Answer:
16,848+17,160+17,576+18,200+18,720+19,240+21,840=
129,584
Step-by-step explanation:
[tex]$8.10, $8.25, $8.45, $8.75, $9.00, $9.25, and $10.50\\[/tex]
Annually= Yearly, A year has 365 days.
They work 40 hours a week, 8*5=40.
There are aprox, 10 holidays in a year. (You can change this in your work)
They have 2 weeks unpaid vacation, 14 days.
There are aprox, 52 weeks in a year. (You can change this in your work)
52 weeks - 2 weeks of unpaid vacation= 50 weeks.
Now Let's calculate the weekly income, for
$8.10*40=$324 per week.
$8.25*40=$330 per week.
$8.45*40=$338 per week.
$8.75*40=$350 per week.
$9.00*40=$360 per week.
$9.25*40=$370 per week.
$10.50*40=$420 per week.
Now Let's calculate the annually income, for each clerk.
324*50=16,200 + 648=16,848
330*50=16,500 + 660=17,160
338*50=16,900 + 676=17,576
350*50=17,500 + 700=18,200
360*50=18,000 + 720=18,720
370*50=18,500 + 740=19,240
420*50=21,000 + 840=21,840
Now the total annual payroll=
16,848+17,160+17,576+18,200+18,720+19,240+21,840=
129,584
Please help! Dad will murder me if I don't have this done by the time he gets home! 100 points for whoever solves this!
Answer:
3(4)to the 3
Step-by-step explanation:
Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the specified axis.
y = 6x − x2, y = 8; about x = 2
Answer:
[tex]\mathbf{V = [\dfrac{ 8 \pi }{3}] }[/tex]
Step-by-step explanation:
Given that:
y = 6x - x² , y = 8 about x = 2
To find the volume of the region bounded by the curves about x = 2; we have the radius of the cylindrical shell to be x - 1, the circumference to be 2 π (x -2 ) and the height to be 6x - x² - 8
6x - x² - 8
6x - x² - 8 = 0
-x² + 6x - 8 = 0
x² - 6x + 8 = 0
(x -4) (x - 2 ) = 0
So;
x = 2 , x = 4
Thus, the region bound of the integral are from a = 2 and b = 4
Therefore , the volume of the solid can be computed as :
[tex]V = \int \limits ^b _a \ 2x \times f(x) \ dx[/tex]
[tex]V = \int \limits ^4_2 2 \pi (x -2) (6x -x^2 -8) \ dx[/tex]
[tex]V = 2 \pi \int \limits ^4_2 (6x^2 - x^3 -8x -12 x - 2x^2 +16) \ dx[/tex]
[tex]V = 2 \pi \int \limits ^4_2 (8x^2 -x^3-20x +16) \ dx[/tex]
[tex]V = 2 \pi \int \limits ^4_2 ( -x^3+8x^2-20x +16) \ dx[/tex]
[tex]V = 2 \pi [\dfrac{ -x^7}{4}+\dfrac{8x^3}{3} -\dfrac{20x^2}{2} +16x]^4_2[/tex]
[tex]V = 2 \pi [\dfrac{ -(4^4-2^4)}{4}+\dfrac{8(4^3-2^3)}{3} -\dfrac{20(4^2-2^2)}{2} +16(4-2) ]^4_2[/tex]
[tex]V = 2 \pi [\dfrac{ -(256-16)}{4}+\dfrac{8(64-8)}{3} -10(16-4)} +16(2) ][/tex]
[tex]V = 2 \pi [\dfrac{ 4}{3}][/tex]
[tex]\mathbf{V = [\dfrac{ 8 \pi }{3}] }[/tex]
attachment help for question c no explanation only answer thank you
Answer:
Tablets.
Step-by-step explanation:
You didn't want an explanation so....here you go....no explanation.
Hope that helps and maybe earns a brainliest.
Have a great day!
PLEASE HELP ME!! I WILL GIVE BRAINLIEST!!
Find the output, y, when the input, x, is -5.
Answer:
[tex]\boxed{y = -2}[/tex]
Step-by-step explanation:
Hey there!
To find y when x is -5 we go to -5 on the x-axis.
When at -5 find where the blue line is vertical to -5,
which is -2.
Hope this helps :)
which of these expressions are equivalent to p/3?
A. p-2/3
B. 1/3p
C. p-3
D. 3/p
E. 3p/p
This is assuming that p is not in the denominator. To make it more clear that p is not in the denominator, I recommend you write (1/3)p.
Taking 1/3 of a number is the same as dividing by 3.
Example:
27/3 = 9
27*(1/3) = 9
what is the first step to solving this problem: 3x-10=2(x+3)
Answer:
x = 16
Step-by-step explanation:
3x - 10 = 2(x+3)
First step is solve this:
2(x+3) = 2*x + 2*3 = 2x + 6
then:
3x - 10 = 2x + 6
3x - 2x = 6 + 10
x = 16
Check:
3*16 - 10 = 2(16+3)
48 - 10 = 2*19 = 38
Answer:
x = 16
Step-by-step explanation:
you start off by isolating the variable