The graph of f(x) = 2x2 + x – 15 passes through the point (0, –15) and one of its zeros is (2.5, 0). What is the other zero of the function?

Answers

Answer 1

Answer:

x=-3

Step-by-step explanation:


Related Questions

Find the total surface area of a right cylinder with a radius of 3 inches and a height of 17 inches. Round to the nearest tenth.

Answers

Answer:

Step-by-step explanation:

Find the total surface area of a right cylinder with a radius of 3 inches and a height of 17 inches. Round to the nearest tenth.

Your

In the circle below, EG is a diameter and EF is tangent at E. Suppose mEF = 124°. Find the following. Does anyone know this?

Answers

Answer:

Step-by-step explanation:

If EG is a diameter, then arc EFG is a semicircle and its measure is 180. Arc FG then is 180 - 124 = 56. Since angle FEG is an inscribed angle and the arc it cuts off is arc FG, then the measure of the inscribed angle is half the measure of the arc it cuts off...so angle FEG is 28 degrees. Keep that in mind; we'll need it in a sec.

If HE is tangent to the circle at E, then angle HEG is a 90 degree angle. Adding that to angle FEG will give you angle FEH. Angle FEH = 90 + 28 = 118

Please answer thanks! Brainliest

Answers

Step-by-step explanation:

The last two answers is correct

Answer:

4

Step-by-step explanation:

The answer to T - H is negative

f(x) = 4* and g(x) = 45
Use the values given in the table and the functions to
determine the missing values.
A=
X
f(x)
g(x)
B=
1
-2
C =
16
1
4
-1
UNI->
0
1
1
4
2
2
16
с

Answers

Answer:

The missing values are [tex]A = \frac{1}{4}[/tex], [tex]B = 1[/tex] and [tex]C = 4[/tex], respective.

Step-by-step explanation:

We find the values regarding A, B and C by evaluating [tex]g(x)[/tex] at respective values of [tex]x[/tex]:

[tex]x = -2[/tex]

[tex]g(-2) = 4^{-\frac{2}{2} }[/tex]

[tex]g(-2) = 4^{-1}[/tex]

[tex]g(-2) = \frac{1}{4}[/tex]

[tex]A = \frac{1}{4}[/tex]

[tex]x = 0[/tex]

[tex]g(0) = 4^{\frac{0}{2} }[/tex]

[tex]g(0) = 1[/tex]

[tex]B = 1[/tex]

[tex]x = 2[/tex]

[tex]g(2) = 4^{\frac{2}{2} }[/tex]

[tex]g(2) = 4^{1}[/tex]

[tex]g(2) = 4[/tex]

[tex]C = 4[/tex]

Answer:       A=1/4,   B=1,   C=4

Step-by-step explanation:

Correct on edge 2022

Find the missing angle measurements of HFG ? , fill in the boxes

Answers

Answer:

Angle HFG = 24 degrees

Step-by-step explanation:

From the diagram, we have the following;

Angle EFH and angle HFG are complementary (they add up to be 90 degrees)

angle EFH + angle HFG = 90

Angle HFG = 90-66

Angle HFG = 24 degrees

What is the length of Line segment A C?

Answers

Answer:

12

Step-by-step explanation:

The triangles are similar because they have the same angles.

Make a proportion to solve for AC which we will substitute with variable x.

AM = MB = 4

AB = AM + MB = 8

BN = NC = 3

BC = BN + NC = 6

big triangle sides: 8, 6, x

small triangle sides: 4, 3, 6

now we can write proportion.

8/4 = x/6

x = 12

AC = 12

A batter gets 6 hits in 12 times at bat. What is the experimental

probability that she will get a hit in her next time at bat?​

Answers

Answer:

1/2 or 50% or .5

Step-by-step explanation:

She hits at .500 that's pretty good. I'd take her on my fantasy team.

Find the inverse of y=5^x-9
(the -9 is not in the power)

Answers

Step-by-step explanation:

y = 5^x -9

5^x = y + 9

x = ^5 log (y+9)

f~'(x) = ^5 log (x+9)

What is the radius of a circle with a diameter of 6 meters

Answers

3 meters
radius = d/2

Hope this helps ;)

Answer:

the radius is 3 m

Step-by-step explanation:

the radius of a circle is always one half of the diameter.

Here the diameter is 6 m, so the radius is 3 m.

Volunteers who had developed a cold within the previous 24 hours were randomized to take either zinc or placebo lozenges every 2 to 3 hours until their cold symptoms were gone (Prasad et al., 2000). Twenty-five participants took zinc lozenges, and 23 participants took placebo lozenges. The mean overall duration of symptoms for the zinc lozenge group was 4.5 days, and the standard deviation of overall duration of symptoms was 1.6 days. For the placebo group, the mean overall duration of symptoms was 8.1 days, and the standard deviation was 1.8 days.

a. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the zinc lozenges.

b. Calculate a 95% confidence interval for the mean overall duration of symptoms if everyone in the population were to take the placebo lozenges.

c. On the basis of the intervals computed in parts (a) and (b) and/or the picture you constructed in part (c), is it reasonable to conclude generally that taking zinc loz-enges reduces the overall duration of cold symptoms more than if taking a placebo? Explain why you think this is or is not an appropriate conclusion.

d. In their paper, the researchers say that they checked whether it was reasonable to assume that the data were sampled from a normal curve population and decided that it was. How is this relevant to the calculations done in parts (a) and (b)?

Answers

Answer:

a. (3.83952, 5.16049)

b. (7.32, 8.88)

c. The difference in the range of the confidence intervals suggest that taking the zinc loz-enges reduces the overall duration of cold symptoms

d. The assumptions required for the validity validity of a t-test include that the data is sampled from a source that have data that are normally distributed

Step-by-step explanation:

The given parameters are;

The number of participants that took zinc lozenges, n₁ = 25

The number of participants that took a placebo, n₂ = 23

The mean duration of the symptoms for the zinc lozenge group, [tex]\overline x_1[/tex] = 4.5 days

The standard deviation of overall duration, s₁ = 1.6 days

The mean duration of the symptoms for the placebo group, [tex]\overline x_2[/tex] = 8.1 days

The standard deviation, s₂ = 1.8 days

a. The 95% confidence interval if everyone in the population were to take zinc lozenges is given as follows;

[tex]CI=\bar{x}_1\pm t_{\alpha/2} \times \dfrac{s_1}{\sqrt{n_1}}[/tex]

n₁ = 25, the degrees of freedom (df) = n₁ - 1 = 24

The t-value for 95% confidence interval, with df = 24, with t = 2.064

Therefore, we have;

[tex]CI_{zl}=4.5 \pm 2.064 \times \dfrac{1.6}{\sqrt{25}}[/tex]

[tex]CI_{zl}[/tex] = 4.5 ± 0.66048

[tex]CI_{zl}[/tex] = (3.83952, 5.16049)

b. The 95% confidence interval if everyone in the population were to take the placebo is given as follows;

[tex]CI_p=\bar{x_2}\pm t_{\alpha/2} \times \dfrac{s_2}{\sqrt{n_2}}[/tex]

n₂ = 23, the degrees of freedom (df) = n₂ - 1 = 22

The t-value for 95% confidence interval, with df = 22, with t = 2.074

Therefore, we have;

[tex]CI_p =8.1 \pm 2.074 \times \dfrac{1.8}{\sqrt{23}}[/tex]

[tex]CI_p[/tex] = 8.1 ± 0.7784

[tex]CI_p[/tex] = (7.32, 8.88)

c. Based on the difference in the range of the 95% confidence interval for the mean duration of cold symptoms of the group that take zinc lozenges, (3.83952, 5.16049), and the mean of the group that are on a placebo, (7.32, 8.88), there is sufficient statistical evidence to suggest that there is a difference between the mean and taking zinc lozenges reduces the overall duration of cold symptoms more than if taking placebo

d. The assumptions required for validity when carrying out a t-test include;

i) The measurement scale is ordinal or continuous

ii) The sample is a simple random sample

iii) The data gives a normal distribution curve

iv) The sample size is reasonably large

v) The variance are homogeneous

Among these assumptions, the data must be randomly sampled from the population of interest and that the data variables follow a normal distribution

The common assumptions made when doing a t-test include those regarding the scale of measurement, random sampling, normality of data distribution, adequacy of sample size and equality of variance in standard deviation

Given the points A(-3, -2) and B(6, 1), determine the coordinates of point P on directed line segment that partitions in the ratio 2/1.

Answers

Answer:

[tex]P = (3,0)[/tex]

Step-by-step explanation:

Given

[tex]A = (-3,-2)[/tex] ---- [tex](x_1,y_1)[/tex]

[tex]B = (6,1)[/tex] --- [tex](x_2,y_2)[/tex]

[tex]m:n =2:1[/tex]

Required

The coordinates of P

This is calculated as:

[tex]P = (\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}][/tex]

So:

[tex]P = (\frac{2*6+1*-3}{2+1},\frac{2*1+1*-2}{2+1})[/tex]

[tex]P = (\frac{9}{3},\frac{0}{3})[/tex]

[tex]P = (3,0)[/tex]

What is the edge length of
a cube of 1/8 m^3

Answers

Step-by-step explanation:

The volume of a cube is the edge³, so to find the edge, you need to calculate the cubic root of it:

[tex] \sqrt[3]{ \frac{1}{8} } = \frac{1}{2 } [/tex]

A ladder of length 8m rests against a wall so that the angle bsetween the ladder and wall is 45 degree .How far is the base of the ladder from the wall?

Answers

Answer: 8√2

Explanation: Use the 45-45-90 theorem to solve.

45 45 90
s s s√2
8√2 8√2 8

HELPPP PLS!! WILL MARK BRAINLIEST!! #plato
Drag each tile to the correct box.
Arrange the entries of matrix A in increasing order of their cofactor values.

Answers

Answer:

a23, a31, a21, a11, a12, a33

Step-by-step explanation: I got it right on Edumentum.

Answer:

a23, a31, a21, a11, a12, a33

Step-by-step explanation:

Find the sum of the first seven prime numbers that have a units digit of 7.

Answers

Answer:

7, 17, 37, 47, 73, 79, 97

Step-by-step explanation:

they have 7's as one of their digits

Please help

Calculate the volume of the given figure. Use 3.14 for ™.

3 ft

The volume of the solid figure shown in the drawing is approximately (Round to two decimal places as needed.)

Answers

Answer:

Step-by-step explanation:

Vol of a cylinder = pi * r^2 h

Vol of cone = 1/3 pi r^2 h

cylinder = pi *  (1)^2 * (3) = 3 pi

cone = 1/3 pi (1^2) 4 = 4/3 pi

total =   3 pi +  4/3 pi

        = pi(3+ 4/3) = pi(4.333)

= 13.6 f^3

I need help with this it's urgent!

Answers

Answer:

I looks like it's anwser D

Answer:

$460.80

Step-by-step explanation:

with we us our formula equation I=prt we now cam solve for our depreciated value

with we substitute our varibles with the correct numerals we now get

I= 960 x 0.12 x 4

we turn our 12% into a decimal to be Simplified into our equation.

If we now solve we will get

I = 960 x 0.12 x 4

I = 460.8

GIJL is a trapezoid with mid segment of HK. If IJ =7 cm and GL=15 cm, what is the length of HK?

Answers

Consider IJ and GL are the parallel sides of the trapezoid.

Given:

In a trapezoid GIJL, HK is the mid segment, IJ =7 cm and GL=15 cm.

To find:

The length of the mid segment HK.

Solution:

The length of the mid segment of a trapezoid is:

[tex]\text{Midsegment}=\dfrac{b_1+b_2}{2}[/tex]

where, [tex]b_1,b_2[/tex] are two parallel side or bases of the trapezoid.

HK is the mid segment, and the parallel sides are IJ =7 cm and GL=15 cm. So, the length of the mid segment is:

[tex]HK=\dfrac{IJ+GL}{2}[/tex]

[tex]HK=\dfrac{7+15}{2}[/tex]

[tex]HK=\dfrac{22}{2}[/tex]

[tex]HK=11[/tex]

Therefore, the length of HK is 11 units.

Simplify the expression. –(10)–2


100

–100

Answers

Answer:

-12, 0

Step-by-step explanation:

100 because two negatives make a positive

Find B
Plzz find the right answer and don’t just guess

Answers

Answer:

Step-by-step explanation:

using pythagoras theorem

a^2 + b^2 = c^2

B^2 + 8^2 = 15^2

B^2 + 64 + 225

B^2 = 225 - 64

B^2 = 161

B = [tex]\sqrt{161}[/tex]    OR  12.7

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

Step-by-step explanation:

circumference of circle=2πr

=2*π*9

=18π m

[tex]{ \bf{ \underbrace{Given :}}}[/tex]

Radius of the circle = 9 m.

[tex]{ \bf{ \underbrace{To\:find:}}}[/tex]

The circumference of the circle.

[tex]{ \bf{ \underbrace{Solution :}}}[/tex]

A. C = 18 π

[tex]\sf\orange{The\:circumference \:of\:the\:circle\:is\:18\:π\:m.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

We know that,

[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:2Πr }[/tex]

[tex] = 2 \: \pi \times 9 \: m \\ = 18 \: \pi \: m[/tex]

Therefore, the circumference of the circle is 18 π m.

[tex]\large\mathfrak{{\pmb{\underline{\blue{Happy\:learning }}{\blue{!}}}}}[/tex]

What value of b will cause the system to have an infinite number of solutions? y=6x-b -3x+1/2y=-3

Answers

Answer:

b = 6

Step-by-step explanation:

solve the second equation for 'y':

-3x + 1/2y = -3

add 3x to each side to get:

1/2y = 3x - 3

multiply all terms by 2 to eliminate the denominator to get:

y = 6x - 6

now compare '6x-6' with '6x-b'

you want both expressions to be equal because then there are an infinite number of solutions:

b = 6

What is the slope of every perpendicular line to y-2/3x=-4

Answers

Answer:

The slope of the line perpendicular is -3/2.

Step-by-step explanation:

y-2/3x=-4

y = 2/3x - 4

The slope of the line perpendicular is -3/2.

attachment below or above

Answers

Answer:

840

Step-by-step explanation:

600×140% =840 hope this helps

To find the amount of grizzly bears there were in 1975, we are going to find 140% of 600 grizzly bears then subtract it from 600. The answer we get will be the amount present in 1975.

600 × 140/ 100 = 840 grizzly bears

840 - 600 = 240 grizzly bears

Can someone please help me get surface area and lateral surface area

Answers

Answer:

Step-by-step explanation:

suface area of base=1/2×9×7.8=9×3.9=35.1 yd²

lateral surface area=3×1/2×9×10=135 yd²

total surface area=135+35.1=170.1 yd²

i assumed it is an equilateral triangular base.

as √(7.8²+4.5²)=9.0049≈9

gradient of line AB (3,7) and (5,11)​

Answers

Answer:

Gradient is change in y over change in x.

gradient = y1-y2 ÷ x1-x2

=7-11 ÷ 3-5

=-4 ÷ -2

=2

Use the slope/gradient formula below:

[tex] \large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]

This formula is for when we want to find the gradient when we have two given points. (We also call it Rise Over Run or changes of y over the changes of x.)

We are given two points which are (3,7) and (5,11). Substitute these points in the equation. (the ordered pairs are in (x,y) and not (y,x))

[tex] \large{m = \frac{11 - 7}{5 - 3} } \\ \large{m = \frac{4}{2} \longrightarrow \boxed{m = 2}}[/tex]

Hence, the gradient of AB is 2.

Answer

gradient is 2

Enter a range of values for x.

Answers

Answer:   3 < x < 34

=============================================================

Explanation:

Ignore the sides that are 'a' units long.

We'll compare the sides that are 26 units and 27 units long. We see the 27 unit side is larger, which makes the 93 degree angle larger than the 3x-9 degree angle.

Symbolically, we would say

3x-9 < 93

At the same time, the 3x-9 is also larger than 0

So

3x-9 > 0 or 0 < 3x-9

Put together, we can form this compound inequality

0 < 3x-9 < 93

-------------------

Let's isolate x like so

0 < 3x-9 < 93

0+9 < 3x-9+9 < 93+9 .... add 9 to all sides

9 < 3x < 102

9/3 < 3x/3 < 102/3 .... divide all sides by 3

3 < x < 34

x is any number between 3 and 34, but cannot equal either endpoint

For example, x = 10 is valid since 3 < 10 < 34 is true. But x = 50 is not a solution since 3 < 50 < 34 is false. We can't have x = 3 and we also can't have x = 34 either, but we can have anything in between those endpoints.

Which one goes where?:( WILL GIVE BRAINLIEST!<33

Answers

Answer:

1 pair of parallel sides: B

2 pairs of parallel sides: A, D

3 pairs of parallel sides: C

Step-by-step explanation:

When two lines are parallel, they will never intersect.

Eighty percent of students surveyed said they feel more focused after exercising. Nine hundred fifty students were surveyed.

Students Who Feel More Focused after Exercise
20%
20%
20%
20%
20%


How many students said they feel more focused after exercising?

Answers

Answer:

760

Step-by-step explanation:

it was 760 students that

How many solutions does the system have?
-87 + 2y = 8
- 40 +y=4

Answers

Please mark brainliest!

Answer is : No solution

A system of two equations can be classified as follows:

If the slopes are the same but the y-intercepts are different, the system has no solution.

If the slopes are different, the system has one solution.

If the slopes are the same and the y-intercepts are the same, the system has infinitely many solutions.

Definition Linear Equation in One Variable
A linear equation in one variable is an equation that can be written in the form ax+b=c, where a, b, and c are real numbers and .
Linear equations are also first-degree equations because the exponent on the variable is understood to be 1.
Objective 3: Identify Equations That Are Contradictions and Those That Are Identities
A conditional equation is an equation that is true for some values of the variable but not for others. Every linear equation that is a conditional equation has one solution. However, not every linear equation in one variable has a single solution. There are two other cases: no solution and the solution set of all real numbers.
Consider the equation x  x 1. No matter what value is substituted for x, the resulting value on the right side will always be one greater than the value on the left side. Therefore, the equation can never be true. We call such an equation a contradiction. It has no solution. Its solution set is the empty or null set, denoted by { }
or , respectively.
Now consider the equation xx2x. The expression on the left side of the equation simplifies to the expression on the right side. No matter what value we substitute for x, the resulting values on both the left and right sides will always be the same. Therefore, the equation is always true. We call such an equation an identity. It
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