Answer:
x=-3
Step-by-step explanation:
Find the total surface area of a right cylinder with a radius of 3 inches and a height of 17 inches. Round to the nearest tenth.
Answer:
Step-by-step explanation:
Find the total surface area of a right cylinder with a radius of 3 inches and a height of 17 inches. Round to the nearest tenth.
Your
In the circle below, EG is a diameter and EF is tangent at E. Suppose mEF = 124°. Find the following. Does anyone know this?
Answer:
Step-by-step explanation:
If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.
If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118
Please answer thanks! Brainliest
Step-by-step explanation:
The last two answers is correct
Answer:
4
Step-by-step explanation:
The answer to T - H is negative
f(x) = 4* and g(x) = 45
Use the values given in the table and the functions to
determine the missing values.
A=
X
f(x)
g(x)
B=
1
-2
C =
16
1
4
-1
UNI->
0
1
1
4
2
2
16
с
Answer:
The missing values are [tex]A = \frac{1}{4}[/tex], [tex]B = 1[/tex] and [tex]C = 4[/tex], respective.
Step-by-step explanation:
We find the values regarding A, B and C by evaluating [tex]g(x)[/tex] at respective values of [tex]x[/tex]:
[tex]x = -2[/tex]
[tex]g(-2) = 4^{-\frac{2}{2} }[/tex]
[tex]g(-2) = 4^{-1}[/tex]
[tex]g(-2) = \frac{1}{4}[/tex]
[tex]A = \frac{1}{4}[/tex]
[tex]x = 0[/tex]
[tex]g(0) = 4^{\frac{0}{2} }[/tex]
[tex]g(0) = 1[/tex]
[tex]B = 1[/tex]
[tex]x = 2[/tex]
[tex]g(2) = 4^{\frac{2}{2} }[/tex]
[tex]g(2) = 4^{1}[/tex]
[tex]g(2) = 4[/tex]
[tex]C = 4[/tex]
Answer: A=1/4, B=1, C=4
Step-by-step explanation:
Correct on edge 2022
Find the missing angle measurements of HFG ? , fill in the boxes
Answer:
Angle HFG = 24 degrees
Step-by-step explanation:
From the diagram, we have the following;
Angle EFH and angle HFG are complementary (they add up to be 90 degrees)
angle EFH + angle HFG = 90
Angle HFG = 90-66
Angle HFG = 24 degrees
What is the length of Line segment A C?
Answer:
12
Step-by-step explanation:
The triangles are similar because they have the same angles.
Make a proportion to solve for AC which we will substitute with variable x.
AM = MB = 4
AB = AM + MB = 8
BN = NC = 3
BC = BN + NC = 6
big triangle sides: 8, 6, x
small triangle sides: 4, 3, 6
now we can write proportion.
8/4 = x/6
x = 12
AC = 12
A batter gets 6 hits in 12 times at bat. What is the experimental
probability that she will get a hit in her next time at bat?
Answer:
1/2 or 50% or .5
Step-by-step explanation:
She hits at .500 that's pretty good. I'd take her on my fantasy team.
Find the inverse of y=5^x-9
(the -9 is not in the power)
Step-by-step explanation:
y = 5^x -9
5^x = y + 9
x = ^5 log (y+9)
f~'(x) = ^5 log (x+9)
What is the radius of a circle with a diameter of 6 meters
Answer:
the radius is 3 m
Step-by-step explanation:
the radius of a circle is always one half of the diameter.
Here the diameter is 6 m, so the radius is 3 m.
Volunteers who had developed a cold within the previous 24 hours were randomized to take either zinc or placebo lozenges every 2 to 3 hours until their cold symptoms were gone (Prasad et al., 2000). Twenty-five participants took zinc lozenges, and 23 participants took placebo lozenges. The mean overall duration of symptoms for the zinc lozenge group was 4.5 days, and the standard deviation of overall duration of symptoms was 1.6 days. For the placebo group, the mean overall duration of symptoms was 8.1 days, and the standard deviation was 1.8 days.
a. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the zinc lozenges.
b. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the placebo lozenges.
c. On the basis of the intervals computed in parts (a) and (b) and/or the picture you constructed in part (c), is it reasonable to conclude generally that taking zinc loz-enges reduces the overall duration of cold symptoms more than if taking a placebo? Explain why you think this is or is not an appropriate conclusion.
d. In their paper, the researchers say that they checked whether it was reasonable to assume that the data were sampled from a normal curve population and decided that it was. How is this relevant to the calculations done in parts (a) and (b)?
Answer:
a. (3.83952, 5.16049)
b. (7.32, 8.88)
c. The difference in the range of the confidence intervals suggest that taking the zinc loz-enges reduces the overall duration of cold symptoms
d. The assumptions required for the validity validity of a t-test include that the data is sampled from a source that have data that are normally distributed
Step-by-step explanation:
The given parameters are;
The number of participants that took zinc lozenges, n₁ = 25
The number of participants that took a placebo, n₂ = 23
The mean duration of the symptoms for the zinc lozenge group, [tex]\overline x_1[/tex] = 4.5 days
The standard deviation of overall duration, s₁ = 1.6 days
The mean duration of the symptoms for the placebo group, [tex]\overline x_2[/tex] = 8.1 days
The standard deviation, s₂ = 1.8 days
a. The 95% confidence interval if everyone in the population were to take zinc lozenges is given as follows;
[tex]CI=\bar{x}_1\pm t_{\alpha/2} \times \dfrac{s_1}{\sqrt{n_1}}[/tex]
n₁ = 25, the degrees of freedom (df) = n₁ - 1 = 24
The t-value for 95% confidence interval, with df = 24, with t = 2.064
Therefore, we have;
[tex]CI_{zl}=4.5 \pm 2.064 \times \dfrac{1.6}{\sqrt{25}}[/tex]
[tex]CI_{zl}[/tex] = 4.5 ± 0.66048
[tex]CI_{zl}[/tex] = (3.83952, 5.16049)
b. The 95% confidence interval if everyone in the population were to take the placebo is given as follows;
[tex]CI_p=\bar{x_2}\pm t_{\alpha/2} \times \dfrac{s_2}{\sqrt{n_2}}[/tex]
n₂ = 23, the degrees of freedom (df) = n₂ - 1 = 22
The t-value for 95% confidence interval, with df = 22, with t = 2.074
Therefore, we have;
[tex]CI_p =8.1 \pm 2.074 \times \dfrac{1.8}{\sqrt{23}}[/tex]
[tex]CI_p[/tex] = 8.1 ± 0.7784
[tex]CI_p[/tex] = (7.32, 8.88)
c. Based on the difference in the range of the 95% confidence interval for the mean duration of cold symptoms of the group that take zinc lozenges, (3.83952, 5.16049), and the mean of the group that are on a placebo, (7.32, 8.88), there is sufficient statistical evidence to suggest that there is a difference between the mean and taking zinc lozenges reduces the overall duration of cold symptoms more than if taking placebo
d. The assumptions required for validity when carrying out a t-test include;
i) The measurement scale is ordinal or continuous
ii) The sample is a simple random sample
iii) The data gives a normal distribution curve
iv) The sample size is reasonably large
v) The variance are homogeneous
Among these assumptions, the data must be randomly sampled from the population of interest and that the data variables follow a normal distribution
The common assumptions made when doing a t-test include those regarding the scale of measurement, random sampling, normality of data distribution, adequacy of sample size and equality of variance in standard deviation
Given the points A(-3, -2) and B(6, 1), determine the coordinates of point P on directed line segment that partitions in the ratio 2/1.
Answer:
[tex]P = (3,0)[/tex]
Step-by-step explanation:
Given
[tex]A = (-3,-2)[/tex] ---- [tex](x_1,y_1)[/tex]
[tex]B = (6,1)[/tex] --- [tex](x_2,y_2)[/tex]
[tex]m:n =2:1[/tex]
Required
The coordinates of P
This is calculated as:
[tex]P = (\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}][/tex]
So:
[tex]P = (\frac{2*6+1*-3}{2+1},\frac{2*1+1*-2}{2+1})[/tex]
[tex]P = (\frac{9}{3},\frac{0}{3})[/tex]
[tex]P = (3,0)[/tex]
What is the edge length of
a cube of 1/8 m^3
Step-by-step explanation:
The volume of a cube is the edge³, so to find the edge, you need to calculate the cubic root of it:
[tex] \sqrt[3]{ \frac{1}{8} } = \frac{1}{2 } [/tex]
A ladder of length 8m rests against a wall so that the angle bsetween the ladder and wall is 45 degree .How far is the base of the ladder from the wall?
HELPPP PLS!! WILL MARK BRAINLIEST!! #plato
Drag each tile to the correct box.
Arrange the entries of matrix A in increasing order of their cofactor values.
Answer:
a23, a31, a21, a11, a12, a33
Step-by-step explanation: I got it right on Edumentum.
Answer:
a23, a31, a21, a11, a12, a33
Step-by-step explanation:
Find the sum of the first seven prime numbers that have a units digit of 7.
Answer:
7, 17, 37, 47, 73, 79, 97
Step-by-step explanation:
they have 7's as one of their digits
Please help
Calculate the volume of the given figure. Use 3.14 for ™.
3 ft
The volume of the solid figure shown in the drawing is approximately (Round to two decimal places as needed.)
Answer:
Step-by-step explanation:
Vol of a cylinder = pi * r^2 h
Vol of cone = 1/3 pi r^2 h
cylinder = pi * (1)^2 * (3) = 3 pi
cone = 1/3 pi (1^2) 4 = 4/3 pi
total = 3 pi + 4/3 pi
= pi(3+ 4/3) = pi(4.333)
= 13.6 f^3
I need help with this it's urgent!
Answer:
I looks like it's anwser D
Answer:
$460.80
Step-by-step explanation:
with we us our formula equation I=prt we now cam solve for our depreciated value
with we substitute our varibles with the correct numerals we now get
I= 960 x 0.12 x 4
we turn our 12% into a decimal to be Simplified into our equation.
If we now solve we will get
I = 960 x 0.12 x 4
I = 460.8
GIJL is a trapezoid with mid segment of HK. If IJ =7 cm and GL=15 cm, what is the length of HK?
Consider IJ and GL are the parallel sides of the trapezoid.
Given:
In a trapezoid GIJL, HK is the mid segment, IJ =7 cm and GL=15 cm.
To find:
The length of the mid segment HK.
Solution:
The length of the mid segment of a trapezoid is:
[tex]\text{Midsegment}=\dfrac{b_1+b_2}{2}[/tex]
where, [tex]b_1,b_2[/tex] are two parallel side or bases of the trapezoid.
HK is the mid segment, and the parallel sides are IJ =7 cm and GL=15 cm. So, the length of the mid segment is:
[tex]HK=\dfrac{IJ+GL}{2}[/tex]
[tex]HK=\dfrac{7+15}{2}[/tex]
[tex]HK=\dfrac{22}{2}[/tex]
[tex]HK=11[/tex]
Therefore, the length of HK is 11 units.
Simplify the expression. –(10)–2
100
–100
Answer:
-12, 0
Step-by-step explanation:
Find B
Plzz find the right answer and don’t just guess
Answer:
Step-by-step explanation:
using pythagoras theorem
a^2 + b^2 = c^2
B^2 + 8^2 = 15^2
B^2 + 64 + 225
B^2 = 225 - 64
B^2 = 161
B = [tex]\sqrt{161}[/tex] OR 12.7
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Answer:
Step-by-step explanation:
circumference of circle=2πr
=2*π*9
=18π m
[tex]{ \bf{ \underbrace{Given :}}}[/tex]
Radius of the circle = 9 m.
[tex]{ \bf{ \underbrace{To\:find:}}}[/tex]
The circumference of the circle.
[tex]{ \bf{ \underbrace{Solution :}}}[/tex]
A. C = 18 π ✅
[tex]\sf\orange{The\:circumference \:of\:the\:circle\:is\:18\:π\:m.}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
We know that,
[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:2Πr }[/tex]
[tex] = 2 \: \pi \times 9 \: m \\ = 18 \: \pi \: m[/tex]
Therefore, the circumference of the circle is 18 π m.
[tex]\large\mathfrak{{\pmb{\underline{\blue{Happy\:learning }}{\blue{!}}}}}[/tex]
What value of b will cause the system to have an infinite number of solutions? y=6x-b -3x+1/2y=-3
Answer:
b = 6
Step-by-step explanation:
solve the second equation for 'y':
-3x + 1/2y = -3
add 3x to each side to get:
1/2y = 3x - 3
multiply all terms by 2 to eliminate the denominator to get:
y = 6x - 6
now compare '6x-6' with '6x-b'
you want both expressions to be equal because then there are an infinite number of solutions:
b = 6
What is the slope of every perpendicular line to y-2/3x=-4
Answer:
The slope of the line perpendicular is -3/2.
Step-by-step explanation:
y-2/3x=-4
y = 2/3x - 4
The slope of the line perpendicular is -3/2.
attachment below or above
Answer:
840
Step-by-step explanation:
600×140% =840 hope this helps
Can someone please help me get surface area and lateral surface area
Answer:
Step-by-step explanation:
suface area of base=1/2×9×7.8=9×3.9=35.1 yd²
lateral surface area=3×1/2×9×10=135 yd²
total surface area=135+35.1=170.1 yd²
i assumed it is an equilateral triangular base.
as √(7.8²+4.5²)=9.0049≈9
gradient of line AB (3,7) and (5,11)
Answer:
Gradient is change in y over change in x.
gradient = y1-y2 ÷ x1-x2
=7-11 ÷ 3-5
=-4 ÷ -2
=2
Use the slope/gradient formula below:
[tex] \large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]
This formula is for when we want to find the gradient when we have two given points. (We also call it Rise Over Run or changes of y over the changes of x.)
We are given two points which are (3,7) and (5,11). Substitute these points in the equation. (the ordered pairs are in (x,y) and not (y,x))
[tex] \large{m = \frac{11 - 7}{5 - 3} } \\ \large{m = \frac{4}{2} \longrightarrow \boxed{m = 2}}[/tex]
Hence, the gradient of AB is 2.
Answer
gradient is 2Enter a range of values for x.
=============================================================
Explanation:
Ignore the sides that are 'a' units long.
We'll compare the sides that are 26 units and 27 units long. We see the 27 unit side is larger, which makes the 93 degree angle larger than the 3x-9 degree angle.
Symbolically, we would say
3x-9 < 93
At the same time, the 3x-9 is also larger than 0
So
3x-9 > 0 or 0 < 3x-9
Put together, we can form this compound inequality
0 < 3x-9 < 93
-------------------
Let's isolate x like so
0 < 3x-9 < 93
0+9 < 3x-9+9 < 93+9 .... add 9 to all sides
9 < 3x < 102
9/3 < 3x/3 < 102/3 .... divide all sides by 3
3 < x < 34
x is any number between 3 and 34, but cannot equal either endpoint
For example, x = 10 is valid since 3 < 10 < 34 is true. But x = 50 is not a solution since 3 < 50 < 34 is false. We can't have x = 3 and we also can't have x = 34 either, but we can have anything in between those endpoints.
Which one goes where?:( WILL GIVE BRAINLIEST!<33
Answer:
1 pair of parallel sides: B
2 pairs of parallel sides: A, D
3 pairs of parallel sides: C
Step-by-step explanation:
When two lines are parallel, they will never intersect.
Eighty percent of students surveyed said they feel more focused after exercising. Nine hundred fifty students were surveyed.
Students Who Feel More Focused after Exercise
20%
20%
20%
20%
20%
How many students said they feel more focused after exercising?
Answer:
760
Step-by-step explanation:
How many solutions does the system have?
-87 + 2y = 8
- 40 +y=4