Tenim tres resistors en sèrie, calcula la tensió que hi haurà a cadascuna d'elles sabent que una d'elles és de 680 Ω i les altres són de 220 Ω. El generador té una tensió de 12V.

Answers

Answer 1

Resposta:

Per a càrrega de 680Ω: 7,27 volts

Per a les dues càrregues de 220Ω: 2,36 volts cadascuna

Explicació:

Segons la llei d’ohms

E = IRt

E és la força electromotriu = 12V

I és el corrent total que circula al circuit

Rt és la resistència equivalent total

Com que els 680Ω, 220Ω i 220Ω estan en sèrie;

Rt = 680 + 220 + 220

Rt = 1120Ω

Obteniu el corrent total del circuit:

Recordem que: E = IRt

I = E / Rt

I = 12/1120

I = 0,0107A

Tingueu en compte que el mateix corrent flueix a través de resistències connectades en sèrie, però tensions diferents.

Obteniu les tensions individuals;

Per a càrrega de 680Ω;

V = IR

V = 0,0107 * 680

V = 7,27 Volts

Per a la càrrega de 220Ω

V = IR

V = 220 (0,0107)

V = 2,36 volts

Per tant, les tensions de les dues càrregues de 220Ω seran de 2,36 volts cadascuna


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