The article source and supplementary information compare p-toluenesulfonic acid and Amberlyst-15 as catalysts that can be used to synthesis Methyl Diantilis. In a paragraph please summarize and explain the differences between these two catalysts. This summary should include both differences of chemical principles and laboratory practicality.

Answer:

Density of liquid = 1.59 g/cm³

Explanation:

We'll begin by converting 0.610 L to cm³. This can be obtained as follow:

1 L = 1000 cm³

Therefore,

0.610 L = 0.610 L × 1000 cm³ / 1 L

0.610 L = 610 cm³

Finally, we shall determine the density of the liquid. This can be obtained as follow:

Volume of liquid = 610 cm³

Mass of liquid = 972 g

Density of liquid =?

Density = mass / volume

Density of liquid = 972 / 610

Density of liquid = 1.59 g/cm³

The density of any given liquid is equivalent to the mass of the liquid divided by the volume of the liquid.

From the given information, we have:

The mass of the unknown liquid to be = 972 g

The volume of the unknown liquid to be = 0.610 L = 610 cm³

If the formula for calculating [tex]\mathbf{Density = \dfrac{Mass}{Volume}}[/tex]

Then;

[tex]\mathbf{Density \ of \ the \ unknown \ liquid = \dfrac{972 \\ g}{610 \ cm}}[/tex]

[tex]\mathbf{Density \ of \ the \ unknown \ liquid = 1.593442623 \ g/cm}[/tex]

The Density of the unknown liquid ≅ 1.593  g/cm³

In conclusion, the density of the unknown liquid is 1.593  g/cm³ to 3 significant figures.

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Answer:

∆o

Explanation:

Usually, the d level consists of a set of five degenerate d orbitals. These orbitals rema degenerate until the approach of ligands.

When ligands approach, the d orbitals are split into higher energy eg and lower energy t2g orbitals.

There exists an energy difference between this t2g and eg levels. This energy difference is called the octahedral crystal field splitting denoted as ∆o.

Answer:

Acids react with most metals to form hydrogen gas and salt. ... When an acid reacts with metal, salt and hydrogen gas are produced

Answer:

[tex]\boxed {\boxed {\sf 8.22 \ \textdegree C}}[/tex]

Explanation:

The question asks us to calculate the temperature of the gas at the higher volume. Since the pressure is constant, we are only concerned about volume and temperature. We will use Charles's Law. This states that the volume of a gas and the temperature of the gas have a directly proportionate relationship. The formula is:

[tex]\frac {V_1}{T_1}= \frac{V_2}{T_2}[/tex]

The gas starts at a volume of 4.17 liters and a temperature of 7.62 degrees Celsius.

[tex]\frac {4.17 \ L}{7.62 \textdegree C} = \frac{V_2}{T_2}[/tex]

The gas is expanded to a new volume of 4.50 liters, but the temperature is unknown.

[tex]\frac {4.17 \ L}{7.62 \textdegree C} = \frac{4.50 \ L}{T_2}[/tex]

We want to solve for the temperature at a higher volume. We must isolate the variable T₂. Cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

[tex]4.17 \ L * T_2 = 4.50 \ L * 7.62 \textdegree C[/tex]

The variable is being multiplied by 4.17 liters. The inverse of multiplication is division. Divide both sides by 4.17 L.

[tex]\frac {4.17 \ L * T_2 }{4.17 \ L}= \frac{4.50 \ L * 7.62 \textdegree C}{4.17 \ L}[/tex]

[tex]T_2=\frac{4.50 \ L * 7.62 \textdegree C}{4.17 \ L}[/tex]

The units of liters (L) cancel.

[tex]T_2=\frac{4.50 * 7.62 \textdegree C}{4.17 }[/tex]

[tex]T_2=\frac{34.29}{4.17 } \textdegree C[/tex]

[tex]T_2=8.22302158273 \textdegree C[/tex]

The original measurements of liters and temperature have 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place.

The 3 to the right in the thousandth place tells us to leave the 2 in the hundredth place.

[tex]T_2 \approx 8.22 \ \textdegree C[/tex]

The temperature of the gas at the higher volume is approximately 8.22 degrees Celsius.

Answer:

a) 0.001525 mol Ca(NO₃)₂

b) 2.29 × 10²⁴ atoms Mg

General Formulas and Concepts:

Atomic Structure  

Explanation:

a)

Calcium (Ca) has a +2 charge on the periodic table. Polyatomic ion for nitrate (NO₃) has a -1 charge. We need to balance the compound:

Ca(NO₃)₂

To find the molar mass of calcium nitrate, we must pull data from the PT.

Ca has a molar mass of 40.08 g/mol

N has a molar mass of 14.01 g/mol

O has a molar mass of 16.00 g/mol

Add these all together and multiply respectively to find the molar mass of the compound:

40.08 + 2[14.01 + 3(16.00)] = 164.1 g/mol

To find the amount of moles we have given grams, divide the grams by the molar mass:

(0.2502 g) / (164.1 g/mol) = 0.001525 mol Ca(NO₃)₂

We are given 4 sig figs and our final answer is in 4 sig figs.

b)

We need to know Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc. This converts moles into atoms, molecules, formula units, etc.

We are given 3.80 moles of Mg. To find the number of atoms, we multiply Avogadro's number:

3.80 mol Mg · (6.022 × 10²³ atoms Mg/ 1 mol Mg) = 2.28836 × 10²⁴ atoms Mg

Since we are given 3 sig figs, we must round:

2.28836 × 10²⁴ atoms Mg ≈ 2.29 × 10²⁴ atoms Mg

Answer:

Solution given:

a.

we have

1 mole of calcium nitrate=164.088g

now

0.2502g of calcium nitrate=1/164.088*0.2502=

0.0015248 mole of calcium nitrate

0.2502 grams of calcium nitrate

=0.0015248moles.

b.

1 mole of magnesium=[tex]6.02214076 × 10^{23}[/tex]atoms

3.80 mole of magnesium=[tex]6.02214076 × 10^{23}×3.80=2.2884*10^{24}[/tex]atoms

[tex]\bold{\underline{2.2884*10^{24}}}[/tex]atoms

are contained in 3.80 moles of magnesium.

Answer:

its kcl ,option.b)

Explanation:

because its contains k+and cl- which is and ionic bond

Answer:

The following properties are either physical or chemical. Which one is different from the rest based on those two categories? We chose all of the above

Answer:

1. RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)

2. Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)

3. (NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)

Explanation:

Let's consider the dissolving equations for the following compounds.

1. Rubidium hydroxide

RbOH(s) ⇒ Rb⁺(aq) + OH⁻(aq)

2. Sodium carbonate

Na₂CO₃(s) ⇒ 2 Na⁺(aq) + CO₃²⁻(aq)

3. Ammonium selenite

(NH₄)₂SeO₃(s) ⇒2 NH₄⁺(aq) + SeO₃²⁻(aq)

Answer:

the answer is d.) potassium

Explanation:

Answer:

Pilot scale up

Explanation:

Preformulation studies are carried out on candidate drug molecules that show sufficient pharmacological promise in animal model(pharma approach).

It involves preliminary study of the properties of a drug which is considered a potentially active ingredient against a particular disease condition.

Scale-up is the term used to refer to the increase in the batch size of a product. This is only done after a drug has been proven successful against the target disease after extensive pilot studies.

Scale-up is the last operation carried out when a drug has passed through all stages. It is not included in preliminary preformulation studies

D.22

is my answer than welcome

Answer:

19.3 g of NaCl can be produced

Explanation:

We state the reaction:

Cl₂ (g) + 2NaI (s) →  2NaCl (s) + I₂ (s)

We need to determine limiting reagent:

15.4 g . 1mol /70.9g = 0.217 moles of chlorine

49.6 g . 1mol / 149.89g = 0.331 moles of NaI

Ratio is 1:2. 1 mol of chlorine reacts to 2 moles of NaI

0.217 moles may react to (0.217 . 2)/1 = 0.434 moles of NaI

It is ok to say the NaI is the limting reactant because we need 0.434 moles of it and we only have 0.331.

Ratio is 2:2.

0.331 moles of NaI can produce 0.331 moles of NaCl

We convert mass to moles: 0.331 mol . 58.45g /mol = 19.3 g

Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

Answer:

[tex]Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary for us to write the complete molecular equation as shown below:

[tex]Pb(NO_3)_2(aq)+Ni(s)\rightarrow Ni(NO_3)_2(aq)+Pb(s)[/tex]

Now, we can separate the nitrates in ions as they are aqueous to obtain:

[tex]Pb^{2+}(aq)+2(NO_3)^-(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+2(NO_3)^-(aq)+Pb(s)[/tex]

And then, we cancel out the nitrate ions as the spectator ones, for us to obtain the net ionic equation:

[tex]Pb^{2+}(aq)+Ni(s)\rightarrow Ni^{2+}(aq)+Pb(s)[/tex]

Best regards!

Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.

hope this helps you

have a nice day:)

Answer:

3.07 Cal/g

Explanation:

Step 1: Calculate the heat absorbed by the calorimeter

We will use the following expression.

Q = C × ΔT

where,

Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ

According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.

Step 2: Convert 86.1 kJ to Cal

We will use the conversion factor 1 Cal = 4.186 kJ.

86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal

Step 3: Calculate the number of Cal per gram of candy

20.6 Cal/6.70 g = 3.07 Cal/g

Answer:

3: Lactone

Explanation:

Lactones are defined as carboxylic esters that contain the structure (−C(=O)−O−) which is essentially showing that an ester has now become part of the chemical structure of the ring.

Thus, looking at the question, it has the structure as defined in Lactones.

Thus, we can say that the compound is a Lactone.

Explanation:

the carbon would be sp3 hybridized, and it doesn't matter which carbon, since either of them have a full octet

Answer:

D. all of the above

Explanation:

A and C are verified by Keplar's laws of planetary motion.

B is verified by the equatorial and polar aces of the Planet.

Answer:

c

Explanation:

they dont have to orbit the sun specifically and are commonly more ovoid than spherical

Answer:

The answer is D. The energy possessed by an electron at a set distance from the nucleus.

Explanation:

Energy levels (also called electron shells) are fixed distances from the nucleus of an atom where electrons may be found. Electrons are tiny, negatively charged particles in an atom that move around the positive nucleus at the center.

Energy levels are the fixed amount of energy that a system described by quantum mechanics, such as a molecule, atom, electron, or nucleus, can have.

An energy level is the energy possessed by an electron at a set distance from the nucleus. Therefore, option D is correct.

Any discrete value from a set of total energy values for a subatomic particle constrained by a force to a finite space or for a system of such particles, such as an atom or a nucleus, is referred to as the energy level, also known as the energy state, in physics.

Since an electron's rotation in a shell is linked to a specific amount of energy. When it moves from one energy level to another, or when it jumps to another shell, the energy changes. As a result, a shell also indicates an electron's energy along with its location, and these are known as energy levels.

The shell or orbital that an electron is in with respect to the atom's nucleus is referred to as its primary energy level.

Thus, option D is correct.

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Answer:

Following are the responses to the given points:

Explanation:

For question 1:

Butanoic acid, butane, and butanone are also the three chemicals most dissolve in water. Its intermolecular force forces are produced by carboxylic acid functional groups with water.

For question 2:

Butanoic acid is a rancid buffer.

Methanoic acid is responsible for the stinging red ants

For question 3:

Methyl butanoate's chemical structure.

Answer: 0.085 (Ms)⁻¹

Explanation: Half life = 12 s

is the initial concentration = 0.98 M

Half life expression for second order kinetic is:

k = 0.085 (Ms)⁻¹

The rate constant for this reaction is 0.085 (Ms)⁻¹ .

Answer:

The left side equation is:

[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]

Explanation:

For the reaction of acetic acid HCH3CO2 with the water, The equilibrium constant equation is

[tex]HCH_{3}COO + H_{2}O \rightleftharpoons CH_{3}COO^{-} + H_{3}O[/tex]

The left side of this equilibrium constant equation will be written as shown below:

[tex]Ka = \frac{[CH_{3}COO^{-}] [H_{3}O^{+}]}{[HCH_{3}COO] [H_{2}O]}[/tex]

Answer:

2

Explanation:

Lead(|V) fluoride

Ammonium Nitrate

Lithium sulfide

For the rules, I don't know what you were taught. I just do it intuitively since I have done so much chemistry.

The first one the roman numerals represents the charge of the lead which much match the 4- charge from the 4 fluorides.

The second one is just two polyatomic ions which you just have to remember.

The last one is the typical ionic compound naming technique i guess.

Answer:

Solution given:

e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide

Solution given:

Balanced chemical equation:

[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]

when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide

f) chromium (III) hydroxide plus sulfuric acid

Balanced chemical equation:

[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]

When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.

g) aluminum metal plus chlorine gas

[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]

When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.

e) The heating of sodium carbonate to produces sodium oxide and carbon dioxide

Solution given:

Balanced chemical equation:

[tex]\boxed{\bold{\green{Na_{2}CO_{2} +heat \rightarrow Na_{2}O +CO_{2}}}}[/tex]

when sodium carbonate is heated it decomposed and form sodium oxide and carbon dioxide

f) chromium (III) hydroxide plus sulfuric acid

Balanced chemical equation:

[tex]\boxed{\bold{\green{2Cr(OH)_{3}+ 3H_{2}SO_{4} → Cr_{2}(SO_{4})_{3} + 6H_{2}O}}}[/tex]

When chromium (III) hydroxide react with sulfuric acid double displacement takes place and forms produce chromium(III) sulfate and water.

g) aluminum metal plus chlorine gas

[tex]\boxed{\bold{\green{2Al(s) + 3Cl_2(g) \rightarrow 2AlCl_2 }}}[/tex]

When aluminum metal is added to chlorine gas Combination reaction takes place and forms aluminum chloride.

Answer:

I think you can make 26, hope this helped.

Explanation:

Answer:

Option A. 1:1

Explanation:

From the question given above, the following data were obtained:

Li => 1s² 2s¹

Cl => 1s² 2s²2p⁶ 3s²2p⁵

Lithium (Li) will form compound with Cl by losing 1 electron as shown below:

Li —> Li⁺ + e¯ ..... (1)

Cl on the other hand will accept 1 electron from Li to form the chloride ion, Cl¯ as shown below:

Cl + e¯ —> Cl¯ ...... (2)

Combining equation 1 and 2, we have:

Li + Cl + e¯ —> Li⁺ + Cl¯ +

Cancel e¯ from both side

Li + Cl —> Li⁺Cl¯

Thus, the ratio of metallic cation (+) to non-metallic anion (-) in the compound is 1:1

``````````````````````````````````

Answer:

Alkenes, Markovnikov's, Alkenes, Alkyl halides, and less.

Explanation:

Alkenes must undergo addition because they have easily broken π bonds.

Markovnikov's rule states in the addition of HX to an unsymmetrical alkene, the H atom bonds to the less substituted carbon atom.

Alkenes are unsaturated hydrocarbons because they have fewer than the maximum number of hydrogen atoms per carbon.

Alkyl halides have good leaving groups and therefore readily undergo substitution and elimination reactions.

In hydroboration, the boron atom bonds to the less substituted carbon.