The daily supply of oxygen for a particular multicellular organism is provided by 625 square feet of lawn. A total of 8750 square feet of lawn would provide the daily supplies of oxygen for how many organisms

Answer:

2x = 3

Step-by-step explanation:

Here we have a balanced equation using the hanger method.

The left side shows two x'es, so the left side of the equation should be 2x.

The right shows three units with a value of "1", so the right side of the equation should be 3.

As a result, 2x = 3 is our final answer.

Answer:

Michelle < Staci < Kelly < Kyle

Kyle is the greatest distance from work, while Michelle is the closest to work.

Step-by-Step Explanation:

1 kilometer = 0.62137119 mile(s)

4.5 miles = 0.62137119 × 4.5 = 2.79617036 kilometers

4,200 meters = 4.2 kilometers

670,000 centimeters = 6.7 kilometers

So,

Michelle = 2.8 kilometers (rounded up)

Kelly = 5.6 kilometers

Staci = 4.2 kilometers

Kyle = 6.7 kilometers

So,

Michelle < Staci < Kelly < Kyle

Kyle is the greatest distance from work, while Michelle is the closest to work.

Hope this helps! ^^

Answer:

28cm

Step-by-step explanation:

7x4

or

7+7+7+7

Answer:

First, do 4x*4x. then,16x*16x. next, 64x*64x. and,256x*256x. answer:1024x. Divide 1024x by 8x. answer to that is 128.

Answer:

The expression in simplified form:

[tex]\frac{4x^5}{8x}=\frac{x^4}{2}[/tex]

Step-by-step explanation:

Given the expression

[tex]\frac{4x^5}{8x}[/tex]

We need to simplify the expression.

Simplifying the expression

[tex]\frac{4x^5}{8x}[/tex]

Cancel the common factor: 4

[tex]=\frac{x^5}{2x}[/tex]

Cancel the common factor

[tex]=\frac{x^4}{2}[/tex]

Therefore, the expression in simplified form:

[tex]\frac{4x^5}{8x}=\frac{x^4}{2}[/tex]

Answer:

hi deez

Step-by-step explanation:

Answer:

let natural no be x

(x-20)=96/x

x²-20x-96=0

x²-24x+4x-96=0

x(x-24)+4(x-24)=0

(x-24)(x+4)=0

either

x=24

x=-4

Answer:

6

Step-by-step explanation:

it as a interior angle of a regular polygon is 23

Answer:

7x + 21

Step-by-step explanation:

7(x+3)

7x + 7(3)

7x + 21

[tex] - 4s = - 10 - 5s \\ - 4s + 5s = - 10 \\ s = - 10[/tex]

[tex] - 4( - 10) = - 10 - 5( - 10) \\ 40 = - 10 + 50 \\ 40 = 40 \: \: \tiny \boxed{ \green \checkmark}[/tex]

No Solutions

When both sides of equation are different. For example, 3 = 4 which makes the equation false. That means the equation is false for all real numbers, thus having no solutions.

One Solution

A common type solution because you see this type of solution a lot. If you can solve the equation for a variable like x = 2 or s = 0. That's one solution.

Infinitely Many Solutions

When both sides are same like 3 = 3 or 7 = 7. That means the equation is true for all real numbers. You can see this type of solution by solving the equation with same both sides like 3x+2 = 3x+2.

Answer:

x=23

Step-by-step explanation:

You simplify both sides of the equation, then isolate the variable.

Answer:

x=23

Step-by-step explanation:

Answer:

Step-by-step explanation:

A = (3.14)(8)2

= 200.96

Answer:

4x-3 or A

Step-by-step explanation: because there are 4 x's and 3 "-" which makes it 4x-3

Answer:

Hi, this is a strange problem but I believe the answer is A) 4x-3.

Step-by-step explanation:

I think the X symbols represent "X"es and the dashes represent single negative digits. I may be wrong, but I think this is what your teacher is most likely looking for. Good luck! :)

Answer:

725/100 X 15 = 108.75

108.75 + 80 = 188.75

weekend = $188.75

Answer:

6; 8; 10

Step-by-step explanation:

First side: x

Second side: x+2

Third side: x+4

x + x + 2 + x + 4 = 24

3x + 6 = 24

3x = 18

x=6

First side: 6

Second side: 8

Third side: 10

Answer:

1/8

Step-by-step explanation:

Answer:

The equation in slope-intercept form perpendicular to the given equation [tex]y = -3x + 4[/tex] through the given point (6,-2) is [tex]\mathbf{y=\frac{1}{3}x}[/tex]

Step-by-step explanation:

We need to write an equation in slope-intercept form perpendicular to the given equation through the given point

y = -3x + 4

(6,-2)

The general equation in slope intercept form is: [tex]y=mx+b[/tex] where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding slope:

The given line is perpendicular to required line, so there slopes are opposite

The slope of given line [tex]y = -3x + 4[/tex] is m = -3, (By comparing it with general equation y=mx+b, we get m = -3)

The slope of required line is: [tex]m = \frac{1}{3}[/tex]

Finding y-intercept:

y-intercept can be found by using slope [tex]m = \frac{1}{3}[/tex] and the point(6,-2)

[tex]y=mx+b\\-2=\frac{1}{3}(-6)+b\\-2=-2+b\\b=-2+2\\b=0[/tex]

So, we get y-intercept b =0

Equation of required line:

So, the equation of required line having slope [tex]m = \frac{1}{3}[/tex] and y-intercept b =0 is:

[tex]y=mx+b\\y=\frac{1}{3}x+0\\y=\frac{1}{3}x[/tex]

So, the equation in slope-intercept form perpendicular to the given equation [tex]y = -3x + 4[/tex] through the given point (6,-2) is [tex]\mathbf{y=\frac{1}{3}x}[/tex]

Answer:

R(t) = 10 + 0.50t

Step-by-step explanation:

Answer:

The traveller's speed is 5ft/s and the walkway speed is 3ft/s

Step-by-step explanation:

Given

Represent the traveller's speed with T and the walkway's speed with W.

When the traveller walk against the walkway, we have:

[tex]T - W = 2[/tex] ---- i.e. 2ft/s against the walkway

When the traveller walk with the walkway, we have:

[tex]T + W = 8[/tex] ---- i.e. 8ft/s with the walkway

Required

Solve for W and T

[tex]T - W = 2[/tex] --- (i)

[tex]T + W = 8[/tex] --- (ii)

Add (i) and (ii)

[tex]T + T - W + W = 2 + 8[/tex]

[tex]T + T = 2 + 8[/tex]

[tex]2T = 10[/tex]

Divide both sides by 2

[tex]\frac{2T}{2} = \frac{10}{2}[/tex]

[tex]T = \frac{10}{2}[/tex]

[tex]T = 5[/tex]

Substitute 5 for T in (ii)

[tex]T + W = 8[/tex]

[tex]5 + W = 8[/tex]

Make W the subject

[tex]W = 8 - 5[/tex]

[tex]W = 3[/tex]

Hence, the traveller's speed is 5ft/s and the walkway speed is 3ft/s

Answer:

Draw a line of a givens point

Answer:

4:7  7 being to total number of marbles (part to whole ratio)

There are 16 blue marbles were in the bag before I added more.

A ratio indicates how many times one number contain in another number. The ratio of two number is written as x : y, which is equivalent to x/y. Where, x and y are individual amount of two quantities. And, Total quantity gives after combine as x + y.

Given that;

The ratio of blue marbles to yellow marbles is 4 : 3.

And,  If I add 5 blue marbles and remove 3 yellow marbles, the ratio will be 7:3.

Now,

Since, The ratio of blue marbles to yellow marbles is 4 : 3.

Hence, Number of blue marbles = 4x

Number of yellow marbles = 3x

And, If I add 5 blue marbles and remove 3 yellow marbles, the ratio will be 7:3.

Then, We can formulate;

⇒ 4x + 5 / 3x - 3 = 7x / 3x

⇒ (4x + 5) / (3x - 3) = 7 / 3

⇒ 3 (4x + 5) = 7 (3x - 3)

⇒ 12x + 15 = 21x - 21

⇒ 15 + 21 = 21x - 12x

⇒ 36 = 9x

⇒ x = 4

Thus, The number of blue marbles = 4x

                                                      = 4 × 4

                                                      = 16

Learn more about the ratio visit:

https://brainly.com/question/169670

#SPJ2

Answer: 6

Step-by-step explanation:

Answer:

[tex]y = 4x + 6[/tex]

Step-by-step explanation:

Given

[tex]Initial\ Fee = \$6.00[/tex]

[tex]Rate = \$4.00[/tex]

Required

Derive the linear equation

Let the number of games be x.

Let the total cost be y

So, if the rate of 1 game is $4

Then x games costs 4x

The total cost (y) is then calculated as:

y = Initial Fee + Cost of x games

Substitute values for initial fee and cost of x games

[tex]y = 6 + 4x[/tex]

Rewrite as:

[tex]y = 4x + 6[/tex]

Answer:

Linear function

Step-by-step explanation:

None of the X values repeat so its Linear

Answer:

Darn, I could have helped you but I'll leave it to the boys :) goodluck!!

Answer:

(a) When a = 4 and b = -5,  a² + b² - a·b = 61

(b) When a = 4 and b = -5,  a³·b + a·b² = -220

(c)  [tex]When \ a = 4 \ and \ b = -5, \ \dfrac{a - b}{a + b} + a -b = 0[/tex]

(d) When a = 4 and b = -5, (a + b)² - (a - b)² = 82

Step-by-step explanation:

The question relates to evaluation of expressions, given the values of the variables, "a" and "b"

Where;

a = 4 and b = -5

(a) For a² + b² - a·b, we have;

a² + b² - a·b = 4² + (-5)² - 4 × (-5) = 16 + 25 + 20 = 41 + 20 = 61

(b) For a³·b + a·b² we have;

a³·b + a·b² = 4³·(-5) + 4·(-5)² = 64 × (-5) + 4 × 25 = -320 + 100 = -220

(c) For [tex]\dfrac{a - b}{a + b} + a -b[/tex], we have;

[tex]\dfrac{a - b}{a + b} + a -b = \dfrac{4 - (-5)}{4 + (-5)} + 4 - (-5) = \dfrac{4 + 5}{4 -5} + 4 + 5= \dfrac{9}{-1} + 4 + 5 = -9 + 4 + 5 = 0[/tex]

[tex]\therefore when \ a = 4 \ and \ b = -5, \ \dfrac{a - b}{a + b} + a -b = 0[/tex]

(d) For (a + b)² - (a - b)² we have;

(a + b)² - (a - b)² = (4 + (-5))² - (4 - (-5))² = (4 - 5)² - (4 + 5)² = (-1)² - 9² = 1 + 81 = 82

When a = 4 and b = -5, (a + b)² - (a - b)² = 82