surface area of sphare​

Answer:

Hey there!

Do you mean- [tex]n^2+2n?[/tex]

If so, then your answer would be 5^2+2(5), or 35.

Let me know if this helps :)

Answer:A

Step-by-step explanation:

The phrase can be described broadly as adjusted gross income (AGI) minus allowable tax deductions.

"Adjusted gross income, or AGI, is your gross income minus certain adjustments. The IRS uses this number as a basis for calculating your taxable income. AGI can also determine which deductions and credits you may qualify for."

Since, Taxable income is the portion of your gross income used to calculate how much tax you owe in a given tax year.

It can be described broadly as adjusted gross income (AGI) minus allowable itemized or standard deductions.

Taxable income includes wages, salaries, bonuses, and tips, as well as investment income and various types of unearned income.

Hence, the phrase can be described broadly as adjusted gross income (AGI) minus allowable tax deductions.

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Find the value of xy².

xy²

★ Substituting the values of x and y ,we get :

⇒ -12 × ( -3 )²

⇒ -12 × 9

⇒ -108

Answer:

  y = (x -1)² -3

Step-by-step explanation:

A quadratic with a vertex at (h, k) will have an equation of the form ...

 y = a(x -h)² +k

You have (h, k) = (1, -3), and a vertical scale factor* of 1. So, the equation of the graphed curve is ...

  y = (x -1)² -3

_____

* One way to determine the value of "a" in the form shown is to look at the vertical difference between the vertex and the points 1 unit right or left of the vertex. Here, those points are 1 unit above the vertex, so the vertical scale factor "a" is 1.

Answer:

1/5

Step-by-step explanation:

1/5

2/3+3/3+4/3

=2/5*3/6

= 1/5

I'm not sure.

Answer:

The answer should be 0.022

Answer:

associative property

The solution is,  property is shown in the matrix addition below is

associative property.

Here, we have,

The property shown in the given matrix addition is associative property.

Let's define associative property first,

The Associative Property of Addition for Matrices states :

Let A , B and C be m×n matrices .

Then, (A+B)+C=A+(B+C) .

Associative Law of Addition of Matrix:

Matrix addition is associative. This says that, if A, B and C are Three matrices of the same order such that the matrices B + C, A + (B + C), A + B, (A + B) + C are defined then A + (B + C) = (A + B) + C.

Since P and Q are of the same order and pij = qij then, P = Q.

Here, from the given information,

we get, A , B and C be 4×1 matrices,

and,  (A+B)+C=A+(B+C)

So, The solution is,  property is shown in the matrix addition below is

associative property.

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Answer:

C, at 0/25, 1/20, 2/15, 3/10,...

Answer:

C

Step-by-step explanation:

Answer: 1.

Step-by-step explanation: 1^5 is really just 1, 5 times.

1*1*1*1*=1

Answer:

The linear distance between the two points is the square root of the sum of the squared values of the x-axis distance and the y-axis distance. To carry on the example: the distance between (3,2) and (7,8) is sqrt (52), or approximately 7.21 units.

Step-by-step explanation:

Answer:

Step-by-step explanation:

distance formula and pythagorean formula

Answer:

[tex]\Large \boxed{{(10x+10)=110}}[/tex]

Step-by-step explanation:

Vertical opposite angles are equal.

[tex](10x+10)=110[/tex]

Answer:

The answer is C.

Step-by-step explanation:

Reason:

For the angles shown, angle (10z+10)° is the same with 110°

So the equation is (10z+10)° = 110°

That's the answer. (C).

Answer:

None of the answers seem to be correct.

Step-by-step explanation:

The given equation is of the form y = mx + b where m is the slope and b is the y-intercept.

Here, m = -14

Two parallel lines have the same slope. So, the slope of the new line will be -14.

To calculate the y-intercept substitute x=4 and y=4 in the equation.

4 = (-14)(4) + b

Solving for b, we get b = 60.

So, the new equation will be y = -14x + 60

The equation of the line parallel to the given line is y =-14x+60, none of the given options is correct.

The equation of the straight line is given by y = mx +c , Where m is the slope of the line and c is the y-intercept.

The equation of the line is y = -14x -3

The slope of the line parallel to this will be the same as the given line.

m = -14 for both the lines

The line equation parallel to the given line is

y = -14x +c

The line passes through the points (4,4)

4 = -14 * 4 + c

c = 60

y = -14x +60

Therefore, the equation of the line parallel to the given line is y =-14x+60.

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Answer:

70%

Step-by-step explanation:

So 5600/8000 is the fraction and 80 = 1% so 5600/80 will be your answer

Answer:

Step-by-step explanation:

-8 + 8a = -12 + 4a

4a - 8 = -12

4a = -4

a = -1

Answer:

a = -1

Step-by-step explanation:

[tex]4(-2+2a) = -12 +4a\\-8+8a=-12+4a\\8a = -4 +4a\\4a=-4\\\frac{4a}{4} =\frac{-4}{4} \\a=-1[/tex]

I hope that makes since... I tried to show my work the best I could.

Answer:

The answer is

Step-by-step explanation:

To find an equation of the line using a point and the slope we use the formula

y - y1 = m(x - x1)

where

m is the slope

(x1 , y1) is the point

From the question

slope = -3/2

Point = (4,8)

So the equation of the line is

[tex]y - 8 = - \frac{3}{2} (x - 4)[/tex]

Multiply through by 2

2y - 16 = -3( x - 4)

2y - 16 = - 3x + 12

3x + 2y = 16 + 12

We have the final answer as

Hope this helps you

Answer: 0.29 or 29%

Step-by-step explanation:

Given :

Probability that the athletes are football players : P(football ) = 0.28

Probability that the athletes are basketball players : P(basketball) = 0.25

Probability that the athletes play both football and basketball: P( both football and basketball ) = 0.24

Now, using formula

P(either  football or basketball)= P(football )+ P(basketball+ P( both football and basketball )

⇒P(either  football or basketball)= 0.28+0.25-0.24 = 0.29

Hence, the probability that they are either a football player or a basketball player = 0.29 .

Answer:

a. La ganancia es de $ 4,060,000.00

b. 31 vehículos

Step-by-step explanation:

(a) Los parámetros dados son;

El número de automóviles tipo sedán fabricados = 24

El número de camiones tipo SUV fabricados = 16

El número de camiones tipo VAN fabricados = 12

El número de camionetas pick-up fabricadas = 8

El número de autos deportivos fabricados = 2

La ganancia por la venta de autos tipo sedán = $ 185,000 - $ 140,000 = $ 40,000

La ganancia por la venta de camionetas tipo SUV = $ 320,000 - $ 250,000 = $ 70,000

La ganancia por la venta de camiones tipo VAN = $ 400,000 - $ 310,000 = $ 90,000

La ganancia por la venta de las camionetas pick-up = $ 285,000 - $ 210,000 = $ 75,000

La ganancia por la venta de los autos deportivos = $ 550,000 - $ 400,000 = $ 150,000

La ganancia = 24 * $ 40 000 + 16 * $ 70 000 + 12 * $ 90 000 + 8 * $ 75 000 + 2 * $ 150 000 = $ 4060 000

(b) Por lo que hay una tasa de producción constante, solo la mitad de los automóviles se producirán dentro del período de 12 horas

Por lo tanto, tu fabricado

12 autos sedán, 8 camionetas tipo SUV, 6 camionetas tipo VAN, 4 camionetas pick-up y 1 auto deportivo para hacer un total de 31 vehículos.

Answer:

14.6

Step-by-step explanation:

In the question, we are told that:

Yivgeny's gymnastics scores were 1.5, 1.7, 5.5, and 9.1.

In the question, we are also told that to calculate his total score, we add his top two scores.

Yivgeny's top two gymnastics scores are:

5.5 and 9.1.

Hence, his total scores = 5.5 + 9.1

= 14.6

Yivgeny's total scores = 14.7

Answer:

Proof in the explanation.

Step-by-step explanation:

I expanded both sides as a first step. (You may use foil here if you wish and if you use that term.)

This means we want to show the following:

[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

[tex]=12\cos^2(\theta)-9-4\cos^2(\theta)\tan^2(\theta)+3\tan^2(\theta)[/tex].

After this I played with only the left hand side to get it to match the right hand side.

One of the first things I notice we had sine squared's on left side and no sine squared's on the other. I wanted this out. I see there were cosine squared's on the right. Thus, I began with Pythagorean Theorem here.

[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

[tex]3-9\tan^2(\theta)-4(1-\cos^2(\theta))+12\sin^2(\theta)\tan^2(\theta)[tex]

Distribute:

[tex]3-9\tan^2(\theta)-4+4\cos^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]

Combine like terms and reorder left side to organize it based on right side:

[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

After doing this, I since that on the left we had products of sine squared and tangent squared but on the right we had products of cosine squared and tangent squared. This problem could easily be fixed with Pythagorean Theorem again.

[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+12(1-\cos^2(\theta))\tan^2(\theta)-9\tan^2(\theta)[/tex]

Distribute:

[tex]4\cos^2(\theta)-1+12\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

Combined like terms while keeping the same organization as the right:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

We do not have the same amount of the mentioned products in the previous step on both sides. So I rewrote this term as a sum. I did this as follows:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

Here, I decide to use the following identity [tex]\cos\theta)\tan(\theta)=\sin(\theta)[/tex]. The reason for this is because I certainly didn't need those extra products of cosine squared and tangent squared as I didn't have them on the right side.

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]

We are again back at having sine squared's on this side and only cosine squared's on the other. We will use Pythagorean Theorem again here.

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8(1-\cos^2(\theta))-9\tan^2(\theta)[/tex]

Distribute:

[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8+8\cos^2(\theta)-9\tan^2(\theta)[/tex]

Combine like terms:

[tex]12\cos^2(\theta)-9+3tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)[/tex]

Reorder again to fit right side:

[tex]12\cos^2(\theta)-9+4\cos^2(\theta)\tan(\theta)+3\tan^2(\theta)[/tex]

This does match the other side.

The proof is done.

Note: Reordering was done by commutative property.

X - (-20) = 5

When you subtract a negative, change it to addition:

X + 20 = 5

Subtract 20 from both sides:

X = -15

Answer:

[tex]\boxed{x=-15}[/tex]

Step-by-step explanation:

[tex]x-(-20)=5[/tex]

[tex]\sf Distribute \ negative \ sign.[/tex]

[tex]x+20=5[/tex]

[tex]\sf Subtract \ 20 \ from \ both \ sides.[/tex]

[tex]x+20-20=5-20[/tex]

[tex]x=-15[/tex]

Answer:

itself and numbers divisible by 7

Answer:

True

Step-by-step explanation:

Answer:

true as positive are bigger than negetive

Step-by-step explanation:

Answer:

Its 14

Step-by-step explanation:

8+6=14

Answer:

The answer is 16

08

+ 06

----------

16

Hope it helps ;)

Please mark as brainliest

Step-by-step explanation:

x be an irrational number between 9.5 and 9.7.

So, we consider that  x = 9.562536941412578914...

Rounding to the nearest hundredth

x = 9.56.

9.56763865854637984..... (rounded 9.57)

irrational because it has no pattern

Answer:  [tex]\large \sqrt{91}[/tex]

Step-by-step explanation:

An irrational number is a square root in its simplest form.

We want an irrational number between 9.5 and 9.7

                               [tex]\huge 9.5<\sqrt x <9.7[/tex]

square all sides     90.25 < x < 94.09

Answer: The square root of any number between 90.25 and 94.09 will work so there are an infinite number of possible answers. [tex]\sqrt{91}, \sqrt{92}, \sqrt{93}, \sqrt{94}[/tex]

Answer:

(4,2) is the answer on AP EX

The coordinate of the image of point A is (-4,-2)

Transformation is the process of changing the graph to a new graph by Rotation, Reflection, Translation, and Dilation.

The coordinate of A is (4,-2)

When it is reflected across y axis, the coordinate (x,y) changes to ----> (-x,y)

So, the coordinates of A (4,-2) changes to (-4,-2)

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Answer:

3

3+3=6

3+3+5=11

13

13-3=10

10-3=7

15

15-7=8

8-5=3

32+43=75

75-40(highest ten)=35

76+15=91

91-70=21

Answer: You are correct. There is only one answer and that is choice B) vertical line of symmetry.

We can draw a vertical line through the center to have one half mirror over this line to get the other half. We can't do the same with a horizontal line or any other kind of line.

We do not have rotational symmetry. Rotating the figure will produce an image different from the original. The angle of rotation is some angle x such that 0 < x < 360.

Answer:

Theres more than one answer so b and a

Step-by-step explanation:

Answer:

  40

Step-by-step explanation:

Any solution x will mod 23 will also have x+23n as a solution, for some integer n. Since 900/23 = 39 3/23, we know there are 39 or 40 three-digit integers of this form.

As it happens, 100 is the smallest 3-digit solution. So, there are 40 three-digit numbers that are of the form 100 +23n, hence 40 solutions to the equation.

_____

The equation reduces, mod 23, to ...

  10x = 11

Its solutions are x = 23n +8.

3√3 is not equivalent to 9³/₄

3√3 is equivalent to   [tex]9^\frac34[/tex]

step-by-step:

[tex]9^\frac34=(3^2)^\frac34=3^{2\cdot\frac34}=3^{\frac32}=3^{1+\frac12}=3^1\cdot3^\frac12=3\cdot\sqrt3=3\sqrt3[/tex]

The simplest form of the number [tex]9^\frac{3}{4}[/tex]   is  [tex]3 \ \sqrt[]{3}[/tex].

It is given that the  [tex]9^\frac{3}{4}[/tex]

It is required to find the simplest value of [tex]9^\frac{3}{4}[/tex]

It is defined as the number if we multiply the number by itself we get the original number it is a non-negative number.

We have:

= [tex]9^\frac{3}{4}[/tex]

We can write the above number as below:

[tex]= (3^2)^\frac{3}{4}[/tex]

By the property of powers:

[tex]\rm (x^a)^b= x^a^\times ^b[/tex] , we get:

[tex]3^2^\times^\frac{3}{4} \\\\\\3^\frac{3}{2} \\\\\sqrt{3^3} \\\\\sqrt{3}\times \sqrt{3}\times\sqrt{3}\\\\3\sqrt{3}[/tex]

Thus, the simplest form of the number [tex]9^\frac{3}{4}[/tex]   is  [tex]3 \ \sqrt[]{3}[/tex].

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[tex]\displaystyle f(x)=\sin(3x)\\\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3(x+h))-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3x+3h)-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{3x+3h+3x}{2}\right)\sin\left(\dfrac{3x+3h-3x}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{\dfrac{3h}{2}}\cdot\dfrac{3}{2}[/tex]

[tex]\displaystyle f'(x)=\lim_{h\to0}2\cos\left(\dfrac{6x+3h}{2}\right)\cdot\dfrac{3}{2}\\\\f'(x)=\lim_{h\to0}3\cos\left(\dfrac{6x+3h}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x+3\cdot 0}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x}{2}\right)\\\\f'(x)=3\cos(3x)[/tex]

The derivative of sin 3x using first principles is; 3cos(3x)

We want to find the derivative of sin 3x using first principles.

Step 1;

f'(x) = [tex]\lim_{h \to \ 0} \frac{(sin3(x + h)) - sin(3x)}{h}[/tex]

Step 2; Expand the bracket to get;

f'(x) = [tex]\lim_{h \to \ 0} \frac{(sin(3x + 3h)) - sin(3x)}{h}[/tex]

Step 3: According to trigonometric identities, we know that;

sin A - sin B = [tex]2cos\frac{A + B}{2} sin\frac{A - B}{2}[/tex]

Applying that to the answer in step 2 gives;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(3x + 3h + 3x)}{2}) sin\frac{(3x + 3h - 3x)}{2})}{h}[/tex]

Step 4; Simplify the brackets to obtain;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(6x + 3h)}{2}) sin\frac{(3h)}{2})}{h}[/tex]

Step 5; Rewrite the denominator to get;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(6x + 3h)}{2}) sin\frac{(3h)}{2})}{\frac{3h}{2}*\frac{2}{3}}[/tex]

Step 6; Input the limit of 0 for h to get;

f'(x) = [tex]\frac{2(cos\frac{(6x)}{2}) sin\frac{(0)}{2})}{\frac{0}{2}*\frac{2}{3}}[/tex]

⇒ f'(x) = [tex]\frac{2(cos3x)}{2/3} \frac{ 0}{{0}}[/tex]

0/0 = 1. Thus;

f'(x) = 3cos(3x)

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