The following data on total body bone mineral content (TBBMC) (g) for a sample both during lactation (L) and in the post-weaning period (P). Subject 1 1928 2126 2 2549 2885 3 2825 2895 4 1924 1942 5 1628 1750 6 2175 2184 7 2114 2164 8 2621 2626 9 1843 2006 10 2541 2627 P
(a) Assuming that the normality assumption is satisfied, does the data suggest that true average total body bone mineral content during post-weaning exceeds that during lactation by more than 25g? State and test the appropriate hypotheses using a significance level of .05.
(b) Calculate an upper confidence bound using a 95% confidence level for the true average difference between TBBMC during post-weaning and during lactation.

Answer:

  D. Neither Gordon nor Tess

Step-by-step explanation:

The vertices ABC are in clockwise order. The corresponding vertices FGE are also in clockwise order. On this basis, you can say that there cannot be a single reflection (as across x=1), because that would reverse the order to counterclockwise. Gordon cannot be correct.

The left-right orientation of vertices A and C is reversed to a right-left orientation for corresponding vertices F and E. This means two reflections or a rotation is involved. Translation cannot reverse the orientation like this, so Tess cannot be correct.

ΔFGE and ΔABC are a reflection of each other across the origin, equivalent to the two reflections "across the x-axis" and "across the y-axis." This is also equivalent to a rotation of 180° about the origin.

Neither Gordon nor Tess is correct.

not gordon or tess

Step-by-step explanation:

A fraction is the numerator divided by the denominator best describes a fraction.

Given,

- A fraction is the denominator divided by the numerator.

- A fraction is the numerator divided by the denominator.

- A fraction is the numerator multiplied by the denominator.

- A fraction is the denominator multiplied by the numerator.

We need to find which option best describes a fraction.

A fraction has two parts: Numerator and Denominator.

It is in the form of Numerator / Denominator.

We have,

- A fraction is the denominator divided by the numerator.

It is written as denominator / Numerator.

- A fraction is the numerator divided by the denominator.

It is written as Numerator / Denominator

- A fraction is the numerator multiplied by the denominator.

It is written as Numerator x Denominator.

- A fraction is the denominator multiplied by the numerator.

It can be written as Denominator x Numerator.

We see that the option "a fraction is a numerator divided by the denominator" is the correct answer.

Thus A fraction is the numerator divided by the denominator best describes a fraction.

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Answer:

3x + 2y = -2

Step-by-step explanation:

Given Equation is − 2 x  +  3 y  =  12

3 y  = 2 x  +  12

y =  ( 2 /3 )  y  +  12

Slope of this line is  m  =  2/ 3

Slope of Line A m a  =  2

Slope of Line B  m b  =  2/ 3

Slope of Line C  m c  =  − ( 2 /3 )

Slope of Line D  m d  =  −  ( 3 /2 )

since  m d  =  − 1 /m  ,  D  is perpendicular to the given line

Answer:

x = 12

∠A = 144

Step-by-step explanation:

+ We have: ∠A = ∠C (alternate interior)

                ∠D = ∠C ( vertically opposite angles)

=> ∠A = ∠C (because = ∠C)

=> 10x + 24 = 6x + 72

=> 10x - 6x = 72 - 24

        4x      = 48

          x      = 12

+ ∠A = 10x + 24

 ∠A = 10 x 12 + 24

∠A = 144

Answer:

Option B (4,5)

Step-by-step explanation:

The integers (4, 5) do not have real zero.

Knowing what zeros represent can assist us in determining when and how to locate the zeros of functions given their expressions and a function's graph. The value of x when the function itself reaches zero is typically referred to as a function's zero.

A function's zero can take many different forms, but as long as they have a y-value of zero, we will consider them to be the function's zero.

Given Expression

f(x) = x³ + 9x² + 8x - 5

to find which is not a real zero,

condition of real zero is for any function f(a , b) if f(a).f(b) < 0 the function have at least a zero.

1: (-8, -7)

f(-8).f(-7) = [(-8)³ + 9(-8)² + 8(-8) - 5][(-7³)  + 9(-7)² + 8(-7) - 5]

f(-8).f(-7) = (-5)(37)

f(-8).f(-7) = -185 < 0 points  have at least a zero

2:  (4, 5)

f(4).f(5) = [(4)³ + 9(4)² + 8(4) - 5][(5³)  + 9(5)² + 8(5) - 5]

f(4).f(5) = 235 x 385

f(4).f(5) = 94,475 > 0

points do not have any zeros

3: (0, 1)

f(0).f(1) = [(0)³ + 9(0)² + 8(0) - 5][(1³)  + 9(1)² + 8(1) - 5]

f(0).f(1) = -5 x 13

f(0).f(1) = -65 < 0

points  have a zero

4: (–2, –1)

f(-2).f(-1) = [(-2)³ + 9(-2)² + 8(-2) - 5][(-1³)  + 9(-1)² + 8(-1) - 5]

f(-2).f(-1) = 7 x (-5)

f(-2).f(-1) = -35 < 0

points  have a zero

Hence only point  (4, 5) do not have a zero.

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Answer:

The answer is 0.31

Step-by-step explanation:

Old Method                                       New Method                          .

Mean                      73.5625                  Mean            75.70588

Standard Error        3.143736             Standard Error  2.923994

Median                    72                          Median            75

Mode                       90                          Mode               64

Standard deviation  12.57494           Standard deviation 12.05594

Sample Variance     158.1292            Sample Variance     145.3456

Kurtosis                     -1.14544              Kurtosis                   -0.76646

Skewness                 0.171025             Skewness                0.091008

Range                       39                        Range                      41

Minimum                   55                        Minimum                 56

Maximum                  94                        Maximum                 97

Sum                          1177                        Sum                        1287

Count                         16                         Count                      17

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: μNew< μOld

Alternative hypothesis: μNew > μOld

Note that these hypotheses constitute a one-tailed test. The null hypothesis will be rejected if the mean difference between sample means is too small.

Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a two-sample t-test of the null hypothesis.

Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).

[tex]SE=\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} } \\\\SE=4.29[/tex]

DF = 31

[tex]t = \frac{(x_1-x_2)-d}{SE} \\\\t = - 0.4997[/tex]

where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is the size of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between population means, and SE is the standard error.

The observed difference in sample means produced a t statistic of - 0.499. We use the t Distribution Calculator to find P(t < - 0.499) = 0.311

Therefore, the P-value in this analysis is 0.311.

Interpret results. Since the P-value (0.311) is greater than the significance level (0.05), we cannot reject the null hypothesis.

From the above test we do have sufficient evidence in the favor of the claim that new method is efficient than the old method.

Answer:

- 6

Step-by-step explanation:

[tex]slope = \frac{ - 4 - 2}{0 - ( - 1)} = \frac{ - 6}{0 + 1} = \frac{ - 6}{ 1} = - 6 \\ [/tex]

Answer:

Length: 11

Width: 5

Step-by-step explanation:

Let W = width

Let L = length

Length is 4 less than 3 times the width  ==>  L = 3*W - 4  

Let P = Perimeter = 2*W + 2*L

Perimeter is 22 more than twice the width  ==>  P = 2*W + 22

Setting the 2 expressions for the perimeter equal to each other gives  

2*W + 2*L = 2*W + 22

2*L = 22

L = 11  

So 11 = 3*W - 4

3*W = 15

W = 5

The length is 11 and the width is 5  

Check:  3*W - 4 = 11 = Length

           Perimeter = 32 = 22 more than 2*5 = 10

Answer: 0.00494.

Step-by-step explanation:

Given : The proportion of the company's orders come from first-time customers. [tex]p=0.45[/tex]

Sample size : n= 166

Now , the probability that the sample proportion is between 0.24 and 0.35 would be :-

[tex]P(0.24<p<0.35)=P\left({\dfrac{0.24-0.45}{\sqrt{\dfrac{0.45(1-0.45)}{166}}}<\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}<\dfrac{0.35-0.45}{\sqrt{\dfrac{0.45(1-0.45)}{166}}}}\right)\\\ \ \left[\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\right][/tex]

[tex]=P(-5.44<z<-2.58)=P(z<-2.58)-P(z<-5.44)\\\\=1-P(z<2.58)-(1-P(z<5.44))\\\\=P(z<5.44)-P(z<2.58)\\\\=1-0.99506\ [\text{By z-value table}]\\\\=0.00494[/tex]

Hence, the probability that the sample proportion is between 0.24 and 0.35 is 0.00494.

Step-by-step explanation:

tags is not a fixed cost

Answer:

4/15

Step-by-step explanation:

The total number of spins completed is 6+8+7+9 = 30

The letter B came up 8 times

P(B) = number of B's over total

P(B) = 8/30 = 4/15

Answer:

Step-by-step explanation:

A. Find the point on the x-axis marked with a 4. Follow the vertical line down until it meets the blue line of the graph. At that point, follow the horizontal line to the left until it meets the y-axis at -3. This tells you ...

  f(4) = -3

__

B. Find the point on the y-axis marked with a 1. Then find the x-values corresponding to the places where the horizontal line at y=1 intersects the blue curve. There are two of them: one at x=-6, another at x=0.

 f(x) = 1  for  x = -6 and x = 0

Answer:

The y-intercept is (0,5)

Step-by-step explanation:

y-intercept can be found by plugging x=0 into given equation

f(x)=5(6)^0=5(1)=5  

which same as given y-intercept (0,5)

Answer:

1 83/200

Step-by-step explanation:

You need to make the 2/3 a decimal which is 0.66 repeating. Then you do 5.66 divided by 4 which equals 1.415 then you need to simplify.

Hope this helps.

Answer:

60

Step-by-step explanation:

they each have 3 boxes, so you can multiply 3 by 2 to get 6. if each box has 10 crayons, then multiply 6 by 10 to get 60.

The total number of crayons that Alex and Annie have in all will be 30 crayons.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Alex and Annie each have 3 boxes of crayons. Each box has 10 crayons. Then the total number of crayons is given as,

Total = 3 x 10

Total = 30

The total number of crayons that Alex and Annie have in all will be 30 crayons.

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Answer:

mean: 46.63636

median: 34

mode: 87

range:95

How To:

Step 1 : To find Mean

    Average = ( 1 + 5 + 5 + 7 + 8 + 10 ) / 6

             =36 / 6

    Mean = 6

Step 2 : To find Median

   Middle value = ( 5 + 7 ) / 2

               = 12 / 2

    Median = 6

Step 3 : To find Mode

   Mode = 5 (The number with more repetition, here 5 is repeated two times)

Step 4 : To find Range

    Range = Largest number - Smallest number

       = 10-1

       = 9

Range = 9

Answer:

Mean: 46.6

Mode: 87

Median: 34

Range: 95

Step-by-step explanation:

Mean: (finding the average)

Median: (the middle number of the data set)

Mode: (the most number repeated from the data set)

Range: (is the difference between the highest value and the lowest value)

first arrange the following data set.

23, 87, 19, 34, 37, 87, 81, 5, 14, 100, 26

so:

5, 14, 19, 23, 26, 34, 37, 81, 87, 87, 100

Lets us first find the mean by adding up all the numbers and dividing it by the amount of numbers in the data set.

Mean: 5 + 14 + 19 + 23 + 26 + 34 + 37 + 81 + 87 + 87 + 100 = 513/11 = 46.6

Mode: 87

Median: 34

Range: 100 - 5 = 95

Answer:

(a) Probability that 2 or fewer will withdraw is 0.2061.

(b) Probability that exactly 4 will withdraw is 0.2182.

(c) Probability that more than 3 will withdraw is 0.5886.

(d) The expected number of withdrawals is 4.

Step-by-step explanation:

We are given that a university found that 20% of its students withdraw without completing the introductory statistics course.

Assume that 20 students registered for the course.

The above situation can be represented through binomial distribution;

[tex]P(X =r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,......[/tex]

where, n = number of trials (samples) taken = 20 students

            r = number of success  

            p = probability of success which in our question is probability  

                  that students withdraw without completing the introductory  

                  statistics course, i.e; p = 20%

Let X = Number of students withdraw without completing the introductory statistics course

So, X ~ Binom(n = 20 , p = 0.20)

(a) Probability that 2 or fewer will withdraw is given by = P(X [tex]\leq[/tex] 2)

P(X [tex]\leq[/tex] 2) =  P(X = 0) + P(X = 1) + P(X = 2)

=  [tex]\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}[/tex]

=  [tex]1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}[/tex]

=  0.2061

(b) Probability that exactly 4 will withdraw is given by = P(X = 4)

                      P(X = 4) =  [tex]\binom{20}{4} \times 0.20^{4} \times (1-0.20)^{20-4}[/tex]

                                 =  [tex]4845\times 0.20^{4} \times 0.80^{16}[/tex]

                                 =  0.2182

(c) Probability that more than 3 will withdraw is given by = P(X > 3)

P(X > 3) =  1 - P(X [tex]\leq[/tex] 3) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

=  [tex]1-(\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}+\binom{20}{3} \times 0.20^{3} \times (1-0.20)^{20-3})[/tex]

=  [tex]1-(1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}+1140\times 0.20^{3} \times 0.80^{17})[/tex]

=  1 - 0.4114 = 0.5886

(d) The expected number of withdrawals is given by;

                        E(X)  =  [tex]n\times p[/tex]

                                 =  [tex]20 \times 0.20[/tex] = 4 withdrawals

Answer:

168

Step-by-step explanation:

SA= 2B + hp

h=9

p=16

B= 1/2 bh

B= 1/2 6(4)

B=12 x 2 = 24

9 x 16= 144

144+24= 168

BRAINLIEST really needed!!

Answer:

A. 6.9

Step-by-step explanation:

Edge 2020

The standard deviation for the set of population data given in the question is 6.9

Mean = summation of data / number

μ = 130 / 5

μ = 26

σ = √[[(x₁ - μ)² + (x₂ - μ)² + (x₃ - μ)² + (x₄ - μ)² + (x₅ - μ)²] / n]

σ = √[[(14 - 26)² + (23 - 26)² + (31 - 26)² + (29 - 26)² + (33 - 26)²] / 5]

σ = √[236 / 5}

σ = 6.9

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The increase in the money supply that causes prices to rise and leads to inflation, loses purchasing power.

Inflation refers to the persistent rise in the general prices of commodities in the economy over a period of time. If the prices of goods and services increase in an economy without an increase in income of people, it reduces the purchasing power of individuals.

This follows the law of demand which states that; the higher the price, the lower the quantity demanded; the lower the price, the higher the quantity demanded.

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Answer:

b

Step-by-step explanation:

Answer:

  31 ft

Step-by-step explanation:

The statue represents the side of a right triangle that is opposite the angle of elevation. The distance to the statue represents the side adjacent to the angle. Then ...

  Tan = Opposite/Adjacent

  tan(61°) = h/(17 ft)

Multiplying by 17 ft, we have ...

  h = (17 ft)tan(61°) ≈ 30.67 ft

  h ≈ 31 feet

Answer:12 months

Step-by-step explanation:

400+400=800 so  950-800=150 1800/150=12

Answer: either a or b

Step-by-step explanation:

Answer:

Step-by-step explanation:

To undo the division of p by 3, one multiplies by the inverse of 1/3. That is, one multiplies by 3.

Then you have ...

  3(p/3) = 3(12)

  p = 36 . . . . . simplify

To check this work, you can substitute 36 for p:

  36/3 = 12 . . . . . true statement

So, the solution process is ...

  multiply both sides of the equation by 3

  substitute 36 for p to check the work

Answer:

Step-by-step explanation:

I took the assignment and it's correct :)

Good luck ;)

Answer:

5 sessions each

Step-by-step explanation:

Let the personal training sessions be x.

Then at Silver Gym Sarah would spend:

And at Fit Factor she would spend:

Since total costs are same, the amounts will be equal:

So Sarah would buy 5 training sessions for each of the gyms.

And she would spend $185 at each.

Answer:

Step-by-step explanation:

Answer:

D. 625

Step-by-step explanation:

If the side length for each block is 2 1/2 then two blocks together make 5 so 4 blocks going up makes the height 10 and two blocks for the width make 5 and the 5 blocks on the bottom going across for length make 12 1/2 and 5*10*12 1/2= 625

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=2.4\\\\H_a:\mu> 2.4[/tex]

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=45-1=44[/tex]

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

[tex]P-value=P(t>2.5801)=0.0066[/tex]

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.