Tarzan weighs 73 kg. From a 26.1 m vine, he swings. Tarzan is travelling at 3.65 m/s when he is at his lowest point in his swing. The vine is under 2635.3 kg-m/s^2 of tension at the swing's lowest point.
The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire. Every physical object in contact with another one applies some force to that object. For items that are hung, the tension is equal to the gravitational acceleration times the mass of the object.
Here m=73kg
acc (a) = 26.1 m
g=10
d= 3.65 m/s
Tension t = mg + ma.
Tension t = m(g + a).
t = m(g + a)
t= 73(10+26.1)
t= 73(36.1)
t= 2635.3 kg-m/s^2
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b) how far will the cart move in the 4.5 s if the shopper places a(n) 84 n child in the cart before pushing it? answer in units of m.
The cart of the supermarket will move 3.99 m if the shopper places an 84 N child in cart and is pushing.
Given that,
Mass of the cart = 25.1 kg
Horizontal force = 13.3 N
It is pushed for 3.6 sec
Mass of the cart and child = Total force/ Acceleration = (25.1* 9.8 + 84)/9.8 = 33.67 kg
From the equations of motion, we know,
Initial velocity = 0
Time t = 4.5 s
Distance s = ut + 1/2* a* t² = 0 + 1/2* (13.3/33.67)* (4.5)² = 3.99 m
Thus, the cart will move for 3.99 m after placing the child.
The question is incomplete. The complete question is 'A shopper in a supermarket pushes a loaded cart with a horizontal force of 13.3 Newtons. The cart has a mass of 25.1 kg and is pushed for 3.60 seconds, starting from rest.'
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WILL GIVE BRAINLY IF RIGHT
what would happen if you dropped, at the same time, particles of different shapes from a boat into still water
Explanation:
If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.
a pendulum is pulled to a height of 1.28 m above the lowest position and released. what is its speed at the level of the lowest position?
The speed at the level of the lowest position is 5.01m/s.
How do you conserve energy?Energy cannot be created or destroyed; it can only be changed from one form of energy to another, according to the law of conservation of energy. This implies that a system always has the same amount of energy, barring external energy addition.
To reduce expenses and protect the resources for future use, energy conservation is necessary. The environment is contaminated by the harmful gases released into the atmosphere by conventional energy sources. Traditional energy sources are finite and could run out one day.
This is a typical energy conservation question, Set the kinetic energy at the bottom and the potential energy at the height to be equal.
mgh = 1/2mv²
gh = v²/2
v = √2gh
v = √2×9.8×1.28m/s
v = 5.01m/s.
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A fast ride at Six Flags makes a circular loop. If the tangential speed of the cart as it moves around the loop is 10 m/s, and the radius of the loop is 5 m, what is the centripetal acceleration of the cart as it moves around the loop?
The centripetal acceleration of the Cart is 20 m/s2.
What is centripetal acceleration?Centripetal acceleration is a change in velocity that points toward the center of a circular path. It is the acceleration an object experiences when its velocity changes direction, but its speed remains constant. It is always directed toward the center of the circle and is caused by a force, such as gravity or friction. The magnitude of the centripetal acceleration is equal to the square of the object's velocity divided by the radius of the circle. Examples of centripetal acceleration include the motion of a satellite orbiting the Earth, a car rounding a curve, and a roller coaster car making a loop.
Given that,
Speed of the Cart = 10m/s
Radius of the loop = 5m
We know that the acceleration of the car can be computed as follows:
a = v2/R
a = (10.0 m/s)2/(5.0 m)
a = 20.0 m/s2
Thus, the centripetal acceleration of the Cart is 20 m/s2
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which deductible level would result in the lowest premium for automobile insurance?
The deductible level that would result in the lowest premium for automobile insurance is from $250 or $500
Is a greater or lower deductible preferable?For those who anticipate needing expensive medical care or continuous medical treatment, a plan without a deductible typically offers good coverage and is a wise decision.
In most circumstances, a plan's premium will be lower the larger its deductible. You save money on what you pay each month when you're willing to pay more up front when you need care.
The typical range for a comprehensive deductible suggested by insurance agents is between $100 and $500. It makes sense to have a smaller deductible for comprehensive claims because they often involve less damage than collision claims.
High-deductible health plans typically have cheaper premiums but need greater upfront payments before insurance will cover medical expenses. Meanwhile, higher premiums are typically associated with health insurance plans with lower deductibles since they provide more predictable expenses and frequently more robust coverage.
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if the minute hand has a mass of 130 kg, what is the torque being applied by the mass of the minute hand itself?
The torque being applied by the mass of the minute hand itself is 3470.303N-m. if it has mass of 130kg.
In material science and mechanics, torque is a standard mechanical amount, what might be compared to direct force.[1] It is likewise alluded to as the snapshot of power (likewise shortened to second). It addresses the capacity of a power to deliver change in the rotational movement of the body. The idea began with the examinations by Archimedes of the use of switches, which is reflected in his well known expression: "Give me a switch and a spot to stand and I will move the Earth". The law of preservation of energy can likewise be utilized to grasp force. The image for force is ordinarily , the lowercase Greek letter tau. While being alluded to as snapshot of power, it is normally signified by M.
Torque is given by the formula=r×F
or Torque=rFsinθ
Now,we have r=6meter,F=130 ˣ 9.8=1274N,θ=27°,sin27°=0.453
So,Torque=6 ˣ 1274ˣ0.453
=>Torque=3470.303N-m.
Hence,torque applied by the mass is 3470.303N-m.
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(Complete question) is:
if the minute hand has a mass of 130 kg, what is the torque being applied by the mass of the minute hand itself?length of minute hand is 6 meters long,and angle made by minute hand is 27 degrees.
ernie is trying to swim directly across a rushing river. ernie can swim at a rate of 6.2 m/s. the river's current is moving at a rate of 10.7 m/s. calculate the magnitude of ernie's resultant velocity?
The magnitude of Ernie's resultant velocity is [tex]V=8.72m/s[/tex].
Velocity:
Velocity is the direction in which an object is moving and serves as a measure of the rate at which its position is changing as seen from a specific point of view and as measured by a specific unit of time. In kinematics, the area of classical mechanics that deals with the motion of bodies, velocity is a fundamental idea.
Given,
Ernie's swimming rate with respect to the river [tex]V_{ER} =6.2 m/s[/tex]
River's current rate [tex]V_{R}=10.7 m/s[/tex]
Hence,
The magnitude of Ernie's resultant velocity
[tex]V[/tex] = [tex]V_{R} -V_{ER}=10.7i - 6.2j[/tex]
[tex]V=\sqrt{(10.7)^{2}-(6.2)^{2} }[/tex]
[tex]V=8.72m/s[/tex]
Hence,
The magnitude of Ernie's resultant velocity is [tex]V=8.72m/s[/tex].
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what is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then released from rest, and whose period is 0.66 s ? assume that the displacement at the start of the motion is positive.
Answer:
x = A cos ω t at t = zero, x displacement equals amplitude
x = .088 m cos ω t describes the motion
We need yet to find ω in terms of P which is given
ω = √(k / m)
P = 1 / f and f = ω / (2 π)
Thus ω = 2 π f = 2 π / P since 1 / f = P
This gives us
x = .088 m cos 2 π / .66 * t
on average, how much time separates the rise of one civilization in the galaxy from the rise of the next?
Between climbs, 100,000,000,000/1,000,000 equals 100,000 years. Our civilization is quite young compared to most or all of the others because it just emerged a few thousand years ago.
How much time separates the rise of one civilization in the galaxy from the rise of the next?Turn-based strategy video games like Civilization have been around since 1991. Sid Meier created the first game in the series and contributed creatively to the majority of the others; as a result, the formal titles of these games, such Sid Meier's Civilization VI, typically include his name.
An sophisticated condition of human society with highly developed institutions of government, culture, industry, and shared social conventions is known as a civilization.
Between climbs, 100,000,000,000/1,000,000 equals 100,000 years. Our civilization is quite young compared to most or all of the others because it just emerged a few thousand years ago. Given these plausible hypotheses, it is likely that there are no other civilizations that are younger than 50,000 years old.
The complete question is :Time Between Civilizations. Suppose that there are 100 billion stars in the Milky Way Galaxy, that 1 in 1 million stars gets a civilization at some point, and that these civilizations have arisen at random times over the past 5 billion years. On average, how much time separates the rise of one civilization in the galaxy from the rise of the next? Based on your answer, should we expect to make radio contact with another civilization that is either at or below our own current level of technological development?
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solar eclipses are slightly more common than lunar eclipses. why, then, is it more likely that your region of the country will experience a lunar eclipse than a total solar eclipse? umbra
It has been estimated that solar eclipses occur around three times more frequently than lunar eclipses. However, that statistic fully disregards penumbral lunar eclipses.
The total number of solar and lunar eclipses is about equal when penumbral lunar eclipses are taken into account.Eclipses of the sun and moon happen about equally frequently. Because Earth's shadow on the Moon is far greater than the Moon's shadow on Earth during a solar eclipse, lunar eclipses happen more frequently. The probability of seeing a lunar eclipse is therefore higher than the probability of seeing a solar eclipse.When the Moon passes through the shadow of the Earth, a lunar eclipse can be seen from wherever on Earth that the Moon is above the horizon, which covers more than half of the planet. The Moon's shadow, however, is far smaller than Earth's when it seems to move in front of the Sun during a solar eclipse. When projected onto the surface of the Earth, it is only approximately 480 km (300 miles) wide.As a result, only a small portion of the Earth can observe solar eclipses, making it challenging to travel to a spot where one may be seen. They are therefore less frequently visible from any given position.
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an explosion of gas from a hawaiian volcano blows a rock into the sky. the rock has 2000j of kinetic energy. what was its mass if the rock had a velocity of 20m/s? ( ke
The mass of the rock will be 20 kg. This can be determined from the kinetic energy equation, k = 1/2 mv².
What is the straightforward meaning of kinetic energy?Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object. Kinetic energy may be transmitted from one thing to another, for example during collisions, and is determined by the mass of an item and its movement or speed.
How to solve the question?Given in the question,
Kinetic Energy of rock = 2000J
Velocity of rock = 20 m/s
also, k.e. = 1/2 mv²
2000 = 1/2 m × 20²
m = 20 kg
The mass of rock that blew in the sky was 20 kg.
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9. A piece of iron with a mass of 9.8 g has an initial temperature of 32.6°C. As it is heated, it absorbs 365J of energy. What is the final temperature of the iron? (The specific heat of iron is .46 J/g °C)
The final temperature of the piece of iron with the mass of 9.8 grams on the absorption of 365J of energy is 113.56°C.
What is Specific heat capacity?
The specific heat capacity of a material can be defined as the quantity of heat energy (J) which is absorbed per unit mass (kg) of the material when its temperature is increased by 1 K (or 1 °C). The SI unit of specific heat capacity is J/(kg K) or J/(kg °C).
The specific heat capacity of a material can be calculated by the formula:
Q = m × c × ΔT
where, Q = heat energy,
m = mass of the material,
c = specific heat capacity,
ΔT = change in temperature
The final temperature of the piece of iron can be calculated by the formula:
Q = m × c × ΔT
ΔT = (Final temperature - initial temperature)
365J = 9.8 × 0.46 × ΔT
365J = 4.508 × ΔT
ΔT = 80.96
ΔT = Final temperature = initial temperature
ΔT = (T - 32.6)
80.96 = (T - 32.6)
T = 80.96 + 32.6
T = 113.56°C
Therefore, the final temperature of the piece of iron is 113.56°C.
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find the maximum transverse speed of a point on the string. (f) what would be the equation y1x, t2 for this string if it were vibrating in its eighth harmonic?
In a one-dimensional string, a harmonic wave has a maximum transverse velocity and maximum transverse acceleration of 1ms-1 and 1ms-2, respectively.
What is maximum transverse speed of a point on the string?We have attached a harmonic wave with a frequency of 80 Hodge to the string. Additionally, a positive extraction travels at a speed of 12 m/s with an amplitude of 0.025 m. Next, we must create a proper wave function for this wave in the first. In light of this.
we have established that the frequency F is the hurt amplitude is 0.025 m, and the speed is 12 m/s. As a result, given that we are aware of the wave function's writing, we may determine whether or not the sign K x minus omega T applies. Omega, which equals two pi into, is the angular frequency in this case. Thus, we can say that this word has been introduced. 80 is to be purchased That makes 160 by, too.
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a force of 40 n is needed to keep a 10-kg steel box sliding across a level floor with a constant velocity of 8 m/s. what is the net force on the box?
The net force on the box is 40N.
A net force is what?The net force acting on an object is the result of all pushing and pulling forces acting on the object collectively (the sum). If there is an imbalance in the pushing and pulling forces acting on an object, the object will accelerate in the direction of the net force.
According to Newton's second law, an object's acceleration is inversely proportional to its mass and proportional to both the resultant force and the resultant force.
Force = m × a
40 = 10 × a
a = 40/10
a = 4m/s²
Net force ∑F = m×a
∑F = 10 × 4
∑F = 40N.
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Question 8 of 20
You heat a pot of water on a gas stove. Not all the energy from the
combustion of the gas is transformed into thermal energy. What happens to
the rest of the energy released when the gas burns?
OA. It is transformed into light energy.
OB. It is transformed into chemical energy.
C. It is transformed into electrical energy.
OD. It is transformed into nuclear energy.
SUBMIT
Answer:
None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.
Explanation:
a 1,402-kg car rounds an unbanked curve with a radius of 53 m at a speed of 9.9 m/s. what minimum coefficient of friction must exist between the road and tires to prevent the car from slipping?
To keep the car from slipping, the road and tires need to have a minimum coefficient of friction of 0.188.
The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, but it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible. Yes. Because the adhesive forces between molecules are stronger when the contact surface is substantially polished, frictional force increases. In this situation, the friction coefficient will be higher than one.
Here m= 1402 kg
r=53
v= 9.9 m/s
g=9.8
coefficient = (v^2) / rg
coefficient = (9.9^2) / (53*9.8)
coefficient = 98.01/519.4
coefficient = 0.188
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there must be equal amounts of mass on both side of the center of mass of an object.T/F
An object's centre of mass must be surrounded by an equal amount of mass on both sides. It is untrue.
Does an object's centre of mass have to be located there?The centre of mass of an item typically, but not always, sits within the thing itself. For instance, a ball's centre of mass is located in its exact centre, while a book's centre of mass is located in its middle.
When two masses are equivalent, what happens?When two objects of equivalent mass and speed approach one another, they stay together. After staying together, the two surfaces come to rest while retaining motion but losing kinetic energy. several of the energy of motion gets converted to thermal energy, or heat.
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9) During a game of bowling, which of the following describe the ball's motion?(SELECT ALL ANSWERS THAT APPLY)
A) The ball is accelerated while it is pushed by the student's hand due to an
unbalanced force.
B) The ball slows down as it rolls because friction exerts an unbalanced force.
C) The ball is accelerated while it is held in the student's hand due to balanced
Forces.
D) The ball does not change its motion as it rolls because of the balanced force
provided by friction.
E) The ball does not change its motion while it is held in the student's hand due to
balanced forces.
During a game of bowling the ball's motion:
The ball is accelerated while it is pushed by the student's hand due to an unbalanced force.The ball slows down as it rolls because friction exerts an unbalanced force.The ball does not change its motion while it is held in the student's hand due to balanced forces.The correct options are A,B and E.
Description of a bowling ball's motionBowling ball motion is commonly divided into sequential skid, hook, and roll phases. When the ball moves down the lane in the skid and hook phases, frictional contact with the lane causes the ball's forward (translational) speed to continually decrease, but to continually increase its revolution rate (rotational speed).
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Uing two billiard ball and 3 to 4 entence decided experiment to demontrate the law of conervation of momentum. (4 point)
So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.
What is momentum?Momentum is a commonly used term in sports. A team that has the momentum is on the move and is going to take some effort to stop. A team that has a lot of momentum is really on the move and is going to be hard to stop. Momentum is a physics term; it refers to the quantity of motion that an object has. A sports team that is on the move has the momentum. If an object is in motion (on the move) then it has momentum.Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving. Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.To learn more about velocity refer to:
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a 65 kg person dives into the water from the 10 m platform. a. what is her speed as she enters the water?
The speed of the person as she enters the water is 14.2 m/s.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy that an object has due to its motion. This energy can be transferred from one object to another or converted into other forms of energy. Kinetic energy is dependent on an object's mass and its velocity. The greater an object's mass or velocity, the more kinetic energy it has. Kinetic energy can be used to do work, such as powering a machine or vehicle. It can also be used to generate electricity or to heat up objects.
The speed of the person as she enters the water can be calculated using the equation for kinetic energy:
KE = ½mv²
Where m is the mass of the person (65 kg) and v is the speed.
Solving for v, we get:
v = √(2KE/m)
Since the potential energy of the person just before she enters the water is equal to the kinetic energy of the person just after she enters the water, we can calculate the kinetic energy as:
PE = mgh
KE = mgh
Where m is the mass of the person (65 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height of the platform (10 m).
Plugging this into the equation for v, we get:
v = √(2mgh/m)
v = √(2gh)
v = √(2*9.8*10)
v = 14.2 m/s
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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?
The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.
To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.
Now, we know that momentum =mass × velocity
So, initial momentum of first object=6.2×3=18.6Kg-m/sec
Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec
Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg
Now, both objects are moving with common velocity, so assume both have velocity v
=>So, final momentum of both objects is =14.2×v
according to law of conservation of momentum
=>18.6+25=14.2v
=>43.6=14.2v
=>v=43.6/14.2
=>v=3.07m/sec
Hence, final velocity of objects are 3.07m/sec.
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Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.
The volume of the toy is 80 ml.
To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.
In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.
The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.
It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.
Answer:
Volume of the toy: [tex]80\; {\rm mL}[/tex].
Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)
Explanation:
The graduated cylinder initially measures the volume of water in this cylinder:
[tex]V(\text{water}) = 70\; {\rm mL}[/tex].
Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:
[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].
Rearrange to find the volume of the toy:
[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].
To find the average density of this toy, divide mass by volume:
[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].
a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:
The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
How to find velocity ?To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:
Mass flow rate = Density * Flow rate
= Density * (Area * Velocity)
Where:
Density is the density of the fluid
Flow rate is the volume flow rate, or the rate at which volume flows through the pipe
Area is the cross-sectional area of the pipe
Velocity is the velocity of the fluid
The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.
The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:
A = pi * r^2
Where:
A is the cross-sectional area of the pipe
r is the radius of the pipe
The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:
A = pi * (1.5 cm)^2
= 7.07 cm^2
The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:
A = pi * (3 cm)^2
= 28.27 cm^2
Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:
(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)
Solving for v, the velocity on the narrow side, you get:
v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)
= 11.6 m/s
The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
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Where does the depenent variable go on a graph?
The dependent variable go on the Y-axis on a graph.
what is a dependent variable?The dependent variable is described as the variable that is being measured or tested in an experiment.
Dependent variable can be explained using the example where a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it.
The independent variable is found on the x-axis (horizontal line) of the graph and the dependent variable is displayed on the y-axis.
The difference between independent variable and the dependent variable is that in an experiment, the independent variable is the variable that is varied or manipulated by the researcher.
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the force between between two objects increases by what factor if the distance between them is changed 4.5 times the original separation?
The new gravitational force between the object will be 1/20.25 times of the original force.
The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,
F = GMm/R²
Here,
G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.
As per the given question the distance between the object is increased 4.5 times the original separation.
R' = 4.5R.
The new force of attraction between the object will be,
F' = GMm/(R')²
F' = GMm/(4.5R)²
F' = GMm/20.25R²
F' = F/20.25
So, the new force of attraction between the two objects will become 1/20.25 times of original force.
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when you look at a single slit diffraction pattern produced on a screen by light of a single wavelength, you see a bright central maximum and a number of maxima on either side, their intensity decreasing with distance from the central maximum. if the wavelength of the light is increased:_____.
The pattern gets bigger as the light wave length gets longer. other maxima are further from the central one and are wider.
What wavelength does it have?A wavelength is the distance between two identical locations (adjacent crests) in successive cycles in a waveform signals that is transmitted by a wire or in space. Typically, this length is expressed in feet (m), millimeters (cm), or millimeters (mm) in wireless systems (mm).
What do wavelengths and frequencies refer to?The distance that separates two wave crests is known as the wavelength, and it also applies to troughs. The number of vibrations that pass across a certain area in a second, or 60hz (Hz), is the unit of measurement for frequency (Hertz).
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A 20 kg wagon is pulled along the level ground by a rope inclined 30 degrees above the horizontal (friction is
negligible) (A) How large is the pulling force is the wagon accelerates of .40 m/s²? (B) What is the normal force of
the wagon?
Answer:
(A) 9.2 Newtons
(B) 200.8 Newtons
Explanation:
Attached is the free body diagram I drew along with some of the work/formulas I used. Please ask me any questions you have in the comments about my diagram/work. I'd be happy to walk you through it.
- Determine the tension in each cable in the diagram to the right.
Tension of the three cables connecting the celling, 7 kg ball, 4 kg ball, 5 kg ball respectively 156.8 N, 88.2 N and 49 N.
What is tension?The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
Tension of the cable connecting the celling and 7 kg ball:
= (7 kg + 4 kg + 5Kg) × 9.8 m/s²
= 156.8 N.
Tension of the cable connecting the 7kg ball and 4 kg ball:
= (4 kg + 5Kg) × 9.8 m/s²
= 88.2 N.
Tension of the cable connecting the 4kg ball and 5 kg ball:
= 5Kg× 9.8 m/s²
= 49 N.
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x-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequency. suppose an x-ray camera uses x-rays with a wavelength of 4.04. calculate the frequency of the x-rays.
If an X-ray camera uses X-rays with a wavelength of 4.04. the frequency of the x-rays is 36.9 PHz.
Compared to ultraviolet rays and gamma rays, X-rays have a wavelength of 0.01–10 nm, which corresponds to frequencies in the range of 3×10⁻¹⁶–3×10⁻¹⁹ Hz and energies in the range of 100 eV to 100 keV.
using, C=Lf,
Where C is the speed of light,
L stands for wavelength
Given,
C= 8.13 nm = 8.13* 10-9 m
f=C/L
f= (3x108m/s) / (8.13^ 10-9 m)
f= 3.69 x1016Hz (10 PHz = 1016Hz)
hence frequency, f= 36.9 PHz
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a mass m at the end of a spring oscillates with a frequency of 0.83 hz. when an additional 780-g mass is added to m, the frequency is 0.60 hz. what is the value of m?
Given the following data:
Initial frequency = 0.83 Hz.
Additional mass = 780 grams to kg = 0.78 kg
New frequency = 0.60 Hz
To determine the value of the initial mass, m, we would apply the following formula:
;f=1/2л⟌k/m
Where:
F is the frequency.
m is the mass
k is the spring constant.
For mass (m):
0.83=1/2л⟌k/m ...equation 1.
For additional mass:
0.60=1/2⟌k/m+0.78 ...equation 2.
Next, we would divide eqn. 1 by eqn. 2:
;0.83/0.60=1/2л⟌((k/m)/1)/2л⟌m+0.78
1.3833=⟌k/m/⟌k/m+0.78
Taking the square of both sides, we have:
1.9135=k/m/k/m+0.78
1.9135=k/m×m+0.78/k
1.9135=m+0.78/m
1.9135m-m=0.78
0.9135m=0.78
m=0.78/0.9135
m=0.8538kg
the value of mass is 0.8538.
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