Suppose you are in mission control on the moon, in charge of launching a moon-orbiting communications satellite.
a) 2430 N.
b) 1.84 x 10^6 m.
c) F = m * v^2 / r
d) 2157 m/s
e) 2.87 x 10^4 s
f)1.17 x 10^-3 m/s^2
What is the weight of the statlite?a. The weight of the satellite near the surface of the moon would be the mass of the satellite multiplied by the acceleration due to gravity on the moon. The acceleration due to gravity on the moon is about 1.62 m/s^2, so the weight of the satellite would be
1500 kg * 1.62 m/s^2 = 2430 N.
b. The radius of the orbit of the satellite would be the distance from the center of the moon to the altitude of the satellite. The radius of the moon is 1.74 x 10^6 m, so the radius of the orbit of the satellite would be
1.74 x 10^6 m + 100 km = 1.84 x 10^6 m.
c. The centripetal force is the force that is required to keep an object in circular motion. It is equal to the mass of the object times its velocity squared, divided by the radius of its orbit. To find the centripetal force on the satellite, we need to know its velocity. We can find this using the equation for the centripetal force, which is:
F = m * v^2 / r
where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the orbit.
d. To find the required orbital velocity for the satellite, we can rearrange the equation for the centripetal force to solve for v:
v = sqrt(F * r / m)
Plugging in the values, we get:
v = sqrt(2430 N * 1.84 x 10^6 m / 1500 kg) = 2157 m/s
e. The orbital period is the time it takes for an object to complete one orbit. It is equal to the circumference of the orbit divided by the velocity of the object. The circumference of the orbit is 2 * pi * r, where r is the radius of the orbit. The velocity of the object is the orbital velocity we calculated above. Plugging these values into the equation, we get:
T = 2 * pi * r / v
Plugging in the values, we get:
T = 2 * pi * 1.84 x 10^6 m / 2157 m/s = 2.87 x 10^4 s
f. Yes, the satellite is accelerating while in orbit. The direction of the acceleration is towards the center of the orbit, and the magnitude of the acceleration is the centripetal acceleration, which can be calculated using the equation:
a = v^2 / r
Plugging in the values, we get:
a = 2157 m/s^2 / 1.84 x 10^6 m = 1.17 x 10^-3 m/s^2
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A job is done slowly, and an identical job is done quickly. Both jobs require the same amount of.... but different amounts of...
Answer:
work, power
Explanation:
Work = Fnet x distance
Work is NOT dependent on time
Power = Work ÷ time
The slower the work is done, the higher the power. The faster the same amount of work is done, the lower the power. Power, with work constant, is inversely proportional to time.
The linear density of a string is 1.6 10-4 kg/m. A transverse wave on the string is described by the equation y = (0.021 m) sin[(2.7 m-1)x + (20 s-1)t].what is the wave speed?what is the tension in the string?
The required wave speed and tension in the string are 15 m/s , 0.036 N respectively.
What is speed?Speed is characterized as. The pace of progress of position of an item toward any path. Speed is estimated as the proportion of distance to the time in which the distance was covered. Speed is a scalar amount as it has just course and no extent.
According to question:(a) The wave speed is given by v=λ/T=ω/k,
where λ is the frequency, T is the period ω is the precise recurrence (2π/T), and k is the rakish wave number(2π/λ).
The displacement has the structure y=y sin(kx+ωt), so 4k=2.0m
furthermore, ω=30 rad/s.
Hence v=(30 rad/s)/(2.0m)=15 m/s.
b) Since the wave speed is given by v= τ/μ
, where τ is the pressure in the string and μ is the straight mass thickness of the string, the strain is
τ=μv =(1.6×10 kg/m)(15 m/s) =0.036 N.
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again, in just a couple of sentences, briefly consider the reason for visible differences between one wavelength image's contents versus another's.
Understanding an object's structure and function requires observation at a variety of wavelengths.
We perceive at different wavelengths for what reason?This is due to the fact that we have just lately been able to view the complete electromagnetic spectrum of the universe.There are objects in our universe that emit a wide variety of radiation having wavelengths either being too short or long for human eyes to see.
Why do astronomers capture photos using different wavelengths of light?Astronomers can learn something distinctive about an item by examining its light at various wavelengths.Astronomers may see "the broad picture" of what's actually happening with that object by examining all available wavelengths and developing models that account for everything those photographs show.
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Question From what activity can you be sure that athletes find great utility?
Composing music
Raising children
Playing sports
Reading books
Playing sport is the activity in which you can be sure that athletes find great utility and is therefore denoted as option C.
Who is an Athlete?This is referred to a person who competes in one or more sports such as soccer, basketball etc that involve physical strength, speed, or endurance etc.
Therefore playing sports by an athlete will lead to an increase in utility as a result of them developing various skills and composure from it in the form of endurance, strength etc and various positions on the field which isn't applicable in reading books or composing music and is therefore the reason why it was chosen as the correct choice in this scenario.
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a concentration of 400 ppm is the safe soil lead concentration threshold. the scientist used method a and found the soil sample had a lead concentration of 1358 ppm. write a conclusion about the lead concentrations in this sample of soil. in your conclusion include one recommendation from the table.
The lead pollution can be remediated by the appllication of the approppiate reagents.
What is the recommendation?We know that we need to always consider the threshold concentration of pollution as we are looking at the safety of the environment
Now we are told that the safe concentration of the lead must not be more than 400 ppm. Above that concentration, the effects may be quiet fatal.
There should be spirited attempts to remediate the soil by the use different methods so that the soil can become good again for the growing of crops.
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If a cable originates inside one building and leaves the building, the landlord loses control of that cable. T or F?
It is true to say that If a cable originates inside one building and leaves the building, the landlord loses control of that cable.
Cable originating from one building to another building will have total control by the landlord from which the cable have passed. Since cable passes from one building to another building in that case some part of cable is not inside the building due to that control over the cable is distributed between more than one type of landlords .Worms can be spread through means other than direct network .Now, when it passed between the two building, in that case if one landlord did some changes in some part of cable then that change will not be controlled by the landlord who live in other building.
Hence, given statement is true.
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after extinguishing a fire on the first floor of a two-story balloon-framed house, the best action for crews is to immediately open the walls and check for fire in the:
After extinguishing a fire on the first floor of a two-story balloon-framed house, the best action for crews is to immediately open the walls and check for fire in the basement, second floor, and attic.
The vertical struts of the outer wall are continuous from the foundation to the roof with a balloon frame structure. When the roof collapses into a structure, it can provide a watertight cover over a buried fire. Heavy wood is more stable than lightweight structures in fire conditions.
Marion of the building is surrounded by balloons, from the foundation to the eaves line he extends upwards more than two stories. A mansard or mansard roof is his four-sided gambrel-style hipped roof characterized by his two slopes on either side, the lower slope pierced with dormer windows and angled more steeply than the upper.
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a man who is 6 feet tall is walking away from a lamp post at a rate of 5 feet per minute the lamp post is 20 feet tall the person casts a shadow on the ground in from of them
(a) The growing rate of shadow when the person is 30 ft from the lamp post is 15/7 ft/m
(b) The moving rate of the tip of the shadow when the person is 30 ft from the lamp post is 50/7 ft/m
Given,
Height of the man = 6 ft
Height of the lamp post = 20 ft
[tex]\frac{dx}{dt} =5 ft/m[/tex]
Let,
The distance between the base of lamp and the man = x
From the geometry,
[tex]\frac{6}{20} =\frac{y}{x+y}[/tex]
[tex]6(x+y) = 20y[/tex]
[tex]3x=7y[/tex] .......................(1)
And,
[tex]6(\frac{dx}{dy} )=14(\frac{dy}{dt} )[/tex]
[tex]\frac{dy}{dt}=\frac{15}{7}[/tex]
∵ [tex]\frac{dx}{dt} =5 ft/m[/tex]
∴ [tex]\frac{dx}{dt}+\frac{dy}{dt} =5+\frac{15}{7}[/tex][tex]=\frac{50}{7}[/tex]
Hence,
(a) The growing rate of shadow when the person is 30 ft from the lamp post is 15/7 ft/m
(b) The moving rate of the tip of the shadow when the person is 30 ft from the lamp post is 50/7 ft/m
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a converging lens with a focal length of 20 cm and a diverging lens with a focal length of -38 cm are 78.0 cm apart. a 2.7-cm-tall object is 40 cm in front of the converging lens.
The image height for a converging lens with a 20 cm focal length and a diverging lens with a 38 cm focal length that are 78.0 cm apart is 1.35 cm. 40 cm are in front of the converging lens
And a 2.7 cm tall object is there. An optical lens that converges all light rays travelling through it is known as a converging lens. A converging lens main function is to concentrate and converge the incoming light rays from an object to create an image. Depending on how close an object is to the lens, the image may be enlarged or unchanged.
h = (-di/do)(-di2/do2)*height
h = (-38/38)(-(-15))/30 (2.7)
h = -1.35 cm
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The complete question is-
a converging lens with a focal length of 20 cm and a diverging lens with a focal length of -38 cm are 78.0 cm apart. a 2.7-cm-tall object is 40 cm in front of the converging lens. Calculate the image height. Express your answer to two significant figures and include the appropriate units.
the activation energy of the forward reaction is equal to the sum of the activation energy for the reverse reaction and the enthalpy change for the forward reaction.
No, the activation energy for a forward reaction is not equal to the activation energy for the reverse of the same reaction.
In order for compounds to undergo a chemical reaction, a certain amount of energy is required, known as the activation energy. The unit of measurement for a reaction's activation energy (Ea) is either joules per mole (J/mol), kilojoules per mole (kJ/mol), or kilocalories per mole (kcal/mol). You can think of activation energy as the size of the potential barrier between the minima of the potential energy surface related to the initial and final thermodynamic states, which is also referred to as the energy barrier. If the system temperature is high enough, there should be a sizable number of molecules with translational energies that are equal to or higher than the activation energies.
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which of these situations corresponds to n independent bernoulli trials having the same probability p of success?
The probability mass function is obtained as:
[tex]p(x=x)=12 c_x \quad(0.4)^x(1-0.4)^{1 x-x} ; x=0,1,2 \ldots .12[/tex]
Outcome is,
[tex]n=12 \\ p=0.4[/tex]
Let X be discrete random variable which takes value [tex]$i=1,2 \ldots$[/tex].
Now the probability of mass function at point is is given by:
[tex]p(x=p)=p\left(x_i\right)=F\left(x_i\right)-F\left(x_{(i-1)}\right)[/tex]
By using Bernoulli's random variable:
[tex]P(x=x)=p^x(1-p)^{1-x} x=0,1[/tex]
where as [tex]$x=0 \Rightarrow$[/tex] corresponds to failure
[tex]$x=1 \Rightarrow$[/tex] correspond to Success
p is probability function of Success.
Therefore the total number of Success in ' n ' independent Bernoulli trials is Sum of ' n ' bernoulis random variable which gives binomial distribution.
By using multiplication rule the probability of observing ' x 'Successes in ' n ' independent bernoulli trials it can be written as:
[tex]\underbrace{p \times p \times \ldots \times p}_{x \text { times }} \times(\underbrace{() 1-p) \times(1-p) \times \ldots \times(1-p)}_{n-x \text { times }}[/tex]
The probability mass function :
[tex]p(x=x)=12 c_x \quad(0.4)^x(1-0.4)^{1 x-x} ; x=0,1,2 \ldots .12[/tex]
where as
[tex]n=12 \\ p=0.4[/tex]
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Note:- The question is as follow,
Consider the probability space [tex]$(S, M, P)$[/tex] that models the observed proportion of successes in n independent Bernoulli trials with probability of success equal to p. For example, given n=12 and p=0.4, the outcome [tex]\frac{5}{12}=.41 \overline{6} \:in $(S, M, P)$[/tex] should have the same probability as the outcome of 5 successes in 12 independent Bernoulli trials with probability of success equal to 0.4. Give a formula for the density function f(s) for this probability space in terms of the density [tex]$f_{n, p}$[/tex] of the binomial distribution with size n and probability p. ( points)
A 472 kg roller coaster is on top of a 12 m high hill. It starts from rest and then goes down the hill. How fast is
it going when it reaches the bottom?
The roller coaster is going with 15.34 m/s when it reaches the bottom.
What is law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.
According to the question, potential energy of the roller coaster at initial position = mass * acceleration due to gravity* height = mgh
Let the speed of the roller coaster at the bottom = v.
So, kinetic energy at the bottom = 1/2 * mass * speed^2 = 1/2 mv^2
From conservation of energy:
mgh = 1/2mv^2
v= √( 2gh)
= √( 2 × 9.8 × 12) m/s
= 15.34 m/s.
Hence, the speed of it at the bottom is 15.34 m/s.
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the gravitational force exerted on a solid object is 5.00 n. when the object is suspended from a spring scale and submerged in water, the scale reads 3.50 n (fig. p14.11). find the density of the object
Density of the object is 3333.33 kg/m³.
Density can be defined as the ratio of the mass of a body to its volume.
The SI unit of density is kg/m³.From Archimedes principle,
Rd = W/U = D/D'
Where Rd = relative density,
W = weight of the object in air,
U = upthrust in water,
D = Density of the object,
D' = Density of water.
W/U = D/D'
Density (D) of the solid can be calculated by the equation,
D = D'(W/U)
As we have,
W = 5.0 N,
U = 5.0 -3.5 = 1.5 N,
D' = 1000 kg/m³
Since U = lost in weight = weight in air - weight in water
D = 1000(5/1.5)
D = 3333.33 kg/m³
Thus the density of the solid object is 3333.33 kg/m³
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Which em spectrum pass through our atmosphere most easily?
Visible light, gamma ray, infrared radiation, or radio waves??
Answer:
Gamma Ray but read below
Explanation:
All of the types of electromagnetic radiation listed can pass through Earth's atmosphere, although some types are absorbed or blocked more easily than others.
Visible light, infrared radiation, and radio waves are able to pass through the atmosphere relatively easily, while gamma rays are more likely to be absorbed.
This is because gamma rays have a higher energy than the other types of radiation, so they are more easily absorbed by the atoms and molecules in the atmosphere.
Answer:
Gamma Rays
Explanation:
It has the highest possible frequency lowest wavelength and the most energetic charge. Its travels at the speed of light and is highly penerative
you thoughtfully set a 1 kg box on top of a loaf of bread and the loaf compresses by 15 cm. Thinking of the bread as a spring, its spring constant is
Answer:
k = 65.3 N/m
Explanation:
Fs = Fg = mg = (1.0 kg)(-9.8 m/s²) = -9.8 N
x = 15 cm = 0.15m
Fs = -kx (Hooke's Law)
-k = Fs/x = (-9.8 N)(0.15 m) = -65.3
k = 65.3 N/m
In a series resonant LCR circuit, the voltage across R is 100 volts and R= 1Ω with C = 2μF. The resonant frequency ω is 200 rad/s. At resonance, the voltage across L is :A4×10 −3voltB2.5×10 −2voltC40 voltD2.5×10 5volt
In a series resonant LCR circuit, the voltage across R is 100 volts and R= 1Ω with C = 2μF. The resonant frequency ω is 200 rad/s. At resonance, the voltage across L is D) 2.5 × 10⁵ volt.
given that :
V = 100 v
R = 1Ω
ω = 200 rad/s
C = 2μF
ω² = 1 / LC
(200)² = 1/ L × 2 × 10⁶
L = 12.5 H
current = 100 A
now, at resonance ,
voltage across the L is equals to voltage across C
voltage across L = 100 × ( 1 / 200 × 2 × 10⁶)
voltage across L = 2.5 × 10⁵ volt.
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the bitewing tab is a heavy paperboard tab or loop fitted around a periapical film or sensor and used to stabilize the receptor during exposure. (2) the periapical receptor is oriented in the bite loop so that the tab portion extends from the white side (tube side) of the film or sensor.
the bitewing tab is a heavy paperboard tab or loop fitted around a periapical film or sensor and used to stabilize the receptor during exposure. true
What is stabilize?
to stop changing and fix something, especially to prevent it from getting worse, or to induce something to stop changing and fix it: These drugs reduce blood pressure and calm your heart rate.
the periapical receptor is oriented in the bite loop so that the tab portion extends from the white side (tube side) of the film or sensor.True
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If a conductor is in electrostatic equilibrium near an electrical charge:A) The total charge on the conductor must be zero.B) The electric field inside the conductor must be zero.C) The charges on the conductor must be uniformly distributed.D) The sum of all forces between conductor and the electrical charge must be zero.
If a conductor is in electrostatic equilibrium near an electrical charge i.e. the correct option is, B) The electric field inside the conductor must be zero.
Because charge carriers can freely move within a conductor, when a charged or uncharged conductor is exposed to an external electric field, charge will flow until a steady state is reached, at which point the net flow of charge will cease. This state is known as electrostatic equilibrium. If the conductor is charged, the charges within it are rearranged, resulting in a zero net electric field inside the conductor. The net field inside the conductor again becomes zero if the conductor is polarized after being neutral.A neutral or charged conductor will typically achieve electrostatic equilibrium with a net zero electric field inside of it when it is kept close to an electric charge.The conductor in electrostatic equilibrium has characteristics such as a zero electric field inside and excess charges that are located on the surface. Therefore, the conductor's internal electric field must be zero.
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A 4kg blob of putty moving at 8 m/s slams into a 12 kg blob of putty at rest. What is the velocity of the two stuck- together blobs immediately after colliding?
The speed of the to stick together blobs immediately after colliding will be 2m/s.
How to solve?Given that:
Mass of first blob = 4kg = m1
Velocity of blob = 8m/s = v1
Mass of second blob = 12kg = m2
Velocity of blob = 0m/s = v2
To find:
Final velocity = Vf
Formula to be use:
(m1*v1) + (m2*V2) = Vf(m1 + m2)
(4*8) + (12*0) = Vf(4+12)
32 + 0 = Vf(16)
32 = Vf(16)
Vf = 2m/s
So the speed of two blobs immediately after colliding = 2m/s
How do we arrive at the V1 and V2 equations for elastic collisions?V1: (m1-m2/m1+m2)
u1 + (2m2/m1+m2)
u2 V2: ( 2m1/m1+m2) u1 + (m2-m1/m1+m2) u2 Assume that mass 1 has an initial velocity of u1, a final velocity of v1, a mass 2 beginning velocity of u2, and a mass 2 final velocity of v2.
What in physics does m1v1 m2v2 mean?V1 stands for the volume of stock solution required to create the new solution. M1 = Stock solution concentration. The total volume of the solution is V2.
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find the linear acceleration of the spool below (mass m, moment of inertia i) if it is rolling without slipping:
The linear acceleration of the spool below (mass m, moment of inertia i) if it is rolling without slipping: A spool of mass m and moment of inertia I (around its center) is free to roll without slipping on a table. It has an inner radius of r and an outer radius of R.
In mechanics, acceleration is the charge of the alternate velocity of an item with recognition of time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the internet pressure acting on that item.
Acceleration, is the price at which speed modifications with time, in terms of each pace and path. A point or an object transferring in an instant line is accelerated if it quickens or slows down. movement on a circle is multiplied although the rate is constant due to the fact the path is always converting.
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On a baseball field, first base is about 30 m away from home plate and second base is 30 m away from first base. A batter gets a hit and makes it to second base. What is the hitters final displacement from home plate?
The hitters final displacement from home plate is 60 m.
What is displacement?The displacement of an object is the change in the position of the object.
The displacement of an object is determined from the shortest distance between the initial position and the final position of an object.
The hitters final displacement from home plate is calculated as follows;
Δx = x₁ - x₂
where;
x₁ is the initial position x₂ is the final positionΔx = x₁ - x₂
Δx = 30 m - ( - 30 m)
Δx = 30 m + 30 m
Δx = 60 m
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Match the astronomical distance measuring techniques with their approximate ranges: Triangulation. distances up to about 1000 light years.
Spectroscopy. distances up to about 10,000 light years.
What is astronomical distance?Astronomical distance is the measurement of space between objects in the universe. It is usually measured in light years, which is the distance light travels in a year. Astronomical distance is incredibly vast and hard to comprehend, as it is measured in trillions of miles. Astronomical distance is used to measure distances between objects in the universe such as stars, galaxies, and planets. Astronomical distances are also used to measure the size of the universe, as well as the age of galaxies and stars. Astronomical distances can be measured using advanced instruments such as telescopes and spectroscopes. Astronomical distances are essential for understanding the structure of the universe and the evolution of galaxies and stars.
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A child on a bike traveled 20 m east, and then 30 m north. What was the displacement of the child?
50 m, north
36 m, north
36 m, northeast
50 m, northeast
The displacement of the child is 36 m, northeast.
Define displacement.
Displacement is the difference between an object's starting location and any subsequent position (such as the position of a body or geometric figure). An object's position in relation to a reference frame changes when there is displacement. It is allegedly displaced. The vector quantity displacement has a magnitude and a direction.
Here, imagine
Distance travelled to east is side AB of a right sided traingle,
AB = 20m
Distance travelled to north is side BC of the same triangle ,
BC = 30m
To find total displacement is to find side AC of the above triangle,
According to Pythagorus theorem
(AC)^2= (AB)^2 + (BC)^2
(AC)^2 = (20)^2 + (30)^2
AC = 36m
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Two blocks with masses 3m and 4m are on a collision course with the same initial speeds v The block with mass 3m is traveling to the left, and the 4 block is traveling to the right. They undergo a head-on elastic collision and each bounces back, along the same line as it approached. Find the final speeds of the particles (Enter your answers in terms of the initial speed of each mass.) Vam X Apply the final velocity equations for elastic collisions: mi 2m2 11+ 22 m, m2 + 2m m + mm Note that il- lvl = v. Be careful of your signs! Vam
The final velocity equations for elastic collisions is
[tex]$\begin{aligned}& u_1=\frac{3}{2} v_i \\& u_2=\frac{1}{2} v_i\end{aligned}$$[/tex]
A collision between two bodies in physics is referred to as an elastic collision if their combined kinetic energy stays constant. There is no net conversion of kinetic energy into other forms, such as heat, noise, or potential energy, in an ideal, fully elastic collision.
Lat their final speeds of bouncing back are u_1 and u_2 As the collision is clastic, e=1So,u_1+u_2=v_i+v_i=2 v_i
From momentum conservation, 3 m v_i-4 m v_i=4 m u_2-3 m u_1
[tex]$$\begin{aligned}& \Rightarrow \quad-2 v_i=4 u_2-3 u_1 \\& \Rightarrow 3 u_1-5 u_2=2 v_i-\text { (2) }\end{aligned}$$[/tex]
From (1) and (2),
[tex]$$\begin{aligned}u_1+u_2 & =3 u_1-5 u_2 \\\Rightarrow 2 u_1 & =6 u_2 \Rightarrow u_1=3 u_2\end{aligned}$$[/tex]
From (1),
[tex]$3 u_2+u_2=2 v_i$[/tex]
[tex]$$\text { and } \begin{aligned}\Rightarrow u_2 & =\frac{1}{2} v_i \\u_1 & =3 u_2=\frac{3}{2} v_i .\end{aligned}$$[/tex]
So,
[tex]$$\begin{aligned}& u_1=\frac{3}{2} v_i \\& u_2=\frac{1}{2} v_i\end{aligned}[/tex]
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g draw shear force and bending moment diagrams of the below beam. make sure to include/show all necessary values on the diagrams and the way that you calculate them
The maximum absolute values of the shear and bending moment is 2P and 3Pₐ respectively.
(a) Diagram is shown in image.
From A to B:
+∑Fy = 0: V = -P
+∑M₁ = 0: M = -P
From B to C:
+∑Fy = 0:
-P-P-V = 0
⇒ V = -2P
+∑M₂ = 0:
Pₓ+P(x - a)+M =0
⇒ M = -2Pₓ + Pₐ
(b) The maximum bending moment occurs in a beam, when the shear force at the section is zero or changes the sign because at point of contra fixture the bending moment is zero.
Therefore
= |V|max = 2P
= |M|max = 3Pₐ
Thus, the maximum absolute values of the shear and beading moment is 2P and 3Pₐ.
-- The given question is incomplete, I answer the question in general according to my knowledge and the complete question is
"For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the maximum absolute values of the shear and bending moment." --
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An electromagnetic wave travelling in the x-direction has frequency of 2×10 14 Hz and electric field amplitude of 27 Vm −1. From the options given below, which one describes the magnetic field for this wave?
The magnetic field for this wave is
[tex]B(x, t)=(9*10^{-8}T )i sin[2\pi (1.5*10^{-8}x-2*10^{14}t )][/tex].
Electromagnetic Wave:
The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves or EM waves. In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves.
Given,
Frequency of the wave; [tex]f=[/tex] [tex]2*10^{14} Hz[/tex]
The amplitude of the Electric Field; [tex]E_{0} = 27 N/C[/tex]
We know that Maxwell's equation is given by,
[tex]\frac{E_{0} }{B_0} =c[/tex] .....................(1)
Where,
[tex]E_{0} =[/tex] The amplitude of the electric field
[tex]B_{0}=[/tex] The amplitude of the magnetic field
[tex]c=[/tex] The velocity of light = [tex]3*10^{8} N/m^{2}[/tex]
By solving equation (1), we get
[tex]B_{0} =\frac{27}{3*10^{8} }[/tex]
[tex]B_{0}=9*10^{-8}[/tex]
We know that,
Angular frequency; ω [tex]= 2\pi f[/tex]
The equation of the magnetic field can be given by
[tex]B_{0}sin(kx-\omega t) =B_{0}sin(2\pi (\frac{x}{\lambda}-ft ))[/tex]
[tex]B_{0}sin(kx-\omega t)=9*10^{-8} sin(2\pi (\frac{x}{\lambda}-2*10^{14} t))[/tex].
Hence,
The magnetic field for this wave is
[tex]B(x, t)=(9*10^{-8}T )i sin[2\pi (1.5*10^{-8}x-2*10^{14}t )][/tex].
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landings at the top and bottom of stairs should be at least equal in length to the of the stairway.
In cases when the stairway is straight, the width of the landing in the direction of travel must at least match the stair's width and cannot be greater than 1219mm.
The four main axes are north, south, east, and west. A map is a representation or drawing of the entire or a portion of the surface of the earth done to scale and on a flat surface. A spherical shape, however, cannot be totally flattened. Distance, direction, and symbol are the three elements that make up a map.
Most maps have an arrow with the letter "N" on them in the upper right-hand corner. North is indicated by this arrow's orientation. It is referred to as the north line. You can determine which direction is east, west, or south once you know which way is north. The four main axes are North, South, East, and West.
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a person holds a book at rest a few feet above a table. the person then lowers the book at a slow constant speed and places it on the table. which of the following accurately describes the change in the total mechanical energy of the earth-book system?
The person exerts negative work on the book by applying a force in the direction opposite to its displacement, causing the total mechanical energy to decrease. Hence, option (D) is correct.
The given problem is based on the concept of mechanical energy. The mechanical energy is the energy of any object by virtue of its position or motion. And mathematically, it is expressed as the sum of kinetic energy and potential energy.
And the work completed is described as,
W = F * d
here,
W is the work done
F is the applied force
d is the displacement
The individual lowers the book in the provided situation at a slow manner. This means some work has been done by applying force in downward direction. This work will be negative, because it is opposite to the displacement. So, work done is negative.
And according to work energy concept,
Work done = Change in kinetic energy
Negative work accounts for negative value of kinetic energy. Which means kinetic energy is decreasing continuously. Additionally, if kinetic energy declines, mechanical energy will eventually follow.
The question is incomplete. The complete question is ' A. the total mechanical energy is unchanged, because there is no change in the book's kinetic energy as it is lowered to the table.
B. the total mechanical energy is unchanged, because no work is done on the earth-book system while the book is lowered.
C. the total mechanical energy decreases, because the person does positive work on the book by exerting a force that opposes the gravitational force.
D. The total mechanical energy decreases, because the person does negative work on the book by exerting a force on the book in the direction opposite to its displacement.'
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Assume a small spacecraft is in open space. One panel is a dedicated radiator (dimensions in image) and is painted with S13 GLO white paint (emissivity = .89). If the radiator is at 30C and has a full view factor to space, how much heat can it reject from the system? (How much is this radiator radiating to space?). Use 3K for space temperature. Round answer up to one decimal place. No need to include units.
This radiator's Heat radiation is 12.8 W.
Provided, the temperature of the radiator θ = 30°C
So, the absolute temperature of the radiator,
T = ( θ + 273 ) K
= ( 30 +273 ) K
= 303 K
Also provided, the temperature of the surrounding space, T₀ = 3 K
The emissivity of the white paint, ε = 0.89
The length of one side of the radiator, L = 0.3m and the breadth, B = 0.1m.
Now, the amount of rate of heat transfer by a system at temperature T to a surrounding space at temperature T₀ is given by the formula,
Q = σεFA(T⁴-T₀⁴).
where A is the area of the system exposed to the surrounding, F is the view factor, σ is the Stefan-Boltzmann constant = 5.67 × 10⁻⁸Wm⁻²K⁻⁴ and σ is the emissivity of the system.
Here, the surface area of the radiator,
A = LB = (0.3m) (0.1m) = 0.03 m²
According to the question, the radiator has a full view factor to the space, i.e. we can say, the view factor in this case is, F = 1.
Substituting all known values into the equation we just mentioned we get,
Q = σεFA(T⁴-T₀⁴)
= (5.67 × 10⁻⁸Wm⁻²K⁻⁴) (0.89) (1) (0.03 m²) [ (303K)⁴ - (3K )⁴ ]
= 12.76 W
≈ 12.8 W
So, the rate of heat radiation is, Q = 12.8 W
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Induction charging is a method used to charge an object without actually touching the object to any other charged object.the process by which an object receives a static charge when placed near a second charged object is known as
Induction charging is a method used to charge an object without actually touching the object to any other charged object. The process by which an object receives a static charge when placed near a second charged object is known as inductance.
Induction charges another body without came in contact with that body.
During induction, charges move between objects that briefly touch; during conduction, charges move between objects that are rubbed together.
if the charges have the same sign, then the force is repulsive, this means that the forces point away from each other, so in this case the forces have opposite directions.
Charging by conduction refers to the contact of a charged object to a neutral object, which is the opposite of induction.
Charging by induction refers to charging an object without making contact, it could be through an electric field.
Therefore, the induction charging is a method used to charge an object without actually touching the object to any other charged object. The process by which an object receives a static charge when placed near a second charged object is known as inductance.
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