The area of a rectangle is 35 m², and the length of the rectangle is 3 m more than double the width. What is the dimensions of the rectangle?

The required answer is the domain is time (t) and the range is a distance (d) i.e. Option 2.

What are domain and range?

The value range that can be plugged into a function is known as its domain. In a function like f, this set represents the x values f(x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.

From the given question, and the above definition of domain and range,

the time (t) acts as an x-values or input value and the distance (d) acts as a y-value or output value

Hence, the domain is time (t) and the range is a distance (d) i.e. Option 2.

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Answer:

There is 1/32 pound food for each fish

Step-by-step explanation:

24 fish = 3/4 pound food

1 fish = (3/4)/24 pound food = 1/32 pound food

(Problem solved by using unitary method)

Answer: 60 miles per 4 gallons. If that's the question.

Step-by-step explanation:

If in an analysis of variance problem involving 3 treatments and 10 observations per treatment, S S E = 399.6. The M S E for this situation is  C. 14.8.

We would be making use of this formula to find or determine the MSE which is the variance within the sample.

MSE = S S E / r (c-1)

Where:

MSE represent variance within the sample = ?

SSE represent sum of the squares of error = 399.6

r represent 3 treatment

c represent observation per treatment = 10

Let plug in the formula so as to know the variance within the sample (MSE )

Sample variance ( MSE ) = 399.6 /3 (10 - 1 )

Sample variance ( MSE ) = 399.6 / 3 (9)

Sample variance ( MSE ) = 399.6 / 27

Sample variance ( MSE ) = 14.8

Therefore  we can conclude that the correct option is C which is 14.8.

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If the price is reduced to $11.40 the number of DVDs sold will be 1177.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a video store manager observed that the number of DVDs sold seems to vary inversely to the price per DVD. If the store sells 710 DVDs per week when the price per DVD is $18.90.

The number of DVDs sold for $11.40 will be calculated by forming the inverse equation for the number of DVDs.

N = K / P

Here, N is the number and P is the price and K is the inverse constant.

The value of K will be,

K = N x P

K = 18.90 x 710

K = 13419

The number of DVDs for $11.40 will be,

N = K / P

N = 13419 / 11.40

N = 1177

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Derivative of function is 5(2x + 4) * (x² + 4x + 6)⁴.

What is differentiation?

In arithmetic, the derivative of a function of a true variable measures the sensitivity modification of the perform price with relation to a change in its argument. Derivatives are a elementary tool of calculus.

Main body:

by using product rule;

Let = u = x² + 4x + 6

⇒ du/dx = 2x + 4 .

Now y = u⁵

⇒ dy/dx = 5u⁴ .

dy/dx = dy/dx * du/dx = 5u⁴ * (2x + 4)

= 5 * (x² + 4x + 6)⁴ * (2x + 4)

= 5(2x + 4) * (x² + 4x + 6)⁴

hence , derivative of function is 5(2x + 4) * (x² + 4x + 6)⁴.

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a) The amounts that the team needs to sell is given as follows:

b) The advantage and disadvantage is given as follows:

The amounts needed are found applying the proportion, considering the costs and the number of candles.

A package of 5 candles for $18, hence the number of candles needed to earn $1404, in packages, is given as follows:

5 candles - $18

n candles - $1404

Applying cross multiplication, we have that:

18n = 5 x 1404

n = 5 x 1404/18

n = 390 candles.

With a single candle, the number of candles is calculated as follows:

1404/4 = 351 candles.

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Answer:

21/79

Step-by-step explanation:

(7x6)÷2[{45÷3(7×2-15+6)}+4)​

(7*6)/2[{15(7*2-15+6)}+4)

(42)/2[{15(14-15+6)}+4)

(42)/2[{15(5))}+4)

(42)/2[{75}+4)

(42)/2[75 + 4]

(42)/2 * 79

42/2 * 79

21/79

Ф {0, [3√3/2(3√3-π)]}

The poster above has good diagrams ; so , I will just go through the calculations .

The region of integration is with in the circle x ^2+y^2=2y but outside the circle   x^2+y^2=1.

I would convert to polar . With polar , we have  x^2+y^2=r^2 ,x=rcosФ and        y=rsinФ
We thus have the first circle becomes x^2+y^2=2y ⇒r^2=2rsinФ Divide through by r,  and you get r=2sinФ(1).  
This is the upper circle in the previous posters diagrams .

The other equation of a circle becomes :
x^2 + y^2 =  1  ⇒ r^2 = 1 ⇒ r =  1   (2)      
These two curves intersect at :
r= 2sinФ =1 ⇒     sinФ=1/2  ⇒Ф= [tex]\alpha[/tex]/6 or 5[tex]\pi[/tex]/6    
From the previous poster's diagrams , we can see that there is as much mass on either side of the positive. y axis or
Ф=[tex]\pi[/tex]/2 axis in polar ; so , the X  coordinate of the center of mass is zero  
X=0 We can also see from his diagrams that the mass and moment of mass is symmetrical about the Ф=[tex]\pi[/tex]/2
we only need to integrate from Ф=[tex]\pi[/tex]/6 to Ф=[tex]\pi[/tex]/2  ( the answers from to are the same and double )
The differential of area in polar coordinates is
d A=rdrdФ  They say the area mass density is inversely proportional to the distance from the origin .

This can be written as : p=k/r. We can thus say the differential of mass is
d M=PDA=

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For statement 'A chi-square test of independence is used when both variables are ___.'

b. ordinal

d. nominal

In this question we have been given a statement 'A chi-square test of independence is used when both variables are ___.'

We need to select the correct choices for the given statement.

We know that the Chi-Square Test of Independence is used to test if two categorical variables are associated.

It is a nonparametric test.

It can only compare categorical variables.

The categorical variables are classified as nominal and ordinal variables.

Chi-Square Test is used to test for a statistically significant relationship between nominal and ordinal variables.

Therefore, for a chi-square test of independence is used when both variables ordinal  and nominal.

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Answer: To calculate the length of a loan, you need to know the total cost of the loan, the monthly payment amount, and the interest rate. In this case, the total cost of the car is $16,000, the monthly payment amount is $250, and the interest rate is 7.3%.

First, you need to calculate the total interest that will be paid on the loan. This can be done by multiplying the total cost of the loan by the interest rate, and then dividing by 100 to convert the result to a percentage. In this case, the total interest paid would be $16,000 * 7.3 / 100 = $1,168.

Next, you need to subtract the total interest from the total cost of the loan to find the total amount of the loan that will be used to pay for the car. In this case, the total amount of the loan used to pay for the car would be $16,000 - $1,168 = $14,832.

Finally, you can use this total amount and the monthly payment amount to calculate the length of the loan by dividing the total amount by the monthly payment amount. In this case, the length of the loan would be $14,832 / $250 = 59.32 months, or just over four years. The answer is 59.32 months.

Step-by-step explanation:

The probability that the product of the two two-digit numbers is less than 200 is given as follows:

43/8010.

A probability is calculated as the division of the number of desired outcomes in the context of the experiment by the number of total outcomes.

There are 90 different two-digit numbers, hence the number of total outcomes for the product is of:

90 x 89 = 8010.

(the numbers have to be different)

The desired outcomes which result in a product of less than 200 are of given as follows:

Hence the number of desired outcomes is given as follows:

9 + 8 + 6 + 5 + 4 + 4 + 3 + 2 + 2 = 43.

Meaning that the probability is of:

43/8010.

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Answer: 3

Step-by-step explanation: schoology whack

8 and 7 are missing frequency in the incomplete distribution.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Class Interval                       frequency            Cumulative frequency                  

0 -   10                                         3                                3                

10 - 20                                         a                              3+a                

20 - 30                                       20                           23+a              

30 - 40                                        12                           35+a              

40 - 50                                         b                          35+a+b  

Mode = 26    hence lies in 20 - 30

f of modal class = 20

Mode  = 20  +  10( 20 - a) / (20 - a + 20 - 12)

26 = 20 + 10 (20 - a) / (28 - a)

60(28 - a)  = 10 ( 20 - a)

168 -6a = 200 - 10a

4a = 32

a = 8

Class Interval                       frequency            Cumulative frequency                  

0 -   10                                         3                                3                

10 - 20                                         8                                11                

20 - 30                                       20                              31              

30 - 40                                        12                              43            

40 - 50                                         b                            43+b  

Median = 27

27  =  20  + 10  ( (43 + b)/2 - 11)/ 20

7 =  ( (21 +  b)/ 4

28 =     (21 +  b)

b = 7

Hence, the missing frequencies are 8 and 7.

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The freezing point of the 2.75 m solution of octane in benzene is -8.56 °C.

The freezing point of a solution is the temperature at which the solution becomes a solid. The freezing point of a solution is lower than the freezing point of the pure solvent because the solute particles interfere with the movement of the solvent molecules, which slows down the freezing process.

To determine the freezing point of a solution, we can use the freezing point depression equation:

ΔTf = Kf x molality

where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of the solute in the solution expressed in moles of solute per kilogram of solvent.

To find the freezing point of a 2.75 m solution of C8H18 (octane) in benzene, we need to know the freezing point depression constant for benzene, which is 5.12 °C/m. We can then use the equation above to calculate the change in freezing point:

ΔTf = 5.12 °C/m x 2.75 m = 14.06 °C

To find the freezing point of the solution, we need to subtract the change in freezing point from the freezing point of the pure solvent. The freezing point of pure benzene is 5.5 °C, so the freezing point of the 2.75 m solution of octane in benzene is:

5.5 °C - 14.06 °C = -8.56 °C

This means that the freezing point of the 2.75 m solution of octane in benzene is -8.56 °C. At this temperature, the solution will become a solid.

The value of AC according to given equation of Parallelogram is 188 units.

What is parallelogram?

In elementary geometry, a parallelogram may be a  quadrilateral with 2 pairs of parallel sides. the alternative or facing sides of a quadrangle square {measure} of equal length

Main body:

according to question:

AE = 9X-5

AC = 14X+34

as E is midpoint of AC so , we can say

2AE = AC

2(9x-5)= 14x+34

18x-10= 14x+34

4x = 44

x = 11

Now we need to find AC = 14x+34

                                         = 14*11+34

                                         = 188 units

Hence the value of AC according to given equation of Parallelogram is 188 units.

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The equations that represent a linear function are :

A linear function is a function that represents a straight line on the coordinate plane.  The degree of a linear equation must be 0 or 1 for each of its variables.

A linear function has the following form. y = mx + b.

A linear function has one independent variable and one dependent variable. The independent variable is x and the dependent variable is y.

Therefore, linear function can be represented in slope intercept form as follows;

y = mx + b

where

Therefore, the linear function of the equations are as follows;

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The required answer is the fourth root of 625 is 5. In summary, the fourth root of 625 is 5.

To find the fourth root of 625, we need to determine the number that, when raised to the power of 4, equals 625. Here's the step-by-step process:

Step 1: Start with the number 625.

Step 2: Take the fourth root of 625.

Since we're looking for the fourth root, we need to find a number that, when raised to the power of 4, equals 625.

Step 3: Determine the number that, when raised to the power of 4, equals 625.

To find this number, we can use the concept of exponentiation. Let's denote the unknown number as "x". Mathematically, we have [tex]x^4 = 625[/tex]..

Step 4: Solve the equation [tex]x^4 = 625[/tex].

To solve this equation, we need to find the value of x. Taking the fourth root of both sides of the equation, we have [tex]\sqrt[4]{(x^4)} =\sqrt[4] {625}.[/tex]

The fourth root of 625 is (625)^(1/4).

Step 5: Simplify the expression.

We can simplify [tex]\sqrt[4]{ 625}[/tex] as follows:

[tex]\sqrt[4]{ 625} = \sqrt[4]{ 5^4}= 5^{4/4} = 5^1 = 5.[/tex]

Therefore, the fourth root of 625 is 5. In summary, the fourth root of 625 is 5.

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The correct option that describes the vertical asymptote is; B: There is a vertical asymptote at x = 4 because Limit of g (x) as x approaches 4 minus = infinity and limit of g (x) as x approaches 4 plus = infinity

A vertical asymptote of a graph is defined as a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a.

A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;

In a graph, these vertical asymptotes are given by dashed vertical lines.

An example is a value of x for which the denominator of the function is 0, and the function approaches infinity for these values of x.

We are given the function;

g(x) = 2(x + 4)²/(x² - 16)

Simplifying the denominator gives;

(x² - 16) = (x + 4)(x - 4)

Thus, our function is;

g(x) = 2(x + 4)²/[(x + 4)(x - 4)]

(x + 4 ) will cancel out to give;

g(x) = 2(x + 4)/(x - 4)

Vertical asymptote:

Point in which the denominator is 0, so:

(x - 4) = 0

x = 4

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The number of meetings they attended in the last five years (x) and the number of papers they submitted to peer reviewed journals (y) during the same period is [tex]-8.6+3.15[/tex].

What is formula for slope and intercept is?

[tex]$$\begin{aligned}& b=\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& a=\bar{y}-b \bar{x} \\& \hat{y}=a+b x\end{aligned}$$[/tex]

The slope is

[tex]$$\begin{aligned}b & =\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& =\frac{12 \times 318-(12 \times 4)(12 \times 4)}{12 \times 232-(12 \times 4)^2} \\& =3.15\end{aligned}$$[/tex]

The intercept is

[tex]$$\begin{aligned}a & =\bar{y}-b \bar{x} \\& =4-3.13 \times 4 \\& =-8.6\end{aligned}$$[/tex]

The regression equation is

[tex]$$\begin{aligned}\hat{y} & =a+b x \\& =-8.6+3.15 x\end{aligned}$$[/tex]

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Step-by-step explanation:

Area of circle 1= pie r²

=3.14 x 5²

=3.14x 25

= 78.5km²

Area of circle 2=3.14 x 5.2²

= 3.14 x 27.04

= 84.9km²

change in area= 84.9-78.5

=6.4

radius²= 6.4/ 3.14

r²=2.03

r =√2.03

r=1.42

(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

What is the property of slopes of parallel lines and perpendicular lines?

If two lines are given and they are parallel to each other then the slopes are equal and for perpendicular lines, the product of their slopes is equal to -1.

(7) The line AB is passing through the points (-1, 5/2) and (3/2, -1/2).

   Slope = y2 - y2/x2 - x1

              = (-1/2 - 5/2)/(3/2-(-1))

              = -6/5

   As line AB and line CD are parallel in nature so the slope of line CD is also -6/5.

(8) The line AB is passing through the points (1/2, 1) and (5/2, 5/2).

    Slope = y2 - y2/x2 - x1

              = (5/2 - 1)/(5/2-1/2)

              =3/2/2

             = 3/4

    Line CD is passing through points (1, 1) and (2, 3).

    Slope = y2 - y2/x2 - x1

              = (3 - 1)/(2-1)

              =2/2

             = 1

  As the product of their slopes is not equal to -1.

  So lines are neither parallel nor perpendicular.

(9) Slope of AB can be computed as (-2, 1) and (-5, 5)

     Slope = 5 - 1/-5 + 2

                = 4/-3.

  The slope of line passing through the point P = -4/3 as we have to draw the parallel line.

 Point P = (-1, 3)

Equation of the line :

      y - 3 = -4/3(x + 1)

    3y +9 = -4x - 4

   3y = -4x - 13

Now we can draw the line

(10) Slope of line AB = -4/3

    So the slope of the line passing through point P should be 3/4 in order to be perpendicular to line AB.

     Equation of the line passing through point P:

       y - 3 = 3/4(x - (-1))

       y - 3 = 3/4(x+1)

Hence,

(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

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The supplement of BIE equals the supplement of GMD is a false assertion if lines BG and CF are parallel.

Angles with a supplementary sum are those whose sum is 180 degrees. For instance, the total of angle 130° and angle 50° is 180°, hence they are supplementary angles.

Lines BG and CF are parallel, as shown in the figure.

If BIE = X, then its supplement of BIE will be 180 - X;

similarly, if GMD = Y, then its supplement of GMD will be 180 - Y.

Since BG and CF are parallel, the supplements of BIE and GMD are interior angles on the same side ( as shown in figure)

and for parallel line the interior angle on the same side is 180

so 180 - X and 180 -Y there sum should be 180

They cannot be equal

line BG and CF are parallel, then the supplement of BIE = the supplement of GMD are not equal.

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The factor that produces the corresponding dimensions of cylinder B is: 3/2.

Similar solids have the same shape but different sizes, and which means the ratio of their corresponding linear measurements are the same.

To find the scale factor of similar solids, you can use the formula:

scale factor = (size of the similar solid) / (size of the original solid)

For example, if you have two similar solids, one with a volume of 64 cubic units and the other with a volume of 16 cubic units, the scale factor would be:

scale factor = (16 cubic units) / (64 cubic units) = 1/4

This means that the smaller solid is 1/4 the size of the larger solid.

Given the following:

Circumference of the base of cylinder A = 4π units [the radius = 2 units]

Area of the base of cylinder B = 9π units² [the radius = 3 units]

Scale factor = radius of the base of cylinder B / radius of the base of cylinder A

Scale factor = 3/2

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Complete Question:

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units. The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

The probability of drawing two numbers from both jars whose product is even = 5/9.

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.

Total number of outcomes =9

Favorable cases = (1,2), (2,1), (3,2), (2,3), (2,2)

The probability of drawing two numbers from both the jars whose product is even = 5/9

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The best interpretation of the standard deviation on this problem is given as follows:

A single value randomly selected from the distribution of w will vary from 4 by 3.5 attempted experiments.

The standard deviation of a data-set is calculated as the square root of the sum of the differences squared between each observation of the data-set and the mean, divided by the number of observations in the data-set.

The interpretation of this calculation is that the standard deviation represents by how much each value of the distribution is expected to vary from the mean, on average.

This means that the correct statement is given as follows:

A single value randomly selected from the distribution of w will vary from 4 by 3.5 attempted experiments.

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Answer:

I was willing to pay $20 more for the toy than I actually paid.

Step-by-step explanation:

Let us take the maximum bid be y

So,

(y × 60) ÷ 100 = 30

60y/100 = 30

60y/100 × 100 = 30 × 100

60y = 3000

60y/60 = 3000/60

y = 50

60% of $50 is $30

So,

50 - 30 = 20

Thus, I was willing to pay $20 more for the toy than I actually paid.

The terminal point on the unit circle use exact values are,

( x , y ) = ( [tex]\sqrt{\frac{3}{2} }[/tex] , - [tex]\frac{1}{2}[/tex] )

Decimals are the numbers, which consist of two parts namely, a whole number part and a fractional part separated by a decimal point. For example, 12.5 is a decimal number.

According to the question, it is provided that,

θ =  11π/6 radians

Now,

x = 1.cos(11π/6)

x = cos(11π/6)

x = cos(330°)

x = [tex]\sqrt{\frac{3}{2} }[/tex]

y = 1.sin(11π/6)

y = sin(11π/6)

y = -0.5

y = - [tex]\frac{1}{2}[/tex]

Then,

( x , y ) = ( [tex]\sqrt{\frac{3}{2} }[/tex] , - [tex]\frac{1}{2}[/tex] )

These two represents the terminal points

To find the terminal positions, we merely used the aforementioned equations, equated these two equations, and concluded that the same should be taken into consideration.

It could be figure out by using the x and y points

Therefore

The terminal point on the unit circle use exact values are,

( x , y ) = ( [tex]\sqrt{\frac{3}{2} }[/tex] , - [tex]\frac{1}{2}[/tex] )

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Answer:

125+25n

Step-by-step explanation:

We are given that

Heather opens a bank account with=$125

Each week she deposited money  into her account=$25

We have to find the explicit rule for the amount of money that has Heather after n weeks.

Heather has money after 1 week=125+25=$150

Heather has money after 2 week=125+2(25)=$175

Heather has money after 3 weeks=125+3(25)=$200

Heather has money after n weeks=125+25(n)

Hence, the explicit rule for the amount of money that has Heather after n weeks is given by

125+25n