Answer:
The program in Python is as follows:
widget = int(input("Widgets: "))
price = widget * 9.9
tax = price * 0.55
ship = price * 0.40
totalprice = price + tax + ship
print("Total Price: $",totalprice)
Explanation:
The question is incomplete, as what is required is not stated.
However, I will write convert the pseudocode to a programming language (in Python)
Get the number of widgets
widget = int(input("Widgets: "))
Calculate price
price = widget * 9.9
Calculate the tax
tax = price * 0.55
Calculate the shipping price
ship = price * 0.40
Calculate the total price
totalprice = price + tax + ship
Print the calculated total price
print("Total Price: $",totalprice)
Write a method that prints on the screen a message stating whether 2 circles touch each other, do not touch each other or intersect. The method accepts the coordinates of the center of the first circle and its radius, and the coordinates of the center of the second circle and its radius.
The header of the method is as follows:
public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2)
Hint:
Distance between centers C1 and C2 is calculated as follows:
d = Math.sqrt((x1 - x2)2 + (y1 - y2)2).
There are three conditions that arise:
1. If d == r1 + r2
Circles touch each other.
2. If d > r1 + r2
Circles do not touch each other.
3. If d < r1 + r2
Circles intersect.
Answer:
The method is as follows:
public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){
double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));
if(d == r1 + r2){
System.out.print("The circles touch each other"); }
else if(d > r1 + r2){
System.out.print("The circles do not touch each other"); }
else{
System.out.print("The circles intersect"); }
}
Explanation:
This defines the method
public static void checkIntersection(double x1, double y1, double r1, double x2, double y2, double r2){
This calculate the distance
double d = Math.sqrt(Math.pow((x1 - x2),2) + Math.pow((y1 - y2),2));
If the distance equals the sum of both radii, then the circles touch one another
if(d == r1 + r2){
System.out.print("The circles touch each other"); }
If the distance is greater than the sum of both radii, then the circles do not touch one another
else if(d > r1 + r2){
System.out.print("The circles do not touch each other"); }
If the distance is less than the sum of both radii, then the circles intersect
else{
System.out.print("The circles intersect"); }
}
The _________ attack exploits the common use of a modular exponentiation algorithm in RSA encryption and decryption, but can be adapted to work with any implementation that does not run in fixed time.
A. mathematical.
B. timing.
C. chosen ciphertext.
D. brute-force.
Answer:
chosen ciphertext
Explanation:
Chosen ciphertext attack is a scenario in which the attacker has the ability to choose ciphertexts C i and to view their corresponding decryptions – plaintexts P i . It is essentially the same scenario as a chosen plaintext attack but applied to a decryption function, instead of the encryption function.
Cyber attack usually associated with obtaining decryption keys that do not run in fixed time is called the chosen ciphertext attack.
Theae kind of attack is usually performed through gathering of decryption codes or key which are associated to certain cipher texts The attacker would then use the gathered patterns and information to obtain the decryption key to the selected or chosen ciphertext.Hence, chosen ciphertext attempts the use of modular exponentiation.
Learn more : https://brainly.com/question/14826269
How are dates and times stored by Excel?
Answer:
Regardless of how you have formatted a cell to display a date or time, Excel always internally stores dates And times the same way. Excel stores dates and times as a number representing the number of days since 1900-Jan-0, plus a fractional portion of a 24 hour day: ddddd. tttttt
Explanation:
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