The amount of time needed to complete a job, t, varies inversely with the number of workers, w. If 10 workers can complete a job in 20 minutes, how many minutes would it take 5 workers?

Answers

Answer 1
it would take 40 minutes for 5 workers
Answer 2

The amount of time needed to complete a job by 5 workers is

40 minutes.

What is a unit rate?

It is the quantity of an amount of something at a rate of one of another quantity.

In 2 hours, a man can walk for 6 miles

In 1 hour, a man will walk for 3 miles.

We have,

The amount of time needed to complete a job, t, varies inversely with the number of workers.

Number of workers = W

Time to complete 1 work  = T

This means,

T = 1 / W

W = 1 / T

10 workers can complete a job in 20 minutes.

This can be written as:

10 W = 1 / 20

Divide 10 on both sides.

1 W = 1 / 200

This means,

1 worker can complete a job in 200 minutes.

Now,

1 W = 1/ 200

Multiply 5 on both sides.

5 W = 5/200

5 W = 1 / 40

This means 5 workers will take 40 minutes to complete the work.

Thus,

The amount of time needed to complete a job by 5 workers is

40 minutes.

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Related Questions

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Weights of Dogs in Shelter A
2 box plots. The number line goes from 6 to 30. For the weights of dogs in shelter A, the whiskers range from 8 to 30, and the box ranges from 17 to 28. A line divides the box at 21. For shelter B, the whiskers range from 10 to 28, and the box ranges from 16 to 20. A line divides the box at 18.
Weights of Dogs in Shelter B

Which is true of the data in the box plots? Select three choices.
The median weight for shelter A is greater than that for shelter B.
The median weight for shelter B is greater than that for shelter A.
The data for shelter A are a symmetric data set.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.

Answers

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18  true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18   false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is  symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4  True

Annual windstorm losses, X and Y, in two different regions are independent, and each is uniformly distributed on the interval [0, 10]. Calculate the covariance of X and Y, given that X+ Y < 10.

Answers

Answer:

[tex]Cov(X,Y) = -\frac{ 25}{9}[/tex]

Step-by-step explanation:

Given

[tex]Interval =[0,10][/tex]

[tex]X + Y < 10[/tex]

Required

[tex]Cov(X,Y)[/tex]

First, we calculate the joint distribution of X and Y

Plot [tex]X + Y < 10[/tex]

So, the joint pdf is:

[tex]f(X,Y) = \frac{1}{Area}[/tex] --- i.e. the area of the shaded region

The shaded area is a triangle that has: height = 10; width = 10

So, we have:

[tex]f(X,Y) = \frac{1}{0.5 * 10 * 10}[/tex]

[tex]f(X,Y) = \frac{1}{50}[/tex]

[tex]Cov(X,Y)[/tex] is calculated as:

[tex]Cov(X,Y) = E(XY) - E(X) \cdot E(Y)[/tex]

Calculate E(XY)

[tex]E(XY) =\int\limits^X_0 {\int\limits^Y_0 {\frac{XY}{50}} \, dY} \, dX[/tex]

[tex]X + Y < 10[/tex]

Make Y the subject

[tex]Y < 10 - X[/tex]

So, we have:

[tex]E(XY) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{XY}{50}} \, dY} \, dX[/tex]

Rewrite as:

[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {XY}} \, dY} \, dX[/tex]

Integrate Y

[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{XY^2}{2}}} }|\limits^{10 - X}_0 \, dX[/tex]

Expand

[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{X(10 - X)^2}{2} - \frac{X(0)^2}{2}}} }\ dX[/tex]

[tex]E(XY) =\frac{1}{50}\int\limits^{10}_0 {\frac{X(10 - X)^2}{2}}} }\ dX[/tex]

Rewrite as:

[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 X(10 - X)^2\ dX[/tex]

Expand

[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 X*(100 - 20X + X^2)\ dX[/tex]

[tex]E(XY) =\frac{1}{100}\int\limits^{10}_0 100X - 20X^2 + X^3\ dX[/tex]

Integrate

[tex]E(XY) =\frac{1}{100} [\frac{100X^2}{2} - \frac{20X^3}{3} + \frac{X^4}{4}]|\limits^{10}_0[/tex]

Expand

[tex]E(XY) =\frac{1}{100} ([\frac{100*10^2}{2} - \frac{20*10^3}{3} + \frac{10^4}{4}] - [\frac{100*0^2}{2} - \frac{20*0^3}{3} + \frac{0^4}{4}])[/tex]

[tex]E(XY) =\frac{1}{100} ([\frac{10000}{2} - \frac{20000}{3} + \frac{10000}{4}] - 0)[/tex]

[tex]E(XY) =\frac{1}{100} ([5000 - \frac{20000}{3} + 2500])[/tex]

[tex]E(XY) =50 - \frac{200}{3} + 25[/tex]

Take LCM

[tex]E(XY) = \frac{150-200+75}{3}[/tex]

[tex]E(XY) = \frac{25}{3}[/tex]

Calculate E(X)

[tex]E(X) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{X}{50}}} \, dY} \, dX[/tex]

Rewrite as:

[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {X}} \, dY} \, dX[/tex]

Integrate Y

[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 { (X*Y)|\limits^{10 - X}_0 \, dX[/tex]

Expand

[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 ( [X*(10 - X)] - [X * 0])\ dX[/tex]

[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 ( [X*(10 - X)]\ dX[/tex]

[tex]E(X) =\frac{1}{50}\int\limits^{10}_0 10X - X^2\ dX[/tex]

Integrate

[tex]E(X) =\frac{1}{50}(5X^2 - \frac{1}{3}X^3)|\limits^{10}_0[/tex]

Expand

[tex]E(X) =\frac{1}{50}[(5*10^2 - \frac{1}{3}*10^3)-(5*0^2 - \frac{1}{3}*0^3)][/tex]

[tex]E(X) =\frac{1}{50}[5*100 - \frac{1}{3}*10^3][/tex]

[tex]E(X) =\frac{1}{50}[500 - \frac{1000}{3}][/tex]

[tex]E(X) = 10- \frac{20}{3}[/tex]

Take LCM

[tex]E(X) = \frac{30-20}{3}[/tex]

[tex]E(X) = \frac{10}{3}[/tex]

Calculate E(Y)

[tex]E(Y) =\int\limits^{10}_0 {\int\limits^{10 - X}_0 {\frac{Y}{50}}} \, dY} \, dX[/tex]

Rewrite as:

[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 {\int\limits^{10 - X}_0 {Y}} \, dY} \, dX[/tex]

Integrate Y

[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 { (\frac{Y^2}{2})|\limits^{10 - X}_0 \, dX[/tex]

Expand

[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 ( [\frac{(10 - X)^2}{2}] - [\frac{(0)^2}{2}])\ dX[/tex]

[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 ( [\frac{(10 - X)^2}{2}] )\ dX[/tex]

[tex]E(Y) =\frac{1}{50}\int\limits^{10}_0 [\frac{100 - 20X + X^2}{2}] \ dX[/tex]

Rewrite as:

[tex]E(Y) =\frac{1}{100}\int\limits^{10}_0 [100 - 20X + X^2] \ dX[/tex]

Integrate

[tex]E(Y) =\frac{1}{100}( [100X - 10X^2 + \frac{1}{3}X^3]|\limits^{10}_0)[/tex]

Expand

[tex]E(Y) =\frac{1}{100}( [100*10 - 10*10^2 + \frac{1}{3}*10^3] -[100*0 - 10*0^2 + \frac{1}{3}*0^3] )[/tex]

[tex]E(Y) =\frac{1}{100}[100*10 - 10*10^2 + \frac{1}{3}*10^3][/tex]

[tex]E(Y) =10 - 10 + \frac{1}{3}*10[/tex]

[tex]E(Y) =\frac{10}{3}[/tex]

Recall that:

[tex]Cov(X,Y) = E(XY) - E(X) \cdot E(Y)[/tex]

[tex]Cov(X,Y) = \frac{25}{3} - \frac{10}{3}*\frac{10}{3}[/tex]

[tex]Cov(X,Y) = \frac{25}{3} - \frac{100}{9}[/tex]

Take LCM

[tex]Cov(X,Y) = \frac{75- 100}{9}[/tex]

[tex]Cov(X,Y) = -\frac{ 25}{9}[/tex]

How many solutions does the nonlinear system of equations graphed below have?

Answers

Answer:

2

Step-by-step explanation:

2 is the answer because the circle touches the line only 2 times.

Hope this helps.

Which graph represents the function f(x) = 2^x+ 3?

Answers

Answer:

Where's the graph?

Step-by-step explanation:

After a certain number of football matches , a footballer averages 1 goal per game.He only scored 2 goals in the next 10 games and his average dropped to 0.8 goals per game .How many football matches did he play altogether?​

Answers

Answer:

He played 40 matches in total, scoring 32 goals.

Step-by-step explanation:

Since after a certain number of football matches, a footballer averages 1 goal per game, and he only scored 2 goals in the next 10 games and his average dropped to 0.8 goals per game, to determine how many football matches did he play altogether you must perform the following calculation:

10/10 + 2/10 = 12/20 = 0.6

8/8 + 2/10 = 10/18 = 0.55

12/12 + 2/10 = 14/22 = 0.64

20/20 + 2/10 = 22/30 = 0.73

24/24 + 2/10 = 26/34 = 0.76

30/30 + 2/10 = 32/40 = 0.8

Thus, he played 40 matches in total, scoring 32 goals.

What are the center and radius of the circle defined by the equation x^2 + y^2 -6x + 8y + 21=0

Answers

Answer:

Step-by-step explanation:

(x²-6x)+(y²+8y)=-21

(x²-6x+9)+(y²+8y+16)=-21+9+16

(x-3)²+(y+4)²=4

center=(3,-4),radius=√4=2

To the nearest degree, find the measure of angle A.

Answers

Cosine(angle) = adjacent leg/ hypotenuse

Cosine( angle ) = 18/20

Angle = arccos(18/20)

Angle = 26 degrees

Answer:

26°

Step-by-step explanation:

For a right triangle, we can use trigonometry equations :-

In this case we need to use cosine equation .

cos A = adjacent side / hypotenuse

cos A = 18 / 20

A = cos × 18/20

A = arccos × 18/20

A = 26°

Given the functions:
g(n) = 3n - 5
f(n) = n2 + 50
Find:
(g+f)(8)

Answers

Answer:

[tex](g + f)(8) =133[/tex]

Step-by-step explanation:

Given

[tex]g(n) = 3n - 5[/tex]

[tex]f(n) = n^2 + 50[/tex]

Required

[tex](g + f)(8)[/tex]

This is calculated as:

[tex](g + f)(n) =g(n) + f(n)[/tex]

So, we have:

[tex](g + f)(n) =3n - 5 + n^2 +50[/tex]

[tex]Substitute[/tex] 8 for n

[tex](g + f)(8) =3*8 - 5 + 8^2 +50[/tex]

[tex](g + f)(8) =24 - 5 + 64 +50[/tex]

[tex](g + f)(8) =133[/tex]

In the number 1326308 is between which two numbers in a million?

Answers

Answer:

1326308 is in between 1326307 and 1326309

 In The Diagram, P, Q, R, Are Points On The Circle With Centre 0 And Diameter 14cm. Angle PQR=35 Degree. Find, Correct To One Decimal Place A. The Length Of The Minor Are PQ; B. The Chord PQ.

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in the diagram, P, Q, R, are points on the circle with centre 0 and diameter 14cm. angle PQR=35 degree. find, correct to one decimal place
a. The length of the minor are PQ;
B. The chord PQ.

Answers

Answer:

a

Step-by-step explanation:

because the diagram the length decimal place degree

What is the surface area of the regular pyramid below?

Answers

D. 304 sq units

Surface area is just finding the area of each face of a 3d figure and adding it up together:

Area of square base:
8 • 8 = 64 sq units

Area of ONE triangle face:
1/2 • 15 • 8 = 60 sq units
MULTIPLY that by 4 because we have 4 triangle faces: 60 • 4 = 240 sq units

ADD area of square base and 4 triangle faces: 240 + 64 = 304

FINAL ANSWER OF SURFACE AREA:
304 sq. units

BRAINLIEST will be much appreciated!
-SpaceMarsh, have a nice day/night!

3^4 +3 • 5= _. (Input whole numbers only.) Numerical Answers Expected!​ Please explain.

Answers

Answer:

96

Step-by-step explanation:

81+15=96

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{3^4 +3 \times5}\\\\\\\mathsf{3^4}\\\mathsf{= 3\times3\times3\times3}\\\mathsf{=9\times9}\\\mathsf{= \bf 81}\\\\\\\mathsf{81+5\times3}\\\\\mathsf{3\times5=\bf 15}\\\\\\\\\mathsf{81+15}\\\mathsf{= \bf 96}\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 96}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

2x-5y=22n y=3x-7 Use substitution to solve the system.

Answers

Answer:

x = 1 , y = -4

Step-by-step explanation:

2x - 5y = 22 ------- ( 1 )

y = 3x - 7      ------- ( 2 )

Substitute ( 2 ) in ( 1 ) :

2x - 5 (3x - 7) = 22

2x - 15x + 35 = 22

- 13x = 22 - 35

- 13x =  - 13

 x = 1

Substitute x in ( 1 ) :

2x - 5y = 22

2 ( 1 ) - 5y = 22

- 5y = 22 - 2

-5y = 20

y = - 4

If 21% of kindergarten children are afraid of monsters, how many out of
each 100 are afraid?

Answers

Answer:

The appropriate answer is "21".

Step-by-step explanation:

Given:

Afraid percentage,

p = 21%

or,

  = 0.21

Sample size,

n = 100

As we know,

⇒ [tex]X=np[/tex]

By putting the values, we get

        [tex]=0.21\times 100[/tex]

        [tex]=21[/tex]

First,i would rewrite 3/4 as an equivalent fraction with a denominator of ____

The equivalent fraction is ____ Then, I would compare the equivalent fraction to 7/12\


PLEASE TELL ME THE ANSWERS IN THE BLANKS!!!

Answers

Answer:

denominator of 12 (first blank) making the numerator 9. equivalent fraction 9/12 (second blank)

Step-by-step explanation:

lowest common denominator is 12. make sure what you do to the denominator (4times3)= 12, you do to the numerator (3times3)=9

Answer:

The first blank is the denominator of 12 so the numerator is 9. Which makes the answer 9/12

Step-by-step explanation:

Hope this helps! :)>

the second difference 4;x;8;y;20;.... is 2​

Answers

9514 1404 393

Answer:

x = 5y = 13

Step-by-step explanation:

First differences are ...

  x -4, 8 -x, y -8, 20 -y

Then second differences are ...

  (8 -x) -(x -4)

  (y -8) -(8 -x)

  (20 -y) -(y -8)

Each of these is said to be 2, so we have ...

  12 -2x = 2   ⇒   x = 5

  28 -2y = 2   ⇒   y = 13

And an equation we can use to check:

  x +y -16 = 2   ⇒   5 +13 -16 = 2 . . . . true

_____

The explicit formula for the sequence is ...

  an = n^2 -2n +5

Which best explains whether a triangle with side lengths 2 in., 5 in., and 4 in. is an acute triangle?

The triangle is acute because 22 + 52 > 42.
The triangle is acute because 2 + 4 > 5.
The triangle is not acute because 22 + 42 < 52.
The triangle is not acute because 22 < 42 + 52.

Answers

9514 1404 393

Answer:

  The triangle is not acute because 2² + 4² < 5²

Step-by-step explanation:

The square of the hypotenuse of a right triangle with the given short sides would be 2² +4² = 20. So, that hypotenuse would be √20, about 4.47. The long side of this triangle is longer than that, so the angle opposite is larger than 90°. The triangle with sides 2, 4, 5 is an obtuse triangle.

  The triangle is not acute because 2² + 4² < 5²

The triangle is not acute because 22 + 42 < 52.

Option C is the correct answer.

What is a triangle?

A triangle is a 2-D figure with three sides and three angles.

The sum of the angles is 180 degrees.

We can have an obtuse triangle, an acute triangle, or a right triangle.

We have,

To determine if a triangle is acute, we need to check whether all three angles of the triangle are acute angles (less than 90 degrees).

Pythagorean theorem,

- If the square of the length of the hypotenuse is greater than the sum of the squares of the other two sides, then the triangle is acute.

- If the square of the length of the hypotenuse is less than the sum of the squares of the other two sides, then the triangle is obtuse.

Now,

The triangle with side lengths 2 in., 5 in., and 4 in. is not a right triangle.

So we can't use the Pythagorean theorem directly.

Now,

We can check if the sum of the squares of the two shorter sides is greater than the square of the longest side.

2² + 4² = 4 + 16 = 20

5² = 25

Since 20 < 25, we know that the triangle is not acute.

Therefore,

The triangle is not acute because 22 + 42 < 52.

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someone plz help me porfavor!!!!!

Answers

Answer:

c. y = ¼x - 2

Step-by-step explanation:

Find the slope (m) and y-intercept (b) then substitute the values into y = mx + b (slope-intercept form)

Slope = change in y/change in x

Using two points on the graph, (0, -2) and (4, -1):

Slope (m) = (-1 - (-2))/(4 - 0) = 1/4

m = ¼

y-intercept = the point where the line intercepts the y-axis = -2

b = -2

✔️To write the equation, substitute m = ¼ and b = -2 into y = mx + b:

y = ¼x - 2

Which of the following is NOT a solution to the linear equation y=3x+2?
Select the correct answer below:
(1,5)
(2,8)
(3,10)
(4,14)

Answers

Answer:

(3,10)

Step-by-step explanation:

When x is 3

[tex]{ \bf{y = 3x + 2}} \\ { \bf{y = (3 \times 3) + 2}} \\ { \bf{y = 11}}[/tex]

y is 11, and this is invalid because it is not at accord.

The correct coordinates which is NOT a solution to the linear equation

y = 3x+2 is,

⇒ (3, 10)

What is Equation of line?

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

Linear equation is,

⇒ y = 3x + 2

We know that;

The solution of linear equation is satisfy the eqaution.

Hence, We can check as;

⇒ y = 3x + 2

Put x = 1. y = 5

⇒ 5 = 3 × 1 + 2

⇒ 5 = 5

Thus, It is solution of linear equation.

⇒ y = 3x + 2

Put x = 2. y = 8

⇒ 8 = 3 × 2 + 2

⇒ 8 = 8

Thus, It is solution of linear equation.

⇒ y = 3x + 2

Put x = 3, y = 10

⇒ 10 = 3 × 3 + 2

⇒ 10 ≠ 11

Thus, It is not solution of linear equation.

Thus, The correct coordinates which is NOT a solution to the linear equation y = 3x+2 is,

⇒ (3, 10)

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A custodian has 5 and 1/2 gallons of paint each of the book cases she is painting requires 1/2 gallon of paint how many book cases will the custodian be able to paint with that amount of paint A.3 B.4 C.11 D.15

Answers

Answer:

Option C.

Step-by-step explanation:

Find the product with the exponent in simplest
form. Then, identify the values of x and y.
6
X
- 64
.
6
X
y =
DONE

Answers

Answer:

[tex]\displaystyle 8^\bigg{\frac{8}{3}}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Exponential Rule [Powering]: [tex]\displaystyle (b^m)^n = b^{m \cdot n}[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \bigg(8^\bigg{\frac{2}{3}} \bigg)^4[/tex]

Step 2: Simplify

Exponential Rule [Powering]:                                                                           [tex]\displaystyle 8^\bigg{\frac{2}{3} \cdot 4}[/tex]Multiply:                                                                                                             [tex]\displaystyle 8^\bigg{\frac{8}{3}}[/tex]

A trailer is 22 feet long. 9 feet wide,
and 7 feet high. What is the volume of
the trailer?

Answers

Answer:

1386

Step-by-step explanation:

22 × 9 × 7 = 1386 cubic feet

V= L x W x H = 22x9x7 = 1386

what is the equation of a circle with a center (-7, -3) and radius 2?

i’ll mark you brainliest!!

Answers

Answer:

2nd

Step-by-step explanation:

bvfhmvdv funny Kahn just list Kay have also off weit

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Compute the product AB by the definition of the product of​matrices, where Ab1 and Ab2 are computed​ separately, and by the​row-column rule for computing AB.

Matrix A= [2 -2]
[3 4]
[4 -3]

Matrix B =
[4 -1]
[-1 2]

Answers

Answer:

[tex]A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right][/tex]

Step-by-step explanation:

Given

[tex]A =\left[\begin{array}{cc}2&-2\\3&4\\4&-3\end{array}\right][/tex]

[tex]B = \left[\begin{array}{cc}4&-1\\-1&2\end{array}\right][/tex]

Required

[tex]AB[/tex]

To do this, we simply multiply the rows of A by the column of B;

So, we have:

[tex]A * B = \left[\begin{array}{ccc}2*4 + -2*-1&2*-1+-2*2\\3*4+4*-1&3*-1+4*2\\4*4-3*-1&4*-1-3*2\end{array}\right][/tex]

[tex]A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right][/tex]

What is a Parrel line?

Answers


Parallel lines are lines in a plane that are always the same distance apart. Parallel lines never intersect.

Answer:

parrel line never meet

FLIGHT TO TOKYO TAKE 2 HOURS 20 MINUTES U ARRIVE AT 4:15PM WHICH TIME DID HE SET OFF

Answers

Answer: 1:55 PM

Step-by-step explanation:

Turn 4:15 to 24-hr clock system which is 1615hrs

16:15 - 02:20 = 1355hrs

The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they charge for the product: P(c) = –20c2 + 320c + 5,120. What is the maximum profit the company can make from the product?

Answers

Answer:

6400

Step-by-step explanation:

Given the profit function ;

P(c) = –20c2 + 320c + 5,120

The maximum value is given by :

f(h) ; where, h = - b /2a

From P(C) ; a = - 20 ; b = 320

h = - b / 2a = - 320 / 2(-20) = - 320 / 40 = 8

c = h

P(8) = –20(8)² + 320(8) + 5,120

P(8) = - 1280 + 2560 + 5120

= 6400

Answer:

B.) $640,000

Step-by-step explanation:

Wayne is picking out some movies to rent, and he is primarily interested in dramas and horror films. He has narrowed down his selections to 7 dramas and 16 horror films. How many different combinations of 3 movies can he rent if he wants at least two dramas

Answers

Answer:

The number of selections is 49.

Step-by-step explanation:

drama = 7

horror films = 16

Select 3 movies at least two dramas

For 2 drama and 1 horror film

(3 C 2) x (16  C 1) = 48

For 3 drama

(3 C 3) = 1

So, total number of selections is 48 + 1 = 49.  

José tiene 30 años menos que su padre y 27 más que su hijo. entre los 3 suman 135 años ¿ cuántos años tiene cada uno?​

Answers

Answer:

44 años tiene jose . el padre 74 y el hijo 17 años.

Step-by-step explanation:

what is the sum factor of 3600​

Answers

Answer:

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

Find the prime factorization of the number 3,600. Factor Tree.

2|3,600.

2|1,800.

2|900.

2|450

5|225

5|45

3|9

3|3

|1

Setup the equation for determining the number of factors or divisors.

3600=2x2x2x2x3x3x5

Sum factors=2+2+2+2+2+3+3+5=24

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