Answer:
The line between 1 5/8 and 1 7/8 is exactly 1 3/4.
Step-by-step explanation:
1 3/4 = 1 6/8
Since the lines are every 1/8 of a cup, there are a total of 16 lines indicating 1/8 of a cup for a total of two full cups.
1/8 less than 1 6/8 is 1 5/8.
1/8 more than 1 6/8 is 1 7/8.
The line between 1 5/8 and 1 7/8 is exactly 1 3/4.
Nijah has 45 stickers.
She gives 2/5 to her sister.
She gives 1/3 of her remaining stickers to Brett.
How many stickers does Nijah have left?
Answer:
Nijah has 6 stickers left.
Step-by-step explanation:
Starting stickers:
45
2/5 are given away:
[tex]\frac{2}{5}[/tex] * 45
[tex]\frac{2}{5}[/tex] * [tex]\frac{45}{1}[/tex]
[tex]\frac{90}{5}[/tex]
18
1/3 of the remaining are given away:
[tex]\frac{1}{3}[/tex] * 18
[tex]\frac{1}{3}[/tex] * [tex]\frac{18}{1}[/tex]
[tex]\frac{18}{3}[/tex]
6
Nijah has 6 stickers left.
Answer:
18
Step-by-step explanation:
Find the part she gave to her sister
45 *2/5 = 18
The part remaining is
45 - 18 = 27
She gives 1/3 to Brett
27 * 1/3 = 9
She has 27 - 9 = 18
She has 18 remaining
the product of 5 and z
Answer:
5z
Step-by-step explanation:
As product = multiplication =>
5 x z --> 5(z)
[tex]\text{Find the product of 5 and z}\\\\\text{The key term in this questions is product, and in math it translates to}\\\text{the answer when multiplled}\\\\\text{In this case, you would multiply them together to get your "product"}\\\\\text{Solve:}\\\\5\cdot z\\\\\boxed{5z}[/tex]
Two of the lights at the local stadium are flickering. They both just flickered at the same time.
One of the lights flickers every 7 seconds and the other light flickers every 8 seconds.
How many seconds until both lights will flicker at the same time again?
seconds
Answer:
56
Step-by-step explanation:
you have to find the LCM of 7 AND 8.
which is 56
Answer:
The answer is 56
Step-by-step explanation:
Mrs. Yadav purchase 25 kg of vegetable at Rs 20 per kg and sold at a loss of Rs 50 find her
Selling rate and loss percent
Answer:
[tex] \boxed{loss\% \: = 10\%}[/tex][tex] \boxed{selling \: price = Rs 450}[/tex]Step-by-step explanation:
Given,
Cost price of 25 kg of vegetables ( CP ) = 25 × 20
= Rs 500
Loss amount = Rs 50
Selling price ( SP ) = ?
Loss percent = ?
Now, let's find the loss percent :
[tex] \mathsf{ \frac{loss}{cost \: price} \times 100\%}[/tex]
[tex] \mathsf{ = \frac{50}{500} \times 100\%}[/tex]
[tex] \mathsf{ = 10\%}[/tex]
Loss % = 10 %
Now, let's find the selling price:
[tex] \mathsf{ \frac{CP(100 - l\%)}{100} }[/tex]
[tex] \mathsf{ = \frac{500(100 - 10)}{100}} [/tex]
[tex] \mathsf{ = \frac{500 \times 90}{100} }[/tex]
[tex] \mathsf{ = \frac{45000}{100} }[/tex]
[tex] \mathsf{= 450}[/tex]
Hope I helped!
Best regards!
PLZ HELP !!!!!! ASAP!!!
Part (a)
BC = opposite side (furthest leg from the reference angle)
AB = adjacent side (closest leg from the reference angle)
AC = hypotenuse (always opposite the 90 degree angle)
=============================================
Part (b)
i. False. Angle B is 90 degrees as shown by the square angle marker.
ii. False. Side AB is opposite angle C. Note how "C" is part of "BC", so that means we cannot have BC be opposite C.
iii. True. Leg AB is the closer leg to angle A. We have "A" in "AB" to see this without having to draw the diagram. Refer to part (a) above.
iv. False. The longest side of any right triangle is always the hypotenuse. The longest side of any triangle is always opposite the largest angle.
==============================================
Part (c)
cos(theta) = adjacent/hypotenuse = AB/AC
tan(theta) = opposite/adjacent = BC/AB
Refer back to part (a) to determine the opposite,adjacent and hypotenuse side lengths.
==============================================
Part (d)
The reference angle has changed, so the opposite and adjacent sides swap. The hypotenuse remains the same regardless of what reference angle you pick.
sin(C) = opposite/hypotenuse = AB/AC
cos(C) = adjacent/hypotenuse = BC/AC
tan(C) = opposite/adjacent = AB/BC
Note the tangent ratio is the reciprocal of what we found back in part (c).
Answer & Step-by-step explanation:
(a)
The hypotenuse is on line CA (the hypotenuse is always opposite the 90° angle (marked by a little square))
The adjacent is on the line BA (adjacent is next to the given angle, but NOT the hypotenuse)
The opposite is on the line CB (this is opposite the given angle)
(b)
i. false (b is a right angle)
ii. false (the side opposite C is BA)
iii. true
iv. false (the side opposite B is the hypotenuse, and the hypotenuse is always the longest side in a triangle)
(c)
cosine ratio: [tex]cos=\frac{adjacent}{hypotenuse}[/tex]
tangent ratio: [tex]tan=\frac{opposite}{adjacent}[/tex]
The cosine and tangent ratios of the given angle:
[tex]cos0=\frac{AB}{CA} \\\\tan0=\frac{CB}{AB}[/tex]
(d)
Remember SOH-CAH-TOA:
Sine=Opposite/Hypotenuse
Cosine=Adjacent/Hypotenuse
Tangent=Opposite/Adjacent
Using the angle C, plug in the appropriate sides:
[tex]sinC=\frac{BA}{CA}\\\\ cosC=\frac{CB}{CA}\\\\ tanC=\frac{BA}{CB}[/tex]
:Done
You are the owner of Decorama Flooring Tod and Claudia have asked for an estimate 15 feet*23 feet dinning room 12ft*18 kitchen 9ft*11 ft and 10ft*12 ft how many square ft required(multipy length by the width)
Answer:
Step-by-step explanation:
The question is not properly written. Here is the correct question.
You are the owner of Decorama Flooring. Tod and Claudia have asked you to give an estimate for tiling four rooms of their house. The living room is 15 feet*23 feet, dinning room is 12ft*18ft, the kitchen is 9ft*11 ft and the study room is 10ft*12 ft how many square ft of tiles are required for each room. (multiply length by the width).
We must understand that a floor tile is rectangular in nature.
Area of a rectangle = Length * width
To get the amount of square feet required for each room, we must multiply the length and width of each of the rooms together as shown.
For the living room;
Length = 15 feet and Width = 23 feet
Amount of square feet of tiles needed for the living room = 15feet * 23 feet
= 345 ft²
For the dining room;
Length = 12 feet and Width = 18 feet
Amount of square feet of tiles needed for the dining room = 12feet * 18 feet
= 216 ft²
For the kitchen;
Length = 9 feet and Width = 11 feet
Amount of square feet of tiles needed for the kitchen = 11feet *9feet
= 99 ft²
For the study room;
Length = 10 feet and Width = 12 feet
Amount of square feet of tiles needed for the study room = 10feet * 12 feet
= 120 ft²
PLEASE HELP ME REALLY QUICK!
Answer:
90 degrees
Step-by-step explanation:
Add them together. 58+32=90
90 degrees
add them togather
What is the product?
8.25 x
1
5
0.82
O 1.65
0 8.25
16.5
Answer:
Answers
product, and assign a number to each person. ... 0.82. 12–13. 9. 0.18. 1.00. Total. 50. 1.00. F requency. 0. 1. 2. 3. 4. 5. 6. 7. 8 ... 3.12 (a) x = 25661.3333, ˜x = 25514.5 (b) Skewed ... N(8.25, 0.0002857).
Answer:
the answer is c
Step-by-step explanation:
i just took the test
Solve the equation
(If possible please show work)
m∠QPSm, is a straight angle m∠RPS=6x+11 m∠QPR=7x+143 ;Find RPS
Answer:
23
Step-by-step explanation:
6x + 11 + 7x + 143 = 180
13x + 154 = 180
13x = 26
x = 2
m<RPS = 6(2) + 11 = 23
Determine the most precise name for KIET (parallelogram,rhombus,rectangle or square.) you must use slope or length. K(0,0) I(2,2) T(5,-5) E(7,-3)
Answer: rectangle.
Step-by-step explanation:
Given points: K(0,0) I(2,2) T(5,-5) E(7,-3)
Distance formula to find distance between [tex]A(a,b)[/tex] and [tex]B(c,d)[/tex]: [tex]AB=\sqrt{(d-b)^2+((c-a)^2}[/tex]
[tex]KI=\sqrt{(2-0)^2+(2-0)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]
[tex]KT=\sqrt{(5-0)^2+(-5-0)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]
[tex]TE=\sqrt{(7-5)^2+(-3+5)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]
[tex]IE=\sqrt{(7-2)^2+(-3-2)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]
i.e. KI = TE and KT= IE, so opposite sides equal.
It can be a parallelogram or rectangle. [if all sides are equal it would be square or rhombus]
[tex]IT=\sqrt{(5-2)^2+(-5-2)^2}=\sqrt{3^2+7^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]
[tex]KE=\sqrt{(7-0)^2+(-3-0)^2}=\sqrt{7^2+3^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]
IT= KE, i.e. diagonals are equal.
It means KIET is a rectangle.
Which expression, in exponential form, is equivalent to 26x3y 47z5r3 A) ( 26x3y 47z5r3 )2 B) (26xy) 1 2 (47zr) 1 2 C) 26 1 2 x 3 2 y 1 2 47 1 2 z 5 2 r 3 2 D) 26x 3 2 y 1 2 47z 5 2 r 3 2
Answer:
The answer is "all the choices were wrong"
Step-by-step explanation:
Given value:
[tex]\bold{26x^3y 47z^5r^3}[/tex]
In the given question all the choices were wrong because it is not equivalent to given equation:
In choice A) [tex]( 26x^3y 47z^5r^3 )^2[/tex] in the value is whole squared, that's why it is wrong.
In choice B) [tex](26xy)^{12} (47zr)^{12}[/tex] when we open its value it will give different values, that's why it is wrong.
In option C and D( [tex]26^{12} x^{32} y^{12} 47^{12} z^{52} r^{32}[/tex] and [tex]26x^{32} y^{12}47z^{52} r^{32}[/tex]) both values will give different values.
Answer:
it's C
Step-by-step explanation:
I just did it
This is the new one! Please help I’m so lost
Answer:
(a) (f o g)(x) = x^2 - 15x + 54
(b) (g o f)(x) = x^2 + 3x - 9
(c) (f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x
(d) (g o g)(x) = x - 18
Step-by-step explanation:
f(x) = x^2 + 3x
g(x) = x - 9
(a)
(f o g)(x) = f(g(x)) = (g(x))^2 + 3(g(x)) = (x - 9)^2 + 3(x - 9)
(f o g)(x) = x^2 - 18x + 81 + 3x - 27
(f o g)(x) = x^2 - 15x + 54
(b)
(g o f)(x) = g(f(x)) = f(x) - 9 = x^2 + 3x - 9
(c)
(f o f)(x) = f(f(x)) = (x^2 + 3x)^2 + 3(x^2 + 3x)
(f o f)(x) = x^4 + 6x^3 + 9x^2 + 3x^2 + 9x
(f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x
(d)
(g o g)(x) = g(g(x)) = x - 9 - 9 = x - 18
what is the value of this expression when g= -3.5?
8-|2g-5|
a. 20
b. 10
c. 6
d. -4
Answer:
d. -4
Step-by-step explanation:
Let's plug in g
8 - |2(-3.5) - 5|
8 - |-7-5|
8 - |-12|
The absolute value is always positive of any number,
8 - 12
= -4
Answer:
D. -4
Step-by-step explanation:
We are given this expression:
[tex]8-|2g-5|[/tex]
and asked to evaluate when g= -3.5 Therefore, we must substitute -3.5 in for g.
[tex]8-|2(-3.5)-5|[/tex]
First, multiply 2 and -3.5
2 * -3.5 = -7
[tex]8-|-7-5|[/tex]
Next, subtract 5 from -7.
-7-5= -12
[tex]8-|-12|[/tex]
Next, evaluate the absolute value of -12. The absolute value is how far away a number is from 0, and it is always positive. The absolute value of -12 is 12.
[tex]8-12[/tex]
Subtract 12 from 8.
[tex]-4[/tex]
The value of the expression is -4 and D is the correct answer.
what is -7 + 11 - 14 + 3 + 12
Answer:
5
Step-by-step explanation:
Answer:
5 (Follow PEMDAS left—>right)
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
Answer:
a) From A ∩ A' = ∅, we have;
A ∩ (A' ∪ B) = A ∩ B
b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;
A ∩ (A ∪ B)' = ∅
Step-by-step explanation:
a) By distributive law of sets, we have;
A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
From the complementary law of sets, we have;
A ∩ A' = ∅
Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have
A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)
A ∩ A' = ∅ (complementary law of sets)
Therefore;
(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B) = (A ∩ B) (Addition to zero identity property)
∴ A ∩ (A' ∪ B) = A ∩ B
b) By De Morgan's law
(A ∪ B)' = A' ∩ B'
Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')
By associative law of sets, we have;
A ∩ (A' ∩ B') = (A ∩ A') ∩ B'
A ∩ A' = ∅ (complementary law of sets)
Therefore, (A ∩ A') ∩ B' = ∅ ∩ B' = ∅
Which gives;
A ∩ (A ∪ B)' = ∅.
A pet store is offering a $5 in-store coupon for every person who buys a flea control product. If the flea control products range from $29.53 to $56.15, which compound inequality represents this situation?
Question 19 options:
29.53 ≤ x + 5 ≤ 56.15
29.53 ≤ x/5x ≤ 56.15
29.53 ≤x5≤ 56.15
29.53 ≤ 5 x – 5 ≤ 56.15
Answer:
29.53 ≤ x + 5 ≤ 56.15
Step-by-step explanation:
A $5 in-store coupon for every person who buys a flea control product which ranges between $29.53 to $56.15. This means that if you bought a flea control product you would be given an additional $5 that means that for buying a flea product, $5 is given to you. If you have $x, and you bought a flea product you would have x + 5. The inequality that represents this situation is given as:
29.53 ≤ x + 5 ≤ 56.15
41 =12d-7 d= Math is not my strong suit. I love to read and write but I can not do math without a little bit of help.
Answer:
[tex]\huge\boxed{d = 4 }[/tex]
Step-by-step explanation:
41 = 12d - 7
Adding 7 to both sides
41+7 = 12d
48 = 12 d
Dividing both sides by 12
4 = d
OR
d = 4
Answer:
[tex]\large \boxed{{d=4}}[/tex]
Step-by-step explanation:
[tex]41 =12d-7[/tex]
Add 7 on both sides.
[tex]41 +7=12d-7+7[/tex]
[tex]48=12d[/tex]
Divide both sides by 12.
[tex]\displaystyle \frac{48}{12} =\frac{12d}{12}[/tex]
[tex]4=d[/tex]
help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help help ill give brainly ;))
Answer:
a) 22:25 is the earliest time
b)15 min
Step-by-step explanation:
Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....
10:10(standard) = 22:10 (military)
22:10 -> 15min-> 22:25
Answer:
a) 22:25 is the earliest time
b)15 min
Because
Since the time is in military time you must add the time it takes her to get to the bus stop to 12. then the rest is self explainitory....
Please answer this question now
Answer:
76 degrees.
Step-by-step explanation:
Let as consider O is the center of the circle . So from the figure it is clear that
[tex]\angle AOB=44^{\circ}[/tex]
[tex]\angle COD=118^{\circ}[/tex]
By central angle theorem, central angle subtended by an arc is twice of inscribed angle of the same arc.
We know that, [tex]\angle BAD=97^{\circ}[/tex] and angle BOD is the central angle subtended by arc BD.
[tex]\angle BOD=2\times \angle BAD[/tex]
[tex]\angle BOD=2\times 97^{\circ}[/tex]
[tex]\angle BOD=194^{\circ}[/tex]
Now,
[tex]\angle BOD=\angle BOC+\angle COD[/tex]
[tex]194^{\circ}=\angle BOC+118^{\circ}[/tex]
[tex]194^{\circ}-118^{\circ}=\angle BOC[/tex]
[tex]76^{\circ}=\angle BOC[/tex]
[tex]m(arc(BC))=76^{\circ}[/tex]
Therefore, the measure of arc BC is 76 degrees.
A box contain 12 balls in which 4 are white 3blue and 5 are red.3 balls are drawn at random from the box. Find the chance that all three balls are of different colour
Answer:
white: 1/3, blue: 1/4, red: 5/12
Step-by-step explanation:
Take the amount of balls each color has and divide by 12.
White:
4/12 = 1/3
Blue:
3/12 = 1/4
Red:
5/12 (can't simplify)
Answer:
3/44 or 0.068
Step-by-step explanation:
(3/12 × 2/11 × 1/10)+(5/12 × 4/11 × 3/10)+(4/12 × 3/11 × 2/10)
=3/44
Sagan scored 1200 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 980 and standard deviation 100. Andrea scored 27 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 20 and standard deviation 5. Who performed better on the standardized exams and why? Sagan scored higher than Andrea. Sagan's standardized score was 2.2, which is 2.2 standard deviations above the mean and Andrea's standardized score was 1.4, which is 1.4 standard deviations above the mean. Sagan scored higher than Andrea. Sagan's score was a 1200, which is greater than Andrea's score of 27. Andrea scored higher than Sagan. Andrea's standardized score was 1.4, which is 1.4 standard deviations above the mean, but closer to the mean than Sagan's standardized score of 2.2 standard deviations above the mean. Sagan scored higher than Andrea. Sagan's score was 220 points above the mean of 980, and Andrea's was 7 points above the mean of 20. Andrea scored higher than Sagan. Andrea is only 9 points from the top score of 36 on the ACT, and Sagan is 400 points from the top score of 1600 on the SAT.
Answer:
A
Step-by-step explanation:
Option A is correct. Sagan scored higher than Andrea. Sagan's standardized score was 2.2, which is 2.2 standard deviations.
Answer: Correct
Sagan scored higher than Andrea. Sagan's standardized score was 2.2, which is 2.2 standard deviations above the mean and Andrea's standardized score was 1.4, which is 1.4 standard deviations above the mean.
Step-by-step explanation: No clue:)
hi there can you please help me
[tex]t = \sqrt{ \frac{ab - s}{r + ak} } [/tex]
[tex]t=\sqrt{\dfrac{ab-s}{r+ak}}\\\\t^2=\dfrac{ab-s}{r+ak}\\\\rt^2+akt^2=ab-s\\\\akt^2-ab=-rt^2-s\\\\a(kt^2-b)=-(rt^2+s)\\\\a=-\dfrac{rt^2+s}{kt^2-b}\\\\a=-\dfrac{rt^2+s}{-(b-kt^2)}\\\\a=\dfrac{rt^2+s}{b-kt^2}[/tex]
The members of an Olympiad team contributed
a total of $ 1.69 for refreshments for their
weekly practices. Each member contributed the
same amount and paid for his or her share in
five coins. How many nickels were contributed
by all of the members?
Answer:
26 nickels
Step-by-step explanation:
Given that
Total contributed = $1.69
Number of coins = 5
based on the above information,
The number of nickels to be contributed is
Here first we have to determine the prime factors of 169 i.e 13 and 13
This represents that there are 13 member gives their $0.13 per person so it would be $1.69
Also there are 13 cents out of which 3 cents would be 3 pennies the remaining 10 cents would be 2 nickels
So the 13 people contributed to 2 nickels
Therefore, it would be
= 13 × 2
= 26 nickels
How many cubes with side lengths of \dfrac12 \text{ cm} 2 1 cmstart fraction, 1, divided by, 2, end fraction, start text, space, c, m, end text does it take to fill the prism? Cubes
Answer:
24
Step-by-step explanation:
Answer
24!
Step-by-step explanation:
Person above me is correct :)
Varadha bought two bags of rice of weights 45 kg and 63 kg. Find the maximum weight required, to measure the weight of rice exact number of times. options : 1.6 kg 2.35 kg 3.3 kg 4.9 kg
Answer:
3 kg
Step-by-step explanation:
given data
weights bag1 = 45 kg
weights bag2 = 63 kg
solution
we will take here first HCF of 75 and 69
factor of 75 = 3 × 5 × 5
factor of 69 = 3 × 23
so here HCF of 75 and 69 = 3
so that here maximum weight required, to measure the weight of rice exact 3 times
so correct option is 3. 3 kg
Answer:
4. 9 kg
Step-by-step explanation:
The greatest common factor of 45 kg and 63 kg is 9 kg.
45 = 9×5
63 = 9×7
A 9 kg weight could be used to weigh these amounts exactly.
_____
Comment on the problem statement
Appropriate formatting is helpful. It is difficult to tell that your answer choices are not 1.6, 2.35, 3.3, and 4.9. None of those makes any sense. With minimal formatting effort, you could list them as ...
1. 6 kg
2. 35 kg
3. 3 kg
4. 9 kg
Even better, the choices could be identified using letters and/or a separator other than a decimal point: A) 6 kg, B) 35 kg, and so on. The idea is to make it very clear what the numbers of the choices are. Less confusion is better.
Two trains leave New York at the same time heading in opposite directions. Train A travels at 4 5 the speed of train one. After seven hours they are 693 miles apart. What was the speed of train A?
Answer:
Speed of train A is 44 miles/hr.
Step-by-step explanation:
Let the speed of train A = [tex]u\ miles/hr[/tex]
Let the speed of train one = [tex]v\ miles/hr[/tex]
Train A travels at [tex]\frac{4}{5}^{th}[/tex] the speed of train one.
i.e.
[tex]u = \dfrac{4}{5}v \\\Rightarrow v =\dfrac{5}{4}u.... (1)[/tex]
Distance traveled = 693 miles
Time taken = 7 hours
They are travelling in opposite directions so the resultant speed will appear to be faster.
Relative speed = [tex]u+v\ miles/hr[/tex]
The trains are 693 miles apart in 7 hours that means they have traveled a total distance of 693 miles in 7 hours with a speed of ([tex]u+v[/tex]) miles/hr.
Using the formula:
[tex]Speed = \dfrac{Distance}{Time}[/tex]
[tex]u+v = \dfrac{693}{7}\\\Rightarrow u+v=99 ...... (2)[/tex]
Putting the value of v using equation (1):
[tex]\dfrac{5}4u+u=99\\\Rightarrow 5u+4u = 99 \times 4\\\Rightarrow 9 u = 99 \times 4\\\Rightarrow u = 11 \times 4 = \bold{44\ miles/hr}[/tex]
Speed of train A is 44 miles/hr.
Please answer. I need this to be done, Thanks. Will give brainliest
Answer:
The answer is s^26/pq59
Step-by-step explanation:
Answer:
p^ -1 q ^ -59 s ^26
or without negative exponents
s^ 26 /(p q^ 59)
Step-by-step explanation:
When multiplying , we can add the exponents when the bases are the same
p^0 q ^ -60 r^-1 s^25 * p^-1 qrs
When there is no exponent written, there is an implied 1
p^ (0+-1) q^(-60+1) r ^( -1 +1) s ^ ( 25+1)
p^ -1 q ^ -59 r ^0 s ^26
r^0 = 1
p^ -1 q ^ -59 s ^26
If you need the negative exponents written as positive
a^-b = 1/ a^b
s^ 26 /(p q^ 59)
Simplify to create an equivalent expression. -3(2+4k)+7(2k-)
Answer:
[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]
Step-by-step explanation:
The question seem incomplete; however, the given parameter is assumed as
[tex]-3(2 + 4k) + 7(2k)[/tex]
Required
Simplify
[tex]-3(2 + 4k) + 7(2k)[/tex]
Start by opening the brackets
[tex]-3*2 -3* 4k + 7*2k[/tex]
[tex]-6 -12k +14k[/tex]
Collect Like Terms
[tex]-6 -12k +14k[/tex]
[tex]-6 + 2k[/tex]
Reorder the above expression
[tex]2k - 6[/tex]
The answer can be further simplified as
[tex]2(k - 3)[/tex]
Hence;
[tex]-3(2 + 4k) + 7(2k)[/tex] = [tex]2k - 6[/tex] or [tex]2(k - 3)[/tex]
Write and solve an equation to answer the question. How many people must attend the third show so that the average attendance per show is 3000?
Answer:
3250
Step-by-step explanation:
so for the first and 2nd show, the attendance is 2580 and 2920.
The average of both these numbers is 2750
the if the third show had 3000 people, the average attendance would only be 2875.
We need the average number to be 3000.
2750 is 250 less than 3000, so the other number must be 250 more.
3250 is how many people should go to the last show.
=====================================
Explanation:
We have 2580 people attend the first show and 2920 attend the second. So far, that's 2580+2920 = 5500 people. Add on another x people to get 5500+x, which represents the sum of all three days attendance figures. Divide this sum by 3 to get the average attendance
average attendance = (sum of individual attendance values)/(number of days)
average attendance = (5500+x)/3
So that's why (5500+x)/3 goes in the first box. The parenthesis are important to ensure that you divide all of "5500+x" over 3. If you just wrote 5500+x/3, then the computer would think you just want to divide x only over 3.
----------------
We set (5500+x)/3 equal to 3000 as we want the average of the three days to be 3000
(5500+x)/3 = 3000
5500+x = 3*3000
5500+x = 9000
x = 9000-5500
x = 3500
We need 3500 people to show up on day 3 so that the average of all three days is 3000.
3500 goes in the second box.
----------------
Check:
The figures for the three days are 2580, 2920, and 3500
They add to 2580+2920+3500 = 9000
Which divides to 9000/3 = 3000, which is the average we're after. So the answer is confirmed.
