Answer:-3x2-5x+2
Step-by-step explanation:
Distribute -2x to x+3, and then x+1 to x-2
[tex]-2x^{2}[/tex] [tex]-6x[/tex] [tex]-x(x-2)+1(x-2)[/tex]
[tex]-2x^{2} -6x-x^{2} +2x+1x-2[/tex]
[tex]-3x^{2} -3x-2[/tex]
Sorry it’ll be -3x2 -5x +2
a car can complete journey of 300 km with the average speed of 60 km per hour how long does it take to complete the journey what is the speed of the car if it covers only 200 km in the same interval of the time
please I need help urgent
Answer:
a. 5 hours
b. 40 kph
Step-by-step explanation:
300 km ÷ 60 km = 5 hours
200 km ÷ 5 hours = 40 kilometers per hour
points V W X Y and Z are collinear, VZ= 52, XZ =20, and WX=XY=YZ find the indicated length
21.) WX 22.) VW 23.) WY 24.) VX 25.) WZ 26.) VY
Answer:
WX=10; VW=22; WY=20; VX=32; WZ=30;VY=42
Step-by-step explanation:
1)WX=XY=XZ/2=20/2=10
2)VW=VZ-WX-XY-YZ=VZ-3*WX=52-3*10=52-30=22
3)WY=WX+XY=2*WX=2*10=20
4)VX=VW+WX=22+10=32
5)WZ=WX+XY+YZ=3*WX=3*10=30
6)VY=VZ-YZ=52-10=42
The points V, W, X, Y and Z are collinear. The indicated lengths are
[tex]WX=10\\VW=22\\WY=20\\VX=32\\WZ=30\\VY=42[/tex]
Given :
points V, W, X, Y and Z are collinear, VZ= 52, XZ =20, and WX=XY=YZ
Lets make diagram using the given information
The diagram is attached below
XY=YZ
XZ=20, so [tex]XY+YZ=20\\Both XY and YZ are same\\XY+XY=20\\2XY=20\\Divide \; by \; 2\\XY=10[/tex]
[tex]WX=XY=YZ \\XY=10\\WY=10\\YZ=10\\[/tex]
Now we find out VW
[tex]VW+WX+XY+YZ=52\\VW+10+10+10=52\\VW+30=52\\Subtract \; 30\\VW=52-30\\VW=22[/tex]
Now we find the indicated length
[tex]WX =10[/tex]
[tex]VW=22\\WY=WX+XY=10+10=20\\VX=VW+WX=22+10=32\\WZ=WX+XY+YZ=10+10+10=30\\VY=VW+WX+XY=22+10+10=42[/tex]
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Consider this equation. tan) 19 17 If 8 is an angle in quadrant II, what is the value of Cos() OA. 19 6 OB. 17 6 O c. V18 6 OD. 17
Using trigonometric identities, it is found that the value of [tex]\cos{\theta}[/tex] is given by:
B. [tex]\cos{\theta} = \frac{\sqrt{17}}{6}[/tex]
What is the tangent of an angle?It is given by the division of it's sine by it's cosine, that is:
[tex]\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}[/tex]
In this problem, the equation given is:
[tex]\tan{\theta} = -\sqrt{\frac{19}{17}}[/tex]
That is:
[tex]\frac{\sin{\theta}}{\cos{\theta}} = -\sqrt{\frac{19}{17}}[/tex]
[tex]\sin{\theta} = -\sqrt{\frac{19}{17}}\cos{\theta}[/tex]
The following identity is applied:
[tex]\sin^2{\theta} + \cos^2{\theta} = 1[/tex]
Then:
[tex]\left(-\sqrt{\frac{19}{17}}\cos{\theta}\right)^2 + \cos^2{\theta} = 1[/tex]
[tex]\frac{36}{17}\cos^2{\theta} = 1[/tex]
[tex]\cos^2{\theta} = \frac{17}{36}[/tex]
[tex]\cos{\theta} = \frac{\sqrt{17}}{6}[/tex]
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Answer:
Hi sorry I just wanted to ask is it B or D? positive or negative?
Step-by-step explanation:
edmentum is the worst
I'll give brainliest :)
Are the lines y = –x – 4 and 5x + 5y = 20 perpendicular? Explain.
Yes; the product of their slopes is −1.
Yes; their slopes are equal.
No; their slopes are equal.
No; their slopes are not equal
Answer:
C
Step-by-step explanation:
In the equation y = -x - 4, the gradient is -1.
While in the second equation,
5x + 5y = 20
y = -x + 4
So the gradient is -1 too
Both sides are not perpendicular to each other because if you apply the formula, m1m2 = -1, and if substitute both gradient, (-1)(-1) = 1 ≠ -1
Therefore, no they are not perpendicular but parallel instead.
Answer: C
Step-by-step explanation:
Look above fool
A vehicle is travelling from rest. After 10 seconds its velocity will be 20ms find acceleration?
Initial velocity (u) = 0m/s
Final velocity (v) = 20m/s
Time (t) = 10 s
Acceleration (a)
= (v - u)/t
= [(20m/s) - (0m/s)]/10s
= (20m/s)/10s
= (20m/s²)/10
=> 2m/s²
enter the repeating digit
[tex] \frac{9}{11} [/tex]
Answer:
Step-by-step explanation:
[tex]\frac{9}{11}=0 .818181....[/tex]
__
= 0.81
please help asap it's important!!!
Answer:
486cm^2
Step-by-step explanation:
Surface area of cube = (6a^2)
6×9×9=486.
find the length of a line joining the point ( 4,3 ) and origin .
Answer:
i think you have to count till you get to 4 or 3 then the remaining you plus with the 3
Answer:
[tex]d=5[/tex]
Step-by-step explanation:
you have to use the distance formula, making the origin (0,0) the 1st point and (4,0) the second point.
[tex]d=\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2} }[/tex]
[tex]d=\sqrt{(4-0)^{2}+(3-0)^2 }[/tex]
[tex]d=\sqrt{(4)^2+(3)^2}[/tex]
[tex]d=\sqrt{16+9}[/tex]
[tex]d=\sqrt{25}[/tex]
[tex]d=5[/tex]
The two cones below are similar. What is the value of x?
Cone 1
Height = 10
Radius = 3
Cone 2
Height = 3
Radius = x
A. 0.3
B. 0.9
C. 0.09
D. 0.18
Answer:
If they are similar, the ratio of 10/3 should be the same as the 3/x
then solve
10/3 = 3/x
cross multiply
10x=8
x = 9/10
so C. is the right answer
The missing value in the smaller cone is 0.9 units.
What is similarity?Similarity in math is a concept that relates to the shape and size of figures. Two figures are similar if they have the same shape, but not necessarily the same size.
Given that, two similar cones, we need to find the value of x in the smaller cone,
Since, the cones are similar, then according to the definition of similarity,
we know that the dimensions will be in equal proportion,
Let the dimensions of the big cone be H (height) and R (radius) and that of smaller cone be h (height) and r (radius)
So,
H / R = h / r
10 / 3 = 3 / x
x = 9/10
x = 0.9
Hence, the missing value in the smaller cone is 0.9 units.
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Two friends are writing practice problems to study for a trigonometry test. Sam writes the following problem for his friend Anna to solve:
In right triangle ABC, the measure of angle C is 90 degrees, and the length of side c is 8 inches.
Solve the triangle.
Anna tells Sam that the triangle cannot be solved. Sam says that she is wrong.
Who is right? Explain your thinking
Answer:
Anna is right in her meaning concerning on triangle solvability.
Step-by-step explanation:
The side [tex]c[/tex] represents the hypotenuse of a right triangle as [tex]C = 90^{\circ}[/tex] and is opposite to that angle. There are two ways to solve this triangle trigonometrically:
i) Law of Sine
[tex]\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}[/tex] (1)
ii) Law of Cosine
[tex]c^{2} = a^{2} + b^{2} - 2\cdot a\cdot b \cdot \cos C[/tex] (2)
The Pythagorean Theorem is a particular case of the Law of Cosine for [tex]C = 90^{\circ}[/tex]
The triangle cannot be solved as there is an input missing, either another side or another angle. If [tex]C = 90^{\circ}[/tex], then (2) is reduced into this form:
[tex]c^{2} = a^{2}+b^{2}[/tex] (2b)
In this case we need to know the measure of either [tex]a[/tex] or [tex]b[/tex] to determine its counterpart and the values of the missing angles by (1). In nutshell, Anna is right.
The access code for a cars security system consists of 4 digits. The first digit cannot
be 0 and the last digit nust be even. How many different codes are available?
Answer:
4500
Step-by-step explanation:
The first digit can't be 0. so it will be a number from 1000 to 9999. That's a total of 9000 numbers (9999-1000+1=9000). Since the last digit must be an even number that is one half of the 9000 numbers which is 4500.
If you apply the changes below to the absolute value parent function, 1(x) = 1X, what is the equation of the new function? Shift 8 units left. • Shift 3 units down. O A. g(x) = (x + 81 - 3 O B. g(x) B. g(x) = (x - 3| + 8 O c. g(x) = [X - 31- 8 D. g(x) = (x - 8 - 3
Answer:
A. g(x) = |x + 8| - 3Step-by-step explanation:
If the function is f(x), then shift 8 units left and 3 units down will result in:
g(x) = f(x + 8) - 3Apply to the given function to get:
g(x) = |x + 8| - 3Correct choice is A
Please help with this question
Answer:
-3.662rad × 180/π = -209.8°
Step-by-step explanation:
Answer:
1 degree = .01745329 radians
1 radian = 57.2957877856 degrees
-209.8 degrees = .01745329 * -209.8 =
-3.66170024200 radians
Step-by-step explanation:
Correct answer gets 5 stars and brainliest
Answer:
Does the answer help you?
Answer:
D
Step-by-step explanation:
Using the converse of Pythagoras' identity.
If the square of the longest side is equal to the sum of the squares on the other two sides then the triangle is right.
longest side = 12 and 12² = 144
5² + 8² = 25 + 64 = 89
Since 5² + 8² ≠ 12² , then triangle is not right → D
please help me!!! :)
Answer:
C
Step-by-step explanation:
f(x) = x-8 when x>3, f(7)=7-8=-1
arrange0.2,¼,30%,10%in ascending and descending order
Answer:
Ascending- 10%, 0.2, 1/4, 30%
Descending- 30%, 1/4, 0.2, 10%
Step-by-step explanation:
0.2 = 2/10 = 4/20
1/4 = 5/20
30% = 30/100 = 6/20
10% = 10/100 = 2/20
Ascending
-2/20, 4/20, 5/20, 6/20
- 10%, 0.2, 1/4, 30%
Descending
- 6/20, 5/20, 4/20, 2/20
- 30%, 1/4, 0.2, 10%
Select the correct answer. Consider this system of equations, where function f is quadratic and function g is linear:
y = f(x)
y = g(x)
Which statement describes the number of possible solutions to the system?
A. The system may have no, 1, 2, or infinite solutions.
B. The system may have no, 1, or infinite solutions.
C. The system may have 1 or 2 solutions.
D. The system may have no, 1, or 2 solutions
Answer:
C is the answer
Step-by-step explanation:
Quadratic equations have at most 2 solution, and linear equations only have 1 solution, and since y is equal to both of them, it can only have 1 or 2 solutions.
The correct answer is option D. The system may have no, 1, or 2 solutions
What is quadratic equation?A quadratic equation is a second-order polynomial equation in a single variable x , ax²+bx+c=0. with a ≠ 0 .
f(x) is a quadratic function and g(x) is linear function
y=f(x)
y=g(x)
Quadratic equations have at most 2 solution
linear equations only have 1 solution,
f(x)=g(x)=y
y is equal to both of them, it can only have 1 or 2 solutions.
A line and a parabola can intersect zero, one, or two times
Therefore, a linear and quadratic system can have zero, one, or two solutions
Hence, the correct answer is option D. The system may have no, 1, or 2 solutions
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WORKED EXAMPLES
Try Vertical Angle Problems
ZC and Dare vertical angles.
m_C=° and mZD=(-3x +80)°
What is mZC
Enter your answer in the box.
Answer:
M<C = 20°
Step-by-step explanation:
Because they’re vertical angles, that means they’re equal to each other so:
m<C = m<D
x = -3x + 80
x + 3x = 80
4x = 80
x = 20
Since m<C equals x, that means m<C is 20°
Solve for a.
-4a – 2a – 7 = 11
a =
[?]
Answer:
or, -4a - 2a -7 = 11
or, -4a -2a =11 +7
or, - 6a = 18
or, a= 18÷ -6
a= -3
The number 804 is divisible by what numbers?
Answer: 804 is divisible by 1, 2, 3, 4, 6, 12 ,67 ,134 ,201, 268, 402 ,804
Answer:
The factors of 804 are: 1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402,804.
Step-by-step explanation:
21 is 35% of what number (shown work)
Answer:
60
Step-by-step explanation:
Is means equals and of means multiply
21 = 35% * n
21 = .35*n
Divide each side by .35
21/.35 = .35n/.35
60 = n
Answer:
60
Step-by-step explanation:
35% of 60 is 21 its that simple
Two points, A and B, are on opposite sides of a building. A surveyor chooses a third point, C, 80 yd from B and 104 yd from A, with angle ACB
measuring 51.2º. How far apart are A and B (to the nearest yard)?
HURRYYY GIVING 20 POINTS!!
Answer:
Step-by-step explanation:
The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. The distance between A and B is 85.6 yds.
What is the Law of Cosine?The law of cosine helps us to know the third side of a triangle when two sides of the triangle are already known the angle opposite to the third side is given. It is given by the formula,
[tex]c =\sqrt{a^2 + b^2 -2ab\cdot Cos\theta}[/tex]
where
c is the third side of the triangle
a and b are the other two sides of the triangle,
and θ is the angle opposite to the third side, therefore, opposite to side c.
The three points A, B, and C will form a triangle. Therefore, using the law of cosine the measure of the third side AB can be written as,
[tex]AB =\sqrt{(AC)^2 + (BC)^2 -2(AC)(BC)\cdot \cos(51.2^o)}\\\\AB =\sqrt{(80)^2 + (104)^2 -2(80)(104)\cdot \cos(51.2^o)}\\\\AB = \sqrt{6400+10816-16640\cos51.2^o}\\\\AB = \sqrt{7328.4}\\\\AB=85.6\rm\ yd[/tex]
Hence, the distance between A and B is 85.6 yds.
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In a large midwestern university (the class of entering freshmen being on the order of 6000 or more students), an SRS of 100 entering freshmen in 1999 found that 20 finished in the bottom third of their high school class. Admission standards at the university were tightened in 1995. In 2001 an SRS of 100 entering freshmen found that 10 finished in the bottom third of their high school class. The proportion of all entering freshmen in 1999 and 2001, who graduated in the bottom third of their high school class, are p1 and p2, respectively.Is there evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced, as a result of the tougher admission standards adopted in 2000, compared to the proportion in 1999? To determine this, you test the hypothesesH0 : p1 = p2 , Ha : p1 > p2.The P-value of your test isA. 0.976.B. 0.024.C. 0.048.D. 0.001.
Answer:
B. 0.024
The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.
Step-by-step explanation:
Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
1999:
Of 100, 20 were in the bottom thid. So
[tex]p_B = \frac{20}{100} = 0.2[/tex]
[tex]s_B = \sqrt{\frac{0.2*0.8}{100}} = 0.04[/tex]
2001:
Of 100, 10 were in the bottom third, so:
[tex]p_A = \frac{10}{100} = 0.1[/tex]
[tex]s_A = \sqrt{\frac{0.1*0.9}{100}} = 0.03[/tex]
To determine this, you test the hypotheses H0 : p1 = p2 , Ha : p1 > p2.
Can also be rewritten as:
[tex]H_0: p_B - p_A = 0[/tex]
[tex]H_1: p_B - p_A > 0[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{s}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
From the sample:
[tex]X = p_B - p_A = 0.2 - 0.1 = 0.1[/tex]
[tex]s_A = \sqrt{s_A^2+s_B^2} = \sqrt{0.03^2+0.04^2} = 0.05[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{0.1 - 0}{0.05}[/tex]
[tex]z = 2[/tex]
P-value of the test and decision:
The p-value of the test is the probability of finding a difference of proportions of at least 0.1, which is 1 subtracted by the p-value of z = 2.
Looking at the z-table, z = 2 has a p-value of 0.976.
1 - 0.976 = 0.024, so the p-value is given by option B.
The p-value of the test is 0.024 < 0.05(standard significance level), which means that there is enough evidence that the proportion of freshmen who graduated in the bottom third of their high school class in 2001 has been reduced.
Simplify the following, leaving your answer with a positive exponent:
x^-12/ x^-7
Answer:
[tex]\frac{1}{x^{5} }[/tex]
Step-by-step explanation:
x^-12/ x^-7
= x^(-12-(-7))
= x^-5
= 1/x^5
Instructions: Find the value of the trigonometric ratio. Make sure to
simplify the fraction if needed.
Х
40
32
N
24
Y
Tan Z
Answer:
tan Z = 4/3
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta= opp / adj
tan Z = 32/24
Divide top and bottom by 8
tan Z = 4/3
Which is the graph of y = RootIndex 3 StartRoot x EndRoot?
Given:
The equation is:
[tex]y=\sqrt[3]{x}[/tex]
To find:
The graph of the given equation.
Solution:
We have,
[tex]y=\sqrt[3]{x}[/tex]
The table of values is:
x y
-8 -2
-1 -1
0 0
1 1
8 8
Plot these points on a coordinate plane and connect them by a free hand curve as shown in the below graph.
Answer:
D
Step-by-step explanation:
edge 2020
Alonso overdrew his bank account and his account balance showed -$50. He spent an
additional $37 going out to the movies with friends. Write an expression and draw a line
number to determine Alfonso's current bank account balance.
Answer:
-$87
Step-by-step explanation:
SEE THE IMAGE FOR SOLUTION
HOPE IT HELPS
HAVE A GREAT DAY
what is the answer to 7b-7-8b= -15
Answer:
b=8
Step-by-step explanation:
7b-7-8b=-15
Combine like terms
-b-7=-15
Add 7 on both sides
-b=-15+7
-b=-8
Divide by -1
b = 8
Answer: b = 8
Step-by-step explanation:
Given
7b - 7 - 8b = -15
Combine like terms
-b - 7 = -15
Add 7 on both sides
-b - 7 + 7 = -15 + 7
-b = -8
Divide -1 on both sides
-b / -1 = -8 / -1
b = 8
Hope this helps!! :)
Please let me know if you have any questions
What are the solutions to the system of equations graphed below?
Answer:
The answer is B (4, 8) and (0, -8)
The probability of drawing a red candy at random from a bag of 25 candies is 2/5. After 5 candies are removed from tehe bag, what is the probability of randomly drawing a red candy from the bag?
Given:
The probability of drawing a red candy at random from a bag of 25 candies is [tex]\dfrac{2}{5}[/tex].
To find:
The probability of randomly drawing a red candy from the bag after removing 5 candies from the bag.
Solution:
Let n be the number of red candies in the bag. Then, the probability of getting a red candy is:
[tex]P(Red)=\dfrac{\text{Number of red candies}}{\text{Total candies}}[/tex]
[tex]\dfrac{2}{5}=\dfrac{n}{25}[/tex]
[tex]\dfrac{2}{5}\times 25=n[/tex]
[tex]10=n[/tex]
After removing the 5 candies from the bag, the number of remaining candies is [tex]25-5=20[/tex] and the number of remaining red candies is [tex]10-5=5[/tex].
Now, the probability of randomly drawing a red candy from the bag is:
[tex]P(Red)=\dfrac{5}{20}[/tex]
[tex]P(Red)=\dfrac{1}{4}[/tex]
Therefore, the required probability is [tex]\dfrac{1}{4}[/tex].