the coefficient of x in -7xy is -7​

Answer:

31 square units

Step-by-step explanation:

See the picture below.

Each full or almost full square was counted first. There are 24 of them.

Then parts of squares of counted together to add to 1 square. They are color coded in the figure below. After adding them all up, the total was 31.

The area of the irregular shape is,

⇒ 27.5 square units

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

The irregular shape is very similar to a trapezium with coordinates are,

(-3,3), (2, 2), (2, -2) and (-3, -4).

Now, We know that;

Area of a trapezium is,

⇒ [(a + b)/2] × h

where, a and b refer to the two parallel sides and h is the distance between them.

Hence,  From the above coordinates:

a = 7 length units,

b = 4 length units and

h = 5 length units.

Therefore, We get;

The approximate area = [(7 + 4)/2]5

                                   = 27.5 square units

Thus, The area of the irregular shape is,

⇒ 27.5 square units

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Answer:

x = 17/4

Step-by-step explanation:

Let x = the number

8x-14 = 4x+3

Subtract 4x from each side

8x -14-4x = 4x+3-4x

4x-14 = 3

Add 14 to each side

4x-14+14 = 3+14

4x = 17

Divide by 4

4x/4 = 17/4

x = 17/4

Answer:

[tex]{ \tt{3 {y}^{2}(y + 4) - 7(y + 4) }} \\ = { \tt{(y + 4)( {3y}^{2} - 7) }}[/tex]

Answer:

8^1/3

Step-by-step explanation:

(8^5/3)^1/5

8^5/3×1/5

8^5/15

8^1/3

Answer:

Step-by-step explanation:

Exponent Rule: [tex](a^{m})^{n}=a^{m*n}[/tex]

[tex](8^{\frac{5}{3}})^{\frac{1}{5}}= 8^{\frac{5}{3}}*{\frac{1}{5}}\\\\\\=8^{\frac{1}{3}}\\\\= \sqrt[3]{8} \\\\= \sqrt[3]{2*2*2}\\\\= 2[/tex]

Answer:

3

Step-by-step explanation:

Given the polynomial : p(x)=1−2x2−3x3+4x

Rearranging : p(x) = -3x³ - 2x² + 4x + 1

Looking at the polynomial Given, we can see that it is a univariate polynomial, that is it has only one variable which is x. Thus for polynomials of this sort, the order of the polynomial is the highest exponent occurring in the polynomial equation. Therefore, the order of the polynomial above is 3, because the highest power of the function is 3.

This means that those with 4 as their highest exponent are of order 4 and those with highest exponent as 2 are of order 2.

The answer is: (2, 3) :)

we have to find the value of the x°=<GHC

In the triangle BDH,

<D=31°

<B=47°

we know that,

Sum of three angle of a triangle is 180°

According to the question,

<D+<B+<BHD=180°

31°+47°+<BHD=180°

78°+<BHD=180°

<BHD=180°-78°

<BHD=102°

But,

<GHC and <BHD forms a straight line

so,

<GHC+<BHD=180°

102°+x=180°

x=180°-102°

x=78°

Therefore,

The value of x is 78°

Answer:

Numbers greater than or equal to 0.

Step-by-step explanation:

The domain of this function is {x∈R | x≥0}, meaning that x can be anything greater than or equal to 0.

Answer:

119.95 years

Step-by-step explanation:

The general equation is given by:

[tex]P = A*(1 + \frac{r}{n} )^{n*t}[/tex]

Where:

A is the initial amount, we know that the first deposit is of $150, then:

A = $150

t is the variable, in this case, is the number of years.

n =  number of times that the interest is compounded in one unit of t, because the interest is compounded monthly, we have n = 12.

r = interest rate in decimal form.

r = 2.5%/100% = 0.025

Replacing these in our equation, we get that:

[tex]P = 150*(1 + \frac{0.025}{12} )^{12*t}[/tex]

Now we want to find the time such that his savings, P, are equal to $3000.

Then we need to solve the equation:

[tex]P = 150*(1 + \frac{0.025}{12} )^{12*t} = 3000[/tex]

[tex](1 + \frac{0.025}{12} )^{12*t} = 3000/150 = 20\\[/tex]

Now, remember that:

Ln(a^x) = x*ln(a)

So if we apply the natural logarithm to bot sides, we get:

[tex]Ln((1 + \frac{0.025}{12} )^{12*t}) = Ln( 20)\\\\(12*t)*Ln(1 + \frac{0.025}{12}) = Ln(20)\\\\t = \frac{Ln(20)}{12*Ln(1 + \frac{0.025}{12})} = 119.95[/tex]

So after 119.95 years you will have the $3000.

Answer:

See attachment for graph

Step-by-step explanation:

See comment for correct question

Given

[tex]y = \log_bx[/tex]

Required

The corresponding points on [tex]y =b^x[/tex]

On the graph, we have:

[tex](x_1,y_1) \to (1,0)[/tex]

[tex](x_2,y_2) \to (2,1)[/tex]

[tex](x_3,y_3) \to (4,2)[/tex]

[tex](x_4,y_4) \to (8,3)[/tex]

[tex](x_5,y_5) \to (16,4)[/tex]

First, we solve for b in [tex]y = \log_bx[/tex]

Using laws of logarithm, the equivalent of the above is:

[tex]x = b^y[/tex]

[tex](x_2,y_2) \to (2,1)[/tex] implies that:

[tex]2 = b^1[/tex]

[tex]2 = b[/tex]

Rewrite as:

[tex]b =2[/tex]

So, the equation [tex]y =b^x[/tex] becomes:

[tex]y = 2^x[/tex]

Using the same values of x, we have:

[tex](x_1,y_1) = (1,2)[/tex]

[tex](x_2,y_2) = (2,4)[/tex]

[tex](x_3,y_3) = (4,16)[/tex]

[tex](x_4,y_4) = (8,256)[/tex]

[tex](x_5,y_5) = (16,65536)[/tex]

See attachment for graph

The points (1,2), (2,4), and (4,16) are plotted on the graph attached below and this can be determined by using the given data.

Given :

Logarithmic Function  --  [tex]\rm y = log_b(x)[/tex]    --- (1)

The following steps can be used in order to determine the corresponding points that must be on the graph [tex]\rm x = b^y[/tex]:

Step 1 - Now, substitute the value of x and y that is (2,1) in the expression [tex]\rm x = b^y[/tex].

[tex]\rm 2 = b^1[/tex]

b = 2

Step 2 - Now, substitute the value of b in the equation [tex]\rm y=b^x[/tex].

[tex]\rm y = 2^x[/tex]    --- (2)

Step 3 - At (x = 1) the above expression becomes:

y = 2

Step 4 - At (x = 2) the expression (2) becomes:

y = 4

Step 5 - At (x = 4) the expression (2) becomes:

y = 16

The graph of [tex]\rm y = 2^x[/tex] is attached below.

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Answer:

Hello,

3

Step-by-step explanation:

Let say x the whole number not null to find.

[tex]x+\dfrac{1}{x} =\dfrac{10}{3} \\\\\\\dfrac{x^2+1}{x} =\dfrac{10}{3} (reducing\ to\ the\ same\ denominator)\\\\3x^2+3=10x\ (cross\ products)\\\\\\3x^2-10x+3=0\ (passing\ all\ terms\ in\ the\ first\ member)\\\\\Delta=10^2-4*3*3=64=8^2\\\\x=\dfrac{10-8}{6} =\dfrac{2}{6}= \dfrac{1}{3} \ not \ a \ whole\ number\\\\x=\dfrac{10+8}{6} =3\\\\[/tex]

[tex] \Huge \underline {\mathcal {{{\color{orange}{108 \degree}}}}} [/tex]

Option ( A ) is the correct answer.

Answer:

[tex]18n - 24[/tex]

Step-by-step explanation:

[tex]6(3n - 4) = 18n - 24[/tex]

Answer:

18n-24

Step-by-step explanation:

6(3n-4)

Open the brackets .......

(6×3n)-(6×4)

=18n_24

Answer:

Mean = 30516.67

Standard deviation, s = 3996.55

P(x < 27000) = 0.0011518

Step-by-step explanation:

Given the data:

28500 35500 32600 36000 34000 25700 27500 29000 24600 31500 34500 26800

Mean, xbar = Σx / n = 366200 /12 = 30516.67

Standard deviation, s = [√Σ(x - xbar) / n-1]

Using calculator, s = 3996.55

The ZSCORE = (x - mean) / s/√n

Zscore = (27000 - 30516.67) / (3996.55/√12)

Zscore = - 3516.67 / 1153.7046

Zscore = - 3.048

P(x < 27000) = P(Z < - 3.049) = 0.0011518

Answer:

x=5

Step-by-step explanation:

The sides have to be equal length

3x+4 = 5x-6

Subtract 3x from each side

3x+4-3x = 5x-6-3x

4 = 2x-6

Add 6 to each side

4+6 = 2x-6+6

10 = 2x

Divide by 2

10/2 =2x/2

5 =x

Two parallel sides is 3x + 4 = 5x - 6

[tex]\bf \large \longrightarrow \: \: 3x \: + \: 4 \: = \: 5 x \: - \: 6[/tex]

[tex]\bf \large \longrightarrow \: \:6 \: + \: 4 \: = \: 5x \: - \: 3x[/tex]

[tex]\bf \large \longrightarrow \: \:10 \: = \: 2x[/tex]

[tex]\bf \large \longrightarrow \: \: \frac{10}{2} \: = \: x \\ [/tex]

[tex]\bf \large \longrightarrow \: \: \cancel\frac{10}{2} \: \large \: ^{5} \: = \: x \\ [/tex]

[tex]\bf \large \longrightarrow \: \:x \: = \: 5[/tex]

Option ( B ) is the correct answer.

Answer:

[tex]8x^{4}[/tex]

3n-10

(a÷5)+12

Step-by-step explanation:

Numbers listed as in the picture.

70) 8 * [tex]x^{4}[/tex]= [tex]8x^{4}[/tex]

71) 3 * n -10= 3n-10

72) 12+ a/5= (a÷5)-12

Given:

Dividing a number by 2 always results in a smaller number.

To find:

The counterexample to the given claim.

Solution:

If 0 is divided by is divided by any non-zero real number [tex]a[/tex], then

[tex]\dfrac{0}{a}=0[/tex]

Let us consider the unknown number be 0. Then dividing a number by 2, we get

[tex]\dfrac{0}{2}=0[/tex]

Here, the result is not a smaller number because [tex]0=0[/tex].

Therefore, the counterexample to the given claim is "Dividing 0 by 2".

Answer:

-1

Step-by-step explanation:

Answer:

What was the average temperature change per hour -3 degrees per hour​

Step-by-step explanation:

Take the temperature drop and divide by the time

-13 1/5 ÷ 4 2/5

Change to improper fractions

-(13 *5+1)/5 ÷ (4*5+2)/5

-66/5 ÷22/5

Copy dot flip

-66/5 * 5/22

Rewrite

-66/22 * 5/5

-3 degrees per hour

Since we are looking for a drop

3 degrees per hour

Answer:

( 25 x 100 )

option 1 is the answer

Step-by-step explanation:

Remaining options are not correct since they don't have 100 as a factor.

Step-by-step explanation:

HELIUM: To fill air balloon

ARGON: Used for filling incandescent metal filament electric bulbs

Answer: I divided 16.75 by 5

Step-by-step explanation:

For every 1 gallon hes using 3.35

So 22 x 3.35 is 73.70 so hell need 70 cent more

Answer:

look at the png below

Step-by-step explanation:

Answer:

y = 4x-3

Step-by-step explanation:

First we need to determine the slope

Using two points on the line (0,-3)  (1,1)

Using the slope formula

m = (y2-y1) /(x2-x1)

   = (1- -3)/(1-0)

 (1+3)/  (1-0)

  4

We know the y intercept, -3

y = mx+b where m is the slope and b is the y intercept

y = 4x-3

Answer:

  r = K * q / V

Step-by-step explanation:

V =  K * q / r

Answer:

-1

Step-by-step explanation:

Increasing the x-value by one results in the y-value decreasing by 1. Therefore, the average rate of change is -1.

Answer: -1

Step-by-step explanation: ;)

Answer:

[tex]4.\\\text{E. }x=5, x=-6,\\\\5.\\\text{A. }x=7, x=-3\\\\\text{18.}\\\text{D. No mistakes.}[/tex]

Step-by-step explanation:

For [tex]a=|b|[/tex], there are two cases:

[tex]\begin{cases}a=b,\\a=-b\end{cases}[/tex]

Question 4:

Given [tex]5|2x+1|=55[/tex],

Divide both sides by 5:

[tex]|2x+1|=11[/tex]

Divide into two cases and solve:

[tex]\begin{cases}2x+1=11,2x=10, x=\boxed{5}\\-(2x+1)=11,2x+1=-11, 2x=-12, x=\boxed{-6}\end{cases}[/tex]

Therefore, the solutions to this equation are [tex]\boxed{\text{E. }x=5, x=-6}[/tex].

Question 5:

Given [tex]\frac{1}{2}|4x-8|-7=3[/tex],

Add 7 to both sides:

[tex]\frac{1}{2}|4x-8|=10[/tex]

Multiply both sides by 2:

[tex]|4x-8|=20[/tex]

Divide into two cases and solve:

[tex]\begin{cases}4x-8=20,4x=28, x=\boxed{7}\\-(4x-8)=20, 4x-8=-20, 4x=-12, x=\boxed{-3}\end{cases}[/tex]

Therefore, the solutions to this equation are [tex]\boxed{\text{A. }x=7, x=-3}[/tex]

Question 18:

There are no mistakes in the solution shown. The answer properly isolates the term with absolute value with no algebraic mistakes. Following that, the answer divides the equation into both absolute value cases and solves algebraically correctly. Therefore, the correct answer is [tex]\boxed{\text{D. No mistakes.}}[/tex]

Put the data set in order:

12, 14, 24, 31, 41, 46, 49

In order to find a value of x using the range, x has to be on either end of the data set. Meaning:

x, 12, 14, 24, 31, 41, 46, 49 or 12, 14, 24, 31, 41, 46, 49, x

Since the range is the highest value minus the lower value, you can set two equations for x:

x - 12 = 63

x = 75

49 - x = 63

x = -14

Thus, x = 75, -14

Two values of x are -14 & 75

The difference between highest and lowest numbers of the set of numbers is called the range of numbers.

The given values are 12, 46, 31, 49, 24, 41, 14

Arranging all the values in ascending order we get,

12, 14, 24, 31, 41, 46, 49

If x will be included, then x is in the 1st position or in the last position.

Then the values are x, 12, 14, 24, 31, 41, 46, 49 or 12, 14, 24, 31, 41, 46, 49, x

The range of the number is 63

So, we get two equations from it.

1 ) 49-x = 63

2 ) x-12 = 63

Solving eq. (1) we get, x = 49-63 = -14

Solving eq. (2) we get, x = 63+12 = 75

So the values of x are -14 & 75

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Answer:

4

Step-by-step explanation:

8-2x=5(x-4)

8-2x=5x-20

28=7x

x=4

Answer: x=4

given equation: 8 - 2x= 5(x-4)

STEP 1: distribute the 5 with ONLY the parenthesis which is (x-4)

so it will be 5x-20 (-20 because 5 x -4= -20)

Now the equation is 8 - 2x= 5x - 20

STEP 2: ADD 20 on both SIDES

8+20= 28

New equation: 28 - 2x= 5x

STEP 3: ADD 2x on both sides 2x+5x= 7x

STEP 4: Now divide 28 by 7

28/7= 4

Therefor x= 4

Given:

In a quadrilateral ABCD, diagonals AC and BD intersect at point E.

[tex]AE\cong EC[/tex]

[tex]BE\cong DE[/tex]

To prove:

The figure is a parallelogram.

Solution:

We know that if the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.

In a quadrilateral ABCD, diagonals AC and BD intersect at point E.

[tex]AE\cong EC[/tex]

[tex]BE\cong DE[/tex]

Since the diagonals AC and BD of a quadrilateral ABCD bisect each other, therefore the quadrilateral ABCD is a parallelogram.

Hence proved.