[tex]inverse function of \frac{3^x+2}{3^x-5}[/tex]

Hi there!  

»»————-　★　————-««

I believe your answer is:  

(-3, -1) and (1, 3)

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex]{ \tt{y = x + 2 - - - (a)}} \\ { \tt{ {x}^{2} + {y}^{2} = 10 - - - (b) }} \\ substitute \: for \: y \: in \: (b) : \\ { \tt{ {x}^{2} + {(x + 2)}^{2} = 10 }} \\ { \tt{ {x}^{2} + {x}^{2} + 4x + 4 = 10 }} \\ { \tt{2 {x}^{2} + 4x - 6 = 0}} \\ { \tt{ {x}^{2} + 2x - 3 = 0 }} \\ { \boxed{ \bf{x = 1 \: and \: - 3}}} \\ in \: (a) : \\ y = x + 2 \\ { \boxed{ \bf{y = 3 \: and \: - 1}}}[/tex]

Answer:

20 degree

Step-by-step explanation:

x + x + 70 = 110 degree (sum of two opposite interior angle equal to the exterior angle formed)

2x = 110 - 70

x = 40/2

x = 20 degree

Answer:

433 in.²

Step-by-step explanation:

Divide the figure into 2 rectangles

Area of the figure = area of the bigger rectangle + area of smaller rectangle

✔️Area of bigger rectangle = L*W

L = 29 in.

W = 13 in.

Area of the bigger rectangle = 29*13

= 377 in.²

✔️Area of the smaller rectangle = L*W

L = 7 in.

W = 8 in.

Area of the bigger rectangle = 7*8

= 56 in.²

✅Area of the figure = 377 + 56 = 433 in.²

Answer:

A = [12 + 9(pi)] yd^2 = 40.3 yd^2

Step-by-step explanation:

A = area of triangle + area of semicircle

A = bh/2 + (pi)r^2

A = (6 yd)(4 yd)/2 + (pi)(3 yd)^2

A = 12 yd^2 + 9(pi) yd^2

A = [12 + 9(pi)] yd^2 = 40.3 yd^2

Answer:

y=179x

Y=105x+2046

Step-by-step explanation:

Answer:

Step-by-step explanation:

From the given information:

ΔG° = -30.5 kJ/mol

By applying the following equation to calculate the value of K.

ΔG° =-RT㏑K

making ㏑ K  the subject of the formula:

[tex]\mathtt{ In \ K} = \dfrac{\Delta G^0}{-RT}[/tex]

where;

Temperature at 25° C = (25 + 273)K

= 298K

R = 8.3145 J/mol.K (gas cosntant)

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-(8.3145 \ J/mol. K \times 298 \ K}[/tex]

[tex]\mathtt{ In \ K} = \dfrac{-30.5 \times 10^{3}\ J /mol} {-2477.721 J/mol }[/tex]

㏑K = 12.309

[tex]K = e^{12.309}[/tex]

K = 221682.17

K = 2.22 × 10⁵

b) The reaction for the metabolism of glucose is given as:

[tex]C_6H_{12} O_6 + 6O_{2(g)} \to + 6CO_{2(g)} + 6H_2O_{(l)}[/tex]

From the above expression, let calculate the Gibbs free energy by using the formula:

[tex]\Delta G^0_{rx n }= \Delta G^0_{product}- \Delta G^0_{reactant}[/tex]

[tex]\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)][/tex]

At standard conditions;

The values of corresponding compounds are substituted into the equation above:

Thus,

[tex]\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -3786 +911 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875 \ kJ/mol[/tex]

[tex]\Delta G^0_{rx n }= -2875000 \ J/mol[/tex]

Now, the no of ATP molecules generated = [tex]\dfrac{\Delta G^0 \text{of metabolism for glucose}}{\Delta G^0 \text{of hydrolysis for ATP}}[/tex]

= (-2875000 J/mol ) / -30500 J/mol

= 94.26

≅ 94 ATP molecules generated

Answer:

h(t) = -16t2 + 186t + 43

at the ground h = 0

hence;  -16t2 + 186t + 43 = 0  

solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 - 4ac)1/2)/2a

gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)

Step-by-step explanation:

Answer:

−7.361097448

Step-by-step explanation:

Answer:

0.0597in/s

Step-by-step explanation:

The volume of the spherical balloon V= 4/3πr³

r is the radius of the balloon

The rate at which the volume is changing dV/dt is expressed as;\

dV/dt = dV/dr*dr/dt

dV/dr = 3(4/3πr²)

dV/dr = 4πr²

dV/dr = 4π(2)²

dV/dr = 16π

dV/dt = 3 in³/s

Substitute inti the formula

3 = 16πdr/dt

dr/dt = 3/16π

dr/dt = 3/50.24

dr/dt = 0.0597in/s

Hence the balloon is increasing at the rate of 0.0597in/s

i think the correct answer is 2 hours and 10 mins

Answer:

1865.16 m^2

Step-by-step explanation:

first let 's find radius of a circle

radius=diameter/2

=18/2

=9 m

area of a cylinder=2πrh+2πr2

=2*3.14*9*24 + 2*3.14*(9)^2

=1356.48 + 2*3.14*81

=1356.48 + 508.68

=1865.16 m^2

Answer:

1866.11 m²

Step-by-step explanation:

Formula = 2πrh + 2πr²

Surface area = 2 * 3.14 * 9 * 24 + 2*3.14* 81 ≈ 1866.11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

[tex] \frac{7}{4} - \frac{3}{4} = \frac{4}{4} [/tex]

Step-by-step explanation:

To find the number midway between 3/2 and 4/2, add them up and divide by 2

we have, 3/2 + 4/2 = 7/2

7/2 ÷ 2 = 7/4

Repeat the same for the number midway between 1/2 and 2/2 to get 3/4

The answer then is, 7/4 - 3/4 = 4/4

Answer:

y=2x-1

Step-by-step explanation:

Answer:

[tex]95 - \frac{3}{4} [/tex]

[tex] = \frac{95}{1} - \frac{3}{4} [/tex]

[tex] = \frac{380}{4} - \frac{3}{4} [/tex]

[tex] = \frac{380 - 3}{4} [/tex]

[tex] = \frac{377}{4} [/tex]

[tex] = 376\frac{1}{4} [/tex]

Answer:

The ball reaches the maximum height after 1 seconds

Step-by-step explanation:

Given

[tex]y = -16t^2 + 32t + 4[/tex] --- the function missing from the question

Required

Time to reach maximum height

The time (t) to reach maximum height is calculated using:

[tex]t = -\frac{b}{2a}[/tex]

Where

[tex]y =at^2 + bx + c[/tex]

So, by comparison:

[tex]a = -16[/tex]

[tex]b = 32[/tex]

[tex]c = 4[/tex]

So, we have:

[tex]t = -\frac{b}{2a}[/tex]

[tex]t = -\frac{32}{2*-16}[/tex]

[tex]t = -\frac{32}{-32}[/tex]

[tex]t = \frac{32}{32}[/tex]

[tex]t = 1[/tex]

Answer:

uₙ₊₁ = uₙ + ¹/₂

Step-by-step explanation:

uₙ₊₁ = uₙ + d

u₈ = 3

u₁₀₀ = 49

We can establish the following:

u₉ = 3 + d

u₁₀ = (3 + d) + d = 3 + 2d

u₁₁ = (3 + 2d) + d = 3 + 3d

so...

u₈₊ₐ = 3 + ad

u₁₀₀ = u₈₊₉₂ = 3 + 92d

3 + 92d = 49

92d = 46

d = ¹/₂

∴ uₙ₊₁ = uₙ + ¹/₂

mid point =((4+(-4))/2,(-5+5)/2)

=(0,0)

The midpoint between the points (4, -5) and (-4, 5) is (0, 0).

To find the midpoint between two points ([tex]x_1, y_1[/tex]) and ([tex]x_2, y_2[/tex]), you can use the midpoint formula:

Midpoint = [tex]((x_1+ x_2)/2, (y_1+ y_2)/2)[/tex]

In this case, the two points are (4, -5) and (-4, 5).

So, the midpoint using the formula:

[tex]x_1[/tex] = 4

[tex]y_1[/tex] = -5

[tex]x_2[/tex]= -4

[tex]y_2[/tex] = 5

Midpoint

= ((4 + (-4)) / 2, (-5 + 5) / 2)

= (0 / 2, 0 / 2)

= (0, 0)

Therefore, the midpoint between the points (4, -5) and (-4, 5) is (0, 0).

Learn more about midpoint here:

https://brainly.com/question/24089949

#SPJ2

Step-by-step explanation:

the other answer is correct.

just for a little bit of explanation :

the first position after the decimal point is for tenths. the second position for hundredths. the third for thousandths. then ten-thousandths, hundred-thousandths, millionths, ...

so, you would need 1000 thousandths to have a 1 at the first position before the decimal point. everything less than that has to be a number after the decimal point. and thousandths have to end (writing from left to right) with the thousandths-position. hundredths with the hundredths-position and so on.

Step 1: 360÷30(exterior angle)= 12 sides

Step 2: (12-2)×180= 1800 (sum of the interior angles of the polygon)

Test: 1800÷ 12 sides= 150 ( 1 interior angle)

Answer:

[tex]x^2 + y^2 = 52[/tex]

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Equation of a circle:

The equation of a circle with center [tex](x_0,y_0)[/tex] and radius r has the following format:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

Center at the origin;

This means that [tex]x_0 = 0, y_0 = 0[/tex]

So

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

[tex](x - 0)^2 + (y - 0)^2 = r^2[/tex]

[tex]x^2 + y^2 = r^2[/tex]

Passes through (4, 6)

The radius is the distance from this point to the center. So

[tex]r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]r = \sqrt{(4-0)^2+(6-0)^2}[/tex]

[tex]r = \sqrt{16+36}[/tex]

[tex]r = \sqrt{52}[/tex]

So

[tex]r^2 = 52[/tex]

Then

[tex]x^2 + y^2 = r^2[/tex]

[tex]x^2 + y^2 = 52[/tex]

Hey there!

I hope you have a great one too :)

Answer:

[tex]\sqrt{x^2 + y^2}[/tex]

Step-by-step explanation:

to find diatance between AB

A(0 , 0) = (x1 , y1)

B(x , y) = (x2 , y2)

distance formula = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

=[tex]\sqrt{(x - 0)^2 + (y - 0)^2}[/tex]

=[tex]\sqrt{x^2 + y^2}[/tex]

Answer: The company will recognize commission expense in the amount of $2,400 in December

Step-by-step explanation:

Based on the information given in the question, the company will recognize commission expense in the amount of $2,400 in December.

A commission is regarded as a fee which is paid to a salesperson by a company in exchange for completing a sale.

It should be noted that in the accrual basis of accounting, commission should be recorded in the same period as when the sale generated was generated.

Answer:

b. The company will recognize commission expense in the amount of $2,400 in December.

Step-by-step explanation:

Based on the information given the statements that is true will be: THE COMPANY WILL RECOGNIZE COMMISSION EXPENSE IN THE AMOUNT OF $2,400 IN DECEMBER reason been that each salesperson were paid a commission in the amount of $800 for each cycle sold, which is 3 cycles during the month of December.

Calculation to determine the Commission Expense

Commission Expense=$800*3 cycles

Commission Expense=$2,400

Therefore The company will recognize commission expense in the amount of $2,400 in December.

That is the same as writing [tex]10\sqrt{30}[/tex]

======================================================

Explanation:

The diagram shows that

That must mean DC = AC-AD = 60-50 = 10

We'll use this to help find BD as shown below

AD/BD = BD/DC

AD*DC = BD*BD .... cross multiply

(BD)^2 = AD*DC

BD = sqrt(AD*DC) ..... geometric mean formula

BD = sqrt(50*10)

BD = sqrt(500)

----------------------

Now apply the pythagorean theorem to find AB. Focus on triangle ABD.

(AD)^2 + (BD)^2 = (AB)^2

(AB)^2 = (AD)^2 + (BD)^2

(AB)^2 = (50)^2 + (sqrt(500))^2

(AB)^2 = 2500 + 500

(AB)^2 = 3000

AB = sqrt(3000)

AB = sqrt(100*30)

AB = sqrt(100)*sqrt(30)

AB = 10*sqrt(30)

Answer:

p = 18

Step-by-step explanation:

Let's solve your equation step-by-step.

−2(8p+2)−3(2−7p)=2(4+2p)

Step 1: Simplify both sides of the equation.

−2(8p+2)−3(2−7p)=2(4+2p)

(−2)(8p)+(−2)(2)+(−3)(2)+(−3)(−7p)=(2)(4)+(2)(2p)(Distribute)

−16p+−4+−6+21p=8+4p

(−16p+21p)+(−4+−6)=4p+8(Combine Like Terms)

5p+−10=4p+8

5p−10=4p+8

Step 2: Subtract 4p from both sides.

5p−10−4p=4p+8−4p

p−10=8

Step 3: Add 10 to both sides.

p−10+10=8+10

p=18

Therefore, the final answer is 18, I hope this helps :D

Answer:

p=18

Step-by-step explanation:

See image below:)

Answer:

1.33

Step-by-step explanation:

so mean is the average

so what you have to do is add the numbers for each person and then divide by the amount of numbers present. the question is asking for the difference so subtract the numbers for each from person.

mia's mean= 34.33

sophia's mean= 35.667

sophia-mia= 1.33

(check my work, and if you need help just comment)

Answer:

2821.51

73425.64

28124.24

4124.24

Step-by-step explanation:

Effective rate: .058/2 = .029

This question is kind of ambigous and I'll make the assumption that there is no payment at time 0

[tex]175000=x\frac{(1+.029)^{2*18}-1}{.029}\\x=2821.511[/tex]

interested earned:

175000-2821.51*36= 73425.64

2.)

Same assumption as question 1 (there is no payment at time 0)

effective rate: .063/12= .00525

[tex]400(\frac{(1+.00525)^{60}-1}{.00525})=28124.24[/tex]

Interest earned: 28124-400*60=4124.24

Answer:

First problem: monthly payment $2741.99; interest earned $76,288.36

Second problem: amount in account $28,271.90; interest earned $4271.90

Step-by-step explanation:

First problem:

You open an account with a deposit. The deposit is the first monthly payment. This means that this is an annuity in which you pay at the beginning of the pay period. That makes it into an "annuity due."

[tex] A = \dfrac{F}{\frac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

where A = periodic payment,

F = future value

i = interest rate per compounding period, n = number of compounding periods

[tex]A = \dfrac{175000}{\frac{(1 + \frac{0.058}{2})^{2 \times 18} - 1}{\frac{0.058}{2}} \times (1 + \frac{0.058}{2})}[/tex]

[tex] A = 2741.99 [/tex]

Interest earned:

[tex] 2 \times 18 \times 2741.99 - 175000 = 76288.36 [/tex]

Second problem:

Once again, the account starts with a deposit of the monthly payment, so this is also an annuity due, meaning the payments occur at the beginning of each compounding period. Here, we are given the monthly payment, an d we need to find the future value.

[tex] F = A \times \dfrac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

[tex] F = 400 \times \dfrac{(1 + \frac{0.063}{12})^{5 \times 12} - 1}{\frac{0.063}{12}} \times (1 + \frac{0.063}{12})} [/tex]

[tex] F = 28271.90 [/tex]

The interest earned is:

[tex] 28271.90 - 12 \times 5 \times 400 = 4271.90 [/tex]