Answer:
Explanation:
The Bohr effect describes how low pH (acidity) lowers the affinity of hemoglobin for oxygen, making hemoglobin more likely to offload oxygen in areas of low pH, which for reasons I'll get into, tissues in need of oxygen tend to have.
an object 5 cm in size is placed at 30 cm in front of a concave mirror of focal length 45 CM at what distance from the mirror should a screen be placed in order to obtain a shop image find the magnification size and nature of the image
Answer: Given: h₀=5cm
p=30cm
hi
f=45cm
require: q=?
hi=?
formulas:
1/f=1/p+1/q
hi/h₀=q/p
calculations:1/q=1/f-1/p
1/q=1/45-1/30
1/q=0.022=0.033
1/q= = -0.011
q=1/-0.011
q= -90.91cm
hi=p × h₀/q
hi=30ₓ5/-90.91
hi=150/-90.91
hi= -1.65cm
image is virtual , erect and diminished
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What symbol is a concentration be
[tex]Option \: (b)[/tex]
Explanation:
Second STATEMENT SAYS REGARDING TO THE CHEMICAL poison
A pendulum of mass 18 kg is released from rest at some height, as shown by
point A in the image below. At the bottom of its arc at point B, it is traveling at
a speed of 17 m/s. What is the approximate amount of energy that has been
lost due to friction and air resistance? (Recall that a=98 m/s2
By the work-energy theorem, the total work done on the mass as it swings is
W = ∆K = 1/2 (18 kg) (17 m/s)² = 153 J
No work is done by the tension in the string, since it's directed perpendicular to the mass at every point in the arc. Similarly, the component of the mass's weight mg pointing perpendicular to the arc also performs no work.
If we ignore friction/drag for the moment, the only remaining force is the parallel component of weight, which performs mgh = (176.4 N) h of work, where h is the vertical distance between points A and B.
Now, if w is the amount of work done by friction/air resistance, then
(176.4 N) h - w = 153 J
If you know the starting height h, then you can solve for w.
một vật m=1kg có động lượng bằng 10kg.m/s. động năng của vật là
how can mass be measured?
spring scale
balance
scale
bathroom scale
Answer:
ballance
i just took the quiz
Solid to gas and gas to solid on the basis of kinetic model.
Explanation:
The kinetic molecular theory of matter states that: ... The average amount of empty space between molecules gets progressively larger as a sample of matter moves from the solid to the liquid and gas phases. There are attractive forces between atoms/molecules, and these become stronger as the particles move closer together.
which is part of the convection cycle in earths atmosphere?
a. hot, denser air rises
b. cold, denser air rises
c. hot, less-dense air rises
d. cold, less-dense air falls
Help me please!!!!!!!!!
Answer:
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Explanation:
Answer pls. This is for People like me with this Question . Help!!! Question 3 of 20 What happens to the electric force between two particles if the distance between them is reduced by half? O A. It decreases to half the original force. OB. It increases to twice the original force. O C. It increases to 4 times the original force. O D. It decreases to 1/4 of the original force.
Answer:
It increases twice the original
Which statements describe a situation with a displacement of zero? Check all that apply.traveling south for 30 miles, then turning west and traveling another 30 milesriding on a Ferris wheel whose entrance and exit are the samewalking around the block, starting from and ending at the same houseriding on an escalator from the bottom floor to the top floorrunning exactly one lap around a racetrack
Answer:
• riding on a Ferris wheel whose entrance and exit are the same
• walking around the block, starting from and ending at the same house
• running exactly one lap around a racetrack
Explanation:
Displacement simply means the.change in position of an object. In a situation whereby the initial and final position are thesame, the displacement will be zero.
The statements that describe a situation with a displacement of zero include:
• riding on a Ferris wheel whose entrance and exit are the same
• walking around the block, starting from and ending at the same house
• running exactly one lap around a racetrack
Answer:
• riding on a Ferris wheel whose entrance and exit are the same
• walking around the block, starting from and ending at the same house
• running exactly one lap around a racetrack
Explanation:
B,C,E
A ball is launched horizontally at 150 m/s from a cliff. What is its vertical speed after 3 seconds?
A. 150 m/s
B. 50 m/s
C. 0 m/s
D. 30 m/s
Answer:
v_f = 30 m/s
Explanation:
v_f = v_I + a*t
v_f = 0m/s + (9.81m/s²)*(3s)
v_f = 29.43m/s
v_f = 30 m/s
Since the object is being launched horizontally off the cliff the only vertical force acting on the ball is gravity which is an acceleration of 9.81m/s². So we have all the flowing information to use the the kinematic equation: v_f = v_I + a*t.
A frictionless pulley used to lift 8000N of concrete. What is the minimum effort required to raise the block
Answer: 8000N
Explanation: since it is frictionless that means it has 100% efficiency therefore the mechanical advantage is 1 meaning the load equals to the effort
Can someone help me with this Physics question please?
Q. The half-life of tritium (hydrogen-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a mishap, what mass of the sample will remain after 49.2 years?
Answer:
Explanation:
The formula for this, the easy one, is
[tex]N=N_0(\frac{1}{2})^{\frac{t}{H}[/tex] where No is the initial amount of the element, t is the time in years, and H is the half life. Filling in:
[tex]N=48.0(\frac{1}{2})^{\frac{49.2}{12.3}[/tex] and simplifying a bit:
[tex]N=48.0(.5)^4[/tex] and
N = 48.0(.0625) so
N = 3 mg left after 12.3 years
How many half-lifes is 49.2 years ?
(49.2 years) / (12.3 years per half-life) = 4 half-lifes.
In 4 half-lifes, (1/2) · (1/2) · (1/2) · (1/2) of the original sample remains.
That's (1/2⁴) or (1/16) of the original.
(1/16) of 48.0 mg = 3 mg .
=======================
Step-by-step:
== Start with 48 mg .
== After one half-life, 24 mg remains.
== Then, after the second half-life, 12 mg remains.
== Then, after the third half-life, 6 mg remains.
== Then, after the fourth half-life, 3 mg remains.
While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.
After the police car passes, its frequency is 460Hz. What is the speed of the police car? (speed of
sound = 340 m/s)
Answer:
v = 17.68 m/s
Explanation:
Given that,
While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.
After the police car passes, its frequency is 460Hz.
We need to find the speed of the police car.
The formula is as follows :
[tex]v=\dfrac{v_o(f-f')}{f+f'}[/tex]
Put all the values,
[tex]v=\dfrac{343(510-460)}{510+460}\\\\=17.68\ m/s[/tex]
So, the speed of the police car is 17.68 m/s.
1. Which pair of physical quantities consists of two vectors?
a. Electric charge and momentum
b. Displacement and distance
c. Velocity and force
d. Temperature and kinetic energy
Answer:
Velocity and force consists of two vectors as they both have magnitude and direction
Pair of physical quantities consists of two vectors are velocity and force.
What are physical quantities ?"The seven elemental physical quantities are mass, time, temperature, mole, length, luminosity, and electrical charge. "Some derived physical quantities are velocity, heat, density, pressure, and momentum. Extensive physical quantities depend on the amount of substance or the size of the object.
What is velocity ?"Velocity is the speed at which something moves in a particular direction. For example as the speed of a car travelling north on a highway, or the speed a rocket travels after launching. "The scalar means the absolute value magnitude of the velocity vector is always be the speed of the motion.
Know more about physical quantity here
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Why is a flower not a good blackbody radiator?
Answer:
A flower emits only visible light
A flower reflects much of the light that hits it
write the relation of m² with its a multiple
Explanation:
The square meter is the SI-derived unit of area. It has a symbol m² (33A1 in Unicode). It is defined as the area of a square whose sides measure exactly one metre.
Convertir 25 km/h a m/s
Answer:
6.9 m/s
Explanation:
1000m = 1km
3600s = 1hr
25000m/3600s
6.9m/s
Different nutrients play different roles in our bodies. Which is the energy-storing nutrient?
O carbohydrates
O minerals
O proteins
O fats
Answer:
D. Fats
Explanation:
they are the long term energy storing nutrient carbohydrates are a quick way for energy minerals dont contain any energy and neither do proteins
fats
Explanation:
it is nutrient kept in the body
Cuánto demorará un cuerpo en alcanzar su máxima altura, sabiendo que fue lanzado, verticalmente hacia arriba, con una velocidad cuyo valor fue de 90 m/s?
Answer:
The maximum height reached is 413.27 m.
Explanation:
How long will it take for a body to reach its maximum height, knowing that it was thrown, vertically upwards, with a velocity whose value was 90 m / s?
initial velocity , u = 90 m/s
gravity, g = 9.8 m/s^2
Let the maximum height is h.
At maximum height the velocity v = 0
Use third equation of motion
[tex]v^2 = u^2 - 2 gh\\\\0 = 90\times 90 - 2 \times 9.8 \times h\\\\h = 413.27 m[/tex]
A walkway suspended across a hotel lobby is supported at numerous points along its edges by a vertical cable above each point and a vertical column underneath. The steel cable is 1.27cm in diameter and is 5.75m long before loading. The aluminum column is a hollow cylinder with an inside diameter of 16.14cm, and an unloaded length of 3.25m. When the walkway exerts a loa force of 8500N on one of the support points, through what distance does the point move down?
Answer:
[tex]\triangle I=8.60*10^{-4}m[/tex]
Explanation:
From the question we are told that:
Diameter [tex]d=1.27cm[/tex]
Length [tex]l=5.75m[/tex]
Diameter of aluminum column [tex]d_a=16.14cm[/tex]
Length of aluminum column [tex]l_a=3.25m[/tex]
Load Force [tex]F=8500N[/tex]
Generally the equation for Young modulus is mathematically given by
[tex]\gamma=\frac{FL}{A \triangle L}[/tex]
Given the The load force
[tex]F=\frac{Y_aA_a\triangle I}{L_a}+\frac{YA \triangle I}{L}[/tex]
[tex]\triangle I=\frac{F}{\frac{Y_aA_a}{L_a}}+\frac{YA}{L}[/tex]
[tex]\triangle I=\frac{8500N}{ \frac{7*10^{10} \pi (0.1624^2-0.1614^2)}{4*3.15}+ \frac{20*10^10 \pi (0.0127^2)}{4(5.75)}}[/tex]
[tex]\triangle I=8.60*10^{-4}m[/tex]
An object elongates from a length of 45 cm to a length of 55 cm. The percent strain is
41%
22%
122%
82%
18%
36%
Answer:
22%
Explanation:
55 - 45 = 10
10/45 simplifies to 2/9
2/9 = 0.22222... so 22.22% (rounded 22%)
slader At a carnival, you can try to ring a bell by striking a target with a 10.8-kg hammer. In response, a 0.408-kg metal piece is sent upward toward the bell, which is 4.23 m above. Suppose that 18.8 percent of the hammer's kinetic energy is used to do the work of sending the metal piece upward. How fast must the hammer be moving when it strikes the target so that the bell just barely rings
Answer:
The hammer must be moving at a speed of approximately 4.082 meters per second.
Explanation:
According to the statement and based on Principle of Energy Conservation, change in gravitational potential energy experimented by the metal piece ([tex]U_{g,o}[/tex]), in joules, must be equal to 18.8 percent of the translational kinetic energy of the hammer ([tex]K_{h}[/tex]), in joules.
[tex]U_{g, o} = 0.188\cdot K_{h}[/tex] (1)
By definitions of gravitational potential and translational kinetic energies, we expand (1):
[tex]m_{o}\cdot g\cdot h = 0.188\cdot \left(\frac{1}{2}\cdot m_{h}\cdot v^{2}\right)[/tex] (2)
Where:
[tex]m_{o}[/tex] - Mass of the metal piece, in kilograms.
[tex]g[/tex] - Gravitational acceleration, in meters per square second.
[tex]h[/tex] - Distance travelled by the metal piece, in meters.
[tex]m_{h}[/tex] - Mass of the hammer, in kilograms.
[tex]v[/tex] - Initial speed of the hammer, in meters per second.
If we know that [tex]m_{o} = 0.408\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]h = 4.23\,m[/tex] and [tex]m_{h} = 10.8\,kg[/tex], then the initial speed of the hammer is:
[tex]m_{o}\cdot g\cdot h = 0.188\cdot \left(\frac{1}{2}\cdot m_{h}\cdot v^{2}\right)[/tex]
[tex]10.638\cdot m_{o}\cdot g \cdot h = m_{h}\cdot v^{2}[/tex]
[tex]v = 3.261\cdot \sqrt{\frac {m_{o}\cdot g \cdot h}{m_{h}}}[/tex]
[tex]v = 3.261\cdot \sqrt{\frac{(0.408\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.23\,m)}{10.8\,kg} }[/tex]
[tex]v \approx 4.082\,\frac{m}{s}[/tex]
The hammer must be moving at a speed of approximately 4.082 meters per second.
The engine starter and a headlight of a car are connected in parallel to the 12.0-V car battery. In this situation, the headlight operates at 38 W and the engine starter operates at 2.40 kW. If the headlight and starter were then rewired to be in series with each other, what total power would they consume when connected to the 12.0-V battery
Answer:
The total power they will consume in series is approximately 2.257 W
Explanation:
The connection arrangement of the headlight and the engine starter = Parallel to the battery
The voltage of the battery, V = 12.0 V
The power at which the headlight operates in parallel, [tex]P_{headlight}[/tex] = 38 W
The power at which the kick starter operates in parallel, [tex]P_{kick \ starter}[/tex] = 2.40 kW
We have;
P = V²/R
Where;
R = The resistance
V = The voltage = 12 V (The voltage is the same in parallel circuit)
For the headlight, we have;
R₁ = V²/[tex]P_{headlight}[/tex] = 12²/38 = 72/19
R₁ = 72/19 Ω
For the kick starter, we have;
R₂ = V²/[tex]P_{kick \ starter}[/tex] = 12²/2.4 = 60
R₂ = 60 Ω
When the headlight and kick starter are rewired to be in series, we have;
Total resistance, R = R₁ + R₂
Therefore;
R = ((72/19) + 60) Ω = (1212/19) Ω
The current flowing, I = V/R
∴ I = 12 V/(1212/19) Ω = (19/101) A
We note that power, P = I²R
In the series connection, we have;
[tex]P_{headlight}[/tex] = I² × R₁
∴ [tex]P_{headlight}[/tex] = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W
The power at which the headlight operates in series, [tex]P_{headlight, S}[/tex] ≈ 0.134 W
[tex]P_{kick \ starter}[/tex] = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W
The power at which the kick starter operates in series, [tex]P_{kick \ starter, S}[/tex] ≈ 2.123 W
The total power they will consume, [tex]P_{Total}[/tex] = [tex]P_{headlight, S}[/tex] + [tex]P_{kick \ starter, S}[/tex]
Therefore;
[tex]P_{Total}[/tex] ≈ 0.134 W + 2.123 W = 2.257 W
which best describes how air moves during convection?
a. cool air warms as it mixes with denser air
b. warm air cools as it mixes with cooler, denser air
c. warm air is displaced by cooler denser air
a. cool air warms as it mixes with denser air
Explanation:
c. warm air is displaced by cooler denser air
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what is the source of energy
A 25.0 kg probe fell freely with acceleration of 2.00 m/s^2 just before it landed on a distant planet. What is the weight of the space probe on that planet
Answer:
The weight of the probe is 50 Newtons
Explanation:
Newtons second law states that F = ma
Given the mass of 25kg, and the acceleration of 2m/s^2, we can substitute both values into the equation to find the weight force.
[tex]F = ma[/tex]
[tex]F = 25 * 2[/tex]
[tex]F = 50N[/tex]
The weight of the probe is 50 Newtons
Is a nanoliter greater then one liter?
Deepta adhivnav having weight 450N and 350N are playing see-saw. Deepta sits at a distance of 2m from the fulcrum, how far should abhinav be seated in order to balance deepta?
Answer:
Explanation:
This is a torque problem where balance is achieved when the sum of the torques equal 0. The equation for torque is
[tex]\tau=F*r[/tex] where F is the force in Newtons that is perpendicular to the lever arm, and r is the length of the lever arm in meters.
450(2) = 350r and
[tex]\frac{450(2)}{350}=r[/tex] so
r = 2.6 m
Size of image is equal to size of object in convex lens, when object is placed:
(a) at F
(b) between F & O
(c) between F & 2F
(d) at 2F
Pls answer fast
Explanation:
the object should be placed at 2F
Answer:
at 2F
Explanation:
hope it will help you
