The answers please I need answers

A true average strain in a way that converys information about precision and reliability (24.33, 27.67)

From given information we have:

the sample size n = 20

the mean failure strain x(bar) = 26.0

the standard deviation s = 3.4

Assuming a normal distribution for failure strain, we need to estimate true average strain in a way that converys information about precision and reliability.

A 95% confidence interval is necessary; other confidence intervals can be calculated in a similar way.

c = 0.95 or 95%

In the table with the critical values for t distributions in the appendix, locate the row beginning with degrees of freedom.

Here, the degree of freedom :

df = 20 - 1

df = 19

and  α = (1-c)/2

          = 0.025

To find the t-value:

t_(α/2) = 2.145

Therefore, the error margin is:

E = t_(α/2) × s/√n​

E = 2.145× 3.4/√19

E ≈ 1.67

And the confidence interval would be,

(x{bar} - E, x{bar} + E) = (24.33, 27.67)

Therefore, the confidence interval is: (24.33, 27.67)

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a) The amounts that the team needs to sell is given as follows:

b) The advantage and disadvantage is given as follows:

The amounts needed are found applying the proportion, considering the costs and the number of candles.

A package of 5 candles for $18, hence the number of candles needed to earn $1404, in packages, is given as follows:

5 candles - $18

n candles - $1404

Applying cross multiplication, we have that:

18n = 5 x 1404

n = 5 x 1404/18

n = 390 candles.

With a single candle, the number of candles is calculated as follows:

1404/4 = 351 candles.

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Economies of scale occur when average cost declines with an increase in output. This occurs up to output level Q1.

Diseconomies of scale occur when average cost increases with an increase in output. This begins at output level Q3.

The phenomenon known as economies of scale occurs when the size or magnitude of the production generated by a business increases while the average cost per unit of output decreases.

The Long Run Average Cost Curve demonstrates how a firm's average expenses change over time. The shift from point A to point B illustrates how the cost per unit decreases as the curve slopes down. Because of economies of scale, the average cost grows less proportionally to output over the downward sloping region of the curve.

Minimum efficient scale is the level of output where economies of scale have been fully exploited.

A competitive firm produces at the minimum point of ATC in the long run and thus achieves productive efficiency.

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Answer: 84 bells

Step-by-step explanation:

12 + 9x8

84

To use the intermediate value theorem to show that there is a root of the given equation in the specified interval, we first need to find the values of the function at the two endpoints of the interval. Let's say the function is denoted by f(x) and the interval is [a, b].

If f(a) and f(b) have opposite signs (one is positive and the other is negative), then by the intermediate value theorem, there must be at least one root of the equation f(x) = 0 in the interval [a, b]. This is because the intermediate value theorem states that if a function is continuous on a closed interval and the function takes on different values at the endpoints of the interval, then there must be at least one point in the interval where the function takes on the value of the intermediate value between the two endpoints.

For example, suppose we have the equation f(x) = x^2 - 3 and we want to show that there is a root of the equation in the interval [1, 2]. We can evaluate the function at the two endpoints of the interval:

f(1) = 1^2 - 3 = -2

f(2) = 2^2 - 3 = 1

Since f(1) and f(2) have opposite signs, by the intermediate value theorem, there must be at least one root of the equation f(x) = 0 in the interval [1, 2]. To find the root, we can use a root-finding algorithm such as bisection or Newton's method.

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Answer:

There is 1/32 pound food for each fish

Step-by-step explanation:

24 fish = 3/4 pound food

1 fish = (3/4)/24 pound food = 1/32 pound food

(Problem solved by using unitary method)

The required answer is the domain is time (t) and the range is a distance (d) i.e. Option 2.

What are domain and range?

The value range that can be plugged into a function is known as its domain. In a function like f, this set represents the x values f(x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.

From the given question, and the above definition of domain and range,

the time (t) acts as an x-values or input value and the distance (d) acts as a y-value or output value

Hence, the domain is time (t) and the range is a distance (d) i.e. Option 2.

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Graph (C) which has points (0, 400) and (16, 0) represent the solution to the given situation of Rashawn.

In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way.

The relationships between two or more items are frequently represented by the points on a graph.

Graphs and charts are useful visual aids because they make information accessible and quick to understand.

Therefore, it is not unexpected that print and electronic media frequently use graphs.

When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.

So, Rashawn consumed 25 pages of his book daily till it was finished. There were 400 pages in his book.

400 / 25 = 16 days is the estimated number of days he needs to finish the book.

He will have 400 pages finished in 0 days and 0 pages in 16 days.

As a result, the situation is represented by a graph with a line segment in the first quadrant.

Days are shown on the x-axis, and Pages left are listed on the y-axis.

The line segment's ends are (0, 400) and (16, 0).

Therefore, graph (C) which has points (0, 400) and (16, 0) represent the solution of the given situation of Rashawn.

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Complete question:
Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.

Which sketch represents this situation?

a) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 400 end ordered pair and begin ordered pair 25 comma 0 end ordered pair.

b) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 16 end ordered pair and begin ordered pair 400 comma 0 end ordered pair.

c) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 400 end ordered pair and begin ordered pair 16 commas 0 ends ordered pair.

d) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y-axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 25 ends ordered pair and begin ordered pair 400 commas 0 ends ordered pair.

Answer:

y = -1/2x - 2

Step-by-step explanation:

y = mx+b, m = -1/2, and b (the y-intercept) is -2.

Answer

2x73

Step-by-step explanation:

Answer:

(11.5, 7.5)

Step-by-step explanation:

17 + 6 / 2 = 11.5

2 + 13 / 2 = 7.5

Answer: We can set up the equation 21 stickers/pack + 24 stickers/pack + x stickers/pack = 15 stickers.

We can solve this equation to find that x, the number of stickers in each pack, is equal to 6 stickers/pack. Answer: 6

Answer: 20

Step-by-step explanation:

24 + 21 = 45

45 + 15 = 60

60 / 3 = 20

The value of p is 0.16. So the option b is correct.

A local entrepreneur takes a random sample of 100 people.

Of the urban participants, 22 buy a real tree.

Of the rural participants, 28 buy a real tree.

Let p1 = the proportion of all people who live in rural communities and buy a real Christmas tree.

Let p2 = the proportion of all people who live in urban communities and buy a real Christmas tree.

We have to find the p-value

p1 = X1/N1

p1 = 28/100

p1 = 0.28

p2 = X2/N2

p2 = 22/100

p2 = 0.22

p = (X1 + X2)/(N1 + N2)

p = (28+22)/(100+100)

p = 0.25

Below are the null and alternative Hypothesis,

Null Hypothesis, H0: p1 = p2

Alternate Hypothesis, Ha: p1 > p2

Test statistic

z = (p1 - p2)/√(p*(1-p)*(1/N1 + 1/N2))

z = (0.28-0.22)/√(0.25*(1-0.25)*(1/100 + 1/100))

z = 0.9798

P-value Approach

P-value = 0.16

Hence, the option A is correct. 0.16 is the p-value.

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Answer:

Step-by-step explanation:

12.5663706144

Hello,

I hope you and your family are doing well!

The classmate should bike for 50 minutes at 11 mph and at 150 minutes for 15 mph. (See explanation below)

First, let's find how many calories your classmate burns while biking at 11 mph:

calories burned = time * rate of calorie burn

Since your classmate bikes at 11 mph for 50 minutes, the number of calories he burns at this speed is:

calories burned = 50 minutes * 5 calories/minute = 250 calories

Now, let's find how many calories your classmate burns while biking at 15 mph:

calories burned = 400 calories - 250 calories = 150 calories

Since your classmate burns 1 calorie per minute while biking at 15 mph, he needs to bike at this speed for 150 minutes to burn the remaining calories:

time = calories burned / rate of calorie burn

time = 150 calories / 1 calorie/minute = 150 minutes

Please rate this answer 5 stars and brainliest if you find it helpful.

Happy Holidays!

There are two angles for the sine function such that sin θ = - 0.093: (i) 185.3°, (ii) 354.7°.

In this problem we must determine two values of the angle of the sine function such that its result is - 0.093. According to the features of the trigonometric function, sine is negative for angles between 180° and 360°.

Since trigonometric functions are trascendent functions, we can only obtain approximate values of the angle by means of inverse trigonometric functions and numerical methods. There are two possible solutions:

sin⁻¹ - 0.093

θ₁ ≈ 185.336° or θ₂ ≈ 354.664°

θ₁ ≈ 185.3° or θ₂ ≈ 354.7°

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(a) A vector function, r(t), that represents the cylinder x^2+y^2 = 25 and the surface z = xy.

(b) A vector function, r(t), that represents the paraboloid z = 7x^2 + y^2 and the parabolic cylinder y = 2x^2 is r(t) = <t, 2t^2, 7t^2+4t^4.

(a) We have to find a vector function, r(t), that represents the curve of intersection of the two surfaces.

The cylinder x^2+y^2 = 25 and the surface z = xy.

The given cylinder is x^2+y^2 = 25

We can write it as

x^2+y^2 = 5^2………………(1)

The given surface is z = xy………………..(2)

Let x = 5cost and y = 5sint, then x and y satisfy the equation 1

Now putting x=5cost and y=5sint in equation (2), we get

z = (5cost)(5sint)

z = 25sintcost

Now x=5cost, y=5sint and z=25sintcost

Hence, r(t) = <x(t),y(t),z(t)>

r(t) = <5cost, 5sint, 25sintcost>

(b) We have to find a vector function, r(t), that represents the curve of intersection of the two surfaces.

The paraboloid z = 7x^2 + y^2 and the parabolic cylinder y = 2x^2.

The given paraboloid z = 7x^2+y^2………………………(1)

The parabolic cylinder y = 2x^2……………………….(2)

Let x = t, then from equation 2

y = 2t^2

Now putting the value of x and y in equation (1)

z = 7t^2+(2t^2)^2

z = 7t^2+4t^4

Now x=t, y=2t^2 and z=7t^2+4t^4

Hence, r(t) = <x(t),y(t),z(t)>

r(t) = <t, 2t^2, 7t^2+4t^4>

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As pre the concept of vector, div F is negative at P1 and divF is positive at P2.

In math the term vector refers the quantity that has both magnitude and direction but not position

Here we have to determine whether div F is positive or negative at P1 and at P2.

Let us consider if  div F(P)>0, the net flow is outward near P and P is called a source and if  div F(P)<0, the net flow is inward near P and P is called a sink.

Here by observing the graph of F, we have identified that the vectors end near the P1 are the larger than the vectors starts near the point P1,

So, the net flow is inward near P1 and div F is negative at P1

Where P1 is called a sink

Whereas, by observing the graph of F we have identified that the vectors end near P2 are shorter than the vectors starts near the point P2,

So, the net flow is outward and div F   is positive at P2 and the P2 is called a source

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The domain and range of such equation in which case the distance travelled d is dependent on the time, t is best described by the answer choice; 2. The domain is time (t) and the range is distance (d).

It follows from the task content that the domain and range of the function as described in the task content is to be determined.

According to the task content; A train travels at 80 miles per hour.

On this note, the equation that compares the time (t) with the distance (d) as required is;

d = 80 t

On this note, the dependent and independent variables are d and t respectively.

Consequently, the domain is time which is the set of all possible inputs while the range is distance which is the set of all possible output values.

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Answer:true, false, false, true

Step-by-step explanation:

stem                            leaf

0                               7, 7, 8, 8

1                                   3 , 3

2                                   5, 2

What is stem and leaf plot ?

A stem and leaf plot, also known as a stem and leaf diagram, arranges data in a way that makes it simple to see how often certain sorts of values occur. It is a graph that displays ordered numerical data. A stem and a leaf are divided into each piece of data.

A stem and leaf plot is shown as a customized table with the first or final digit of each data value divided into a stem and the remaining digit in a leaf. The stem and leaf plot key is the symbol " | " that is used to display stem and leaf values.

For instance, the stem and leaf plot key is used to represent 46 as 4 on the stem and 6 on the leaf.

in 2|5 , 2 is the stem side and 5 is the leaf side

in 0|7 , 0 is the stem side and 7 is the leaf side

in 1|3 , 1 is the stem side and 3 is the leaf side

in 0|8 , 0 is the stem side and 8 is the leaf side

in 2|2 , 2 is the stem side and 2 is the leaf side

in 0|7 , 0 is the stem side and 7 is the leaf side

in 1|3 , 1 is the stem side and 3 is the leaf side

in 0|8 , 0 is the stem side and 8 is the leaf side

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(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

What is the property of slopes of parallel lines and perpendicular lines?

If two lines are given and they are parallel to each other then the slopes are equal and for perpendicular lines, the product of their slopes is equal to -1.

(7) The line AB is passing through the points (-1, 5/2) and (3/2, -1/2).

   Slope = y2 - y2/x2 - x1

              = (-1/2 - 5/2)/(3/2-(-1))

              = -6/5

   As line AB and line CD are parallel in nature so the slope of line CD is also -6/5.

(8) The line AB is passing through the points (1/2, 1) and (5/2, 5/2).

    Slope = y2 - y2/x2 - x1

              = (5/2 - 1)/(5/2-1/2)

              =3/2/2

             = 3/4

    Line CD is passing through points (1, 1) and (2, 3).

    Slope = y2 - y2/x2 - x1

              = (3 - 1)/(2-1)

              =2/2

             = 1

  As the product of their slopes is not equal to -1.

  So lines are neither parallel nor perpendicular.

(9) Slope of AB can be computed as (-2, 1) and (-5, 5)

     Slope = 5 - 1/-5 + 2

                = 4/-3.

  The slope of line passing through the point P = -4/3 as we have to draw the parallel line.

 Point P = (-1, 3)

Equation of the line :

      y - 3 = -4/3(x + 1)

    3y +9 = -4x - 4

   3y = -4x - 13

Now we can draw the line

(10) Slope of line AB = -4/3

    So the slope of the line passing through point P should be 3/4 in order to be perpendicular to line AB.

     Equation of the line passing through point P:

       y - 3 = 3/4(x - (-1))

       y - 3 = 3/4(x+1)

Hence,

(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

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Answer: the number is -16

Step-by-step explanation: if you add 17 to -49, you will get -32. you do this because it is 17 less than NOT more than. that would be called inverse operations. then, you divide that number by 2 to get -16. again, you use inverse operations because you are going backwards to try and find the number.

Answer: -16

Step-by-step explanation: So, to solve, we should write an equation. It should look like this:

2x - 17 = -49

So, using inverse operations, we would add 17 to - 49, which is -32, then divide that by 2, which would be -16. I hope this helped!

P.S. our new equation would look like 2(16) - 17 = -49

32-17 = 49

32 + -17 = 49

49 = 49

It checks out.

Answer:

Step-by-step explanation:

To find the percentage increase in the dog's weight, you can use the following formula:

percentage increase = (final value - initial value) / initial value x 100%

In this case, the initial value is 40 pounds and the final value is 48 pounds, so the percentage increase is:

percentage increase = (48 - 40) / 40 x 100% = 8 / 40 x 100% = 20%

Therefore, the dog's weight increased by 20%.

Answer:

the answer would be e because you can't determine the side length

Answer: (B)

Step-by-step explanation:

Step 1: Find minimum values of the third side.

53-17 = 36

Step 2: Find maximum values of the third side.

17+53 = 70

Step 3: Find equation

36 < x < 70

omgggg thats what she said

Answer: Answer is 8.47

Step-by-step explanation:

[(6x2.99)-1] ÷2

16.94 / 2

8.47

Answer:

8.47

Step-by-step explanation:

[(6x2.99)-1] ÷2  16.94 /2 =8.47

Answer:

y=-5.5x-52

Step-by-step explanation:

Your input: find the equation of a line given two points P = (-10 , 3) and Q = (-8 , -8). The slope of a line passing through the two pointsP=(x1,y1) and Q=(x2,y2) is given byWe have that x1 = -10 , y1 = 3, x2 = -8 , y2 = -8Step 2:Plug the given values into the formula for slope:Step 3:Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).b = 3 - (-5.5) ⋅ (-10) = -52Step 4:Finally, the equation of the line can be written in the form y=mx+b.y = -5.5x -52The equation of the line in the slope-intercept form is:y = -5.5x -52The equation of the line in the point-slope form is:y - (3) = -5.5 ⋅ ( x - (-10))The equation of the line in the point-slope form is:y - (-8) = -5.5 ⋅ ( x - (-8))The general equation of the line is:-5.5x - y -52 = 0

The expressions are x=9°+n.36° and x= -9°+n36°.

So, options C and D are correct.

A finite combination of symbols that are well-formed in accordance with context-dependent rules is referred to as an expression or mathematical expression in mathematics. Mathematical symbols can represent variables, operations, functions, brackets, punctuation, and grouping to help specify the logical syntax and order of operations. Lambda expressions are a new class of expressions that Alonzo Church and Stephen Kleene introduced in the 1930s for formalizing functions and their evaluation. In mathematical logic and the theory of programming languages, they serve as the foundation for the formal system known as lambda calculus.

Given,

4cos(10x)+2=2

4cos(10x)=0

cos(10x)=0

10x=90°+n360°

x=(90°/10°)+n(360°/10)

x=9°+n.36°

(or)

10x= -90°+n360°

x= -9°+n36°

Therefore, the expressions are x=9°+n.36° and x= -9°+n36°

Hence, options C and D are correct.

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