the bitewing tab is a heavy paperboard tab or loop fitted around a periapical film or sensor and used to stabilize the receptor during exposure. true
What is stabilize?
to stop changing and fix something, especially to prevent it from getting worse, or to induce something to stop changing and fix it: These drugs reduce blood pressure and calm your heart rate.
the periapical receptor is oriented in the bite loop so that the tab portion extends from the white side (tube side) of the film or sensor.True
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compare the time it takes for light to travel 1000 m on the surface of the earth and in outer space.
Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.
Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.
The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.
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A(n) ____________________ is a dynamic variable on the free store without any pointer pointing to it.
A inaccessible object is a dynamic variable on the free store without any pointer pointing to it.
How to find the height of an inaccessible object using sextant?Utilize the sextant's arc to determine the angle. By dividing the object's distance from the point of observation by the tan of the angle you calculated, you may use a scientific calculator to get the object's height.
How can heights and distances that are absent or unavailable be measured?The measuring of heights and distances that are unreachable is made easier by right-triangle trigonometry. By drawing a right triangle with the unknown height or distance as one of its sides and a known side and angle on the other, it is possible to determine the unknown height or distance.
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Answer:
dynamic variable
if an object producing sound is moving away from you, you would observe a wavelength than an object moving toward you. group of answer choices
If an object producing sound is moving away from us, the wavelength of the sound heard is longer than the actual wavelength. The conclusion is from the concept of Doppler effect.
What is the Doppler effect?The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.
The equation of the Doppler effect is
f₀ = [(v ± v₀)/(v ± vs)] × fs
Where
f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound wavesNote:
v₀ (+) if the observer moves closer to the sound source.vs (+) if the sound source moves away from the observer.When an object producing sound is moving away from us, the frequency of the sound we heard changed.
Let's say we are at rest, it means v₀ = 0. The sound source is moving away makes vs (+).
With the Doppler's effect, we get
f₀ = [(v+0) / (v+vs)] × fs
f₀/fs = v/(v+vs)
v < v+vs
f₀ < fs
The frequency of sound we heard is lower that the actual frequency.
The wavelength is inversely proportional to the frequency. It is described in the equation:
λ = c/f
It means that the lower the frequency, the longer the wavelength.
Hence, the phenomenon which the wavelength of the sound we heard is longer than the actual wavelength when the sound source is moving away from us is called the Doppler's effect.
Here is the group of answer choices:
(a) Band width
(b) Doppler's effect
(c) Sound refraction
(d) Vibrations
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Calculate the internal energy of 1.2moles of steam at 177degree
Answer:
18447 J
Explanation:
To calculate the internal energy of steam at a given temperature, we need to know the specific heat capacity of steam and the enthalpy of vaporization. The specific heat capacity of steam at a constant pressure is approximately 2.08 J/g*K, and the enthalpy of vaporization (latent heat) at 100°C is 2257 kJ/kg.
We can use the following equation to calculate the internal energy of steam at a given temperature:
U = m * Cp * (T - T_b) + m * L
Where U is the internal energy, m is the mass of the steam, Cp is the specific heat capacity of steam, T is the temperature of the steam, Tb is the boiling temperature of the steam, and L is the enthalpy of vaporization.
Since we are given the amount of steam in moles (1.2 moles) and the temperature (177°C), we can convert the moles of steam to mass using the molar mass of water (18 g/mol). The boiling temperature of water at standard atmospheric pressure is 100°C, so we can use this value for Tb.
First, we need to convert the temperature from degrees Celsius to kelvins:
T = 177°C + 273 = 450 K
Then, we can calculate the mass of the steam:
m = 1.2 moles * 18 g/mol = 21.6 g
Substituting these values into the equation for internal energy, we get:
U = 21.6 g * 2.08 J/g*K * (450 K - 273 K) + 21.6 g * 2257 kJ/kg
Solving for the internal energy, we get:
U = 18,447 J
Therefore, the internal energy of 1.2 moles of steam at 177°C is approximately 18,447 J.
A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page, as shown above. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines.
If wire loop is being pulled to the right with a constant velocity of 3 meters per second , then the potential difference induced between points X and Y is 3V .
it is given that a 5Ω resistor is connected between points X and Y ;
the magnetic field (B) = 0.5 ;
length of wire (l) [tex]=[/tex] 2 ;
velocity of the wire loop (v) = 3 m/s ;
the potential difference will be induced because charge separation on the vertical hand wire of wire loop.
Points X and Y are the same as the top and bottom of left wire.
The EMF(potential difference) induced in wire is given by
EMF = B*l*v
substituting the values ,
we get
= (0.5)(2)(3) = 3V
Therefore , the induced potential difference between points X and Y is 3V .
The given question is incomplete , the complete question is
A wire loop, 2 meters by 4 meters, of negligible resistance is in the plane of the page with its left end in a uniform 0.5-tesla magnetic field directed into the page. A 5-ohm resistor is connected between points X and Y. The field is zero outside the region enclosed by the dashed lines. The loop is being pulled to the right with a constant velocity of 3 meters per second. Make all determinations for the time that the left end of the loop is still in the field, and points X and Y are not in the field.
Determine the potential difference induced between points X and Y.
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A car moving with a speed of 90km/hr was brought to rest by the application of the
Brakes in 10s How far did the car travel after the brakes were applied?
The distance travelled by the car after the brake was applied is 125 m.
What is the distance travelled by the car?
The distance travelled by the car is calculated by applying the following kinematic equation as shown below.
Mathematically, the distance travelled by the car at the given average speed is calculated as;
s = [ ( v + u ) / 2 ] t
where;
v is the final velocity of the car = 0u is the initial velocity of the car = 90 km/hr = 25 m/st is the time of motion of the car = 10 sThe distance travelled by the car is calculated as;
s = [ ( 0 + 25 m/s ) / 2 ] ( 10 s )
s = 125 m
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One of the most controversial ideas to come out of instinct theories of aggression was Lorenz's proposal that society provide acceptable ways of permitting , or the process of discharging built-up aggressive energy.
The general instinct hypothesis, which contends that people are physiologically predisposed to or possess inclinations for violent behaviours, is known as the instinct theory of aggression in psychology.
This theory is more focused on aggression. The instinct theory of aggressiveness holds that human aggression is akin to sex and hunger, and that it can only be regulated rather than eradicated.In an effort to understand why we become aggressive and whether that behaviours can be altered, psychologists have developed three primary theories of aggression. Although many hypotheses have been put out, these three have proven most reliable and are crucial to comprehending the origins of violence. These hypotheses comprise as,
Adversity theory based on instinctTheory of Frustration and AggressionTheory of Social LearningTo know more about theory of aggression
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which of the following sequences lists methods for determining distance in the correct order from nearest to farthest?
Parallax, main-sequence fitting, cepheid variables, Tully-Fisher relation, and Hubble's law are the sequence lists methods for determining distance.
Parallax is the closest method for determining distance. This method uses the principle of triangulation to measure the distance of a nearby star relative to Earth. Main-sequence fitting is another method used to measure the distance of stars. This method compares the brightness of a star to other stars of known distance and luminosity to determine its distance.
Cepheid variables are stars whose brightness varies in a predictable way over time. This method uses the period of the star's brightness to determine its intrinsic luminosity, and then its distance. The Tully-Fisher relation is a method for measuring the distance of galaxies. This method uses the rotation speed of the galaxy and its brightness to calculate its distance.
Finally, Hubble's law is the most distant method for determining distance. This law states that the farther away a galaxy is, the faster it moves away from us. This allows us to calculate the distance of galaxies by measuring their rate of recession.
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crane lifts a 400 kg crate upward with an acceleration of 3.00 m/?. Determine the force on the crane.
The crane is under 5120 N of force. The crane touches the rock boulder and uses mechanical force to lift it.
What are the units of a force?Force is a physical phenomenon that can change an object's shape as well as its state of motion or rest. The SI unit of force is the Newton.
Cranes fall under which of the following three forces?Jib, gantry, and overhead cranes are the three pieces of machinery used most frequently in the industry. Depending on the type of item to be moved, either a chain or wire rope hoist will be used. In the shipbuilding sector, material handling is the main use of overhead cranes during the assembly process.
Briefing:
Mass (m) = 400kg
Acceleration (a) = 3.00 m/s^2
Gravitational acceleration (g) = 9.81 m/s^2
Force (F) = mg + ma
Force (F) = m (g + a)
Force (F) = 400 (9.81+3)
Force (F) = 5120 N
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what is the length of the y component shown below?
The length of the y component shown is C. 2.0.
How to find the length ?We are given the angle of the vector, and the length of one of the components of the vetor. Given the angle we have, the available component is the hypotenuse. The y component that we are to find, will then be the opposite or perpendicular component.
To solve for the length of the y - component therefore, the useful operation would be the Sin function.
The length of the y - component would be:
Sin 42 ° = Opposite / Hypotenuse
Sin 42 ° = y component / Hypotenuse
y - component = Sin 42 ° x Hypotenuse
y - component = Sin 42 ° x 3
y - component = 0. 6691 x 3
y - component = 2. 0
In conclusion, the y - component is 2.0.
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Full question is:
What is the length of the y-component of the vector shown below?
A. 2.2 B. 3 c. 2.0 D. 2.7A soccer player runs at 10 m/s and runs into a 80 kg referee standing on the field causing the referee to fly forward at 6.0 m/s. Assume the soccer player comes to complete stop after impact. What would be the mass of the soccer player be?
The mass of soccer player will be 120kg. Writing down 1/2 m1 will help us remember that KE = 1/2 mv2 (v1i) 2 + 1/2 m2(vi) (vi) 2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) 2.
How to solve ?According to Newton's third law,
Given that a soccer player runs at 10m/s and plows into a 80kg referee standing on the field causing the referee to fly forward at 56m/s. Let
mass of the player = ?
initial velocity of the player = 10m/s
Final velocity of the player
mass of the referee = 80 kg
Initial velocity of the referee = 0 ( since he is at rest )
Final velocity of the referee = 6 m/s
Since it is a perfectly elastic collision,
U1 =V2 - V1 ........ (1)
M1U1 = M2V2 + M1V1........ (2)
Substitute all the necessary parameters into the equation (1)
10 = 6 - V1
V1 = 10 - 6
V1 = 4 m/s
Now, Substitute all the necessary parameters into the equation (2)
10M1 = (80 x 6) + (4M1)
10 M1- 4 M1 = 480
4M1 = 480
M1 = 480/4
M1 = 120kg
Therefore, the mass of soccer player will be 120kg
Collision formula: What is it?When kinetic energy (KE) and momentum (p) are conserved during a collision, the collision is said to be elastic. To put it another way, it denotes that KE0 = KEf and po = pf. Writing down 1/2 m1 will help us remember that KE = 1/2 mv2 (v1i) 2 + 1/2 m2(vi) (vi) 2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) 2.
How is velocity determined?By dividing the entire distance traveled by the time it took the object to go a certain distance, you may calculate the object's initial velocity. V, d, and t are the three variables that make up the equation V = d/t.
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the use of the doppler effect in the study of astronomy
Emily and Henry were in the lab and graphed the heating of ice to 125°C. Emily and Brad made an observation that the graph contains three sloped and two level portions. Emily and Brad determined that the two level portions in the graph represented:
The two level portions in the graph represented phase changes.
What are phase changes?
The transition of matter from one state (solid, liquid, gas, or plasma) to another is referred to as a phase change. These changes also take place when the pressure on the system varies, as well as when the system receives enough energy or loses enough energy.
The slope of the line dividing two phases is determined by the relative densities of the two phases. The solid-liquid line, for instance, slopes up and to the right if the liquid is less dense than the solid, whereas up and to the left if the liquid is denser than the solid.
Therefore the two level portions in the graph represented phase changes.
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For a particular nonlinear spring, the relationship betweem the magnitude of the applied force F and the resultant displacement x from equilibrium is given by the equation F = k x^2 What is the amount of work done by stretching the spring a distace x0? A) kx0^3 B) (1/2)kx0 C) (1/2)kx0^3 D) (1/3)kx0^2 E) (1/3)kx0^3
To get the work, you have to integrate the force as a function of [tex]$x$[/tex] from zero displacement to Xo
[tex](Integral of) $\mathrm{k} \mathrm{x}^{\wedge} 2 \mathrm{dx}$ from 0 to $\mathrm{Xo}_{\mathrm{o}}=(1 / 3) \mathrm{k}\left(\mathrm{Xo}^{\wedge}\right)^{\wedge} 3$[/tex]
The work done by stretching the spring to the given distance is [tex]W=\frac{k x_0}{3}[/tex]
The given parameters:
- Applied force on the spring [tex]$=F$[/tex]
- Extension of the spring [tex]$=x_0$[/tex]
The work done by stretching the spring to the given distance is calculated as follows;
[tex]W=\frac{k x_0}{3}[/tex]
[tex]$$\begin{aligned}& W=\int_{x_a}^{x_b} F d x \\& W=\int_{x_a}^{x_b} k x^2 d x \\& W=k \int_{x_a}^{x_b} x^2 d x \\& W=k\left[\frac{x^3}{3}\right] \\& W=k\left[\frac{x_b-x_a}{3}\right] \\& W=k\left[\frac{x_0-0}{3}\right] \\& W=\frac{k x_0}{3}\end{aligned}[/tex]
Thus, the work done by stretching the spring to the given distance is
[tex]W=\frac{k x_0}{3}[/tex]
measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.
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Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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a particle moves under the influence of a conservative force. the equation for the potential energy as a function of position is given by: u(x)
A particle moves under the influence of a conservative force, The maximum x-coordinate of the particle at x = -3 m is 7 m.
Given that,
Potential energy of the particle u(x) = 5x² - 20x + 2
We know the relation between force and potential energy as,
F = -du/dx = -d/dx (5x² - 20x + 2) = -(10 x - 20 ) = 20 - 10 x at mean position x = 2.
At x = -3, amplitude is given by x = 2 - (-3) = 5
The maximum x co-ordinate is given as x = 5 + 2 = 7 m
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for the circuit below all values are rms with a source frequency of 60 hertz. the generator impedance is negligible (0 w). calculate the value of ib and and determine the value of vb-n. now, calculate the rms values of apparent, real and reactive power of zb. (show units for all)
The reactive power of the branch (Qb) can be calculated from its voltage and current 676.16 VA.
What is reactive power?Reactive power is the power in an AC circuit that is required to establish and maintain a voltage across a load. It is associated with the storage and release of energy in the form of electric and magnetic fields. Reactive power does not contribute to the actual work output of a system and is measured in Volt-amperes reactive (VARs). Power factor is a measure of reactive power relative to the total power in a system.
Source frequency = 60 Hz
Generator impedance = 0 W
Circuit:
Vg = 170 V
R1 = 10 Ω
R2 = 20 Ω
Zb = 20 + j10 Ω
The current flowing through the generator (Ig) and the branch (Ib) can be calculated from Ohm's Law:
Ig = Vg/R1 + Vg/R2 = 170/10 + 170/20 = 17 A
Ib = Ig - Vg/Zb = 17 - 170/(20 + j10) = 17 - 16.4 + j4.4 = 0.6 + j4.4 A
Since Ib is a complex number, we can find its magnitude (|Ib|) and angle (θ):
|Ib| = √(0.6² + 4.4²) = 4.46 A
θ = tan⁻¹(4.4/0.6) = 80.16°
The voltage across the branch (Vb-n) can be calculated using Ohm's Law:
Vb-n = Ib × Zb = (0.6 + j4.4) × (20 + j10) = -8.4 + j74.4 V
The apparent power of the branch (Sb) can be calculated from its voltage and current:
Sb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = -45.48 + j367.04 VA
The real power of the branch (Pb) can be calculated from its voltage and current:
Pb = Vb-n × Ib = (-8.4 + j74.4) × (0.6 + j4.4) = -45.48 - j367.04 W
The reactive power of the branch (Qb) can be calculated from its voltage and current:
Qb = Vb-n × Ib* = (-8.4 + j74.4) × (0.6 - j4.4) = 676.16 VA
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A large cannon is mounted on a cart with frictionless wheels that is initially at rest on a horizontal surface. The cannon fires a large cannonball to the right with a speed v_b which is then caught by a trap firmly attached to the cart. What is the final speed of the cannoncart-cannonball system? V > v_b, to the left
The final velocity of the cannonball-cart system is less than the initial velocity of the cannonball and the system will move in the direction of the cannonball ( V < v_b ).
What is the law of conservation of linear momentum?
The law of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.
Mathematically, the law of conservation of linear momentum is given as;
Pi = Pf
where;
Pi is the sum of the initial momentumPf is the sum of the final momentumm₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is the mass cannon ballu₁ is the initial velocity of the cannon ballm₂ is the mass of the cartu₂ is the initial velocity of the cartv is the final velocity of the cannoncart-systemsince the cart is initially at rest, the initial velocity of the cart = 0
m₁u₁ + 0 = v ( m₁ + m₂ )
m₁u₁ = v ( m₁ + m₂ )
v = ( m₁u₁ ) / ( m₁ + m₂ )
given initial velocity of the cannon ball = v_b
The final velocity of the cannonball-cart system is calculated as follows;
V = ( m₁v_b ) / ( m₁ + m₂ )
Hence, V < v_b
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Design a parallel RLC circuit (see (Figure 1)) with a resonant radian frequency of 5000 rad/s. Take that L 10 mH.a) Find the value of C Express your answer to three significant figures and include the appropriate units. C= 4.00 μFb) Find the value of R so that the response is critically damped. Express your answer to three significant figures and include the appropriate units R- 25.0 Ω
The value of R so that the response is critically damped using the equation is 25.0Ω.
What is Farads?Farads is the unit of measure for capacitance, which is the amount of electrical charge stored for a given voltage. Farads can be used to measure the amount of energy stored in a capacitor, which is made up of two conductive plates separated by an insulating material. The higher the capacitance, the more energy can be stored in a given capacitor. Farads are named after Michael Faraday, the British scientist who discovered the relationship between electricity and magnetism.
The resonant frequency of an RLC circuit is given by the equation:
ω_r=1/sqrt(LC)
where ω_r is the resonant frequency in rad/s, L is the inductance in Henries, and C is the capacitance in Farads.
Given the resonant frequency of 5000 rad/s and the inductance of 10 mH, we can calculate the capacitance as follows:
C=1/(ω_r^2*L)
C=1/(5000^2*0.01)
C=4.00μF
We can find the value of R so that the response is critically damped using the equation:
R=2*sqrt(L/C)
R=2*sqrt(0.01/4.00)
R=25.0Ω
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A uniform plane wave with parallel polarization is propagating in a lossless dielectric medium (l is € 1), and is incident obliquely onto a plane boundary with another lossless dielectric medium (u 2, E 2). (30%) (a) Derive the Snell's laws of reflection and refraction in terms of the refractive indices and angles. (b) Derive the general expressions for the reflection and the transmission coefficients of the EM field. Find such expressions in terms of the refractive indices if both media are nonmagnetic, i.e., M F M 240. (c) Derive the general expression for the Brewster angle. Find such an expression in terms of the refractive indices if both media are nonmagnetic. (d) Prove that, under the condition of no reflection, the sum of the Brewster angle and the angle of refraction is 90° if both media are nonmagnetic. (e) For total reflection to occur, find the condition for the medium property and the critical angle.
Transmission coefficients are used in physics and electrical engineering when considering wave propagation in discontinuous media. The snells law is n₁sinθ1 = n₂sinθ2
The transmission coefficient describes the amplitude intensity or total power of the transmitted wave relative to the incident wave. The transmission coefficient is defined as the ratio of the transmitted particle flux to the incident particle flux and depends on the incident energy.
The sum of the reflected and transmitted energy must equal the total incident energy, so the transmission coefficient is calculated simply by subtracting the reflection coefficient. The ratio of the reflected wave amplitude to the incident wave amplitude is called the reflection coefficient.
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In the figure, a climber leans out against a vertical ice wall that has negligible friction. Distance a is 0.945 m and distance L is 1.95 m. His center of mass is distance d = 0.89 m from the feet-ground contact point. If he is on the verge of sliding, what is the coefficient of static friction between feet and ground?
The coefficient of static friction between feet and ground is 0.2522.
What is static friction?Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.
The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as
fs =μsFN1
The μs can be calculated as
μs = a / √L² - a² x d / L
μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95
μs = 0.945 / √2.91225 x 0.89 / 1.95
μs = 0.2522
Thus, the coefficient of static friction between feet and ground is 0.2522.
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In a diffraction experiment, a coherent light source illuminates a pair of identical slits in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by 2.05 m. A student sketches the pattern that appears on the screen. The locations of the centers of the bright and dark fringes are accurate, but the shading is only qualitative. The color chosen may not be an ideal match to the actual light source. TITUTE THI HT -50.0 -40.0 -30.0 -20.0 -10.0 0.0 10.0 20.0 30.0 40.0 50.0 y (cm) * 25% Part (a) Enter the ratio of the slit separation, d, to the slit width, D, as a whole number. d = D TT 7 8 9 HOME E 4 5 6 sino cos tan cotano asin acos atan acotan sinh cosho tanh) cotanh O Degrees Radians 1 2 3 + 0 END . VO BACKSPACE DE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. A 25% Part (b) Calculate and enter the ratio of the slit width to the wavelength of the light source. A 25% Part (C) If the slit separation is 17 um, then calculate and enter the wavelength, in nanometers, of the light source. 25% Part (d) What is the slit width, in micrometers?
(a) The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width, in micrometers;
d = 20.5 µm
(a) We know that Fringe width is given by,
[tex]\beta =\frac{D\lambda}{d}[/tex]
Where,
D = slit to screen distance
λ = wavelength
d = slit width
Given in the question,
D = 2.05 m
[tex]\beta =4 cm=0.04m[/tex]
Now,
[tex]\frac{d}{D} =\frac{\lambda}{\beta } =\frac{400*10^{-9} }{0.04}[/tex]
d/D = 0.0001
Hence,
The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b) Ratio of d & λ,
[tex]\frac{d}{\lambda} =\frac{D}{\beta }[/tex]
[tex]\frac{d}{\lambda}=\frac{2.05}{0.04}[/tex]
[tex]\frac{d}{\lambda}=51.25[/tex]
Hence,
The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength of the light source,
[tex]\lambda=\frac{D\beta }{d}[/tex]
[tex]\lambda=\frac{17*10^{-6} *0.04}{2.05}[/tex]
[tex]\lambda=331.7nm[/tex]
Hence,
The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width,
[tex]d =\frac{D\lambda}{\beta }[/tex]
[tex]d=\frac{400*10^{-9} *2.05}{0.04}[/tex]
[tex]d=20.5 \mu m[/tex]
Hence,
The slit width, in micrometers;
d = 20.5 µm
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Determine the momentum of …
a. … an electron (m= 9.1 x10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbit in the H atom).
b. … a 0.45 Caliber bullet (m = 0.162 kg) leaving the muzzle of a gun at 860 m/s.
c. … a 110-kg professional fullback running across the line at 9.2 m/s.
d. … a 360,000-kg passenger plane taxiing down a runway at 1.5 m/s
A. The momentum of the electron is 1.98×10⁻²⁴ Kg.m/s
B. The momentum of the Caliber bullet is 139.32 Kg.m/s
C. The momentum of the professional fullback is 1012 Kg.m/s
D. The momentum of the passenger plane is 540000 Kg.m/s
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed mathematically as:
Momentum = mass × velocity
A. How do I determine the momentum of the electron?
Mass of electron = 9.1×10⁻³¹ KgVelocity of electron = 2.18×10⁶ m/sMomentum of electron =?Momentum = mass × velocity
Momentum of electron = 9.1×10⁻³¹ × 2.18×10⁶
Momentum of electron = 1.98×10⁻²⁴ Kg.m/s
B. How do I determine the momentum of the Caliber bullet?
Mass of Caliber bullet = 0.162 KgVelocity of Caliber bullet = 860 m/sMomentum of Caliber bullet =?Momentum = mass × velocity
Momentum of Caliber bullet = 0.162 × 860
Momentum of Caliber bullet = 139.32 Kg.m/s
C. How do I determine the momentum of the professional fullback?
Mass of professional fullback = 110 KgVelocity of professional fullback = 9.2 m/sMomentum of professional fullback =?Momentum = mass × velocity
Momentum of professional fullback = 110 × 9.2
Momentum of professional fullback = 1012 Kg.m/s
D. How do I determine the momentum of the passenger plane?
Mass of passenger plane = 360000 KgVelocity of passenger plane = 1.5 m/sMomentum of passenger plane =?Momentum = mass × velocity
Momentum of passenger plane = 360000 × 1.5
Momentum of passenger plane = 540000 Kg.m/s
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A certain 50.0-Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 13.0 kV/m. (a) What is the wavelength of this very low frequency electromagnetic wave? (b) What is its maximum magnetic field strength?
An electromagnetic wave radiating from a specific 50.0-Hz AC power line has a maximum electric field strength of 13.0 kV/m. This extremely low frequency electromagnetic pulse has a wavelength of 6.00 x [tex]10^{6}[/tex]m.
An electromagnetic wave is what?A sinusoidal graph illustrates electromagnetic waves. It is made up of time-varying electric and magnetic fields that are perpendicular to each other and to the direction that waves travel.
How do wavelength and frequency relate to one another?Inverse proportionality describes the relationship between frequency and wavelength. Longer wavelengths are correlated with lower frequency, and vice versa. The fact that a wave's speed is equal to the product of its frequency and wavelength helps to explain how these two properties are related.
Briefing:
Given that,
Frequency of the power line, f = 50.0 Hz
Value of maximum electric field strength of 13.0 kV/m
The wavelength of this very low frequency electromagnetic wave is given by using relation as:
[tex]c = f[/tex]λ
λ [tex]= \frac{c}{f}[/tex]
λ [tex]= \frac{3.8 * 10^{8} m/s }{50}[/tex]
λ = 6 x [tex]10^{6}[/tex] m
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(1) A table tennis ball is dropped
onto the floor from a height of
4m and it rebounds to a height of
3m. If the time of contact with the floor is 0.01s, what is the magnitude and direction of the acceleration during the contact.
Answer:
Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1
:. acceleration, a=v2+v1Δt ..(i)
When body falls from height h1,
then u=o,v1,a=gandS=h1
As, v21=u2+2aS,
:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1
Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2
As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2
Putting values in (i) we get,
a=2–√gh2+2–√gh1Δt)
a=2–√×9.8×3+2–√×9.8×40.01
= 1652m/s2.
Explanation:
What is the Force of Gravity acting on the object in the diagram?
The force of gravity acting on the 23 Kg object in the diagram is 225.4 N
How do I determine the force of gravity?The force of gravity is defined as follow:
Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Using the above formula, we can easily obtain the force gravity acting on the 23 Kg object. This is shown below:
Mass (m) = 23 KilogramsAcceleration due to gravity (g) = 9.8 m/s²Force of gravity (F) =?Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Force of gravity = 23 Kg × 9.8 m/s²
Force of gravity = 225.4 N
Thus, from the calculation made above, we can conclude that the gravitaional force is 225.4 N
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Question
A rabbit moves a distance of 85 meters in 13 seconds.
What is the rabbits average speed?
7.26 m/s
0.15 m/s²
6.54 m/s
6.54 m/s²
Important Formula:
[tex]s=\dfrac{d}{t}[/tex]
__________________________________________________________
[tex]d=85m[/tex] (measured in meters)
[tex]t=13s[/tex] (measured in seconds)
[tex]s=?[/tex] (measured in meters per second; m/s)
__________________________________________________________
[tex]s=\dfrac{d}{t}[/tex]
[tex]s=\dfrac{85}{13}[/tex]
__________________________________________________________
[tex]\fbox{6.54 m/s},\fbox{Option C}[/tex]
What does the law of conservation of energy state?
energy cannot be destroyed but it can change forms
energy always gets used up in every chemical reaction
energy can be destroyed but not created
energy is always the same and it cannot be changed
I think it is "energy cannot be destroyed but it can change forms".
based on the graphic, in what part of the electromagnetic spectrum does vegetation have the strongest response?
Between 400 nm and 700 nm of the electromagnetic spectrum, vegetation has the strongest response.
The electromagnetic spectrum travels in waves and spans an extensive spectrum from very long radio waves to very brief gamma rays. The human eye can simplest come across only a small portion of this spectrum called visible light.
In order from maximum to lowest power, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible mild, infrared radiation, and radio waves.
In a tumbler, the purple mild travels the fastest, and the violet light travels the slowest of all seven hues. Velocity and wavelength are without delay proportional.
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Joan is initially driving her car at 10 m/s when she decides to go faster. She accelerates uniformly at 4 m/s2 for 100 meters. How fast is Joan going?
a
50 m/s
b
35 m/s
c
30 m/s
d
26 m/s
Joan is going with speed 30 m/s. Hence, option (C) is correct.
What is acceleration?Acceleration is the rate at which a velocity changes over time. It qualifies as a vector quantity because it possesses both direction and magnitude. Meter/second^2 (m/s^2) is the SI unit of acceleration.
Given that: initial speed of the car: u = 10 m/s.
Uniform acceleration of the car: a = 4 m/s^2.
Distance travelled: s = 100 meters.
Let, the final speed is = v
Using the formula v² = u² + 2as, we get:
v = √(10² + 2×4×100) m/s.
= 30 m/s.
Hence, final speed of the car is 30 m/s.
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