Answer:
physical, or biological anthropology.
Explanation:
When there is a need to study human kind through the X-ray of relationships between human biology, its cultural diversity, and evolution ,the aspect anthropology for this is Biological anthropology.
Therefore biological anthropology is concerned about how the interaction between the cultural diversity and biological process results in the adaptations of mankind to different environments.The influence of these on growth, behaviours, existence.
The primary focus of biological anthropologists is to study in details the concept of ,mechanism of variation, adaptation.and how these lead to evolution and origin of mankind.
Sequel to this ,most evidences for this concept are obtained from the study of fossil materials,study of other related primates to man, and components of functional biology and genetics.
The most abundant element in the body of living things is: a) Hydrogen b) Nitrogen c) Carbon d) Oxygen
Answer:
D. Oxygen
Explanation:
Oxygen is the most abundant element in the bodies of living things. For example, oxygen is about 65% of the human body.
Oxygen in the body is mostly in the form of water, since the bodies of living things need water to create energy needed every day.
You believe that the cytosolic protein p007 is involved in mediating growth hormone-stimulated proliferation in cells. You wish to establish a cell model using your cultured fibroblasts. Provide clear explanations to the following, each worth 2.5 pts each. a) Describe how you would transfect the growth hormone receptor DNA into your cells to create stable cell lines, and include a description of the benefits of using stable cell lines versus transiently transfected cell line. b) Describe how you would measure specific receptor binding of GH to your stable cell line. c) Describe how you would measure growth hormone-induced proliferation in your stable cell line. Make sure to include controls. d) Describe how you would use RNAi to demonstrate the requirement for p007 in growth-hormone stimulated proliferation. Make sure to include controls.
Answer:
Following are the answer to this question:
Explanation:
In option a:
There are many ways, which can be defined as follows:
It keeping cells "qualified," use heat shock and handle ions like Ca and ice incubating.It uses Micro-injection with DNA. It uses the biolistics or even the process of gene-gun.The stable cell charts indicate simple and definitive outcomes when their relationship to specific results. Moreover, relative to temporary cell lines, findings are more reliable and error-free. These lines also easily break and much less.
In option b:
Radio tests including linking tests could be used
The Ligand Binding Assays is an analysis, that is based on the binding of ligands to antibodies, or other macromolecules. Its existence and distance of formed ligand-receptor complexes are defined using a system of measurement that is usually electrical or fluorescent.
In option c:
The method for measuring the levels of cell growth is accessible and the Another way is to measure the metabolism within the same cell. So many color pigments were also accessible that can permeate an organism as well as react with some proteins as well as other factors, and that can effectively identify a color final product.
Throughout relation to the amount of metabolism exercise, cell proliferation could be evaluated by researching one or even more cell markings. The BrdU limited liability assessment is a very well-published illustration.
Its specific antibody can detect BrdU and high BrdUincorporations levels are linked to high levels of cell proliferation. Command cell without DNA receptor growth hormone.
In option d:
The cell growth will stop after each use of RNA interference ( RNAi). The p007 formation as well as the effect on growth caused by the intrusion will be a goal. If development is delayed effectively, the theory will be tested successfully to a cell without any of the required DNA. The RNAi is the free cell
According to kirk smith a professor of environmental health at the university of california berkley indoor fires increase risks of pneumonia tuberculosis lung cancer and low birth weight in babies born of women expose during pregnancy. What simple solution is being widely promoted to reduce the risk of death?
a) preparing meals using solar cookers.
b) switching from wood to burning crop waste as a fuel source.
c) adding more windows to houses as a source of ventilation.
d) passing a green tax to make homeowners pay for their pollution.
e) providing asthma inhalers to children under the age of 12 years.
Answer:
preparing meals using solar cookers.
Explanation:
solar cookers radiates at low rates.Therefore the most of the nutrients in the foods are conserved.Thus most micro nutrients for biochemical activities are retained. Vitamins which can not withstand high temperature are preserved.
Most importantly carcinogens which are usually associated with high heat foods are avoided ,when cook with low heat of solar cookers
The solar cooker is smoke free,therefore irritation of the lungs,lung cancer associated with high heat cookers is avoided.
Specifically,local Mayan women exposed to high heat smoke cookers, suffers lung cancer,and those with pregnancy gives to infants with low birth weights. Children exposed to theses high heat also experienced acute lower respiratory infections.
Thus the smokeless,low heat solar cooker is safer.
Animal migration on savannas is often governed by
distance
reproduction
rainfall
fire
Answer:
The answer would be rainfall.
Explanation:
The reason why this is the answer is because rain is essential for survival in such a hot and dry climate. Droughts are quite frequent in the savanna and the lack of water leads to the death of many organisms.
Answer:
Rainfall is what often governs animal migration on savannas.
Explanation:
Brainlies please
4. Unlike a scientific theory, a scientific law describes an observed pattern in nature without
attempting to explain it.
O true
Ofalse
Answer:
False
Any discovery must first be tested and have an explanation
Outside the lining of the alveolus is blood, which is at a gauge pressure of 5 mmHg, while air is contained inside the alveolus. What is the absolute pressure inside the alveolus
Answer:
765 mmHg
Explanation:
The gauge pressure = 5 mmHg
To get the absolute pressure we use the relationship
[tex]P_{ab}= P_{g}+ P_{atm}[/tex]
where [tex]P_{ab}[/tex] is the absolute pressure = ?
[tex]P_{g}[/tex] is the gauge pressure = 5 mmHg
[tex]P_{atm}[/tex] = atmospheric pressure = 760 mmHg
substituting, we have
[tex]P_{ab}[/tex] = 5 mmHg + 760 mmHg = 765 mmHg
Explain what, if any, is the issue facing DNA polymerase in regards to its 5’->3’ activity when replicating DNA.
Answer:
The two strands of DNA are replicated in different ways
Explanation:
DNA replication is a process that occurs during the S phase of the cell cycle that consists of making two identical copies of the double-stranded DNA molecule, which subsequently are distributed in the daughter cells during cell division. During this process, DNA polymerase can add nucleotides in 5' to 3' direction, but not in 3' to 5' direction. In consequence, the DNA strand that has 3’ to 5’ directionality can be synthesized directly, while the DNA template strand that has 5’ to 3’ directionality can't be synthesized in a continuous manner and thereby it is created by adding small DNA fragments, which are known as Okazaki fragments (150-200 nucleotides in size).
Saprobic microorganisms are important decomposers of plant litter, animal matter, and dead microbes. This is an example of a(n) ______________.
Answer:
The correct answer would be - heterotrophs (chemoheterotrophs)
Explanation:
Heterotrophs are the living organisms that are directly or indirectly depend on the autotrophs or the organisms that can make their own food for energy and growth.
Saprobic microorganism are free living organisms that get their energy from decomposing rotten or dead organic matter such as plant litter, animal matter and dead microbes. It is performed with the help of enzymes or chemicals they release to decompose such matter. they also known as chemoheterotrophs.
Thus, the correct answer would be - heterotrophs (chemoheterotrophs).
Provide one example of quantitative data that can be collected when using a microscope?
Answer: there 3 ducks by the pond
Explanation:
Quantitative is numbers. how many.
S100A8 sex chromosome? yes or no
Answer:
yes !!
Explanation:
because it's yes !!
Answer:
YES
Explanation:
I know this because i looked it up
who is the father of Genetic
Answer:
hey there
Explanation: answer is gregor mendal is the father of genetic in 19th century.
Answer:
Gregor Johann Mendel
DIHYBRID CROSSES
In all of the examples we have only been concerned with one trait. It is possible, however, to track the inheritance of more than one trait at a time. When one is investigating the inheritance of two traits at once the cross is called a dihybrid cross. Strictly speaking, a dihybrid cross is one between two individuals that are heterozygous for two traits, meaning that they are hybrids in two senses. For example, in humans eye color is determined by multiple factors, but if we compare only blue eyes to brown eyes, brown is dominant (R) and blue acts as a recessive allele (r). If a man heterozygous for both eye color and bent little finger has a child with a woman who also heterozygous for both traits, this would be a dihybrid cross. Which is/are possible genotypes for a person with bent little finger and blue eyes?
1. bbrr
2. BBRR
3. BBrr
4. Bbrr
Referring to the previous question, which is/are possible genotypes for a person with straight little finger and blue eyes?
1. bbrr
2. BbRr
3. Bbrr
4. bbRr
Answer:
Question 1: bbrr
Question 2: bbRr
Explanation:
To address the first question, the possible genotype for someone with bent little finger and blue eyes would be bbrr.
Since brown eye (B) is dominant over blue eyes (b), in order for the blue eye color to be expressed, it has to be in bb condition. The only option with bb genotype is option 1.
For the second question, the possible genotype for a person with a straight little finger and blue eyes would be bbRr.
Blue eye genotype is bb as explained in the first question while straight little finger would be Rr since the bent little finger has been represented by the genotype rr in the first question.
fur color in mice is affected by a single gene the gene for fur color has two alleles: b that causes dark brown fur and b that causes light brown fur. What is or could be the genotyes of a mouse with dark brown fur
Answer:
(BB) or (Bb)
Explanation:
Given that (B) allele , is responsible for fur that is dark brown, and (b) allele is responsible for fur color that is light brown, the dominant allele is (B) allele for dark brown fur. Dark brown fur allele would always express itself over the recessive allele, (b).
For a mouse that has dark brown fur, the possible genotype it could have is either (BB) => 2 dominant allele, or (Bb) => 1 dominant allele and a recessive allele. The dominant allele would always express itself even in the presence of the recessive allele.
The ion composition of perilymph is like that of interstitial fluid; high sodium and low potassium levels. If someone ruptured the vestibular membrane, the membrane between the vestibular duct (Scala vestibuli) and the cochlear duct (Scala media), what would be the effect of such a rupture on the concentration of potassium in the endolymph in the cochlear duct
Answer:
The concentration of potassium will decrease
Explanation:
The cochlear ducts are composed of two distict types of fluids: 1-perilymph, rich in sodium (140 mM) and low in potassium (5 mM), and 2- endolymph, rich in potassium (1 mM) and low in sodium (150 mM). The perilymph fluid has a similar composition to the rest of the extracellular fluids, while endolymph present a unique ion composition that is not found in other fluids of the body. It is believed that the cochlea can regulate potassium flow without using energy (i.e., without use ATP), since potassium enters into the cells through passive pathways, while this ion ion leaves the cells by an active mechanism.
Which philosopher believed that the soul operated on three levels: reason, will, and desire? A. Socrates B. Plato C. John Locke D. Hippocrates Please select the best answer from the choices provided A B C D
Answer:
B. Plato
Plato was known as a renowned philosopher in Athens, Greece. He believed that the soul operated on three levels which include Reason, Will and Desire.
Plato was of the notion that the soul was tripartite as a result of it having three levels of operation. He also believed that the soul can never die and will still be in operation and thought even after a person dies.
Answer:
Which philosopher believed that the soul operated on three levels: reason, will, and desire?
A. Socrates
B. Plato
C. John Locke
D. Hippocrates
Acidification of the stomach uses all of the following types of transport EXCEPT: A. channels. B. pumps. C. antiporters. AND. symporters. E. All of these are used by parietal cells.
Answer: Option E.
All of these are used by parietal cells.
Explanation:
Parietal cells are found in the stomach and they produced gastric acid(Hcl)..
HCl is produced when water mixed with carbondioxide in the parietal cell to produced carbonic acid which is catalyses by carbonic anhydrase. The carbonic acid then dissociates into hydrogen ion and carbonate ion.
Parietal cell produce HCl due to histamine (via H2 receptors), acetylcholine (M3 receptors) and gastrin (gastrin receptors).
Therefore it uses channels, pumps, antiporter.
A class is debating pros and cons of using sea walls to reduce beach erosion. What is the best way for them inform their
decision-making?
They should each write an opinion paragraph to send to the local paper.
They should hold the debate on stage, so that they can be judged.
They should watch movies about beaches.
They should research wave action and collect data about erosion in the area.
Answer:
They should research wave action and collect data about erosion in the area.
Explanation:
everyone has their own opinion, and movies aren't gonna make the cut, and no one wants to see a debate in school, so they should research first to get the info they need
if a person who is blood type O marries a person who is blood type A, what are the possible blood types their children could have
Answer:
The possible blood types their children could have are A or 0.
Explanation:
The I gene determines the blood type of a person. I is the dominant allele, while i is the recessive allele.
IA dominant over i. The person presents A type of antigens. IB dominant over i. The person presents B type of antigens. IA and IB are codominant. The person presents both types of antigens, A and B. i is the recessive allele. The person does not present any antigen.Cross: a person who is blood type O with a person who is blood type A
Parental) ii x IA-
Gametes) i i IA -
Punnet Square) IA -
i IAi -i
i IAi -i
The - symbol represents the possibility of either IA allele or i allele. This is, the parental with blood type A might have the genotype IAIA or IAi
F1) 2/4 = 1/2 IAi
2/4 = 1/2 -i (-i could be either IAi or ii, depending on the genotype of the parental with blood type A)
Option 1: ii x IAIAF1) 100% IAi (The whole progeny will have blood type A)
Option 2: ii x IAiF1) 50% IAi (Half of the progeny will have blood type A)
50% ii (Halfa of the progeny will have blood type 0)
The possible blood types their children could have are A or 0.
Alexei Romanov suffered from hemophilia, a condition that (1 point)
causes the body to produce too many blood cells due to the body's inability to form fibrin proteins.
o prevents blood from clotting normally due to the body's inability to form fibrin proteins.
O causes the body to produce abnormally shaped red blood cells due to the body's inability to form fibrin proteins.
o prevents the body from absorbing vitamin B12 due to the body's inability to form fibrin proteins.
Answer:
prevents blood from clotting normally due to the body's inability to form fibrin proteins.
Explanation:
Haemophilia is a genetic disorder which could be inherited and it is characterized by constant bleeding and loss of blood when injuries occur. This is as a result of the inability of the body to form fibril proteins. The fibril proteins are responsible for the production of platelets . The platelets are responsible for the clotting of blood.
This validates haemophilia being a disorder which prevent blood from clotting normally due to the body's inability to form fibrin proteins.
For those who need more answers
1. Adenine
2. Prevents blood from clotting normally due to the bodys inability to form fibrin proteins
3. TCA
4. DNA has the sugars deoxyribose, while RNA has the sugar ribose
5. tRNA carries amino acids to the ribosome and helps form proteins
In the DNA isolation process, cells are mixed with sodium chloride (i.e. NaCl) because the sodium (Na ) neutralizes the negative charge of DNA.
a. True
b. False
Answer:
this is true it neutralise easily
It is true that in the DNA isolation process, cells are mixed with sodium chloride (i.e. NaCl) because the sodium (Na ) neutralizes the negative charge of DNA.
What is DNA isolation?DNA extraction is a method of separating DNA from cell membranes, proteins, and other cellular components using physical and/or chemical methods from a sample. In 1869, Friedrich Miescher isolated DNA for the first time.
The ability to extract DNA is critical for studying the genetic causes of disease and developing diagnostics and drugs.
It is also required for forensic science, genome sequencing, detecting bacteria and viruses in the environment, and determining paternity.
Because sodium (Na+) neutralizes the negative charge of DNA, cells are mixed with sodium chloride (i.e. NaCl) during the DNA isolation process. It makes homogenization easier.
Thus, the given statement is true.
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g Riboswitch is a mechanism of gene activity regulation by mRNA conformation. Riboswitch can regulate ______.
Answer: c. both transcription and translation
Explanation:
Riboswitchs are mRNA elements that influence the activity of genes certain genes by regulating same and are found in other organisms apart from humans such as bacteria, plants and fungi.
They regulate activity by binding to specific small molecules known as ligands thus causing a structural rearrangement that enables either transcription or translation to be modulated in the gene.
Select the scenarios that describe an abiotic factor that is density independent. Select the TWO answers that are correct.
a. Fir trees grow in number, increasing the amount of food available for moose
b. Heavy and continuous rains flood the land, submerging habitats.
c. Lightning strikes a tree and begins a fire that clears the land.
d. Ticks infesting moose weaken the moose's health and reproductive success.
e. Frigid temperatures flow into the area, causing hypothermia and death.
Answer: Option B and C.
Heavy and continuous rains flood the land, submerging habitats.
c. Lightning strikes a tree and begins a fire that clears the land.
Explanation:
Heavy and continuous rains flood the land, submerging habitats.
Lightning strikes a tree and begins a fire that clears the land.
The above are example of density independent abiotic factors because rainfall and lightning affect the population size of the environment by decreasing it's population sizes.
Abiotic factors are the non living part of the environment and they include rain fail, temperature,lightning, humidity e.t.c.
Density independent abiotic factors are factors that decrease or increase the population size of the ecosystem.
Therefore, Heavy and continuous rains flood the land, submerging habitats.
cLightning strikes a tree and begins a fire that clears the land are density independent factor because they decrease the population size.
The scenarios that describe an abiotic factor that is density independent are ; ( B and C )
Heavy and continuous rains flood the land, submerging habitats ( B )Lightning strikes a tree and begins a fire that clears the land ( C )Abiotic factors are Nonliving components of an ecosystem that has a significant effect on the ecosystem such as ; Rain, rocks, Temperature and humidity. Density Independent factors are factors in an ecosystem that can cause the decrease or increase of the population size of an ecosystem.
Heavy and continuous rainfall is an abiotic factor that has the ability to decrease the population of an ecosystem by submerging organisms habitats.
Lightning striking a tree and setting it ablaze which clears the land also reduces the population of the ecosystem because the fire will lead to loss of habitats and death of some organisms .
Hence we can conclude that The scenarios that describe an abiotic factor that is density independent are Heavy and continuous rains flood the land, submerging habitats and Lightning strikes a tree and begins a fire that clears the land .
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Please answer ASAP, the assignments in due really soon :) 30 Points!!! The image below shows the lac operon, which breaks down lactose in bacteria. Which statement correctly describes the expression of this gene?
Answer:
B. Gene expression is influenced by high lactose levels in the environment.
Explanation:
The lactose operon (lac operon) functions for the metabolism and transport of lactose in several bacteria.
Gene expression is influenced by high lactose levels in the environment as genes are expressed in the presence of high level lactose and absence of glucose. High level lactose carry an activator protein called catabolite activator protein (CAP), which let the RNA polymerase do transcription of the operon.
Hence, the correct option is "B".
Answer:
C
Explanation:
^he said it was right^
have an amazing day! :)
Two students are comparing scientific experiments to investigations. They came up with the following ideas. Student A: Testing plant growth in different types of soils Student B: Comparing the water level in a lake during different times of the year Which student gave an example of a scientific experiment? Student A because it requires experimental and control groups Student B because it requires a hypothesis Student A because it is preferably done in natural settings Student B because it is preferably done across a long period of time
Answer:
Student A because it requires experimental and control groups
Explanation:
Answer:
i took the test, its A
Student A because it requires experimental and control groups
Explanation:
In the quest to understand the basis of infertility in humans, researchers have identified a mutation in a gene associated with chiasmata. This protein normally acts to promote homologous recombination.Why might a defect in homologous recombination have consequences for fertility?A. The chiasmata halts the whole process of meiosis, if crossover do not form properly.B. Crossover formation is a necessary step in meiosis I to ensure proper chromosome segregationC. A checkpoint requires a certain level of genetic variability for meiosis to proceed.D. Chiasmata are the connections between the centromeres and the centromeres that pull them to each pole of the daughter cells.
Answer:
B. Crossover formation is a necessary step in meiosis I to ensure proper chromosome segregation
Explanation:
Crossing-over is a unique phenomenon that occurs in the prophase I stage of meiosis I, where non-sister chromatids of homologous chromosomes exchange their chromosomal segment. The physical point where this exchange occurs is called CHIASMATA. Hence, a mutation that affects the gene associated with the chiasmata will affect the occurrence of crossing over or homologous recombination.
Crossing-over, through the formation of the chiasmata, is responsible for the physical alignment and proper segregation of chromosomes into gametes. Naturally, the chiasmata formed as a result of recombination during meiosis helps ensure that the chromosomes stay together until it is the right time to separate. This way, any chromosomal defect in the resulting gamete is prevented.
However, an error or defect in homologous recombination might give rise to gametes with chromosomal disorder, a condition known as ANEUPLOIDY i.e. missing or additional chromosomes in gametes. This can affect the fertility of the involved human.
an advertisement on tv claims children grow faster with the use of vitamin gro. vitamin gro is a 25mg pill taken twice a day. the viewer has little knowledge about how children grow, but he knows that children need a complete diet and a good exercise routine. he decided to put the commercial to the test. the viewer uses his 6 nieces who are the same age to conduct the experiments. to make the experiment easier he uses his six nieces using labels such as child 1, child 2 and so on. he records their height every 3 days for 7 days. What are the variables?
Answer:
Independent variable - vitamin gro and exercise routine.
Dependent variable - growth of children or nieces.
Explanation:
There are two variables present in an experiment called dependent and independent variables.
Independent variables are those variables which can be controlled in an experiment and dependent variables are those variables which are measured in the experiment under the influence of the independent variable.
In the given experiment, the independent variable will be vitamin gro and exercise routine and the dependent variable is the growth of children or nieces because vitamin gro and exercise routine can be controlled and growth of children is dependent on vitamin gro and exercise routine.
Suppose an experimenter becomes proficient with a technique that allows her to move DNA sequences within a prokaryotic genome. If a researcher moves the repressor gene (lacI), along with its promoter, to a position at some several thousand base pairs away from its normal position, which of the following results would be expected?
A) The repressor will no longer bind to the operator.
B) The repressor will no longer bind to the inducer.
C) The lac operon will be expressed continuously.
D) The lac operon will function normally.
Answer:
D) The lac operon will function normally.
Explanation:
The promoter area can be described as the area that causes the transcription to initiate for a particular gene. Promoters may be near the genes from which they initiate transcription or they may display multiple scenes upstream. The lock operon works normally because the promoter area can still enable transcription on many base pairs. Detects repression promoter and works normally.so correct option is D) The lac operon will function normally.
If a researcher moved the repressor gene of lac I, along with its promoter; the lac operon will function normally. Option D is correct.
Promotor:
It is the genetic sequence that is recognized by the RNA polymerase to start the transcription.
Here, researcher moved the repressor gene of lac I , along with its promoter.
Therefore, transcription starts, it will express the repressor gene also because repressor gene was moved with promotor.
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chapter 1 in microscope biology
Answer:
100*
Explanation:
it is a bacteria which needs to be seen under a strong microscope.
Which of the following is NOT a factor of sustainability?
Group of answer choices
economics
ethics
biodiversity
natural capital
solar energy
Answer:
natural capital
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Is zinc renewable or not?
Answer: Zinc is non renewable.
Explanation:
Non-Renewable resources are resources that cannot be replenished easily through natural process. These are the sources which are used in wise manner so that they do not get depleted. For example: coal, petroleum etc.
Renewable resources are resources that can be replenished overtime through natural process.These are the sources which never depletes completely. For example: bio mass energy, solar energy etc.
As zinc cannot be replenished easily through natural process, it is non renewable.
