:

[tex]\frac{4/3}{4} = \frac{x}{5}[/tex]

now we can solve this:

[tex]\frac{4/3}{4} = \frac{4}{3*4} = \frac{x}{5} \\\\\frac{1}{3} = \frac{x}{5}[/tex]

now we can multiply both sides by 5 to get:

[tex]\frac{5}{3} = x[/tex]

Now let's look at another example, this time we will have the variable x in the denominator:

[tex]\frac{7}{12} = \frac{3 + 4/7}{x}[/tex]

We can see that we have a mixed number in one numerator.

Let's rewrite that number as a fraction:

3 + 4/7

let's multiply and divide the 3 by 7.

(7/7)*3 + 4/7

21/7 + 4/7

25/7

Then we can rewrite our equation as

[tex]\frac{7}{12} = \frac{25/7}{x}[/tex]

Now we can multiply both sides by x to get:

[tex]\frac{7}{12}*x = \frac{25}{7}[/tex]

Now we need to multiply both sides by (12/7) to get:

[tex]x = \frac{25}{7}*\frac{12}{7} = 300/49[/tex]

Answer:

Step-by-step explanation:

width = x

length= x + 5

a)  x + 5

b) x * (x+5) = 300

x^2 + 5x = 300

x^2 + 5x - 300 = 0

Δ = 25 + 1200 = 1225

width = (-5 + 35)/2 = 15 cm

lenght = 15 + 5 = 20 cm

Answer:

a) length = x + 5  

b) [tex]x^{2}[/tex] + 5x - 300 = 0

Step-by-step explanation:

x = width

x + 5 = length

(x)(x + 5) = 300

[tex]x^{2}[/tex] + 5x = 300

[tex]x^{2}[/tex] + 5x - 300 = 0

(x+20)(x-15)

x = -20 or x = 15  ( disregard the -20. measurements can't be negative)

width = 15

length = x+ 5 =  15+5 = 20

Step-by-step explanation:

sorry bestie but it hard to find

Answer:

He must survey 123 adults.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

Assume that a recent survey suggests that about 87​% of adults have heard of the brand.

This means that [tex]\pi = 0.87[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

How many adults must he survey in order to be 90​% confident that his estimate is within five percentage points of the true population​ percentage?

This is n for which M = 0.05. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.05 = 1.645\sqrt{\frac{0.87*0.13}{n}}[/tex]

[tex]0.05\sqrt{n} = 1.645\sqrt{0.87*0.13}[/tex]

[tex]\sqrt{n} = \frac{1.645\sqrt{0.87*0.13}}{0.05}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645\sqrt{0.87*0.13}}{0.05})^2[/tex]

[tex]n = 122.4[/tex]

Rounding up:

He must survey 123 adults.

Answer:

-1/4 is the least, 0.75 is second, and 1 1/2 is the greatest

Step-by-step explanation:

-1/4 is the least already because it is negative.

1 1/2 is really 1.5 so now compare 0.75 and 1.5.

1.5 is bigger therefore the order  is :

-1/4, 0.75, 1 1/2

Answer:

u = 26

v = 13√3

it's 30-60-90 triangle

Answer:

1/4

Step-by-step explanation:

that is the answer

I found the constant which was -3

a = 1/4

b=-1

Answer:

the value of a in the function's equation is 1/4

Step-by-step explanation:

Plato answer

Step-by-step explanation:

Given:

[tex]\vec{\textbf{F}}(x, y, z) = ye^z\hat{\textbf{i}} + xe^z\hat{\textbf{j}} + xye^z\hat{\textbf{k}}[/tex]

A vector field is conservative if

[tex]\vec{\nabla}\textbf{×}\vec{\text{F}} = 0[/tex]

Looking at the components,

[tex]\left(\vec{\nabla}\textbf{×}\vec{\text{F}}\right)_x = \left(\dfrac{\partial F_z}{\partial y} - \dfrac{\partial F_y}{\partial z}\right)_x[/tex]

[tex]= xe^z - ye^z \neq 0[/tex]

Since the x- component is not equal to zero, then the field is not conservative so there is no scalar potential [tex]\phi[/tex].