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In triangle sum of 2 sides must be greater than the 3rd side. So, the third > 8 - 6 = 2 and also the third < 8 + 6 = 14. So, the answer is 2 < third side < 14. The third side lies between(2,14).
Step-by-step explanation: Brainlyest please
On a single toss of a fair coin, the probability of heads is 0.5 and the probability of tails is 0.5. If you toss a coin twice and get heads on the first toss, are you guaranteed to get tails on the second toss? Explain. Yes, since the coin is fair. No, each outcome is equally likely regardless of the previous outcome. Yes, tails will always result on the second toss. No, tails will never occur on the second toss.
Answer:
No, each outcome is equally likely regardless of the previous outcome.
Five more than the square of a number Five more than twice a number Five less than the product of 3 and a number Five less the product of 3 and a number Twice the sum of a number and 5 The sum of twice a number and 5 The product of the cube of a number and 5 The cube of the product of 5 and a number. 5 + x2 5 + 2x 5 - 3x 3x - 5 2x + 5 2(x + 5) 5x3 (5x)3 WILL MARK BRAINLIEST AND DON'T PUT A FAKE ANSWER TO GET POINTS EITHER CUS I NEED HELP
Answer:
BelowStep-by-step explanation: Let all unknown no be x
Five more than the square of a number
= [tex]5 + x^2[/tex]
Five more than twice a number ;
[tex]5+2x\\= 2x+5[/tex]
Five less than the product of 3 and a number ;
[tex]5- 3x\\= 3x-5[/tex]
Twice the sum of a number and 5 ;
[tex]2(x+5)\\[/tex]
The sum of twice a number and 5 ;
[tex]2x+5[/tex]
The product of the cube of a number and 5;
[tex]x^3 \times 5\\=5x^3[/tex]
The cube of the product of 5 and a number ;
[tex](5\times x)^3\\(5x)^3[/tex]
How would you simplify and rationalize this expression? [tex]\frac{5\sqrt[4]{2}}{4\sqrt[4]{162} }[/tex]
Answer:
5/12
Step-by-step explanation:
(5 * 2^1/4)/4 * 162^1/4) = (5 * 2^1/4)/4 * 3 *2^1/4)
multiply top and bottom by 2^3/4
(5 * 2)/4 * 3 * 2) = 10/24 = 5/12
Given below are descriptions of two lines. Line 1: Goes through (-2,10) and (1,1) Line 2: Goes through (-2,8) and (2,-4)
Answer:
Option (2)
Step-by-step explanation:
1). If two lines have the same slope, lines are defined as parallel.
m₁ = m₂
2). If the multiplication of the slopes of two lines is (-1), lines will be perpendicular.
m₁ × m₂ = (-1)
Line 1 : It passes through two points (-2, 10) and (1, 1).
Slope of the line 1 = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{1+2}{10-1}[/tex]
= [tex]\frac{3}{9}[/tex]
m₁ = [tex]\frac{1}{3}[/tex]
Line 2 : It passes through two points (-2, 8) and (2, -4).
Slope of the line 2 = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{8+4}{-2-2}[/tex]
= [tex]-\frac{12}{4}[/tex]
m₂ = -3
Since, m₁ × m₂ = [tex]\frac{1}{3}\times (-3)[/tex]
= (-1)
Therefore, given lines are perpendicular to each other.
Option (2) is the correct option.
The product of a number and 3 is equal to 15 minutes twice the number, find the number.
Answer:
The answer is 3Step-by-step explanation:
Let the number to be found be x
The product of a number and 3 is written as
3 × x = 3x15 minus twice the number is written as
15 - 2xNow equate the two statements
That's
3x = 15 - 2x
Group like terms
3x + 2x = 15
5x = 15
Divide both sides by 5
the final answer is
x = 3Hope this helps you
find the value of each variable and the measure of each angle
Answer:
y = 90x = 302x° = 60°(y+x)° = 120°(y-x)° = 60°Step-by-step explanation:
Adjacent angles are supplementary, so ...
(y +x) +(y -x) = 180
2y = 180 . . . . . . . . . simplify
y = 90 . . . . . . . . . . . divide by 2
__
2x +(y +x) = 180
3x +90 = 180 . . . . substitute for y
x + 30 = 60 . . . . . . divide by 3
x = 30 . . . . . . . . . . subtract 30
__
With these values of x and y, the angle measures are ...
2x° = 2(30)° = 60°
(y+x)° = (90+30)° = 120°
(y-x)° = (90-30)° = 60°
PLEASE HELP Weekly wages at a certain factory are
normally distributed with a mean of
$400 and a standard deviation of $50.
Find the probability that a worker
selected at random makes betweenh
$250 and $300.
Answer: 0.0215 .
Step-by-step explanation:
Let X denotes the weekly wages at a certain factory .
It is normally distributed , such that
[tex]X\sim N(\mu=400,\ \sigma= 50)[/tex]
Then, the probability that a worker selected at random makes between
$250 and $300:
[tex]P(250<X<300)=P(\dfrac{250-400}{50}<\dfrac{x-\mu}{\sigma}<\dfrac{300-400}{50})\\\\=P(\dfrac{-150}{50}<z<\dfrac{-100}{50})\ \ [z=\dfrac{x-\mu}{\sigma}]\\\\=P(-3<z<-2)\\\\=P(z<-2)-P(z<-3)\\\\=1-P(z<2)-(1-P(z<3))\\\\=P(z<3)-P(z<2)\\\\=0.9987-0.9772\\\\=0.0215[/tex]
Hence,the required probability = 0.0215 .
Evaluate the following expressions: 2(−1 + 3) − 7
Answer:
-3 is the answer.
Step-by-step explanation:
=2(-1+3)-7
=2(2)-7
=4-7
=-3
Hope it will help you :)
The population of men at UMBC has a mean height of 69 inches with a standard deviation of 4 inches. The women at UMBC have a mean height of 65 inches with a standard deviation of 3 inches. A sample of 50 men and 40 women is selected. What is the probability that the sample mean of men heights is more than 5 inches greater than the sample mean of women heights
Answer:
The probability that the sample mean of men heights is more than 5 inches greater than the sample mean of women heights is 0.0885.
Step-by-step explanation:
We are given that the population of men at UMBC has a mean height of 69 inches with a standard deviation of 4 inches. The women at UMBC have a mean height of 65 inches with a standard deviation of 3 inches.
A sample of 50 men and 40 women is selected.
The z-score probability distribution for the two-sample normal distribution is given by;
Z = [tex]\frac{(\bar X_M-\bar X_W)-(\mu_M-\mu_W)}{\sqrt{\frac{\sigma_M^{2} }{n_M}+\frac{\sigma_W^{2} }{n_W} } }[/tex] ~ N(0,1)
where, [tex]\mu_M[/tex] = population mean height of men at UMBC = 69 inches
[tex]\mu_W[/tex] = population mean height of women at UMBC = 65 inches
[tex]\sigma_M[/tex] = standard deviation of men at UMBC = 4 inches
[tex]\sigma_M[/tex] = standard deviation of women at UMBC = 3 inches
[tex]n_M[/tex] = sample of men = 50
[tex]n_W[/tex] = sample of women = 40
Now, the probability that the sample mean of men heights is more than 5 inches greater than the sample mean of women heights is given by = P([tex]\bar X_M-\bar X_W[/tex] > 5 inches)
P([tex]\bar X_M-\bar X_W[/tex] > 5 inches) = P( [tex]\frac{(\bar X_M-\bar X_W)-(\mu_M-\mu_W)}{\sqrt{\frac{\sigma_M^{2} }{n_M}+\frac{\sigma_W^{2} }{n_W} } }[/tex] > [tex]\frac{(5)-(69-65)}{\sqrt{\frac{4^{2} }{50}+\frac{3^{2} }{40} } }[/tex] ) = P(Z > 1.35)
= 1 - P(Z [tex]\leq[/tex] 1.35) = 1 - 0.9115 = 0.0885
The above probability is calculated by looking at the value of x = 1.35 in the z table which has an area of 0.9115.
Assume that women's heights are normally distributed with a mean given by mu = 64.3 inches, and a standard deviation given by sigma= 2.2 inches.
A) If a woman is randomly selected, find the probability that her height is less than 65 inches.
B) If 34 women are randomly selected, find the probability that they have a mean height less than 65 inches.
Answer:69
Step-by-step explanation:
An octagonal pyramid ... how many faces does it have, how many vertices and how many edges? A triangular prism ... how many faces does it have, how many vertices and how many edges? a triangular pyramid ... how many faces does it have, how many vertices and how many edges?
1: 8 faces and 9 with the base 9 vertices and 16 edges
2: 3 faces and 5 with the bases 6 vertices and 9 edges
3: 3 faces and 4 with the base 4 vertices and 6 edges
Hope this can help you.
If I chose a number uniformly from the integers from 1 to 25, calculate the conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18.
Answer:
1/7Step-by-step explanation:
If I choose a number from the integers 1 to 25, the total number of integers I can pick is the total outcome which is 25. n(U) = 25
Let the probability that the number chosen at random is a multiple of 6 be P(A) and the probability that the number chosen at random is is larger than 18 be P(B)
P(A) = P(multiple of 6)
P(B) = P(number larger than 18)
A = {6, 12, 18, 24}
B = {19, 20, 21, 22, 23, 24, 25}
The conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is expressed as P(A|B).
P(A|B) = P(A∩B)/P(B)
Since probability = expected outcome/total outcome
A∩B = {24}
n(A∩B) = 1
P(A∩B) = n(A∩B)/n(U)
P(A∩B) = 1/25
Given B = {19, 20, 21, 22, 23, 24, 25}.
n(B) = 7
p(B) = n(B)/n(U)
p(B) = 7/25
Since P(A|B) = P(A∩B)/P(B)
P(A|B) = (1/25)/(7/24)
P(A|B) = 1/25*25/7
P(A|B) = 1/7
Hence the conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is 1/7
a radion station usa 1\6 of its time for the news. in a 12 hour day, how many hours are used for music & entertainment?
Answer:
10 hours
Step-by-step explanation:
In order to answer this question, you must assume that all air time not spent on news is spent on music & entertainment. That would usually not be the case, as there would usually be advertisements and public service programming along with everything else.
The time spent on news is ...
(1/6)(12 hours) = 2 hours
If the rest is spent on music and entertainment, then ...
12 -2 = 10 . . . hours are used for music and entertainment
If the occurrence of one event does not influence the outcome of another event, then two events are:
A. conditional
B. disjoint
C. independent
D. interdependent
Answer:
C. Independent
Step-by-step explanation:
Independent events are events that have no impact on each other.
So, if the occurrence of an event doesn't influence the outcome of another, this means that they are independent because they do not impact each other.
This must mean C is correct because the two events have to be independent.
A technician is testing light bulbs to determine the number of defective bulbs. The technician records the table below to show the results. Result of Light Bulb Test Number of Bulbs Tested 14 28 84 336 Number of Defective Bulbs Found 1 2 6 ? The technician expects to find 24 defective bulbs when 336 are tested. Which statement explains whether the technician’s reasoning is correct, based on the information in the table?
Answer:
He should find 24 defective lightbulbs.
Step-by-step explanation:
1. Divide the number of defective bulbs by the total number of bulbs for each section.
2. Make sure the number you get is the same each time.
3. Divide the guessed number of bulbs (24) by the total number of bulbs (336)
4. If the number you got for step 4 matches the number you got for step 3, then he is right
Answer:
The answer is A
Step-by-step explanation:
on NCCA
ACDF,BE is a mid segment what is x?
Answer:
X= 15
Step-by-step explanation:
the above equation will be used to determine the value of x.
the above equation will be used to determine the value of x.
6x-12= 2x+20+18
6x-2x = 20+12+18
4x= 60.
X= 60/4
X= 15
x = 15
PLS HELP ASAP Solve the inequality and enter your solution as an inequality in the box below 8>4-x>6
Answer:
−4<x<−2
Step-by-step explanation:
8 > 4 − x > 6
8 > −x + 4 > 6
8 + −4 > −x + 4 + −4 > 6 + −4
4 > −x > 2
Since x is negative we need to divide everything by -1 which gives us...
−4 < x < −2
. In statistics, a data set has the following characteristics: (Choose all that apply) A:A data set is a collection of similar data. B:A data set can contain only quantitative data. C:A data set is any piece of descriptive or quantitative information on any object of study. D:A data set contains data all of which have some common characteristic.
Answer:
A. A data set is a collection of similar data.
D. A data set contains data all of which have some common characteristic.
Fill in the blanks and explain the pattern.
4.25, 4.5,__,__,__,5.5,__,6.0
Answer:
4.25, 4.5, 4.75, 5.00, 5.25, 5.5, 5.75, 6.00
Step-by-step explanation:
it is an arithmetic sequence with common difference 0.25
round 38562 to one significant figure
Answer:
plz refer the attachment
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hi my lil bunny!
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
ROUND 38562 to ONE significant figure.
Answer:
= 4000
Rounding Significant Figures Rules
~ ↓↓↓↓↓↓↓ ~
Non-zero digits are always significant
Zeros between non-zero digits are always significantLeading zeros are never significantTrailing zeros are only significant if the number contains a decimal pointExamples of Significant Figures❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
If this helped you, could you maybe give brainliest..?
❀*May*❀
Find the total area the regular pyramid. T.A=
Answer:
18√91 +54√3
Step-by-step explanation:
Name the point at the top of the pyramid "A", the point at the left front corner "B", and the one in the center of the hexagonal base "C". Then right triangle ABC is shown. The "base" BC of that triangle is the same measure as the front edge (6), because the diameter of a regular hexagon is equal to twice the side length.
Using the Pythagorean theorem, we can find the face edge length to be ...
AB^2 = BC^2 +AC^2
AB^2 = 6^2 +8^2 = 100
AB = √100 = 10
If we call the midpoint of the front edge "D", then we need to find the length of AD in order to determine the face area. Again, we can use the Pythagorean theorem.
AB^2 = BD^2 +AD^2
AD^2 = AB^2 -BD^2 = 10^2 -3^2 = 91
AD = √91
The area of one of the 6 lateral faces is ...
A = (1/2)bh = (1/2)(6)√91 = 3√91
The area of one of the 6 equilateral triangles that make up the base is ...
A = (√3)/4·s^2 = (√3)/4(6^2) = 9√3
Then the total area of the pyramid is ...
total area = 6 × (face area + partial base area)
= 6(3√91 +9√3)
total area = 18√91 +54√3
Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation, they discovered that his equation had all the same solutions as Fiona’s. Which equation could be Henry’s? x – x minus StartFraction 5 over 4 EndFraction y equals StartFraction 25 over 4 EndFraction.y = x – x minus StartFraction 5 over 2 EndFraction y equals StartFraction 25 over 4 EndFraction.y = x – x minus StartFraction 5 over 4 EndFraction y equals StartFraction 25 over 2 EndFraction.y = x – x minus StartFraction 5 over 2 EndFraction y equals StartFraction 25 over 2 EndFraction.y =
Answer:
D. [tex]x-\frac{5}{2}y = \frac{25}{2}[/tex]
Step-by-step explanation:
Given
[tex]y = \frac{2}{5}x - 5[/tex]
Required
Determine its equivalent
From the list of given options, the correct answer is
[tex]x - \frac{5}{2}y = \frac{25}{2}[/tex]
This is shown as follows;
[tex]y = \frac{2}{5}x - 5[/tex]
Multiply both sides by [tex]\frac{5}{2}[/tex]
[tex]\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)[/tex]
Open Bracket
[tex]\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5[/tex]
[tex]\frac{5}{2}y = x - \frac{25}{2}[/tex]
Subtract x from both sides
[tex]\frac{5}{2}y - x = x -x - \frac{25}{2}[/tex]
[tex]\frac{5}{2}y - x = - \frac{25}{2}[/tex]
Multiply both sides by -1
[tex]-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1[/tex]
[tex]-\frac{5}{2}y + x = \frac{25}{2}[/tex]
Reorder
[tex]x-\frac{5}{2}y = \frac{25}{2}[/tex]
Hence, the correct option is D
[tex]x-\frac{5}{2}y = \frac{25}{2}[/tex]
Answer:
The 4th option
Step-by-step explanation:
Which of the following is the correct set notation for the set of perfect squares between 1 and 100 (including 1 and 100)?
Select the correct answer below:
{p2∣p∈ℤ and 1≤p≤10}
{p2∣p∈ℤ and 1
Answer:
[tex]\{P^2: P\ E\ Z\ and\ 1\leq p\leq 10\}[/tex]
Step-by-step explanation:
Given
Range: = 1 to 100 (Inclusive)
Required
Determine the notation that represents the perfect square in the given range
Represent the range with P
P = 1 to 100
Such that the perfect squares will be P² and integers
In set notation, integers are represented with Z
The set notation becomes
[tex]\{P^2: P\ E\ Z\ and\ 1\leq p\leq 10\}[/tex]
The [tex]\leq[/tex] shows that 1 and 100 are inclusive of the set
Consider the following. x = t − 2 sin(t), y = 1 − 2 cos(t), 0 ≤ t ≤ 2π Set up an integral that represents the length of the curve. 2π 0 dt Use your calculator to find the length correct to four decimal places.
Answer:
L = 13.3649
Step-by-step explanation:
We are given;
x = t − 2 sin(t)
dx/dt = 1 - 2 cos(t)
Also, y = 1 − 2 cos(t)
dy/dt = 2 sin(t)
0 ≤ t ≤ 2π
The arc length formula is;
L = (α,β)∫√[(dx/dt)² + (dy/dt)²]dt
Where α and β are the boundary points. Thus, applying this to our question, we have;
L = (0,2π)∫√((1 - 2 cos(t))² + (2 sin(t))²)dt
L = (0,2π)∫√(1 - 4cos(t) + 4cos²(t) + 4sin²(t))dt
L = (0,2π)∫√(1 - 4cos(t) + 4(cos²(t) + sin²(t)))dt
From trigonometry, we know that;
cos²t + sin²t = 1.
Thus;
L = (0,2π)∫√(1 - 4cos(t) + 4)dt
L = (0,2π)∫√(5 - 4cos(t))dt
Using online integral calculator, we have;
L = 13.3649
Solve 5(2x + 4) = 15. Round to the nearest thousandth.
[tex]5(2x + 4) = 15\\10x+20=15\\10x=-5\\x=-\dfrac{5}{10}=-0,5[/tex]
Answer:
[tex]\huge\boxed{x=-0.5}[/tex]
Step-by-step explanation:
[tex]5(2x+4)=15\qquad\text{divide both sides by 5}\\\\\dfrac{5\!\!\!\!\diagup(2x+4)}{5\!\!\!\!\diagup}=\dfrac{15\!\!\!\!\!\diagup}{5\!\!\!\!\diagup}\\\\2x+4=3\qquad\text{subtract 4 from both sides}\\\\2x+4-4=3-4\\\\2x=-1\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{-1}{2}\\\\\boxed{x=-0.5}[/tex]
Find the point on the terminal side of θ = negative three pi divided by four that has an x coordinate of -1. Show your work for full credit. Please explain the exact process of how you get your answer because I do not understand it at all. If you don't explain properly or try to just snatch some points I will try to delete your answer.
Answer:
See below.
Step-by-Step Explanation:
Please refer to the attachment.
If you have any questions, feel free to comment!
Answer:
(-1,-1)
Step-by-step explanation:
theta = -3 pi/4
Changing to degrees =
theta = -3 * 180/4 =-135
x coordinate of -1
The y value would be
= 45
tan 45 = y /1
y = tan 45
y = 1
But we are in the third coordinate so x and y are negative
The coordinates are
(-1,-1)
Armando is baking 36 batches of brownies for the bake sale. Each batch of brownies takes cups of flour. What is a reasonable estimate of the amount of flour that he will need to bake all thirty-six batches of brownies?
Answer:
Well, let's assume that "cups" = 3 cups of flour.
Step-by-step explanation:
First, multiply 3x36.
If for some reason this is incorrect, try 2 cups instead of 3. Both are reasonable measurements when it comes to baking.
g a video game claims that the drop rate for a certain item is 5% according to the game publisher. in online forums, a number of players are complaining that the drop rate seems to be low. in order to test the drop rate claim, 100 players agree to attempt to get the drop, each attempting 10 times. of the 1000 tries, the item only drops 40 times state the null hypothesis needed to test this claim group of answer choices
Answer:
p0 = 0.05
Step-by-step explanation:
solve the following system of equations
1/2x+1/4y=-2
-2/3x+1/2y=6
x=
y=
Answer:
x = -6
y = 4
Step-by-step explanation:
Rewriting the equations :
2x + y = -84x - 3y = -36Now, solving the two equations using substitution method, we get :
x = -6
y = 4
Answer:
y = 4
x = -6
Step-by-step explanation:
1/2 x + 1/4 y= -2 first equation
-2/3 x + 1/2 y = 6 second equation
solution:
from the first equation:
8(1/2 x + 1/4 y) = -2*8
8x*1/2 + 8y*1/4 = -16
8x/2 + 8y/4 = -16
4x + 2y = -16 third equation
from the second equation
6(-2/3 x + 1/2 y) = 6*6
6x*-2/3 + 6y*1/2 = 36
-12x/3 + 6y/2 = 36
-4x + 3y = 36 fourth equation
from the third & fourth equation:
4x + 2y = -16
-4x + 3y = 36
0 + 5y = 20
5y = 20
y = 20/5
y = 4
from the fourth equation:
-4x + 3y = 36
-4x + 3*4 = 36
-4x + 12 = 36
-4x = 36 - 12
-4x = 24
x = 24/-4
x = -6
Check:
from the first equation:
1/2 x + 1/4 y = -2
1/2 *-6 + 1/4 * 4 = -2
-3 + 1 0 -2
from the second equation:
-2/3 x + 1/2 y = 6
-2/3 * -6 + 1/2 * 4 = 6
4 + 2 = 6
If Ac={vt2/r) and vt=2 and r=2 find Ac
a. 4
b. 2
C. 1
D. 8
given: [tex] Ac=\frac{vt2}r \quad vt=2 \quad r=2[/tex]
$\therefore Ac=\frac{(2)2}{2}=2$